Answer:
d)9991.15
Step-by-step explanation:
We have a sum of money ($6000) compounded daily at an annual interest rate of 8.5% for 6 years.
If the interest is compound daily, and we take a m=365 days a year (or 365 subperiods m), the daily nominal interest rate is:
[tex]i_d=\dfrac{i}{m}=\dfrac{0.085}{365}=0.000232877[/tex]
Then, we can express the final valueo of $6000 compounded daily at an annual interest rate of 8.5% for 6 years as:
[tex]FV=IV\left(1+\dfrac{i}{m}\right)^{n\cdot m}\\\\\\FV=6000(1+0.000232877)^{6\cdot 365}\\\\FV=6000(1.000232877)^{2190}\\\\FV=6000\cdot1.665192322\\\\FV\approx9991.15[/tex]
If <10 and <15 are congruent, which lines are parallel? A.lines b and c B.lines c and d C.lines a and b D.No lines are parallel. - Refer to second picture. Given the information in the diagram, determine if M ll N If so, give the theorem or postulate used to support your conclusion. A.yes; converse of the consecutive interior angles theorem B.yes; converse of the alternate interior angles theorem C.yes; converse of the corresponding angles postulate D.no
Problem 1
Answer: C. lines a and bExplanation: Circle or highlight the angles 10 and 15. They are alternate interior angles with line d being the transversal cut. It might help to try to erase line c to picture the transversal line d better. With d as the transversal, and angles 10 and 15 congruent, this must mean lines a and b are parallel by the alternate interior angle theorem converse.
==============================================
Problem 2
Answer: D. noExplanation: The angles at the top are 32 degrees, 90 degrees, and x degrees which is the missing unmarked angle at the top (all three angles are below line m). The three angles must add to 180 to form a straight angle
32+90+x = 180
x+122 = 180
x = 180-122
x = 58
The missing angle is 58 degrees. This is very close to 57 degrees at the bottom. Though we do not have an exact match. This means lines m and n are not parallel. The alternate interior angles must be congruent for m and n to be parallel, as stated earlier in problem 1.
The Nutty Professor sells cashes for $6.00 per pound and Brazil nuts for $5.30 per pound. How much of
each type should be used to make a 35 pound mixture that sells for $5.64 per pound?
Answer:
17 pound of cashew and 18 pound of Brazil nutsStep-by-step explanation:
Let X be the amount of cashews that the nutty professor will mix.
Since, the total weight of the nuts should be 35 lbs
The amount of Brazil nuts = 35 - X
Now,
[tex]6x + 5.30(35 - x) = 5.64(35)[/tex]
[tex]600x + 530(35 - x) = 564 \times 35[/tex]
[tex]600x + 18550 - 530x = 19740[/tex]
[tex]70x = 19740 - 18550[/tex]
[tex]70x = 1190[/tex]
[tex]x = \frac{1190}{70} [/tex]
[tex]x = 17[/tex]
Again,
[tex] 35 - x[/tex]
[tex]35 - 17[/tex]
[tex]18[/tex]
17 pounds of cashew and 18 pounds of Brazil nuts.
Hope this helps...
Good luck on your assignment...
The figure shows eight congruent triangles made by dividing a square that has an area of 64 cm2. What is the area of ABH? A. 20 cm2 B. 16 cm2 C. 8 cm2 D. 6 cm2 E. 4 cm2
Answer:
the answer is C.
Step-by-step explanation:
64 ÷ 8 = 8
Answer:
c- 8cm squared
Step-by-step explanation:
plato
Rachel measured the lengths of a random sample of 100 screws. The mean length was 2.9 inches, and the population standard deviation is 0.1 inch. To see if the batch of screws has a significantly different mean length from 3 inches, what would the value of the z-test statistic be?
Answer:
z = 10
Step-by-step explanation:
The value of the z-statistic is given by:
[tex]z = \frac{X - \mu}{s}[/tex]
In which:
X is the measured value.
[tex]\mu[/tex] is the expected value.
