A 20-kilogram mass is attached to a spring. If the frequency of simple harmonic motion is 2/p cycles/s, what is the spring constant k? What is the frequency of simple harmonic motion if the original mass is replaced with an 80-kilogram mass?

Answer:

Step-by-step explanation:

Given system of equations in the question are,

-3x + y = -6

y = [tex]\frac{1}{2}x-1[/tex]

We can rewrite these equation as,

-3x + y = -6

y = 3x - 6 ------(1)

Table of input-output values for this equation will be,

x       0      1        2         3          4

y      -6     -3       0         3          6

y = [tex]\frac{1}{2}x-1[/tex] ------(2)

Table for this equation will be

x        0        2         4         6         8

y        -1        0         1          2         3

By plotting these points on the graph we find (2, 0) is a common point in both the tables,

Therefore, (2, 0) is the only one solution of the given system of equations.

Answer:

A

Step-by-step explanation:

Answer:

A True, law of detachment.

Answer:

Due to the higher z-score, David has the higher standardized score

Step-by-step explanation:

Z-score:

In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Which student has the higher standardized score

Whoever had the higher z-score.

David:

Scores on Ms. Bond's test have a mean of 70 and a standard deviation of 11. David has a score of 52 on Ms. Bond's test. So [tex]X = 52, \mu = 70, \sigma = 11[/tex]

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{52 - 70}{11}[/tex]

[tex]Z = -1.64[/tex]

Steven:

Scores on Ms. Nash's test have a mean of 64 and a standard deviation of 6. Steven has a score of 52 on Ms. So [tex]X = 52, \mu = 64, \sigma = 6[/tex]

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{52 - 64}{6}[/tex]

[tex]Z = -2[/tex]

Due to the higher z-score, David has the higher standardized score

Answer:

A)

Step-by-step explanation:

Answer:

[tex] \dfrac{5x^2 + 5x + 3}{3x^2 + 3x} [/tex]

Step-by-step explanation:

[tex] \dfrac{2x + 3}{3x} + \dfrac{x}{x + 1} = [/tex]

[tex] = \dfrac{(x + 1)(2x + 3)}{(x + 1)(3x)} + \dfrac{(3x)(x)}{(3x)(x + 1)} [/tex]

[tex] = \dfrac{2x^2 + 3x + 2x + 3}{3x^2 + 3x} + \dfrac{3x^2}{3x^2 + 3x} [/tex]

[tex] = \dfrac{2x^2 + 5x + 3 + 3x^2}{3x^2 + 3x} [/tex]

[tex] = \dfrac{5x^2 + 5x + 3}{3x^2 + 3x} [/tex]

Answer:

56 ft

Step-by-step explanation:

Because the bedroom is similar to the bed we can write that

7 : 15 = 6 : x

x = 15*6/7 ≈ 12.86 ft

Perimeter of the bedroom is

15*2 + 12.86 *2 ≈ 56 ft

Answer:

(a)[tex]R(x)=-0.02x^2+610x[/tex]

(b)[tex]R'(x)=-0.04x+610[/tex]

(c)R'(5400)=$394

Step-by-step explanation:

Given that x is the quantity demanded and the speaker's unit price (in dollars) is p where:

p = −0.02x + 610 (0 ≤ x ≤ 20,000)

(a)Revenue function R.

Revenue = Price X Quantity Demanded

Therefore:

R(x)=xp

[tex]=x(-0.02x + 610)\\R(x)=-0.02x^2+610x[/tex]

(b)Marginal revenue function R'(x)

If [tex]R(x)=-0.02x^2+610x[/tex]

Then, the marginal revenue function

[tex]R'(x)=-0.04x+610[/tex]

(c)We want to compute R'(5,400)

[tex]R'(5400)=-0.04(5400)+610\\R'(5400)=394[/tex]

From the above, we can infer that the revenue that will be generated on the sales of the 5401st item is $394.

