The magnitude of the force exerted on the 300 kg bumper car is 500 N.
option B.
What is Newton's third law of motion?
Newton's third law of motion states that for every action force, there is an equal and opposite reaction force. That is action force and reaction force are equal in magnitude but opposite in direction.
Mathematically, the formula for Newton's third law of motion is given as;
Fa = - Fb
where;
Fa is the force exerted on 200 kg bumperFb is the reaction force of 300 kg bumperFb = - 500 N
| Fb | = 500 N
Thus, the force exerted by 200 kg bumper is to the force exerted by 300 kg bumper.
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the drawing shows a uniform electric field that points in the negative y direction; the magnitude of the field is 3230 n/c. determine the electric potential difference the following points.
These locations, where the potential difference between Vab and Vcb is 0 and 258v, respectively, have a uniform electric field with a magnitude of 3230 n/c.
The potential difference, also referred to as voltage, is equal to the amount of current multiplied by the resistance. One Joule of energy is consumed by a charge when it moves between two points in a circuit at a potential difference of one Volt. respectively, have a uniform electric field with a magnitude of 3230 n/c. An electric field is a type of physical field that exists around electrically charged particles and which influences the behaviour of all other charged particles nearby (or E-field).
whereas Vcb = E/d = 3230*0.08 = 258v, Vba = E/d = 0
Vba = E/d = 0
Vcb = E/d = 3230*0.08 = 258v
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Question 4 (Mandatory) (1 point)
MS-PS1-2: Which is an example of a chemical reaction?
Examples of reactions could include burning sugar or steel wool, fat reacting with sodium hydroxide, and mixing zinc with hydrogen chloride.
Define chemical reaction?A chemical reaction is a process that transforms one set of chemical substances into another.A chemical reaction is a process that converts one or more substances, known as reactants, into one or more different substances, known as products.Chemical elements and compounds are both examples of substances.Chemical reactions involve the formation of new bonds between atoms in product particles and the breaking of chemical bonds between reactant molecules (particles). The number of atoms is the same before and after the chemical change, but the number of molecules is different.When chemical bonds between atoms form or break, chemical reactions occur.To learn more about chemical reaction refer to:
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part a compare the energy of a 1-megaton hydrogen bomb to the energy released by a major earthquake.
The energy of a 1-megaton hydrogen bomb will be 5 times to the energy released by a major earthquake.
A weapon with a 1 megaton yield would be as powerful as 1 million tonnes of TNT. In terms of joules, a megaton is equal to 4.18 1015. A 1-megaton hydrogen bomb will have a 5 times greater energy output than a large earthquake. An earthquake emits energy at a variety of frequencies, so all of the shaking frequencies during the entire event must be taken into account in order to get an appropriate figure. The observed amplitude increases tenfold with each whole number rise in size, while the energy released is 32 times greater.
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if the 1.5-m-long cord ab can withstand a maximum force of 3500 n, determine the force in cord bc and the distance y so that the 200-kg crate can be supported. fbc
3500 N is the same amount of force in cord BC as it is in cord AB. The equation of equilibrium Fy=Fabsin(theta)=Fbccos(theta), where theta is the angle between the two cords, may be used to compute the distance y.
The idea of force equilibrium can be used. To balance the weight of the crate (200 kg * 9.8 m/s2 = 1960 N), the force in cord BC (F bc) must be equal to the force in cord AB (3500 N). The idea of mechanical advantage may also be used to determine the distance y, which in this example equals the weight-to-force ratio of the BC cord. As a result, y = (200 kg * 9.8 m/s2) / 3500 N = 0.564 m if we assume that y is the distance from the point of suspension to the container. As a result, the distance y is 0.564 m and the force in cord BC is 3500 N.
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if 34.5 g of copper reacts with 70.2 g of silver nitrate, according to the following reaction, what is the maximum number of grams of silver that can be produced?\
44.55g of silver can be produced by reacting 34.5 g of copper with 70.2 g of silver nitrate by following the chemical reaction in the given condition.
