In general, empirical formulas are normally formula with the least values for the subscripts.
They usually don't have only even numbers as the subscripts and they tend to have 1 as the subscript of at least one element.
From this, we can conclude that the molecular formula that is also an empirical formula is CH4.
It means that the correct answer is b. CH4.
a bar of gold has a mass of 12.4kg a volume of 3 cm^3?
We need to calculate the density of the bar of gold, using the following formula:
[tex]\text{density}=\frac{mass}{volume}.[/tex]The units of density must be in kg/m^3 or g/cm^3. We can do the conversion from kg to g. Remember that 1 kg equals 1000 g:
[tex]12.4kg\cdot\frac{1000g}{1kg}=12400g\text{.}[/tex]Now, we can apply the formula using the last data:
[tex]\begin{gathered} density=\frac{12400g}{3cm^3} \\ \text{density}=4133.33\text{ }\frac{g}{cm^3} \end{gathered}[/tex]Let's see how would be the density in kg/m^3, remembering that 1 m^3 equal 1000000 cm^3:
[tex]undefined[/tex]What is a discrete amount of energy called?QuarkPrismThermonQuantum
Answer: A discrete amount of energy is called quantum.
Who discovered neutrons?A. James ChadwickB. J. J. ThompsonC. Ernest RutherfordD. John Dalton
Answer:
Explanation:
The question requires us to choose the option that
12.Which statement best describes a heterogeneous mixture?Select one:a. All the particles in the mixture have identical chemical and physical properties.b. All of the particles in the mixture easily pass through filter paper.c. Particles are evenly mixed throughout the mixture.d. Particles do not look the same throughout the solution.
ANSWER
Option D
EXPLANATION;
Heterogenous mixture is defined as the type of mixture with a non uniform composition.
Heterogenous mixture can also be defined as type of mixture in which the composition is not uniform throughout the mixture.
Therefore, the particles in heterogenous mixture does not look the same throughout the solution.
Hence, the correct option is D
Conservation of Mass Activity WorksheetInstructions: Observe and analyze the interactions between the substances pictured in the slide show. Compare the properties of substances before and after each interaction. You will submit your completed worksheet for grading.Data TableOn the table below, record your observations before and after the interactions and explain how mass was conserved. Describe the changes in properties that prove a chemical reaction occurred. The first row is an example. Observations Before InteractionObservations After InteractionHow was mass conserved?Proof of a Chemical ReactionExample: Sugar + HeatThe sugar is in tiny white particles in a pile. Heat is not seen but is implied by the heat source. The pile of sugar in the pot has a mass of 100 grams.There is a solid, light brown mass at the bottom of the pot. It has a mass of 100 grams.The mass of the sugar is the same in melted form as it is in solid crystal form.There was not a chemical reaction. Sugar did not change composition. It only melted. Melting point is a physical property, and this is a physical change.Steel Wool + Oxygen (Fire) Egg + Heat Water + Heat Zinc + Hydrogen Chloride Sodium Hydroxide + Copper Sulfate
Steel wool and Oxygen (Fire)
Steel wool is mostly iron (Fe) and oxygen cannot be seen but it is used during heating or burning of substances. When iron is burned, it reacts with oxygen in the air to form iron oxide (FeO2). This reaction releases heat. When the steel wool is heated, a new substance is created. The mass of steel wool (product) is increased. This is a chemical change/reaction because the steel wool changes to iron oxide, and mass is not conserved.
Egg and heat
An egg is a liquid substance which consists of colorless substance and yellow yolk. Heat is not seen but produced by the heat source. When the egg is heated, it becomes a solid. The mass of the egg is not changed, it remains the same, the only difference is that it changes from being a liquid to solid. Only a physical change occurred.
Water and heat
Water (I will assume it is in its liquid state) is liquid and heat is the source of energy, it cannot be seen but is implied by the heat source which can be a stove in this case. When liquid water is heated, its state is changed to vapor or gas. The mass of the water remains the same, thus mass is conserved because this is a physical reaction or change.
Zinc and hydrogen Chloride
Zinc is a brittle metal at room temperature and has a silver-greyish appearance. Hydrogen Chloride is a colourless gas at room temperature. When zinc reacts with hydrochloric acid (hydrogen chloride), the metal displaces the hydrogen to form zinc chloride. This is a chemical reaction since zinc increases in mass, thus mass is not conserved.
