8. (a) a spherical mirror is cut in half horizontally and the top half removed. will an image be formed by the bottom half of the mirror? how does the image formed by the half mirror compare to the image formed before cutting the mirror in half?

There is a thermal efficiency of 0.46 for a heat engine. With each cycle, it absorbs 780 J of heat from the high-temperature storage. B) 200 J waste heat it discard each cycle.

The thermal efficiency of a heat engine is defined as the ratio of the work output to the heat input, so in this case, the thermal efficiency is 0.46. Therefore, the work output is 0.46 * 780 J = 360 J.

The waste heat discarded each cycle is the difference between the heat input and the work output, so 780 J - 360 J = 200 J.

How much useful work does the heat engine perform in each cycle?

The useful work that the heat engine performs in each cycle can be determined by using the formula: thermal efficiency * heat absorbed = useful work. In this case, the thermal efficiency is 0.46, and the heat absorbed is 780 J.

Therefore, the useful work done by the engine is 0.46 * 780 J = 360 J.

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The rightward directions she gives are as follows: 1. Move 400 meters to the northwest. 3. The wealth is hidden there, 700 meters to the east-southeast.

This means that anything is pushed toward the center of the earth, which causes the pulled object to accelerate by 9.8 meters per second as it "falls" to the earth. As a result, each second that such a body is dragged towards the earth, its velocity (speed with direction) increases by around 9.8 meters per second.

It should be remembered that gravitation is not a continuous force; gravity weakens the more you are from the center of the Earth. Since it fluctuates from 9.83 at the poles to 9.78 at the equator, it isn't even a consistent at the surface. Due to this, we utilize an average value of 9.8.

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The speed of the penny after 2.5 seconds is 24.5 m/s.

What is speed?

Speed is a scalar quantity that refers to "how fast an object is moving." It is the rate at which an object changes its position, and it is measured in units of distance per unit of time (such as meters per second or miles per hour). Speed is related to the distance traveled by an object and the time it takes to travel that distance, and it can be calculated by dividing the distance traveled by the time it took to travel that distance.

The speed of an object in free fall can be calculated using the equation:

v = g * t

where v is the velocity, g is the acceleration due to gravity (approximately 9.8 m/s^2 on the Earth's surface) and t is the time elapsed.

In this scenario, the penny is dropped off the top of the Statue of Liberty, which is 93 m tall, and we want to find the speed of the penny after 2.5 seconds.

So, we can substitute the values in the equation:

v = 9.8 m/s^2 * 2.5 s = 24.5 m/s

Therefore, the speed of the penny after 2.5 seconds is 24.5 m/s (assuming no air resistance).

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When this problem is solved, we will arrive at the value 72741 to 4 meters per second.

An object's total, directionless motion is measured in terms of distance. Distance may also be referred to as the amount of ground covered by an element, depending on the starting or finishing point.

By calculating its distance, we can determine an object's actual size. One can measure the space that an object takes up above us. Its true size can be determined after we know how far away it is. As you get further away, something gets smaller.

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If a current of 16A flows through a wire with a resistance of 0.6 Ohms, the voltage is: 9.6V.

Using this formula to determine the voltage

V = I × R

Where:

V = voltage = ?

I = current = 16A

R = resistance = 0.6 Ohms

Let plug in the formula

V = 16A ×  0.6 Ohms

V = 9.6V

Therefore the voltage is 9.6V

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The possible ways that heat can be transferred in this system are:

The most typical method of heat transfer is conduction, which involves the direct exchange of heat between two things.

Heat waves are created during the radiation heat transfer process and may be absorbed, reflected, or transmitted through a cooler substance. Earth is warmed by the sun using electromagnetic radiation. Heat waves come from warm bodies.

When Joiya sets the bottle of water down on a table or chair, then by conduction, heat ( or the loss of it ) would move around the table. Radiation would allow for the cold temperature to move into the air around the cold bottle.

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Options for this question include:

The speed when they hit the street will be equal to each other.

Air resistance and gravity are the two fixed forces of nature which move on any object on Earth. For example, when a plane flies through the air, the air particles are pressing against the aeroplane, making it harder for the aircraft to move. When you see a feather fall, it is greatly affected by air resistance.

