A 50-foot flagpole casts a shadow that is 30 feet long. A nearby building casts a shadow 130 feet long. What is the height, to the nearest foot, of the building?

Answers

Answer 1

the key to solve this problem is to find the angle. The angle tell us the position of the sun in the sky, then using trigonometry, we can know the hieght of the building.

To find the angle, we use the flag pole. We know the two legs of the right triangle. The trigonometric function that relates us an angle and two legs is tangent

[tex]\tan (\theta)=\frac{oppossite\text{ side}}{adyacent\text{ side}}[/tex]

In this case, the oposite leg to the angle is 50ft and the adyancent is 30ft

then,

[tex]\begin{gathered} \tan (\theta)=\frac{50ft}{30ft} \\ \theta=\tan ^{-1}(\frac{5}{3})\approx59º \end{gathered}[/tex]

The angle is 59º. Now we can go to the building. Using tangent again, we want to know the height, wich is the lenght of the opposite leg to the angle. Let's call the height h:

[tex]\begin{gathered} \tan (59º)=\frac{h}{130ft} \\ h=\tan (59º)\cdot130ft=216ft \end{gathered}[/tex]

The height of the building is 216ft

A 50-foot Flagpole Casts A Shadow That Is 30 Feet Long. A Nearby Building Casts A Shadow 130 Feet Long.

Related Questions

Which describes the transtormation trom figure ABCDEF to figure A'B CD E F, andtells Whather the to fgures are similar or congruent?Ooilation, similar0 reflection, similarratatión, congruem2 translation, congruent

Answers

Answer: translation, congruent.

Explanation

• A dilation is an expansion o reduction of a figure.

,

• A reflection is the image of a figure in a mirror.

,

• A rotation is a circular movement around an axis or rotation.

,

• A translation is moving a figure to a certain distance.

Based on this definitions, we can see that our figure A'B'C'D' describes a translation.

Write and solve a proportion using the fractions from parts (a) and (b) to determine how many miles she walks after 10 minutes. Round your answer to the hundredths place. ✓ Write the equation using the "WIRIS editor" button

Answers

if she walked 2 miles in 35 minutes, in 10 minutes she walks:

[tex]\frac{y}{10}=\frac{2}{35}\rightarrow y=\frac{2}{35}\cdot10=\frac{20}{35}=\frac{4}{7}\approx0.57mi[/tex]

Find the product? (x^2-2x-3)(3x^2+4x-1)

Answers

Solution

For this case we can do the following:

[tex](x^2-2x-3)(3x^2+4x-1)[/tex]

And we can multiply and we got:

[tex]3x^4+4x^3-x^2-6x^3-8x^2+2x-9x^2-12x+3[/tex]

and if we simplify we got:

[tex]3x^4-2x^3-18x^2-10x+3[/tex]

what is the function g(x) created from f(x)= x^2 by moving the graph left 4 units, vertically stretching it by a factor of 5, and shifting the graph down 8 units

Answers

As given by the question

There are given that the equation of current graph:

[tex]f(x)=x^2[/tex]

Now,

According to the question,

There are also given that graph left 4 units, that means

[tex](x+4)^2[/tex]

Then,

Vertical stretching it by a factor of 5 units

So,

The equation will be:

[tex]f(x)=5(x+4)^2[/tex]

Then,

And, shifting the graph down 8 units

So,

[tex]f(x)=5(x+4)^2-8[/tex]

Hence, the correct option is D

There are 113 girls and 121 boys in the marching band. The routine the band is practicing has all the musicians standing in equal rows. If the number of rows is between 10 and 15, how many rows are there? How many musicians are standing in each row?

Answers

Answer:

13 rows, 18 musicians per row

Step-by-step explanation:

Because there are in between 10 and 15 rows, I divided 234 (the total amount of musicians, 113+121) by all number in between 10 and 15: 10, 11, 12, 13, 14, and 15. Because the problem states that they were equally divided into, and you cant split a person into multiple parts, the answer logically must be a whole number. 234/ 13 rows equated to a whole number, or 18, the amount of musicians in each row.

What is the reciprocal of -3.4?

