9.0 mol Al reacts with 6.0 mol O2 to
form Al2O3 according to the
reaction below:
4A1+302 → 2Al2O3
How many moles of Al2O3 form from
6.0 mol O2?
[?] mol Al₂O3
Round your answer to the tenths place.
mol ALO
HELP PLS TO MOVE ON !!

Answer: I got you fam

Explanation:

A limiting reactant is a reactant in a chemical reaction that limits the amount of product created.

So for example if there are elements X and Y reacting to create product XY, once say element X runs out, the reaction stops, even though there is still more of the reactant Y. So there is 0 g of element X remaining, and maybe 2 g left of element Y. X is the limiting reactant since it limits the amount of product made.

Theoretical yield is the maximum amount of product that could be made in an experiment. This occurs if a reaction is 100% effective (and experimentally, this doesn't usually happen, which is why it is called theoretical).

Answer:H = 5

Explanation: You would get this answer if you divide by 2 then multiple by 7

Answer:

The name for CH3-CH2-C(O)-OCH3 is ethyl methanoate.

Explanation:

All the balanced chemical equations obey the law of conservation of mass. The numbers which are used to balance the chemical equation are called the coefficients. So here the mass of zinc is 55 g.

According to the law of conservation of mass, the mass can neither be created nor be destroyed but it can be converted from one form to another. The reactants appear on the left hand side and the products appear on the right hand side.

The amount of products is equal to the amount of reactants according to the law of conservation of mass.

25 + 125 = 95 + Zn

Zn = 55 g

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The color of the object appears as yellow/orange.

The visible light spectrum spans a wavelength range of 400 to 700 nanometers (nm), with shorter wavelengths appearing as blue or violet and longer wavelengths as red.

This object is absorbing light with wavelengths between 430 and 400 nm, indicating that it is absorbing light that is visible in the blue and violet spectrum.

We know that this color that we see is actually a complementary color to blue/violet from the color wheel.

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The concept combined gas law is used here to determine the new volume of the balloon. This law relate one thermodynamic variable to another holding everything else constant. The new volume is 4.12 L.

The combination of Boyles law, Charles's law and Avogadro's law gives the combined gas law. This law states that the product of pressure volume and temperature of a system remains constant.

The equation is:

P₁V₁ / T₁ = P₂V₂ / T₂

V₂ = P₁V₁T₂ / P₂T₁

0.7455 × 3.1 × 279.9 / 0.528 × 296.8 = 4.12 L

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Parts B and C of the marble's fall did the marble experience unbalanced forces. Option 4 is correct.

A force is a push or pull (interaction) which changes the momentum of an object, either stationary or in motion when unopposed. All objects experience different forces depending on their environment. When immersed in fluids, unbalanced forces of one upward moving force tends to cancel the gravity force moving downward on a sinking object causing deceleration to a constant sinking speed.

This upward moving force is called as Buoyant force. This is where at part A, the object will experiences a balanced force of gravity which accelerates due to the absence of an opposing force acting upwards on the object. At part B, the speed of the sinking object decreases due to an unbalanced force that cancels the acceleration by the buoyant force. Once the sinking object’s acceleration is cancelled, its sinking speed turns constant at part C.

Hence, 4. is the correct option.

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--The given question is incomplete, the complete question is

"A student used a video camera to record another student dropping a marble through water in a graduated cylinder. The students watched the video in slow motion and made the observations shown below. During which part or parts of the marble's fall did the marble experience unbalanced forces? (1) Part A only (2) Parts A and B only (3) Part C only (4) Parts B and C only."--

The oxidation state of oxygen in magnesium pyrophosphate (Mg2P2O7) is +5.

o calculate the oxidation state of oxygen in magnesium pyrophosphate (Mg2P2O7), we first need to know the oxidation states of the other atoms in the molecule.

The magnesium ion (Mg2+) has a fixed oxidation state of +2 in this compound, and the phosphate ion (PO43-) has an overall oxidation state of -3.

We can set up an equation to solve for the oxidation state of oxygen (O) in the pyrophosphate ion:

2(+2) + 2(O) + 7(-2) = 0

Simplifying the equation gives:

4 + 2O - 14 = 0

2O = 10

O = +5

Therefore, the oxidation state of oxygen in magnesium pyrophosphate (Mg2P2O7) is +5.

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The oxidation number of oxygen in magnesium pyrophosphate is -2.

Oxidation number refers to the hypothetical charge of an atom within a molecule.

For monoatomic ions, the oxidation number always has the same value as the net charge corresponding to the ion.