Sodium hydroxide and Copper sulfate
Sodium hydroxide is a white solid and copper sulfate is a blue solid. When sodium hydroxide reacts with copper sulfate a blue precipitate of copper hydroxide is formed. This is a chemical reaction, thus the mass of one of the reactants will be larger in products. However, mass is conserved if all products are observed/calculated.
How many moles of methane(CH4)are in 7.31x1025 molecules?Let's begin by setting up our equation.What belongs in the green box?7.31x1025 molecules CHA?A. 1 mole CH4B. 6.02 x 1023 molecules CHAEnter
Answer
B. 6.02 x 10²³ molecules CH₄
Explanation
Avogardro's constant says 1 mole of a substance has 6.02 x 10²³ molecules.
⇒ 1 mole = 6.02 x 10²³ molecules/atoms
Therefore, the mole of methane in the given molecules can be calculatedas follows
[tex]Mole\text{ of methane }=\frac{7.31\times10^{25}_{}}{6.02\times10^{23}\text{ }molecules\text{ }CH_4}=121.43\text{ mole}[/tex]Hence, what belongs to the green box is 6.02 x 10²³ molecules CH₄
In the reaction below, 7.0 mol of NO and 5.0 mol of O₂ are reacted together. The reaction generates 2.3 mol of NO₂. What is the percent yield for the reaction?2 NO (g) + O₂ (g) → 2 NO₂ (g)
Answer
Percent yield for the reaction = 32.86%
Explanation
Given:
Moles of NO = 7.0 mol
Moles of O₂ = 5.0 mol
Moles of NO₂ generated = 2.3mol
2 NO (g) + O₂ (g) → 2 NO₂ (g)
What to find:
The percent yield for the reaction.
Step-by-step solution:
The percent yield for the reaction can be calculated using:
[tex]Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\%[/tex]The actual yield = moles of NO₂ generated = 2.3mol
The theoretical yield can be calculated as follows:
First, we need to determine the limiting reactant, using balanced equation for the reaction.
From the equation, 2 mol NO reacts with 1 mol O₂
So 7.0 mol NO will require (7.0 mol x 1 mol)/2 mol = 3.5 mol O₂
This means the 7.0 mol of NO will be completely consumed by only 3.5mol of O₂. Hence, NO is the limiting reactant and O₂ is the reactant in excess.
The next step is to use the limiting reactant to calculate the theoretical yield for the reaction.
From the reaction equation, 2 mol NO generates 2 mol NO₂
So 7.0 mol NO will generate:
[tex]\frac{7.0\text{ }mol\text{ }NO\times2\text{ }mol\text{ }NO_2}{2\text{ }mol\text{ }NO}=7.0\text{ }mol\text{ }NO_2[/tex]Finally, put actual yield = 2.3 mol, and theoretical yield = 7.0 mol into the percent yield formula above:
[tex]\begin{gathered} Percent\text{ }yield=\frac{2.3mol}{7.0mol}\times100\% \\ \\ Percent\text{ }yield=0.3286\times100\% \\ \\ Percent\text{ }yield=32.86\% \end{gathered}[/tex]How many moles of h2o are there in 180g of water (molar mass is 18.001g/mole)
First, remember that:
1 mol of any compound is the same thing as the molecular mass of the compound.
So, we could say that 1 mol of H2O is equal to the molecular mass of H2O, which is 18.001g/mole.
Given that we have 180g of water, we could write:
[tex]180gH_2O\cdot\frac{1molH_2O}{18.001gH_2O}=10molesH_2O[/tex]Therefore, there are 10 moles of water in 180g of water.
To convert grams to moles, we just divide the amount in grams we have by the molecular mass.
[tex]\text{moles}=\frac{\text{mass given}}{molecular\text{ mass}}[/tex]How many electrons would be too many for a nitrogen atom
Hydrochloric acid and oxygen gas form water and chlorine gas. How many moles of oxygen are required to produce 4.59 moles of chlorine gas.
Answer:
2.295 moles of O2 are needed.
