9. The first system of measurement that was based on units of ten was the ____ system

Answer:  Atoms cannot be created nor destroyed, and they are indestructible; they cannot be broken into smaller parts. This was based on the Law of Conservation

Explanation: hope this helps you a little!!

Answer:

4. y = 2.38333t - 26.55 is the answer.

The simple solution is to count all the integers that only have odd digits and subtract them from 900. Final solution: 900 – 125 = 775.

Odd and even numbers have opposite parities, therefore 13 is an example of an odd number. In particular, zero has an even parity. The parity of any pair of consecutive integers is opposite. The last digit of an integer stated in the decimal numeral system determines whether the value is even or odd. That example, an odd number is one where the last digit is one, three, five, seven, or nine; otherwise, an even number is one where the last digit is one, two, four, six, or eight.

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The correct answer is true.

The algebraic sum of the inverses of the individual resistances is then the inverse of the equivalent resistance of two or more resistors linked in parallel.

The total or equivalent resistance, RT, is equal to half the value of one resistor if the two parallel resistances or impedances are equal and of the same value. That is equivalent to R/2, R/3, etc., for three parallel resistors of identical value.

The total resistance, RT, will always drop when more parallel resistors are added since the equivalent resistance is always smaller than the smallest resistor in the parallel network.

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Vacuum tubes enjoy numerous upper hands over semiconductor gadgets in applications between 300 MHz and 300 GHz.

A vacuum tube, electron tube, valve (English use), or cylinder (North America), is a gadget that controls electric flow stream in a high vacuum between terminals to which an electric potential distinction has been applied.

The sort known as a thermionic cylinder or thermionic valve uses thermionic emanation of electrons from a hot cathode for basic electronic capabilities like sign intensification and current correction. Non-thermionic sorts, for example, a vacuum phototube, notwithstanding, accomplish electron outflow through the photoelectric impact, and are utilized for such purposes as the discovery of light powers. In the two sorts, the electrons are advanced from the cathode to the anode by the electric field in the cylinder. Sound power speaker utilizing tubes, in activity. Red-orange sparkle is from warmed fibers. Delineation addressing a crude triode vacuum tube and the polarities of the run of the mill dc working possibilities. Not shown are the impedances (resistors or inductors) that would be remembered for series with the C and B voltage sources.

Every group of vacuum tubes (triodes, tetrodes, and their subordinates including magnetrons, klystrons, crossed field speakers, voyaging wave tubes and gyrotrons) have their own qualities as far as working recurrence, quick data transmission, top power, mean power, gain (enhancers), electrical proficiency, linearity, dependability and lifetime. This makes it simpler to choose the most reasonable vacuum tube for a given application.

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Between a negative and positive charge along the line connecting the two charges, the electric field may be zero. if the two charges have the same size. When there is no longer any net force between the two charges, the third charge should be positioned between the two charges.

The internet pressure is the vector sum of all forces acting on an item.

When an item is in equilibrium, whether it is at rest or moving at a constant speed, there is no net force acting on it. A vector can only have magnitudes of zero when all of its components are zero.

In mechanics, the term "net force" refers to the vector sum of all forces acting on a particle or object. The internet pressure, which is a single pressure, replaces the influence of the real forces on the particle's motion. The net pressure is the sum of all forces acting on an item.

Newton's second regulation, which says that F = ma, wherein F represents the net force, can be used to compute the net force. The item's mass is given with the aid of m. Acceleration is a.

The internet force performing on an object is 0 whilst it is in equilibrium, whether it's far at rest or moving at a consistent pace.

handiest whilst all of a vector's components are 0 can a vector have magnitudes of zero. the general pressure acting on an item is referred to as the net force. while the forces are equal and cancel every different out, it will become zero. If there may be a internet force performing on an object, it's going to accelerate in that direction; but, except the object is shifting simple, this is not the same as the path of movement.

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If you double your driving speed, then the stopping distance will be four times the original.

