ok then I don't understand well but I think its 45.10.00
The cost of 2 bunches of
roses and 5 bunches of
carnations is £45.
The cost of 3 bunches of
roses and 4 bunches of
carnations is £50.
Find the cost of one bunch of each
Answer:
vtdOveractivity of the pituitary gland is called hyperpituitarism. Several disorders related to an overactive pituitary gland can occur.
...
Symptoms may include:
Nervousness.Rapid or irregular heartbeat.Weight loss.Fatigue.Muscular weakness.
2 (3) to the power of 3 + 5
Answer:
13122
Step-by-step explanation:
Our equation is 2(3)⁸
once its solve we get 13122 as our answer
which option is right??
Answer:
its the third choice
Step-by-step explanation:
Side angle side cuz there r 2 sides congruent in the picture shown above.
you have to estimate
Answer:
75,388
Step-by-step explanation:
Long Multiplication form
[tex]\mathrm{Mutliply\:the\:bold\:numbers}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&0&\textbf{2}\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&8\end{matrix}}[/tex]
[tex]\frac{\begin{matrix}\space\space&8&\textbf{0}&2\\ \times \:&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply}\\\\8\cdot \:4=32[/tex]
[tex]\mathrm{Carry\:}3\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&9&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}3\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&3&\space\space&\space\space&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Multiply\:the\:top\:number\:by\:the\:bolded\:digit\:of\:the\:bottom\:number}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\textbf{8}&\textbf{0}&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:2\cdot \:9=18[/tex]
[tex]\mathrm{Carry\:}1\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}8\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&1&\space\space\\ \space\space&\space\space&8&0&\textbf{2}\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&\space\space&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:number\:to\:the\:multiplication}:\quad \:1+0\cdot \:9=1[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&\space\space&\textbf{1}&\space\space\\ \space\space&\space\space&8&\textbf{0}&2\\ \space\space&\times \:&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&\space\space&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Mutliply\:the\:bold\:numbers}:\quad \:8\cdot \:9=72[/tex]
[tex]\mathrm{Carry\:}7\mathrm{\:to\:the\:column\:on\:the\:left\:and\:write\:}2\mathrm{\:in\:the\:result\:line}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&\textbf{8}&0&2\\ \times \:&\space\space&\space\space&\textbf{9}&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ \space\space&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:carried\:digit,\:}7\mathrm{,\:to\:the\:result}[/tex]
[tex]\frac{\begin{matrix}\space\space&7&\space\space&1&\space\space\\ \space\space&\space\space&8&0&2\\ \times \:&\space\space&\space\space&9&4\end{matrix}}{\begin{matrix}\space\space&3&2&0&8\\ 7&2&1&8&\space\space\end{matrix}}[/tex]
[tex]\mathrm{Add\:the\:rows\:to\:get\:the\:answer.\:\:\:Fill\:in\:trailing\:zeros\:\:(not\:required)}[/tex]
[tex]\frac{\begin{matrix}\space\space&\space\space&8&0&2\\ \space\space&\times \:&\space\space&9&4\end{matrix}}{\begin{matrix}0&3&2&0&8\\ 7&2&1&8&0\end{matrix}}[/tex] [tex]=75,388[/tex]
See Image for the addition:
Flying against the wind, a jet travels 3780 miles in 6 hours. Flying with the wind, the same jet travels 5950miles in 7 hours. What is the rate of the jet in still air and what is the rate of the wind? 1111 Rate of the jet in still air:
The rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
The given parameters;
distance traveled against the wind, d₁ = 3780 milestime of motion, t₁ = 6 hoursdistance traveled with wind, d₂ = 5950 milestime of motion, t₂ = 7 hoursLet the rate of the jet in still air = R₁
Let the rate of the wind = R₂
The rate of the jet against the wind:
[tex]R_1 - R_2 = \frac{3780}{6} \\\\R_1 - R_2 = 630[/tex]
The rate of the jet with the wind:
[tex]R_1 + R_2 = \frac{5950}{7} \\\\R_1 + R_2 = 850\\\\[/tex]
The rate of the jet in still air is calculated as follows;
[tex]R_1 = \frac{630 + 850}{2} \\\\R_1 = 740 \ mph[/tex]
The rate of the wind is calculated as follows;
[tex]R_1 - R_2 = 630\\\\R_2 = R_1 - 630\\\\R_2 = 740 - 630 \\\\R_2 = 110 \ mph[/tex]
Thus, the rate of the jet in still air is 740 mph and the rate of the wind is 110 mph.
Learn more about rate here:https://brainly.com/question/11664428
Please tell me how much can 6 go into 14 without going over 14
Evaluate the algebraic expression if w= -0.5, x = 2, y= -3, and z = 2.5.