[tex]s = \frac{\sigma}{\sqrt{n}}[/tex] is the standard deviation of the sample. [tex]\sigma[/tex] is the standard deviation of the population.
In this question:
The mean length was 2.9 inches, and the population standard deviation is 0.1 inch.
This means that [tex]\mu = 2.9, \sigma = 0.1[/tex]
Random sample of 100 screws.
This means that n = 100.
To see if the batch of screws has a significantly different mean length from 3 inches, what would the value of the z-test statistic be?
3 inches, so [tex]X = 3[/tex]
[tex]s = \frac{0.1}{\sqrt{100}} = 0.01[/tex]
[tex]z = \frac{X - \mu}{s}[/tex]
[tex]z = \frac{3 - 2.9}{0.01}[/tex]
[tex]z = 10[/tex]
Answer:
-10
Step-by-step explanation:
If we first note the denominator of fraction numerator sigma over denominator square root of n end fraction equals fraction numerator 0.1 over denominator square root of 100 end fraction equals fraction numerator begin display style 0.1 end style over denominator 10 end fraction equals 0.01
Then, getting the z-score we can note it is z equals fraction numerator x with bar on top minus mu over denominator begin display style 0.01 end style end fraction equals fraction numerator 2.9 minus 3 over denominator 0.01 end fraction equals negative 10
This tells us that 2.9 is 10 standard deviations below the value of 3, which is extremely far away.
If sin y° = a/6 and tan y° = a/b what is the value of sec y°
Answer:
[tex]sec\ y = \frac{6}{b}[/tex]
Step-by-step explanation:
Given
[tex]sin\ y = \frac{a}{6}[/tex]
[tex]tan\ y = \frac{a}{b}[/tex]
Required
sec y
From trigonometry;
[tex]sec\ \theta = tan\ \theta\ /\ sin\ \theta[/tex]
Substitute y for θ
[tex]sec\ y= tan\ y\ /\ sin\ y[/tex]
Substitute values for tan y and sin y
sec y = a/b ÷ a/6
[tex]sec\ y= \frac{a}{b} /\ \frac{a}{6}[/tex]
[tex]sec\ y= \frac{a}{b} *\ \frac{6}{a}[/tex]
[tex]sec\ y= \frac{6 * a}{a *b}[/tex]
[tex]sec\ y= \frac{6 a}{ab}[/tex]
Divide numerator and denominator by a
[tex]sec\ y= \frac{6}{b}[/tex]
Hence, the value of sec y is
[tex]sec\ y= \frac{6}{b}[/tex]
Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from B, a distance of about 456.2456.2 miles. A second flight option flies first to city C and then connects to A. The bearing from B to C is N2929degrees°E, and the bearing from B to A is N59.759.7degrees°E. The bearing from A to B is S59.759.7degrees°W, and the bearing from A to C is N78.978.9degrees°W. How many more frequent flyer miles will Adam receive if he takes the connecting flight rather than the direct flight? Adam would receive nothing more frequent flyer miles.
Answer:
105.6 miles
Step-by-step explanation:
The bearing from B to C is N29°EThe bearing from B to A is N59.7°E. The bearing from A to B is S59.7°WThe bearing from A to C is N78.9°W. Distance from A to B = 456.2 milesIn the diagram
The angle at B = 59.7°-29°=30.7°
The angle at A =180°-(78.9°+59.7°)=41.4°
Using the sum of angles in a triangle, Angle C = 107.9°
Applying the Law of Sines
[tex]\dfrac{b}{\sin B}=\dfrac{c}{\sin C}\\b=\dfrac{c}{\sin C} \times \sin B\\\\=\dfrac{456.2}{\sin 107.9^\circ} \times \sin 30.7^\circ\\\\AC=b=244.76$ miles[/tex]
Similarly
[tex]\dfrac{a}{\sin A}=\dfrac{c}{\sin C}\\a=\dfrac{c}{\sin C} \times \sin A\\\\=\dfrac{456.2}{\sin 107.9^\circ} \times \sin 41.4^\circ\\\\BC=a=317.04$ miles[/tex]
Therefore:
AC+BC=244.76+317.04 =561.8 miles
Difference
561.8 - 456.2 =105.6 miles
Therefore, Adam would receive 105.6 miles more frequent flyer miles.
