5w-8/3 =4w+2
Please solve with steps

It clearly states to use mental math not brainly, sorry bro can't do anything for you

Answer:

2. Isosceles

4. 25, 65, 90

Step-by-step explanation:

Isosceles triangles have two equivalent sides

All the interior angles of triangles always add up to 180 degrees

Answer:

slope = 20

Step-by-step explanation:

Calculate the slope m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (10, 200) ← 2 points on the line

m = [tex]\frac{200-0}{10-0}[/tex] = [tex]\frac{200}{10}[/tex] = 20

Answer:

a

Step-by-step explanation:

Answer:

a

Step-by-step explanation:

Answer:

x = 11.25

Step-by-step explanation:

The sum of the angles is 90 degrees since it is a right angle

6x+2x = 90

8x = 90

Divide each side by 8

8x/8 =90/8

x =11.25

Answer:

Yes, he has enough pieces to wrap the present

Step-by-step explanation:

Given

[tex]Presents = 7[/tex]

[tex]Cuts = 6[/tex]

Required

Is there enough pieces to wrap all presents

As a general rule;

When a piece is cut in 1 place, you get 2 pieces

When a piece is cut in 2 places, you get 3 pieces

When a piece is cut in 3 place, you get 4 pieces

This implies that:

n cuts gives n + 1 pieces

i.e.

[tex]n \to n + 1[/tex]

So, we have:

[tex]6\ cuts \to (6 + 1) pieces[/tex]

[tex]6\ cuts \to 7\ pieces[/tex]

Hence, there are enough pieces.

Answer:

-0.25n + 1

Step-by-step explanation:

Difference between all numbers: -0.25

Hence,

[tex]t_n = -0.25n + 1[/tex]

Feel free to mark it as brainliest :D

Answer: 13/4

Step-by-step explanation: it was 3.25 and that as a fraction is 13/4

3/4 + ( 1/3 × 6 ) + 1/2 =

3/4 + 2/4 + ( 2 ) =

3 + 2/4 + 8/4 =

5/4 + 8/4 =

5 + 8/4 =

13/4

Answer:

1 1/3 mph

Step-by-step explanation:

distance = rate x time

5 = 3.75r

5/3.75 = r

r = 1 1/3 mph

Answer:

Something you do frequently or on a regular basis is known as a habit.

When he gets nervous, he has a cute habit of licking his lips. [includes]

...an investigation into the eating habits of people in the United Kingdom.

Step-by-step explanation:

Answer:

627square inches

Step-by-step explanation:

Area of the composite figure.. = area of triangle + area of parallelogram

Since the triangle is an equilateral triangle;

Area of the triangle = r²sintheta

Area of the triangle = 18²sin60

Area of the triangle = 324sin60

Area of the triangle  = 324(0.8860)

Area of the triangle = 280.584 square in

Area of the triangle = 281 square inches

Area of parallelogram = absintheta

Area of parallelogram = 20(20)sin60

Area of parallelogram = 400(0.8660)

Area of parallelogram = 346.4square inches

Area of parallelogram = 346 square inches

Area of the figure = 346  + 281

Area of the figure  = 627square inches

Answer:

C, -7+12

Step-by-step explanation:

-7--12= 5

-7--12 can also be -7+12

Answer:

The answer is c

Step-by-step explanation:

-7-(-12) = 5

Answer:

A) 140

B) 75

C) 80

D) 20

E) 80

Step-by-step explanation:

Para resolver este problema debemos construir un diabrama de Venn y llenarlo según los datos que se nos brindan.

Comenzamos nombrando cada círculo:

E= personas que usan máquinas eléctricas

M= personas que usan máquinas mecánicas

C = personas que usan computadoras.

- Luego llenamos el área central con un 20, el cual representa las personas que usan los 3 tipos de maquinas.

- En la parte exterior del diagrama de Venn colocamos un 60 por las personas que no usan ninguna de las máquinas.

- En la intersección entre M y C restamos:

25-20=5

Entonces colocamos este 5 en esa región.

- En la intersección entre E y C restamos:

35-20=15

Entonces colocamos este 15 en esa región.

- En la intersección entre E y M restamos:

40-20=20

Entonces colocamos este 20 en esa región.

- En la región de E restamos:

110-20-20-15=55

Entonces colocamos este 55 en esa región.

- En la región de M restamos:

50-20-20-5=5

Entonces colocamos este 5 en esa región.

- En la región de C restamos:

60-15-20-5=20

Entonces colocamos este 20 en esa región.