Equations of motion are equations that describe a physical system's behavior in terms of its motion as a function of time. Equations of motion, The three equations of the motion are,

where

S is the distance,

u is the initial velocity,

v is the final velocity,

t is the time,

a is the acceleration.

Given that the car is traveling at a speed and is needed to be stopped, therefore, the car will deaccelerate. Also, the final velocity of the car will become 0. Therefore, we can write,

v² - u² = 2as

Substitute the values,

Therefore, we can write,

v² - u² = 2as₁

(0)² - u² = 2(-a)s₁

-u² = -2as₁

u² = 2as₁

s₁ = u² / 2a

Now, if you double your driving speed. Therefore, we can write,

v² - u² = 2as

Substitute the values,

Therefore, we can write,

v² - u² = 2as₂

(0)² - (2u)² = 2(-a)s₂

-4u² = -2as₂

4u² = 2as₂

s₂ = 4u² / 2a

Since u²/2a is equal to s₁, therefore, we can write,

s₂ = 4(u² / 2a)

s₂ = 4(s₁)

Hence, if you double your driving speed, then the stopping distance will be four times the original.

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The Grand Canyon is 884 m deep from the spot where I heard the echo

The formula for uniformly rectilinear motion (URM) and procedure we will use to solve this exercise is:

v = x /t

Where:

Information about the problem:

Notice that the echo is a sound that is produced when its wave hits an object (Grand Canyon) and returns to the place where it was emitted (person), that is to say that to calculate the time in which the echo arrived effectively to the bottom of the canyon we must divide it by 2.

t(canyon's bottom) = t(echo)/2

t(canyon's bottom)  = 5.2 s/2

t(canyon's bottom)  = 2.6 s

Applying the velocity formula, and isolating the distance, we get:

v = x /t(canyon's bottom)

x = v * t(canyon's bottom)

x = 340 m/s * 2.6 s

x = 884 m

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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By applying the specified constant pressure, the system's work done to reduce its volume from start to final is 32 l atm.

Initial volume v1 = 17.0  l

final volume v2 = 9.0 l

Pressure P= 4.0 atm

When a gas expands, there is an amount of work that is done that is equal to the product of the gas's pressure and its volume change.

We apply the formula for work done by gas against a constant external pressure.

expression: Work done = -(P. d V)

Therefore substituting the values :

Work done = - P (v2 - v1)

= - 4.0 x (-8.0) l atm

= 32 l atm.

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The muzzle velocity of the bullet is 510.3 m/s.

The projectile's speed when it exits the gun's muzzle is known as muzzle velocity.

The quality (burn speed, expansion) and quantity of the propellant, the mass of the projectile, and the length of the barrel all affect the muzzle velocity of conventional firearms. While a slower burning propellant can use a heavier projectile, it requires a longer barrel to burn completely.

Apply the kinematics equation,

v=u+at

Here v is the final velocity, u is the initial velocity, a is the acceleration and t is the time interval during which a body is under acceleration.

The muzzle velocity of a bullet is the velocity with which the bullet leaves contact with the barrel of the gun.

The muzzle velocity or the final velocity of the bullet will be

v=u+at

v=0+(6.3×[tex]10^{5}[/tex])(8.1×[tex]10^{-4}[/tex])
=50.3 m/s

Therefore, the muzzle velocity of the bullet is 510.3 m/s.

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A business entrepreneur has a product or service for the business world, a Social one has ideas for social change, a Serial one has multiple startups and a Lifestyle one starts up their business due to their lifestyles.

A business entrepreneur starts new business with his own money. Some of the famous business entrepreneurs are Steve Jobs, Mark Zuckerberg and Bill Gates. A social entrepreneur develops solutions for social issues and directly addresses them. For example, microfinancing institutions provide banking services to low - income and unemployed people.

A serial entrepreneur can create ideas into successful businesses on a regular basis. They do not stop at one business. Elon Musk is a great example of a serial entrepreneur. A lifestyle entrepreneur creates business to change their lifestyle. A lifestyle entrepreneur does not necessarily make profits. Blogging and photography are some of the examples of lifestyle entrepreneurship.