Explanation:
1st) It is necessary to write and balance the chemical reaction:
[tex]4HCl+O_2\rightarrow2H_2O+2Cl_2[/tex]2nd) From the balanced reaction we can see that to produce 2 moles of chlorine gas (Cl2), 1 mole of oxygen gas (O2) is needed. So, with a mathematical rule of three we can calculate the amount of oxygen gas moles needed to produce 4.59 moles of Cl2:
[tex]\begin{gathered} 2\text{ moles Cl}_2-1\text{ mole O}_2 \\ 4.59\text{ moles Cl}_2-x=\frac{4.59\text{ moles Cl}_2*1\text{ mole O}_2}{2\text{ moles Cl}_2} \\ x=2.295\text{ moles O}_2 \end{gathered}[/tex]Finally, 2.295 moles of O2 are needed
Calculate the [H3O+] value of each aqueous solution.NaOH with [OH−]=1.0×10−2M Express your answer using two significant figures.
Answer
[H₃O⁺] = 1.0 x 10⁻¹² M
Explanation
Given that:
[OH⁻] = 1.0 x 10⁻² M
What to find:
To calculate the [H₃O⁺] of the NaOH solution.
Step-by-step solution:
The [H₃O⁺] of the NaOH solution can be calculated using the relation given below:
[H₃O⁺] x [OH⁻] = 1.0 x 10⁻¹⁴
Therefore, the [H₃O⁺] will be:
[tex].\left[H₃O⁺\right]=\frac{1.0\times10^{-14}}{[OH^-]}=\frac{1.0\times10^{-14}}{1.0\times10^{-2}}=1.0\times10^{-12}\text{ }M[/tex]Hence, the [H₃O⁺] value of the NaOH aqueous solution is 1.0 x 10⁻¹² M
state the preparation and properties of carboxylic acids.
thankyou!
An organic compound with a carboxyl functional group is known as a carboxylic acid. They can be found in abundance in nature and are also synthesized by humans. Carboxylic acids deprotonate to produce a carboxylate anion with the general formula R-COO-, which can be used to make several useful salts including soap.
preparation ---
using Alcohol -(see image)
With the addition of oxidizing agents, primary alcohol is oxidized to produce carboxylic acid. As a result, the oxidation of primary alcohols yields aldehydes, which are then oxidized again to yield carboxylic acids.
using Grignard reagents-(see image)
The Grignard reagents reaction allows for the formation of carboxylic acid. Grignard reagents form carboxylic acid salts when they react with crushed dry ice or solid carbon dioxide.
properties ---
1)Carboxylic acid molecules are polar due to the presence of two electronegative oxygen atoms
2)They also participate in hydrogen bonding due to the interaction of the carbonyl group (C=O) and the hydroxyl group.
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what are halogen compounds
ANSWER
EXPLANATION
Halogen are non-metals compound that constitute group 7 or 17. The halogen elements are Fluorine, Chlorine, Bromine, Iodine etc. They are called halogen because it produce sodium salts of the same properties.
Halogen has 7 valence electrons at their outermost shell and they both have similar chemical properties.
Describe an example where an open system might result in conclusions that go against the Law of Conservation of Mass
Answer
A pot of boiling water is an open system because a burner supplies energy in the form of heat, and matter in the form of water vapor is lost as the water boils.
Explanation
The law of conservation of mass states that matter cannot be created or destroyed in a chemical reaction.
The description of an example where an open system might result in conclusions that go against the above law is a pot of boiling water is an open system because a burner supplies energy in the form of heat, and matter in the form of water vapor is lost as the water boils.
Note: An open system can exchange both matter and energy with its surroundings while a closed system can exchange energy but not matter with its surroundings. However, the last type of system is an isolated system, and an isolated system exchanges neither energy nor matter with the surroundings.
Which of the following statements best describes photochemical smog in large cities in the United States?Photochemical smog is more prevalent during winter months.Answer A: Photochemical smog is more prevalent during winter months.APhotochemical smog causes negative human health impacts such as eye and lung irritation.Answer B: Photochemical smog causes negative human health impacts such as eye and lung irritation.BPhotochemical smog contains secondary pollutants that form when sulfur dioxide and nitrogen oxide interact in the atmosphere.Answer C: Photochemical smog contains secondary pollutants that form when sulfur dioxide and nitrogen oxide interact in the atmosphere.CPhotochemical smog is composed of primary and secondary pollutants that are not reactive.
Answer
C: Photochemical smog contains secondary pollutants that form when sulfur dioxide and nitrogen oxide interact in the atmosphere.