First, we balanced the equation
1Cu + 2AgNO3 → 1Cu(NO3)2 + Ag
Then, we find the moles of each reagent
molCu = 34.5g/(63.55*9/mol) = 0.543 mol
molAgNO3 = 70.2/(63.55*9/mol) = 0.423 mol
Now, we find the limiting reagent from the quantities of product that can be formed from each reagent
molAgNO3 = 0.543 molCu.2molAgNO3/1molCu= 1.086 mol
molCu = 0.413molAgNO3.1molCu/2molAgNo3 = 0.206mol
1,086 moles of AgNO3 is necessary for each mole of Cu since we have 0.413 moles of Ag(NO3), the nitrate is the limiting reagent
the value of the limiting reagent determines the amount of product that is generated
∴ 0,413 mol of Ag can be produced
Ag = 0.423mol.107.87*g/mol = 44.55 g = 44,55g
Ag≈ 44.6 g
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a car travels along stright line at constant speed of 20 m/s for a distance d and then another distance in the same direction at constant speed of 30 km/hr. what is averege speed of the entire trip?
A car traveling at a constant speed of 20 m/s has travelled 3 minutes × 60 seconds/minute * 20 m/s = 3600 meters after 3 minutes.
What is speed?The rate at which an object's position changes in any direction is referred to as its speed. The ratio of distance travelled to travel time is used to determine speed. Velocity and speed are two terms used to describe how quickly an object moves along a path. That is to say, velocity is a vector and speed is a scalar value.
Speed is defined as the rate at which a distance changes over time. The base units of distance and time are combined to form the SI unit of speed. Distance multiplied by speed Time is equal to one metre per second. The SI unit for speed is the m/s.
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suppose that you drive the 9.7 km from your university to home in 25.5 min. (note: average speed is distance traveled divided by time of travel.) your average speed in km/h is
The average speed of the travel from university to home is calculated to be 22.82 km/hr.
Average speed is known to be described as the total distance travelled by an object in particular time interval.
Given that,
Distance travelled = 9.7 km
Time taken for travel = 25.5 min
We know, 1 hour = 60 min
Converting minutes to hours, we have, 25.5/60 = 0.425 hr
The relation between distance, speed and time is known to be, distance = speed × time
Making speed as subject, we have,
Speed = Distance/time = 9.7/0.425 = 22.82 km/hr
The required average speed of the travel from university to home is calculated to be 22.82 km/hr.
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The top of the mercury thread in a mercury glass thermometer reached point X at 0 Celsius and point Z at 100 Celsius..
The top of the mercury thread in a mercury glass thermometer reached point X at 0 Celsius and point Z at 100 Celsius- Point Y.so, option (b) is correct.
What is thermometer ?
An instrument used to gauge how hot or cold something is is called a thermometer. Thermometers can be used to check your temperature or determine whether you have a fever. The definition of a thermometer, which is made up of the words thermo (heat) and meter (measuring tool), is rather simple.
What is mercury ?
A variety of industries employ mercury. It is used to make caustic soda and chlorine gas, as well as in thermometers, barometers, batteries, and electrical switches.: a heavy silver-white toxic metallic element that is liquid at normal temperatures and is utilized particularly in scientific instruments. the quicksilver symbol for the element mercury.
Therefore, top of the mercury thread in a mercury glass thermometer reached point X at 0 Celsius and point Z at 100 Celsius- Point Y.so, option (b) is correct.
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A small fly of mass 0.30 g is caught in a spider's web. The web vibrates predominately with a frequency of 3.4 Hz.
-what is the value of the effective spring stiffness constant "k" for the web, in N/m?
-At what frequency would you expect the web to vibrate if an insect of mass 0.60g were trapped, in Hz?
I tried using the equation f=1/2pi*sqrt(k/m) but am not getting it right. Help greatly appreciated!!!!
The effective spring stiffness constant "k" for the web will be 0.139 N/m and frequency will be 2.83 Hz.
Frequency is defined as the rate of changes in current direction per second. It is given in hertz (Hz), an internationally recognised unit of measurement. One cycle per second is equal to one hertz. Cycles per second are represented by the unit hertz (Hz). A cycle is the technical term for a whole alternating current or voltage pulse.
