Answer:
is this a mudder question
Please help me out with this one???
Answer:
take another pic i cant see it
Explanation:
Mark is pushing a box down the hall. Mark is using 5N to push the box 20m. How much work is Mark doing?
Answer:
The answer is 100 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distanceFrom the question
force = 5N
distance = 20m
We have
workdone = 5 × 20
We have the final answer as
100 JHope this helps you
Why does the crane need a counterbalance?
Answer:
To make the lifting more efficient. It lets there be less taxing and saves a ton of energy!!
Explanation:
help ASAPPPPPPPPPPPPP pls
Answer:
The answer for this question is
D
A falcon is diving at a speed of 30m/s. It accelerates at a rate of 40m/sand reaches a speed of
100m/s. Calculate the distance it travels during its acceleration.
Answer:
Reasd through the explanartion first :)
Explanation:
Initial velocity, u = 30 m/s
Final velocity, v = 100 m/s
Acceleration, a = 40 m/s²
Distance traveled, s = ?
According to the 3rd equation of motion,
We know that,
v² - u² = 2as
So, putting all the values, we get
⇒ v² - u² = 2as
⇒ (100)² - (30)² = 2 × 40 × s
⇒ 10000 - 900 = 80s
⇒ 9100 = 80s
⇒ 9100/80 = s
⇒ s = 113.75 m.
If a car that is moving 20.0 m/s has a momentum of 29000 kg·m/s, what mass is the car?
Answer:
Mass = 1450kg
Explanation:
P = M * V (where p is momentum, m is mass and v is velocity)
29000 = 20 * M
M = 29000 / 20
M= 1450 kg
In Newton’s second law, if the net force acting on object doubles. The object’s Will also double
Answer: Explanation:
If the net force on an object is doubled, its acceleration will double If the mass of an object is doubled, the acceleration will be halved .
In Newton’s second law, if the net force acting on object doubles then either acceleration is double or mass is double.
What is force?A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.
According to Newtons second law force is product of mass and acceleration.
F = ma
In Newton’s second law, if the net force acting on object doubles then either acceleration is double or mass is double.
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A school bus moves slower and slower. Using what you have learned about forces, explain why the bus moves slower and slower.
Explanation:
the weight of the people inside the bus
One Newton equals .225
A 52-kg bike is moving along a smooth road at a constant velocity of 8.4 m/s. What is the net force acting on the bike
Answer:
0 N
Explanation:
Net force = mass × acceleration
∑F = ma
The velocity is constant, so the acceleration is 0. Therefore, the net force is 0.
The net force acting on the bike is 0 N.
What is net force?Net force is the sum of all forces acting on an object. The net force can be calculated using Newton's second law, which states that F = ma, where: F is the net force. m is the mass of the object. a is acceleration.
The velocity is constant, so the acceleration is 0. Therefore, the net force is 0 N.
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A driver in a 500 kg car going 20 m/s sees a large box in the middle of the road 100 meters away. How much net force is required to get the car to stop without hitting the box?
50 POINTS AND WILL GIVE BRAINLY! THIS IS URGENT
Answer:
100
Explanation:
my apologies if I am wrong
A wave has a frequency of 8 Hz, how long is the period?
A 16
B .125
C 64
D 8
Answer:
A is the answer because if you multiply 8 and 2 the period of wave frequency is 16Hz long.
Explanation:
Answer:
B 0.125 its a simple conversion
If the radius of atom is 4 × 10^-3 nm (Nano meter), so its diameter is: *
8 × 10^-12 m
8 × 10^-3 µm
8 × 10^-6 km
8 × 10^-9 cm
Answer:
8 x 10^-12
Explanation:
Radius = 4 x 10^-3nm = 4 x 10^-12 m
by the formula,
diameter = 2 x radius
diameter = 2 x (4 x 10^-12)
diameter = 8 x 10^-12 m
1.Which of the following are examples of projectile motion
a. a airplane taking off
b.a tennis ball lobbed over a net
c. a plastic disk sailing across a lawn
d.a hawk diving to catch a mouse
e. a parachutist drifting to Earth
f. a frog jumping from land into the water
Answer:
b and f
Explanation:
Following are examples of projectile motion: a. A tennis ball lobbed over a net c. A plastic disk sailing across a lawn d. A hawk diving to catch a mouse e. A parachutist drifting to Earth. The correct options are A, C, D and E.
