(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
It is the amount of change in velocity per unit time. The velocity change can be calculated using the formula: velocity change = final velocity - initial velocity. This is the time when: The rate of change in velocity is expressed in
Given
A ball is thrown from a 10 m high cliff at the velocity 20 ms-¹ with an angle of 30° to the horizontal plane as shown in the picture below. 40 m from the edge of the cliff is a 10 m high wall.
We have to determine
a) Will the ball pass over the wall?
b) If not, where will it hit the wall and with what velocity?
From the given information
Initial velocity v =20m/s
Initial velocity along x direction vx = vcos300
= 20 cos300
= 20 x 0.866
= 17.32m/s
Initial velocity along y direction vy = v sin300
= 20 sin300
= 20 x 0.5
= 10m/s
Displacement along +ve x = 40m
Time required to travel t = x/vx
= 40/17.32
= 2.31seconds
At this time displacement of the ball along the y direction
Sy = vyt – 1/2gdt2
= 10x2.31 – ½ x 9.81 x (2.31)2
= 23.10 – 26.17
= - 3.07m
Since displacement is in a negative value, it will hit the wall and will not pass over the wall
The ball will hit at d distance from the ground
H = (10 – 3.07)
= 6.93m
Final velocity along +ve y = v’y = vy –gt
= 10 – 9.81 x 2.31
= 10 – 22.66
=-12.66m/s
velocity along +ve x = v’y = vx
= 17.32m/s
So-net velocity of the ball v’= √((v^' x)^2+(v^' y)^2 )
= √(〖(17.32)〗^2+〖(-12.66)〗^2 )
= 21.45m/s
Therefore
(a) The ball will not pass over the wall
(b) The velocity is 21.45m/s
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explain how the energy/velocity of water/wind controls the size of the particles in clastic/detrital) rocks
In fast-moving water only coarse material settles out and fine material is carried away. In slow-moving water only fine material, which can settle out.
What is the velocity of water?The velocity of water is the rate at which water moves.A technique that can quickly clear your drains is high-velocity water jetting. This procedure forces water through your pipes at a very high velocity, which aids in dissolving and removing any material that has built up in your drains.The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s), over change in time (t).The volume and speed of the water affect the flow. It is significant because of how it affects the stream's ecosystems, living things, and water quality. Large, fast-moving rivers can be exposed to pollution releases and experience minimal effectsTo learn more about velocity of water refer to:
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a moth at about eye level is 16.4 cm in front of a plane mirror; you are behind the moth, 48.8 cm from the mirror. what is the distance between your eyes and the apparent position of the moth's image in the mirror?
The distance between the moth and its image in the mirror is equal to the distance between the moth and your eyes, which is equal to 43.7 centimeters.
The distance from the moth to its image is 16.4 cm, which is equal to 48.8 cm, because it's a plane mirror. So, if you want to know how far away from you the moth looks like it is, just subtract 48.8 cm (the distance between your eyes) from 16.4 cm (the distance between you and the moth).
The angle between these two objects is 48 degrees,
so S = 1/2 2 sin(48)
= 0.958 meters.
Moth + Mirror (dist1) + Me (dist2) = 48 * 0.958 = 43.7 centimeters
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A kangaroo moves with a constant speed of 90 km/h for 20 m on a straight road. Calculate the distance traveled in this period of time
We first apply the data to the problem.
Data:
V = 90km/hT = 20minD = ?Now, we convert the minutes to hours.
Conversion:
T = 20 min • (1 hr / 60 min)T = 1/3 hrThen, we apply the formula that is.
Formula:
D = V • TFinally we develop the problem.
Developing:
D = (90km/h) • (1/3h)D = 30kmThe distance traveled by the kangaroo is 30 kilometers.
A mass on a spring undergoes shm. When the mass is at its maximum displacement from equilibrium, its instantaneous velocity?.
When the spring undergoes simple harmonic motion and its mass is at maximum displacement then its instantaneous velocity is zero.
Simple Harmonic Motion:
Simple harmonic motion is a periodic motion in which the acceleration of the object undergoing the simple harmonic motion is directly proportional to the distance of the object from its equilibrium position and is always directed toward the mean position.
At the maximum displacement, the spring is under its greatest tension, which forces the mass upward. At the maximum displacement, the spring reaches its greatest compression, which forces the mass back downward again.
Therefore we get that when mass is at its maximum displacement from equilibrium its instantaneous velocity is zero.
