Answer: -1
Step-by-step explanation:
[tex]5t-3=3t-5[/tex]
Add 3 to both sides.
[tex]5t=3t-2[/tex]
Subtract 3t from both sides.
[tex]2t=-2[/tex]
[tex]t=-1[/tex]
Hope this helps!
Answer: t=-1
Step-by-step explanation:
1) add 3 to both sides
2) subtract 3t from both sides
3) Divide both sides by 2
Figure G is rotated 90Degrees clockwise about the origin and then reflected over the x-axis, forming figure H. On a coordinate plane, triangle G has points (negative 3, 1), (negative 1, 2), (negative 2, 5). Triangle H has points (2, negative 1), (1, negative 3), (5, negative 2). Which sequence of transformations will produce the same results?
Answer:
The 1st selection is appropriate.
_____
2nd: the rotation would need to be 90° CCW
3rd, 4th: rotation or double reflection will give the original orientation. This figure is reflected an odd number of times, so has its orientation reversed.
Hope it helps.. Mark brainliest
The sequence of transformations are reflection over the y-axis and then a rotation 90 clockwise about the origin.
What is rotation rule of 90°?Here are the rotation rules: 90° clockwise rotation: (x, y) becomes (y, -x) 90° counterclockwise rotation: (x, y) becomes (-y, x) 180° clockwise and counterclockwise rotation: (x, y) becomes (-x,-y).
Given that, figure G is rotated 90° clockwise about the origin and then reflected over the x-axis, forming figure H.
Vertices of triangle G are (-3, 1), (-1, 2) and (-2, 5).
The reflection of point (x, y) across the y-axis is (-x, y).
On reflection over x-axis, we get coordinates as (3, 1), (1, 2) and (2, 5)
90° clockwise rotation: (x, y) becomes (y, -x)
On 90° clockwise rotation, we get coordinates as (1, -3), (2, -1) and (5, -2)
Triangle H has points (2, -1), (1, -3), (5, -2).
Hence, the sequence of transformations are reflection over the y-axis and then a rotation 90° clockwise about the origin.
Learn more about the rotation of 90° counterclockwise here:
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30% of a number is 45 what is the number ?
Hey there! I'm happy to help!
When talking about percents, the word "is" usually means equals. Let's use this to solve an equation! We will call our number n. Note that 30% is equal to 0.3 in decimal form because 0.3 is 30% of one! :D
0.3n=45
To solve, we need to isolate the n. To do this, we divide both sides by 0.3 because this cancels out the 0.3 that is being multiplied by n and it shows us what n will then equal.
0.3n÷0.3=45÷0.3
n=150
Therefore, 30% of 150 is 45. Try multiplying 0.3 by 150 and you will get 45!
Have a wonderful day! :D
7. The radius of a cylinder whose curved surface area is 2640 2 and height 21 cm is _________. (a) 100 ° (b) 50° (c) 80° (d) 90°
Answer:
The answer is 21.25cm
Step-by-step explanation:
Hope i am marked as brainliest
The diameter of a circle is 3.5 inches. What is the circumference of the circle?
Answer:
About 11 (10.9955742876...)
Step-by-step explanation:
Circumference=(pi) (diameter) or C=πd
Hope this helps!
The circumference of the circle is about 11 inches.
We are given that the diameter of a circle is 3.5 inches.
Noted that the circumference of the circle that has a radius of r is defined as the product of diameter to the pie value.
Therefore circumference of the circle = 2πr
Circumference=(2πr)
The diameter or C = πd
diameter = 3.5 inches
Circumference=(3.5 x 3.14)
Circumference = (10.99) inches
Learn more about circumference here;
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Show that (a - b)+(b-c)+(c -a)3 = 3 (a - b) (b -c) (c-a)
Answer:
I think that it should be
[tex] {(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]
Step-by-step explanation:
Here,
we take , a - b = A,b-c = B , c - a= C
A+B+C = 0
we know that,
[tex] {a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)[/tex]
Here , A+B+C = 0
so,
A^3 +B^3 + C^3 = 3 ABC
now we put the values
[tex]{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)[/tex]
I am done .