Therefore,

1. Business Entrepreneur - Has an ideal, product or service for the business world

2. Social Entrepreneur - Has to innovative ideas for social change, solutions, etc.

3. Serial Entrepreneur - Has multiple startups do to new ideas.

4. Lifestyle Entrepreneur - Start up their business due to their lifestyles such as sports hobbies or passions

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Answer:

1. Business

2. Social

3. Serial

4. Lifestyle

If a sample's absorbance reading is higher than 1.0 when being measured with a UV-vis spectrometer, it must be diluted in order to obtain a lower absorbance value.

The logarithm of light transmission (T) through a sample is known as absorbance. Transmission is the difference between the amount of light that passes through a sample and a blank in intensity (I) (Io). Thus, absorbance equals log (Io/I).

At an absorbance of 2, you are at 1%T, which denotes that the sample is blocking (absorbing) 99% of the light that is available. When you have an ABS of 3, you are at 0.1% T, which means that the sample is blocking (absorbing) 99.9% of the light that is available. These ranges fall outside of spectrometers' useful range.

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I will store carolina distance learning kit box in a refrigerator.

To increase their shelf life, they should be refrigerated as soon as they arrive. Keep the lyophilized cultures away from youngsters in a sealed, labeled plastic bag.

Bacteria must be suspended in a medium that supports their viability during freezing, water removal, and subsequent storage if they are to be preserved by lyophilization.

The vials should be put within a freeze-dryer chamber, and the chamber should be vacuumed as directed by the manufacturer. Give the culture enough time to fully lyophilize (dry out).

Water is removed from a product after it has been frozen, and it is then placed in a vacuum, allowing the product to convert directly from solid to vapor without going through a liquid phase. This process is known as lyophilization or freeze drying.

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For getting the mass of the truck, we have to just multiply the volume with the liquid density given and then add up the empty truck mass with it.

A liquid's density is a gauge of how heavy it is relative to the amount being measured or in simpler terms, the density of any kind of liquid is a measure of how much heavy it is for the amount measured.

Any kind of liquid that weighs heavier is termed denser if you weigh two liquids with similar volumes or amounts. A substance which is less dense than water will float if it is gently put on the water's surface.

Just like any kind of solid, the density of a liquid will be equal to the mass of the liquid divided by its volume. i.e., D = m/v.

Mass of the truck = (Volume x liquid density) + empty mass of the truck

= (28,000 x 0.90) + 15,500 kg

= 25,200 + 15,500

= 40,700 kg

Thus the mass of tge truck can be calculated as 40,700 kg.

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A third positive charge [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex] can be placed on the x-axis so that the net electric force on it is zero.

whilst -factor charges are in touch, there may be

[tex]F = k \frac{q_{1}q_{2} }{ r^{2} }[/tex]

Where

[tex]k = 9 * 10^{9} Nm^{2}C^{-1}[/tex] = the coulomb constant.

The charges' magnitudes are [tex]q_{1}[/tex] and [tex]q_{2}[/tex].

r is the separation of the charges.

Let,

The third charge equals Q at, x equals x from the source.

because there is no net force acting on the third charge.

Hence,

[tex]f_{1} + f_{2} = 0[/tex]

⇒ [tex]k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0[/tex]

⇒ [tex]\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0[/tex]

⇒ [tex]\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }[/tex]

⇒ [tex]\frac{\sqrt{2} }{x} = \frac{1}{2a-x}[/tex]

⇒ [tex]2\sqrt{2}a - \sqrt{2} = x[/tex]

⇒ [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex]

handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.

at the same time as the pressure between  identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.

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The magnitude of the acceleration attained by the tool will be [tex]0.2\frac{m}{s^{2} }[/tex]

It is given that the force is acting upon a tool that attains an acceleration. The tool has a certain mass. We know that Force is calculated by the product of mass and acceleration of the object which gives us the following equation:    =>  F = m*a, where F = Force, m = Mass of the object, and a = acceleration attained by the object.