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lorry is moving with a uniform acceleration of 1.5ms2 .at a certain time it is travelling at a spedd of 6ms .calculate the speed of the lorry 4s later
The speed of the lorry 4 seconds later, given it was moving with uniform acceleration of 1.5 m/s² is 12 m/s
How do I determine the final speed of the lorry?We'll begin by listing out the various parameters obtained from the question. This is shown below:
Acceleration (a) = 1.5 m/s²Initial speed (u) = 6 m/sTime (t) = 4 secondsFinal speed (v) =?The final speed of the lorry can be obtained as follow:
a = (v - u) / t
1.5 = (v - 6) / 4
Cross multiply
v - 6 = 1.5 × 4
v - 6 = 6
Collect like terms
v = 6 + 6
v = 12 m/s
Thus, from the calculation made above, the final speed of the lorry is 12 m/s
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HELP! will mark brainliest
State your hypothesis. Make sure your hypothesis is worded as an if, then statement and relates the independent variable of wrong length to the dependent variable of wave frequency.
If I increases the string length, the frequency will decreases and vise versa.
What is frequency?In physics, frequency is the number of waves that pass a fixed point in a unit of time as well as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time.
For string wave, we know that,
frequency, n = [tex]\frac{1}{lD}[/tex][tex]\sqrt{\frac{T}{\pi \rho} }[/tex]
where, l = length of the string.
D = diameter.
T = tension
ρ = density of the material.
Hence, we can see that, frequency of the wave is inversely proportional to the length of the wire. So, on increasing string length, frequency of the wave will decreases.
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What was the force of gravity on the ball when it was at the highest point in its flight?
2. There is a bell at the top of a tower that is 45m high. The bell weighs 190N.
The bell has
energy. Calculate it:
Answer:
4,275
Explanation:
formula:1/2mv square
1/2×190×45=4,275
If two tractors are pulling against each other at a tractor pull and the first tractor exerts 500N of force to the East and the second tractor exerts 350N of force to the west and the combined weight of the tractor is 800 kg, what is the acceleration of both tractors? In what direction?
Answer:
Explanation:
Given:
F₁ =500 N
F₂ = 350 N
m₁ = m₂ = m = 800 kg
__________
R - ?
a - ?
Resultant force:
R = 500 - 350 = 150 N
System acceleration:
a = R / (m₁ + m₂) = R / (2·m)
a = 150 / (800 + 800) = 0.094 m/s²
Direction R and a - East
a car moving at 30 m/s backwards it completes this motion is 6/s. what is the acceleration of this car
The acceleration of this car is 5 m/s².
Acceleration is the rate of change of the velocity of an item with appreciation to time. Accelerations are vector portions. The orientation of an item's acceleration is given by the orientation of the net pressure appearing on that object.
Calculation:-
initial velocity = 0 from rest
final velocity = 30 m/s
time = 6 sec
acceleration = rate of change of velocity
= 0 - (-30) /6
= 5 m/s²
Acceleration is the charge at which velocity modifications with time, in terms of each speed and route. A factor or an object moving in a straight line is accelerated if it quickens or slows down. movement on a circle is extended despite the fact that the rate is consistent because the course is continually changing.
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9. if suddenly, the sun were to quantum tunnel to a different dimension and stop applying a force on the planets, in what kind of path would the planets move? explain.
The planets move on linear motion without acceleration. Motion in one spatial dimension is described as linear motion, often known as uniform motion or rectilinear motion.
Explain about the Linear motion?Moving in a straight line is the motion that an object naturally exhibits. A forceless item will move in a straight line indefinitely, according to Newton's First Law of Motion.
An object is said to be moving linearly when it has a tendency to move in a straight line. Rectilinear motion is another name for linear motion. Many of the things we do every day, like walking, bowling, playing on a slide, etc., exhibit linear motion in reality.
Both the ultimate displacement and the velocity are positive, indicating that they are moving in the same direction. The link between displacement, average velocity, and time is described by the equation x = x0+(average v)t.
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a baseball and a bowling ball with the same momentum are rolling toward you. which one needs more efforts (either longer time or larger force) to be stopped?
The baseball will require longer time and the bowling ball will require more effort to be stopped.
The bowling ball and baseball is moving with same momentum.
Let us say the momentum of the bowling ball is MV and the momentum of the baseball is mv.
According to second law of newton,
F = ΔMV/Δt
F = MΔv/Δt
So, the force is directly proportional to the speed of the object.
The speed of the bowling ball will be less than that of the baseball because the mass of the bowling ball is more and the mass of the baseball is less.