(a) m = 0.30 g = 0.30 x 10^-3 kg
f = 3.4 Hz
Spring frequency can be calculated using the formula below
f = [tex]\frac{1}{2pi} \sqrt{\frac{k}{m} }[/tex]
so solving,
Where, k be the spring constant
k = 0.139 N/m
(b)
k = 0.139 N/m
Let the frequency be f.
f = [tex]\frac{1}{2pi} \sqrt{\frac{k}{m} }[/tex]
f = 2.83 Hz
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What goes up must come down"-if you throw a baseball in the air, it will go upwards and then descend in a _____ curve.
Answer:
it will come down in a parabola curve
1. What is the work done created when a vehicle is pushed by a force of 106N producing a distance of 10.5m?
2. What is the friction force if the coefficient of friction of a box in a ground is 0.3 and its mass is 101kg, and the gravitational acceleration is 9.81 m/s2?
3. What is the net work done if the change in kinetic energy 200 J
4. What is the net work done if an object of mass 50 kg initially moving at 2m/s increases its velocity to 6 m/s?
5. What is the final velocity of an object with a mass of 5.2kg if the initial velocity was 2 m/s and the net work done is 50 J.
6. If the mass of the object (M) is 2kg.
The force (F) of 58 N displaces the object M by 3 m. The coefficient of friction is 0.3 and the gravitational acceleration is 9.81 m/s2. Find the net work done.
HELP ASAP
The net work done is the sum of the work done by the force (F) and the work done by friction.
What is the net work done if the change in kinetic energy 200 J?The work done by force (F) is calculated as Force × Distance (F × d), which in this case is 58 N × 3 m = 174 Nm.The work done by friction is calculated as Force × Distance (μ × m × g × d), in this case 0.3 × 2 kg × 9.81 m/s2 × 3 m = 58.2 Nm.Therefore, the net work done is 174 Nm + 58.2 Nm = 232.2 Nm. This is the amount of work done when the object of mass 2 kg is displaced by a force of 58 N over a distance of 3 m, with a coefficient of friction of 0.3 and a gravitational acceleration of 9.81 m/s2.The net work done in this example is the sum of the work done by the force of 58 N and the work done by the frictional force.The work done by the force of 58 N is given by W = F x d = 58 N x 3 m = 174 J.The work done by the frictional force is given by W = Ff x d = Ff x d = 0.3 x 9.81 x 2 kg x 3 m = 29.22 J.Therefore, the net work done is the sum of both work, which is W = 174 J + 29.22 J = 203.22 J.This type of net work is known as the work of non-conservative forces, since the frictional force opposes the motion of the object and reduces the total energy of the system.To learn more about the work of non-conservative forces refer to:
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a rocket is to be launched from deep space where there is no gravitational field. 81% of the initial mass of the rocket is fuel and this fuel is injected with a relative velocity of 2300 m/s.
The rocket's initial upthrust when it first starts traveling upwards is 2300 N.
What is force?A force is an effect in physics that may modify the velocity of an item. A force can cause a mass item to change its velocity, or accelerate. Intuitively, force may be characterized as a push or a pull. A force is a vector quantity since it has both magnitude and direction. The term "force" has a specific meaning in science. At this level, it is quite acceptable to refer to a force as a push or a pull. A force is not something that an item possesses or possesses. Another item applies a force to another. The concept of a force is not restricted to living or nonliving entities.
Here,
It ejects fuel vapours at the rate of 1 kg/sec. this fuel is injected with a relative velocity of 2300 m/s.
F=dm/dt*v
=1*2300
=2300 N
The initial upthrust on the rocket when it just starts moving upwards is 2300 N.
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men went to the moon by means of a shell shot from a large cannon sunk in the ground. part a what muzzle speed must the cannon have in order for the shell to reach the moon? express your answer to two significant digits and include the appropriate units. activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type vshell vshell
The smallest speed at which a moving object, like a rocket, can fly outward into space and escape the gravitational field of a celestial body, such the earth.