Answer:

[tex]\boxed{CD = 7.1}[/tex]

Step-by-step explanation:

The coordinates are (6,-5) and (-1,-4)

Distance Formula = [tex]\sqrt{(x2-x1)^2+(y2-y1)^2}[/tex]

CD = [tex]\sqrt{(-1-6)^2+(-4+5)^2}[/tex]

CD = [tex]\sqrt{(-7)^2+(1)^2}[/tex]

CD = [tex]\sqrt{49+1}[/tex]

CD = [tex]\sqrt{50}[/tex]

CD = 7.1 units (nearest tenth)

Answer: CD = 7.1

Step-by-step explanation:

Plug in each x coordinate and y coordinate into the distance formula.

d = √(-1 - 6)² + (-4 + 5)²

d = √(-7)² + (1)²

d = √49 + 1

d = √50

√50 = 7.1

d = 7.1

Answer:

true

Step-by-step explanation:

Answer:

Polly can choose 33264 schedules.

Step-by-step explanation:

None of these sections interfere with each other, so:

For each statistics choice, there are 12 composition choices.

For each composition choice, there are 11 section of Ethics choices.

For each section of Ethics choice, there are 18 Physics choises.

There are 14 statistics choices.

From how many possible schedules can Polly choose?

14*12*11*18 = 33264

Polly can choose 33264 schedules.

Answer:

0

Step-by-step explanation:

Using the slope formula

m = (y2-y1)/(x2-x1)

    = (4-4)/(3-4)

     = 0/-1

   = 0

Answer:14/3 ×2/7Step-by-step explanation:14/3÷7/2

take reciprocal

=14/3×2/7

Hope this may help you

If the answer is correct please mark me the brainlest

Answer:

Option 2

Step-by-step explanation:

=> [tex]4\frac{2}{3} / 3\frac{1}{2}[/tex]

Changing them into improper fractions

=> [tex]\frac{14}{3} / \frac{7}{2}[/tex]

Changing division sign into multiplication and inverting the term after it

=> [tex]\frac{14}{3} * \frac{2}{7}[/tex]

Answer:

5

Step-by-step explanation:

=> 2x+3

For x = 1

=> 2(1) + 3

=> 2+3

=> 5

Answer:

5

Step-by-step explanation:

2x + 3

Put x as 1 and evaluate.

2(1) + 3

2 + 3

= 5

Answer:

B / px= k

Step-by-step explanation:

B = kpx

Divide each side by px

B / px= kpx/px

B / px= k

Answer:

First option

Step-by-step explanation:

B=kpx

B=k*(px)

Then,

[tex]k = \frac{b}{px} [/tex]

Answer:

  (–ꝏ, 0) U (0, 5)

Step-by-step explanation:

The relation can be written as ...

  x³ < 5x²

  x³ -5x² < 0

  x²(x -5) < 0

This is not true for x = 0. It is true for x < 5, otherwise. Then the solution set is ...

  x ∈ {(–ꝏ, 0) U (0, 5)}

Answer:

C

Step-by-step explanation:

got it right on edge

Answer:

a. Test statistic t = -0.14

b. P-value = 0.443

c. D. Fail to reject H0. There is insufficient evidence to support the claim that those given a sham treatment have pain reductions that vary more than those treated with magnets.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that those given a sham treatment have pain reductions that vary more than the pain reductions for those treated with magnets.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2< 0[/tex]

The significance level is α=0.05.

The sample 1 (sham), of size n1=20 has a mean of 0.44 and a standard deviation of 1.24.

The sample 2 (magnet), of size n2=20 has a mean of 0.49 and a standard deviation of 0.95.

The difference between sample means is Md=-0.05.

[tex]M_d=M_1-M_2=0.44-0.49=-0.05[/tex]

The estimated standard error of the difference between means is computed using the formula:

[tex]s_{M_d}=\sqrt{\dfrac{\sigma_1^2+\sigma_2^2}{n}}=\sqrt{\dfrac{1.24^2+0.95^2}{20}}\\\\\\s_{M_d}=\sqrt{\dfrac{2.4401}{20}}=\sqrt{0.122}=0.3493[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-0.05-0}{0.3493}=\dfrac{-0.05}{0.3493}=-0.14[/tex]

The degrees of freedom for this test are:

[tex]df=n_1+n_2-2=20+20-2=38[/tex]

This test is a left-tailed test, with 38 degrees of freedom and t=-0.14, so the P-value for this test is calculated as (using a t-table):

[tex]P-value=P(t<-0.14)=0.443[/tex]

As the P-value (0.443) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that those given a sham treatment have pain reductions that vary more than the pain reductions for those treated with magnets.

