Answer:
4.4 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 3.5 L
Initial temperature (T₁) = 296 K
Final temperature (T₂) = 376 K
Final volume (V₂) =?
The final volume of the balloon can be obtained by using the Charles law equation as illustrated below:
V₁ / T₁ = V₂ / T₂
3.5 / 296 = V₂ / 376
Cross multiply
296 × V₂ = 3.5 × 376
296 × V₂ = 1316
Divide both side by 296
V₂ = 1316 / 296
V₂ = 4.4 L
Thus, the final volume of the balloon is 4.4 L
Consider a iron-silver voltaic cell that is constructed such that one half-cell consists of the iron, Fe, electrode immersed in a Fe(NO3)3 solution, and the other half-cell consists of the silver, Ag, electrode immersed in a AgNO3 solution. The two electrodes are connected by a copper wire. The Fe electrode acts as the anode, and the Ag electrode acts as the cathode. To maintain electric neutrality, you add a KNO3 salt bridge separating the two half-cells. Use this information to solve Parts B, C, and D. Part B The half-cell is a chamber in the voltaic cell where one half-cell is the site of the oxidation reaction and the other half-cell is the site of the reduction reaction. Type the half-cell reaction that takes place at the anode for the iron-silver voltaic cell. Indicate the physical states of atoms and ions using the abbreviation (s), (l), or (g) for solid, liquid, or gas, respectively. Use (aq) for an aqueous solution. Do not include phases for electrons. Express your answer as a chemical equation.
Answer:
See explanation
Explanation:
In the voltaic cell, energy is produced by spontaneous chemical reaction. One half cell functions as the anode (in this case it is the Fe/Fe^2+ half cell) while the other half cell functions as the cathode (in this case it is the the Ag/Ag^+ half cell).
At the anode;
Fe(s) -----> Fe^2+(aq) + 2e
At the anode;
2Ag^+(aq) + 2e ------> 2 Ag(s)
Overall cell equation;
Fe(s) + 2Ag^+(aq) ------> Fe^2+(aq) + 2 Ag(s)
Draw the atomic structure with electronic configuration of Potassium
Answer:
Explanation:
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1) ____C3H8 + ____O2 → ____CO2 + ____H2O
During the age of the dinosaurs, most mammals grew no bigger than a?
Answer:
T-rex
Explanation:
2) Using the following equation:
Water is added to iron and over time iron (III) oxide along with hydrogen gas is produced.
a. How many grams of iron (III) oxide will be produced when 15.5g of iron reacts with excess water?
b. Calculate the percent yield if your team produced 14.5g of iron (III) oxide.
c. If the reaction takes place under STP then how many liters of hydrogen gas are produced?
the answer is 133
because thats how the water is
What happens to plates at divergent boundaries?
Answer: A divergent boundary occurs when two tectonic plates move away from each other. Along these boundaries, earthquakes are common and magma (molten rock) rises from the Earth's mantle to the surface, solidifying to create new oceanic crust. ... Two plates sliding past each other forms a transform plate boundary.
If 18.0 g of CO2 is produced in the reaction of C2H2 with O2 to form CO2 and
H2O, how many grams of H20 are produced in this reaction?
O 3.68 g
9.0 g
14.7 g
None of the above
7.37 g
Answer:
3.68 g
Explanation:
[tex]n_{CO2}[/tex] = 18 ÷ 44 = 0.4
2C2H2 + 5O2 → 4CO2 + 2H2O
2 : 5 : 4 : 2
0.409 (moles)
⇒ [tex]n_{H2O}[/tex] = 0.409 × 2 ÷ 4 = 0.2045 moles
⇒ [tex]m_{H2O}[/tex] = 0.2045 × 18 = 3.68 grams
If a gas is cooled from 343.0 K to 283.15 K and the volume is kept constant what final pressure would result if the original pressure was 760.0 mm HG?
Answer:
627.4 mmHg
Explanation:
From Gay-Lussac law:
[tex] \frac{p1}{t1} = \frac{p2}{t2} [/tex]
p1 = 760 mmHg
t1 = 343 K
t2=283.15 K
[tex]p2 = p1 \times \frac{t2}{t1} [/tex]
[tex]p2 = 760 \times \frac{283.15}{343.0} [/tex]
[tex]p2 = 627.4 \: mmhg[/tex]
If a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.
Gay-Lussac's LawGay-Lussac's law states that the pressure of a given mass of gas at a constant volume varies directly with the temperature of the gas. Gay-Lussac's law defined the relationship between pressure and temperature of a gas when kept at a constant volume.
According to the Gay-Lussac's LawP ∝ T (When V = constant)
or, P = kT
or, [tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
Here,
[tex]P_{1}[/tex] = 760.0 mm Hg,
[tex]T_{1}[/tex]= 343.0 K
[tex]T_{2}[/tex] = 283.15 K
Now put the values in above formula, we get
[tex]\frac{P_1}{T_1} = \frac{P_2}{T_2}[/tex]
[tex]\frac{760.0\ \text{mm Hg}}{343.0K} = \frac{P_2}{283.15\ K}[/tex]
[tex]P_{2} = \frac{760.0\ \text{mm Hg} \times 283.15\ K}{343.0\ K}[/tex]
[tex]P_{2} = \frac{215194\ \text{mm Hg}}{343}[/tex]
[tex]P_{2}[/tex] = 627.4 mm Hg
Thus, we can say that if a gas is cooled from 343.0 K to 283.14 K and the volume is kept constant the final pressure would be 627.4 mm Hg if the original pressure was 760.0 mm Hg.