Y obtenemos el diagrama de Venn que representa esta encuesta (Ver figura adjunta)

Y ahora ya lo podemos usar para responder a las preguntas:

A) Número de personas que no usan computadora. Sumamos los números fuera del círculo C:

55+20+5+60=140

B) Número de personas que usan una máquina eléctrica pero no computadora: Sumamos los números dentro del círculo E con excepción de los números compartidos por el círculo C y obtenemos:

55+20=75

C) Número de personas que usan solo un equipo: Sumamos los números no compartidos en los círculos E, M y C

55+20+5=80

D) Número de personas que usan máquina mecánica y eléctrica pero no computadora: Usamos el número compartido entre E y M que no son compartidos con C

20

E) Sumamos el número que se encuentra solo en C y los que están afuera del diagrama:

20´60=80

Answer:

..........

Step-by-step explanation:

Given:

The height of the ladder = 15 m

When the ladder leans at point B from the ground level, then it makes an angle  of 52° with the horizontal

When the ladder leans at point A from the ground level, then it makes an angle  of 85° with the horizontal

To find:

The distance between point A and point B is?

Solution:

To solve the above-given problem, we will use the following trigonometric ratio of a triangle:

Referring to the figure attached below, we will assume,

BD = AD = 15 m = height of the ladder

∠BDC = 52° = angle of elevation to the foot of the window

∠ADC = 85° = angle of elevation to the top of the window

Now,

In ΔBCD, we have

Opposite side = BC

Hypotenuse = BD = 15 m

θ = 52°

∴

and

In ΔACD, we have

Opposite side = AC

Hypotenuse = AD = 15 m

θ = 85°

∴

∴ The height of the window, AB = AC - BC = 14.94 m - 11.82 m = 3.12 m

Thus, the distance between point A and point B is 3.12 m.

-----------------------------------------------------------------------------------------------

Also View:

A ladder leaning against a wall makes an angle of 60 degree with the horizontal If the foot of the ladder is 2.5 m away from the wall , find the length of the ladder.

Answer:

7

Step-by-step explanation:

you divide 140 by 20 & it gives you 7 i hope this helps ..

Answer:

Rs.27000

Step-by-step explanation:

60000 ÷ 2 = 30000 per year

30000 × [tex]\frac{10}{100}[/tex] = Rs. 3000

30000 - 3000 = Rs. 27000

Answer:

6,500,000

Step-by-step explanation:

Here, we first need to find all the possible selections for the code.

Then, we need to find the number of options for each one of these selections.

We have, 2 letters followed by 4 single digits.

There are 26 letters

There are 10 single digits.

For the first letter, we have 26 options.

For the second letter, we have 25 options (because one is already taken, and we can repeat that)

And for each one of the numbers, we have 10 options (we can repeat the numbers)

The total number of options for the code, is equal to the product of all the numbers of options for each selection, then the total number of possible plate numbers is:

C = 26*25*10*10*10*10 = 6,500,000

Answer:3

Step-by-step explanation:

3-6*12

[tex]\huge\text{Hey there!}[/tex]

[tex]\large\textsf{2h - 3 }\mathsf{>}\large\textsf{ 15}[/tex]

[tex]\large\text{ADD 3 to BOTH SIDES}[/tex]

[tex]\large\textsf{2h - 3 + 3 }>\large\textsf{ 15 + 3}[/tex]

[tex]\large\text{CANCEL out: \textsf{-3 + 3} because that gives you 0}[/tex]

[tex]\large\text{KEEP: \textsf{15 + 3} because it helps you solve for your h-value}[/tex]

[tex]\large\textsf{15 + 3 = \boxed{\large\textsf{\bf 18}}}[/tex]

[tex]\large\text{NEW EQUATION: \textsf{2h} }\mathsf{>}\large\textsf{ 18}[/tex]

[tex]\large\text{DIVIDE 2 to BOTH SIDES}[/tex]

[tex]\mathsf{\dfrac{2h}{2}>\dfrac{18}{2}}[/tex]

[tex]\large\text{CANCEL out: }\mathsf{\dfrac{2}{2}}\large\text{ because it gives you 1}[/tex]

[tex]\large\text{KEEP: }\mathsf{\dfrac{18}{2}}\large\text{ because it gives you your h-value is being compared to}[/tex]

[tex]\large\text{NEW EQUATION: }\mathsf{h > \dfrac{18}{2}}[/tex]

[tex]\mathsf{\dfrac{18}{2}}[/tex]

[tex]\mathsf{= 18\div 2}[/tex]

[tex]=\boxed{\mathsf{\large\textsf {\bf 9}}}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: }\mathsf{\bf h > 9}}}\huge\checkmark\\\\\boxed{\boxed{\rm \bf It\ it\ an\ O P E N E D\ circle\ shaded}}\\\boxed{\boxed{\rm \bf to\ the\ right\ starting\ at\ point\ 9}}\checkmark[/tex]

[tex]\large\text{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

[tex] \quad \quad \quad \quad\tt{2h - 3 > 15}[/tex]

