5. Which of the following is an equivalent form of the parabola y = x - 4x - 12 that displays
the x-intercepts?
A) y + 12 = x² - 4x
B) y = (x - 2)2 - 16
C) y=(x-6) (x + 2)
D) y = x (x – 4) - 12

Answers

Answer 1

Answer:

Your answer is B. Tell me if you need graphics)

Answer 2

it would be C

My best assumption here is you misplaced x^2 in this function. Mostly what is done with the answer C is the function is being FACTORED, and broken down into its simplest form.


Related Questions

Which sentence in this excerpt from Common Sense by Thomas Paine supports the claim that the American colonies could thrive independently from Britain? I have heard it asserted by some, that as America hath flourished under her former connection with Great Britain that the same connection is necessary towards her future happiness, and will always have the same effect. Nothing can be more fallacious than this kind of argument. We may as well assert that because a child has thrived upon milk that it is never to have meat, or that the first twenty years of our lives is to become a precedent for the next twenty. But even this is admitting more than is true, for I answer roundly, that America would have flourished as much, and probably much more, had no European power had any thing to do with her. The commerce, by which she hath enriched herself, are the necessaries of life, and will always have a market while eating is the custom of Europe.

Answers

Answer:

A

Step-by-step explanation:

Answer:

"But even this is admitting more than is true, for I answer roundly, that America would have flourished as much, and probably much more, had no European power had any thing to do with her."

Step-by-step explanation:

Checked 2021

In this problem, y = c1ex + c2e−x is a two-parameter family of solutions of the second-order DE y'' − y = 0. Find a solution of the second-order IVP consisting of this differential equation and the given initial conditions. y(−1) = 9, y'(−1) = −9

Answers

Answer:

[tex]y(x)=\frac{9}{e^{1} } e^{-x} =3.310914971e^{-x}[/tex]

Step-by-step explanation:

This problem is very simple, since they give the solution for the differential equation from the start. So basically, you need to evaluate the initial conditions into the solution, and the derivative of the solution in order to find the value of the constants [tex]c_1[/tex] and [tex]c_2[/tex].

So, first of all, let's find the derivative of [tex]y(x)[/tex]:

[tex]y'(x)=c_1 e^{x} -c_2e^{-x}[/tex]

Now, let's evaluate the first initial condition:

[tex]y(-1)=c_1e^{-1} +c_2e^{-(-1)} =9\\\\c_1e^{-1} +c_2e^{1}=9\hspace{10}(1)[/tex]

Now, the second initial condition:

[tex]y'(-1)=c_1 e^{-1} -c_2e^{-(-1)}=-9\\\\c_1 e^{-1} -c_2e^{1}=-9\hspace{10}(2)[/tex]

Combining (1) and (2) we have a 2x2 System of Equations. Let's use elimination method in order to solve it:

[tex](1)+(2):\\\\c_1e^{-1} +c_2e^{1} +c_1e^{-1} -c_2e^{1}=9-9\\\\2c_1e^{-1} =0\\\\Hence\\\\c_1=0[/tex]

Replacing [tex]c_1[/tex] into (1)

[tex](0)e^{-1} +c_2e^{1}=9\\\\c_2e^{1}=9\\\\Hence\\\\c_2=\frac{9}{e^{1} } =3.310914971[/tex]

Therefore the solution of the second-order IVP is:

[tex]y(x)=\frac{9}{e^{1} } e^{-x} =3.310914971e^{-x}[/tex]

Given the figure below, find the values of x and Z.

Please explain step by step how to solve, this is a guide for a test.

Answers

Answer:

  (x, z) = (7, 69)

Step-by-step explanation:

Easy first: 69° and z° are vertical angles, so congruent:

  z = 69

__

The angle marked with an expression in x is supplementary to either of the other two:

  (6x +69)° +69° = 180°

  6x = 42 . . . . . . . . . . . . divide by °, subtract 138

  x = 7 . . . . . . . . . . . . . . divide by 6

76% is between which of the following two numbers?

Answers

Hey there!

You haven't provided any answer options but here's how you would solve a problem like this.

To find the number in between two numbers, you add it up and divide it by two!

So, what's between 1 and 3? Well you do 1+3 is 4 then divide by 2 you get 2!

100 and 580? You add them to get 680 then divide by two you get 340!

In between 0.57 and 0.69? Adding gives you 1.26 and then divide by two and we have 0.63!