Answers

The reciprocal of a number is the result obtained when 1 is divided by the number

Hence the reciprocal of -3.4 is

= 1/-3.4

= -1/3.4

= -0.2941

Can you please help me solve the step by step7(x-6)=-14

Answers

we have the equation

7(x-6)=-14

solve for x

that means -----> isolate the variable x

step 1

Divide both sides by 7

7(x-6)/7=-14/7

simplify

x-6=-2

step 2

Adds 6 both sides

x-6+6=-2+6

x=4

What is the area of this parallelogram in square meters? 1.2 m 2.8 m

Answers

Solution

For this case we can find the area in the following way:

A= B*h

B= 2.8m represent the base

h= 1.2m represent the height

Replacing we got:

A= 2.8*1.2m = 3.36 m^2

I need to solve this quadratic equation even if the solution with involves imaginary numbers

Answers

Given:

The quadratic equation is:

[tex]25x^2+20x-59=0[/tex]

To solve the equation

[tex]ax^2+bx+c=0[/tex]

we have its roots as:

[tex]x=\text{ }\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}[/tex]

According to our question, we have a= 25 b= 20 c= - 59

Thus,

[tex]x=\frac{-20\pm\sqrt[]{20^2-4(25\times-59)}}{2\times25}[/tex][tex]\begin{gathered} x=\frac{-20\pm\sqrt[]{400+5900}}{50} \\ =\frac{-20\pm\sqrt[]{6300}}{50} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{-20\pm30\sqrt[]{7}}{50} \\ =\frac{-2\pm3\sqrt[]{7}}{5} \\ =\frac{-2+3\sqrt[]{7}}{5},\frac{-2-3\sqrt[]{7}}{5} \end{gathered}[/tex][tex]\begin{gathered} x=\frac{-2+3(2.64575)}{5},\frac{-2-3(2.64575)}{5} \\ x=\frac{-2+7.93725}{5},\frac{-2-7.93725}{5} \\ =\frac{5.93725}{5},\frac{9.93725}{5} \\ =1.18745,\text{ 1.98745} \end{gathered}[/tex]

Hence, x= 1.18745 , 1.98745

X-7=31 find the value of x

Answers

Answer:

add 7 to 31 thats 38 and thats what x equals

Step-by-step explanation:

Translate the following sentence into a one-step inequality: 9 subtracted from b is less than or equal to -21

Answers

[tex]b-9\leq-21[/tex]

Here, we want to get an inequality from the given statement

We take it one step at a time;

9 subtracted from b;

[tex]b\text{ - 9}[/tex]

Is less than or equal to -21

We have this as;

[tex]b\text{ - 9}\leq\text{ -21}[/tex]

At Target you found two sweaters that each cost $20.94, a pair of jeans that cost $17.83, and three pairs of shoes for $24.32 each. After 6.5% sales tax what is the total cost of the bill?

Answers

Given:-

Cost of sweaters is $20.94

Cost of pair of jeans is $17.83

Cost of three pair of shoes is $24.32

To find:-

The total cost of the bill with 6.5% sales tax.

Cost of two sweater is,

[tex]2\times20.94=41.88[/tex]

Cost of one pair of jeans is,

[tex]1\times17.83=17.83[/tex]

Cost of three pairs of shoes is,

[tex]3\times24.32=72.96[/tex]

To find the total cost we need to add all the three cost. so we get,

[tex]41.88+17.83+72.96=132.67[/tex]

Now we find the 6.5% of 132.67. we get,

[tex]\frac{6.5}{100}\times168=10.941[/tex]

Now we add,

[tex]undefined[/tex]

How many times smaller is the value of the three in 53,075 then the three in 38,499

Answers

10 times smaller

To find out how How many times smaller is the value of the 3 in 53,075

Let's check by rewriting it in the expanded form both numbers

53,075 = 50000 +3,000 + 75

38,499=30,000 + 8000 + 499

As we can see in 53075 the 3 is 10 times smaller since 3000 is 10 times smaller than 30,000 in 38,499

10 times smaller

-8-7-6-5-4-3-212.345678-1 0-1-2R-4-5-6s-7-8which action cames pero QRSTIfocion vers SToction or the ansoffection over the autochon over dagena RTEducation

Answers

A reflection over diagonal RT

1) Considering that we're dealing with reflection symmetry and the Parallelogram QRST.