Need help plz someone help me solved this problem! I will mark you as brainiest !
Answer:
see explanation
Step-by-step explanation:
Given
f(x) = 60 × [tex]16^{x}[/tex]
x = 1 → f(1) = 60 × 16 = 960 ← bacteria present after 1 day
x = 2 → f(2) = 60 × 16² = 15360 ← bacteria present after 2 days
x = 3 → f(3) = 60 × 16³ = 245760 ← bacteria present after 3 days
(01.03 MC) Find the value of the following expression.
Answer:
[tex]\frac{16}{9}[/tex].
Step-by-step explanation:
[tex](2^8*3^{-5}*6^0)^{-2}*(\frac{3^{-2}}{2^3})^4*2^{28}\\ (2^8*\frac{1}{3^5}*1)^{-2}*\frac{\frac{1}{3^8} }{\frac{2^{12}}{1} }*2^{28} \\ (\frac{2^8}{3^5})^{-2} * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{1}{\frac{2^8*2}{3^{5*2}} } * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{\frac{1}{1} }{\frac{2^{16}}{3^{10}} } * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{3^{10}}{2^{16}} * \frac{1}{2^8*3^{12}} *2^{28}\\ \frac{2^{28}}{2^{24}*3^2} = \frac{2^4}{3^2}=\frac{16}{9}[/tex]
While starting salaries have fallen for college graduates in many of the top hiring fields, there is some good news for business undergraduates with concentrations in accounting and finance (Bloomberg Businessweek, July 1, 2010). According to the National Association of Colleges and Employers’ Summer 2010 Salary Survey, accounting graduates commanded the second highest salary at $50,402, followed by finance graduates at $49,703. Let the standard deviation for accounting and finance graduates be $6,000 and $10,000, respectively.
a. What is the probability that 100 randomly selected accounting graduates will average more than $52,000 in salary?
b. What is the probability that 100 randomly selected finance graduates will average more than $52,000 in salary?
c. Comment on the above probabilities.
Answer:
Step-by-step explanation:
According to the central limit theorem, if independent random samples of size n are repeatedly taken from any population and n is large, the distribution of the sample means will approach a normal distribution. The size of n should be greater than or equal to 30. Given n = 100 for both scenarios, we would apply the formula,
z = (x - µ)/(σ/√n)
a) x is a random variable representing the salaries of accounting graduates. We want to determine P( x > 52000)
From the information given
µ = 50402
σ = 6000
z = (52000 - 50402)/(6000/√100) = 2.66
Looking at the normal distribution table, the probability corresponding to the z score is 0.9961
b) x is a random variable representing the salaries of finance graduates. We want to determine P(x > 52000)
From the information given
µ = 49703
σ = 10000
z = (52000 - 49703)/(10000/√100) = 2.3
Looking at the normal distribution table, the probability corresponding to the z score is 0.9893
c) The probabilities of either jobs paying that amount is high and very close.
A market research company conducted a survey to find the level of affluence in a city. They defined the category "affluence" for people earning $100,000 or more annually. Out of 267 persons who replied to their survey, 32 are considered affluent. What is the 95% confidence interval for this population proportion? Answer choices are rounded to the hundredths place
Answer:
A 95% confidence interval for this population proportion is [0.081, 0.159].
Step-by-step explanation:
We are given that a market research company conducted a survey to find the level of affluence in a city.
Out of 267 persons who replied to their survey, 32 are considered affluent.
Firstly, the pivotal quantity for finding the confidence interval for the population proportion is given by;
P.Q. = [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ~ N(0,1)
where, [tex]\hat p[/tex] = sample proportion of people who are considered affluent = [tex]\frac{32}{267}[/tex] = 0.12
n = sample of persons = 267
p = population proportion
Here for constructing a 95% confidence interval we have used One-sample z-test for proportions.
