6 time the complement of an
angle is 44° less than 2 times its supplement. Find all angles

The value of the constant of variation is 130

Constant of variation can be defined as the ratio between two variables in  an inverse variation on a direct variation.

From the information given, we have that;

The number of hours is x

The temperature is y

x α 1/ y

x = k/y

k = xy

Substitute the values

k = 2 × 65

k= 130

Thus, the value of the constant of variation is 130

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The complete question:

the number of hours it takes for a block of ice to melt varies inversely as the temperature. If it takes 2 hours for a square inch of ice to melt at 65 degrees find the constant of variation

Answer:

B. 6x²-7x-20

Step-by-step explanation:

(2x-5)(3x+4)

2x(3x+4)-5(3x+4)

Use distributive property.

6x²+8x-15x-20

Combine like terms.

6x²-7x-20

Hope this helps!

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By unitary method we can say that number of stacks of papers Lashona will pass back  from 140 if each stack conatins 28 papers is 5.

According to the given question.

Total number of papers Lashonna passed back = 140

And one stack is made up of 28 papers.

As we know that, the unitary method is a technique for solving a problem by first finding the value of a single unit, and then finding the necessary value by multiplying the single unit value.

Therefore,

By unitary method number of stacks of papers would be made from 140 if each stack conatins 28 papers

= 140/28

= 5

Hence, by unitary method we can say that number of stacks of papers Lashona will pass back  from 140 if each stack conatins 28 papers is 5.

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The angles of the given triangle are 136°,24°, and 20°.

Given that a triangle has angles as  4y°,(y-10)°, and 20° and asked to find out the angles of the given triangle

The sum of the angles of the triangle =180°

⇒4y°+(y-10)° + 20°=180° { adding the given angles and equating it to 180° as the sum of the angles in the triangle is 180°}

⇒5y+10=180°.{added all the given angles and equated it to 180°}

⇒5y=170°

⇒y=34°

⇒4y=136°, (y-10)°=24° and 20°

Therefore the angles of the given triangle are  136°,24°, and 20°.

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Answer:

AP = 29,37,45,...

d= t2-t1

=37-29

=8

n=59

t59=?

tn=a+(n-1)d

t59=29+(59-1)8

t59=28+58×8

t59=28 + 464

t59=492

Step-by-step explanation:

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The two numbers by setting up a linear equation are 56 and 32

Linear equations are equations that have constant average rates of change.

Note that the constant average rates of change can also be regarded as the slope or the gradient

Let the two numbers be x and y

Where

y = 4 + 1/2x

So, we have

x + y = 88

Substitute y = 4 + 1/2x in x + y = 88

x + 4 + 1/2x = 88

Evaluate

1.5x = 84

Divide by 1.5

x = 56

Substitute x = 56 in y = 4 + 1/2x

y = 4 + 1/2 * 56

Evaluate

y = 32

Hence, the two numbers by setting up a linear equation are 56 and 32

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Answer:

ssdf

Step-by-step explanation:

dbd beddbees sveveusbs wie eje edidjebebe djebejdjebe ejd s

Answer:

It's rational, because it can be converted into a reasonable fraction.

➯ Hope this helps!

Answer:

137 ≤ 15x +

Step-by-step explanation:

The value of x is -(11/7).

This problem is related to solving an algebraic equation.

In algebra there are many types of equations such as linear equation in one variable and two variable.

Here we have been given two variables and two equations which means we can solve the equation. To solve an equation in algebra it is important that the number of unknowns is equal to the number of equations given.

Given, m/1=2x+3 i.e., m=2x+3

also m/2=3x+7 i.e., m=6x+14

Now equating both the values of m;

  2x+3=6x+14

⇒6x-2x=3-14

⇒4x=-11

∴ x= -(11/4)

Hence, the value of x is -11/4.