So, a greater force will be required to stop the baseball ball,
F = mΔv/Δt
v is more and the contact period Δt of the transfer of momentum is less so baseball will require longer time and a grater force will be required to stop the bowling ball because the speed is less.
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3. The average human walks at a speed of 5 km per hour. If your PE teacher asks you to
walk for
40 minutes in
gym class, how far would you walk (km)?
The average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
What is Average speed?
The average speed is the displacement of a particle divided into a time in which the displacement occurs. Instead, instantaneous speed is the limit of the average speed as the time interval approaches zero.
Usually,
Speed = Distance/ Time
Assuming you also walk with the average human walking speed of 5 km/h. We know the above formula of speed and now making distance the subject, distance is a product of speed and time.
Here, time is 40 minutes and if expressed in hours can be converted as,
40/60 = 0.6 hours.
Distance = 5 × 0.6
= 3 km
Thus,the average human walks at a speed of 5 km per hour. If your PE teacher asks you to walk for 40 minutes in gym class, you would walk for 3 Km.
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A light, inextensible cord passes over a light,
frictionless pulley with a radius of 14 cm. It
has a(n) 14 kg mass on the left and a(n)
8.6 kg mass on the right, both hanging freely.
Initially their center of masses are a vertical
distance 1.9 m apart.
The acceleration of gravity is 9.8 m/s².
A light, inextensible cord passes over a light, frictionless pulley with a radius of 8.9 cm. It has a 19 kg mass on the left and a 2.6 kg mass on the right, both hanging freely. The rate at which the two masses are accelerating when they pass each other is 7.44 m/s². The tension in the cord is 44.84 N.
What is tension of wire ?
In physics, tension is the force exerted on one or more bodies by ropes, cords, cables, or similar bodies. Anything that is pulled, hung, supported, or swung by a rope, cord, cable, etc., is subject to tension. Like all forces, stress can accelerate or deform objects.
Using Newton's Law to the mass m₁
m₁ g - T = m₁ a
where;
the tension T = m₁ (g -a) ----- Let this be equation (1)
For mass m₂,
T - m₂ g = m₂ a ------- Let this be equation (2)
equation both equation (1) and (2) together;
By rearrangement and collecting like terms;
a(m₂ + m₁) = g(m₁ - m₂)
Making acceleration (a) the subject of the formula:
a = 7.44 m/s²
According to equation (1), the cord's tension is:
Tension (T) = m1 (g -a)
T = 19(9.8 - 7.44) (9.8 - 7.44)
T = 19(2.36) (2.36)
T = 44.84 N
From this we can conclude that the speed at which the two masses accelerate as they pass each other is 7.44 m/s² and the tension in the cord as they pass is 44.84 N.
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a 650-n billboard worker stands on a 4.00-m scaffold weighing 600 n and supported by vertical ropes at each end. how far would the worker stand from one of the supporting ropes to produce a tension of 660 n in that rope?
Answer:
1.785 m
Explanation:
Without the worker the scaffolding produces 300N tension in each rope
if worker is in the middle, each rope will support 1/2 of worker's weight (325 N) for a total of 625 N <==== so worker will be pretty close to middle for tension of 660 N
Need 360 N in addition to 300N board
360 * x = 290 ( 4-x)
x = 1.785 meters from an end
Well ....that is kinda the 'intuitive approach'.....maybe this way will be more clear:
The moments around one end have to be = 0 or the plank will move
from the left end moments:
600 ( 2.000) + 650 ( x) = 660 (4.000)
x = 2.215 m from left end or 1.785 m from R end (that has the 660 N tension)
Calculate the average speed of a complete round trip in which the outgoing 300 km is covered at 97 km/h , followed by a 1.0- h lunch break, and the return 300 km is covered at 55 km/h .
The average speed of the complete round trip is 62.85 km/h.
The average speed is nothing but the total distance travelled per unit time.
or in other words,
Average speed = [tex]\frac{Total distance travelled}{total time taken}[/tex]
Now, Total distance travelled = 300km + 300 km = 600 km
and the time taken = t1 + t2 + t3
t1 = distance/speed
t1 = 300km/(97km/h)
t1 = 300/97 Hour = 3.0927 Hour
t2 = 1 Hour
and t3 = distance/speed
t3 = 300km/(55km/h)
t3 = 300/55 Hour = 5.4545 Hour
Total time = t1+t2+t3
T = 3.0927+1+5.4545 = 9.547 Hour
So, average speed = total distance / total time
Average speed = 600km/9.547 Hour
Average speed = 62.85 km/h
Hence the average speed is 62.85 km/h.
