A 2.3 kg ball is held 20 m above the ground and released. How fast is
It moving when it hits the ground?

Explanation:

The triple beam balance is used to measure masses very precisely; the reading error is 0.05g

Answer:

First there is a need to convert 80.0 km/h to m/s. It is equivalent to (200 / 9) m/s. Because the body stops after 4.25 seconds, its acceleration is -(200/9/4.25) m/s^2. The needed force to stop the 2500 kg truck is equal to the product of its mass and its acceleration.

Solving for the net force to stop the 2500 kg truck

Force = mass * acceleration

Force = 2500 kg * -(200/9/4.25) m/s^2

Force = −13072 N or about −13.07 kN

The force exerted on the truck is −13072 N or about −13.07 kN

Answer:

C. Decreasing the pressure

Explanation:

Answer:

Hydrosphere and atmosphere

Explanation:

[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]

Actually Welcome to the Concept of the Power and Energy.

As a pendulum swings from the bottom position to the top position, it gains a height which means it gains the Potential energy.

hence we can say that, kinetic energy is changed into potential energy.

So, the Option A.) is correct.

Answer:

I think it's A)

Explanation:

it could be wrong i don't know hope it's not good luck!

Answer:

[tex]f= 3.0 \times 10 {}^{8} \div 7.0 \times 10 {}^{7} \\ f = 4.28hz[/tex]

Given

Whenever a body is in motion there is always a friction to oppose the motion.

"Friction is a force that resists the motion of one object against another."

Friction is a force that opposes relative motion between surfaces in contact. One of the simpler characteristics of friction is that it is parallel to the contact surface between surfaces and always in a direction that opposes motion or attempted motion of the systems relative to each other.

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Answer:

the three major elements of language include form, content, and use. form involves three sub-components of syntax, morphology, and phonology. content is also known as semantics and use can be known as pragmatics.

Explanation:

hope this helps! :)

Answer:

Force of [tex]37.44 * 10^{8}[/tex] Kgm/s^2 must be  applied to the piston to raise oil to a height of 6.0 m

Explanation:

As we know,

Pressure is the force per unit area

Or [tex]P = \frac{F}{A}[/tex]

Force [tex]= P * A[/tex]

Pressure is the product of density, gravitational constant and height

[tex]P = 780 * 10 * 6[/tex]

Force

[tex]= P * A\\= 780 * 10*6*8*10^4\\= 37.44 * 10^{8}[/tex]Kgm/s^2

The force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N. Force is defined as the ratio of presure and area. Its unit is Newton.

Force is defined as the push or pulls applied to the body. Sometimes it is used to change the shape, size, and direction of the body.

The given data in the problem is;

A is the area of a piston = 8 X 10⁴m².

F is the force=?

h is the height = 6.0 m

Force is defined as the ratio of presure and area. Its unit is Newton.

[tex]\rm P = \frac{F}{A} \\\\ \rm F = P \times A \\\\ \rm F = 780 \times 10^6 \times 8 \times 10^4 \\\\ \rm F = 37.44 \times 10^8[/tex]

Hence the force that must be applied to the piston to raise oil will be 37.44 ×10⁸ N.

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Answer:

90.0N

Explanation:

According to Newtons second law;

F = ma

\sumFx = max

Fm - Ff = max

Given

Moving force Fm = 90.0N

Ff is the frictional force is the mass

ax is the acceleration = 0m/s^2 (constant speed)

Substitute

90 - Ff = 75(0)

90 - Ff = 0

Ff = 90 - 0

Ff = 90.0N

Hence the frictional force is 90.0N

The best estimate of the magnitude of the box's acceleration is 0.35 m/s².

option D is the correct answer (last option)

The magnitude of the acceleration of the box is calculated by applying Newton's second law of motion as follows;

Mathematically, the formula for Newton's second law of motion is given as;

F (net) = ma

F - Ff = ma

where;

F - μmg = ma

where;

The acceleration of the box is calculated as follows;

F - μmg = ma

25 - (0.4 x 7 x 9.81) = 7a

-2.5= 7a

a = -2.5 / 7

a = -0.36 m/s² ≈ -0.37 m/s²

Thus, the acceleration of the box is a function of the applied force and force of friction.

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Answer:

  λ = 6 10⁻⁷ m, color orange

Explanation:

This problem is about the interference phenomenon, constructive interference occurs when the path difference is equal to an integer number of wavelengths

          d sim θ = m λ

Let's use trigonometry, remembering that the angles for these experiments are very small.

          Sin θ = y / L

          tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ

          sin θ = y / L

we substitute

         [tex]d \ \frac{y}{L} = m \lambda[/tex]

A) Donut length is requested

        λ = [tex]\frac{d \ y}{m \ L}[/tex]

let's calculate

        λ = 5 10⁻⁵ 0.06 /( 1  5)

        λ = 6 10⁻⁷ m

B) let's express the wavelength in nm

      λ = 6 10⁻⁷ m = 600 nm

this corresponds to the color orange

Answer:

Equal to 30°C.