And with percents, let's do 45% and 67%. You add you get 112% and then divide by two you have 56%!

So, with your answer options just add them up and divide by two and see which one gives you 76%!

I hope that this helps!

Simplify. Remove all perfect squares from inside the square root. \sqrt{30b^5}= 30b 5 ​

Answers

Answer:

The answer is b=0 or b=9.085603

The equation is solved and the perfect squares are removed from the square root and A = b²√( 30b )

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

Let the equation be represented as A

Now , the value of A is

Substituting the values in the equation , we get

A = √( 30b⁵ )

On simplifying the equation , we get

We can simplify the given expression by breaking down the number inside the square root into its prime factors:

30b⁵ = 2 x 3 x 5 x b⁵

Since we are looking to remove all perfect squares, we can remove the factors of 2 and 3, which are the only perfect squares present in the prime factorization of 30. This leaves us with:

30b⁵ = 2 x 3 x 5 x b⁵

= 2 x 3 x 5 x b⁴ x b

= 30b⁴ x b

Therefore, we can simplify the original expression as:

√(30b⁵) = √(30b⁴ x b) = √(30b⁴) x √b

A = b²√30 x √b

Hence , the expression √(30b⁵) simplifies to A = b²√30 x √b

To learn more about equations click :

https://brainly.com/question/19297665

#SPJ2

How many meters are in 18,200 milliliter

Answers

Answer:

18.2 :)

Have a great day!!!

In triangle ABC, the right angle is at vertex C, a = 714 cm and the measure of angle A is 78° . To the nearest cm, what is the length of side c?

Answers

Answer:

c = 730cm

Step-by-step explanation:

The first thing we would do is to draw the diagram using th given information.

Find attached the diagram.

a = 714 cm

the measure of angle A = 78°

To determine c, we would apply sine rule. This is because we know the opposite and we are to determine the hypotenuse

sin78 = opposite/hypotenuse

sin 78 = 714/c

c = 714/sin 78 = 714/0.9781

c= 729.99

c≅ 730 cm ( nearest cm)

A production facility employs 20 workers on the day shift, 15 workers on the swing shift, and 10 workers on the graveyard shift. A quality control consultant is to select 7 of these workers for in-depth interviews. Suppose the selection is made in such a way that any particular group of 7 workers has the same chance of being selected as does any other group (drawing 7 slips without replacement from among 45).
1. How many selections result in all 7 workers coming from the day shift?
2. What is the probability that all 7 selected workers will be from the day shift?
3. What is the probability that all 7 selected workers will be from the same shift?
4. What is the probability that at least two different shifts will be represented among the selected workers?
5. What is the probability that at least one of the shifts will be un-represented in that sample of workers?

Answers

Answer:

1. 77520

2. [tex]P_1[/tex] = 0.0017

3. [tex]P_2[/tex] = 0.0019

4. [tex]P_3[/tex] = 0.9981

5. [tex]P_4[/tex] = 0.2036

Step-by-step explanation:

The number of ways or combinations in which we can select x elements from a group of n can be calculated as:

[tex]nCx = \frac{n!}{x!(n-x)!}[/tex]

So, there are 77520 selections that result in all 7 workers coming from the day shift. It is calculated as:

[tex]20C7 = \frac{20!}{7!(20-7)!}=77520[/tex]

At the same way, the total number of selections of 7 workers from the 45 is 45C7, so the probability that all 7 selected workers will be from the day shift is:

[tex]P_1=\frac{20C7}{45C7} =0.0017[/tex]

The probability that all 7 selected workers will be from the same shift is calculated as:

[tex]P_2=\frac{20C7+15C7+10C7}{45C7} =0.0019[/tex]

Because the consultant can select all workers from the day shift (20C7) or can select all workers from the swing shift (15C7) or can select all workers from the graveyard shift (10C7).

On the other hand, the probability that at least two different shifts will be represented among the selected workers is the complement of the probability that all 7 selected workers will be from the same shift. So it is calculated as:

[tex]P_3 = 1- P_2=1 - 0.0019 = 0.9981[/tex]

Finally, the probability that at least one of the shifts will be un-represented in that sample of workers is:

[tex]P_4=\frac{25C7+30C7+35C7}{45C7} =0.2036[/tex]

Where 25C7 is the number of ways to select all 7 workers from swing or graveyard shift, 30C7 is the number of ways to select all 7 workers from day or graveyard shift and 35C7 is the number of ways to selects all 7 workers from day shift and swing shift.