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what two basic measurements are taken to test insulation resistance? i. the actual leakage current flowing through the insulation. ii. the actual leakage current flowing through the conductor. iii. the actual resistance of the insulation. iv. the actual resistance of the conductor.
The insulation tester, often known as a Megger, is a device used to assess insulation resistance. For measuring insulating resistance, we utilise the following devices.
What is insulation resistance?
The insulation resistance of wires, cables, and electrical equipment is measured in ohms. It is critical to protect against electric shocks and to avoid equipment damage caused by inadvertent discharges. The insulating resistance is measured by testing and evaluating the status of the isolation (head and body.)
Direct indicating ohm metre with hand-operated DC generator
With direct indicating ohm metre and motor-driven DC generator
Direct indicating ohm metre with DC battery
Direct indicating ohm metre with a full-wave rectifier
Resistance bridge circuit with galvanometer and battery
The insulating resistance is measured using direct current voltage. We can create the DC voltage using a hand-driven dc generator or a motorised dc generator. Insulation functions as a capacitor. If the insulation quality is excellent, the capacitor will block the DC. Leakage current flowing through insulation shows inadequate insulation quality.
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three particles lie in the x-y plane: a 100 gram particle lies at point (1,1), a 200 gram particle lies at point (-2,0), and a 300 gram particle lies at point (0,3). all distances are measured in meters. what is the moment of inertia for this system rotating in the x-y plane around the origin?
The system rotating in the x-y plane about the origin has a moment of inertia of 3.6 kg/m2.
What is Moment of inertia?A body's resistance to having the speed of its rotation along an axis changed by the application of a torque is known as its rotational inertia, and this property may be measured quantitatively (turning force). The axis could be internal or exterior, fixed or not.I = mi * ri2 = m1 * r12 + m2 * r22 + m3 * r32 = 100*12 + 200*22 + 300*32 = 100+800 + 2700 = 3.6Kg-m2The Moment of Inertia for a point mass is defined as the mass times the square of the angle from the rotational reference axis. I=mr2. A kilogram is one kilogram, and a metre is one metre.In physics, a moment can be described as the turning that forces have on objects.To learn more about Moment of inertia refer to:
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the vertical deflecting plates of a typical classroom oscilloscope are a pair of parallel square metal plates carrying equal but opposite charges. the potential difference between the plates is 25.0 v. typical dimensions are about 3.9 cm on a side, with a separation of about 5.4 mm. the plates are close enough that we can ignore fringing at the ends. part a under these conditions, how much charge is on each plate?
If we keep oscilloscope plates close with potential difference 25 V , the Charge on each plate will be 4.68 *10^-11 C.
How to calculate charge ?Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge.The number of charges (electrons) that go from a higher potential to a lower potential is referred to as quantity of charge. It refers to the total amount of electricity flowing via a conductor.The capacitance of a parallel plate capacitor is given by:
C = ∈₀A / d
where
∈₀ = 8.85 *10^-12 F/m is the vacuum permittivity
A is the area of each plate
d is their separation
For the capacitor in the problem:
A= 0.033m² = 0.0011m²
d = 5.2 mm = 0.0052 m
Substituting,
C = (8.85 *10^-12) (0.0011m)/ 0.0052 = 1.87 *10^-12 F
The capacity is related to the charge on the plate by:
Q=CV
where
V = 25.0 V is the potential difference between the plates
C = 1.87 *10^-12 F
Substituting,
Q = (25.0) (1.87 *10^-12) = 4.68 *10^-11 C
Charge on each plate = 4.68 *10^-11 C
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AP physics 1: Extra points!!
Tension force, Friction and gravity are acting on acrobat player while hanging in middle. and this is unbalanced force.
Tension is a contact force that is transmitted through a rope, thread, wire, or other similar material when pressures on the opposing ends tug on it. The rope that holds a tire swing to a tree branch is one such example. The rope is pulled upward by a branch tugging against the rope's tug tension, which is only a pulling force; the rope is dragged downward by gravity. Pushing on a slack rope will not cause it to be strained. As a result, the force of tension must always be represented in the direction that the string is pulling the object in a free-body diagram.
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a 58 kg sprinter, starting from rest, runs a 60 m long race in 7.8 s with a constant acceleration. how much work does the sprinter do during the first 2.5 s of the race?
Work done by the sprinter in first 2.5 s will be 702.699 J.
Work done is the product of force and distance covered.
