A 0.530 M Ca(OH)2 solution was prepared by dissolving 36.0 grams of Ca(OH)2 in enough water. What is the total volume of the solution thus formed?

Answers

Answer 1

Answer:

0.917

Explanation:

Answer 2

Answer:

0.917

Explanation:

Just took the test


Related Questions

A sample of O2 with an initial temperature of 50.0 oC and a volume of 105 L is cooled to -25 oC. The new pressure is 105.4 kPa and the new volume is 55.0 L. What was the initial pressure of the sample? Show your work, using the G.U.E.S.S. method.

Answers

Answer:

71.92 kPa

Explanation:

Using the combined gas law equation;

P1V1/T1 = P2V2/T2

Where;

P1 = initial pressure (kPa)

P2 = final pressure (kPa)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

T1 = 50°C = 50 + 273 = 323K

V1 = 105L

T2 = -25°C = -25 + 273 = 248K

P2 = 105.4 kPa

P1 = ?

V2 = 55.0 L

Using P1V1/T1 = P2V2/T2

P1 × 105/323 = 105.4 × 55/248

105P1/323 = 5797/248

0.325P1 = 23.375

P1 = 23.375 ÷ 0.325

P1 = 71.92 kPa

How many formula units are there in 14.50 moles of any compound?
___X 10^___formula units

Answers

Answer:

8.73 × 10²⁴ formula units

Explanation:

To calculate the number of formula units a substance contain, we multiply the number of moles by Avagadro number (6.02 × 10²³)

number of formula units = 14.50 moles × 6.02 × 10²³

= 87.29 × 10²³

= 8.73 × 10²⁴ formula units.

Is this an alpha or beta decay?

Answers

it would be a alpha decay

Which of these events is likely to have caused the mass extinction of the dinosaurs?

A.An increase in Earth's overall temperature

B. A large volcanic eruption on nearby islands

C. The fallout of a meteor colliding with Earth's surface

D. Rising sea levels flooding low-lying coastlines

Answers

Answer is D! Hope I could help

PLEASE HELP MEEEEEEEEEEEEE

Answers

Answer:

Explanation:

THE BEST ANSWER IS CCC

Electrical charge of an alpha particle is,

A. +1

B. +2

C. +3

D. +4

Answers

Electrical charge alpha particle is +2
Plus 2 is the correct answer have a nice day

What two metals are have atoms larger than that of sodium

Answers

Answer: potassium and rubidium

Explanation:

1) The group 1 of the periodic table contain six elements namely Lithium(Li), Sodium(Na),Potassium(K),Rubidium(Rb),Cesium(Cs) and Francium(Fr). These metals are called alkali metals because they form alkalies( i.e. strong bases capable of neutralizing acids) when they react with water.

2) The heavier alkali metals (K, Rb, and Cs) react so vigorously that they invariably explode.

3) This trend, which is not consistent with the relative magnitudes of the reduction potentials of the elements, serves as another example of the complex interplay of different forces and phenomena—in this case, kinetics and thermodynamics.

the tissue which continually forms new cells in plants​

Answers

Answer:

Meristematic Tissues. Tissues where cells are constantly dividing are called meristems or meristematic tissues. These regions produce new cells.

Explanation:

thank me later

28. Which of the following reactions at equilibrium would NOT be affected by volume
changes at constant temperature?
a. 2 CO(g) + O2(e) < > 2 CO2(g)
b. 2 NO2(g) → N2048)
c. 2 NO(g) + 3 F2(g) → 2 F3NO(e)
d. O3(e) + NO(g) + > NOzle) +
e. None of the above.
Ozig)

Answers

Answer:

Explanation:

is the

Mole ratios used for conversions come from?​

Answers

A mole ratio is a conversion factor that relates the amounts in moles of any two substances in a chemical reaction. The numbers in a conversion factor come from the coefficients of the balanced chemical equation.

Someone please help me

Answers

Answer:reflection

Explanation:

What is the rate of diffusion of NO gas to CO gas?

Answers

Answer:

0.97

Explanation:

Let R₁ represent the rate of diffusion of NO.

Let R₂ represent the rate of diffusion of CO.

Molar mass of NO (M₁) = 14 + 16 = 30 g/mol

Molar mass of CO (M₂) = 12 + 16 = 28 g/mol

Thus, the rate of NO to CO can be obtained as follow:

R₁ /R₂ = √(M₂/M₁)

R₁ /R₂ = √(28/30)

R₁ /R₂ = √(28/30)

R₁ /R₂ = 0.97

R₁ : R₂ = 0.97

NO : CO = 0.97

Therefore, the rate of diffusion of NO to CO is 0.97

How much energy required to raise the temperature of lead by the same degrees.

Answers

Answer:

If a one kilogram block of lead absorbs 2,000 J of energy then the temperature rise will be larger. If 1,000 J of heat is absorbed by a 2 kg block of lead then the temperature of the block doesn't rise as much since the energy is shared between more particles.

Explanation:

a gas with a volume of 20.0l at a pressure of 275 kpa is allowed to expand to a volume of 35.0l. what is the pressure in the container if the temperature remains constant?

1. 2.54 kPa

2. 157 kPa

3. 481 kPa

pls help ;(

Answers

Answer:

[tex]\boxed {\boxed {\sf 2. \ 157 \ kPa}}[/tex]

Explanation:

Since temperature remains constant, the only variables that change are volume and pressure. Therefore, we are using Boyle's Law. This states that the pressure is inversely proportional to the volume. The formula is:

[tex]P_1V_1=P_2V_2[/tex]

We know the gas starts with a volume of 20.0 liters at a pressure of 275 kPa. We can substitute these values into the left side of the formula.

[tex]275 \ kPa *20.0 \ L=P_2V_2[/tex]

We know the gas expands to a volume of 35.0 Liters, but we do not know the pressure.

[tex]275 \ kPa *20.0 \ L=P_2* 35.0 \ L[/tex]

Since we are solving for the new pressure, we must isolate the variable P₂. It is being multiplied by 35.0 Liters and the inverse of multiplication is division. Divide both sides by 35.0 L.

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}= \frac{P_2*35.0 \ L}{35.0 \ L}[/tex]

[tex]\frac {275 \ kPa * 20.0 \ L}{ 35.0 \ L}=P_2[/tex]

The units of liters cancel.

[tex]\frac {275 \ kPa * 20.0 }{ 35.0 }=P_2[/tex]

[tex]\frac {5500}{35.0} \ kPa= P_2[/tex]

[tex]157.142857 \ kPa=P_2[/tex]

The original measurements of pressure and volume have 3 significant figures, so our answer must have the same. For the number we calculated, that is the ones place.

The 1 in the tenths place (157.142857) tells us to leave the 7 in the ones place.

[tex]157 \ kPa= P_2[/tex]

If the gas expanded to a volume of 35.0 liters while the temperature remained constant, the pressure in container was approximately 157 kilopascals.

how many moles are in 29.8grams of CaCl2?

Answers

Answer:

110.984  ?

i apologize if i'm wrong, you can report it if im wrong

have a good day/ night

Explanation:

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