A force applied to all bodies on Earth is Weight ( W ), which is caused by Earth's gravity. If a body is free falling, its only acceleration is g , gravity. So gravity increases velocity. Both objects will show a change in their velocities because of gravity.

The velocity for both objects if one is thrown up and other is thrown down is same which is given by this formula:

where,

v= final velocity,

v₀= initial velocity,

h is the difference in height between building and street and g= acceleration due to gravity.

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The mass of the object is: 100 kg

It is the physical magnitude that expresses the effort necessary to move the mass of one kilogram with an acceleration of one meter per second squared, this is expressed in units of the international system in Newton.

To solve this exercise, the formula and procedure to be applied is:

F = m * a

Where:

Information about the problem:

Applying the force formula and isolating the mass, we get:

F = m * a

m= F/a

m= 5.0x 10^2 n /5.0 m/s²

m= 100 kg

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The velocity of the sailor relative to the aircraft carrier is - 7 m/s.

The velocity of the sailor relative to the aircraft carrier is calculated by applying the principle of relative velocity as shown below.

Vs/c = Vs - Vc

where;

The velocity of the sailor relative to the aircraft carrier is calculated as;

Vs/c = 36 m/s  -  43 m/s

Vs/c = -7 m/s

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Answer:

To keep the other four charges in equilibrium, the charge q that should be placed at the center of the square is equal in magnitude but opposite in sign to the total charge of the other four charges.

The maximum speed the car weighing 1500kg and turning in a horizontal circle which has a radius of 20 meters can take the turn without skidding at 10.84m/s.

Maximum speed is the highest rate of speed that can be attained. Acceleration is the velocity, and because velocity has both a magnitude and direction associated with it, the acceleration changes when an object change the magnitude of their motion, the direction of their motion, or both of these.

Radius of the circular path, r = 20 m

Mass of the car, M = 1500 kg

Maximum speed of the car = v

The coefficient of friction, μ = 0.6

The centrifugal force will balance the friction force so that the car does not slip.

Therefore, mv²/r = μmg

v²/r = μg

v² = μgr

v = √(μgr)

v = √(0.6 × 9.8 × 20)

v = √(117.6)

v = √(294,000)​

v = √(117.6)

v = 10.84m/s

Therefore, the maximum velocity of the car is 10.84 meter per second.

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Yes, the velocity of the ball has changed as it changed its direction from hitting the wall and after it struck the wall.

Speed is a scalar which means it has magnitude but not the direction. Velocity, on the other hand, is a vector with both magnitude and a direction. As the speed of two cars may be the same, if they are heading to different directions, then their velocity are not identical.

The velocity of he ball has changed. Let's call that the initial direction positive, when the ball was going towards the wall, its velocity is positive +V. But when it bounces directly back, the direction is now is negative -V. The direction of the velocity has changed, even though the magnitude has not.

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A tool that uses sound waves to measure the distance of an object is called a sonar device.

A sonar device is a tool that uses sound waves to measure the distance or detect the presence of objects underwater. The device sends out a high-frequency sound pulse that travels through the water and bounces back to the device after hitting an object. By measuring the time it takes for the sound wave to return, the device can determine the distance to the object and generate an image of the underwater environment. Sonar technology is widely used in applications such as navigation, fishing, and search and rescue operations.

Sound waves are a type of mechanical wave that travels through a medium, such as air, water, or solids, and is generated by the vibration of an object. The vibration creates a compression and rarefaction of the medium, which then spreads out as a wave. When these waves reach the ear, they are interpreted by the brain as sound. The speed of sound in a given medium depends on the properties of that medium, such as density and temperature.

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The ratio i100hz/i1000hz is 1000, meaning that the least intense perceptible sound at 100 Hz is 1000 times more intense than the least intense perceptible sound at 1000 Hz.

Intense is an adjective describing something that is extreme or powerful, either in terms of strength, emotion, or concentration. It can refer to a feeling, such as intense emotion, or a physical sensation, such as intense pain.