Mathematically, W = Force * DistanceMass of the sprinter = 58 kg
Distance covered by the sprinter = s = 60 m
Total time taken by the sprinter = t = 7.8 s
According to the Equations of motion S = ut + [tex]\frac{1}{2}at^{2}[/tex]u = initial velocity = 0
a = constant acceleration
60 = [tex]\frac{1}{2}a7.8^{2}[/tex]
60.84 a = 60 * 2
a = 1.97 [tex]m/s^{2}[/tex]
For a = 1.97 [tex]m/s^{2}[/tex] and t = 2.5 s
d = [tex]\frac{1}{2}at^{2}[/tex]
Here also u is '0' because the distance is being measured from the starting point.
d = [tex]\frac{1}{2} *1.97*(2.5)^{2}[/tex]
d = 6.15 m
Work done by the sprinter = F * d
Force = mass * acceleration
F = 58 * 1.97
F = 114.26 N
distance for first 2.5 sec is 6.15 m
Therefore Work done = 6.15 * 114.26
W = 702.699 J
Work done by the sprinter is 702.699 J.
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a laser dazzles the audience in a rock concert by emitting red light with a wavelength of 685 nmnm . calculate the frequency of the light.
Wavelength of 685 nmnm and the frequency of the light 0.43765322
What is the frequency of the light ?Light has a wavelength of 685 nm, which can alternatively be written as 685 x 10-9 m. Wavelength: [=]
We are aware that light travels at a speed of 299 792 458 m/s, or around 3 x 108 m/s. [light speed equals c]
We may use the following formula to determine the frequency (f) given the two values:
f = c / ʎ
replacing the specified values:
f = (685 x 10-9 m) / (3 x 108 m / s)
f = 0.43765322
The frequency of the light 0.43765322
The range of the frequency of visible light is roughly 400 to 700 THz. A Terahertz, or THz, is a frequency measurement equal to one trillion Hertz. the range of electromagnetic fields. f = (463 x 10-9 m) / (3 x 108 m / s)to learn more about frequency of the light refer to:
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a wagon wheel is constructed as shown. each of the eight spokes has a mass of 0.280 kg and are 0.3 m long. the outer rim has a mass of 1.4 kg. a small 10-g mass is attached by a string of negligible mass. the 10-g mass is released (from rest), what is the torque on the wheel?
The torque on the wheel is 0.0294 Nm
What is torque?The term "torque" was coined by the ancient Romans. They described these necklaces with the Latin word "Torquere", a twisted helix, a spiral, which means "twist" and "turn".
Torque is a measure of the force that rotates an object around an axis. Torque causes an object to undergo angular acceleration in the same way that force accelerates an object in linear kinematics. Torque is a vector quantity. Newton meter is the unit of torque.
Torque = Force × Perpendicular distance line of action of force and axis
τ = mg × L
τ = 0.01 × 9.8 × 0.3
τ = 0.0294 Nm
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a bus travels with an average velocity of 60km how long does it take to cover a distance of 500km
Solution: given that; velocity (v)=60km/hr, distance (d)=500km, time (t)=? From velocity=distance/time....... :. 60=500/t, cross-multiply..... 60t=500, divide both sides by 60...... 60t/60=500/60, t=500/60, t=8.33~. Therefore the bus took 8hours, 33 minutes to cover the distance of 500km.
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if the ladder is just on the verge of slipping when the firefighter is 9.10 m from the bottom, what is the coefficient of static friction between ladder and ground?
Static friction between the ladder and the ground has a coefficient of
[tex]\mu_{s}[/tex] = 0.303.
A measure of static friction.The maximum static friction force (F) that can exist between two surfaces before movement starts is divided by the normal force (N) to determine the coefficient of static friction.
x₁ = 8
x₂ = a₁
x₃ = x₁ cos θ
x₃ = 8 cos61 = 3.87m
x₄ = x₂cosθ = 9.1cos 61
x₄ = Lsin 60 = 16sin 60
[tex]x_{s}[/tex] = 13.856m
w₁ = mg = 840
w₂ = mg = 490
N₁ = mg + mg = 490+840 =1330N
N₂ = f = [tex]\mu_{s}[/tex]N₁
Torque about point is zero
[tex]\sum[/tex]Z = 0
mgx₃ +mgx₁ = N₂[tex]x_{s}[/tex]
N₂ = 490×387+840×4.41/13856
N₂ = 404.268
[tex]\mu_{s}[/tex] = N₂/N₁ = 404.268/1330 = 0.303
[tex]\mu_{s}[/tex] = 0.303
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A coaxial cable consists of alternating coaxial cylinders of conducting and insulating material. Coaxial cabling is the primary type of cabling used by the cable television industry and is also widely used for computer networks such as Ethernet, on account of its superior ability to transmit large volumes of electrical signal with minimum distortion. Like all other kinds of cables, however, coaxial cables also have some self-inductance that has undesirable effects, such as producing some distortion and heating
Coaxial cable may experience unpleasant interference from electrical wires. Therefore, even if the cables are divided by wood or other building materials, keep coax wires at least 6 inches away from electrical cables.
