Answer:
F = 1,875 N
Explanation:
force=
[tex] \frac{change \: in \: momentum}{time \: taken} [/tex]
∆H = m∆V
where ∆H ----> change in momentum.
( final momentum - initial momentum )
and ∆V ----> change in velocity
( final velocity - initial velocity )
and m ----> is mass
then f =
[tex] \frac{1500 \times (25 - 15)}{8} [/tex]
= 1,875 N
A mass is hung from a vertical spring and allowed to come to rest or its equilibrium position. The mass is then pulled down an additional 0.25 meters and released. As the mass oscillates it completes one full cycle in 3.0 seconds. Place the numbers below to correctly identify the mass's amplitude, full range of vertical motion, frequency, and period. The full range of vertical motion is the distance between the maximum and minimum heights of the mass.
e amplitude of the spring is______ m.
The full range of vertical motion is _____m.
The frequency of the spring is______ Hz.
The period of the spring is_______ s.
Answer:
Explanation:
Time period of oscillation T = 3 s .
Frequency of oscillation = 1 / T = 1 / 3 = .333 per second .
The mass is pulled down an additional 0.25 meters so amplitude of oscillation A = .25 m .
Full range of vertical motion = .25 x 2 = 0.5 m .
The period of the spring = 3 s .
The audio power of the human voice is concentrated at about 300 Hz. Antennas of the appropriate size for this frequency are impracticably large, so that to send voice by radio the voice signal must be used to modulate a higher (carrier) frequency for which the natural antenna size is smaller. a. What is the length of an antenna one-half wavelength long for sending radio at 300 Hz
Answer:
the length of an antenna one-half wavelength long for sending radio at 300 Hz is 500 km
Explanation:
Given the data in the question;
we know that wave length is;
λ = c/f
c is the speed of voice ( 3 × 10⁸ m/s )
frequency f = 300 Hz
so we substitute
λ = 3 × 10⁸ / 300
λ = 1000000 m
we know that; 1 km = 1000 m
so
λ = 1000000 m / 1000
λ = 1000 km
hence, an antenna one-half wavelength will be;
λ /2
= 1000 km / 2
= 500 km
Therefore, the length of an antenna one-half wavelength long for sending radio at 300 Hz is 500 km
Current Attempt in Progress The atomic radii of a divalent cation and a monovalent anion are 0.52 nm and 0.125 nm, respectively. (a) Calculate the force of attraction between these two ions at their equilibrium interionic separation (i.e., when the ions just touch one another). Enter your answer for part (a) in accordance to the question statement N (b) What is the force of repulsion at this same separation distance
Answer:
a) F = 1.70 10⁻⁹N, F = 1.47 10⁻⁸ N,
b) * the electronegative repulsion, from the repulsion by quantum effects
Explanation:
a) The atraicione force comes from the electric force given by Coulomb's law,
F = [tex]k \frac{ q_1 q_2}{r^2}[/tex]
divalent atoms
In this case q = 2q₀ where qo is the charge of the electron -1,6 10⁻¹⁹ C and the separation is given
F = k q² / r²
F = [tex]2 \ 10^9 \ \frac{2 (1.6 \ 10^{-19} )^2}{ (0.52 10^{-9} )^2 }[/tex]
F = 1.70 10⁻⁹N
monovalent atoms
in this case the load is q = q₀
F = 2 \ 10^9 \ \frac{ (1.6 \ 10^{-19} )^2}{ (0.125 10^{-9} )^2 }
F = 1.47 10⁻⁸ N
b) repulsive forces come from various sources
* the electronegative repulsion of positive nuclei
* the electrostatic repulsion of the electrons when it comes to bringing the electron clouds closer together
* from the repulsion of electron clouds, by quantum effects
5. Did objects have to touch to interact? What causes this?
Answer:
★ For example, a useful analogy for explaining the Earth's gravity force is that the Earth can pull on objects without touching them just like a magnet can affect other objects without touching them. In Addition, the main notion to convey here is that forces can act at a distance with no perceivable substance in between.