I think that it should be
{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)
Step-by-step explanation:
Here,
we take , a - b = A,b-c = B , c - a= C
A+B+C = 0
we know that,
{a}^{3} + {b}^{3} + {c}^{3} - 3abc = (a + b + c)( {a}^{2} + {b}^{2} + {c}^{2} - ab - bc - ca)
Here , A+B+C = 0
so,
A^3 +B^3 + C^3 = 3 ABC
now we put the values
{(a - b)}^{3} + {(b - c)}^{3} + {(c - a)}^{3} = 3(a - b)(b - c)(c - a)
I am done .
Please answer this question now
Answer:
36°
Step-by-step explanation:
<U + < V + <W = 180° (sum of angles in a triangle)
<W = 54°
The tangent is always perpendicular to the radius drawn to the point of tangency...
therefore,
<U = 90°
90° + <V + 54° = 180°
144° + <V = 180°
<V = 180° - 144°
<V = 36°
Answer:
V=36
Step-by-step explanation:
tangent makes rigt angle with radius angle U=90
W+V+U=180
V=180-90-54
V=36
find two rational numbers whose sum is -10,0,15
Answer:
Sum of two rational numbers-
-10 = -5+-5
0= -5+5
15= 10+5
Step-by-step explanation:
The figure above shows a right-angled triangle OAB. AOC is a minor sector enclosed in the triangle. If OA = 7 cm, AB = 6 cm, calculate the area and perimeternof the shaded region. PLEASE HELP!
Answer:
Step-by-step explanation:
Given that:
OA = 7 cm, AB = 6 cm. ∠A = 90°, OA = OC = 7 cm
Using Pythagoras theorem: OB² = OA² + AB²
OB² = 6² + 7²=85
OB = √85 = 9.22 cm
to find ∠O, we use sine rule:
[tex]\frac{AB}{sin(O)}=\frac{OB}{sin(A)}\\ \\sin(O)=\frac{AB*sin(A)}{OB}=\frac{6*sin(90)}{9.22} =0.65 \\\\O=sin^{-1}0.65=40.6^o[/tex]
AOC is a minor sector with radius 7 cm and angle 40.6
The Area of the triangle OAB = 1/2 × base × height = 1/2 × OA × AB = 1/2 × 7 × 6 = 21 cm²
Area of sector OAC = [tex]\frac{\theta}{360}*\pi r^2=\frac{40.6}{360}*\pi *7^2=17.37 \ cm^2[/tex]
Area of shaded region = The Area of the triangle OAB - Area of sector OAC = 21 - 17.37 = 3.63 cm²
Perimeter of arc AC = [tex]\frac{\theta}{360}*2\pi r=\frac{40.6}{360}*2\pi *7=4.96\ cm[/tex]
CB = OB - OC = 9.22 - 7 = 2.22
Perimeter of shaded region = AB + CB + arc AC = 6 + 2.22 + 4.96 = 13.18 cm
The time between failures for an electrical appliance is exponentially distributed with a mean of 25 months. What is the probability that the next failure will not occur before 30 months have elapsed
Answer:
The probability that the next failure will not occur before 30 months have elapsed is 0.0454
Step-by-step explanation:
Using Poisson distribution where
t= number of units of time
x= number of occurrences in t units of time
λ= average number of occurrences per unit of time
P(x;λt) = e raise to power (-λt) multiplied by λtˣ divided by x!
here λt = 25
x= 30
P(x= 30) = 25³⁰e⁻²⁵/ 30!
P (x= 30) = 8.67 E41 * 1.3887 E-11/30! (where E= exponent)
P (x=30) = 1.204 E31/30!
Solving it with a statistical calculator would give
P (x=30) = 0.0454
The probability that the next failure will not occur before 30 months have elapsed is 0.0454
will mark brainliest!!!plz helppp
Answer:
(5,-6)
Step-by-step explanation:
ONE WAY:
If [tex]f(x)=x^2-6x+3[/tex], then [tex]f(x-2)=(x-2)^2-6(x-2)+3[/tex].
Let's simplify that.
