Answer:
1) Deadball
2) Leather
3) Foot Fault
4) Pass
5) Captain
Explanation:
1) In most sports when a ball is out of play or termed temporarily unplayable, it is said to be a Deadball.
2) Volleyballs are generally made of leather materials be it synthetic or genuine leather.
3) In volleyball, when a server steps on or over the end line, it is called foot fault.
4) The first contact of a ball by a player after a serve from a passer is usually called a pass.
5) In volleyball, the referee issues a coin toss in presence of both captains and the captain with the winning toss is the one that makes the choice of play area and the first server.
1. Some penguins are playing turtle hockey on the frictionless ice. Ramona the penguin hits the turtle
with a force of magnitude F, and the turtle experiences an acceleration of magnitude a (Fand a are of
unknown size). Francisco the penguin hits the same turtle with a force of magnitude three times
greater than Ramona's force (3F). What will the resulting acceleration of the turtle be? Answer in
terms of a. Support your answer with reasoning and reference to Newton's Second Law.
Answer:
a' = 3a
Explanation:
Newton's Second Law gives the magnitude of the unbalanced force applied to an object as follows:
F = ma
where,
F = Force Applied
m = Mass of Object
a = acceleration
FOR RAMONA'S PUSH:
F = F
m = m
a = a
Therefore,
F = ma
a = F/m ---------------- equation (1)
FOR FRANSICO'S PUSH:
F = 3F
m = m (mass of turtle will be same)
a = a'
Therefore,
3F = ma'
a' = 3F/m
using equation 1
a' = 3a
Which part of a DC generator keeps the electric current flowing in only one
direction?
A. The permanent magnets
B. The commutator
o
C. The power source
D. The wire coil
HELP NEEDED ASAP I'M GIVING BRAINLIEST
1) Select the best answer from the choices below. Light has many properties of waves, but sometimes it also behaves like:
a
A photon
b
Polarized light
c
Ultraviolet rays
d
A stream of particles
2) What type of waves transmit signals in satellite communication?
a
Microwaves
b
X-rays
c
Gamma Rays
d
Radio Waves
3) Cell phones use digital signals to send and receive information. These digital signals travel as what kind of wave?
a
Gamma rays
b
X-rays
c
Microwaves
d
Radio waves
Answer:
1.
d . A stream of particles
2. D. Radiowave
3. Microwaves
Answer:
1.
d . A stream of particles
2. D. Radiowave
3. Microwaves
Explanation:
PLS HELP THIS IS DUE IN TWO HOURS
Answer:
C
Explanation:
An elevator is being pulled up from the ground floor to the third floor by a cable. The cable is exerting 4500 newtons of force on the elevator. According to Newton's law of action-reaction, what is the gravitational force on the elevator, in newtons, if the elevator is NOT accelerating?
Answer:
The gravitational force on the elevator = 4500N
Explanation:
The given parameters are;
The force applied by the elevator, F = 4500 N
The acceleration of the elevator = Not accelerating
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows;
F = W + Mass of elevator × Acceleration of elevator
∴ F = W + Mass of elevator × 0 = W
F = 4500 N = W
The net force on the elevator is F - W = 0
The gravitational force on the elevator = W = 4500N.
The gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.
Given data:
The magnitude of force on the elevator is, F = 4500 N.
From Newton's third law of motion, the action of the cable force is equal to the reaction of the gravitational force on the elevator which is the weight, W and motion of the elevator as follows,
F = W + ma
Here, a is the acceleration of the elevator. Since, the elevator is not accelerating. Then, a = 0 .
The weight of the elevator is due to the gravitational force. So, we need to obtain the weight as gravitational force.
Solving as,
[tex]F = W+ma\\\\F=W +(m \times 0)\\\\4500=W\\\\W = 4500 \;\rm N[/tex]
Thus, we can conclude that the gravitational force on the elevator, if the elevator is NOT accelerating is 4500 N.
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Is Time and Light both connected in anyway?
Answer:
It is not connected by any way
Which two fundamental forces are only attractive?
O A. Gravitational and strong nuclear
O B. Electromagnetic and weak nuclear
O C. Electromagnetic and strong nuclear
O D. Gravitational and weak nuclear
The two fundamental forces that are only attractive is A. Gravitational and strong nuclear.