Explanation:
Hope you have a great day :)
No, objects have no need to touch for interaction.
Forces that interact with objects without touchingWe know that there are some forces which interact with the objects from far distance without touching such as gravity of the earth. The Earth's gravitational force is that the Earth can pull on objects without touching them so we can conclude that objects have no need to touch for interaction with one another.
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what is the result of mixing 15 garm of water 80 degree celsius with 10 gram of ice -10 degree Celsius ? give specific heat capctiy of ice 0.5 calorie per gram Celsius and letent heat of fusion of ice 80 calorie per gram.
Answer:
50
Explanation:
A tennis ball is shot straight up with an initial velocity of 34 m/s. What is its velocity two seconds after launch?
Answer:
The speed after 2 seconds is 14.4 m/s
Explanation:
Vertical Launch Upwards
In a vertical launch upwards, an object is launched vertically up from a height H without taking into consideration any kind of friction with the air.
The speed changes from an initial value vo to a final value vf, given by:
[tex]v_f=v_o-g.t[/tex]
Where g is the gravitational acceleration ([tex]9.8\ m/s^2[/tex])
The tennis ball is shot up with an initial speed of vo=34 m/s. We are required to find the final speed at t=2 s:
[tex]v_f=34-9.8*2[/tex]
[tex]v_f=14.4\ m/s[/tex]
The speed after 2 seconds is 14.4 m/s
the velocity after 2 seconds of launch is 14.4 m/s
the initial velocity(a) is 34m/s
the time(t) is 2 seconds
acceleration(a) due to gravity is 9.8g
the formula is
v= u - at
v= 34 -(9.8)(2)
= 34 - 19.6
= 14.4 m/s
hence the final velocity is 14.4 m/s
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What is unusual about the material that Emily invented?
Answer:
The material that Emily invented can be easily repaired by shining ultraviolet light on it.
Explanation:
Hope it helps! Please mark brainliest.
Answer:
The material that Emily invented can be easily repaired by shining ultraviolet light on it.
Explanation:
Convert 20 C to F
-40 C to F
40C to F
Answer:
20 C to F
Ans: 68F
-40 C to F
Ans:-40F
40C to F
Ans:104F
what Species can change over time to adapt to their environment
Answer:
Explanation:
Most environments have many niches. If a niche is "empty" (no organisms are occupying it), new species are likely to evolve to occupy it. This happens by the process of natural selection. By natural selection, the nature of the species gradually changes to become adapted to the niche.
Now complete your visual overview by identifying the known variables and the variables you must find. Assume charge 1 is located at the origin of the x axis and the positive x axis points to the right. Let x1, x2, and x3 denote the positions of charge 1, charge 2, and charge 3, respectively. Determine which of the following quantities are known and which are unknown.
Answer:
Explanation:
From the given information;
If we assume that charge 1 is located at the origin;
Then, using the visual overview for identification, we will realize that the known quantities are:
[tex]\mathbf{= q_1, \ q_2 , \ q_3, \ x_1 \ and \ x_2}[/tex]
However, provided that we do not know the exact location of [tex]x_3[/tex],
Then, the unknown quantity is [tex]\mathbf{ x_3}[/tex]
Two satellites are approaching the Earth from opposite directions. According to an observer on the Earth, satellite A is moving at a speed of 0.648c and satellite B at a speed of 0.795c. What is the speed of satellite A as observed from satellite B
Answer:
Explanation:
Satellite A and satellite B are approaching the earth from opposite directions , that means they are approaching each other . The velocity of satellite A and B are .648c and .795c respectively . Their velocities are comparable to velocity of light so they will follow relativistic laws .
Their relative velocity will be given by the following relation .
[tex]V_r=\frac{u+v}{1+\frac{uv}{c^2} } }[/tex]
where u and v are velocities of vehicles coming from opposite direction and c is velocity of light .
[tex]V_r=\frac{.795c+.648c}{1+\frac{.648c\times .795c}{c^2} } }[/tex]
[tex]V_r=\frac{1.443c}{1+.515 } }[/tex]
= .952c
(b) Which statement about beta radiation is true?