The 90% confidence interval for the mean net change in LDL cholesterol after the garlic treatment is approximately -1.799 to 7.199, suggesting that the effectiveness of garlic in reducing LDL cholesterol is not statistically significant.

We have,

To construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment, we can use the formula:

CI = X ± (Z * (σ/√n))

where:

CI is the confidence interval

X is the sample mean

Z is the critical value corresponding to the desired confidence level (90% confidence level corresponds to Z = 1.645 for a large sample size)

σ is the population standard deviation

n is the sample size

Given that the sample mean X of the net change in LDL cholesterol is 2.7, the standard deviation (σ) is 17.8, and the sample size (n) is 47, we can calculate the confidence interval as follows:

CI = 2.7 ± (1.645 * (17.8/√47))

Calculating the standard error (SE):

SE = σ/√n = 17.8/√47 ≈ 2.587

Substituting the values into the confidence interval formula:

CI = 2.7 ± (1.645 * 2.587)

Calculating the upper and lower bounds of the confidence interval:

Upper bound = 2.7 + (1.645 * 2.587) ≈ 7.199

Lower bound = 2.7 - (1.645 * 2.587) ≈ -1.799

Therefore, the 90% confidence interval estimate for the mean net change in LDL cholesterol after the garlic treatment is approximately -1.799 to 7.199.

Interpreting the confidence interval:

Since the confidence interval contains both positive and negative values, it suggests that the effectiveness of garlic in reducing LDL cholesterol is not statistically significant.

The interval includes zero, indicating that there is a possibility that the mean net change in LDL cholesterol after the garlic treatment could be zero (no change).

However, it is important to note that further studies or a larger sample size may be needed to draw more definitive conclusions.

Thus,

The 90% confidence interval for the mean net change in LDL cholesterol after the garlic treatment is approximately -1.799 to 7.199, suggesting that the effectiveness of garlic in reducing LDL cholesterol is not statistically significant.

Learn more about confidence intervals here:

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The 90% confidence interval suggests that the true mean net change in LDL cholesterol after the garlic treatment lies between -1.57 and 6.97 mg/dL. Since the interval contains both positive and negative values, it indicates that the garlic treatment may or may not be effective in reducing LDL cholesterol.

To construct a 90% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment, we can use the formula:

CI = mean ± (Z * (standard deviation / √n))

Here, n represents the sample size (47), Z is the critical value corresponding to a 90% confidence level (Z = 1.645 for a 90% confidence level), and the mean is 2.7 with a standard deviation of 17.8.

Plugging in the values:

CI = 2.7 ± (1.645 * (17.8 / √47))

CI = 2.7 ± (1.645 * (17.8 / 6.856))

CI = 2.7 ± (1.645 * (2.596))

CI = 2.7 ± 4.270

CI = 2.7 + 4.270  ;  CI = 2.7 - 4.270

CI = 6.97             ;  CI = -1.57

Thus, the 90% confidence interval estimate for the mean net change in LDL cholesterol after the garlic treatment is approximately (-1.57, 6.97).

The confidence interval suggests that the effectiveness of garlic in reducing LDL cholesterol is inconclusive. The interval spans both positive and negative values, indicating that the true mean change in LDL cholesterol could be anywhere within this range. Further research or a larger sample size might be needed to draw a more definitive conclusion about the effectiveness of garlic in lowering LDL cholesterol.

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Answer:

1/20

Step-by-step explanation:

5 brown marbles, 3 yellow marbles, 4 red marbles, 6 blue marbles, and 2 orange marbles = 20 marbles

P( brown) = brown / total = 5/20 = 1/4

Replace

5 brown marbles, 3 yellow marbles, 4 red marbles, 6 blue marbles, and 2 orange marbles = 20 marbles

P( red) = red / total = 4/20 = 1/5

P( brown, replace, red) = 1/4 * 1/5 = 1/20

Answer:

B

D

A

Step-by-step explanation:

Given:

A. [tex]2x^3-x^{2} -6x[/tex]

B. [tex]2x^3+8x+4[/tex]

C. [tex]3x^4+x^{2} +x-7[/tex]

D. [tex]3x^4-3x^{2} +5x-7[/tex]

Now, let us evaluate the given expressions one by one.