Distribute with [tex]-6(x-2)[/tex]:
[tex]f(x-2)=(x-2)^2-6x+12+3[/tex]
Combine the end like terms [tex]12+3[/tex]:
[tex]f(x-2)=(x-2)^2-6x+15[/tex]
Use [tex](x-b)^2=x^2-2bx+b^2[/tex] identity for [tex](x-2)^2[/tex]:
[tex]f(x-2)=x^2-4x+4-6x+15[/tex]
Combine like terms [tex]-4x-6x[/tex] and [tex]4+15[/tex]:
[tex]f(x-2)=x^2-10x+19[/tex]
We are given [tex]g(x)=f(x-2)[/tex].
So we have that [tex]g(x)=x^2-10x+19[/tex].
The vertex happens at [tex]x=\frac{-b}{2a}[/tex].
Compare [tex]x^2-10x+19[/tex] to [tex]ax^2+bx+c[/tex] to determine [tex]a,b,\text{ and } c[/tex].
[tex]a=1[/tex]
[tex]b=-10[/tex]
[tex]c=19[/tex]
Let's plug it in.
[tex]\frac{-b}{2a}[/tex]
[tex]\frac{-(-10)}{2(1)}[/tex]
[tex]\frac{10}{2}[/tex]
[tex]5[/tex]
So the [tex]x-[/tex] coordinate is 5.
Let's find the corresponding [tex]y-[/tex] coordinate by evaluating our expression named [tex]g[/tex] at [tex]x=5[/tex]:
[tex]5^2-10(5)+19[/tex]
[tex]25-50+19[/tex]
[tex]-25+19[/tex]
[tex]-6[/tex]
So the ordered pair of the vertex is (5,-6).
ANOTHER WAY:
The vertex form of a quadratic is [tex]a(x-h)^2+k[/tex] where the vertex is [tex](h,k)[/tex].
Let's put [tex]f[/tex] into this form.
We are given [tex]f(x)=x^2-6x+3[/tex].
We will need to complete the square.
I like to use the identity [tex]x^2+kx+(\frac{k}{2})^2=(x+\frac{k}{2})^2[/tex].
So If you add something in, you will have to take it out (and vice versa).
[tex]x^2-6x+3[/tex]
[tex]x^2-6x+(\frac{6}{2})^2+3-(\frac{6}{2})^2[/tex]
[tex](x+\frac{-6}{2})^2+3-3^2[/tex]
[tex](x+-3)^2+3-9[/tex]
[tex](x-3)^2+-6[/tex]
So we have in vertex form [tex]f[/tex] is:
[tex]f(x)=(x-3)^2+-6[/tex].
The vertex is (3,-6).
So if we are dealing with the function [tex]g(x)=f(x-2)[/tex].
This means we are going to move the vertex of [tex]f[/tex] right 2 units to figure out the vertex of [tex]g[/tex] which puts us at (3+2,-6)=(5,-6).
The [tex]y-[/tex] coordinate was not effected here because we were only moving horizontally not up/down.
¡Ayuda!
1. Método del Triángulo: Una embarcación navega a una distancia de 800 km hacia el Oeste y después avanza 1400 km a 135 °. ¿Cuál es la magnitud, dirección y sentido del desplazamiento resultante? R /. 2,080 km, 155 ° NO.
Answer:
La magnitud del desplazamiento resultante es 2045.463 kilómetros. La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.
Step-by-step explanation:
En primer lugar, se construye el triángulo. La figura resultante se encuentra incluida como archivo adjunto. La magnitud del desplazamiento resultante se determina mediante la Ley del Coseno:
[tex]r = \sqrt{(800\,km)^{2}+(1400\,km)^{2}-2\cdot (800\,km)\cdot (1400\,km)\cdot \cos 135^{\circ}}[/tex]
[tex]r \approx 2045.463\,km[/tex]
La magnitud del desplazamiento resultante es 2045.463 kilómetros.
La dirección del desplazamiento resultante es hallada por medio de la Ley del Seno, sabiendo que el ángulo del desplazamiento resultante a la recta de 1400 kilómetros:
[tex]\frac{1400\,km}{\sin \alpha} = \frac{2045.463\,km}{\sin 135^{\circ}}[/tex]
Se despeja el ángulo correspondiente:
[tex]\alpha = \sin^{-1}\left(\frac{1400\,km}{2045.463\,km}\times \sin 135^{\circ} \right)[/tex]
[tex]\alpha \approx 28.945^{\circ}[/tex]
La dirección absoluta del desplazamiento resultante es:
[tex]\alpha' = 180^{\circ}-\alpha[/tex]
[tex]\alpha' = 180^{\circ}-28.945^{\circ}[/tex]
[tex]\alpha' = 151.055^{\circ}[/tex]
La dirección absoluta del desplazamiento resultante es 151.055º, el cual corresponde al sentido noroeste.
y=8-2x. What is the value of y when x = 8?