Tick one box
It is the fastest moving type of radiation.
It is the type of radiation with a negative charge.
It is the type of radiation with the greatest mass.
It is the type of radiation with the greatest range in air.
Answer:
is the fastest moving type of radiationhe
A quarterback, Patrick, throws a football down the field in a long arching trajectory to wide receiver, Tyreek. The football and Tyreek are traveling in the same direction, started at the same spot, and the football was thrown at the same instant that Tyreek began running. Furthermore, both Tyreek and the football have horizontal components of speed of 22.6 mph. Under these circumstances, no matter what angle the football is thrown at, it will land on Tyreek (whether he catches it or not). True or false
Answer:
the statement is False [tex]\frac{x_{ball} }{ x_{rec} }[/tex] = cos θ
Explanation:
Let's analyze this problem, the ball and the receiver leave the same point and we want to know if at the same moment they reach the same point, for this we must have both the ball and the receiver travel the same distance.
Let's start by finding the time it takes for the ball to reach the ground
y = [tex]v_{oy}[/tex] t - ½ g t²
when it reaches the ground its height is y = 0
0 = vo sin θ - ½ g t²
0 = t (vo sin θ - ½ g t)
The results are
t = 0 exit point
t = 2 v₀ sin θ/g arrival point
at this point the ball traveled
[tex]x_{ball}[/tex]= v₀ₓ t
x_{ball} = v₀ cos θ 2v₀ sin θ / g
x_{ball}= 2 v₀² cos θ sin θ/ g
Now let's find that distantica traveled the receiver in time
[tex]x_{rec}[/tex] = v₀ t
x_{rec} = v₀ (2 v₀ sin θ / g)
x_{rec} = 2 v₀² sin θ / g
without dividing this into two distances
[tex]\frac{x_{ball} }{ x_{rec} }[/tex] = cos θ
therefore the distances are not equal to the ball as long as behind the receiver
Therefore the statement is False
Conservation of energy is explained as a scientific law and not a _______ because it does not explain why energy is conserved
Answer:
Theory
Explanation:
Conservation of energy is explained as a scientific law and not a theory because it does not explain why energy is conserved.
A law is a the statement of a scientific fact. It is a product of repeated experiment and observation through time. Most laws do not explain the reason for the logic behind their premise.
A theory on the other hand provides an explanation for an observed phenomenon. Most theories are no immutable. They are often changed when new finds are reported or made.
Laws are immutable and they stand still.
Hlo
what is a force........??
Explanation:
In physics, a force is any interaction that, when unopposed, will change the motion of an object. A force can cause an object with mass to change its velocity, i.e., to accelerate. Force can also be described intuitively as a push or a pull. A force has both magnitude and direction, making it a vector quantity.
Formula
Newton's Second Law
F = m * a
F = force
m = mass of an object
a = acceleration
Jogger A has a mass m and a speed v, jogger B has a mass m/2 and a speed 3v, jogger C has a mass 3m and a speed v/2, and jogger D has a mass 4m and a speed v/2. Rank the joggers in order of increasing kinetic energy. Indicate ties when appropriate. Show your work.