0 = +2(2) + 5(2) + X(7)

0 = 14 + 7x

-14 = 7x

x = -2

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Answer:430 mg/L = 0.43g/L 

Explanation:

All the 3 chemical species are drawn in the images below/

The E1 reaction mechanism instigates a variant of elimination reactions. It materializes in the vicinity of strong acids or bases and it initiates by eliminating a leaving group from the substrate, consequently creating an intermediate carbocation. Once completed, the mechanism eliminates a proton from a neighborly carbon, initiating the construction process of a double bond.

However, performing an E1 reaction in water may yield unexpected results due to water's nucleophilic nature, catalyzing sneaky attacks on the carbocation intermediates, leading to dissimilar products than initially intended. Furthermore, reactions performed with aqueous media cause other side-products thanks to hydrolysis mechanisms that emerge, making them undesirable.

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The chemical formulas are as follows:

Chemical formulas are shorthand notations used to represent the composition of a substance. In this case, the reactants used in Activity 2 are listed with their chemical formulas.

Barium nitrate is represented by the chemical formula Ba(NO₃)₂, which shows that it contains one barium ion (Ba²⁺) and two nitrate ions (NO₃⁻).

Sodium hydroxide is represented by the chemical formula NaOH, which shows that it contains one sodium ion (Na⁺) and one hydroxide ion (OH⁻).

Sodium hydrogen carbonate is represented by the chemical formula NaHCO₃, which shows that it contains one sodium ion (Na⁺), one hydrogen ion (H⁺), one carbonate ion (CO₃²⁻) and one hydrogen carbonate ion (HCO₃⁻).

Similarly, other reactants are represented by their respective chemical formulas.

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An example of a composition which fulfills the qualifications of being both a base and a weak electrolyte is ammonia (NH3).

A base is any constituent which voluntarily receives protons (H+) in an associated chemical reaction while an electrolyte denotes any material that can conduct electricity through liquids or in melted state.

Upon dissolution in water, it is apt to accept a proton from such and thus create the acidic ion known as ammonium (NH4+). Nonetheless, due to its scarce dissociation into hydroxide (OH-) and ammonium ions, it is deemed a weak electrolyte.

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To prepare a buffer solution of pH 9.00, we need to use the Henderson-Hasselbalch equation:

Where [A-]/[HA] is the ratio of the concentrations of the conjugate base and acid of the buffer, respectively. Since we are given the pH and the overall concentration of the buffer, we can solve for the ratio [A-]/[HA]:

Next, we can use the definition of the concentration of a solution to find the concentration of NH4Cl needed to make a 0.125 mol-L^-1 buffer solution:

0.125 mol-L^-1 = [NH4Cl] + [NaOH]

Since the NaOH solution is 1.00 mol-L^-1, we can assume that the contribution of NaOH to the total concentration of the buffer is negligible, and so:

Finally, we can use the molar mass of NH4Cl to find the mass of NH4Cl needed to prepare 1 L of the buffer solution:

So we need to use 6.63 g of NH4Cl and enough volume of 1.00 mol-L^-1 NaOH solution to make a total volume of 1 L. To find the volume of NaOH solution needed, we can use the definition of molarity:

Rearranging this equation, we get:

Since we are adding NaOH solution to NH4Cl to make a total volume of 1 L, the molality of NaOH solution is also 0.125 mol-L^-1. Therefore:

Substituting the values we know:

So we need to use 6.63 g of NH4Cl and 56 mL of 1.00 mol-L^-1 NaOH solution to prepare 1 L of a buffer solution of pH 9.00.

Answer: I got you fam

Explanation:

The formula is Na2CO3 + ZnI2 → 2NaI + ZnCO3

Or -5.19

Answer:

a. The chemical equation for the reaction is:

2Al + 3H₂SO₄ → Al₂(SO₄)₃ + 3H₂

b. To find the mass of required sulfuric acid, we need to use stoichiometry. We can start by finding the number of moles of aluminum used in the reaction:

Molar mass of Al = 27 g/mol

Number of moles of Al = 5.4 g / 27 g/mol = 0.2 mol

According to the balanced equation, 3 moles of H₂SO₄ are required to react with 2 moles of Al. Therefore, the number of moles of H₂SO₄ required is:

Number of moles of H₂SO₄ = 3/2 x 0.2 mol = 0.3 mol

Molar mass of H₂SO₄ = 2 x 1 g/mol + 32 g/mol + 4 x 16 g/mol = 98 g/mol

Mass of H₂SO₄ required = 0.3 mol x 98 g/mol = 29.4 g

Therefore, 29.4 g of sulfuric acid is required to react with 5.4 g of aluminum.

c. To find the volume of hydrogen gas obtained, we need to use the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is its volume, n is the number of moles of the gas, R is the universal gas constant (0.0821 L atm/mol K), and T is the temperature in Kelvin.