2w^2 - 3x + y - 8z
Answer:
-28.50
Step-by-step explanation:
Given the algebraic expression, 2w² - 3x + y - 8z, where w = -0.5, x = 2, y= -3, and z = 2.5:
Substitute the given values for the variables to evaluate the algebraic expression.
2w² - 3x + y - 8z
= 2(-0.5)² - 3(2) + (-3) - 8(2.5)
= 2(0.25) - 6 - 3 - 20
= 0.50 - 6 - 3 - 20
= -28.50
Therefore, 2w² - 3x + y - 8z = -28.50.
Answer:
-28.5
Step-by-step explanation:
Substitute the values for their given variables and evaluate.
[tex]2w^2-3x+y-8z\\\\2(-0.5)^2-3(2)+(-3)-8(2.5)\\\\2(0.25)-6-3-20\\\\0.5-6-3-20\\\\-28.5[/tex]
(2³ x 2⁵) ÷ 2⁸
Solution
Answer:
it is 1
Step-by-step explanation:
Let's use PEMDAS (do the parenthesis first).
2 to the 3 = 2x2x2 = 8
2 to the 5 = 2x2x2x2x2 = 32
8 x 32 = 256 (all the solutions are factors of 2048).
2 to the 8 = 2x2x2x2x2x2x2x2 = 256 again
256 / 256 = 1
7(x+7)≤56 plz help im bad at math
Answer:x[tex]\geq[/tex]1
Step-by-step explanation:
remove the brackets
7x+49≤56
collect like terms
7x≤56-49
7x[tex]\geq[/tex]7
divide both sides by 7
x[tex]\geq[/tex]1
what is a degree 3 polynomial with integer coefficients with zeros 3, -4, 5
PLS HELP REWARDING A LOT!!
Answer:
157°
Step-by-step explanation:
Sum of interior angles of polygon
(n-2)*180 ---- n = total number of sides
7 angles, 7 sides
5*180 = 900
final angle will be
900-162-115-125-138-105-98
=157
Answer:
157
Step-by-step explanation:
it is obvious that it's a heptagon
so (n-2) x180
n=7
(7-2) x 180 =900
900-162-115-125-138-105-98
900-743=157
final unknown=157°
i need help on this math problem
Answer:
Step-by-step explanation:
Slope: 3/1 (positive: line go uphill)
y-intercept: -5
Place your pencil on the vertical line (y) on -5. Go up 3 units and 1 to the right, repeat and trace the line (actually you only need two points to trace a line)
2 - 2x 4x + 12
------- = ---------
4 3
[tex]\tt\frac { 2 - 2 x } { 4 } = \frac { 4 x + 12 } { 3 }[/tex]
[tex]\tt3\left(2-2x\right)=4\left(4x+12\right) [/tex]
[tex]\tt6-6x=16x+48 [/tex]
[tex]\tt6-6x-16x=48 [/tex]
[tex]\tt6-22x=48 [/tex]
[tex]\tt-22x=42 [/tex]
[tex]\tt\:x=\frac{42}{-22} [/tex]
[tex]\boxed{\tt\:x = -\frac{21}{11} = -1\frac{10}{11} \approx -1.90}[/tex]
Method used :-
◇ ✖ Cross multiplication ❌
________
Hope it helps ⚜
Step-by-step explanation:
Given equation is [{(2-2x)/4} = {(4x+12)/3]
On applying cross multiplication then
Since, (a/b) = (c/d)
⇛ab = bc
Where, a = (2-2x), b = (4), c = (4x+12) and d = (3).
Now,
⇛3(2-2x) = 4(4x+12)
Multiply the number outside the bracket with numbers and variables in the bracket.
⇛6 - 6x = 16x + 48
Shift the variable value on LHS and constant on RHS.
⇛-6x - 16x = 48-6
Subtract the values on LHS and RHS.
⇛-22x = 42
Shift the value (-22) from LHS to RHS.
⇛x = 42/-22
Write the obtained answer in lowest form by cancelling method.
⇛x = (42÷2)/(-22÷2)
Therefore, x = 21/-11 = -(21/11)
Answer: Hence the value of x for the given problem is -21/11.
VERIFICATION:
If x = -21/11 then the equation is
[{(2-2x)/4} = {(4x+12)/3]
Substitute the value x = -21/11 in expression, then
⇛[{2-2(-21/11)}/4 = {4(-21/11)+12}/3]
Multiply (-2) from (-21) to get 42 on LHS.
⇛[{2(42/11)}/4 = {4(-21/11)+12}/3]
Again multiply 4 from (-21) to get 81 on RHS.
⇛[{2(42/11)}/4 = {(-81/11) + 12}/3]
Take the LCM of the denominator 1 and 11 is 11 on LHS
⇛[{(2*11 + 42*1)/11}/4 = {(-81*1 + 12*11)/11}/3]
Multiply the numerator on both LHS and RHS.
