Answer:
a) k = 200 N/m
b) E = 4 J
c) Δx = 6.3 cm
Explanation:
a)
In order to find force constant of the spring, k, we can use the the Hooke's Law, which reads as follows:[tex]F = - k * \Delta x (1)[/tex]
where F = 40 N and Δx =- 0.2 m (since the force opposes to the displacement from the equilibrium position, we say that it's a restoring force).Solving for k:[tex]k =- \frac{F}{\Delta x} =-\frac{40 N}{-0.2m} = 200 N/m (2)[/tex]
b)
Assuming no friction present, total mechanical energy mus keep constant.When the spring is stretched, all the energy is elastic potential, and can be expressed as follows:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} (3)[/tex]
Replacing k and Δx by their values, we get:[tex]U = \frac{1}{2}* k* (\Delta x)^{2} = \frac{1}{2}* 200 N/m* (0.2m)^{2} = 4 J (4)[/tex]
c)
When the object is oscillating, at any time, its energy will be part elastic potential, and part kinetic energy.We know that due to the conservation of energy, this sum will be equal to the total energy that we found in b).So, we can write the following expression:[tex]\frac{1}{2}* k* \Delta x_{1} ^{2} + \frac{1}{2} * m* v^{2} = \frac{1}{2}*k*\Delta x^{2} (5)[/tex]
Replacing the right side of (5) with (4), k, m, and v by the givens, and simplifying, we can solve for Δx₁, as follows:[tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} + \frac{1}{2} * 1.8kg* (-2.0m/s)^{2} = 4J (6)[/tex]
⇒ [tex]\frac{1}{2}* 200N/m* \Delta x_{1} ^{2} = 4J - 3.6 J = 0.4 J (7)[/tex]
⇒ [tex]\Delta x_{1} = \sqrt{\frac{0.8J}{200N/m} } = 6.3 cm (8)[/tex]
What is Compression?
Answer:
Compression, decrease in volume of any object or substance resulting from applied stress. Compression may be undergone by solids, liquids, and gases and by living systems.
Explanation:
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Find the velocity of an object that has a mass of 500x10-6 kg and a charge of 1pc if it starts from
rest and passes through a potential difference of 120kV
Answer:
v = 4.8 10⁻⁴ m / s
Explanation:
To solve this exercise we can use the concepts of energy. In this case the potential energy is transformed into kinetic energy
U = K
q V = ½ m v²
v = [tex]\sqrt { \frac{2qV}{m} }[/tex]
in the exercise they indicate the value of the charge q₁ = 1 pC = 1 10⁻¹² C
let's calculate
v = [tex]\sqrt{ \frac{2 \ 1 \ 10^{-12} 120 \ 10^3}{500 ^{2} }[/tex]
v = 4.8 10⁻⁴ m / s
A solenoid that is 69.3 cm long has a cross-sectional area of 24.0 cm2. There are 1260 turns of wire carrying a current of 8.78 A. (a) Calculate the energy density of the magnetic field inside the solenoid. (b) Find the total energy in joules stored in the magnetic field there (neglect end effects).
Answer:
a) 34.17J/m^3
b) 0.0468 J
Explanation:
a) Calculate the energy density of the magnetic field inside the solenoid as follows:
[tex]u_{B} &=\frac{U}{A l} \\ &=\frac{L I^{2}}{2 A l} \quad\left(U=\frac{1}{2} L I^{2}\right) \\ &=\frac{\mu_{0} N^{2} A I^{2}}{2 A l^{2}} \quad\left(L=\frac{\mu_{0} N^{2} A}{l}\right) \\ &=\frac{\mu_{0} N^{2} I^{2}}{2 l^{2}}[/tex]
Substitute the corresponding values in the above equation.
[tex]u_{B} &=\frac{4 \pi\left(10^{-7}\right)(1260)^{2}(8.78)^{2}}{2(0.693)^{2}} \\
&=34.17 \mathrm{~J} / \mathrm{m}^{3}[/tex]
b) Calculate the total energy stored in the solenoid as follows:
[tex]U &=u_{B} A l \\ &=(34.17)\left(24 \times 10^{-4}\right)\left(69.3 \times 10^{-2}\right) \\ &=0.0468 \mathrm{~J}[/tex]
It is 32 degrees F outside. What is this in Kelvin?