So, 95% confidence interval for the population proportion, p is ;
P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level
of significance are -1.96 & 1.96}
P(-1.96 < [tex]\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < 1.96) = 0.95
P( [tex]-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < [tex]{\hat p-p}[/tex] < [tex]1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95
P( [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] < p < [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ) = 0.95
95% confidence interval for p = [ [tex]\hat p-1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] , [tex]\hat p+1.96 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }[/tex] ]
= [ [tex]0.12-1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } }[/tex] , [tex]0.12+1.96 \times {\sqrt{\frac{0.12(1-0.12)}{267} } }[/tex] ]
= [0.081, 0.159]
Therefore, a 95% confidence interval for this population proportion is [0.081, 0.159].
Answer:
0.08 to 0.16
Step-by-step explanation:
Write an expression that is divisible by 7. Use it to find two three-digit numbers numbers divisible by 7.
Answer:
7x+7 is obviously divisible by 7.
put in any value high enough and you can find the two three digit numbers.
Step-by-step explanation:
Two three-digit numbers divisible by 7 are 98 and 105.
Two three-digit numbers divisible by 7 are 98 and 105.To create an expression that is divisible by 7, we can use the property that the difference between two numbers is divisible by 7 if the numbers themselves are divisible by 7.
Let's represent a three-digit number divisible by 7 as "7k" where k is an integer. To find two three-digit numbers divisible by 7, we can use the following expression:
7k - 7
For example, if we substitute k = 15, we get:
7(15) - 7 = 105 - 7 = 98
So, the first three-digit number divisible by 7 is 98.
Similarly, for the second three-digit number, let's substitute k = 16:
7(16) - 7 = 112 - 7 = 105
Therefore, the two three-digit numbers divisible by 7 are 98 and 105.
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Tublu buys a cylindrical water tank of height 1.4m and diameter 1.1m to catch rainwater off his roof. He has a full 2 litres tin of paint in his store and decides to paint the tank (not the base). If he uses 250 ml to cover 1 m2, will he have enough paint to cover the tank with one layer of paint? [take π=3.142]
Answer:
Tublu has more than enough paint to cover the tank surface in one layer coating
Step-by-step explanation:
Height of the cylinder = 1.4 m
diameter of the cylinder = 1.1 m
total volume of paint available = 2 litres
It takes 250 ml to cover 1 m^2 of the tank body
Since only the body is to be painted, we find the perimeter of the circle formed by the body of the tank.
perimeter of the circle formed by the body of the tank = [tex]\pi d[/tex]
==> 3.142 x 1.1 = 3.456 m
This perimeter, if spread out, will form a rectangle with a height of 1.4 m from the base.
The area of the rectangle that will be formed = (perimeter of the cylinder body) x ( height of the cylinder)
==> 3.456 x 1.4 = 4.838 m^2
This is the area that needs to be painted.
Converting the paint volume,
250 ml = 0.25 litres
To paint the above calculated are, we will need 4.838 x 0.25 = 1.21 litres of paint, (of course, excluding the base)
The volume of paint available = 2 litres
volume of paint needed = 1.21 litres
Tublu has more than enough paint to cover the tank surface in one layer coating
A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders
Question:
A cinema can hold 270 people at one performance 5/9 of the seats were occupied of the occupied seats 40% we occupied by concessionary ticket holders.
What is the number of seats occupied by concessionary ticket holders?.
Answer:
60 seats
Step-by-step explanation:
Given
Number of seats = 270
Occupied Seats = 5/9
Concessionary ticket holders = 40% of occupied Seats
Required
The number of seats occupied by concessionary ticket holders
First the number of occupied seat has to be calculated.
[tex]Occupied\ Seats = \frac{5}{9} * 270[/tex]
[tex]Occupied\ Seats = \frac{1350}{9}[/tex]
[tex]Occupied\ Seats = 150[/tex]
Next is to determine the number of seats occupied by concessionary ticket holders.
[tex]Number = 40\%\ of\ occupied\ seats[/tex]
[tex]Number = 40\%\ of\ 150[/tex]
Convert percentage to decimal
[tex]Number = 0.4 * 150[/tex]
[tex]Number = 60[/tex]
Hence, 60 seats were occupied by concessionary ticket holders.