Sp, F = 16N, M = 80 kg, and acceleration = a

Putting these values into the Formula to calculate Force we get :

                 => F = ma    => 16 = 80*a  => a = 16/80

                 => a = 0.2

Hence, we get Acceleration a = [tex]0.2\frac{m}{s^{2} }[/tex]

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By using uniform motion, the time taken to accelerate is 5.21 second.

We need to know about the uniform motion to solve this problem. The uniform motion is an object's motion under acceleration. It should follow the rule

vt = vo + a . t

vt² = vo² + 2a . s

s = vo . t + 1/2 . a . t²

where vt is final velocity, vo is initial velocity, a is acceleration, t is time and s is displacement.

From the question above, we know that

vo = 80 km/h = 80 x 1000/3600 m/s = 22.22 m/s

vt = 110 km/h = 110 x 1000/3600 m/s = 30.56 m/s

a = 1.6 m/s²

By using first equation, we can calculate the time taken

vt = vo + a . t

30.56 = 22.22 + 1.6 . t

1.6t = 8.34

t = 5.21 second

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Answer:

21.4 g/cm3

Explanation:

The thickness of the single sheet of paper is 6.30 × 10-5 m

The thickness can be defined as the measure of the distance between the two surfaces of an object.

It is usually the smallest of three dimensions i.e., length, width, and thickness.

In order to obtain the practical (not the theoretical) thickness of a sheet of paper, the best way would be using a micrometer, dial caliper, or a paper thickness gauge. There is digital as well as analog models of these instruments that can be used while measuring the thickness.

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1500 j is extracted from the cold reservoir when 900 j of work are done on system .

We only need to think about total energy transmitted in terms of work and heat to find a solution to this issue. Essentially, the first law of thermodynamics conjugates this.

Evaluation :

The total work performed in the heat engine is if we consider the heat taken as positive and the heat released as negative.

[tex]W_{1}[/tex] = 2500 - 1000

[tex]W_{1}[/tex] = 1500 j

For the case of the engine pumps the Energy absorbed is

[tex]W_{2}[/tex] = 1500 j

In this way the ratio between the two would be

Ratio  [tex]W_{1} /W_{2}[/tex] = 1

So it is reversible, because the state of efficiency of the body is totally efficient.

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The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

The electric field(E) due to a charge is given by the formula,

E = KQ/r^2

For a point where the electric field is zero, the magnitude of the field due to two charges should be equal so that they cancel each other

Hence, the field produced due to 1.7 uc at the point should be equal to the field produced by the 2.5 uc charge.

Let the distance of the point where the electric field is zero be x from the 1.7 uc.

So, the distance of the point where the field is zero will be (0.125 - x) from 2.5 uc.

K(1.7uc)/x^2 = K(2.5uc)/(0.125 - x)^2

Solving the above equation

x comes out to be 0.056 meters or 5.6 centimeters.

Hence, The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

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The point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

The electric field(E) due to a charge is given by the formula,

E = KQ/r^2                                            equation 1

For a point where the electric field is zero, the magnitude of the field due to two charges should be equal so that they cancel each other

Hence, the field produced due to 1.7 uc at the point should be equal to the field produced by the 2.5 uc charge.

Let the distance of the point where the electric field is zero be x from the 1.7 uc.

So, the distance of the point where the field is zero will be (0.125 - x) from 2.5 uc.

Substitute the values of charges in equation1 and equate the equations for two different charges,

K(1.7uc)/x^2 = K(2.5uc)/(0.125 - x)^2

(1.7uc)(0.125 - x)^2 = (2.5uc) x^2

On simplifying the above equation

x = 0.056 meters or 5.6 centimeters.

Hence, the point where the electric field is zero is situated at a distance of 0.056 meters or 5.6 centimeters from the 1.7 uC charge.