How is escape velocity calculated?The smallest speed at which a moving object, like a rocket, can fly outward into space and escape the gravitational field of a celestial body, such the earth.Escape Earth's speed is 2 X 9.8 X 6.4 X 106 m/s or V = (gR) M/s is equal to 11200 M/s, or 11.2 km/s or 7 mph. Consequently, if an object is launched upward from the surface of the earth at a speed of 11.2 km/s, it will be able to escape, or move past the influence of the earth's gravitational field.Egress speed, When anything decelerates faster than gravity weakens, it never returns because gravity weakens more quickly than it does. With the speed of Earth's escape, the object will continue to move away from the planet forever.To learn more about escape velocity refer to:
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work and Tes...
Three plates may be charged positively or negatively or be
electrically neutral. In the drawing shown, plate A is attracted by
both plates B and C. What occurs if plates B and C are brought
close together?
A
↑
B
A
C
OB and C would attract one another.
OB and C would repel one another.
B and C would exert no force on each other.
There is too little information given to make a conclusion.
a spring is stretched by 35 cm and attached to a 500 g air-track glider, which is then released. the spring does 0.30 j of work on the glider as it returns to its equilibrium length. What is the value of the spring constant?
The value of the spring constant for the spring stretched by 35 cm is 0.000244 J/cm.
To calculate the spring constant, the equation
Work = Force x Distance. The work of the spring (0.30 J) is known, as well as the distance the spring is stretched (35 cm). Therefore, the force is calculated by dividing the work by the distance is 0.0086 erg.
Force = - spring constant x Distance
The force is then divided by the distance the spring is stretched back to its equilibrium position (35 cm) to find the spring constant. The spring constant is the amount of force required to stretch the spring 1 cm. In this example, the spring constant is 0.000244 J/cm.
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find the distance that the earth travels in three days in its path around the sun. assume that a year has 365 days and that the path of the earth around the sun is a circle of radius 93 million miles. [note: the path of the earth around the sun is actually an ellipse with the sun at one focus (see section 11.2). this ellipse, however, has very small eccentricity, so it is nearly circular.] (round your answer to one decimal place.)
To find the distance that the Earth travels in three days in its path around the sun, we first need to find the circumference of the Earth's orbit. We can use the formula for the circumference of a circle, C = 2πr, where C is the circumference, π is approximately equal to 3.14, and r is the radius of the circle (93 million miles).
C = 2πr = 2 * 3.14 * 93 million miles = 584 million miles
Now that we know the circumference of the Earth's orbit, we can find the distance the Earth travels in three days by multiplying the circumference by the proportion of the orbit that the Earth travels in three days.
Three days is 3/365 of a year, so we can use the following formula:
Distance = (3/365) * C = (3/365) * 584 million miles = 40,931 miles
Therefore, the distance that the Earth travels in three days in its path around the sun is approximately 40,931 miles
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A racecar starting from rest acclerates uniformly at a rate of 4.9 meters per second2.What is the car's speed after it has traveled 200 meters
The speed of the car after 200 meters is v = 44.3 m/s (3 sf).
What is speed?The rate at which an object's position changes in any direction is referred to as speed. The ratio of distance travelled to travel time is used to calculate speed. Speed and Velocity both refer to how quickly something moves along a path. Speed measures how quickly something moves along a path.
In other words, velocity is a vector and speed is a scalar value. The rate at which a distance changes over time is referred to as speed. The base unit of distance plus the base unit of time are combined to form the SI unit of speed. Distance times speed metre second equals time. m/s is the SI unit for speed.
u = 0
a = 4.9
s = 200
v² = 0²+2*4.9*200
v = √(2*4.9*200)
v = √1960
v = 44.3 m/s (3 sf)
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a 67-kg base runner begins his slide into second base when he is moving at a speed of 3.3 m/s. the coefficient of friction between his clothes and earth is 0.70. he slides so that his speed is zero just as he reaches the base.
The runner moves 0.80 metres before stopping at second base. To resolve this issue, we can make use of the ideas of labour and energy.