[tex] \quad \quad \quad \quad\tt{2h - 3 + 3 > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h \: \: \cancel{ \color{red}- 3 + 3} \: > 15 + 3}[/tex]

[tex]\quad \quad \quad \quad\tt{2h > 18}[/tex]

[tex]\quad \quad \quad \quad\tt{ \frac{2h}{2} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ \frac{ \cancel{ \color{red}2}h}{ \cancel{ \color{red}2}} > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > \frac{18}{2} }[/tex]

[tex]\quad \quad \quad \quad\tt{ h > 9}[/tex]

[tex]\quad \quad \quad \quad \boxed{\tt { \color{green}h > 9}}[/tex]

________

#LetsStudy

Answer:

18 cm

Step-by-step explanation:

Let X represent a square

For it to be a rectangle, needs to be:

X X X

X X X

X X X

(It's a giant square made of squares)

This works since a square is a rectangle, but a rectangle isn't always a square. No other arrangement of the squares lead to a rectangle.

For Example:

X X X X

X X X X X

It doesn't work because there is an odd number of squares, and only would work if it was a multiple of 3,5,7 etc.. and 3 is the only number that fits.

So if the length is 18cm, the width is also 18cm.

Answer:

n geometry, the notion of a connection makes precise the idea of transporting data[further explanation needed] along a curve or family of curves in a parallel and consistent manner. There are various kinds of connections in modern geometry, depending on what sort of data one wants to transport. For instance, an affine connection, the most elementary type of connection, gives a means for parallel transport of tangent vectors on a manifold from one point to another along a curve. An affine connection is typically given in the form of a covariant derivative, which gives a means for taking directional derivatives of vector fields, measuring the deviation of a vector field from being parallel in a given direction.

Connections are of central importance in modern geometry in large part because they allow a comparison between the local geometry at one point and the local geometry at another point. Differential geometry embraces several variations on the connection theme, which fall into two major groups: the infinitesimal and the local theory. The local theory concerns itself primarily with notions of parallel transport and holonomy. The infinitesimal theory concerns itself with the differentiation of geometric data. Thus a covariant derivative is a way of specifying a derivative of a vector field along another vector field on a manifold. A Cartan connection is a way of formulating some aspects of connection theory using differential forms and Lie groups. An Ehresmann connection is a connection in a fibre bundle or a principal bundle by specifying the allowed directions of motion of the field. A Koszul connection is a connection which defines directional derivative for sections of a vector bundle more general than the tangent bundle.

Connections also lead to convenient formulations of geometric invariants, such as the curvature (see also curvature tensor and curvature form), and torsion tensor.

Step-by-step explanation:

Answer:

n geometry, the notion of a connection makes precise the idea of transporting data[further explanation needed] along a curve or family of curves in a parallel and consistent manner. There are various kinds of connections in modern geometry, depending on what sort of data one wants to transport. For instance, an affine connection, the most elementary type of connection, gives a means for parallel transport of tangent vectors on a manifold from one point to another along a curve. An affine connection is typically given in the form of a covariant derivative, which gives a means for taking directional derivatives of vector fields, measuring the deviation of a vector field from being parallel in a given direction.

Connections are of central importance in modern geometry in large part because they allow a comparison between the local geometry at one point and the local geometry at another point. Differential geometry embraces several variations on the connection theme, which fall into two major groups: the infinitesimal and the local theory. The local theory concerns itself primarily with notions of parallel transport and holonomy. The infinitesimal theory concerns itself with the differentiation of geometric data. Thus a covariant derivative is a way of specifying a derivative of a vector field along another vector field on a manifold. A Cartan connection is a way of formulating some aspects of connection theory using differential forms and Lie groups. An Ehresmann connection is a connection in a fibre bundle or a principal bundle by specifying the allowed directions of motion of the field. A Koszul connection is a connection which defines directional derivative for sections of a vector bundle more general than the tangent bundle.

Connections also lead to convenient formulations of geometric invariants, such as the curvature (see also curvature tensor and curvature form), and torsion tensor.

Step-by-step explanation:

Answer:

x=6, y=5 1/3 or 5.3333

Step-by-step explanation:

Answer:

c) The standard form of the quadratic equation, y = a·x² + b·x + c

The standard form of the quadratic equation is y =  3·x² - 18·x - 48.

Step-by-step explanation:

Answer:

659.4 inches

Step-by-step explanation:

C = 2*3.14*21

C = 131.88

131.88*5 = 659.4 inches

Answer:

y = 50x + 150

Step-by-step explanation:

The y-intercept is 150. b = 150

The slope is found using two points such as (2014, 450) and (2010, 250)

m = (450 - 250)/(2014 - 2010) = 200/4 = 50

y = mx + b

y = 50x + 150

Answer:

Step-by-step explanation:

Is their suppposed to be a pic