(In red the axis of symmetry)

2) So we can reflect that quadrilateral QRST onto itself by those two red lines of symmetry, its line half of that figure is mirrored across.

3) Hence, examining the answers, we can state that the answer is

A reflection over diagonal RT

Malcolm is driving 1, 373 miles from Wichita to Charleston for a family reunion. He drives 468 miles the first day and 434miles the second day. Round each distance to the nearest ten and estimate about how many miles Malcolm has left to drive.

Answers

This problem describes two parts of a trip, on the first day the trip was 468 miles long, and on the second day, it was 434 miles long. We need to calculate how far from the destination the driver is from their destiny after the second day, knowing that the whole trip is 1373 miles long.

The first step we need to take, is to round the distances for each day to the nearest ten, this is done below:

[tex]\begin{gathered} \text{ day 1}\cong470\text{ miles} \\ \text{ day 2}\cong430\text{ miles} \end{gathered}[/tex]

Now we need to subtract the distances for each day from the total distance:

[tex]\begin{gathered} \text{ distance left}\cong1373-470-430 \\ \text{ distance left}\cong473 \end{gathered}[/tex]

The driver needs to drive approximately 470 miles to complete the trip.

Jenny invests $3,072 in a savings accountwith a fixed annual interest ratecompounded continuously. After 8 years,the balance reaches $5,378.07. What isthe interest rate of the account?A) 6% B) 8%C) 79% D) 5%

Answers

Given:

Principal amount, P = $3,072

Time, t = 8 years

Final Amount, A = $5,378.07

To find the interest rate since it is compounded continuously, take the compound interest formula below:

[tex]undefined[/tex]

The office supply superstore sell pens for 60 cents each and pencils for 40 cents each. Diane purchased a total of 17 items (pens and pencils) for $8.20. How many pens did Diane purchase?

Answers

Diane purchased 7 pens

Explanation:

Cost of one pen = 60 cents = 60/100 = $0.60

Cost of one pencil = 40 cents =40/100 = $0.40

let the number of pens bought = x

let the number of pencils bought = y

[tex]\begin{gathered} \text{Diane bought a total of 17 items}\colon \\ nu\text{mber of pens + number of pencils = 17} \\ x\text{ + y = 17 }\ldots equation\text{ 1} \end{gathered}[/tex][tex]\begin{gathered} \text{The cost of the 17 items = \$8.20} \\ nu\text{mber of pens(cost per one) + number of pencils(cost per one) = 8.20} \\ x(0.60)\text{ + y(0.40) = 8.20 } \\ x(0.6)\text{ + y(0.4) = 8.20 } \\ 0.6x\text{ + 0.4y = 8.2 ...equation 2} \end{gathered}[/tex]

combining both equatons:

x + y = 17 ....equation 1

0.6x + 0.4y = 8.2 ...equation 2

using substitution method:

let's make x the subject of formula

from equation 1:

x = 17 - y ....equation 3

substitute for x in equation 2:

0.6(17 - y) + 0.4y = 8.2

10.2 - 0.6y + 0.4y = 8.2

collect like terms:

10.2 - 0.2y = 8.2

10.2 - 8.2 = 0.2y

2 = 0.2y

y = 2/0.2

y = 10

substitute for y in equation 1:

x + 10 = 17

x = 17 - 10

x = 7

x = number of pens = 7

Hence, Diane purchased 7 pens



Find the value of -6 -3 -5 5 7 -6 3 9 9

Answers

Given

To use Sarrus we must copy the first two columns

And the determinant will be

Doing the simplification

[tex]\begin{gathered} -549-(+84) \\ -549-84 \\ \\ -633 \end{gathered}[/tex]

Therefore, the determinant is -633.

Angela earns a gross income of 2800 a month .angela's budget is as shown in the table below how much will Angela have left after paying her taxes?

Answers

Angela's Gross Income (per month) = $2800

Her tax rate is 18%.

Let's find 18% of 2800:

[tex]\begin{gathered} \frac{18}{100}\times2800 \\ =0.18\times2800 \\ =504 \end{gathered}[/tex]

Angela pays $504 in taxes.