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The nec requires a suspended ceiling grid is used to support lay-in type lighting fixtures - the grid be securely fastened together

Does the NEC deal with spill lighting fixtures or mild pollution?

The national electrical Code does now not deal with the difficulty of "spill lights" or "light pollutants" from one belongings to some other because undesirable illumination isn't a(n) ____________________ trouble.

What have to lighting fixtures intended for set up in wet locations be marked with?

A luminaire installed in a bath, in which it's miles in near proximity to steam and water splash ought to be a humid- or wet-location luminaire and marked “suitable for Damp locations” or “appropriate for moist places.”

What article of the NEC defines outlet and receptacle?

210-21(b) Receptacles A “Receptacle,” as described in Article one hundred, is a contact device hooked up at an outlet for the connection of an attachment plug. The words “receptacle” and “receptacles” appear quite often within the country national electrical Code (NEC).

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The car will take 32.5 seconds to exceed the 65mph.

The speed of a car with a turbo engine can be modeled as a function of time using the parabolic equation

s(t) = 2t

We need to find the time taken by the car to exceed the 65 mph.

Put s(t) = 65 mph

65 = 2t

t = 32.5 seconds

The additional compressed air is then forced into the combustion chamber by a turbine that is powered by the exhaust gas of the turbocharged engine. On the other hand, a supercharged engine employs a mechanically-driven process. This kind of charger is often driven by a crankshaft-mounted belt.

In terms of performance and efficiency, a turbocharged engine is superior to a standard engine. The power output of a smaller capacity turbo engine is equivalent to that of a bigger capacity NA engine.

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1.15.42 Loudness of sound is the power emitted by the burper during his record burp.

Decibels: 112.4

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W is the system's overall work product. When the system performs more work than it does for itself, W is positive. The first law of thermodynamics, U=QW, relates the change in the system's internal energy, U, to heat and work.

The internal energy of a system drops when it interacts with its environment. The internal energy of a system grows when work is done on it. Particles accelerate and pick up kinetic energy when energy is applied to increase the temperature. Potential energy is raised when a substance melts or boils because energy is expended in severing the connections holding the particles together.

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Answer:

According to Newton's second law of motion, the acceleration of a body is directly proportional to the force acting on the body and inversely proportional to its mass. The formula for this law is

a

=

F

m

, from which we get the formula

F

=

m

a

. When mass is in kg and acceleration is in

m/s/s

or

m/s

2

, the unit of force is

kgm/s

2

, which is read as kiligram-meter per second squared. This unit is replaced with an N in honor of Isaac Newton. Your problem can be solved as follows:

Known/Unknown:

m

=

3000kg

a

=

2m/s

2

Equation:

F

=

m

a

Solution:

F

=

m

a

=

3000kg

x

2m/s

2

=

6000kgm/s

2

=

6000N

Explanation:

ikikikiki

Answer:

6000

Explanation:

Answer:

we will feel unstable on the skates. Because the recoil force pushes us forward, and affect our balance

80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.

Given data,

length of bridge = 600m

length of train = 200m

Length of bridge + Length of train is the total distance travelled by train to cross the bridge.

So, 600+200 = 800m = 0.8km

Now, applying the formula for time,

[tex]time =\frac{distance}{speed}[/tex]

[tex]time = \frac{0.8}{36}[/tex]

time = 0.022hours

time in seconds= 0.022×60×60

time in seconds= 1.33×60

time in seconds= 80seconds

Therefore, 80Sec or 1.33 min time taken by train to cross a bridge with a uniform speed of 36 kmph.

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Visible light covers a tiny fraction of the electromagnetic spectrum

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A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is

Given that

To find

So according the question

We have

                       u = 10 m/s.

                      v = 7 m/s.

Now, We have to find the coefficient of restitution

We know that,

         [tex]n = \frac{velocity \;\;of \; \;separation}{velocity \;of \;approach}[/tex]

So,

             [tex]n = \frac{8}{10}[/tex]

              n = 0.8

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