Explanation
Photochemical smog is a mixture of pollutants that are formed when nitrogen oxides and volatile organic compounds react to sunlight, creating a brown haze above cities in the United States. It tends to occur more often in summer because that is when we have the most sunlight. Their low concentration causes irritation in the nose and throat and their high concentration causes headache, chest pain, cough, and difficulty in breathing.
What is the wavelength of 101-WCHEM its broadcasting frequency is 101.9 megahertz?
What is the wavelength of 101-WCHEM its broadcasting frequency is 101.9 megahertz?
The relationship between the frequency of an electromagnetic wave and its wavelength is given by this formula:
c = λ * f
where, c stands for the speed of light, λ is the wavelength and f is the frequency.
According to our problem:
f = 101.9 megahertz
λ = ??
And we can search for the value of the speed of light:
c = 2.99 * 10⁸ m/s
To solve the problem we have to convert MHz into cycles/sec
1 MHz = 1 000 000 Hz = 1 * 10⁶ Hz
1 Hz = 1 cycle/sec
f = 101.9 MHz * (1 * 10⁶ Hz) / (1 MHz) = 1.019 * 10⁸ Hz = 1.019 * 10⁸ cycles/sec
Our unknown is the wavelength. Let's solve our formula for λ:
λ = c / f
Replacing:
λ = (2.99 * 10⁸ m/s) / ( 1.019 * 10⁸ cycles/s)
λ = 2.93 m
The wavelength of 101-WCHEM is 2.93 m.
If we want to convert it to cm:
100 cm = 1 m
λ = 2.93 m * 100 cm/(1 m) = 293 cm
The wavelength of 101-WCHEM is 293 cm.
Calculate the heat released when 1200 g of steam changes phase to liquid water. Assume no temperature change and Hv = 2260J/g
According to the explanation given in the previous session, now we have a similar situation, but now we have steam changing to liquid water and a release of heat and not absorption. The formula will be the same:
Q = m * ΔHv
We have:
m = 1200 grams
ΔHv = 2260 J/g, but since we are releasing energy, this value has to be negative, -2260 J/g
Now we add these values into the formula:
Q = 1200 * -2260
Q = - 2712000 Joules or 2712 Kilojoules
Look at the equation.6CO2 + 6H2O → C6H12O6 + 6O2 What process does the chemical equation represent?PhotosynthesisRespirationOsmosisDigestion
H₂O and CO₂ are the substances needed to carry out photosynthesis. Chlorophyll molecules absorb sunlight and break down molecules of H₂O, releasing O₂ and hydrogen. Then, hydrogen binds to CO₂ and forms glucose (C₆H₁₂O₆).
6 CO₂ + 6 H₂O → C₆H₁₂O₆ + 6 O₂
So this chemical reaction equation represents Photosynthesis.
Nitrogen gas is cooled from 300k to 50k. If it’s original volume was 40L,what is the final volume?
In this question, we have a gas going through a change in temperature and the law that shows the relationship between temperature and volume is Charles's gas Law, which can be presented with the following formula:
V1/T1 = V2/T2
We have:
V1 = 40 L
T1 = 300 K
V2 = ?
T2 = 50 K
Now we just need to add these values into the formula:
40/300 = V2/50
0.1333 = V2/50
V2 = 6.7 Liters will be the new volume
Question 7 of 10What is latent heat?A. The heat required to increase the temperature of an object 1°CB. The heat absorbed or released during a phase changeC. The heat absorbed or released when bonds that hold a moleculetogether break or formD. The heat required for a chemical reaction to occurSUBMIT
A. The heat required to increase the temperature of an object 1°C
The latent heat is the energy absorbed or released by a body when its temperature changes
the energy absorbed or released during a phase change is the freezing enthalpy or vapor enthalpy depending on the phases
The energy involved when bonds are broken or formed is the formation enthalpy
the energy involved in a chemical reaction is the reaction enthalpy.
Consider the reaction between calicium oxide and carbon dioxide. CaO(s) + CO2 arrow CaCO3(s)A chemist allows 14.4 g of CaO and 13.8 g of CO2 to react. When the reaction is finished the chemist collects 19.4 g of CACO3. Determine the limiting reactant, theoretical yield and the percent yield for the reaction.
They give us the equation of the reaction already balanced:
CaO(s) + CO2 ----> CaCO3(s)
So we can proceed to do the calculations.
We will initially determine which is the limiting reactant and we will make the theoretical yield calculations based on this reactant. Finally we will find the percent yield by dividing the amount obtained by the chemist by the theoretical amount.