I NEED HELP PLEASE, THANKS! :)
Hey there! :)
Answer:
d ≈ 3.49 units
Step-by-step explanation:
Use the distance formula for polar coordinates to determine the distance:
[tex]d = \sqrt{r_{1} ^{2}+r_{2} ^{2}-2r_{1}r_{2}cos(0_{1}- 0_{2} ) }[/tex] (The '0' is supposed to be theta)
Plug in the values given in the question. Convert radians to degrees to simplify the process.
217π/180 = 217°
-23π/36 = -115°.
Therefore:
[tex]d = \sqrt{7 ^{2}+5 ^{2}-2(7)(5)cos(217-(-115) ) }[/tex]
Begin simplifying:
[tex]d = \sqrt{74-70cos(332) }[/tex]
[tex]d = \sqrt{74-61.81 }[/tex]
Solve:
[tex]d = \sqrt{12.19 }[/tex]
d ≈ 3.49 units
Assume that adults have IQ scores that are normally distributed with a mean of 104 and a standard deviation of 15. Find the third quartile Upper Q 3 , which is the IQ score separating the top 25% from the others. Click to view page 1 of the table. LOADING... Click to view page 2 of the table. LOADING... The third quartile, Upper Q 3 , is nothing . (Round to one decimal place as needed.)
Answer:
z = (X-Mean)/SD
X = Mean + (z*SD)
The z value which separates the bottom 75% (100%-25%) from the top 25% is + 0.6745
Therefore, Q3 = X = 107 + (0.6745*16) = 117.8
Step-by-step explanation:
What is the quotient 15p^-4q^-6/-20p^-12q^-3 in simplified form?
Answer:
-3p^8/4q^3
Step-by-step explanation:
<3
IS this table linear?? Can someone please explain???? What would the weight be if the number of weeks in the fitness program was 0???
Answer:
not linearsomewhere between 184 and 186 (maybe)Step-by-step explanation:
As you show, the weight differences are different for the same week differences, so the table is not linear. A graph (attached) can also show you the table is not linear.
__
The highest rate of weight loss shown in the table is 7 lbs in 3 weeks, or 4 2/3 pounds in 2 weeks. The lowest rate of weight loss shown in the table is 5 lbs in 3 weeks, or 3 1/3 pounds in 2 weeks. Based on the rates shown in the table, we might expect the starting weight to be between 3 1/3 and 4 2/3 pounds more than the first table value:
Week 0 weight: between 184 1/3 and 185 2/3 lbs, estimated.
_____
A "line of best fit" for the data has a y-intercept of about 185 pounds, which is the midpoint between our two estimates above.
If x = 2, then 2x = 4
Answer:
4 = 4
Step-by-step explanation:
=> 2x = 4
Putting x = 2
=> 2(2) = 4
=> 4 = 4
Answer:
TrueSolution,
X= 2
Now,
2x=4
plugging the value of X,
2*2= 4
4 = 4 ( hence it is true)
[tex]2x + 3y < 45[/tex]
Answer:
Hello!
~~~~~~~~~~~~~~~``
Simplifying
2x + 3y = 45
Solving
2x + 3y = 45
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '-3y' to each side of the equation.
2x + 3y + -3y = 45 + -3y
Combine like terms: 3y + -3y = 0
2x + 0 = 45 + -3y
2x = 45 + -3y
Divide each side by '2'.
x = 22.5 + -1.5y
Simplifying
x = 22.5 + -1.5y
Hope this helped you! Brainliest would be nice.
Solve the equation. 3t + 8 = 6t - 13
Answer:
7
Step-by-step explanation:
6t-3t=13plus8
3t=21
t=21/3
t=7
hope it helps
Answer:
t = 7
Step-by-step explanation:
3t + 8 = 6t - 13
Subtract 6t on both sides.
3t + 8 - 6t = 6t - 13 - 6t
-3t + 8 = - 13
Subtract 8 on both sides.