⇛[{(22+42)/11}/4 = {(-81 + 132)/11}/3]
Add the numerator numbers on both LHS and RHS
⇛[{(64/11)}/4 = [{(48/11)}/3]
Now, conver the division fraction in multiply fraction on both LHS and RHS.
⇛[{(64/11) * 4} = {(48/11) * 3}]
Now, write the numbers in Lower form by cancelling method, on both LHS and RHS.
⇛(16/11) = (16/11)
LHS = RHS
Please let me know if you have any other questions.
100 Points
Emily wants to buy turquoise stones on her trip to New Mexico to give to at least 4 of her friends. The gift shop sells small stones for $4 and large stones for $6, and Emily has no more than $30 to spend.
Write and graph a system of Linear Equations and write two possible solutions.
Answer:
Step-by-step explanation:
what is she going to buy? Small stones or big stones? if its small stones then she can buy 7 small stones. If its big stones then she can buy 5 big stones.
HELP ME PLEASE!!!!!!!!!!!
Answer:
SAS theorem >This is the correct
Answer:
SSS theoremStep-by-step explanation:
[tex] \huge\colorbox{pink}{hope \: its \: help}[/tex]
6^3 multiplied by (1/2)^3
Step-by-step explanation:
6³×(½)³
=> 216÷8 = 27.
hope this helps you.
Which of the following could be a helpful first step in solving this equation for q?
p2q+2q=11
Question 5 options:
Combine p2q+2q
Divide the whole equation by 11.
Divide the first term by p2
Factor a q out of p2q+2q
Answer:
D: Factor a q out of p^2 q+ 2q
Step-by-step explanation:
I took the test. Hope it was helpful! :)
The first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, the equation is,
p²q+2q=11
Take q common from the L.H.S as
q(p²+2)=11
The value of q is obtained by rearranging the equation as,
q=11/(p²+2)
The value of q obtained after solving the equation p²q+2q=11 will be q=11/(p²+2).
Thus, the first step in solving this equation p²q+2q=11 for q will be to factor q out of p²q+2q. Option D is correct.
Learn more about the equation here,
https://brainly.com/question/10413253
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Help !!!!!!!!!!!!!!!!!!!!
Answer:
Step-by-step explanation:
One must rearrange the function to decreasing value of exponents
f(x) = -7x⁴ + 8x³ - 3x² - 9x + 11
to see that it is a 4th degree polynomial with leading coefficient of -7
Which expression is the factored form of−4.5n+3?
−1.5(3n+2)
−3(1.5n+1)
−3(1.5n−1)
−1.5(−3n+2)
Answer:
— 3 (1.5n — 1)
Step-by-step explanation:
[tex] - 4.5n + 3 = - \frac{9}{2} n + 3 = 3( - \frac{3}{2} n + 1) = - 3( \frac{3}{2}n - 1) \\ = - 3(1.5n - 1)[/tex]
What is the value of w?
Answer:
w= -2. Solve for w: (w-5) (w+2) = w^2-4. Expand out terms of the left hand side: w^2-3 w-10 = w^2-4. Subtract w^2-4 from both sides
Step-by-step explanation:
Y=4x+8 y=-x-7 solve by substitution
Step-by-step explanation:
Alrighty! here you go image.
Answer:x=15
Step-by-step explanation:
find the integral.......
Answer:
1/5(2ln|x|+3*5^1/3)+c
Step-by-step explanation:
2.
Fit a quadratic function to these three points:
(−2, 8), (0, −4), and (4, 68)
A. y = −2x2 − 2x − 4
B. y = 4x2 + 2x − 4
C. y = −4x2 − 2x − 4
D. y = −2x2 + 2x − 4
Answer:
It's C.
Step-by-step explanation:
Answer:
B
Step-by-step explanation:
just put the x and y values into the equations and see which equation stays true.
for example, point (4, 68) rules out A and C even without detailed calculation, because these 2 expressions can produce for positive x only negative y (and 68 is clearly a positive y).
so, when using this point in B :
68 = 4×4² + 2×4 - 4 = 4×16 + 8 - 4 = 64 + 8 - 4 = 68
correct.
and it is correct also for the other points.
so, B is the right answer.
50 points + brainliest answer questions 7 and 8 with work and all
Answer:
7) m∠BHE = 146°
8) m∠BAC = 25°
Step-by-step explanation:
Question 7:Given that, [tex]\displaystyle\mathsf{\overline{CD}\:||\:\overline{EF}}[/tex], and that [tex]\displaystyle\mathsf{\overline{AB}}[/tex] is a transveral.
We are also provided with the following measures of the angles: m∠DGH = 2x, and m∠FHB = 5x - 51.