Answer:
y = -8
Step-by-step explanation:
Start by filling 8 in place of x
y = 8 - 2(8)
Multiply -2(8)
y = 8 - 16
Subtract 16 from 8
y = -8
Factor x2 - 2x + 3
I have no idea and no one else has done it
Answer:
prime
Step-by-step explanation:
x^2 - 2x + 3
What two numbers multiply to 3 and add to -2
There are none so this cannot be factored in the real numbers
Determine the parent function.
Answer:
y= [tex]\sqrt{x}[/tex]
Step-by-step explanation:
Please answer this question now
Answer:
541.4 m²
Step-by-step Explanation:
Step 1: find m < V
V = 180 - (50+63) (sum of the angles in ∆)
V = 67
Step 2: find side length of XW using the law of sines
[tex] \frac{XW}{sin(V)} = \frac{XV}{sin(W)} [/tex]
Where,
V = 67°
W = 63°
XV = 37 m
XW
[tex] \frac{XW}{sin(67)} = \frac{37}{sin(63)} [/tex]
Multiply both sides by sin(67) to solve for XW
[tex] \frac{XW}{sin(67)}*sin(67) = \frac{37}{sin(63)}*sin(67) [/tex]
[tex] XW = \frac{37*sin(67)}{sin(63)} [/tex]
[tex] XW = 38.2 m [/tex] (to nearest tenth)
Step 3: find the area using the formula, ½*XW*XV*sin(X)
area = ½*38.2*37*sin(50)
Area = 541.4 m² (rounded to the nearest tenth.
Please help me as fast as you can. thanks
Answer:
<DEF = 40<EBF = <EDF = 56<DCF = <DEF =40<CAB = 84Step-by-step explanation:
In triangle DEF, we have:
Given:
<EDF=56
<EFD=84
So, <DEF =180 - 56 - 84 =40 (sum of triangle angles is 180)
____________
DE is a midsegment of triangle ACB
( since CD=DA(given)=>D is midpoint of [CD]
and BE = EA => E midpoint of [BA] )
According to midsegment Theorem,
(DE) // (CB) "//"means parallel
and DE = CB/2 = FB =CF
___________
DEBF is a parm /parallelogram.
Proof: (DE) // (FB) ( (DE) // (CB))
AND DE = FB
Then, <EBF = <EDF = 56
___________
DEFC is parm.
Proof: (DE) // (CF) ((DE) // (CB))
And DE = CF
Therefore, <DCF = <DEF =40
___________
In triangle ACB, we have:
<CAB =180 - <ACB - <ABC =180 - 40 - 56 =84(sum of triangle angles is 180)
[tex]HOPE \: THIS \: HELPS.. GOOD \: LUCK! [/tex]
the hypotnuse of a 45 -45 -90 triangle measures 22√2 units. what is the length of the leg of the triangle?
Answer:
22 units.
Step-by-step explanation:
In 45- 45- 90 triangles, there is a 1 to 1 to the square root of 2 formula. Each side length measures 1x, while the hypotenuse measures x times the square root of 2.
In this case, the hypotenuse measures 22 and the square root of 2 units. To find the value of x, simply divide that by the square root of 2 units, and you get x = 22 units. Multiply that by 1, and you get 22 units, which is the length of the leg of the triangle.
Hope this helps!