What connection exists between the strong nuclear force and gravity?The "strong" nuclear force outperforms gravity by a factor of 10 to the 38th. While gravitational and electromagnetic forces have relatively large ranges of action, the strong and weak nuclear forces operate at close ranges. All objects are affected by the strong and weak nuclear forces, whereas smaller objects are affected by gravitational and electromagnetic forces.
Nuclear forces are the most enticing of the four fundamental forces. There was no explanation provided as to how the nucleus in the atom is kept together by electromagnetism, which maintains matter together.
Therefore, option A is correct.
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An insulated rigid tank initially contains 1.4-kg saturated liquid water and water vapor at 200°C. At this state, 25 percent of the volume is occupied by liquid water and the rest by vapor. Now an electric resistor placed in the tank is turned on, and the tank is observed to contain saturated water vapor after 20 min. Determine:
(a) the volume of the tank
(b) the final temperature
(c) the electric power rating of the resistor
Solution:
Mass of liquid water and water vapor in the insulated tank initially = 1.4 kg
Temperature = 200 °C
And 25% of the volume by liquid water is steam.
State 1
[tex]$m=\frac{V}{v}$[/tex]
[tex]$m=m_f+m_g$[/tex]
[tex]$1.4=\frac{0.25V}{v_f}+\frac{0.75V}{v_g}$[/tex]
[tex]$1.4=\frac{0.25V}{1.1565 \times 10^{-3}}+\frac{0.75V}{0.1274}$[/tex] (taking the value of [tex]$v_g$[/tex] and [tex]$v_g$[/tex] at 200°C )
[tex]$V=6.304 \times 10^{-3}$[/tex]
Now quality of vapor
[tex]$x=\frac{m_g}{m}$[/tex]
[tex]$=3.377 \times 10^{-3}$[/tex]
Internal energy at state 1 can be found out by
[tex]$u_1=u_f+xu_{fg}$[/tex]
[tex]$=850.65+3.377\times10^{-3}\times 1744.65$[/tex]
= 856.54 kJ/kg
After heating with the resistor for 20 minutes, at state 2, the tank contains saturated water vapor [tex]$v_2=v_g \text { and }\ x=1$[/tex]
Tank is rigid, so volume of tank is constant.
[tex]$v_g=v_2=\frac{V}{m}$[/tex]
[tex]$v_g=\frac{6.304\times 10^{-3}}{1.4}$[/tex]
[tex]$v_g=4.502 \times 10^{-3} \ m^3 /kg$[/tex]
Now interpolate the value to get temperature at state 2 with specific volume value to get final temperature
[tex]$T_2=360+(374.14-360)\left(\frac{0.004502-0.006945}{0.003155-0.006945}\right)$[/tex]
= 369.11° C
Internal energy at state 2
[tex]$u_2=2154.9 \ kJ/kg$[/tex]
Now power rating of the resistor
[tex]$P=\frac{m(u_2-u_1)}{t}$[/tex]
[tex]$P=\frac{1.4(2154.9-856.54)}{20 \times 60}$[/tex]
= 1.51 kW
Will give brainliest!! How would you write the direction of the vector above as a global angle?
Answer:
Assuming they're unit vectors (length of 1)
You simply add them together.
The vector pointing right can be described with X and Y
(1, 0).
The vector pointing down
(0, -1).
The numbers are taken from the axis in X and Y directions.
If you add them together you get a final vector.
(1, - 1)
This gives you -45° pointing South East.
Or 360°-45°=315°
If the velocity of an object is zero, then that object cannot be accelerating. | True or False
Answer: False
Explanation:
What happens to the minerals as gneiss forms from schist?
Answer:
Explanation:
Gneiss is a high grade metamorphic rock, meaning that it has been subjected to higher temperatures and pressures than schist. However, unlike slate and schist, gneiss does not preferentially break along planes of foliation because less than 50% of the minerals formed during the metamorphism are aligned in thin layers.
can u plz help
Define: Medium
Answer:
Medium: something in a middle position, maybe in between sizes big or small, or in a situation it's not negative or positive it's just neutral. (I'm sorry if that wasn't helpful)
Explanation:
Where would you find the photosphere
A truck initially traveling at a speed of 22 m/s increases at a constant rate of 2.4 m/s^2 for 3.2s. What is the total distance travelled by the truck during this?