Explain about the Coaxial cables?A form of copper cable known as coaxial cable is designed to prevent signal interference by using a metal shield and other parts. It is generally utilized by cable TV providers to link their satellite antenna facilities to client residences and establishments.
The same coaxial cable network that delivers cable television and internet to your house is used for both services. First, your internet service provider sends a data signal to your modem via the coaxial cable, also known as coax, inside your home.
You will need a coaxial cable connected to your TV if you want to watch live TV through a provider like Free view or Free sat.
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the y-axis carries a uniform linear charge density of -30 nc/m, and there is a 4.0 nc point charge at the point (4 cm, 0 cm, 0 cm) as well as a -12 nc point charge at the point (6 cm, 0 cm, 0 cm). what is the electric flux through a spherical surface of radius 5 cm centered at the origin?
The sphere's surface has a net flow of 339 103 Nm2/C.
What measures the Gauss law?According to Gauss's rule of electricity, any closed surface's electric flux is inversely proportional to the net electric charge q enclosed by the surface, or q = q/0, where 0 is the electric permittivity of empty space, which has a value of 8.854 10-12 square coulombs per newton per square meter.
Given:
The total charge contained within the sphere's surface, q=-3 C
The sphere's radius is 5 cm (5 10 2 m).
To locate
the total electric flux across the sphere's surface.
Explanation:
The net electric flow through the surface of the sphere is determined by Gauss's law, which is as follows:
, Φ = q/ε0
which has a value of 8.854 10-12 square coulombs per newton per square meter.
where the permittivity of empty space equals 0.
Using the known values as a substitute
The sphere's surface has a net flow of 339 103 Nm2/C.
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a block has accleration a when pulled by a string. if two identical blocks are glued together and pulled with twice the orignal force, their accerleation will be?
you get the same acceleration.
we know that:
F = ma
a = F/m
a = 2F/2m
a = F/m
so if we double the force and the mass, you get the same acceleration.
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an airplane has a mass of 26900 kg and takes off under the influence of a constant net force of 38700 n. what is the net force that acts on the plane's 106 kg pilot?
The net force that acts on the plane's 106 kg pilot is 151.58N.
What is a net force?The net force acting on an object is the result of all pushing and pulling forces acting on the object collectively (the sum). If there is an imbalance in the pushing and pulling forces acting on an object, the object will accelerate in the direction of the net force.
All forces acting on an object are added together to form the "net force." If the object is not moving, then this net force must be equal to zero, according to Newton's First Law.
acceleration a = F/m
a = 38700/ 26900
a = 1.43m/s²
F = ma
F = 106×1.43
F = 151.58N.
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when the displacement of a mass on a spring is 1/2 a , what percentage of the energy is kinetic energy?
The formula for total mechanical energy at maximum displacement (amplitude) is
ME = KE + PE = 0 plus (1/2)
*k*A^2 = (1/2)*k*A^2
Now, mechanical energy is constant during the displacement of a mass on a spring.
Now, when x equals A/2, or when displacement is equal to half of amplitude, then
PE = (1/4)*(1/2)*k*x2 = (1/4)*(1/2)*k*(A/2)*2
PE = (1/4)*ME
PE = ME - (1/4)*ME - KE = ME
KE = (3/4)*ME
KE/ME = 3/4 = 0.75
Part B.
When KE = PE, displacement is required.
If this event happens at 'x' displacement, then at this point we are aware that
ME = KE plus PE equals (1/2)*k*A2.
Because KE = PE
ME = PE + PE = (2*PE)*k*A2
PE = (1/4)*k*A^2
PE = (1/2)*k*x2 at x displacement, thus
(1/2)*k*x^2 = (1/4)*k*A^2
x^2 = (1/2)*A^2
(x/A)^2 = 1/2
sqrt(1/2) = 0.7071 for x/A
Using two reliable figures
x/A = 0.71
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