Answer:
273.15
Explanation:(32°F − 32) × 5/9 + 273.15 = 273.15K
Question 10 of 10
Which of the following is an example of a surface wave?
Answer:
gravity wave
Explanation:
A circular loop of radius 13 cm carries a current of 13 A. A flat coil of radius 0.94 cm, having 58 turns and a current of 1.9 A, is concentric with the loop. The plane of the loop is perpendicular to the plane of the coil. Assume the loop's magnetic field is uniform across the coil. What is the magnitude of (a) the magnetic field produced by the loop at its center and (b) the torque on the coil due to the loop
Answer:
[tex]6.28\times 10^{-5}\ \text{T}[/tex]
[tex]1.92\times 10^{-6}\ \text{Nm}[/tex]
Explanation:
[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi 10^{-7}\ \text{H/m}[/tex]
[tex]I_l[/tex] = Current in circular loop = 13 A
[tex]r_l[/tex] = Radius of circular loop = 13 cm
[tex]N[/tex] = Number of turns = 58
[tex]r_c[/tex] = Radius of coil = 0.94 cm
[tex]I_c[/tex] = Current in coil = 1.9 A
[tex]\theta[/tex] = Angle between loop and coil = [tex]90^{\circ}[/tex]
Magnitude of magnetic field in circular loop
[tex]B_l=\dfrac{\mu_0I_l}{2r_l}\\\Rightarrow B_l=\dfrac{4\pi 10^{-7}\times 13}{2\times 13\times 10^{-2}}\\\Rightarrow B_l=6.28\times 10^{-5}\ \text{T}[/tex]
The magnetic field produced by the loop at its center is [tex]6.28\times 10^{-5}\ \text{T}[/tex].
Torque is given by
[tex]\tau=\pi NI_cr_c^2B_l\sin\theta\\\Rightarrow \tau=\pi 58\times 1.9\times (0.94\times 10^{-2})^2\times 6.28\times 10^{-5}\sin90^{\circ}\\\Rightarrow \tau=1.92\times 10^{-6}\ \text{Nm}[/tex]
The torque on the coil due to the loop [tex]1.92\times 10^{-6}\ \text{Nm}[/tex].
a piece of clay with mass m is traveling with an unknown velocity in the positive x-direction, when it collides and sticks to a block of mass 3m, moving with velocity v=-3m/s. after the collision, the block and clay are stuck together and traveling with a velocity of 1 m/s in the negative x-direction. what was the original velocity of the clay mass?
Answer:
13 m in the + x direction.
Explanation:
Givens
m1 = m
m2 = 3m
v1= ? = x
v2 = - 3 m/s
v3 = v4 = - 1 m/s
Equation
Let x be the speed of the lighter object before collision.
Momentum before collision = momentum after collision
Solution
mx - 3m * 3m/s = (m1 + m2)*(-1)
m(x - 3*3m/s) = (m + 3m)(-1)
m(x - 9) = - 4m Cancel the ms
x - 9 = 4 Add 9 to both sides
x = 9 + 4
x = 13 m/s
To measure the internal diameter of a beaker one would reliably use______.
Answer:
Vernier calipers is used to measure the internal diameter of a beaker
In a laser cutting process of aluminum plates of 1mm thick, a through hole is to be drilled, followed by melting-dominated cutting. If the focused laser beam is 0.25 mm in diameter (assuming it is the same of the cut width w), (a) In order to drill a hole through the plate in 1 ms, determine the laser power required. (b) In the cutting, the laser power is adjusted to be 1,500W. Determine the cutting velocity V achievable.