The friction force on the runner's work can be computed as follows:
W_friction = -f_friction * d, where
f_friction = friction force = μ_k * N
N = normal force = m * g
d = distance traveled by the runner
The initial kinetic energy of the runner is given by:
K_initial = (1/2) * m * v^2
The runner's final kinetic energy is zero. According to the work-energy theorem, an object's kinetic energy changes when work is done to it. As a result, the initial kinetic energy of the runner and the work produced by friction are equal:
W_friction = ΔK = K_initial
When we substitute the values, we obtain:
W_friction = - μ_k * m * g * d = (1/2) * m * v^2
μ_k * m * g * d = (1/2) * m * v
^2
d = (1/2) * v^2 / (μ_k * g)
By substituting the values, we get:
d = (1/2) * (3.3^2) / (0.7 * 9.8) = 0.80 m
As a result, the runner moves 0.80 metres before stopping at second base.
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A person measures his or her heart rate by counting the number of beats in 30 s. If 33 ± 1 beats are counted in 30.0 ± 0.5 s, what is
the uncertainty in the heart rate in beats per minute?
The uncertainty in the heart rate in beats per minute is 2 minute by using the rules for propagation of uncertainty.
How to calculate uncertainty in the heart rate in beats per minute?
To find the heart rate in beats per minute, we need to divide the number of beats by the time in minutes. So, we have (33 ± 1 beats) / (0.5 min). To find the uncertainty in the heart rate, we need to find the propagation of uncertainty for this division.
Using the rules for propagation of uncertainty, we have:
(heart rate) = (33 ± 1 beats) / (0.5 min)
(heart rate) = 66 ± (1/0.5) beats/min
(heart rate) = 66 ± 2 beats/min
So the uncertainty in the heart rate is 2 beats per minute.
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which of the following is an example of kinetic energy? view available hint(s)for part a which of the following is an example of kinetic energy? the energy held in bonds between atoms wind rotating a turbine a book on the top shelf of a closet a rock on top of a hill
A windmill turning An illustration of kinetic energy is the following.
What exactly is an energy in science?The ability to "achieve work," or the capability to exert a force strong enough to move an item, is how energy is defined. Despite the ambiguity in the definition, the idea is actually pretty simple: electricity simply refers to the force that propels objects. The two different categories of energy are potential and kinetic.
Simple energy definitionThe most basic definition of energy is the capacity for work. Energy causes things to move and change. It's everywhere and comes in a variety of shapes. Energy is needed while cooking food.
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suppose you receive a traffic ticket for speeding and want to contest it in court. come up with two arguments, one using systematic error and the other using random error, that you could use to challenge the the speed given by either your speedometer or the radar gun.
Systematic error:
You could use systematic error to challenge the speed indicated by your speedometer or radar gun.
A systematic error is one that occurs as a result of a consistent and repeatable cause, such as a malfunctioning instrument or a calibration problem.
You could, for example, argue that the officer's radar gun was not properly calibrated, resulting in a consistently higher measurement of your speed.
Random error:
Another argument you could use to challenge the speed given by your speedometer or radar gun is that the measurement was influenced by random error.
Random error is a type of error that occurs as a result of uncontrollable factors such as wind or temperature changes.
You could, for example, argue that the wind was blowing hard on the day you received the ticket, affecting the accuracy of the radar gun's measurement.
It's important to note that these are just some of the possible arguments for fighting a traffic ticket. When determining whether an error occurred and whether it is significant enough to contest the ticket, the court will consider a number of factors.
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The figure below shows the trajectory of a particle with mass m bound to (orbiting) an object of mass M by the Newtonian gravitational force. At which location(s) does the equation Fnet = m|v⃗|^2/|r⃗| apply?
The figure below shows the trajectory of a particle with mass m bound to (orbiting) an object of mass M by the Newtonian gravitational force therefore the location which equation Fnet = mv²/r applies is at B.
What is Centripetal force?This is referred to as any force which causes a change in direction of velocity toward the center of the circular motion and the formula is mv²/r .
For an object moving in a circular path, the centripetal force acts on it towards the centre of the path and in this scenario, location B is closest to the centre and the force which makes it remain on that same path which is why it was chosen as the correct choice.
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for the charge distribution provided, indicate the region (a to e) along the horizontal axis where a point exists at which the net electric field is zero. (figure 2)
At point C along the horizontal axis, the net electric field is zero.