[tex](4x^3-4+ 7x)-(2x^3-x-8)\\\Rightarrow 4x^3-4+ 7x-2x^3+x+8\\\Rightarrow 2x^3+8x+ 4[/tex]

It is equation B.

So, [tex](4x^3-4+ 7x)-(2x^3-x-8)[/tex] is equivalent to B.

[tex](-3x^2+x^4+x)+(2x^4-7+4x)\\\Rightarrow -3x^2+x^4+x+2x^4-7+4x\\\Rightarrow3x^4-3x^{2} +5x-7[/tex]

It is equation D.

So, [tex](-3x^2+x^4+x)+(2x^4-7+4x)[/tex]  is equivalent to D.

[tex](x^{2} -2x)(2x+3)\\\Rightarrow 2x^3-4x^{2} +3x^{2} -6x\\\Rightarrow 2x^3-x^{2} -6x[/tex]

It is equation A.

So, [tex](x^{2} -2x)(2x+3)[/tex] is equivalent to A.

So, answer is:

B

D

A

Answer:

B D A

Step-by-step explanation:

Hope I Helped

Answer:

the second one

Step-by-step explanation:

We can see that the fence is made by a rectangle and a trapezoid

A1 is the area of the rectangle and A2 is the area of the trapezoid

Answer:

lower 95% Cl is 0.292

Step-by-step explanation:

p^ = 0.4783

n = 23

for 95% Cl,

z = 1.9600

Inputting all the available data into P as attached below

LCL = 0.292

UCL = 0.670

therefore, lower 95% Cl = 0.292

Answer:

EF ≈ 3.8

Step-by-step explanation:

Using the Sine rule in Δ DEF

[tex]\frac{EF}{sin75}[/tex] = [tex]\frac{DE}{sin50}[/tex] , that is

[tex]\frac{EF}{sin75}[/tex] = [tex]\frac{3}{sin50}[/tex] ( cross- multiply )

EF × sin50° = 3 × sin75° ( divide both sides by sin50° )

EF = [tex]\frac{3sin75}{sin50}[/tex] ≈ 3.8

Answer:

The margin of error is of 0.038 = 3.8%.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].

For this problem, we have that:

[tex]n = 320, \pi = \frac{70}{320} = 0.21875[/tex]

90% confidence level

So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]M = 1.645\sqrt{\frac{0.21875(1-0.21875)}{320}}[/tex]

[tex]M = 0.038[/tex]

The margin of error is of 0.038 = 3.8%.

Answer:

mean score of class B = 1778/25 = 71.12

Step-by-step explanation:

This was your question : Class A has 12 pupils and class B has 25 pupils. Both classes sit the same maths test. The mean score for class A is 80. The mean score for both classes is 74. What is the mean score (rounded to 2 DP) in the maths test for class B?

mean of class A = Σfx/Σf

mean of class A =  80

Σfx = 80 × 12 = 960

Mean score for both classes = 74

where

b = Σfx  of class B

960 + b/37 = 74

cross multiply

960 + b = 2738

b = 2738 - 960

b = 1778

mean score of class B = Σfx/Σf

Σfx = 1778

Σf = 25

Therefore,

1778/25 = 71.12

Answer:

a). Horizontal distance = 11.1 m

b). Maximum height = 6.2 m

c). Firefighter is 13.7 m from the house

Step-by-step explanation:

Given question is incomplete; find the complete question in the attachment.