PLZZZ I NEED HELP I’ll give 20 POINTS
What is the median of the following data set?
(6,3, 9, 1,7)
03
06
08
09

Answers

Answer:

6

Step-by-step explanation:

Arrange the data from smallest to largest

1,3,6,7,9

The median is the middle number

1,3   ,6,   7, 9

The middle number is 6

Simplify: |4-5| / 9 × 3³ - 2/5 a.61/10 b.13/5 c.11/10 d.-2/15

Answers

━━━━━━━☆☆━━━━━━━

▹ Answer

Answer = b. 13/5

▹ Step-by-Step Explanation

|4 - 5| ÷ 9 × 3³ - 2/5

|-1| ÷ 9 × 3³ - 2/5

1 ÷ 9 × 3³ - 2/5

1/9 × 3³ - 2/5

1/3² × 3³ - 2/5

3 - 2/5

Answer = 13/5

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

[tex] \boxed{\sf b. \ \frac{13}{5}} [/tex]

Step-by-step explanation:

[tex] \sf Simplify \: the \: following: \\ \sf \implies \frac{ |4 - 5| }{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf 4 - 5 = - 1 : \\ \sf \implies \frac{ | - 1| }{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf Since \: - 1 \: is \: a \: negative \: constant, \: |-1| = 1: \\ \sf \implies \frac{1}{9} \times {3}^{3} - \frac{2}{5} \\ \\ \sf {3}^{3} = 3 \times {3}^{2} : \\ \sf \implies \frac{ \boxed{ \sf 3 \times {3}^{2}} }{9} - \frac{2}{5} \\ \\ \sf {3}^{2} = 9 : \\ \sf \implies \frac{3 \times 9}{9} - \frac{2}{5} \\ \\ \sf \frac{9}{9} = 1 : \\ \sf \implies 3 - \frac{2}{5} [/tex]

[tex] \sf Put \: 3 - \frac{2}{5} \: over \: the \: common \: denominator \: 5 : \\ \sf \implies 3 \times \frac{5}{5} - \frac{2}{5} \\ \\ \sf \implies \frac{3 \times 5}{5} - \frac{2}{5} \\ \\ \sf 3 \times 5 = 15 : \\ \sf \implies \frac{ \boxed{ \sf 15}}{5} - \frac{2}{5} \\ \\ \sf \implies \frac{15 - 2}{5} \\ \\ \sf 15 - 2 = 13 : \\ \sf \implies \frac{13}{5} [/tex]

i need this fast plz

Answers

Answer:

180-130 = 50 degrees because its same side angle

m<2 = 50

Step-by-step explanation:

the second one m<1 is 105 for the same reason

Question 3 of 10
2 Points
If h(x) =(fºg)(x) and h(x) = 3(x + 2), find one possibility for f (x) and g(x).

Answers

Answer:

[tex]\boxed{\sf \ \ \ \text{one possibility is } f(x)=3x \ and \ g(x)=x+2 \ \ \ }[/tex]

Step-by-step explanation:

hello

h(x)=f(g(x))=3(x+2)

if we have f(x)=3x and g(x)=x+2 then

f(g(x))=f(x+2)=3(x+2)

hope this helps

Use the standard normal table to find P(z ≥ 1.06). Round to the nearest percent.

Answers

Answer:

14%

Step-by-step explanation:

On edge 2020

Brainliest to whoever gets this correct This word problem has too much information. Which fact is not needed to solve the problem? Tanisha tried to sell all her old CDs at a garage sale. She priced them at $2 each. She put 80 CDs in the garage sale, but she sold only 35 of them. How many did she have left? A. All of the information is needed. B. Tanisha sold the CDs for $2 each. C. Tanisha put 80 CDs in the sale. D. Tanisha sold 35 of the CDs.

Answers

B. tanisha sold the cds for $2 each

Answer:

B. Tanisha sold the CDs for $2 each.

Step-by-step explanation:

PLEASE HELP SOLVE THIS!!!!!