The least intense perceptible sound at 100 Hz is about one millionth of a Pascal, while the least intense perceptible sound at 1000 Hz is about one billionth of a Pascal. Therefore, the ratio i100hz/i1000hz is 1000, meaning that the least intense perceptible sound at 100 Hz is 1000 times more intense than the least intense perceptible sound at 1000 Hz.

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Part a: Velocity with no friction: v = 6.41 m/s.

Part b:  velocity of the moving object when it reached at the bottom is found as  5.29 m/s.

Potential energy P.E

P.E =  mgh

P.E = 38 x 9.8 x 2.1   J

This all transforms to kinetic energy just at bottom = 0.5 mv² if there is no energy loss.

So,

0.5 x 38 x v² = 38 x 9.8 x 2.1,

v = 6.41 m/s

Part b: If friction results in a loss of energy of 250 J

0.5 x 38 x v² = 38 x 9.8 x 2.1 - 250

v² = 532.04/ (0.5 x 38)

v = 5.29 m/s

Thus, the velocity of the moving object when it reached at the bottom is found as  5.29 m/s.

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The correct question is-

2. A 38kg child is at the top of a slide that is 2. 1m tall.

(a) If there is no friction, how fast will they be moving when they reach the bottom of the slide?

(b) If they lose 250. 0J of energy to sound, heat, and friction, how fast will they be moving when they reach the bottom?

The minimum thickness of a soap bubble film (air-soap-air) with refractive index 1.38 that results in a constructive interference in the reflected light if this film is illuminated by a beam of light of wavelength 610 nm is 150

nm.

The refractive index of an optical medium is described as a dimensionless number that gives the indication of the light bending ability of that medium.

Condition for constructive interference is given as ,

2μt = (2n + 1) λ/2

t =  (2n + 1) x 900 / 4x 1.5

where n = 0(for minimum thickness)

Therefore t= 150nm

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Option E -  it remains the same , if a simple pendulum oscillates with small amplitude and its length is doubled .

The greatest displacement or distance that a point on a wave or vibrating body may travel in relation to its equilibrium position

A wave's amplitude is the difference between its starting position and its maximum displacement. Frequency is the amount of waves which pass past the certain place each second. Period is the length of time it takes for a wave cycle to finish.

    Given,length of a simple pendulum  is doubled .

To find, frequency of motion.

we have Time period T before doubling the length,

T = 2π[tex]\sqrt{\frac{L}{g} }[/tex]   L- length,g-acceleration due to gravity

T/2π = [tex]\sqrt{\frac{L}{g} }[/tex]  

g = L(2π/T[tex])^{2}[/tex]   → 1

when length is doubled,Time period [tex]T^{'}[/tex]

[tex]T^{'}[/tex] = 2π [tex]\sqrt{\frac{2L}{g} }[/tex]

( [tex]T^{'}[/tex] /2π[tex])^{2}[/tex] = [tex]\frac{2L}{g}[/tex]

g=2L( 2π/T[tex])^{2}[/tex] → 2

from equation 1 and 2

L( 2π/T[tex])^{2}[/tex] = 2L( 2π/T[tex])^{2}[/tex]

2π/T=[tex]\sqrt{2}[/tex](2π/T)

1/T  =[tex]\sqrt{2}[/tex](1/T)

we know,frequency γ = 1/T

γ  =[tex]\sqrt{2}[/tex]  γ '

γ ' =[tex]\frac{1}{\sqrt{2} }[/tex]  γ

Therefore option E is correct.

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here is ur answer

MARK BRAIN PLease

If the work required to speed a car up from 10km/h to 20km/h is 5.0 x 10^3 J, the work required to increase the cars speed from 20km/h to 30km/h is: 8.33 × 10³J.

Using this formula to determine the   work required to increase the cars speed from 20km/h to 30km/h

[tex]Wii = Wi (V^2_2- V^2_1) /v^2_2 - v^2_1[/tex]

Let plug in the formula

Work required = (5 × 10³) (30² -20²) / (20² -10²)

Work required = (5 × 10³)  ( 900 - 400) /(400  - 100)

Work required = (5 × 10³) ( 500) / 300

Work required = 8.33 × 10³J

Therefore the Work required is 8.33 × 10³J.