Electrically charged particles are surrounded by a physical phenomenon termed an electric field that either attracts or repels all other adjacent charged particles. The physical field surrounding a system of charged particles can also be referred to. Electric charges and time-varying electric currents make up electric fields.Both electric and magnetic fields are manifestations of the electromagnetic field, one of the four fundamental interactions (sometimes known as forces) of nature.
1. In the region B along the horizontal axis , a point exists at which the net electric field is zero.
2. Nowhere in any region along the horizontal axis the net electric field is zero.
3. In the region A along the horizontal axis , a point exists at which the net electric field is zero.
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Vacillate the change in the. Kinetic energy KE of the bottle when the mass is increased use the formula KE=1/2 mv2 where m is the mass and v is the speed
When the mass is 0.125 kg, the kinetic energy is 1 J
When the mass is 0.250 kg, the kinetic energy is 2 J.
When the mass is 0.375 kg, the kinetic energy is 3 J.
When the mass is 0.500 kg, the kinetic energy is 4 J.
What is the kinetic energy of the bottle?
The kinetic energy of the bottle is the energy possessed by the bottle due to its mass and motion.
K.E = ¹/₂mv²
where;
m is the mass of the bottlev is the speed of the bottleWhen the mass is 0.125 kg, the kinetic energy is calculated as;
K.E = ¹/₂ x 0.125 kg x ( 4 m/s )²
K.E = 1 J
When the mass is 0.250 kg, the kinetic energy is calculated as;
K.E = ¹/₂ x 0.25 kg x ( 4 m/s )²
K.E = 2 J
When the mass is 0.375 kg, the kinetic energy is calculated as;
K.E = ¹/₂ x 0.375 kg x ( 4 m/s )²
K.E = 3 J
When the mass is 0.500 kg, the kinetic energy is calculated as;
K.E = ¹/₂ x 0.5 kg x ( 4 m/s )²
K.E = 4 J
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How do measured values of weather and climate differ?
Measured values of weather and climate differ from one another because the weather is a short-term change in the atmosphere whereas climate is the environmental condition over a long period in a specific area.
How do measure values of weather and climate differ?The part of weather and climate are those quantities or properties that are steady regularly. The six main elements are weather and climate: temperatures, atmospheric pressure, wind, humidity, drizzle, and cloudiness. Different land can have different climates.
Weather is called the day-to-day information of atmospheric changes in a specific area at a specific time. Climate is the statistical details on the average weather condition of a specific land for more than 30 years. 2. The weather of a place involves the short-term atmospheric condition.
So we can conclude that The difference allying weather and climate is a measure of time.
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) find the amplitude, period, and horizontal shift. (assume the absolute value of the horizontal shift is less than the period.)
By applying trigonometry function graph theory, it can be concluded that the amplitude is 2, the period is π, the horizontal shift is 0, and the equation that represents the graph is y = 2 cos (2x)
A trigonometry function is a function whose graph repeats continuously over a certain period. The trigonometry function graph consists of hills and valleys that repeat continuously over a certain period.
There are some terms regarding a trigonometry function graph:
Amplitude is the farthest deviation of a point on a trigonometric function graph from its horizontal line (eg the x-axis).Period is the distance the trigonometric function graph repeats from the initial reference point to the first repetition point.Horizontal shift is a shift to the left or right of the sin graph so that it is the same as the cosine graph and vice versa.Now we look at our trigonometric function graph.
Since the farthest deviation of the graph is in points (0,2), (π/2,-2), and (π,2), thus the amplitude of the graph is 2. We denote it as a = 2.
The graph repeats from the initial reference point to the first repetition point after π, thus the period of the graph is π.
The value of k can be obtained from this:
2π/k = period
k = 2π/period
= 2π/π
= 2
The horizontal shift is 0, which means there's no shifting on the cosine graph.
Now we input the value of a, k and b into the equation:
y = a cos (k (x - b))
= 2 cos (2 (x - 0))
= 2 cos (2x)
Thus the amplitude is 2, the period is π, the horizontal shift is 0, and the equation that represents the graph is y = 2 cos (2x)
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a small metal ball is given a negative charge, then brought near (i.e., within a few millimeters) to end a of the rod. what happens to end a of the rod when the ball approaches it closely this first time? select the expected behavior.