-3t + 8 - 8 = - 13 - 8
-3t = - 21
Divide both sides by -3.
(-3t)/-3 = -21/-3
t = 7
someone help please, already tried 168 says its wrong??
Answer:
245 might be the answer
Step-by-step explanation:
(7*7*10)/2
Find the value of s(t(-3)):
s(x) = - 3x-2
t(x) = 5x - 4
Please helppp!
Answer:
(-3x-2/x) multiply by (-15x+12/x) so It's (A)
Hope this helped you!!
Step-by-step explanation:
The function f(x) = x^2+4 is defined over the interval (-2,2). If the interval is dived into n equal parts what is the height of the right endpoint of the kth rectangle?
Answer:
Option (A).
Step-by-step explanation:
The function f(x) = x² + 4 is defined over the interval (-2, 2)
Total number of equal parts between this interval = 5
If the interval is divided into n equal parts, height of the right endpoint of each rectangle = [tex]\frac{5}{n}[/tex]
Height of the endpoint of the k rectangles = [tex]k.\frac{5}{n}[/tex]
Therefore, height of the endpoint of the kth rectangle = Height of first rectangle + height of k rectangles
= -2 + [tex]k.\frac{5}{n}[/tex]
Option (A). will be the answer.
The height of the right endpoint of the kth rectangle h = -2 + k (5/n)
What is the height?The height is a vertical distance between two points. In the case of the triangle, the height will be the distance between the base and the top vertex of the triangle.
The function f(x) = x² + 4 is defined over the interval) (-2, 2 )
Total number of equal parts between this interval = 5
If the interval is divided into n equal parts, the height of the right endpoint of each rectangle = (5/n)
Height of the endpoint of the k rectangles = k (5/n)
The height of the endpoint of the kth rectangle:-
= Height of first rectangle + height of k rectangles
= -2 + k ( 5/n )
Therefore the height of the right endpoint of the kth rectangle h = -2 + k (5/n)
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A rectangular park is 8 miles long and 6 miles wide. How long is a pedestrian route that runs diagonally across the park?
Hey there! :)
Answer:
10 miles.
Step-by-step explanation:
To solve for the diagonal side, we can simply visualize the sides of the rectangle as sides of a right triangle with the diagonal being the hypotenuse.
We can use the Pythagorean Theorem (a² + b² = c²), where:
a = length of short leg
b = length of long leg
c = length of the diagonal
Solve:
c² = a² + b²
c² = 6² + 8²
c² = 36 + 64
c² = 100
c = 10 miles. This is the length of the pedestrian route.
Answer:
10 milesSolution,
Hypotenuse (h) = R
Perpendicular (p) = 8 miles
Base (b) = 6 miles
Now,
Using Pythagoras theorem:
[tex] {h}^{2} = {p}^{2} + {b}^{2} [/tex]
Plugging the values:
[tex] {r}^{2} = {(8)}^{2} + {(6)}^{2} [/tex]
Calculate:
[tex] {r}^{2} = 64 + 36[/tex]
[tex] {r}^{2} = 100[/tex]
[tex]r = \sqrt{100} [/tex]
[tex]r = 10 \: miles[/tex]
Length of route = 10 miles
Hope this helps...
Good luck on your assignment...
Good Morning can I get some help please?
Answer:
5x + 10 = 25
Subtract 10 on each side to make x alone
5x = 15
divide by 5 on each side
x=3 so x=3
3x + 12 = 48
48-12=36
3x=36
divide by 3
x=12
4x + 8 = 16
4x = 8
x=2
2x + 15=25
2x=10
x=5
5x + 20 = 50
5x=30
x=6
hope this helps
1. 3
2.12
3.2
4.5
5.6
Step-by-step explanation:
Answer:
x = 3x = 12x = 2x = 5x = 6Step by step explanation
First:
Move the constant to the Right Hand Side and change its signCalculate the differenceDivideCalculateSolution,
1. 5x + 10 = 25
Move constant to the R.H.S and change its sign:
5x = 25 - 10
Calculate the difference
5x = 15
Divide both sides by 5
5x/5 = 15/5
calculate
X = 3
2. 3x + 12 = 48
or, 3x = 48 - 12
or, 3x = 36
or, 3x/x = 36/3
x = 12
3. 4x + 8 = 16
or, 4x = 16 - 8
or, 4x = 8
or, 4x/x = 8/4
x = 2
4. 2x + 15 = 25
or, 2x = 25 - 15
or, 2x = 10
or, 2x/x= 10/2
x = 5
5. 5x + 20 = 50
or, 5x = 50-20
or, 5x = 30
or, 5x/x = 30/5
x = 6
Hope this helps...