Area of a triangle is 1400 cm² the base of the triangle is 5 times the height what is the height of the triangle
Answer:
≈23.66
Step-by-step explanation:
Height ---> x
base ---> 5x
Formula for area of triangle: (base*height)/2
((5x)(x))/2 = 1400
[tex]5x^{2}[/tex]/2 = 1400
[tex]5x^{2}[/tex] = 1400 · 2 = 2800
[tex]x^2[/tex] = 2800/5 = 560
x= √560 ≈ 23.66
This is Algebra 1 functions and I'm struggling with this one function-
-1•f(-9)+7•g(6)=_____
Answer:
38
Step-by-step explanation:
f(-9) is the value of f(x) when x = -9. Therefore, f(-9) = 4 from the graph. Doing the same with g(6), we can see that g(6) = 6. Our expression becomes:
-1 * 4 + 7 * 6
= -4 + 42
= 38
Find the midline for f(x)=2cos(3x−5π6)−2
Answer: y = -2
Step-by-step explanation:
f(x) = A cos (Bx - C) + D
↓
center line (aka midline)
f(x) = 2 cos (3x - 5π/6) - 2
↓
midline = -2
The midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D
What is cos function?It is defined as a function that is sin-cos wave in nature, and it has a domain of all real numbers and lies between the [a, a] where is the amplitude of the function.
It is given that the cos function is:
f(x) = 2cos(3x - 5π/6) - 2
As we know, the standard form of the cos function is:
f(x) = Acos(Bx - C) + D
Here, A is the amplitude
B is the period of the cos function
C is the phase shift of the cos function
D is the vertical shift of the cos function/midline
On comparing:
D = -2
The midline:
y = -2
Thus, the midline of the cos function f(x) = 2cos(3x − 5π/6) − 2 is y = -2 after comparing with standard cos function f(x) = Acos(Bx - C) + D
Learn more about the cos function here:
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Please help me.. T-T
Step-by-step explanation:
The inequality is [tex]\frac{x}{-3}[/tex] >2
[tex]\frac{x}{-3}[/tex] > 2 multiply each side by -3 x < 2*(-3) the sign is switched since we multiplied by a negative number x < -6x is less than -6 and -6 is excluded so it will be represented by an empty circle and a line going toward negative values
so it's D
What is 1/9 of 63% of 6000?
Answer:
420
Step-by-step explanation:
To find 63% of 6000, we can do 0.63 * 6000 = 3780 because 63% = 0.63.
1/9th of that is 1/9 * 3780 = 420.
Answer:
420
Step-by-step explanation:
Let's first start by finding 63% of 6000 so we can later find 1/9 of that number.
We can set up a percentage proportion.
[tex]\frac{x}{6000} = \frac{63}{100}[/tex]
[tex]6000\cdot63=378000\\378000\div100 = 3780[/tex]
Now to find 1/9 of 3780.
[tex]\frac{1}{9} \cdot \frac{3780}{1}\\\\\frac{3780}{9} = 420[/tex]
So, the answer is 420.
Hope this helped!
There are 25 students in Mr. Jones’ art class. Mr. Jones is planning a project where each student needs 0.3 jar of paint. Exactly how much paint does Mr. Jones need for the art project?
Answer:
7.5 jars
Step-by-step explanation:
There are 25 students in the art class.
Mr Jones is planning that for the project, each of the 25 students will need 0.3 jar of paint.
The amount of paint Mr Jones needs for this project is therefore the product of the number of students in the class by the amount of paint each student needs.
That is:
25 * 0.3 = 7.5 jars of paint
Mr Jones needs 7.5 jars of paint for the art project.
Ami buys x apples and y bananas. The apples cost 15p each and the bananas cost 20p each. The total cost of Ami's apples and bananas is £1.80. a Write an equation for the total cost of Ami's apples and bananas.
Answer:
0.15x + 0.20y = 1.80
Step-by-step explanation:
Here, we are interested in writing an equation for the total cost of the apples and bananas
before we write , kindly understand that 100p = £1
So the cost of apple which is 15p will be 15/100 =£ 0.15
The cost of bananas which is 20p will be 20/100 = £0.2
Thus, the total cost of the apples bought will be number of apples bought * price of apple bought = 0.15 * x = £0.15x
The cost of bananas = number of bananas bought * price of bananas = 0.2 * y = £0.2y
So the total cost of the apples and bananas will be;
0.15x + 0.20y = 1.80
Find the value of x in the
following parallelogram:
2x - 10
2x + 50
Answer:
The value of x is 35
Step-by-step explanation:
In order to calculate the value of x in the following parallelogram: 2x - 10
2x + 50, we would have to calculate the following formula:
m<QPS+m<PQR=180°
According to the given data we have the following:
m<QPS=2x - 10
m<PQR=2x + 50
Therefore, 2x - 10+2x + 50=180
4x+40=180
x=140/4
x=35
The first three steps in determining the solution set of the system of equations algebraically are shown.
y = x2 − x − 3
y = −3x + 5
What are the solutions of this system of equations?