Answer:
a) P = 118.4 W, b) t = 7.9 10⁻⁵ s
Explanation:
a) Let's analyze this interesting exercise a bit, we suppose that all the laser
energy is used to heat the aluminum, we should calculate the energy necessary to bring the solid aluminum to the melting temperature and add the energy to carry out the change of solid state to liquid,
let's use the calorimeter equation
Q₁ = m c_e ΔT
and the energy of change of these solid to liquid (fusion process)
Q₂ = m L
the energy required to create the hole is
Q_ {total} = Q₁ + Q₂
if there are no losses this is the laser energy
E = Q_ {total}
The aluminun data c_e =9000 J/kgC, L = 322 103 J/kg, ρ = 2.7 103 kg/m3 , T₂ = 660C, T₀= 25C
Let's find the mass of the hole, which we approximate by a cylinder of diameter d = 0.25 mm = 0.25 10⁻³ m and a thickness of e = 1 mm = 1 10⁻³ m
let's use the concept of density
ρ = m / V
the volume of a cylinder is
V = π r² e = π (d²/4) e
we substitute
m = [tex]\rho \pi \frac{d^2 e}{4}[/tex]
let's calculate
m = π/4 2.7 10³ (0.25 10⁻³)² 1 10⁻³
m = 1,325 10⁻⁷ kg
we calculate the energy
E = 1,325 10⁻⁷ 900 (660 - 25) + 1,325 10⁻⁷ 322 10³
E = 7.57 10⁻² + 4.27 10⁻²
E = 1.184 10⁻¹ J
Let's use the power ratio
P = E / t
P = 0.1184 /1 10⁻³
P = 118.4 W
b) In this part they indicate that the laser power is P = 1500 W, find the time to deposit the energy to melt the aluminum
P = E / t
t = E / P
t = 0.1184 / 1500
t = 7.9 10⁻⁵ s
What do all magnets have in common? Select all that apply.
magnetic domains are aligned
magnetic domains are not aligned
movement of protons creates a magnetic field
all magnets have opposite poles ( a North pole and South pole)
movement of electrons creates a magnetic field
moving electrons generate magnetic fields
Answer:
all magnets have opposite poles (north and south)
magnetic domains are aligned
moving electrons generate a magnetic filed
movement of electrons creates a magnets field
A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center of the circle? Answerin units of kg · m2/s. What is its moment of inertia about an axis through the center ofthe circle and perpendicular to the plane of the motion? Answer inunits of kg · m2. What is t
Explanation:
Given that,
Mass of the particle, m = 4 kg
Speed of the particle, v = 2.5 m/s
The radius of the circle, r = 2 m
We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :
[tex]L=mvr[/tex]
Substitute all the values,
[tex]L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s[/tex]
So, the angular momentum of the particle is 20 kg-m² s.
A block of wood and a block of aluminum have been sitting out for a while. How do their temperatures compare?
Answer:
Block of aluminum
Explanation:
The block of aluminum because of the conductivity, and is a metal, so it gets hotter faster
The temperature of wood and the aluminium will depend upon thier thermal coductivity.
What is thermsal conductivity?The thermal conductivity of any material is defined as the amount of heat from a material can flow in a unit area per unit degree centigrade for a unit distance.
The thermal conductivity of wood is around 0.90 to 0.197 w/mk and that of aluminium is around 88 to 251 w/mk.
We can see that the aluminium block will absorb much amount of heat as compared to the wood block. Because the thermal conductivity of aluminium is much higher then the wood.
Hence temperature of wood and the aluminium will depend upon thier thermal coductivity.
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How least count determine the precision of a measurement?
Explanation:
The least count of the normal scale is 1mm whereas the least count of vernier calliper is 0.01 mm
1 gram of radium is reduced by 3.1 mg in 5 years by alpha decay.
Calculate the half-life of radium.
Answer:
1 gm = 1000 mg
N = No e^-y t where y = lambda the decay constant
N / N0 = .9969
ln .9969 = - y t
-.00310 = - 5 y
y = .00310 / 5 = .000621
So the half-life = .693 / y
T^1/2 = .693 / .000621 = 1116 or about 1120 yrs
Which of the following should you do to improve your fitness level and increase your assessment scores by the end of the semester?
OA Watch a lot of TV
B.