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Answer: 3 gallons of gas left

Step-by-step explanation: since the car started out with 15 1/5 and then fills up 5 3/5 now there is 20 4/5 in the car then since the car consumed 17 4/5 just subtract the 17 4/5 from 20 4/5 and then you get 3 gallons left since 17 - 20 = 3 and 4/5 - 4/5 = 0/0 or 0 the answer is just 3 gallons left

Answer: it is 3 gallons

Step-by-step explanation:

a)

Solution,

Given,

Cost for 1 pen = $ 1.50

= 1.50×100 cents

= 150 cents

Cost for 1 ruler = 80 cents

No. of Pens needed to be bought = x

No. of rulers needed to be bought = x+10

Now,

Cost for x pens = x×150 cents

= 150x cents

Cost for (x+10) rulers = (x+10)×80 cents

= 80x cents+800 cents

Then,

Total cost = 150x cents+(80x cents+800 cents)

= 150x cents+80x cents+800 cents

= 230x cents+800 cents

= $(230x ÷ 100)+$(800 ÷ 100)

= $2.3x + $8

Therefore,Louise spent $2.3x and $8 as total amount

b)

Sorry,I dont know inequality

The data measured on ordinal scale exhibits all the properties of data measured on nominal scale.

A nominal scale  can be described as the scale of measurement  which is been assign events or objects with respect to a discrete categories.

However in relation with nominal scale, Ordinal scale  serves as the  2nd level of measurement  which help to give the reports of  ranking as well as  ordering of the data  however the  degree of variation  is not usually considered, hence data measured on ordinal scale exhibits all the properties of data measured on nominal scale.

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Usando la propiedad exponencial, hay que el resultado es: 125/64.

Con el expoente negativo, hay que:

[tex]\left(\frac{a}{b}\right)^{-x} = \left(\frac{b}{a}\right)^{x}[/tex]

Así, la expresion equivalente es dada por:

[tex]\left(\frac{16}{25}\right)^{-\frac{3}{2}} = \left(\frac{25}{16}\right)^{\frac{3}{2}}[/tex]

Hay que 25 = 5² y 16 = 4², así:

[tex]\left(\frac{25}{16}\right)^{\frac{3}{2}} = \left(\frac{5^2}{4^2}\right)^{\frac{3}{2}} = \left(\frac{5}{4}\right)^3 = \frac{125}{64}[/tex]

Así, hay que el resultado es: 125/64.

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The first-order differential equation is non-separable and non-linear.

[tex]\frac{dx}{dy} +e^{x} y=x^{2} y^{2}[/tex]

[tex]\frac{1}{y^{2} } \frac{dx}{dy} +e^{x} \frac{1}{y} =x^{2}[/tex]

[tex]\frac{dt}{dx} -e^{x} t = -x^{2}[/tex]

Since, x and y terms separated also linear equation

linear and separable both

[tex]\frac{dy}{dx} = cos y = tan x[/tex]

non-linear and non-separable

What distinguishes a linear equation from a non-linear equation?

Something that is linear is related to a line. A line is built using all of the linear equations. A non-linear equation is one that cannot be represented by a straight line.  It has a changeable slope value and resembles a graphed curve.

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[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-9}~,~\stackrel{y_1}{4})\qquad B(\stackrel{x_2}{7}~,~\stackrel{y_2}{4}) ~\hfill AB=\sqrt{(~~ 7- (-9)~~)^2 + (~~ 4- 4~~)^2} \\\\\\ ~\hfill AB=\sqrt{( 16)^2 + ( 0)^2}\implies \boxed{AB=16} \\\\\\ B(\stackrel{x_1}{7}~,~\stackrel{y_1}{4})\qquad C(\stackrel{x_2}{7}~,~\stackrel{y_2}{-8}) ~\hfill BC=\sqrt{(~~ 7- 7~~)^2 + (~~ -8- 4~~)^2}[/tex]

[tex]~\hfill BC=\sqrt{( 0)^2 + ( -12)^2}\implies \boxed{BC=12} \\\\\\ C(\stackrel{x_1}{7}~,~\stackrel{y_1}{-8})\qquad A(\stackrel{x_2}{-9}~,~\stackrel{y_2}{4}) ~\hfill CA=\sqrt{(~~ -9- 7~~)^2 + (~~ 4- (-8)~~)^2} \\\\\\ ~\hfill CA=\sqrt{( -16)^2 + (12)^2}\implies CA=\sqrt{400}\implies \boxed{CA=20} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{Perimeter}{16~~ + ~~12~~ + ~~20\implies \text{\LARGE 48}}[/tex]

The probability that:

Probability refers to the possibility of the occurrence of an event.