Answer:
82.7 m
Explanation:
u= 22m/s
a= 2.4 m/s^2.
t= 3.2 secs
Therefore the distance travelled can be calculated as follows
S= ut + 1/2at^2
= 22 × 3.2 + 1/2 × 2.4 × 3.2^2
= 70.4 + 1/2×24.58
= 70.4 + 12.29
= 82.7 m
Hence the distance travelled by the truck is 82.7 m
GIVING THE REST OF MY POINTS!
Energy can be:
A. destroyed or converted to another form.
B. destroyed.
C. created, but never destroyed.
D. converted to another form.
pls help me with this question pls
Explanation:
pls help me with this question pls
A man carries a load of mass 2.6kg from one end of a uniform pole 100cm long which has a mass 0.4kg. The pole rest on his shoulder at a point 60.0cm from the load and he holds it by the other end. What vertical force must be applied by his hand and what is the force on his shoulder?
Answer:
F = 39.2 N (hand force) and N = 68.6 N (shoulder force)
Explanation:
In this exercise we must use the rotational and translational equilibrium conditions, we have several forces: the weight (W) of the pole applied at its geometric center, the load (w1) at one end, the shoulder support (N) 60 cm from the load and hand force (F) at the other end of the pole
Let's set the reference system at the fit point of the shoulder
∑ τ = 0
We will assume that the counterclockwise turns are positive
w₁ 0.60 + W 0.1 + F₁ 0 - F 0.4 = 0
all distances are measured from the support of the man (x₀ = 0.60 m)
F = (w₁ 0.60 + W 0.1) / 0.4
F = (m₁ 0.6 + m 0.1) g / 0.4
let's calculate
F = (2.6 0.6 + 0.4 0.1) 9.8 / 0.4
F = 39.2 N
this is the force that the hand must exert to keep the system in balance
We apply the translational equilibrium condition
-w₁ -W + N - F = 0
N = w₁ + W + F
N = (m₁ + m) g + F
let's calculate
N = (2.6 + 0.4) 9.8 + 39.2
N = 68.6 N
Which of the following is a FALSE statement? (A) Heat moves through solids by conduction (B) Molecules move faster in warmer substances (C) Warm water is denser than cold water (D) Heat moves through liquids and gases by convection
Answer:
C.
Explanation:
What is the Net Force acting
on the box below?
Which of the following is a characteristic of a base?
A. pH greater than 7
B. pH between 4 and 13
C. pH between 4 and 9
D. pH less than 7
Answer:
A. pH greater than 7
Explanation:
Because a base has a pH scale of 8 to 14
A box sitting still on the ground by itself has a Normal Force of 700N, what is the mass? (gravity’s acceleration is 9.80 m/s²)
Answer:
Mass, m = 71.42 kg
Explanation:
Given that,
Normal force acting on a box, F = 700 N
We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,
F = mg
Where m is the mass of the box
[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]
So, the mass of the box is 71.42 kg.
I have a really long assignment I don't understand! please help
I can try and help whats it about?
There is friction between the block and the
table.
The suspended 2 kg mass on the left is
moving up, the 4 kg mass slides to the right
on the table, and the suspended mass 4 kg on
the right is moving down.
The acceleration of gravity is 9.8 m/s
2
.What is the magnitude of the acceleration
of the system?
1. 1.67253
2. 1.9845
3. 1.75311
4. 2.47673
5. 2.1315
6. 2.058
7. 2.548
8. 1.33933
9. 1.5288
10. 2.03127
Answer in units of m/s
2
.
Answer:
5 no
Explanation:
actually the 4kg lying on table has no influence
it slides towards 4kg weight hung
as it has excess 2kg force
force=miu × m ×g
The magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
Given data:
The masses suspended from the table are, m = 2 kg and m' = 4 kg.
And the mass kept on the table is, m'' = 4 kg.
The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,
[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]
Since, the mass kept on the right side is more. Then at equilibrium,
-f + m''g + (m' +m)a = m'g
Here,
a is the magnitude of acceleration of the system.
Solving as,
-4.312+ 4(9.8) + (4 -2)a = 4(9.8)
2a = 4.312
[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]
Thus, we can conclude that the magnitude of acceleration of the entire system is [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.
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A soccer ball is kicked with an initial velocity 13 m/s at an angle of 35 degrees from the horizontal. What is the maximum height reached by the ball?