(−2, −1) and (4, 17)
(−2, 11) and (4, −7)
(2, −1) and (−4, 17)
(2, 11) and (−4, −7)
Answer:
(2, −1) and (−4, 17)
Step-by-step explanation:
I used a graphing tool to graph the systems of equations. The parabola and line pass at points (2, -1) and (-4, 17).
Answer:(2, −1) and (−4, 17) Its C on Edge 2023
Step-by-step explanation: Its (C) after an extensive research
Given the coordinate points of the preimage, use the transformation given to provide the points of the image. E(−5,−1) D(−5,1) C(−1,0) B(−2,−3) Rotation: 180∘ about the origin
Answer:
The points of the image are;
E'(5, 1), D'(5, -1), C'(1, 0), E'(-2, -3)
Step-by-step explanation:
The coordinates of the preimage are E(-5, -1) D(-5, 1) C(-1, 0) B(-2, -3)
Rotation of a point 180° about the origin gives;
Coordinates of the point of the preimage before rotation = (x, y)
The coordinates of the image after rotation = (-x, -y)
Therefore, the coordinates of the points EDCB after 180° rotation about the origin are;
E(-5, -1) rotated 180° becomes E'(5, 1)
D(-5, 1) rotated 180° becomes D'(5, -1)
C(-1, 0) rotated 180° becomes C'(1, 0)
B(-2, -3) rotated 180° becomes E'(-2, -3).
What are the square roots of; (note: i think there are supposed to be 2 each) 36 12 1.96 0.64 400 25/36
Answer:
36 : 6 and -6
12 = [tex]2\sqrt{3} , -2\sqrt{3}[/tex]
1.96 =1.4 and -1.4
0.64 : 0.8 and -0.8
400 : 20 and -20
25/36 = 5/6 and -5/6
Step-by-step explanation:
we know that
(-x)^2 = x^2
ALSO
(x)^2 = x^2
thus, square of both negative and positive number is same positive number.
_________________________________________________
36 = 6*6
36 = -6*-6
hence
square roots of 36 is both -6 and 6
12 = 4*3 = [tex]2^2*\sqrt{3} *\sqrt{3}[/tex]
[tex]\sqrt{12} = 2\sqrt{3}[/tex]
also
12 = [tex]-2\sqrt{3} *-2\sqrt{3}[/tex]
[tex]\sqrt{12} = -2\sqrt{3}[/tex]
___________________________________
1.96 = 196/100 = (14/10)^2
1.96 = 196/100 = (-14/10)^2
hence
[tex]\sqrt{1.96} = 14/10 \ or -14/10[/tex]
_______________________________
0.64 = 64/100 = (8/10)^2 = 0.8^2
0.64 = 64/100 = (-8/10)^2 = (-0.8)^2
Thus, square root of 0.64 = 0.8 and -0.8
_________________________________
400 = 20^2
400 = (-20)^2
[tex]\sqrt{400} = 20\\\sqrt{400} = -20\\[/tex]
__________________________________
25/36 = (5/6)^2
25/36 = (-5/6)^2
[tex]\sqrt{ 25/36} = 5/6 \\\sqrt{ 25/36} = (-5/6[/tex]
Write an equation of the line that passes through the point (–4, 6) with slope –4.
Answer:
y = - 4x - 10
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Here m = - 4 , thus
y = - 4x + c ← is the partial equation
To find c substitute (- 4, 6) into the partial equation
6 = 16 + c ⇒ c = 6 - 16 = - 10
y = - 4x - 10 ← equation of line
Answer:
y = -4x+10
Step-by-step explanation:
Using the slope intercept form of a line
y = mx+b where m is the slope and b is the y intercept
y = -4x +b
Substituting the point in
6 = -4(-4) + b
6 = 16+b
Subtract 16 from each side
-10 =b
The equation is
y = -4x+10
Sketch the graph of y=-3(x-3)2+4 and identify the axis of symmetry.
Answer:
The axis of symmetry of parabola is the equation where it cuts the middle of the graph.
So the axis of symmetry is x = 2 .