a 200 kg car is travelling at 33m/s. what is the kinectic energy of the car​

Answer: [tex]278\ Hz[/tex]

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

[tex]\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m[/tex]

Condition for destructive interference is

[tex]\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}[/tex]

for second destructive interference; n=2

[tex]\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz[/tex]

Answer:

the focal length of the eyepiece is 17.23 cm

Explanation:

The computation of the focal length of the eyepiece is shown below:

= Focal length of objective lens ÷ angular magnification magnitude

= 86.3 ÷ -5.01

= 17.23 cm

Hence, the focal length of the eyepiece is 17.23 cm

We simply divided the angular magnification magnitude from the focal length of objective lens so that the focal length of the eyepiece could come

Answer:

b. He is 8 years old

Explanation:

We will use Einstein's formula for time dilation, to calculate the age of Lee. Because Lee was traveling comparable to the speed of light, his age must be lesser than Leigh.

[tex]T = \frac{T_o}{\sqrt{1-\frac{v^2}{c^2} } }[/tex]

where,

T₀ = Time on Earth = ?

T = Relative Time = 10 years

v = relativistic speed of Lee = 0.714 c

c = speed of light = 3 x 10⁸ m/s

Therefore,

[tex]10\ years = \frac{T_o}{\sqrt{1-\frac{(0.714\ c)^2}{c^2} } } \\\\[/tex]

T₀ = 7 years

Hence, the age of Lee will be:

[tex]Lee's\ Age = 1\ year + 7\ years = 8\ years[/tex]

b. He is 8 years old

Answer:

acceleration are

     hollow cylinder < hollow sphere < solid cylinder < solid sphere

Explanation:

To answer this question, let's analyze the problem. Let's use conservation of energy

Starting point. Highest point

          Em₀ = U = m g h

Final point. To get off the ramp

          Em_f = K = ½ mv² + ½ I w²

notice that we include the kinetic energy of translation and rotation

energy is conserved

        Em₀ = Em_f

        mgh = ½ m v² +1/2 I w²

angular and linear velocity are related

         v = w r

         w = v / r

we substitute

          mg h = ½ v² (m + I / r²)

          v² = 2 gh   [tex]\frac{m}{m+ \frac{I}{r^2} }[/tex]

          v² = 2gh    [tex]\frac{1}{1 + \frac{I}{m r^2} }[/tex]

this is the velocity at the bottom of the plane ,, indicate that it stops from rest, so we can use the kinematics relationship to find the acceleration in the axis ax (parallel to the plane)

         v² = v₀² + 2 a L

where L is the length of the plane

         v² = 2 a L

         a = v² / 2L

we substitute

         a = [tex]g \ \frac{h}{L} \ \frac{1}{1+ \frac{I}{m r^2 } }[/tex]

let's use trigonometry

         sin θ = h / L

we substitute

         a = g sin θ   \ \frac{h}{L} \  \frac{1}{1+ \frac{I}{m r^2 } }

the moment of inertia of each object is tabulated, let's find the acceleration of each object

a) Hollow cylinder

      I = m r²

we look for the acerleracion

      a₁ = g sin θ    [tex]\frac{1}{1 + \frac{mr^2 }{m r^2 } }[/tex]1/1 + mr² / mr² =

      a₁ = g sin θ    ½

b) solid cylinder

       I = ½ m r²

       a₂ = g sin θ  [tex]\frac{1}{1 + \frac{1}{2} \frac{mr^2}{mr^2} }[/tex] = g sin θ   [tex]\frac{1}{1+ \frac{1}{2} }[/tex]

       a₂ = g sin θ   ⅔

c) hollow sphere

     I = 2/3 m r²

     a₃ = g sin θ   [tex]\frac{1}{1 + \frac{2}{3} }[/tex]

     a₃ = g sin θ [tex]\frac{3}{5}[/tex]

d) solid sphere

     I = 2/5 m r²

     a₄ = g sin θ  [tex]\frac{1 }{1 + \frac{2}{5} }[/tex]

     a₄ = g sin θ  [tex]\frac{5}{7}[/tex]

We already have all the accelerations, to facilitate the comparison let's place the fractions with the same denominator (the greatest common denominator is 210)

a) a₁ = g sin θ ½ = g sin θ      [tex]\frac{105}{210}[/tex]

b) a₂ = g sinθ ⅔ = g sin θ     [tex]\frac{140}{210}[/tex]

c) a₃ = g sin θ [tex]\frac{3}{5}[/tex]= g sin θ       [tex]\frac{126}{210}[/tex]

d) a₄ = g sin θ [tex]\frac{5}{7}[/tex] = g sin θ      [tex]\frac{150}{210}[/tex]

the order of acceleration from lower to higher is

     a₁ <a₃ <a₂ <a₄

acceleration are

     hollow cylinder < hollow sphere < solid cylinder < solid sphere

Answer:

Yes, the value will be the same.