Answers

Answer:

20) -43

21) 25

22)-9

Step-by-step explanation:

20) -6 (-6 + 49)/6 = -43

21) 10 - (-10 - (-1 + 6)) = 25

22) 1 - 10/2 - 5 = -9

Step-by-step explanation:

22

Let's calculate the expression khowing that m= 1 and n = 5

m-[tex]\frac{m+m}{2}[/tex] -nm- [tex]\frac{2m}{2}[/tex]-n m-m-n0-n0-5-5

20

Let's calculate the expression khowing that n= -7 and p= - 6

[tex]\frac{p(p+n^{2}) }{6}[/tex] [tex]\frac{-6(-6+(-7)^{2}) }{6}[/tex][tex]\frac{-6(-6+49)}{2}[/tex] [tex]\frac{-6*43}{6}[/tex] -1*43-43

21

Let's calculate the expression khowing that n = -6 and m = -1 and p = -10

mp-(p-(m-n))mp-(p-m+n)mp-p+m-n(-1)*(-10)-(-10)+(-1)-(-6)10+10-1+620-1+619+625

Of 1000 randomly selected cases of lung cancer, 823 resulted in death within 10 years.
a. Calculate a 95% two-sided confidence interval on the death rate from lung cancer.
b. Using the point estimate of p obtained from the preliminary sample, what sample size is needed to be 95% confident that the error in estimating the true value of p is less than 0.03?
c. How large must the sample be if you wish to be at least 95% confident that the error in estimating p is less than 0.03, regardless of the true value of p?

Answers

Answer:

a) [tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

b) [tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

c) [tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Step-by-step explanation:

Part a

[tex]\hat p=\frac{823}{1000}=0.823[/tex]

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 95% of confidence, our significance level would be given by [tex]\alpha=1-0.95=0.05[/tex] and [tex]\alpha/2 =0.025[/tex]. And the critical value would be given by:

[tex]z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96[/tex]

The confidence interval for the mean is given by the following formula:  

[tex]\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

If we replace the values obtained we got:

[tex]0.823 - 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.799[/tex]

[tex]0.823 + 1.96\sqrt{\frac{0.823(1-0.823)}{1000}}=0.847[/tex]

The 95% confidence interval would be given by (0.799;0.847)

Part b

The margin of error for the proportion interval is given by this formula:  

[tex] ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]    (a)  

And on this case we have that [tex]ME =\pm 0.03[/tex] and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

[tex]n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}[/tex]   (b)  

And replacing into equation (b) the values from part a we got:

[tex]n=\frac{0.823(1-0.823)}{(\frac{0.03}{1.96})^2}=621.79[/tex]  

And rounded up we have that n=622

Part c

[tex]n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.96})^2}=1067.11[/tex]  

And rounded up we have that n=1068

Anja is choosing her extracurricular activities for the year. She can choose one sport to play and one instrument to learn using the list below:
Sports: softball, basketball, tennis, or swimming
Instruments: guitar, piano, or clarinet​. How many combinations are possible?

Answers

Answer:

The number of possible combinations of sports and instrument that Anja can select is 12.

Step-by-step explanation:

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

[tex]{n\choose k}=\frac{n!}{k!\cdot(n-k)!}[/tex]

It is said that Anja can choose one sport to play and one instrument to learn using the list below:

Sports: softball, basketball, tennis, or swimming

Instruments: guitar, piano, or clarinet​.

There 4 options for sports and 3 for an instrument.

Compute the number of ways to select one sport to play as follows:

[tex]n (S)={4\choose 1}=\frac{4!}{1!\cdot(4-1)!}=\frac{4!}{3!}=\frac{4\times3!}{3!}=4[/tex]

Compute the number of ways to select one instrument to learn as follows:

[tex]n(I)={3\choose 1}=\frac{3!}{1!\cdot(3-1)!}=\frac{3!}{2!}=\frac{3\times2!}{2!}=3[/tex]

Compute the number of possible combinations of sports and instrument that Anja can select as follows:

Total number of possible combinations = n (S) × n (I)

                                                                  [tex]=4\times 3\\=12[/tex]

Thus, the number of possible combinations of sports and instrument that Anja can select is 12.

Answer:

12

Step-by-step explanation:

Hurry!! Determine the intervals for which the function shown below is decreasing.