Perform cardiovascular exercise
OC. Eat a diet high in fat and sugar
OD
All of the above
It’s Not Lhysics It’s Pe btw
Question 3 of 15
Which process is often used to determine what coefficients to use to balance
an equation?
A. Trial and error
B. Neutral numbers
C. Roundabout
D. Lavoisier's
Help?
Answer:
A. Trial and error
Explanation:
Trial and error method is a method adopted when trying to solve a quadratic equation. This equation is mostly the balancing of the right hand side and the left hand side in-order to form a unique point or to equate to zero when one is subtracted from the other. In trail and error method, the coefficients is used to determine when the actual equation is balanced and the likely answer it should be if the equation is expanded through multiplication method.
The definition that best describes invention is:
Your answer:
Invention is the first product produced on an assembly line
Invention is having a desired goal to achieve something
Invention is changing the size of an existing product
Invention is a process of turning ideas into devices or systems
Answer: Invention is a process of turning ideas into devices or systems.
Explanation:
Invention is a process of turning ideas into devices or system. Invention, simply has to do with bringing of ideas together so as to create something unique.
It should be noted that without creativity, invention can't take place. Examples of invention include the light bulb, fans etc. They are products that were designed based on the ideas that someone had Wich was turned into a device.
A student is provided with a rubber cylinder and a patch of synthetic fur. The rubber cylinder and the patch are electrically neutral. The student rubs the cylinder back and forth along the fur. A short time later, after the cylinder and fur have been placed on insulating stands, the student determines that the fur has a net negative electric charge. Before the patch of fur attained its net negative charge, it was considered to be electrically neutral. Which of the following claims, with appropriate evidence, is correct about the distribution of charge in the patch of fur before the charging process?
a. It is an isolated system.
b. It is a closed system.
c. It is an open system.
d. The type of system cannot be determined unless information is known about the net force exerted on the system at any given time.
Answer:
Option b ( It is a closed system) is the appropriate answer.
Explanation:
The mass transfer isn't made on a platform. There seems to be no mass transfer, the mechanism can't be separated as power lines will interfere beyond the physical boundaries including its fur patch.The mechanism can't however be separated and, while the mass transfer is indeed not present, several field lines will communicate well outside the mechanism.The other options are not linked to the situation in question. Thus, the answer is correct.
What is the energy of an electromagnetic wave that has a frequency of 5.0 * 10^5 Hz? Use the equation E=hf, where h=6.626 * 10^-34 J*s.
I will mark brainliest!!! :)
Answer:
3.3*10^-28j
Explanation:
A P E X
The energy of an electromagnetic wave that has a frequency of 5.0 * 10^5 Hz is 3.3 * 10 ^ -28 J
What is Electromagnetic waves ?Electromagnetic waves are the waves that are created as a result of vibration between an electric field and a magnetic field . They are composed of oscillating magnetic and electric field
Energy of Electromagnetic waves can be calculated by
Energy = h * f where h = plank's constant = 6.626 * 10^-34 J s.
f = frequency of electromagnetic waves
given : h = 6.626 * 10^-34 J s.
frequency = 5.0 * 10^5 Hz
Energy of electromagnetic waves = (6.626 * 10^-34 J s) *( 5.0 * 10^5 Hz)
= 33.13 * 10 ^ -29 J
= 3.3 * 10 ^ -28 J
correct answer is c)3.3 * 10 ^ -28 J
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What is the motion of an apple when it falls from a tree ? a)Constant b)accelerating c)decelerating d)zero
The motion of an apple when it falls from a tree is
b) Accelerating
The motion of apple is when it falls from a tree is the case of free fall.
During free fall , the initial velocity of the apple or any object is zero but it gains some velocity due to gravitatonal acceleration .
Question is in the image
Answer:
thank you
Explanation:
What determines the precision of a measurement?
Answer:
Precision is determined by a statistical method called a standard deviation To determine if a value is precise find the average of your data, then subtract each measurement from it
If the force of gravity changes what will happen and what would cause it to change?