Explanation:

Yes, or at least to some degree, that value of K will remain the same. You're looking for a difference in absorbance, and the difference should be visible at all wavelengths, not only at the limit. That being said, resolution varies, and if we don't read the value to the maximum, we can get a less accurate reading.

Answer:

correct answer is A

Explanation:

The diagram shows a series circuit with three resistors and two power sources.

In a series circuit the current through the entire circuit is constant and the resistance is the sum of the resistances in the circuit.

When the power sources are placed in opposite position the voltage between them is subtracted.

     V_b - 30 = I (10 + 4 + 6)

     V_b = I (20) - 30

      V_b = 30 - 2 20

       V_b = 10 V

the correct answer is A

Answer:

Homogeneous mixtures

Explanation:

I think so because homogeneous means mixed mixtures

Answer:

fffffgggggggggggggghhh

Answer:

Answer will be the 2nd one. I think it will be the Answer

Answer:

D. all regions of the spectrum

Explanation:

I did some research ; )

Answer:

Nuclear fusion

Explanation:

This is because main sequence of star is powered by fusion of hydrogen to helium atoms together and this process releases energy. The energy released when the gas collapse into a protostar make the center of the protostar to be extremely hot. When the core becomes very hot, nuclear fusion can start.

Answer:

(A) The total resistance of the circuit is 25 Ω

(B) The current through each resistor is 4.4 A

(C) For 10Ω: Potential drop = 44 V

     For 15Ω: Potential drop = 66 V

Explanation:

Given;

potential difference, V = 110V

resistors in series, = 10Ω and a 15Ω

(A) The total resistance of the circuit is calculated as follows;

Rt = 10Ω + 15Ω = 25Ω

(B) The current through each resistor;

Same current will flow through the two resistors since they are in series.

I = V/Rt

I = 110 / 25

I = 4.4 A

(C) The voltage drop across each resistor;

For 10Ω: Potential drop = IR₁ = 4.4 x 10 = 44 V

For 15Ω: Potential drop = IR₂ = 4.4 x 15 = 66 V

Answer:

Explanation:

The answer is chemical energy

The magnitude of the angular acceleration of the pendulum at the moment of release is; α = 18.45 rad/s²

We are given;

Mass of rod; m = 1 kg

Length of rod; L = 49.8 cm = 0.498 m

Mass of Disk; M = 4 kg

Radius of disk; r = 24.9 cm = 0.249 m

Let us first calculate the torque acting from the formula;

τ = mg(L/2) + MgL

Thus;

τ = (1 × 9.8 × (0.498/2)) + (4 × 9.8 × 0.498)

τ = 21.96 N.m

Using parallel axis theorem, we can find the moment of inertia about the given axis as;

I = (mL²/3) + ½MR² + ML²

Plugging in the relevant values gives;

I = (1 * 0.498²/3) + ½(4 * 0.249²) + (4 * 0.498²)

I = 1.19 kg.m²

The angular acceleration is given by the formula;

α = I/τ

α = 21.96/1.19

α = 18.45 rad/s²

Read more at; https://brainly.com/question/23321366

The unit called horsepower is defined based on the amount of work a horse can do in 1 minute.

James Watt used the horsepower unit for the first time in 1782. According to the account, James Watt used a pony to charge coal from the mines. According to the narrative, he needed a unit to measure the force of one of these animals.

He discovers that they can move 22.000 lbs per minute and decides to (arbitrarily) boost this metric by 50%. Having been the unit 33.000 lb/ft per minute, horsepower is an engine's output horsepower rating, whereas brake horsepower is an engine's input brake horsepower.

Brake horsepower measures an engine's power without accounting for power losses, whereas HP accounts for power losses. Horsepower of the brakes

Therefore, the horsepower unit is defined by the amount of work a horse can do in one minute.

To learn more about horsepower, refer to the link:

https://brainly.com/question/8652948

#SPJ2

Answer:

a = 640 m/s²

Explanation:

From work-kinetic energy principles,

The net force acting on the second object is the gravitational force and the electric force due to the first object.