Answers

Answer:

everywhere except between 2 and 5

(between -inf and 2 and between 5 and inf)

Step-by-step explanation:

If we express $2x^2 + 6x + 11$ in the form $a(x - h)^2 + k$, then what is $h$? (ignore the $)

Answers

Answer:

h = - [tex]\frac{3}{2}[/tex]

Step-by-step explanation:

The equation of a parabola in vertex form is

y = a(x - h)² + k

where (h, k) are the coordinates of the vertex and a is a multiplier

Given

y = 2x² + 6x + 11 ( factor out 2 from the first 2 terms )

   = 2(x² + 3x) + 11

Using the method of completing the square

add/subtract ( half the coefficient of the x- term )² to x² + 3x

y = 2(x² + 2([tex]\frac{3}{2}[/tex] )x + [tex]\frac{9}{4}[/tex] - [tex]\frac{9}{4}[/tex] ) + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² - [tex]\frac{9}{2}[/tex] + 11

  = 2(x + [tex]\frac{3}{2}[/tex] )² + [tex]\frac{13}{2}[/tex] ← in vertex form

with h = - [tex]\frac{3}{2}[/tex]

The route used by a certain motorist in commuting to work contains two intersections with traffic signals. The probability that he must stop at the first signal is 0.36, the analogous probability for the second signal is 0.51, and the probability that he must stop at least one of the two signals is 0.67.What is theprobability that he must stop.
a) At both signals?
b) At the first signal but not at the second one?
c) At exactly on signal?

Answers

Answer:

a) P(X∩Y) = 0.2

b) [tex]P_1[/tex] = 0.16

c) P = 0.47

Step-by-step explanation:

Let's call X the event that the motorist must stop at the first signal and Y the event that the motorist must stop at the second signal.

So, P(X) = 0.36, P(Y) = 0.51 and P(X∪Y) = 0.67

Then, the probability P(X∩Y) that the motorist must stop at both signal can be calculated as:

P(X∩Y) = P(X) + P(Y) - P(X∪Y)

P(X∩Y) = 0.36 + 0.51 - 0.67

P(X∩Y) = 0.2

On the other hand, the probability [tex]P_1[/tex] that he must stop at the first signal but not at the second one can be calculated as:

[tex]P_1[/tex] = P(X) - P(X∩Y)

[tex]P_1[/tex] = 0.36 - 0.2 = 0.16

At the same way, the probability [tex]P_2[/tex] that he must stop at the second signal but not at the first one can be calculated as:

[tex]P_2[/tex] = P(Y) - P(X∩Y)

[tex]P_2[/tex] = 0.51 - 0.2 = 0.31

So, the probability that he must stop at exactly one signal is:

[tex]P = P_1+P_2\\P=0.16+0.31\\P=0.47[/tex]

11- In
how many ways 3 mathematics books, 4 history books ,3
chemisidy books and a biology books can be arranged
on an Shelf so thet all books of the same subjects are
together!​

Answers

Answer:    20,736

Step-by-step explanation:

Math and History and Chemistry and Biology and Subjects

  3!     x        4!        x          3!          x        1!          x        4!       = 20,736

if it takes four men to dig a land in 6 days.how many days will it take 6 men to build that same land.​

Answers

Answer:

4 days

Solution,

____________________________

Men ------------------------------ Days

4 ------------------------> 66 ------------------------> X (suppose)

_____________________________

In case of indirect proportion,

4/6= 6/X

or, 6*X= 6*4 ( cross multiplication)

or, 6x= 24

or, 6x/6= 24/6 ( dividing both sides by 6)

x= 4 days

Hope this helps...

Good luck on your assignment..

Answer:

[tex]\boxed{4 days}[/tex]

Step-by-step explanation:

M1 = 4

D1 = 6

M2 = 6

D2 = x (we've to find this)

Since,  it is an inverse proportion (more man takes less days for the work to complete and vice versa), so we'll write it in the form of

M1 : M2 = D2 : D1

4 : 6 = x : 6

Product of Means = Product of Extremes

=> 6x = 4*6

=> 6x = 24

Dividing both sides by 6

=> x = 4 days

Classify the following triangle. Check all that apply.
A. Isosceles
B. Right
C. Obtuse
D. Equilateral
E. Scalene
F. Acute

Answers

Answer:

Equilateral

Acute

Step-by-step explanation:

The sides are all equal as indicated by the lines on each side - Equilateral

The angles are all equal by the angle marks  180/3 = 60 which is less than 90 degrees.  This makes the angles acute

Which of the following cannot have a Discrete probability distribution? a. The number of customers arriving at a gas station in Christmas day b. The number of bacteria found in a cubic yard of soil. c. The number of telephone calls received by a switchboard in a specified time period. d. The length of a movie

Answers

Answer:

d. The length of a movie

Step-by-step explanation:

A discrete random variable is a variable which only takes on integer values.

A discrete distribution is used to describe the probability of the occurrence of each value of a discrete random variable.

From the given options, the length of a movie is not a discrete variable as it can have decimal values.