Answer:
The maximum height reached by the ball is 2.84 m
Explanation:
Given;
initial velocity of the soccer, u = 13 m/s
angle of projection, θ = 35°
The maximum height reached by the ball = ?
Apply the following kinematic equation, to determine the maximum height reached by the ball.
Maximum height (H) is given as;
[tex]H = \frac{U^2sin^2\theta}{2g} \\\\H = \frac{(13)^2(sin \ 35^0)^2}{2*9.8}\\\\H = 2.84 \ m[/tex]
Therefore, the maximum height reached by the ball is 2.84 m
A 58-kg boy swings a baseball bat, which causes a 0.140-kg baseball to move toward 3rd base with a velocity of 38.0 m/s.
Calculate the kinetic energy of the baseball (rounding your answer to the integer).
Answer:
101 J
Explanation:
Answer:
[tex]\boxed {\boxed {\sf 101 \ Joules}}[/tex]
Explanation:
Kinetic energy can be found using the following formula:
[tex]KE=\frac{1}{2}mv^2[/tex]
The mass of the baseball is 0.140 kilograms and the velocity is 38.0 meters per second.
[tex]m= 0.140 \ kg \\v= 38.0 \ m/s[/tex]
Substitute the values into the formula.
[tex]KE=\frac{1}{2} [0.140 \ kg][(38.0 \ m/s)^2][/tex]
First, evaluate the exponent.
(38.0 m/s)²= 38.0 m/s * 38.0 m/s = 1444 m²/s²[tex]KE=\frac{1}{2}(0.140 \ kg)(1444 \ m^2/s^2)[/tex]
Multiply the two numbers in parentheses together.
[tex]KE=\frac{1}{2}(202.16 \ kg*m^2/s^2)[/tex]
Multiply the fraction by the number, or divide the number by 2.
[tex]KE=101.08 \ kg*m^2/s^2[/tex]
Round to the nearest whole number. The 0 in the tenth place tells us we can leave the number as is.
[tex]KE\approx 101 \ kg*m^2/s^2[/tex]
1 kg*m²/s² is equal to 1 Joule. Therefore, our answer of 101 kg*m²/s² is equal to 101 Joules (J).
[tex]KE\approx 101 \ J[/tex]
The kinetic energy of the baseball is about 101 Joules.
How do the individual forces compare when the rider experiences a sensation being lighter than his normal weight ? What is the acceleration direction when this occurs ?
Answer:
When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.
Explanation:
A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.
Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.
When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma
When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma
However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg
When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0
Which has the most momentum?
Select one:
A. 100 kg at rest
B. 20 kg at 2 m/s
C. 5 kg at 50 m/s
D. 10 kg at 5 m/s
Answer: C
Explanation:
A: 100kg*0m/s (obviously not answer)
B: 20kg*2m/s (=40)
C: 5kg*50m/s (=250, safe bet this one is it)
D: 10kg*5m/s (=50)
5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
To calculate momentum, we use the formula:
Momentum (p) = Mass (m) × Velocity (v)
Let's calculate the momentum for each option:
A. 100 kg at rest
Momentum = 100 kg × 0 m/s = 0 kg m/s
B. 20 kg at 2 m/s
Momentum = 20 kg × 2 m/s = 40 kg m/s
C. 5 kg at 50 m/s
Momentum = 5 kg × 50 m/s = 250 kg m/s
D. 10 kg at 5 m/s
Momentum = 10 kg × 5 m/s = 50 kg m/s
Therefore, 5 kg at 50 m/s, with a momentum of 250 kg m/s has the most momentum.
Hence, the correct option is C.
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________ is the speed and direction of an object
Answer:
velocity
Explanation:
plz mark brainliestʕ•ᴥ•ʔ
A 3kg ball moving at 8 m/s strikes a 2kg ball at rest,if the collision is elastic,what is the speed of the lighter ball if the heavier ball moves at 2m/s in the opposite direction
Answer:
Speed of lighter ball is 4 m/s.
Explanation:
Applying the principle of conservation of linear momentum,
momentum before collision = momentum after collision.
[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]
[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?
(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])
24 + 0 = 16 - 2[tex]v_{2}[/tex]
2[tex]v_{2}[/tex] = 16 - 24
2[tex]v_{2}[/tex] = -8
[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]
= -4 m/s
This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.
Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.
Answer:B
Explanation:
Mass
More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."
Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.
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