So, the gravitational force on the mass is F₁ = Gm₁m₂/r² since m₁ = m₂ = m, U = -Gm²/r²

Also, the electric force on the charge is F₂ = kq₁q₂/r² since q₁ = q₂ = q, U = kq²/r²

The net Force F = ma

So, -F₁ + F₂ = F     (F₁ is negative since it is an attractive force in the negative x -direction and F₂ is positive since it is a repulsive force in the positive x- direction)

-Gm²/r² + kq²/r² = ma

ma = -Gm²/r² + kq²/r²

a = (-Gm²/r² + kq²/r²)/m

a = (-G + kq²/m²)m/r²

Since m = 0.250 kg, q = 4.00 μC = 4.00 × 10⁻⁶ C, r = 3.00 cm = 3.00 × 10⁻² m, G = 6.67 × 10⁻¹¹ Nm²/kg², k = 9 × 10⁹ Nm²/C² and a = acceleration of second mass.

Substituting the variables into the equation, we have

a = (m/r²)(-G + k(q/m)²)]

a = (0.250 kg/{3.00 × 10⁻² m}²)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(4.00 × 10⁻⁶ C/0.250 kg)²)

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(16 × 10⁻⁶ C/kg)²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 9 × 10⁹ Nm²/C²(256 × 10⁻¹² C²/kg²)]

a = (0.250 kg/9.00 × 10⁻⁴ m)(-6.67 × 10⁻¹¹ Nm²/kg² + 2304 × 10⁻³ Nm²/kg²  ]

a = (0.250 kg/9.00 × 10⁻⁴ m)(2.304 Nm²/kg²)

a = 0.576 Nm²/kg /9.00 × 10⁻⁴ m²

a = 0.064 × 10⁴N/kg

a = 64 × 10 N/kg)

a = 640 m/s²

Answer:

Virtual

Explanation:

Answer:

B. Virtual

Good Luck!

Answer:

Not all appliances run on energy. Some of them run on gas. Some both. It just depends on the age of the appliance, the make of the appliance, and the company who made it.

Answer:

C!

Explanation:

Cold fronts generally advance at average speeds of 20 to 25 mph. toward the east — faster in the winter than summer — and are usually oriented along a northeast to southwest line.

Answer:

I think not sure B sorry if this is wrong yay if im right

Explanation:

Answer:

manage your weight better, have stronger bones, have lower blood pressure, less risk of a heart attack, etc.

Answer:

You become healthier, your body starts regulating better, you get stronger bones and muscles, and you lower the risk of diabetes,heart problems and other diseases.

Answer:

Friction.

Explanation:

Answer:

12 J

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 7.6 kg

Distance (d) = 6 m

Velocity (v) = 5 m/s

Force (F) = 2 N

Workdone (Wd) =.?

Workdone can be defined as the product of force and distance moved in the direction of the force. Mathematically, it is expressed as:

Workdone = Force × distance

Wd = F × d

With the above formula, we can obtain the workdone as follow:

Distance (d) = 6 m

Force (F) = 2 N

Workdone (Wd) =.?

Wd = F × d

Wd = 2 × 6

Wd = 12 J

Thus, the workdone is 12 J

Answer:

The potential difference between the ends of a wire is 60 volts.

Explanation:

It is given that,

Resistance, R = 5 ohms

Charge, q = 720 C

Time, t = 1 min = 60 s

We know that the charge flowing per unit charge is called current in the circuit. It is given by :

I = 12 A

Let V is the potential difference between the ends of a wire. It can be calculated using Ohm's law as :

V = IR

V = 60 Volts

So, the potential difference between the ends of a wire is 60 volts. Hence, this is the required solution.

Wouldn't it be B because it's a majority pointing to it?

Sorry if i'm wrong.

Answer:

the distance is 315.3696 m

Explanation:

The computation of the distance is given below:

Given that

Sound intensity = 1.67 × 10^-6 W/m^2

And, the distance = 233 m

Now as we know that

Power = Intensity × surface area

1.67 × 10^-6 × 4π(233)^2 = 1.67 × 10^-6 ÷ 2× 4π × d^2

d^2 = 2 × (223)^2

= √2 × 223

= 315.3696 m

Hence, the distance is 315.3696 m

Answer:

The units of kinetic energy are mass times the square of speed, or kg⋅m2/s2 kg ⋅ m 2 /s 2. But the units of force are mass times acceleration, kg⋅m/s2 kg ⋅ m/s 2, so the units of kinetic energy are also the units of force times distance, which are the units of work

Explanation:

EDGE 2021

Answer:

are nearby and bright i hope this helps