Weak attraction between the sphere and the rod is caused by end A of the rod inducing a positive charge (and correspondingly, end B acquires a negative induced charge).
This suggests that a charge may have moved from A to B. In an insulator, charge flow is restricted, hence the induced charges are frequently insignificant. because a pliable metal ball is charged negatively. Charged matter experiences a force when exposed to an electromagnetic field because of the physical nature of electric charge. Electrical charges can be positive or negative (commonly carried by protons and electrons respectively). Matter experiences a force when retained in an electromagnetic field due to the physical property of electric charge.
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The Ejection Seat at Lake Biwa Amusement Park in Japan is an inverse bungee system. A seat with passengers of total mass 160 kg is connected to elastic cables on the sides. The seat is pulled down 12.0 m stretching the cables launch the passengers upward above their starting position at the ground. Assume that the cables are vertical
Part A
Determine the spring constant of the cable
According to the problem the spring constant of the cable is 130 N/m.
What is spring?Spring is a season of renewal and growth that occurs between winter and summer. It is the time of year when plants and animals come back to life and the days become longer and warmer.
The spring constant of the cable can be determined using Hooke's Law, which states that the force exerted by a spring is proportional to the displacement from equilibrium. In this case, the displacement is 12.0 m, so the spring constant is given by:
k = F/x = (160 kg * 9.8 m/s2)/(12.0 m)
= 130 N/m
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the 50-kg passenger in a car moving at 10 m/s crashes into a tree and stops in 0.2 seconds. the average force exerted on the passenger to bring her to a stop is
The average force exerted on the passenger to bring her to a stop is 2500 Newton.
To calculate the average force exerted on the passenger, we can use the equation: force = mass x acceleration. The acceleration in this case is the deceleration experienced by the passenger, which can be calculated by dividing the change in velocity by the change in time.
In this case, the passenger's velocity changes from 10 m/s to 0 m/s in 0.2 seconds, so the deceleration is:
deceleration = (change in velocity) / (change in time)
deceleration = (0 m/s - 10 m/s) / 0.2 seconds
deceleration = -50 m/s²
Note that the negative sign indicates that the acceleration is in the opposite direction of the velocity. In this case, the passenger's velocity is initially positive (moving forward), but the deceleration is negative, indicating that the force is acting in the opposite direction, slowing the passenger down.
Therefore, the force exerted on the passenger is:
force = mass x acceleration
force = 50 x -50 = 2500 N.
force = 2500 Newton
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romeo (85.0 kg) entertains juliet (57.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m away from juliet, who is in the front of the boat. after the serenade, juliet carefully moves to the rear of the boat (away from shore) to plant a kiss on romeo's cheek.
The 80 kg boat moves 0.694 meter towards the shore, if juliet moves towards the romeo.
The mass of the romeo, m₁ = 85 kg
The mass of the juliet, m₂ = 57 kg
The mass of the boat, m₃ = 80 kg
Distance between romeo and juliet, = 2.70 m
If we take the juliet's initial position as a reference point, X₁ = 0
Centre of mass of the boat, X₂ = 2.7/2 = 1.35 m
Distance of romeo from reference point, X₃ = 2.7
Combined centre of gravity of the whole system,
Xₐ = (85×2.7 + 57×0 + 80×1.35)/(85+57+80)
Xₐ = 1.52
After juliet moves romeo, new center of gravity
Xₙ = ((85+57)×2.7 + 80×1.35)/(85+57+80)
Xₙ = 2.214 m
The distance moved by the boat, d = 2.214 - 1.52
d = 0.694 m
--The given question is incomplete, the complete question is:
"romeo (85.0 kg) entertains juliet (57.0 kg) by playing his guitar from the rear of their boat at rest in still water, 2.70 m away from juliet, who is in the front of the boat. after the serenade, juliet carefully moves to the rear of the boat (away from shore) to plant a kiss on romeo's cheek. How far does the 80 kg bus move towards the shore it is facing?"
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