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The change in position or displacement (Δx) divided by the time intervals (Δt) in which the displacement occurs yields the average velocity.

Depending on the sign of the displacement, the average velocity can be positive or negative.

To begin, in order to calculate average velocities, we need the position for each instant mentioned:

Y(2) = 2 ft

Y(2.5) = 0 ft

Y(2.1) = 13.44 ft

Y(2.05) = 14.76 ft

Y(2.01) = 15.7584 ft

Let us now compute the average velocities:

V(2 - 2.5) = Y(2.5) - Y(2) / 2.5 - 2

= -32 ft/s

V(2 - 2.1) = Y(2.1) - Y(2) / 2.1 - 2

= -25.6 ft/s

V(2 - 2.05) = Y(2.05) - Y(2) / 2.05 - 2

= -24.8 ft/s

V(2 - 2.01) = Y(2.01) - Y(2) / 2.01 - 2

= -24.16 ft/s

Now, we can derive the expression for y for the instantaneous velocity:

For t=2s, V(t) = 40 - 32t V(2) = -24ft/s

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The heat required would be Q = 7.0 g/28 g/mol * 20.8 J/molK * (2T - T) = 544 J.

Heat is the transfer of energy from one body or system to another due to the difference in their temperatures. Heat is commonly transferred through thermal conduction, convection, radiation, or when two bodies with different temperatures come into direct contact.

The heat required for a process at constant pressure is greater than the heat required for a process at constant volume. This is because when a gas is heated at constant pressure, work is done to push the piston outward, so more energy is required.

To double the volume and temperature at constant pressure, the heat required would be equal to the change in internal energy of the system,
which can be calculated using the equation Q = nCvΔT,
where n is the number of moles of gas,
Cv is the molar heat capacity,
and ΔT is the change in temperature.
In this case, the molar heat capacity of nitrogen gas is 20.8 J/molK,
So the heat required would be Q = 7.0 g/28 g/mol * 20.8 J/molK * (2T - T) = 544 J.

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The force required to hold the ping pong ball completely under the water is 36,189.98 dyne.

Diameter of ball = 4.18 cm

The radius of the ball = 2.09 cm

The volume of the ball can be calculated as   V=    [tex]\frac{4}{3}[/tex]π r³                      

Therefore, the volume of the ball = 38.26 cm³

The net force required to completely submerge a ball under water = (Buoyant force) - (the weight of the ball)

If ρ₁ is used for the density of water. Then, the value of ρ₁ is 1 g cm⁻³.

Buoyant force = ρ₁gV

                      = 1 × 980 × 38.26

                      = 37494.80 dyne

Here, ρ₂ = density of ball = 0.0348 1 g cm⁻³.

                 Weight of ball = ρ₂gV

                                           = 0.0348 × 980 × 38.26

                                          = 1304.82 dyne

Therefore, the net force required to completely submerge a ball under water    = 37494.80 - 1304.82 = 36,189.98 dyne or 0.362 N

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There is not enough information to determine which object will reach the bottom of the ramp first. So option 1 is correct.

Without knowing the mass, radius, and coefficient of friction of the objects and the angle of the ramp, we can't determine which object will have the greater acceleration and thus reach the bottom of the ramp first.

To determine which object will reach the bottom of the ramp first, we need to know the acceleration of each object. The acceleration of an object is determined by the net force acting on it.

Which in turn is determined by the gravitational force acting on the object and the frictional force acting on it.

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Geosynchronous satellite makes a round around the earth in 29.93 hours. It makes a difference of 36000 km difference in the altitude.

Geosynchronous satellites are those that remains stationery with respect to a place. This is because their time period to complete a cycle is 23.93 hours, that is exactly the same as the rotation period of the earth. So the satellite appears stationery. The velocity of the geosynchronous satellite around the earth is 3.07 km/s or 3070 m/s.