Answer: B>A=D>C
Explanation:
Kinetic Energy is the product of mass and square of the velocity
For Jogger A
[tex]K.E._a=\frac{1}{2}mv^2[/tex]
For Jogger B
[tex]K.E._b=\frac{1}{2}\times\frac{m}{2}\times(3v)^2=\frac{9}{4}mv^2\\K.E._b=2.25mv^2[/tex]
For Jogger C
[tex]K.E._c=\frac{1}{2}\times3m\times(\frac{v}{2})^2=\frac{3}{8}mv^2\\K.E._c=0.375mv^2[/tex]
For Jogger D
[tex]K.E._d=\frac{1}{2}\times4m\times(\frac{v}{2})^2=\frac{1}{2}mv^2[/tex]
Kinetic Energy of Joggers in increasing order
B>A=D>C
Agnes makes a round trip at a constant speed to a star that is 16 light-years distant from Earth, while twin brother Bert remains on Earth. When Agnes returns to Earth, she reports that she has celebrated 20 birthdays during her journey. (a) What was her speed during her journey
Answer:
Speed of Agnes during her journey was 0.848c
Explanation:
Given that;
Age of Agnes t₀ = 20 years
distance d = 2 × distance of star from Earth = 2 × 16 light-years
= 32 light-years
so get her speed speed; we use the following expression
Yvt₀ = d
( v / √(1 - ([tex]\frac{v}{c}[/tex])²) )² = ( 32 light-years / 20 yrs )²
v² / (1 - ( v²/c²)) = ( 32 × c / 20 )²
v² / (1 - ( v²/c²)) = 2.56 × c²
v² / c²-v²/c² = 2.56 × c²
v²c² / c² - v² = 2.56 × c²
v² / c² - v² = 2.56
v² = 2.56 (c² - v²)
v² = 2.56 (c² - v²)
v² = 2.56c² - 2.56v²
v² + 2.56v² = 2.56c²
3.56v² = 2.56c²
v² = (2.56/3.56)c²
v = √((2.56/3.56)c²)
so v = 0.848c
Therefore, Speed of Agnes during her journey was 0.848c
After an initial race George determines that his car loses 35 percent of its acceleration due to air resistance travelling at 38 m/s on flat ground. Assuming that his car travels with a constant acceleration, calculate the maximum speed (Vm), in meters per second, his car can reach on flat ground?\
Answer:
64.2 m/s
Explanation:
We are given that
Speed ,v=38 m/s
We have to find the maximum speed when his car reach on flat ground.
Using dimensional analysis
[tex]F_{res}\propto v^2[/tex]
If 35% acceleration reduced by F(res) at 38 m/s
Then, 100% acceleration can be reduced by F(res) at v' m/s
[tex]\frac{F_1}{F_2}=\frac{v^2}{v'^2}[/tex]
[tex]v'^2=\frac{F_2}{F_1}v^2[/tex]
[tex]v'=v\sqrt{\frac{F_2}{F_1}}[/tex]
Substitute the values
[tex]v'=38\times \sqrt{\frac{100}{35}}[/tex]
[tex]v'=64.2 m/s[/tex]
Hence, the maximum speed when his car can reach on flat ground=64.2 m/s
The maximum velocity of the car at constant acceleration on the road will be 62.2 m/s.
What is the relation between resistance and speed?
The air resistance is directly proportional to the square of the velocity of an object.
R ∝ v²
The speed of the car was reduced by 35 % at 38 m/s.
So, the speed of the car was reduced by 100% at v' m/s.
The relationship can be given by,
[tex]\dfrac {R_1}{R_2} = \dfrac {v^2}{v'^2}[/tex]
Put the values in the formula and calculate for [tex]v'[/tex],
[tex]v' = \sqrt {\dfrac {R_2 v^2}{R_1 }}[/tex]
[tex]v' = \sqrt {\dfrac { 100\times 38 ^2}{35 }}\\\\v' = 62.2 \rm \ m/s[/tex]
Therefore, the maximum velocity of the car at constant acceleration on the road will be 62.2 m/s.
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a) Two workers are trying to move a heavy crate. One pushes onthe crate with a force A, which has amagnitude of 445 newtons and is directed due west. The other pusheswith a force B, which has a magnitude of 325newtons and is directed due north. What are the magnitude anddirection of the resultant force A + Bapplied to the crate?
b) Suppose the second worker applies a force of-B instead of B. What then arethe magnitude and direction of the resultant force A -B applied to the crate? In both cases express thedirection relative to due west.
Answer:
Divide then multiply or multiply then divide
Explanation:
to get the answer of a and b
The lawn outside your neighbor's house has an approximate area of 175 m2One night it snows so that the snow on the lawn has a uniform depth of 25.5 cm. What volume of snow is on the lawn, in cubic m
The volume of snow on the lawn, in cubic m, is 44.63 or 44.63 m³ if the lawn outside your neighbor's house has an approximate area of 175 m².