It therefore cannot have a Discrete probability distribution.

The correct option is D.

A rectangle measures 18 cm x 3 cm what is its area

Answers

Answer:

Six

Step-by-step explanation:

The answer could be shown in multiple forms, but if I'm correct, the answer to this problem would be six.

Which of the following points is NOT a solution of the inequality y ≥ Ixl + 3?

A. (-3, 0)

B. (-3, 6)

C. (0, 4)​

Answers

Hey there!

To solve this, we need to plug each of our answer options into the inequality and see if it is true. Which ever one doesn't make the inequality true when plugged in is the answer.

OPTION A

(x,y)=(-3,0)

We plug our values into the inequality.

0≥ I-3I+3

You may have noticed the bars surrounding the negative three.. If you didn't know, this is called absolute value. Absolute value is how far the number is from 0 on the number line. -7 is 7 away from 0 on a number line, so the absolute value of -7 is 7. The absolute value of 7 is 7. The absolute value of 0 is 0. Absolute value is signified by these bars. Le'ts finish evaluating.

0≥6

As you can see, zero is not greater than or equal to six. So, option A is false.

Since A is not a solution, we already know that that is the answer, so we don't even need to check B and C. But, we can still evaluate them if you want.

OPTION B

6≥I-3I+3

6≥6

This is true.

OPTION C

4≥I0I+3

4≥3

This is also true.

Therefore, the answer is A. (-3,0)

Have a wonderful day!

Identify the correct HYPOTHESIS used in a hypothesis test of the following claim and sample data: Claim: "The average annual household income in Warren County is $47,500." A random sample of 86 households from this county is obtained, and they have an average annual income of $48,061 with a standard deviation of $2,351. Test the claim at the 0.02 significance level.

Answers

Answer:

We accept H₀

Step-by-step explanation:

Population mean  μ₀ = 47500

Population standard deviation unknown

Sample size    n = 86   degree of freedom  df = 86 - 1  df = 85

Sample mean    μ = 48061

Sample standard deviation 2,351

The claim implies a two tail test with t-studend distributon

Null  Hypothesis                 H₀               μ  =  μ₀

Alternative Hypothesis      Hₐ               μ  ≠  μ₀      

Confidence Interval  mean α = 0,02     and   α/2  =  0,01

With α/2 and df = 85, from t-table we find  t(c)  critical value

t(c) = 2,3710

We compute t(s) as

t(s)  =  ( μ - μ₀ ) / s /√n

t(s)  = ( 48061 - 47500 )/ 2351/√86

t(s)  = 561 * 9,273 / 2351

t(s) = 2,212

Now we compare t(s) and t(c)

t(s) < t(c)       2,212  < 2,371

Then we are in the acceptance region. We accept H₀

Find the critical value z Subscript alpha divided by 2 that corresponds to the given confidence level. 80​%

Answers

Answer:

[tex] Conf= 0.80[/tex]

With the confidence level we can find the significance level:

[tex]\alpha =1-0.8=0.2[/tex]

And the value for [tex]\alpha/2=0.1[/tex]. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

[tex] z_{\alpha/2}= \pm 1.28[/tex]

Step-by-step explanation:

For this problem we have the confidence level given

[tex] Conf= 0.80[/tex]

With the confidence level we can find the significance level:

[tex]\alpha =1-0.8=0.2[/tex]

And the value for [tex]\alpha/2=0.1[/tex]. Then we can use the normal standard distribution and we can find a quantile who accumulates 0.1 of the area on each tail and we got:

[tex] z_{\alpha/2}= \pm 1.28[/tex]

Simplfy the following expressions:

Answers

Answer:

1st one =  d y^27

2nd one = b 2x^9

Step-by-step explanation:

1st one: since the power is being raised to the power of 3 you multiply the numbers

2nd one: the powers aren't being raised so you add the powers together.

12x^13y^10/6X^4y^10

then dividing for exponents is subtracting them so

2x^9 since y gets canceled out

find the average rate of change if the function f(x)=x^2+4x from x1=2 to x2=3

Answers

Replace x with 2 and solve:

2^2 + 4(2) = 4 + 8 = 12

Replace x with 3 and solve:

3^2 + 4(3) = 9 + 12 = 21

The difference between the two answers is : 21 -12 = 9

The difference between the two inputs is 3-2 = 1

The rate of change is the change in the answers I’ve the change in the inputs:

Rate of change = 9/1 = 9

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