Thus, she will have left:

2800 - 504 = $2296

Question 9 (5 points)(02.05 LC)Solve the inequality 2x + 8 < 5x - 4. (5 points)a x > 4 b x > 1 c x < 1 d x < 4

Answers

Given:

2x + 8 < 5x - 4.

Required:

To tell which option is correct

Explanation:

First of all rearrange the equation and subtract what is on rigjt side we get

2x+8-(5x-4)<0

pull out like factors

-3x+12=-3(x-4)

divide both side by 3

remember to flip the inequality sign

solve basic inequality and we get

x>4

Require

Solve the following inequality for x.5x - 3 <2x+6

Answers

As given by the question

There are given that the inequality:

[tex]5x-3<2x+6[/tex]

Now,

Add 3 on both sides of the inequality

So,

[tex]\begin{gathered} 5x-3<2x+6 \\ 5x-3+3<2x+6+3 \\ 5x-<2x+9 \end{gathered}[/tex]

Then,

Subtract 2x from both sides of the above inequality.

[tex]\begin{gathered} 5x<2x+9 \\ 5x-2x<2x+9-2x \\ 3x<9 \end{gathered}[/tex]

Then,

Divide both sides by 3

So,

[tex]\begin{gathered} 3x<9 \\ \frac{3x}{3}<\frac{9}{3} \\ x<3 \end{gathered}[/tex]

Hence, the value of the given inequality is, x < 3.

QUESTION NO. 1: Solve the system by the method of substitution. (If there is no solution, enter NO SOLUTION.)x − y = 26x − 5y = 16(x, y) = (larger x-value)

Answers

Let's determine the solution using the method of Substitution.

Equation 1:

x - y = 2

-y = -x + 2

(-y = -x + 2)/-1

y = x - 2 (Substitue to the second equation)

6x - 5y = 16

6x - 5(x - 2) = 16

6x - 5x + 10 = 16

x = 16 - 10

x = 6 (Substitute to the 1st equation)

y = x - 2

y = 6 - 2

y = 4

Therefore, the solution is x, y = 6, 4

A study is done on the number of bacteria cells in a petri dish. Suppose that the population size after hours is given by the following exponential function.

Answers

Given the exponential function:

[tex]P(t)=1800(1.03)^t[/tex]

Where P models the population size after t hours. The initial population size can be obtained using t = 0:

[tex]\begin{gathered} P(0)=1800(1.03)^0=1800(1) \\ \therefore P(0)=1800 \end{gathered}[/tex]

The initial population size is 1800.

Now, since the term inside the parentheses is greater than 1, we can conclude that this function represents a growth tendency.

Finally, we can take the ratio between the population size at time t and at time t+1:

[tex]\begin{gathered} \frac{P\left(t+1\right)}{P(t)}=\frac{1800(1.03)^{t+1}}{1800(1.03)t}=1.03=1+0.03 \\ \\ Change:\Delta=|1-\frac{P(t+1)}{P(t)}|=|1-1-0.03|=0.03 \end{gathered}[/tex]

In percent form, the change is 3%

I am sending you a oic n= 122 p= 0.64the mean u is 78.1 round to the nearest tenth as needed the variance Q to at the top is 28.1 round to nearest teth as neededthe standard devation Q is blank round to the nearest tenth as needed

Answers

To answer this question, we have that the standard deviation is the

Ngraph?108+fog64Of(-3) = 94O f(-4) = gOf(-3) = g(Of(-4) = 962++B-4-3-2-12+ 1 2 3 4 5 6 x-6--8EL-10NO-120

Answers

Intersection of Lines

The image shows two lines, f(x) in blue and g(x) in red.

The lines intercept at one point (-3, -4).

This means that f(-3) = -4 and g(-3) = -4, therefore:

f(-3) = g(-3)

about how many times greater is the distance from the sun to proxima centuries compared to the distance from sun to mercury? express your answer in scientific notation,using a whole number time a power of 101.4 x 10 x ^60.7 x 10 x ^66.9 x 10^56.9 x 10^7

Answers

Since we have that the distance from the Sun to Mercury is 3.6*10^7 and the distance from the sun to Proxima Centauri is 5.9*10^12, we proceed as follows:

[tex]f=\frac{5.9\cdot10^{12}}{3.6\cdot10^7}\Rightarrow f=\frac{1475000}{9}\Rightarrow f\approx163888.9[/tex]

From this, we have that the distance from the Sun to Proxima Centauri is about 163889 times greater than that from the Sun to Mercury.

The surface area (SA) of a rectangular prism can be determined by using the formula, where l = length, w = width, and h = height.

Answers

Explanation

We must solve for h the following equation:

[tex]SA=2\cdot(l\cdot w+l\cdot h+h\cdot w).[/tex]

(1) We divide both sides by 2:

[tex]l\cdot w+l\cdot h+h\cdot w=\frac{SA}{2}.[/tex]

(2) We pass the term lw on the left side as -lw on the right side:

[tex]l\cdot h+h\cdot w=\frac{SA}{2}-l\cdot w.[/tex]

(3) We take h as a common factor on the left:

[tex]h\cdot(l+w)=\frac{SA}{2}-l\cdot w.[/tex]

(4) Finally, we divide both sides by (l + w):

[tex]h=\frac{\frac{SA}{2}-l\cdot w}{l+w}=\frac{SA}{2(l+w)}-\frac{lw}{l+w}.[/tex]Answer[tex]h=\frac{SA}{2(l+w)}-\frac{lw}{l+w}[/tex]

what is the volume in cubic inches of the candle

Answers

[tex]V\approx21in^{3}[/tex]

1) The volume of a cylinder is given by a formula. This one down here:

[tex]V=\pi\cdot r^2\cdot h[/tex]

2) Note that the Diameter is twice the radius, therefore it is safe to say that the radius is 1.5"

3) So we can plug these data into the formula this way:

[tex]\begin{gathered} V=\pi\cdot(1.5)^2\cdot3 \\ V=\pi\cdot2.25\cdot3 \\ V=3.14\cdot2.25\cdot3 \\ V=21.2057\ldots \\ V\approx21in^{3} \end{gathered}[/tex]

Graph the reflection of rectangle PQRS under a reflection across the given line.

Answers

The line graphed is the line:

[tex]y=x[/tex]

A reflection over this line is a special case where each pre-image point (x,y) is transformed as follows:

[tex](x,y)=(y,x)[/tex]

So, first, le's identify each vertex:

[tex]\begin{gathered} P\colon(-2,5) \\ Q\colon(1,2) \\ R\colon(-3,-2) \\ S\colon(-6,1) \end{gathered}[/tex]

Now, we apply the transformation on each.

[tex]\begin{gathered} (x,y)\to(y,x) \\ P\colon(-2,5)\to(5,-2) \\ Q\colon(1,2)\to(2,1) \\ R\colon(-3,-2)\to(-2,-3) \\ S\colon(-6,1)\to(1,-6) \end{gathered}[/tex]

Now, we plot these image points:

Use the Factor Theorem to find all real zeros for the given polynomial function. One of the factor is given. f(x) = 3x^3 + x^2 - 20x + 12; x+3; yes, the binomial is a factor of the polynomial. ; yes, the binomial is a factor of the polynomial. ; the binomial is not a factor of the polynomial. ; the binomial is not a factor of the polynomial.

Answers

[tex]f(x)=3x^3+x^2-20x+12[/tex]

To determine whether (x + 3) is a factor, let's equate it to zero and solve for x.

[tex]\begin{gathered} x+3=0 \\ x+3-3=0-3 \\ x=-3 \end{gathered}[/tex]

So, let's assume that x = -3. If f(x) = 0 at x = - 3, then (x + 3) is a factor of the polynomial. Let's check.

Replace "x" in the polynomial by -3.

[tex]f(-3)=3(-3)^3+(-3)^2-20(-3)+12[/tex]

Then, simplify.

[tex]f(-3)=-81+9+60+12[/tex][tex]f(-3)=0[/tex]

Since f(x) = 0 when x = -3, then yes, (x + 3) is a factor of the polynomial.

Answer:

f(-3) = 0; yes, the binomial (x + 3) is a factor of the polynomial. (Option 2)

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