Explanation:

The final temperature of both objects are equal to 30°C because of the conduction heat from one object to another. Both objects have same mass of 2 kg and both were isolated from the external environment so conduction of heat occurs from the more hotter body to the less hotter body until the temperature of both objects are equal to each other.

The final temperature of both objects is less than 30° C

The specific heat of an object is the minimum required quantity of heat needed to raise the temperature of 1 gram of the object(substance) by 1° C.

From the parameters given:

Using the Calorimetry principle, we need to understand that the heat lost by an object at a high temperature is proportionally equal to that heat gained by the object at a low temperature.

i.e.

[tex]\mathbf{Q_{lost}= Q_{gain}}[/tex]

[tex]\mathbf{ms_B \Big[40^0 \ C - \theta_o\Big]= ms_A \Big [ \theta_o - 20^0 \ C \Big]}[/tex]

Given that:

Then, let us consider a scenario where [tex]\mathbf{S_A = 1.5S_B}[/tex]

Thus;

[tex]\mathbf{S_B \Big[40^0 \ C - \theta_o\Big]= 1.5S_B \Big [ \theta_o - 20^0 \ C \Big]}[/tex]

[tex]\mathbf{40^0 \ C - \theta_o= 1.5 \theta_o - 20^0 \ C}[/tex]

[tex]\mathbf{ 2.5\theta_o= 70^0 \ C}[/tex]

[tex]\mathbf{ \theta_o= \dfrac{70^0 \ C}{2.5}}[/tex]

[tex]\mathbf{ \theta_o=28 ^0 C}[/tex]

Therefore, we can conclude that since the specific heat of object A is larger than that of object B i.e. [tex]\mathbf{S_A> S_B}[/tex], then the final temperature [tex]\mathbf{ \theta_o<30 ^0 C}[/tex]

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Answer:

Handwashing with soap has been shown to reduce the risk of gastroenteritis by up to 47%.

Of course, avoiding contaminated foods that could harbor toxic bacteria and parasites is also important.

Explanation:

Here's what I found on the web to further explain and give you more info :) , "Vaccinations are also effective, particularly for rotavirus. The rotavirus The use of clean water and good sanitation practices are important for reducing rates of infectious gastroenteritis.

vaccines have seen a marked decline in the rate and severity of disease in both developing and developed countries.

Oral rehydration is the cornerstone of treatment for those suffering from mild to moderate dehydration. This can be achieved through a solution containing water, salts, and sugar. For severe cases of dehydration, hospitalization and intravenous fluids may be required.

Antibiotics are generally not recommended unless the gastroenteritis is bacterial or parasitic and symptoms are severe.

I hope I helped! :)

Would appreciate Brainliest! ;)

Answer:

The velocity of the particles is "0.36×10⁸ m/s".

Explanation:

The given values are:

Magnetic field strength,

B = 5.0×10⁻⁴ N/Amp

In another experiment,

F = 1.8×10⁴

By considering the Lorentz force, the velocity will be:

⇒  [tex]qE=qvB[/tex]

then,

⇒  [tex]v=\frac{F}{B}[/tex]

On substituting the given values, we get

⇒     [tex]=\frac{1.8\times 10^4}{5.0\times 10^{-4}}[/tex]

⇒     [tex]=0.36\times 10^8 \ m/s[/tex]

Answer:

no it would not. that is an open circuit and it would need to be closed at the switch for current to flow.

The correct answer is (A) 8.3mm.

The total displacement will be the vector sum of the two displacements given in the question.

let the displacement to the south represent vector A = 5mm in magnitude directed toward south.

let the displacement to the south-west represent vector B = 4mm in magnitude directed toward south-west.

The angle between vector A and vector B is 45°, the angle between south and south-west.

SO the resultant

R = vectro A + vector B

[tex]R=\sqrt{A^{2}+B^{2}+2ABcos(45) } \\\\R=\sqrt{25+16+40*\frac{1}{\sqrt{2} } } \\\\R=8.3mm[/tex]

The ant's displacement is 8.3 mm in magnitude.

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Answer:

Newtons 1st law of inertia

Explanation:

Explanation:

probably the 1st law of motion, it'll continue at in a straight line as long as no external force is added or the net force equals to zero, same for the centrifugal force and the gravitational force

Answer:

Dynamic equilibrium

Explanation:

This is because dynamic equilibrium is when the body is set on motion at constant velocity. When humans are walking, when achieve unstable equilibrium that is not static or dynamic on the first foot and a non equilibrium when the other foot is involved. In human movement,it is at constant velocity and the Total number of forces acting is zero. This type of equilibrium always return to it's initial point after disturbances since humans did not continually walk all the time .

Answer:

low pressure systems

Explanation:

with a low pressure system over the area the storm can't form

Answer:

It's the Pendulum, it is because during its to and fro motion, it vibrates and simulataneously exhibit kinetic energy.

Explanation:

:)

Answer:

bouncing ball bc it has kinetic energy. the pendulum has potential energy.