Height of the water can be determined by the expression,

h(x) = -0.026x²+ 0.577x + 3

Here x = Horizontal distance of the from the firefighter

a). Since the stream of the water will follow a parabolic path, maximum point of the parabola will be = Vertex of the parabolic path

Horizontal distance from the firefighter at which the water achieves the maximum height = -[tex]\frac{b}{2a}[/tex]

From the quadratic function,

h(x) = -0.026x²+ 0.577x + 3

a = -0.026

b = 0.577

Therefore, the horizontal distance = [tex]-\frac{0.577}{2\times (-0.02612)}[/tex] = 11.05 m

                                                         ≈ 11.1 meters

b). By putting x = 11.1 in the quadratic equation,

    h(x) = -0.02612(11.1)²+ 0.577(11.1) + 3

           = -3.2182 + 6.4047 + 3

           = 6.18 m

           ≈ 6.2 m

c). For h(x) = 6 m

    6 = -0.02612x² + 0.577(x) + 3

    0.02612x² - 0.577x + 3 = 0

    From quadratic formula,

    x = [tex]\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]

    x = [tex]\frac{0.577\pm \sqrt{(-0.577)^2-4(0.02612)(3))}}{2(0.02612)}[/tex]

    x = [tex]\frac{0.577\pm\sqrt{0.019489}}{0.05224}[/tex]

    x = [tex]\frac{0.577\pm0.1396}{0.05224}[/tex]

    x = 13.7 m, 8.37 m

Therefore, the farthest distance of the firefighter from the house will be 13.7 m

Answer:

Step-by-step explanation:

To find the common ratio of the geometric sequence divide the previous term by the next term

That's

0.9 / 0.45 = 2

1.8 / 0.9 = 2

Therefore the common ratio is 2

Hope this helps you

Answer:

S = 2π/9 [³/₂√10 − ½ ln(-3 + √10)]

S ≈ 3.946

Step-by-step explanation:

For a curve rotated about the x-axis, the surface area is:

S = ∫ₐᵇ 2πy ds,

where ds = √(1 + (dy/dx)²) dx.

y = e⁻³ˣ

dy/dx = -3e⁻³ˣ

ds = √(1 + (-3e⁻³ˣ)²) dx

S = ∫₀°° 2πe⁻³ˣ √(1 + (-3e⁻³ˣ)²) dx

If u = -3e⁻³ˣ, then du = 9e⁻³ˣ dx, or du/9 = e⁻³ˣ dx.

When x = 0, u = -3.  When x = ∞, u = 0.

S = ∫₋₃⁰ 2π √(1 + u²) (du/9)

S = 2π/9 ∫₋₃⁰ √(1 + u²) du

S = 2π/9 [ ½ u √(1 + u²) + ½ ln|u + √(1 + u²)| ] |₋₃⁰

S = 2π/9 {[0] − [ -³/₂√10 + ½ ln(-3 + √10) ]}

S = 2π/9 [³/₂√10 − ½ ln(-3 + √10)]

S ≈ 3.946

The area of a surface is the amount of space it occupies.

The area of the resulting surface is [tex]3.947[/tex] square units

The infinite curve is given as:

[tex]y =e^{-3x},\ \ x \ge 0[/tex]

Integrate y, with respect to x

[tex]\frac{dy}{dx} = -3e^{-3x}[/tex]

The area of the curve about the x-axis is:

[tex]S = \int\limits^a_b {2\pi y} \, ds[/tex]

[tex]ds = \sqrt{(1 + (\frac{dy}{dx})^2)}\ dx[/tex]

Substitute [tex]\frac{dy}{dx} = -3e^{-3x}[/tex] in [tex]ds = \sqrt{(1 + (\frac{dy}{dx})^2)}\ dx[/tex]

[tex]ds = \sqrt{(1 + (-3e^{-3x})^2)}\ dx[/tex]

Let

[tex]u = -3e^{-3x}[/tex]

So:

[tex]\frac{du}{dx} = 9e^{-3x}[/tex]

Make [tex]e^{-3x}\ dx[/tex] the subject

[tex]e^{-3x}\ dx = \frac{du}9[/tex]

[tex]x \ge 0[/tex] means that, the value of x is: [tex][0,\infty][/tex]

When [tex]x = 0[/tex]

[tex]u = -3e^{-3x}[/tex]

[tex]u = -3 \times e^{-3 \times 0} = -3[/tex]

When [tex]x = \infty[/tex]

[tex]u = -3 \times e^{-3 \times \infty} = 0[/tex]

Recall that:

[tex]S = \int\limits^a_b {2\pi y} \, ds[/tex]

Substitute [tex]ds = \sqrt{(1 + (-3e^{-3x})^2)}\ dx[/tex] and [tex]y =e^{-3x}[/tex]