P(E) = probability of occurrence of an event E = [tex]\frac{Number Of Favourable Outcomes}{Total Number Of Outcomes}[/tex]

Now,

(a) Total number of books = 5 + 3 + 1 = 9

Probability of getting a dictionary = [tex]\frac{1}{9}[/tex]

(b) Number of ways to select 3 books out of 9 books = [tex]\binom{9}{3}[/tex] =  [tex]\frac{9!}{3!(6!)} = \frac{9\times\ 8 \times 7}{6}[/tex] = 84

Number of ways to select 1 out of 3 books of poems = [tex]\binom{3}{1} = \frac{3!}{2!}[/tex] = 3

Number of ways to select 2 out of 5 novels = [tex]\binom{5}{2} = \frac{5!}{2! 3!} = \frac{5\times 4}{2} = 10[/tex]

Thus, the probability of getting 2 novels and 1 book of poem = [tex]\frac{3\times10}{84} = \frac{10}{28} = \frac{5}{14}[/tex]

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(COMPLETE QUESTION:

If three books are picked at random from a shelf containing 5 novels, 3 books of poems, and a dictionary, what is the probability that (a) a dictionary is selected? (b) 2 novels and 1 book of poems are selected?)

Statistics expert daniel yankelovich believes that middle-class values give Americans a certain amount of self-esteem and a fairly clear idea of who they are.

This is the title that is used to refer to the people that have being trained in such a way that they are able  to apply statistical approaches and methods to the real life problems that exists in the environment.

They are known to be able to get the solutions to problems by the use of models of statistics and analyzing them as well.

Hence we can say that Statistics expert daniel yankelovich believes that middle-class values give Americans a certain amount of self-esteem and a fairly clear idea of who they are

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Answer:

Step-by-step explanation:

jeans           $42.95

sweater    + $36.99

total          = $69.94

tax             + 5% ($3.497 round to nearest hundredth ($3.50))

total with tax = 73.44

hope this helped!!!! let me know if you need anymore help with this :) have a good day!

Answer:

x can be -3, or +3

Step-by-step explanation:

The equation would be

5[tex]x^{2}[/tex] = 45

Divide both sides by 5

[tex]x^{2}[/tex] = 9

Take the square root of both sides

x = ± 3

Answer: x= 33

Step-by-step explanation: hope this helps!!!

The triangle formed by the feet of angle bisectors of a triangle with a single angle measure of 120° is the Right Triangle.

So,

In triangle ABC, ∠A = 120°.

As a result, DE is the exterior angle bisector of ABCD.

Similarly, for the ABC, F is ex-center because AB is the exterior angle bisector and CF is the interior angle bisector.

As a result, DF is the exterior angle bisector.

BC is a straight line.

So, DEF is the right triangle.

As a result, the triangle formed by the feet of angle bisectors of a triangle with a single angle measure of 120° is the Right Triangle.

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The correct form of the question is given below:
Prove in any ΔABC, if one angle is 120°, the Δ formed by the feet of the angle bisectors is right-angled.

Harry's speed on the freeway is 67 miles per hour

Time Harry drove on freeway = 3 hours

Time Harry drove on country road = 6 hours

Total distance covered by him = 483 miles

Let his speed be x miles per hour

Formula to be used:

Speed*Time = Distance

Therefore, the distance covered by him on the freeway  = 3x -----(1)

Distance covered by him on country road = 6(x - 20)------(2)

Formulating the equations using (1) and (2)

3x + 6(x-20) = 483

3x + 6x - 120 = 483

9x = 603

x = 67 miles per hour

So, his speed on the freeway is 67 miles per hour and on the country road it is 47 miles per hour

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Answer: BABABAB

Step-by-step explanation:

BHBAHBABAHBABHABHBAHBABHABHBAbhaBHBA

Answer:

-1 yard per play

play 6 - play 3=0

play 2 - play 4=0

play 1 - play 5 = -6

hope it helped

First of all, every number in each row is odd, so we can eliminate 392 and 394.

The number of elements in each row forms an arithmetic sequence:

• 1st row : 1 element

• 2nd row : 3 elements - and 3 - 1 = 2

• 3rd row : 5 elements - and 5 - 3 = 2

• 4th row : 7 elements - and 7 - 5 = 2

and so on, so that the [tex]n[/tex]-th row has [tex]1 + 2(n-1) = 2n - 1[/tex] elements.