We will follow the following steps:
1. We calculate the moles of the reactants by dividing the given weight by the molar mass.
Molar mass CaO= 56.0774g/mol
Molar mass CO2= 44.01g/mol
2. We calculate the limiting reactant by determining which reactant has fewer moles. This is because the CaO to CO2 ratio is 1 to 1, meaning that the same moles of each reactant are needed to react.
3. We find the moles of CaCO3 by the stoichiometry of the reaction.
4. We find the grams of CaCO3 by multiplying the moles found by the molar mass, this will be the theoretical yield. Molar mass CaCO3=100.0869g/mol
5. We calculate the percent yield by dividing the amount found above by the current yield=19.4g CaCO3.
Let's proceed with the calculations.
1. Moles of reactants
Mol of CaO
[tex]molCaO=14.4gCaO\times\frac{1molCaO}{56.0774gCaO}=0.257molCaO[/tex]Mol of CO2
[tex]molCO_2=13.8gCO_2\times\frac{1molCO_2}{44.01gCO_2}=0.314molCO_2[/tex]2. Limiting reactant
We have fewer moles of CaO, since the ratio is 1 to 1 this will be the limiting reactant, so the following calculations we will do with 0.257mol of CaO
Limiting reactant: CaO
3. Moles of CaCO3
The ratio CaCO3 to CaO is 1/1 so we have the same number of moles of CaO.
Moles of CaCO3 = 0.257mol
4. Grams of CaCO3 (Theoretical yield)
[tex]gCaCO_3=0.257molCaCO_3\times\frac{100.0869gCaCO_3}{1molCaCO_3}=25.7gCaCO_3[/tex]The theoretical yield of CaCO3 is 25.7g
5. Percent yield
[tex]\begin{gathered} PercentYield=\frac{ActualYield}{TheoreticalYield}\times100\% \\ PercentYield=\frac{19.4gCaCO_3}{25.7gCaCO_3}\times100\% \\ PercentYield=75.5\% \end{gathered}[/tex]The percent yield of CaCO3 is 75.5%
How are scientific laws different from scientific theories?OA. Scientific theories are based on mathematical equations, whilescientific laws are based on observations.OB. Scientific theories are used to explain phenomena, while scientificlaws describe the natural world.C. Scientific theories are used to guide investigations, while scientificlaws govern the procedures used by scientists.D. Scientific theories are reviewed by other scientists, while scientificlaws are not.
In the scientific world, we have different names to describe each step of the scientific method, two definitions which are very close to one another are Scientific Law and Scientific Theory.
Usually Scientific laws are described using mathematical equations and formulas to describe what will happen in a given situation, for example the Gravity Law
Scientific theory will describe how a phenomenon happens, and it is usually done through observations and testing, like the Evolution theory
Therefore the best answer will be letter B
A sample containing 4.20 g of O2 gas has an initial volume of 20.5 L . What is the final volume, in liters, when each of the following occurs and pressure and temperature do not change?A sample of 2.25 g of O2 is removed.
Answer
V2 = 10.95 L
Explanation
Given:
mass 1 = 4.20 g
mass 2 = 2.25 g
volume 1 = 20.5 L
Required: volume 2
Solution
Step 1: Find the number of moles of mass 1 and 2.
For mass 1:
n = m/M where n is the moles, m is the mass and M is the molar mass
n = 4.20g/31.998g/mol
n = 0.131 mol
For mass 2:
n = 2.25g/31.998g/mol
n = 0.070 mol
Step 2: For this problem, we will use the ideal gas law equation
PV = nRT
However, P, V and R are constant
Therefore
[tex]\frac{n_1}{V_1}\text{ = }\frac{n_2}{V_2}[/tex]V2 = (V1n2)/n1
V2 = (20.5L x 0.070 mol)/0.131 mol
V2 = 10.95 L
Determine from the balanced chemical reaction ifthe derived mole ratio is correct or incorrect.4Zn + 10HNO3 + 4Zn(NO3)2 + N20 + 5H204 moles Zn10 moles HNO3correctincorrect
Answer
Correct
Explanation
[tex]4Zn+10HNO_3\rightarrow4Zn(NO_3)_2+N_2O+5H_2O[/tex]From the balanced chemical reaction, 4 moles of Zn reacted with 10 moles of HNO3 to produced 4 moles, 1 mole, and 5 moles of Zn(NO3)2, N2O, and H2O respectively.