This gives

[tex]S = \int\limits^0_{-3} {2\pi (e^{-3x}) \sqrt{(1 + (-3e^{-3x})^2)}\ dx}[/tex]

Rewrite as:

[tex]S = \int\limits^0_{-3} {2\pi \sqrt{(1 + (-3e^{-3x})^2)}\ (e^{-3x})\ dx}[/tex]

Substitute [tex]u = -3e^{-3x}[/tex] and [tex]e^{-3x}\ dx = \frac{du}9[/tex]

[tex]S = \int\limits^0_{-3} {2\pi \sqrt{(1 + u^2)}\ \frac{du}9}[/tex]

This gives

[tex]S = \frac{2\pi}{9} \int\limits^0_{-3} {\sqrt{(1 + u^2)}\ du}[/tex]

Integrate with respect to u

[tex]S = \frac{2\pi}{9}[\frac 12 u\sqrt{(1 + u^2)} + \frac 12\ln|u + \sqrt{1 + u^2}|\ ]|\limits^0_{-3}[/tex]

Substitute 0 and -3 for u

[tex]S = \frac{2\pi}{9}([\frac 12\times 0 \times \sqrt{(1 + 0^2)} + \frac 12\ln|0 + \sqrt{1 + 0^2} ] - [\frac 12 \times (-3) \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]

[tex]S = \frac{2\pi}{9}([0] - [\frac 12 \times (-3) \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]

[tex]S = \frac{2\pi}{9}(- [\frac 12 \times (-3) \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]

[tex]S = \frac{2\pi}{9}(- [\frac{-3}2 \times \sqrt{(1 + (-3)^2)} + \frac 12\ln|-3 + \sqrt{1 + (-3)^2} ] )[/tex]

[tex]S = \frac{2\pi}{9}( [\frac{3}2 \times \sqrt{10} - \frac 12\ln(-3 + \sqrt{10}\ )] )[/tex]

[tex]S = \frac{2\pi}{9}( [4.743 + 0.909] )[/tex]

[tex]S = \frac{2\pi}{9}( 5.652 )[/tex]

[tex]S = 3.947[/tex]

Hence, the area of the resulting surface is [tex]3.947[/tex] square units

Read more about areas at:

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Answer:

The answer is "1.555"

Step-by-step explanation:

In the given question choices were not defined som the correct answer to this question can be defined as follows:

Given:

The value of  z* for 88% confidence interval are:

[tex]\to \frac{Z_{\alpha}}{2} \\\\\to Z_{0.06}\\\\\to \boxed{1.555}[/tex]

Answer:

100

Step-by-step explanation:

So this equation would look something like this -->

8(9.75 - 3.25) + 12 x 4 => Since we have decimals then we should subtract in the parenthasees.

9.75 - 3.25 = 6.5

--> 8(6.5) + 12 x 4 --> 8(6.5) + 48 =>

8(6.5) = 52 --> 52 + 48 = 50 + 50 = 100

Thus, we have our answer of 100

Hope this helps!

Answer:

The answer is 100

Step-by-step explanation:

The equation that we are solving is 8(9.75 - 3.25) + 12 x 4

The order of operations are:

These are my steps that I did to solve the problem:

The final answer is 100.

Answer:

y=3

Step-by-step explanation:

y + 3 = –y + 9

Add y to each side

y+y + 3 = –y+y + 9

2y+3 = 9

Subtract 3 from each side

2y+3-3 = 9-3

2y = 6

Divide by 2

2y/2 = 6/3

y =3

Answer:

Hello!

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Your answer would be (B) y = 3

Step-by-step explanation: Isolate the variable by dividing each side by factors that don't contain the variable.

Hope this helped you!

Answer:

  y = √(900 -x²); see below for a graph

Step-by-step explanation:

The high point (30 ft) is the radius of the circle, so the equation is ...

  x² +y² = 30²

Subtract the x-term and take the square root to find y.

  y² = 30² -x²

  y = √(30² -x²) = √(900 -x²)

The graph is shown in the attachment.

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Comment on "how that website works"

We don't know what web site you're referring to, but the one I like is Desmos. It only takes a few minutes to learn to graph the equation here.

You don't even need to solve for y to get the desired graph. You can simply specify that y ≥ 0.