What is volume?It is defined as a three-dimensional space enclosed by an object or thing.
It is given that:
The lawn outside your neighbor's house has an approximate area of 175 m². One night it snows so that the snow on the lawn has a uniform depth of 25.5 cm.
As we know, unit conversion can be defined as the conversion from one quantity unit to another quantity unit followed by the process of division, and multiplication by a conversion factor.
25.5 cm = 0.255 m
Volume = area×depth
Volume = 175×0.255
Volume = 44.63 cubic meters
Thus, the volume of snow on the lawn, in cubic m is 44.63 or 44.63 m³ if the lawn outside your neighbor's house has an approximate area of 175 m².
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3N
3 N
What is the net force of the box?
If the grasses have 100 units of energy, how much can be passed to the grasshoppers?
You perform nine (identical) measurements of the acceleration of gravity (units of m/s2): 10.1, 9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, and 9.90. The true value is 9.81. Calculate the mean value of your results to three significant digits. ________
Answer: The mean value = 9.85m/s².
Explanation:
Mean = [tex]\dfrac{\text{Sum of n observations}}{n}[/tex]
The given measurements the acceleration of gravity (units of m/s²): 10.1, 9.87, 9.76, 9.91, 9.75, 9.88, 9.69, 9.83, and 9.90.
Number of measurements =9
Sum of measurements = 88.69
Mean = [tex]\dfrac{88.69}{9}=9.85444444\approx9.85[/tex]
Hence, the mean value = 9.85m/s².
Bart runs up a 2.5 meter high flight of stairs at a
constant speed in 4.25 seconds chasing his
adolescent gazelle. If Bart's mass is 60 kg,
determine the work he did.
Answer:
1470J
Explanation:
Given parameters:
Height of stairs = 2.5m
Time taken = 4.25s
Mass of Bart = 60kg
Unknown:
Work done by Bart = ?
Solution:
Work done is a function of the force acting to move a body through a distance.
Work done = Weight x height
Work done = mass x acceleration due to gravity x height
Work done = 60 x 9.8 x 2.5 = 1470J
The sound from a trumpet travels at 351 m/s in the frequency of the note is 294 Hz, what is the wavelength of the sound wave?
Answer:
1.19m
Explanation:
Given parameters:
Speed of the trumpet sound = 351m/s
Frequency of the note = 294Hz
Unknown:
Wavelength of the sound = ?
Solution:
To solve this problem, we use the wave - velocity equation.
V = F x ∧
V is the velocity of the body
F is the frequency
∧ is the wavelength
So;
351 = 294 x ∧
∧ = [tex]\frac{351}{294}[/tex] = 1.19m
A 10 kg remote control plane is flying at a height of 111 m. How much
potential energy does it have?
Answer:
10.88kJ
Explanation:
Given data
mass= 10kg
heigth= 111m
Applying
PE= mgh
assume g= 9.81m/s^2
substitute
PE= 10*9.81*111
PE=10889.1 Joules
PE=10.881kJ
Hence the potential energy is 10.88kJ
What is the range of a ball thrown horizontally at 12 m/s if its time of flight is 3.0 s?
Answer:
6
Explanation:
because I did this assignment, :) your welcome
Next time do it by yourself, but here's the answer kid
The dotted lines and arrows represent
Choose the answer that best describes hydrostatic equilibrium.
1. when gravity equalizes the level of liquid on a spherical celestial object
2. when equilibrium is achieved between two celestial bodies orbiting one another 3. when liquid such as water becomes spheroid under weightless conditions 4. when a body has enough mass and gravity to create a celestial body with a round shape
Answer:
the answer should be the third statement
Answer:
when a body has enough mass and gravity to create a celestial body with a round shape
____ and____ are 2 major atmospheric gases
Answer:
Nitrogen and Oxygen are the two major atmospheric gases.