Projectile motion refers to the motion of an object that is launched into the air and moves along a curved trajectory under the influence of gravity alone, with no other forces acting horizontally. In projectile motion, the object follows a path called a parabola.
In the given options, a tennis ball being lobbed over a net, a plastic disk sailing across a lawn, a hawk diving to catch a mouse, and a parachutist drifting to Earth all demonstrate projectile motion. In each case, the objects are initially launched or propelled into the air and subsequently follow a curved path influenced primarily by gravity. The trajectory of these objects can be described by a parabolic shape, which is a characteristic of projectile motion.
The correct options are A, C, D and E.
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Two conducting loops of the same diameter, #1 made of copper and #2 made of aluminum wires of the same length and cross-sections are placed on the horizontal surface in uniform magnetic field directed vertically up. Magnetic field vanishes suddenly. The magnitude of emf in loop #1 is
Answer:
Same as loop #2
Explanation:
The magnitude of emf in loop #1 is the same as that of loop #2
HELP PLEASE AND HURRRRRY
How far a projectile moved horizontally from its starting point is its...
A. trajectory
B. Elipse
C. Range
D. Projectile
Answer:
the path the object follows is called its trajectory so A. trajectory
all known frequencies of the visible spectrum are..
a. solar light
b. light
c. black light
Explanation:
[tex]b. \: light[/tex]
what cells secrete myelin for neurons?
a. schwann cells
b. other neurons
c. osteocytes
d. leukocytes
Answer:
A. Schwann cells
Explanation:
A weight lifter raises a mass of 50kg through a height of 2m. He does this 25 times in one minute. Find his
average power.
Answer:
[tex]average power = 416.67 \: W
[/tex]
Explanation:
[tex]are \: you \: sure \: this \: is \: a \: man \: or \: robot?......haha. \\ the \: average \: power \: is \: given \: by : \\ p_{(a.v)} = \frac{w}{t} \: but \: work \: or \: energy \: expanded \: is \: given \: by : \\ w = \: fs = mgs \: \: therfore, \: p_{(a.v)} = \frac{mgs}{t} \\ note \: the \: followng : \\ p_{(a.v)} = average \: power, \\ w = work \: done \: or \: energy \: expanded, \\ f = force \: due \: to \: gravity \: = weight = mg, \\ s = distance = height = 2m \times 25 \: lifts, \: m = mass = 50kg, \\ \: g \: = \: acceleration \: due \: to \: gavity = 10 {m(s)}^{ - 2} and \: t = time = 60s.
\\ so \: what \: now, ok \: lets \: find \: p_{(a.v)} . \\ p_{(a.v)} = \frac{mgs}{t}= \frac{50 \times 10 \times 50}{60} = 416.66666667 \: watts.[/tex]
A gust of wind blows an apple from a tree. As the apple falls, the force of gravity on the apple is 9.11 N downward, and the force of the wind on the apple is 1.18 N to the right. What is the magnitude of the net external force on the apple? Answer in units of N. Part 2: What is the direction of the net external force on the apple (measured from the downward vertical, so that the angle to the right of downward is positive)? Answer in units of ◦
Answer:
The net external force on the apple is 9.18 N and the direction of net force is 82.6°.
Explanation:
Given that,
Force of gravity = 9.11 N
Force of wind = 1.18 N
We need to calculate the net external force on the apple
Using formula of net force
[tex]F'=\sqrt{(9.11)^2+(1.18)^2+2\times1.18\times9.11\cos90}[/tex]
[tex]F'=9.18\ N[/tex]
We need to calculate the direction of net force
Using formula of direction
[tex]\theta=\tan^{-1}(\dfrac{9.11}{1.18})[/tex]
[tex]\theta=82.6^{\circ}[/tex]
Hence, The net external force on the apple is 9.18 N and the direction of net force is 82.6°.