Good luck on your assignment...
What kind of graph is characterized by presenting values as coordinate points without any connecting element? a. bar graph b. line graph c. scatter plot d. histogram
Answer:
Option C, Scatter Plot. Hope this helps!
Step-by-step explanation:
Answer:
The answer is C on edge 2020.
Step-by-step explanation:
Find all solutions of the given system of equations and check your answer graphically. HINT [See Examples 2–5.] (If there is no solution, enter NO SOLUTION. If the system is dependent, express your answer in terms of x, where y = y(x).) 3x + 2y = 20 2x + 3y = 20 (x, y) = (No Response)
Answer:
( x, y ) = ( -20, 20 )
Step-by-step explanation:
Given data
Y = y(x)
3x + 2y = 20 ---------- equation 1
2x + 3y = 20 ---------- equation 2
find (x, y )
solving equation 1 and equation 2
3x + 2y = 20 * 2 = 6x + 2y = 40 --------- EQUATION 3
2x + 3y = 20 * 3 = 6x + 3y = 60 --------- EQUATION 4
cancelling out ( x )
Add both equation 3 and equation 4
5y = 100. hence y = 100/5 = 20
back to equation equation 2
2x + 3(20) = 20
2x = - 40
x = -20
attached is the graph to check the answer
The product of an irrational number and a rational number is irrational. Sometimes True Always True Never True
Answer:
Always true
Step-by-step explanation:
If you can't express the number as a ratio of integers, multiplying or dividing it by integers will not make it so you can.
If π is irrational, 2π is also irrational.
It is always true that the product of a rational and an irrational number is irrational.
Answer:
all ways true
Step-by-step explanation:
g a) What are some of the distinguishing properties of a normal Distribution? Discuss b) The sampling distribution of the sample means is the curve that describes how the sample means are distributed. True or False Explain c) The mean of sample means is the same as the population for a given sample of size n. True False Explain
Answer:
a) Check Explanation.
b) True. Check Explanation.
c) True. Check Explanation.
Step-by-step explanation:
a) A normal distribution is one which is characterized by four major properties.
- A normal distribution is symmetrical about the center of the distribution. That is, the variables spread out from the center in both directions in the same manner; the right side of the distribution is a mirror image of the left side of the distribution.
The center of a normal distribution is located at its peak, and 50% of the data lies above the mean, while 50% lies below.
- The mean, median and the mode are coincidental. The mean, median and mode of a normal distribution are all the same value.
- A normal distribution is unimodal, that is, has only one mode.
- The ends of the probability curve of a normal distribution never touch the x-axis, hence, it is said too be asymptotic.
b) The sampling distribution of sample means arises when random samples are drawn from the population distribution and their respective means are computed and put together to form a distribution. Hence, the curve of this sampling distribition of sample means will show how the sample means are distributed. Hence, this statement is true.
c) The Central Limit Theorem gives that if the samples are drawn randomly from a normal distribution and each sample size is considerable enough, the mean of the sampling distribution of sample means is approximately equal to the population mean. So, if the conditions stated are satisfied, then thos statement too, is true.
Hope this Helps!!!
What is the square root of 64y16?
4y4
4y8
8y4
8y8
Answer: 8y⁸
Step-by-step explanation:
To find the square root of the expression, you want to find the square root of each term.
The square root of 64 is 8. You can write y¹⁶ as (y⁸)². We can pull out this 2 from the square root because it cancels out with the square root. Therefore, the answer is 8y⁸.