It has been shown that the half-life for this radioactive isotope is 20 years. In the year 2000, an archaeology team unearths pottery and is using this isotope for radiometric dating to place the age of the pottery. It is shown that 95% of the nuclei have decayed. How much mass has decayed? How much mass is left?
I'd prefer to be shown a step-by-step on how to solve for these questions. I do better with seeing the step-by-step, and can retain the information better.
Answer:
(1/2)*n = .05 by the definition of half-life where n is the number of half-lives
n ln .5 = ln .05
n = ln .05 / ln .5 = 4.32 number of half-lives
So 4.32 * 20 = 86.4 years has passed
Actually, they only want the mass left. However, all that has changed is that
95% of the original radioactive atoms have changed to a different form of about the same amount of mass. The amount of mass remaining would be about the same. Also, one doesn't know the percentage of radioactive atoms
that formed the original mass.
PLEASE ILL GIVE BRAINLIST Which term describes the high point of a transverse wave?
O A. Crest
O B. Compression
O C. Rarefaction
O D. Trough
Answer:
I belive that the answer is the A
Crest describes the high point of a transverse wave. Therefore, the correct option is option A.
Transverse waves are those which oscillate in directions that are opposite to the wave's forward motion. Electromagnetic radiation, seismic waves, or water surface ripples are all examples of transverse waves.
A simple transverse wave can be represented by a sine or cosine curve because any point's amplitude—that are, its distance from the axis—is proportional to the sine (or cosine) associated with that angle. Crest describes the high point of a transverse wave.
Therefore, the correct option is option A.
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4. A 100-kg soldier in the Arctic is coasting on his ice skates at a speed of 3.0 m/s. He fires 35 bullets directly forward from his 10.0-kg machine gun. Each bullet has a mass of 60 g and a speed of 500 m/s. What is his final velocity?
Answer:
The gunner must apply 240 N to the gun to stop it from moving back.
Explanation:
!Please help fast!!*18 pts*!
How is light amplified in a laser?
A. Photons "leak" through a partically reflecting mirror, causing them to travel in step.
B. Integrated circuits in a laser amplify the sound produced by photon emission.
C. Photons collide with gas particles, multiply, and reflect back and forth in a tube.
D. Electric current is amplified and directed into gas particles, which emit photons.
Answer:
A.
Explanation:
Some of these photons are absorbed by the atoms in the ground state and the photons are lost to the laser process. However, some photons cause stimulated emission in excited-state atoms, releasing another coherent photon. In effect, this results in optical amplification
When two trains, going in opposite directions, are passing on tracks that are laid out close together, the train cars can often be seen to be leaning in toward one another where they are in proximity. How might the air passing through the narrow gap separating the two trains contribute to the observed attraction between their cars?
g n diffraction, the formula for minima is given by a times s i n (theta )equals m lambda, where a is the width of the slit, theta is the angle of dispersion, m is the order, and lambda is the wavelength. For a wavelength of 630 nm, m equals 3, and a equals 5 times 10 to the power of negative 6 end exponent m. Calculate the angular spread in Degrees. Enter only the numerical value (i.e. omit the unit abbreviations when inputting your answer into Blackboard).
Answer:
θ = 22.2
Explanation:
This is a diffraction exercise
a sin θ = m λ
The extension of the third zero is requested (m = 3)
They indicate the wavelength λ = 630 nm = 630 10⁻⁹ m and the width of the slit a = 5 10⁻⁶ m
sin θ = m λ / a
sin θ = 3 630 10⁻⁹ / 5 10⁻⁶
sin θ = 3.78 10⁻¹ = 0.378
θ = sin⁻¹ 0.378
to better see the result let's find the angle in radians
θ = 0.3876 rad
let's reduce to degrees
θ = 0.3876 rad (180º /π rad)
θ = 22.2º
Why can’t human males be carriers for sex linked (x-linked) disorders?
Answer:
This is because the X chromosome is large and contains many more genes than the smaller Y chromosome. In a sex-linked disease, it is usually males who are affected because they have a single copy of X chromosome that carries the mutation.
Explanation: