A 570 kg elevator accelerates downwards at 1.5 m/s2 for the first 13 m of its motion.
Part A
How much work is done during this part of its motion by the cable that lowering the elevator? Neglect any friction or air resistance.

Answers

Answer 1
Mass of the elevator (m) = 570 KgAcceleration = 1.5 m/s^2Distance (s) = 13 mLet the force be F.We know, F = ma,Therefore, F = (570 × 1.5) N = 855 NAngle between distance and force (θ) = 0°We know, work done = F s Cos θTherefore, work done by the cable during this part = (855 × 13 × Cos 0°) J= (855 × 13 × 1) J= 11115 J

Answer:

11115 J

Hope you could get an idea from here.

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Related Questions

Why is kinetic energy lost in an inelastic collision?

Answers

Answer:

This is because some kinetic energy had been transferred to something else.

Explanation:

An inelastic collision is a collision in which there is a loss of kinetic energy. While momentum of the system is conserved in an inelastic collision, kinetic energy is not.

What is the monthly cost of using a 750 W refrigerator that runs for 8 hours every day, if the cost per kWh is $0.23?

Answers

Answer:

Assuming there are 28 days in each month,

750W = 0.75kW

Cost of electric bill = 0.75 × 8 × 28 × $0.23

                               = $38.64

What is the weight of sugar if 5% of sugar from 6g of sugar

Answers

5/100= 0.05 (I convert the percentage to decimal to determine the weight of sugar)

0.05x6 = 0.3 g

can someone explain why is the answer 3.1?​

Answers

i dont know  Im sorry but why Im messaging is because when more people respond it usually is the first to pop up so someone else will see this and be able to help you            Explanation:

Can someone please help me with number 10

Answers

Answer:

A

Explanation:

increase

Answer:

B???

Explanation:

The rate of it going up is lower than L

It might be D too.

Which statement about diffraction is correct?
O The amplitudes of two waves combine to appear as one big wave.
O Sound waves bend around the corners of various obstacles.
O The amplitudes of two waves combine to appear as a wave smaller than the individual waves.
O Sound waves can only travel in straight lines.

Answers

Answer:

Sound waves bend around the corners of various obstacles.

Explanation:

I took the test

Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. The mass of the eight ball, m2, is 6 g with a velocity of 1 m/s. After the balls collide, they bounce off each other. The number three ball moves off with a velocity of 5 m/s. What is the final velocity and direction of the eight ball? 8. 6 m/s 5. 7 m/s â€"5. 7 m/s â€"8. 6 m/s.

Answers

This question involves the concepts of the law of conservation of momentum and velocity.

The velocity of the eight ball is "5.7 m/s".

According to the law of conservation of momentum:

[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2[/tex]

where,

m₁ = mass of number three ball = 5 g

m₂ = mass of the eight ball = 6 g

u₁ = velocity of the number three ball = 3 m/s

u₂ = velocity of the eight ball = - 1 m/s (negative sign due to opposite direction)

v₁ = final velocity of the three number ball = - 5 m/s

v₂ = final velocity of the eight ball = ?

Therefore,

(5 g)(3 m/s) + (6 g)(- 1 m/s) = (5 g)(- 5 m/s) + (6 g)(v₂)

[tex]v_2=\frac{34\ g.m/s}{6\ g}\\\\[/tex]

v₂ = 5.7 m/s

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how is one kg mass defined in SI system​

Answers

Answer:

It is originally defined as the mass of one liter (10-3 cubic meter) of pure water.

The kilogram, symbol kg, is the SI unit of mass. It is defined by taking the fixed numerical value of the Planck constant h to be 6.626 070 15 × 10-34 when expressed in the unit J s, which is equal to kg m2 s -1 , where the meter and the second are defined in terms of c and ∆νCs.

Pravat exerts a force of 30 N to lift a bag of groceries 0. 5 m. How much work did Pravat do on the bag? Note : Work = Force x Distance 0 J 15 J 30 J 60 J.

Answers

Answer:

15 J

Explanation:

The work done by an object can be found by using the formula

workdone = force × distance

From the question we have

workdone = 30 × 0.5 = 15

We have the final answer as

15 J

Hope this helps you

The amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.

WORK DONE:

The work done by a body can be calculated by multiplying the force exerted by the distance moved. That is;

Work done = force (F) × distance (m)

According to this question, Pravat exerts a force of 30N to lift a bag of groceries 0.5 m. The work done is calculated as follows:

Work done = 30N × 0.5m

Work done = 15J

Therefore, the amount of work done by Pravat if he exerts a force of 30 N to lift a bag of groceries 0.5m is 15J.

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Porque la densidad de un solido es alta?

Answers

[tex] \large \sf{hola \: amigo ♡ }[/tex]

Porque, las partículas en los sólidos están muy juntas. Están empaquetados herméticamente, dando a los sólidos altas densidades.

espero que ayude ♡♡

Which of the balls will exert the smallest force on object A?Why

Answers

The 1kg ball would exert the smallest force.

As force = mass x gravity, this means that the smaller the mass (kg), the lesser the force.

When the mass is lighter (1kg):

Force = mass x gravity
Force = 1 x 9.8
Force = 9.8N

Compared to when the mass is heavier (10kg)

Force = mass x gravity
Force = 10 x 9.8
Force = 98N

Where this proves that the lighter the mass, the smaller the force exerted.

Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms as levers. Which statement describes this as a class three lever?





Question 13 options:

The wood in your hands was the fulcrum, the load your elbow, and the effort (input force) was supplied by your arm muscles.


The wood was the load in your hands, the fulcrum was your elbow and the effort (input force was supplied by your arm muscles.


The fulcrum was the muscles in your arms, the load was the wood in your hands and the effort (input force) was the elbow.

Answers

Answer: The correct answer is the weight of the wood.

Explanation:

Hope this helps

A box slides across a rough surface, eventually coming to rest.
Part A
a. Use the work-energy principle (Khan Academy:Work and the work-Energy Principle and the definition of work to explain why the box comes to rest.

b. Explain how the motion of the box is consistent with the Law of Conservation of Energy.

Answers

Answer:

he was a random act like you to be the first time I see is a great day and night to get a very happy to see you soon I hope that the world is not the same thing to say about this

a) When a box slides across a rough surface, eventually coming to rest, its kinetic energy is used during work done against frictional resistance force.

b) This work done is stored in the box as a potential energy. Thus the motion of the box is consistent with the Law of Conservation of Energy.

What is  work-Energy Principle?

According to the work-energy theorem, the work done by the net force acting on a body equals the change in kinetic energy.

It can simply be written as:

Work done = initial kinetic energy - final kinetic energy

The work energy theorem equation is the one presented above.

Now when a box slides across a rough surface, eventually coming to rest, frictional force comes into play. This force is opposite to the direction of motion of the box. Hence, the kinetic energy of the box is used during work done against frictional resistance force and stored in the box as a potential energy and thus  Law of Conservation of Energy followed.

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A dog is pulling an empty sled attached by a harness that is parallel to the
ground in the snow. The sled is moving with constant velocity. The mass of
the sled is 1.2 kg, and the coefficient of static friction is 0.20. Determine the
harness tension.

Answers

Answer:

Explanation:

There are only two forces causing motion involved. They oppose each other. You know this because there is no acceleration of the sled: you see only a velocity.

The formula when friction is involved is

Fnet = T - mu*Normal

mu is the frictional coefficient

The normal is the downward force caused by the mass of the sled being pulled down by the gravitational constant.

The tension is brought about by the dog pulling in the opposite direction to the frictional force.

The frictional force, oddly, acts in a horizontal direction even though the normal is vertical. It does this because friction always opposes motion.

Since there is no acceleration, the net force = 0

N= m * a_g

m = 1.2 kg

a_g = 9.8

N = 1.2 * 9.8

N = 11.76

The frictional force = mu*Normal Force.

Ff = N * mu

N = 11.76

mu = 0.2

Ff = 0.2 * 11.76

Ff = 2.35

As stated The frictional force and the Tension are equal but in opposite directions

T = 2.35

Someone plz give me some boy advice I really need it.

Answers

If your wanting to know how to talk to them, just act like you know them really well be very causal and be confident in what you say, they also like it when you make the first move to talk to them

What is the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s2? ____________________

Answers

The final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

EQUATION OF MOTION:

The final velocity of a moving object can be calculated by using one of the equations of motion as follows:

V = u + at

Where;

V = final velocity (m/s)u = initial velocity (m/s)a = acceleration (m/s²)t = time (s)

According to this question,

t = 5sa = 4.3m/s²u = 0 m/s (at rest)v = ?

v = 0 + 4.3(5)

v = 21.5m/s.

Therefore, the final velocity of an object that starts from rest and travels for 5 seconds at an acceleration of 4.3 m/s² is 21.5m/s.

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A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head on collision with a 14.0 kg raft moving to the right at 16.0 m/s after the collision the raft moves to the left at 14.4 m/s assuming water simulates a frictionless surface, what is the final velocity of the canoe?

Answers

A 16.0 kg canoe moving to the left at 12.5 m/s makes an elastic head on collision with a 14.0 kg raft moving to the right at 16.0 m/s. After the collision the raft moves to the left at 14.4 m/s assuming water simulates a frictionless surface. Mass of the canoe (m1) = 16 KgMass of the raft (m2) = 14 KgInitial velocity of the canoe (u1) = 12.5 m/sInitial velocity of the raft (u1) = - 16 m/s [Here, the raft's velocity is negative, because the objects are moving in the opposite direction]Total momentum of the system = m1u1 + m2u2 = [(16 × 12.5) + (14 × -16)] Kg m/s = (200 - 224) Kg m/s = -24 Kg m/sFinal velocity of the raft (v2) = 14.4 m/sLet the final velocity of the canoe be v1.Total momentum of the system after the impact = m1v1 + m2v2 = [(16 × v1) + (14 × 14.4)] Kg m/s = 16v1 Kg + 201.6 Kg m/sAccording to the law of conservation of momentum, Total momentum of the system before the impact = Total momentum of the system after the impactor, -24 Kg m/s = 16v1 Kg + 201.6 Kg m/sor, -24 Kg m/s - 201.6 Kg m/s = 16v1 Kgor, -225.6 Kg m/s = 16v1 Kgor, v1 = -225.6 Kg m/s ÷ 16 Kgor, v1 = -14.1 m/s

Answer:

The final velocity of the canoe is -14.1 m/s or 14.1 m/s to the right.

Hope you could get an idea from here.

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( the answer only for points will be reported ) A crane lifts a load of 36000N to a height of 50 metre in 1 minute . What is the power of the crane ?​

Answers

Answer:

- 30 kW

Explanation:

IDEA:

Power of an object that does work(source) is given by:

[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]

where work done is mostly shown as the Force applied on an object to Displace it through some distance in the same direction as the Force.

[tex] \boxed{ \mathsf{ work = force \times displacement}}[/tex]

___________________

INFORMATION:

In the question,

The source of power is the crane, while the object is a load of 36000N.

Note, what's given is the force, not the mass. Since, the SI unit of mass is kg and that of Force is Newton(N).

[The weight of the load is represented in Newton, since weight of an object is the amount of Force with which the Earth attracts that object]

I) work done

So,

Force = 36000NDisplacement = 50 m

=> Work = 36000 × 50

= 1,800,000 J

(The SI unit of work is Joules(J)).

___________________

II) power

After getting the amount of work done, now we have to place it in the formula for power.

That is:

[tex] \boxed{ \mathsf{power = \frac{work \: done}{time} }}[/tex]

Note, During calculations, all quantities must be in their SI units.

SI unit for time is Seconds (s)

But the time we have is in minutes.

___________________

Converting time from minutes to Seconds:

1 minute = 60 Seconds.

Hence,

time = 60 s

[tex] \implies \mathsf{power = \frac{1800000}{60} } \: [/tex]

=> power = 30,000 W

(SI unit of power is Watts(W))

To write four zeroes with a 3 and W is a lot of effort. So, we can look for simple expressions like kilowatts(kW) that can express bigger quantities in lesser terms.

1000 W = 1 kW

•°• 30,000 W = 30 kW.

___________________

Direction and sign:

The crane displaces the load in an upward direction (from the term "lifts")

But, the Force is acting downwards, as the weight of the body is always towards the Earth.

Since, the directions of Force and displacement are opposite, a minus takes its place in front of both Work and power.

___________________

Therefore, the final answer will be:

Power of the crane = - 30 kW

Rafiq has heard that continued exposure to light for 10 days can change the colour of some blue dyes used to colour cotton clothing. He decides to test this. He takes a piece of clothing dyed with a blue dye which is suspected to lose colour on such exposure. He cuts the cloth into two pieces.
Which experiment is likely to help him conclude if the dye indeed can change colour?
He should expose, for 10 days-

A. Both pieces under 2 identical lamps.
B. One piece under a lamp; keep the other in darkness.
C. One piece for 5 days and one for 10 days under identical lamps
D. One piece folded and one piece spread out under 2 identical lamps.

Answers

I think the answer is B

Starting from rest an object accelerates on a straight line at rate of 2ms‐² for 10 seconds. what is the speed of the object at the end of the 10 seconds ​

Answers

Answer:

20 meters/sec

Explanation:

See attachment.

2m/s^2 = (v - 0)/10s

v = 20 m/s

A 5.00 kg crate is on a 21.0 degree hill. Using X-Y axes tilted down the plane, what are the X AND Y components of the NORMAL FORCE?

Answers

Answer:

y-component = 45.75N

x-component = 0N

Explanation:

A balance of forces is demonstrated by an object which is slowing to a stop true or false

Answers

Answer:

its true since i already did this last year, if i am wrong i apologize

Explanation:

A rocket burns fuel at a rate of 239 kg/s
and exhausts the gas at a relative speed of
6 km/s.
Find the thrust of the rocket.
Answer in units of MN.

Answers

The Thrust on the rocket is 1.434 MN.

To calculate the thrust of a rocket, we use the formula below

Thrust: This is the force that moves an aircraft through the air.

⇒Formula

T = M'×v.................... Equation 1

⇒ Where:

T = Thrust of the rocketM' = Fuel ejection ratev = gas exhaust velocity

From the question,

⇒ Given:

M' = 239 kg/sv = 60 km/s = 6000 m/s

⇒ Substitute these values into equation 1

T = 239(6000)T = 1434000 NT = 1.434 MN

Hence, the Thrust on the rocket is 1.434 MN.

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A pitcher throws a softball toward home plate. When the ball hits the catcher’s mitt, its horizontal velocity is 32 meters/second. The softball’s velocity goes to 0 meters/second in 0. 8 seconds when caught. If the softball has a mass of 0. 2 kilograms, what’s the force of the impact? Use F = ma, where. The force of the impact is newtons.

Answers

The force of impact of the softball at the given conditions is 8 N.

The given parameters:

Horizontal velocity of the ball, v = 32 m/sChange in time of motion of the ball, Δt = 0.8 sMass of the ball, m = 0.2 kg

The force of impact of the softball is calculated by applying Newton's second law of motion as follows;

[tex]F = ma\\\\F = m \times \frac{\Delta v}{\Delta t} \\\\F = 0.2 \times \frac{32 - 0}{0.8 - 0} \\\\F = \frac{0.2 \times 32}{0.8} \\\\F = 8 \ N[/tex]

Thus, the force of impact of the softball at the given conditions is 8 N.

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e. Observe: notice or perceive

f. Infer:
g. Repetition:
h. Replication:
i. Data

Answers

The synonym of a word( observe, infer, repetition, replication and data) means another word that is nearest in meaning to the given word.

The synonym of the words given from the question is given below:

Observe: This means to notice or perceive something. Therefore the synonym is notice or perceive.

Infer: This means to conclude something based on evidence and not from explicit statements. Therefore the synonym is deduce or conclude.

Repetition: This means doing or saying something again. Therefore the synonym is recurrence.

Replication: This means the process of reproduction. Therefore the synonym is duplicate.

Data: This means information that is used to make decisions. The synonym is facts.

Therefore, synonym of a word means another word that is nearest in meaning to the given word.

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When an object is balanced about a pivot, the total clockwise moment must be equal to the total __________ __________. What two words complete this sentence?

Answers

Answer:

When an object is balanced, about a pivot, the total clockwise moment must be equal to the total anticlockwise moment about that pivot.

Hope that helps.

When an object is balanced about a pivot, the total clockwise moment must be equal to the total anticlockwise moment.

What is balancing?

Clockwise involves turning to the right while going in the direction of a clock's hands. The moment is referred to as a clockwise moment if the force acting on a body rotates the body clockwise with regard to the axis of rotation.

On the other hand, the moment is referred to as an anti-clockwise moment if the force rotates the body in the opposite direction. The clock face rule can be used to determine this magnet's polarity.

The face of the loop will display the North Pole if the current is flowing counterclockwise. On the other hand, if the current is moving counterclockwise, the South Pole is visible on the loop's face.

Therefore, the total clockwise and total counterclockwise moments must match when an object is balanced about a pivot.

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Why does gravity on Earth have a stronger attraction with you than the sun has with you? Plsssssss help I really need this rn

Answers

Answer:

Although the Earth has a lesser mass than the Sun, it is far closer to you, allowing for a stronger pull.

Explanation:

A car accelerates from 10m/s to 22m/s in 10 seconds. What is the car’s acceleration?

A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s.

Explain please.

Answers

Answer:

See attachment and below

Explanation:

A car accelerates from 10m/s to 22m/s in 10 seconds.

a = (22m/s - 10m/s)/10sec

a = 12m/s/10s

a = 1.2 m/s^2

A skydiver falls from an airplane and achieves a speed of 98m/s after 10 seconds. the starting speed is 0m/s

a = 98m/s - 0m/s)/10sec

a = 9.8 m/s^2

9.8 meters/sec^2 is the acceleration due to gravity.

I don't understand when to use the formule with the constant k, and when to use the formula without it.

In the exercise that i sent here, they use the formule with a constant but I don't get why.

Can someone help me out please?
Thanks.

Answers

Answer:

This appears to be the formula for the electrical force between 2 objects.

You need this constant to calculate the electrical force between 2 charged objects.

Note that k = (1 / 4 * π ∈0)

∈0 is called the permittivity constant and ∈0 = 8.85E-12 farad/m

k = ( 1 / (4 * 3.28 * 8.85E-12) = 8.99E9

This makes F reasonably easy to remember as

F = 9E9 Q1 * Q2 / R^2 Newtons for the electrical force between Q! and Q2 separated by R

a water balloon is thrown a target at 18 m/s. if the water balloon has a mass of 0.4 kg, what is the momentum?

Answers

The momentum of the water balloon at the given speed is 7.2 kgm/s.

The given parameters:

Speed of the water balloon, v = 18 m/sMass of the balloon, m = 0.4 kg

The momentum of the water balloon is calculated as follows;

P = mv

Substitute the given values of mass and velocity as follows;

P = 0.4 x 18

P = 7.2 kg m/s.

Thus, the momentum of the water balloon at the given speed is 7.2 kgm/s.

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