We can start by finding the number of moles of hydrogen gas produced in the reaction. According to the balanced equation, 3 moles of H₂ are produced for every 2 moles of Al. Therefore, the number of moles of H₂ produced is:

Number of moles of H₂ = 3/2 x 0.2 mol = 0.3 mol

Assuming the reaction occurs at standard temperature and pressure (STP), which is 0°C (273 K) and 1 atm, we can use the molar volume of a gas at STP, which is 22.4 L/mol. Therefore:

V = nRT/P = 0.3 mol x 0.0821 L atm/mol K x 273 K / 1 atm = 6.58 L

Therefore, the volume of hydrogen gas produced at STP is 6.58 L.

Explanation:

Answer:

Explanation:

molar mass Cr(NO3)3 = 238 g/mol

Convert 325 ml to liters:  325 mls x 1 L / 1000 mls = 0.325 L

Convert 10.0 g to moles:  10.0 g x 1 mol / 238 g = 0.0420 moles

Molarity = moles/liters = 0.0420 moles / 0.325 L = 0.129 M (3 sig. figs.)

The reaction between calcium nitrate (Ca(NO₃)₂) and sodium oxalate (Na₂C₂O₄) can be represented by the following chemical equation:

Ca(NO₃)₂ + Na₂C₂O₄ → CaC₂O₄ + 2NaNO₃

This is a double displacement reaction, where the calcium ion (Ca²⁺) from calcium nitrate and the oxalate ion (C₂O₄²⁻) from sodium oxalate switch places to form calcium oxalate (CaC₂O₄) and sodium nitrate (NaNO₃). The balanced chemical equation shows that one mole of calcium nitrate reacts with one mole of sodium oxalate to form one mole of calcium oxalate and two moles of sodium nitrate.

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Answer:

To solve this problem, we can use the equation:

Q = m * c * ΔT

where Q is the heat transferred, m is the mass of the substance, c is its specific heat capacity, and ΔT is the change in temperature.

In this case, we know that the heat lost by the metal is equal to the heat gained by the water:

Q lost = Q gained

We can calculate the heat lost by the metal using the equation:

Q lost = m * c * ΔT

where m is the mass of the metal, c is the specific heat capacity of the metal (which we are trying to find), and ΔT is the change in temperature of the metal (100.5 C - 30.2 C = 70.3 C).

We can calculate the heat gained by the water using the equation:

Q gained = m * c * ΔT

where m is the mass of the water and ΔT is the change in temperature of the water (30.2 C - 20.0 C = 10.2 C).

Setting the two equations equal to each other, we get:

m * c * ΔT (metal) = m * c * ΔT (water)

Simplifying, we get:

c (metal) = (m * c * ΔT (water)) / (m * ΔT (metal))

Plugging in the values we know:

m (metal) = 32.8 g

ΔT (metal) = 70.3 C

m (water) = 138.2 g

ΔT (water) = 10.2 C

c (metal) = (138.2 g * 4.184 J/g·K * 10.2 C) / (32.8 g * 70.3 C)

c (metal) = 0.192 J/g·K

Therefore, the specific heat capacity of the metal is 0.192 J/g·K.

The potential across this cell membrane with only potassium channels open is -0.082 V, which means that the inside of the cell is negatively charged relative to the outside.

The potential across a cell membrane can be calculated using the Nernst equation:

E = (RT/zF) ln([ion]out/[ion]in)

 E = potential in volts, R= gas constant (8.314 J/mol*K), T= temperature in Kelvin, z = charge on the ion, F= Faraday constant (96,485 C/mol), and [ion]out and [ion]in are the concentrations of the ion outside and inside the cell, respectively.

K+ (intracellular) ⇌ K+ (extracellular)

The charge on potassium ions is +1, so z = 1.

The temperature is 37°C or 310 K.

The concentrations of potassium ions are [K+]in = 150 mM and [K+]out = 4.0 mM.

Substituting these values into the Nernst equation,

E = (RT/zF) ln([K+]out/[K+]in)

E = (8.314 J/mol.K × 310 K)/(1 × 96,485 C/mol) ln(4.0 mM/150 mM)

E = -0.082 V

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Based on the properties of elements, elements can be arranged into groups in the periodic table as follows:

Group 1 to 3 - metals

Group 14 - non-metals, metalloids, and metals

Group 15 to 18 - non-metals

Groups are the names given to the periodic table's columns. In the table, individuals who belong to the same group make bonds of the same kind and have an equal number of electrons in their atoms' outermost shells.

Periods are the horizontal rows found in the periodic table.

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The concept molarity is an important method which is used to calculate the concentration of a solution. It is mainly employed to calculate the concentration of a binary solution. Here the volume of  barium hydroxide is 21.28 mL.

Molarity of a solution is defined as the number of moles of the solute present per litre of the solution. It is represented as 'M' and its unit is mol/L.