This means that in [tex]n-1[/tex] complete rows, there is a total of

[tex]\displaystyle \sum_{i=1}^{n-1} (2i-1) = n^2 - 2n + 1[/tex]

elements, so that the first element in the subsequent [tex]n[/tex]-th row is the [tex](n^2-2n+2)[/tex]-th number in the sequence {1, 3, 5, 7, …}, i.e the [tex](n^2-2n+2)[/tex]-th odd positive integer. To compute the sum, I use the following well-known formulas.

[tex]\displaystyle \sum_{i=1}^n 1 = n[/tex]

[tex]\displaystyle \sum_{i=1}^n i = \frac{n(n+1)}2[/tex]

Now, the [tex]n[/tex]-th term of the sequence {1, 3, 5, 7, …} is simply [tex]2n-1[/tex], the [tex]n[/tex]-th odd positive integer. So the first element in the [tex]n[/tex]-th row is

[tex]2(n^2-2n+2) - 1 = 2n^2 - 4n + 3[/tex]

and hence the 1st element of the 15th row is

[tex]2\cdot15^2 - 4\cdot15 + 3 = \boxed{393}[/tex]

The value of the numbers given will be:

1. 108

2. 1618

1. The expression given will be calculated as:

= 97.83 - 4.378 + 5.92

= 98 + 4 + 6

= 108

2. 1,342.8+ 85.32 + 173.54 + 16

= 1343 + 85 + 174 + 16

= 1618

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The dimensions of the playing field the width is 54 yards and the length is 210 yards.

Given that the perimeter of the rectangular playing field is 528 yards and the length of the field is 6 yards less than quadruple the width.

Let the width of the rectangular playing field is x yards and it is given that the length of the field is 6 yards less than quadruple the width means the length is 4x-6.

As we know that the perimeter of the rectangle is two times the sum of length and breadth so.

P=2(l+w)

As it is given that the perimeter is 528 yards.

So, we will substitute all the values in the formula, we get

528=2(4x-6+x)

528=2(5x-6)

528=10x-12

528+12=10x-12+12

540=10x

540/10=10x/10

54=x

Now, substitute this values in l=4x-6 to find the length, we get

l=4(54)-6

l=216-6

l=210

Hence, the dimension of the playing field when the perimeter of the rectangular playing field is 528 yards is width is 54 yards and length is 210 yards.

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[tex]Answer:\ -55.102^0F\leq t^0\leq 595.958^0F[/tex]

Step-by-step explanation:

[tex]\displaystyle\\C^0=\frac{5}{9} (F^0-32^0)\\[/tex]

Let's multiply both parts of the equation by 9/5:

[tex]\displaystyle\\\frac{9}{5} C^0=F^0-32^0\\\\\frac{9}{5} C^0+32^0=F^0-32^0+32^0\\\\\frac{9}{5} C^0+32^0=F^0\\\\Thus,\\\\F^0=1.8C^0+32^0[/tex]

[tex]t=-48.39^0C\\Hence,\\t^0(F)=1.8(-48.39^0)+32^0\\t^0(F)=-87.102^0+32^0\\t^0(F)=-55.102^0[/tex]

[tex]t=313,31^0C\\Hence,\\t^0(F)=1.8(313,31^0)+32^0\\t^0(F)=563.958^0+32^0\\t^0(F)=595.958^0[/tex]

[tex]Thus,\\-55.102^0F\leq t^0\leq 595.958^0F[/tex]

The Associative property is not  displayed by any of the given equations.

The associative property of several binary operations in mathematics states that the outcome will not change if the parenthesis in an expression are rearranged.

The order in which the operations are carried out within an expression that has two or more instances of the same associative operator in a row doesn't matter as long as the order of the operands is left untouched.

Examples of associative property :

[tex]{\displaystyle {\begin{aligned}(7+8)+1&=7+(8+1)=9\,\\5\times (3\times 7)&=(5\times 3)\times 7=24.\end{aligned}}}[/tex]

The parentheses were rearranged on each line, but the expression values were left alone. It can be argued that "addition and multiplication of real numbers are associative operations" because this is true for addition and multiplication of all real numbers.

Here 8=8+0 displays additive identity property.

10×1=10 displays multiplicative identity

5+0=5 displays displays additive identity property.

[tex]5\times \frac{1}{5}=1[/tex]  displays multiplicative inverse property.

[tex]3+\frac{3}{4} =3+\frac{3}{4}[/tex]  displays reflexive property.

Hence no equation displays associative property.

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