The magnitude of the net external force on the apple is 9.19 N and the direction of the net external force is 82.6⁰.
The given parameters;
weight of the apple, W = 9.11 Nhorizontal force on the apple, F = 1.18 NThe magnitude of the net external force on the apple is calculated as follows;
[tex]F= \sqrt{F_y^2 + F_x^2} \\\\F= \sqrt{9.11^2 + 1.18^2} \\\\F = 9.19 \ N[/tex]
The direction of the net external force on the apple is calculated as follows;
[tex]\theta = tan^{-1}(\frac{F_y}{F_x} )\\\\\theta = tan^{-1}(\frac{9.11}{1.18} )\\\\\theta = 82.6 \ ^0[/tex]
Thus, the magnitude of the net external force on the apple is 9.19 N and the direction of the net external force is 82.6⁰.
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A car has a velocity of 10m/s.it now accelerates for 1m/s for 1/4 minutes. Find the distance travelled in this time and final speed of the car
¡Hellow!
For this problem, lets recabe information:
v (Velocity) = 10 m/s
a (Aceleration) = 1 m/s²
t (Time) = 1/4 min = 25 s
d (Distance) = ?
v' (Final velocity) = ?
First, for calculate distance, lets applicate formula:
[tex]\boxed{\boxed{\text{d = Vo * t + (a * t}^{2})\text{ * 0,5} } }[/tex]
Lets replace according we information and let's resolve it:
d = 10 m/s * 25 s + (1 m/s² * (25 s)²) * 0,5
d = 250 m + (625 m) * 0,5
d = 2,5 m + 312,5 m
d = 314 meters.
Now, for calculate final speed, lets applicate formula:
[tex]\boxed{\boxed{\text{v' = v + a * t} } }[/tex]
Lets replace according we information and let's resolve it:
v' = 10 m/s + 1 m/s² * 25 s
v' = 10 m/s + 25 m/s
v' = 35 m/s
¿Good Luck?
Att: That guy who use the "ñ".
a blwoing ball traveling 2.0 m/s has a 16 J of Kinetic energy what is the mass of the bowling ball in KG
Answer:
ke=1/2mv2Explanation:
16=m(2)*2
16=m4
m=16÷4
m=4
Two technicians are discussing the FMVSS 135 standards for parking brakes. Technician A states that the hand force required to set the brake should not exceed 80 lb. Technician B states that the foot force to set the brake should not exceed 80 lb. Which technician is correct?
Answer:
Technician A
Explanation:
Technician A is correct because, the hand force required is not supposed and even should not exceed 80 lb.
On the other hand, the foot force limit is even higher at 100 lb. Thus, the required foot force break should not exceed 100 lb. We are given 80 lb in the question, which is quite less than 100 lb. It could exceed 80, but must not exceed 100. Thus only Technician A is correct among them both.
Study the motion map shown. Some of the vectors have been circled. A long black arrow pointing right labeled x. Above that are 5 green arrows of the same length pointing right, positioned end to end. Next to these are 2 shorter green arrows, each with small yellow arrows pointing left just above that are circled. Farther up from the line is a point. Much farther above that are 3 green arrows each longer than the previous. Above the green arrows are 3 yellow arrows of equal length pointed left, each circled. What do the circled vectors represent? distance speed velocity acceleration
Answer:
The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.
Explanation:
Sample Response: The object starts away from the origin and then moves toward the origin at a constant velocity. Next, it stops for one second. Finally, it moves away from the origin at a greater constant velocity.
What did you include in your description? Check all that apply.
The object starts away from the origin.
The object moves toward the origin at a constant velocity.
The object stops for one second.
The object moves away from the origin at a greater constant velocity.
The circled vectors represent speed.
What is speed?
The is the ratio of distance traveled to time of motion. Speed is a scalar quantity because it has only only magnitude.
From the map, as the magnitude (size) of the green arrows changes, the size of the circled arrows changes accordingly.
