A 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2 , what is the coefficient of kinetic friction between the box and the inclined plane?

Answers

Answer 1

Answer:

Explanation:

                            F = ma

mgsinθ - μmgcosθ = ma

      gsinθ - μgcosθ = a

                   μgcosθ = gsinθ - a

                              μ = (gsinθ - a) / gcosθ

                              μ = (9.81sin24 - 0.245) / 9.81cos24

                              μ = 0.4178906...

                              μ = 0.418

Answer 2

The coefficient of kinetic friction will be equal to 0.418.

What is friction?

Friction is the force that prevents solid surfaces, fluid layers, and material elements from sliding against each other. There are various kinds of friction: Dry friction is the force that opposes the relative lateral motion of two in-touch solid surfaces.

Given that a 1.95 kg box sits on an incline of 24 ° with the horizontal. If the box accelerates down the incline at 0.245 m/s 2

The coefficient of kinetic friction will be calculated as,

F = ma

mgsinθ - μmgcosθ = ma

gsinθ - μgcosθ = a

μgcosθ = gsinθ - a

Solve for the value of the coefficient of friction,

μ = (gsinθ - a) / gcosθ

μ = (9.81sin24 - 0.245) / 9.81cos24

μ = 0.4178906...

μ = 0.418

Therefore, the coefficient of kinetic friction will be equal to 0.418.

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Related Questions

The mass of a car is 625kg. Calculate the weight of the gravitational field strength is 10 N/kg.

Answers

Ans: 62.5

Explanation: [tex]F{net}[/tex] = m x a

                    1N = 1kg x 1m/ [tex]s{2}[/tex]

                     

A gazelle is grazing while standing in a fixed location. When it's startled by a predator, the gazelle accelerates uniformly for 16.8 s until it reaches a speed of 21.9 m/s. The gazelle then runs in a straight line at constant speed for an additional 16.4 s. Finally, it uniformly slows to a stop at a rate of 1.8 m/s/s. What is the total distance traveled by the gazelle in meters

Answers

Answer:

Explanation:

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average speed was 21.9/2 = 10.95 m/s

distance covered is 10.95 m/s(16.8 s) = 183.96 m

distance at top speed 21.9 m/s(16.4 s) = 359.16 m

distance while decelerating (0² - 21.9²)/(2(-1.8)) = 133.225 m

total = 183.96 + 359.16 + 133.225 = 676.345 = 676 m

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Anything can happen at any moment. And if you have a plan for anything it will make things easier for you.

Calculate the net force acting on a body of mass 20 kg moving with a
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Answers

Answer:

0 N

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A stereo speaker produces a pure "A" tone, with a frequency of 220.0 Hz.

What is the period of the sound wave produced by the speaker?


T=


What is the wavelength water of the same sound wave as it enters some water, where it has a speed of about 1480 m/s?

λwater=


What is the wavelength air of this sound wave as it travels through air with a speed of about 341 m/s?

λair=

Answers

(a) The period of the sound wave is 0.005 s.

(b) The wavelength of the wave when the speed of the wave is 1480 m/s is 6.73 m.

(c) The wavelength of the sound wave as it travels through air is 1.55 m.

The given parameters;

Frequency of the wave, F = 220 Hz

The period of the sound wave is calculated as follows;

[tex]T = \frac{1}{f} \\\\T = \frac{1}{220} \\\\T = 0.005 \ s[/tex]

The wavelength of the wave when the speed of the wave is 1480 m/s is calculated as follows;

[tex]v = f\lambda \\\\\lambda = \frac{v}{f} \\\\\lambda = \frac{1480}{220} \\\\\lambda = 6.73 \ m[/tex]

The wavelength of the sound wave as it travels through air with a speed of about 341 m/s;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{341}{220} \\\\\lambda = 1.55 \ m[/tex]

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Question 2 of 25

If JKLM is a parallelogram, what is the length of LM?

K

18

8

M

O A. 10

O B. 18

O C. 8

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SUBMIT

Answers

Answer:its  10

Explanation:

Answer:

8

Explanation:

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Answers

Answer:

Explanation:

F = ma

F = 55000 kg(10.4)

F = 572000 N

That is an amazingly large elephant, more like 11 elephants

A more typical mass for a single elephant would be 5000 kg with a weight on Saturn of 52000 N

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Answers

The average value of voltage

The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just barely provides the centripetal force needed for the rotation. Calculate the minimum rotation period assuming a density of 3.70 g/cm3.

Answers

Answer:

m ω^2 R = centripetal force

G M m / R^2 = gravitational force

ω^2 = G M / R^3    for the forces to be equal

d (density) = M / V = M / (4/3 R^3) = 3/4 M / R^3

or M / R^3 = 4 d / 3

Then

ω^2 = G 4 d / 3

d = 3.7 g/cm^2 = 3700 kg/m*3    converting

ω^2 = 6.67E-11 * 3700 * 4 / 3 = 32.9E-8

ω = 5.74E-4

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Explanation:

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Answer:

26 g's

Explanation:

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Have a great day

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no

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Answers

Explanation:

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speed= 38m/s

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Answers

Answer:

C that's 10N I think. not sure though

Fireworks have a very high reaction rate. Describe and explain what could be done to slow down their reaction.

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Answer:

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What are fireworks chemically?

Gunpowder is typically made using three reagents: potassium nitrate, carbon, and Sulphur. These kinds of elements are used in a combustion reaction that results in this detonation explosion. You have solid reagents reacting to produce gases in the form of solid potassium carbonate, solid potassium sulphate, nitrogen gas, and carbon dioxide gas.

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Answers

Answer:

Explanation:

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Answers

Answer:

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Answers

Answer:

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Answer:  Your answer Is A)

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False.

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Answers

Answer:

Explanation:

Potential energy at the top of the slide

PE = mgh = 49(9.8)(3) = 1,440.6 J

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Converted potential that becomes kinetic energy

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If a person climbed Mt. Everest has a mass of 105 kg and a weight of 625 N what would be the acceleration due to gravity?

Answers

The acceleration due to gravity would be 5.95 m/s²

A force is known to be a push or pull and it is the change in momentum per time. It can be expressed by using the relation.

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From the parameters given:

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By replacing the given values into the above equation, we can determine the acceleration.

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