A 1,000 kg truck is traveling at 3 m/s. Suddenly, the driver sees a herd of cows on the road ahead and applies the brakes. The truck's tires could fail after doing 5,000 J of work to slow the vehicle. Can the truck stop before the tires fail?


A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J.


B. Yes, the tires do not do any work, it is only the brakes that do work.


C. No, the truck had to stop suddenly and the quick change in KE will cause the tires to fail.


D. No, the total KE the tires need to transfer out of the system is more than 5,000 J.

Answers

Answer 1

This question involves the concepts of the law of conservation of energy and kinetic energy.

The correct option is "A. Yes, the total KE the tires need to transfer out of the system is less than 5,000 J".

According to the law of conservation of energy:

Loss in Kinetic Energy = Work done by the tires

[tex]\frac{1}{2}mv^2=W[/tex]

where,

W = work done by tires = ?

m = mass of the truck = 1000 kg

v = speed of the truck = 3 m/s

Therefore,

[tex]W=\frac{1}{2}(1000\ kg)(3\ m/s)^2[/tex]

W = 4500 J

Since the failure limit of work done by the tire is 5000 J, which is greater than the actual work done by the tire in this scenario. Hence, the tire will not fail in this case.

Learn more about the law of conservation of energy here:

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The attached picture explains the law of conservation of energy.

A 1,000 Kg Truck Is Traveling At 3 M/s. Suddenly, The Driver Sees A Herd Of Cows On The Road Ahead And

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Answer:

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Hi there!

[tex]\large\boxed{I = 4.8 N}[/tex]

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We can also express this as:

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how many tries did it take to invent the lightbulb?

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Answer:

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Explanation:

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a box takes 350 N to start moving the coefficient of static friction is 0.35. what is the weight of the box?

Answers

Answer:

101.937 kg

Explanation:

The force needed to get the box moving must just cancel the static friction force:

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______________________

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Answer:

Explanation:

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Hi there!

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Consider the schematic of the molecule shown, with two hydrogen atoms, H, bonded to an oxygen atom, O. The angle between the two bonds is 106°. If the bond length r = 0.103 nm long, locate the center of mass of the molecule. The mass mH of the hydrogen atom is 1.008 u, and the mass mO of the oxygen atom is 15.9999 u. (Use a coordinate system centered in the oxygen atom, with the x-axis to the right and the y-axis upward. Give the coordinates of the center of mass in nm.)

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The definition of the center of mass allows to find the result for the position of the mass center of more than the H₂O molecule is;

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the concept of center of mass of a system is the point where external forces are applied, it is given by the expression

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x-axis

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y-axis

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         sin θ = [tex]\frac{x}{L}[/tex]  

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          sin θ = - sin -θ

          cos θ = cos -θ

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        [tex]x_{cm} = 0 \\y_{cm} = \frac{1}{2 \ 1.008 + 15.9999} \ ( 2 \ 1.008 \ 0.103 cos 53)[/tex]

       

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In conclusion using the definition of the center of mass we can find the result for the position of the center of mass of the H₂O molecule is;

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Explanation:

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a
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Part IV Objects on an incline w/ Tension + Friction
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Answers

(a) The normal force on the sleigh is 596.36 N.

(b) The magnitude and direction of acceleration of the sleigh is 3.2 m/s² upwards.

The given parameters;

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The normal force on the sleigh is calculated as follows;

[tex]F_n = mg \times cos(\theta)\\\\F_n = 63 \times 9.8 \times cos(15)\\\\F_n = 596.36 \ N[/tex]

The magnitude and direction of acceleration of the sleigh is calculated as follows;

[tex]\Sigma F= ma\\\\F - mgsin(\theta) - F_f = ma\\\\F - mgsin(\theta) - \mu F_n = ma\\\\510\ - \ 63 \times 9.8 \times sin15 \ -\ 0.25\times 596.36 = 63a\\\\201 .11 = 63a\\\\a = \frac{201.11}{63} \\\\a = 3.2 \ m/s^2 \ upwards[/tex]

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5.54 [kg].

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