Also, the direction of the circled arrow was constant for both top and bottom arrows.
Velocity changes with direction BUT speed does not change with direction, and has a complete meaning with only magnitude.
Thus, the circled vectors represent speed.
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can someone help me answer this? i dont get it and I need help before the next 30 minutes. ill give a brainiest to whoever helps me tyyy :)
Answer:
S=5.83...
Explanation:
s=d/t
Speed=distance/time
s=35/10
s=5.83...
Which unit you would use to measure the following objects? This is so confusing
Answer:
weight of truck in kg, height of person in meter m, amount of water in kiloliter kl, length of eyelash in mm
What happens to the lost mass during nuclear reactions in a star's core?
O It is destroyed
O It becomes dark matter
O It is ejected into space
O It is converted to energy
A 40kg box sits on a shelf 0.5m above the floor. An employee moves the box to a height of 1.8m above the floor. How much work did the employee do in moving the box? A)20J B)72J C)200J D)520J E)720J
Answer:
b)72
Explanation
work done= force* distance
work done=40*1.8
72J
A fixed particle with charge –8.8 nC and a second particle with charge –4.3 nC, respectively, are initially separated by a distance of 0.11 m. They are released and the second particle moves 0.030 m. A) What is the change in electric potential energy? B) Did the second particle move toward or away from the source charge?
Answer:
(a). The change in electric potential energy is 8.3 μJ.
(b). The second particle moves away from the source charge.
Explanation:
Given that,
Charge of first particle = -8.8 nC
Charge of second particle = -4.3 nC
Distance = 0.11 m
They are released and the second particle moves 0.030 m,
(a). We need to calculate the change in electric potential energy
Using formula of potential energy
[tex]U=\dfrac{Kq_{1}q_{2}}{d}[/tex]
Change in potential energy
[tex]\Delta U=\dfrac{kq_{1}q_{2}}{d_{2}}-\dfrac{Kq_{1}q_{2}}{d_{1}}[/tex]
Put the value into the formula
[tex]U=\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.030}-\dfrac{9\times10^{9}\times(8.8\times10^{-9}\times4.3\times10^{-9})}{0.11}[/tex]
[tex]\Delta U=0.000008256\ J[/tex]
[tex]\Delta U=8.3\ \mu J[/tex]
(B). We need to find the second particle move toward or away from the source charge
We know that,
Both charges are same, so the second particle will be repul from the source charge.
So, The second particle moves away from the source charge.
Hence, (a). The change in electric potential energy is 8.3 μJ.
(b). The second particle moves away from the source charge.
Three identical 6.4kg masses are hung by three identical springs. Each spring has a force constant of 7.8 Kn/m and is 12cm long before any masses are attached to it. how long is the bottom most spring going to be after the three masses are hung on it
a. 14.3 b. 16.2 c.12.8 d.10.7
Answer:
The correct option is;
c. 12.8 cm
Explanation:
The given parameters are;
The length of each spring = 12 m = 0.12 m
Given that the masses and the springs are vertically oriented, we have;
The mass on the first spring = 3 × 6.4 = 19.2 kg
The weight on the first spring = 19.2 kg × 9.81 m/s² = 188.352 N
The extension of the first spring = 188.352 N/7,800 N/m ≈ 0.02415 m
The mass on the second spring = 2 × 6.4 = 12.8 kg
The weight on the second spring = 12.8 kg × 9.81 m/s² = 125.568 N
The extension of the second spring = 125.568 N/7,800 N/m ≈ 0.016098 m
The mass on the third spring = 1 × 6.4 = 6.4 kg
The weight on the third spring = 6.4 kg × 9.81 m/s² = 62.784 N
The extension of the third (bottom) spring = 62.784 N/7,800 N/m ≈ 0.00805 m
The total length of the bottom spring = Original length of the bottom spring + Extension of the bottom spring
The total length of the bottom spring ≈ 0.12 m + 0.00805 m = 0.12805 m
The total length of the bottom spring ≈ 0.12805 m ≈ 12.81 cm
The bottom spring will be approximately 12.81 cm long.