The equation connecting molarity and volume of two solution is given as:

M₁V₁ = M₂V₂

V₁  = M₂V₂ / M₁

0.1002 × 25.00 / 0.1177 = 21.28 mL

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A soft drink contains 33g of sugar in 349g of H[tex]_2[/tex]O. 14.3%  is the concentration of sugar in the soft drink in mass percent.

One approach to indicate the concentration of any dissolved component in a solution is by mass percentage. Mass percentage is the ratio of the total weight of a compound in a solution to the overall mass of the solution, expressed in percentages.

In order to express the mass percent of a solution, the grammes of solute are divided by the grammes of solution, and the result is multiplied by 100. As long as you use a comparable number for both the component and solute mass.

Mass percent = (mass of solute/mass of solute+ mass of solvent)×100

                        = ( 33/ 33+ 349)×100

                         =14.3%

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0.30M is the molarity of the given solution with 0.250 mol and 0.835 L volume of solution

The amount of moles of solute that exist in a specific number of litres of the solution, or moles per litre of a solution, is known as molar concentration or molarity. Solvent, and 'solution' to make it simpler to comprehend the principles that will follow. A homogenous combination with any number of solutes in it is referred to as a solution.

Molarity = number of moles/ volume of solution in liter

Molarity = 0.250/ 0.835

             = 0.30M

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The number of atoms remaining after 4 half-lives can be calculated using the formula: N = N0 /[tex]2^4[/tex] . Therefore, after 4 half-lives, approximately 56,250 atoms of the radioactive substance remain.

Radioactive decay is the process by which a nucleus of an atom loses energy by emitting ionizing radiation. The rate of decay of a radioactive substance is measured by its half-life, which is the time it takes for half of the radioactive atoms in a sample to decay.

N = N0 /[tex]2^n[/tex]

where: N0 = initial number of atoms N = final number of atoms

Substituting the given values,

N = 900,000 / [tex]2^4[/tex]

N = 56,250

Rounding to the nearest whole number,

N ≈ 56,250 atoms

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Answer:

The temperature of the iron block is 68.5°C.

Explanation:

The heat released during condensation of water is used to warm the iron block:

q = m_H2O * ΔH_vap = m_fe * c_fe * ΔT

where q is the heat released, m_H2O is the mass of water condensed, ΔH_vap is the enthalpy of vaporization for water, m_fe is the mass of iron, c_fe is the specific heat capacity of iron, and ΔT is the change in temperature of the iron block.

Rearranging the equation gives:

ΔT = (m_H2O * ΔH_vap) / (m_fe * c_fe)

Substituting the given values gives:

ΔT = (0.95 g * 44.0 kJ/mol) / (75.0 g * 0.449 J/(g°C))

ΔT = 46.5°C

Therefore, the final temperature of the iron block is:

T_f = T_i + ΔT = 22°C + 46.5°C = 68.5°C.

The final temperature of the iron block is 68.5°C.

Answer:

cm=0.385 J

cm = (0.15 kg x 4.18 J/gCx (35C - 30C)) / (70 pieces x 0.1 kg/piece x (120C - 35C))

The answer is:

cm = 0.385 J/gc

Therefore, the specific heat of the metal is 0.385

The sound waves from the siren will reflect off the smooth surface of the wall. The light waves from the emergency vehicle will reflect off the smooth surface of the wall. Rougher sections of the wall surface will cause the light waves from the emergency vehicle to scatter.

When sound waves hit a smooth surface, they reflect off the surface in a predictable way called the law of reflection. So, the sound waves from the siren will reflect off the smooth surface of the wall.

Similarly, light waves also follow the law of reflection when they hit a smooth surface. Therefore, the light waves from the emergency vehicle will also reflect off the smooth surface of the wall.

However, when light waves encounter a rough surface, they scatter in all directions due to the irregularities on the surface. Therefore, rougher sections of the wall surface will cause the light waves from the emergency vehicle to scatter.

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The wavelength of one of the spectral lines for strontium chloride SrCl₂ is approximately 460.7 nanometers (nm).

When strontium chloride SrCl₂ is heated, it emits a characteristic red color, which indicates that it produces spectral lines in the red part of the visible spectrum. The most intense spectral line for SrCl₂ is at approximately 460.7 nm, which corresponds to the transition from the 5² electronic configuration to the 4d state.

This transition is responsible for the red color observed when strontium chloride is introduced to a flame. The wavelength of a spectral line is related to the energy of the transition and is given by

λ = hc ÷ E

where λ is the wavelength, h is Planck's constant, c is the speed of light, and E is the energy of the transition. In the case of SrCl₂, the energy of the transition from 5s² to 4d is approximately 2.69 eV, which corresponds to a wavelength of 460.7 nm.

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The complete question is:

What is the wavelength of one of the spectral lines for strontium chloride SrCl₂?