GMm/(R+h)² = mv²/(R+h)

GM/v² = (R+h)²

Where R is the radius of the earth = 6.37 × 10⁶ m, h is the altitude of the satellite above the earth, and M is the mass of the earth that is 6 × 10²⁴ kg, G = 6.67 × 10⁻¹¹ Nm²/kg²

(6.67 × 10⁻¹¹ ×6 × 10²⁴)/(3070)² = (R+h)

(R+h) = 42461989 m

6.37 × 10⁶ + h = 42461989

h = 42461989 - 6.37 × 10⁶

h = 36.09 × 10⁶  m

h = 36000 km.

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The statement that is false is "there are places on earth where all forces are absent." Forces, such as gravity, are always present on Earth.

All the given statements are true except the statement "there are places on earth where all forces are absent." is false.

Forces change the momentum of a body,forces always occur in equal and opposite pairs (Newton's third law), where there is no force, objects continue to move the way they were moving, and forces cause an acceleration to take place are all true statements about forces.

Newton's third law simply states that there is an equal and opposite reaction to every action. So, if object A exerts a force on object B, object B will exert an equal but opposite force on object A.

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In a circle at constant speed, the work done is zero since the Force is always perpendicular to the distance moved as you move incrementally around the circle.

An object moves in a circle at a consistent speed in a motion known as uniform circular motion. Any point on a propeller, for instance, that is rotating continuously, is moving uniformly in circles. The second, minute, and hour hands on a watch are some further examples. It is amazing that despite the constant rotation rate, points on these revolving objects are actually speeding. We must consider the motion in terms of vectors in order to see this.

A centripetal motion is an Objects having a constant speed have zero acceleration in one-dimensional kinematics. In two- and three-dimensional kinematics, a particle can experience acceleration even if its speed is constant if it follows a curved trajectory, like a circle.

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The magnitude of electric force is [tex]2.27 * 10^{6} N[/tex] (downwards)

We know that electric force between two charges is given by equation:

                                         F = [tex]\frac{k.q_{1} .q_{2} }{r^{2} }[/tex]

Where,

k = constant = [tex]9 * 10^{9} Nm^{2} /C^{2}[/tex]

q1 = first charge =35 C

q2 = second charge = -35 C

r = distance between them = 2.2 km = 2200m

Putting these values in above equation we get:

F = -[tex]2.27 * 10^{6} N[/tex] , where negative sign denotes the direction.

So, the magnitude of electric force is [tex]2.27 * 10^{6} N[/tex] (downwards)

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The volume of object will be equal to the volume of water displaced so the object's volume is also 17.04 dm⁻³.

In water, the object appears lighter than in air.

That is,

936 - 769 = 167N.

Water provided the167N buoyant force.

The buoyant force on an object in water is equal to the weight of water displaced by the object. The buoyant force acting on the metal object in this case is 167N. The object must have displaced the same weight of water.

Given g = 9.8m/s²

Water displacement mass:

Mass = weight /g

         = 167/9.8

.         = 17.04 kg

Water displacement volume:

At room temperature, the density of water is 1.000 kg.dm⁻³. Each kilogram of water has a volume of 1 dm³ (one cubic decimeter), which is equal to 1 L. (one liter).

V = Mass / Density

= m/ρ

= 17.04/1.000 kg.dm⁻³

= 17.04dm⁻³

The object is completely submerged. As a result, the object's volume will remain constant. The object is completely submerged. As a result, the object's volume will be equal to the volume of water displaced. The object's volume is also 17.04 dm⁻³.

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The distance between the two parallel plates can be found using the equation E = V/d where E is the electric field, V is the potential difference and d is the distance between the plates. Thus, d = V/E = 125V / 4.25 x 103N/C = 29.41cm

The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.

It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

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The distance between the two parallel plates can be found using the equation E = V/d  , 29.41cm far apart are the plates .

                             E = V/d

where E is the electric field,

V is the potential difference and

d is the distance between the plates.

                          Thus, d = V/E

                          = 125V / 4.25 x 103N/C

                                    = 29.41cm

The relationship between electric field, potential difference and distance in parallel plates is inversely proportional. As the potential difference increases, the electric field between the plates increases and the distance between the plates decreases. And as the distance between the plates increases, the electric field between the plates decreases and the potential difference applied to the plates decreases.

It can be mathematically represented by the formula E = V / d, where E is the electric field, V is the potential difference, and d is the distance between the plates.

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