Explanation:

Answer:

6.621 minutes per mile  

Explanation:

the .621 is repeating

Answer:

B. Fahrenheit measures temperature!

Answer:

2

Explanation:

She's attracted with a great force back to earth's surface

Explanation:

Given info: The Number of turns in the wire is 580 the diameter of  

tube is [tex]8.00 \mathrm{~cm}[/tex] and the length of the tube up to which wire is wrapped is [tex]36.0 \mathrm{~cm}[/tex].  

Formula to calculate the inductance of the coil is,  

[tex]L=\frac{\mu_{0} N^{2} A}{l}[/tex]  

Here,  

[tex]L[/tex] is inductance of the coil.  

[tex]\mu_{0}[/tex] is the permittivity.  

[tex]N[/tex] is the number of turns.  

[tex]l[/tex] is the length up to which wire is wrapped.  

[tex]A[/tex] is the cross sectional area of the coil.  

The expression for the area is,  

[tex]A=\frac{\pi d^{2}}{4}[/tex]

Substitute [tex]\frac{\pi d^{2}}{4}[tex] for [tex]A[/tex] in equation (1).  

[tex]L=\frac{\left(\mu_{0} N^{2}\right) \frac{d d^{2}}{4}}{l}[/tex]

Substitute 580 for [tex]N, 4 \pi \times 10^{-7}[tex] for [tex]\mu_{0}, 8.00 \mathrm{~cm}[tex] for [tex]d[tex] and [tex]36.0 \mathrm{~cm}[tex] for [tex]l .[/tex]  

[tex]\begin{array}{c}  

=\frac{4 \pi \times 10^{-7} \times 580 \times 580 \times \frac{x(8.00 \mathrm{~cm} \times 8.00 \mathrm{~cm})}{4}}{36 \mathrm{~cm}} \\  

=5.90 \mathrm{mH}  

\end{array} [/tex]

Conclusion:  

Therefore, the inductance of the given single conductor wire is  

[tex]5.90 \mathrm{mH} .[/tex]

Given info: The rate of increasing current [tex]4.00 \mathrm{~A} / \mathrm{s}[/tex] and the inductance of the coil [tex]5.90 \mathrm{mH}[/tex].

The generated emf is,

[tex]

\varepsilon=L \frac{d i}{d t}

[/tex]

Here,

[tex]\varepsilon[/tex] is the generated emf.

[tex]L[tex] is the inductance of the coil.

[tex]\frac{d i}{d t}[tex] is the rate of change of current.

Substitute [tex]5.90 \mathrm{mH}[tex] for [tex]L[tex] and [tex]4.00 \mathrm{~A} / \mathrm{s}[tex] for [tex]\frac{d i}{d t}[/tex]

[tex]\begin{array}{c}

\varepsilon=5.90 \mathrm{mH} \times 4.00 \mathrm{~A} / \mathrm{s} \\

= & 23.6 \mathrm{mV}

\end{array}[/tex]

Conclusion:

Therefore, the generated emf is [tex]23.6 \mathrm{mV}[/tex].

Answer:

The Saffir-Simpson Hurricane Wind Scale is a 1 to 5 rating based only on a hurricane's maximum sustained wind speed. This scale does not take into account other potentially deadly hazards such as storm surge, rainfall flooding, and tornadoes.

The Saffir-Simpson Hurricane Wind Scale estimates potential property damage. While all hurricanes produce life-threatening winds, hurricanes rated Category 3 and higher are known as major hurricanes*. Major hurricanes can cause devastating to catastrophic wind damage and significant loss of life simply due to the strength of their winds. Hurricanes of all categories can produce deadly storm surge, rain-induced floods, and tornadoes. These hazards require people to take protective action, including evacuating from areas vulnerable to storm surge.

Explanation:

pls mark as branlist.

Tropical hurricanes or cyclones are usually destructive with great wind speeds of 3 and above according to the Saffir Simpson Hurricane Wind Scale with huge amounts of rainfall resulting in flooding.

The Saffir Simpson Hurricane Wind Scale is scale that classifies wind based on wind speed using a scale of 1-5.

This scale does not take into account wind surge, amount of rainfall and other characteristics of storms.

Storms rated 3 and above are particularly strong and destructive.

Those rated below 3 are mild and less destructive.

Tropical hurricanes or cyclones are usually destructive with great wind speeds of 3 and above according to the Saffir Simpson Hurricane Wind Scale with huge amounts of rainfall resulting in flooding.

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Answer:

the total force vector, on test charge is points from origin to point C( 1, 1 )

Explanation:

Given the data in the question, as illustrated in the image below;

from the Image, OA = 1, OB = AC = 1

so using Pythagoras theorem

a² = b² + c²

a = √( b² + c² )

so

OC = √( OB² + AC² )

we substitute

OC = √( OA² + AC² )

OC = √( 1² + 1² )

OC = √( 1 + 1 )

OC = √2

Coordinate of C( 1, 1 )

Hence, the total force vector, on test charge is points from origin to point C( 1, 1 )