∠DGH and ∠FHB are also corresponding angles, as they have corresponding positions on the same side of the transversal, [tex]\displaystyle\mathsf{\overline{AB}}[/tex]. These two angles also have the same measure.
Solve for x:In order to find the measure of ∠BHE, we could set up an equality statement on ∠DGH and ∠FHB to solve for the value of x.
m∠DGH = m∠FHB
2x = 5x - 51
Add 51 and subtract 2x from both sides of the equation:
2x -2x + 51 = 5x - 2x - 51 + 51
51 = 3x
Divide both sides by 3:
[tex]\displaystyle\mathsf{\frac{51}{3}\:=\:\frac{3x}{3}}[/tex]
x = 17
⇒ m∠DGH = 2x = 2(17) = 34°,
⇒ m∠FHB = 5x - 51 = 5(17) - 51 = 34°.
Since ∠FHB and ∠BHE are supplements (whose sum add up to 180°), we could determine the measure of ∠BHE as follows:
m∠BHE + m∠FHB = 180°
m∠BHE + 34° = 180°
m∠BHE + 34°- 34° = 180°- 34°
m∠BHE = 146°.
Therefore, the measure of ∠BHE is 146°.
Question 8:Given that ΔABC with [tex]\displaystyle\mathsf{\overline{AC}}[/tex] extended to D, and that m∠ABC = 63° and m∠BCD = 92°:
The Exterior Angle Theorem states that the measure of an exterior angle of a triangle is equal to the sum of the two nonadjacent interior angles. In other words: ∠BCD = ∠BAC + ∠ABC.
Before we could apply the Exterior Angle Theorem, we must first find m∠BAC. Since ∠BCD and ∠BCA are supplements:
m∠BCD + m∠BCA = 180°
92° + m∠BCA = 180°
92° - 92°+ m∠BCA = 180° - 92°
m∠BCA = 88°
Solve for m∠BAC:Now that we have the measure for ∠BCA, we can find m∠BAC by applying the Triangle Sum Theorem where it states that the sum of the interior angles of a triangle is equal to 180°.
m∠BCD + m∠ABC + m∠BAC = 180°
92° + 63° + m∠BAC = 180°
125° + m∠BAC = 180°
155° - 155° + m∠BAC = 180° - 155°
m∠BAC = 25°
Therefore, the measure of ∠BAC is 25°.
which of the following are perfect cubes 1)3375 2)8000 3)6859
Answer:
all are perfect cubes
Step-by-step explanation:
you can just cube root the numbers and bom if it aint decimal its a perfect cube
one added to the square root of the sum of a number and one is equal to four. find the number
[tex]\stackrel{\textit{one added to the }\sqrt{\qquad }}{1+\sqrt{\quad }}~~,~~ \stackrel{\sqrt{~~}\textit{ of a number and one}}{\sqrt{x+1}}\implies 1+\sqrt{x+1}\stackrel{\textit{equals}}{=}4 \\\\\\ \sqrt{x+1}=3\implies \left( \sqrt{x+1} \right)^2=3^2\implies x+1=9\implies \boxed{x=8}[/tex]
-7(8) What is it please help me I need help help help help
Compare the expressions 7+3^2-2⋅5 and (3/4+1/8)÷1/8 using , =, or . Show your work. Answer:
[tex]A=7+3^2 -2 \cdot 5 = 7 + 9 - 10 = 9-3=6\\\\\\B = \left(\dfrac 34 + \dfrac 18\right) \div \dfrac 18 = \dfrac 78 \times 8 =7\\\\\\B>A[/tex]
The expression relation is 7+3²-2⋅5 > (3/4+1/8)÷1/8.
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Given:
First, 7+3²-2⋅5
Solving the above expression
= 7 + 9 -2.5
= 16 - 2.5
= 13.5
Second,
(3/4+1/8)÷1/8
= (6/8 + 1/8) ÷ 1/8
= 7/8 ÷ 1/8
= 7/8 x 8/1
= 7
Hence, 7+3²-2⋅5 > (3/4+1/8)÷1/8.
Learn more about Inequality here:
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The height of a parallelogram is 6[tex]a^{2}[/tex][tex]b^{5}[/tex] and the base of a parallelogram is 4[tex]a^{3}[/tex][tex]b^{4}[/tex] Find the area of the parallelogram using the formula A = bh
[tex]\text{Area of parallelogram} = \text{Base}~ \times~\text{Height} = (4a^3b^4)(6a^2 b^5)=24a^5 b^9[/tex]
List all the factors pairs in the table 64
(1, 64), (2, 32), (4, 16), (8, 8).
Answer:
1 x 64
2 x 32
4 x 16
8 x 8
Step-by-step explanation:
Factors of 64: 1, 2, 4, 8, 16, 32 and 64.
Pairs:
1 x 64
2 x 32
4 x 16
8 x 8
Hope this helps :)