Therefore, comparing the mole of Zn to HNO3, then the derived ratio is correct.
Calculate the dH value for the following chemical reaction:C + 2H2O CO2 + 2H2First equation: C + O2 CO2 dH = -394 kJSecond Equation: 2H2 + O2 2H2O dH = -484 kJ
dH = +90kJ
Explanations:
Given the following chemical reactions with their individual enthalpy change expressed as:
[tex]\begin{gathered} C+O_2\rightarrow CO_2\text{ }\triangle H=-394kJ \\ 2H_2+O_2\rightarrow2H_2O\text{ }\triangle H=-484kJ \end{gathered}[/tex]We need the enthalpy change value for the reaction shown:
[tex]2H_2O\rightarrow CO_2+2H_2[/tex]To get the equivalent reaction from the 2chemical reactions above, we will interchange the product and reactant of the formation of water to have:
[tex]\begin{gathered} C+\cancel{O_2}\operatorname{\rightarrow}CO_2\operatorname{\triangle}H=-394kJ \\ 2H_2O\rightarrow2H_2+\cancel{O_2}\triangle H=+484kJ \\ _{--------------------------------------} \\ C+2H_2O\rightarrow CO_2+2H_2\text{ }\triangle H=-396kJ+484kJ=+90kJ \end{gathered}[/tex]Hence the dH value for the following chemical reaction C + 2H2O -> CO2 + 2H2 is +90kJ
SI base units used in chemistry includeQuestion options:A) kilograms, liters, inches, and moles.B) pounds, gallons, moles, and Fahrenheit.C) pounds, gallons, moles, and Celsius.D) kilograms, seconds, moles, and Kelvin.
Answer
D) kilograms, seconds, moles, and Kelvin.
Explanation
The seven SI base units are comprised of the following:
1. Length - meter (m)
2. Time - second (s)
3. Amount of substance - mole (mole)
4. Electric current - ampere (A)
5. Temperature - kelvin (K)
6. Luminous intensity - candela (cd)
7. Mass - kilogram (kg)
Therefore, the SI base units used in chemistry include kilograms, seconds, moles, and Kelvin.
The correct answer is option D) kilograms, seconds, moles, and Kelvin.
How much water must be added to 500.0 mL of a 3.00 M HCl solution to obtain a solution that is 2.00 M
Water must be added to 500.0 mL of a 3.00 M HCl solution to obtain a solution that is 2.00 M is 750ml
A solution is a homogeneous mixture of one or more solutes dissolved in a solvent
Here given data is
M₁V₁ = M₂V₂
M₁ = 2.00 M
V₁ = ?
M₂ = 3.00 M
V₂ =500.0 mL
Si putting this value in equation
M₁V₁ = M₂V₂
2.00 M×V₁ = 3.00 M×500.0 mL
V₁ = 750ml
750ml water must be added to 500.0 mL of a 3.00 M HCl solution to obtain a solution that is 2.00 M
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Perform the followingmathematical operation, andreport the answer to thecorrect number of significantfigures.3.96 x 0.1159 = [?]=
Answer
The answer of the mathematical operation to correct number of significant figures is
[tex]3.96\text{ }\times0.1159=0.459[/tex]If you added 1.9 kJ of heat to 100g of completely solid ethyl alcohol (at its melting temperature) and 100 g of completely solid water (at its melting temperature) which of the statements below would be true:A) the ethyl alcohol would be solid and the water liquidB) both substances would be solid C) both substances would be liquidD)the water would be solid and the ethyl alcohol would be liquid.
Both substances would be liquid, option C
___Na+__H2O➡️__NaOH+__H2In a experiment, 2.35g of Na react with 7.25 g of H2O1) write the formula for the reactant that is the limiting reactant
Answer:
Explanations:
Given the unbalanced chemical reaction expressed as:
[tex]aNa+bH_2O\rightarrow cNaOH+dH_2[/tex]The balanced chemical reaction will be expressed as:
[tex]2Na+2H_2O\rightarrow2NaOH+H_2[/tex]Given the following
Mass of Na = 2.35g
Mass of H2O = 7.25g
Determine the moles of the elements
Moles of Na = Mass/Molar mass
Moles of Na = 2.35/.35