Learn more about Gay-Lussac's Law here: https://brainly.com/question/24691513
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a gas has a pressure of 0.470 atm at 60.0 C. What is the pressure at standard temperature?
Answer:
P2=0.385atm
Explanation:
step one:
Given that the temperature T1= 60 Celcius
we can convert this to kelvin by adding 273k to 60 Celcius
we have T1= 333k
pressure P1= 0.470 atm
step two:
we know that the standard temperature is T2= 273K
Applying the temperature and pressure relationship we have
P1/T1=P2/T2
substituting our given data we have
0.47/333=P2/273
cross multiply we have
P2= (0.47*273)/333
P2= 128.31/333
P2=0.385 atm
what causes ignition
Answer:
An ignition coil can fail due to a high voltage puncture of its body, or an open primary or secondary winding. A few are killed by overheating when the control side of the primary side develops a short to ground. Something as simple as badly worn spark plugs will increase the demand from the coil, and eventually lead to failure.
But if I were to discuss the current leading cause of ignition coil replacement, I would have to say misdiagnosis and bad internet information. This is especially true of modern “coil on plug” systems. Often, the actual coil is fine, and the only damage is the replaceable spark plug boot.
I've seen countless examples of online “advice” to start with replacing all spark plugs and coils at the suggestion of any power loss or hiccup. Then the car owner purchases the cheapest set of coils that they can find. Not only is the initial problem still present , but they likely WILL have a future misfire due to poor quality parts selection. All misfires are not caused by coils and spark plugs.
Explanation:
What will increased temperature in a reaction cause
1 Particles in a reaction to move more slowly
2 Particles in a reaction to move faster
3 Particles in a reaction to generate more electrical ions
4 Particles in a reaction to lose more electrical ions
Calculate the molar mass of PbSo3
Answer:
Lead sulfite is the inorganic compound with the formula PbSo3 or O3PbS.
Explanation:
4 methyl 2 pentanone structural formula
Answer:
(CH3)2CHCH2COCH3
Explanation:
Calculate the molar mass for S206[g).
Answer:
6605.3900 g/
Explanation:
What is the difference between 13.254 m/s and 7.7 m/s? Round your answer to the correct number of significant digits.
Answer:
5.6 m/s
Explanation:
Given,
First number = 13.254 m/s
Second number = 7.7 m/s
We need to find the difference between these two numbers. First we round off 13.254 to one decimal place i.e. 13.254 = 13.3 m/s
The difference between them is given by :
D = 13.3 - 7.7
= 5.6 m/s
Hence, the difference of the two numbers is 5.6 m/s.
Calculate the pH and pOH of a solution of sodium hypoiodite NaOI, with a formal concentration of 0.05784 mol L-1. Note that the compound is soluble, dissolves into sodium and hypoiodite ions, and these react with water. The p K a of hypoiodous acid at 298 K is 10.64. Calculate the pH and the pOH of the resulting solution. Use all the approximations you can, be sure to verify them.
Answer:
pH = 11.70
pOH = 2.298
Explanation:
As we know
NaOI + H2O NaOH + HOI
pH = 7 + ½ (pKa + log (HOI))
Substituting the given values, we get –
pH = 7 + ½ (10.64 + log (0. 0.05784))
pH = 7 + ½ (10.64 -1.2377)
pH = 11.70
pOH = 14 – pH
pOH = 14 -11.70
pOH = 2.298
if u mix 10ml of 70%ethanol with 20ml of 80% ethanol with 50ml water what is the concentration of the resulted solution
Answer:
29% is the final concentration
Explanation:
To solve this question we must find the volume of ethanol added and the volume of the whole solution. The concentration will be:
Volume ethanol / Total volume * 100
Volume ethanol:
10mL * 70% = 7mL ethanol
+
20mL * 80% = 16mL ethanol
= 23mL ethanol
Total volume:
10mL + 20mL + 50mL = 80mL
Concentration:
23mL / 80mL * 100
= 29% is the final concentration
In order to determine the magnetic properties of phosphorus atom we need to find out the number of unpaired electrons present in the ground state of phosphorus atom! Select one of the answers below that represents this number.
Group of answer choices
1
4
3
0
2
Answer:
Think of it this way If you have a phosphorus atom whats its oposites once you found that out you may be able to find the answer
Explanation:
Hope this helps :)
If 4 moles of C2H2 react, how many moles of CO2 can be produced?
Answer:
To solve this exercise you need to know that to create CO₂ with C₂H₂ is necessary to have oxygen. So, the following balanced equation represents the reaction:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)
Explanation:
7 organic compounds of plant origin
Answer:
carbohydrates, lipids, proteins and nucleic acidsHow can you tell if an atom has a positive charge? What type of ion is this?
Answer:i love you
Explanation:
Answer: An atom can acquire a positive charge or a negative charge depending on whether the number of electrons in an atom is greater or less then the number of protons in the atom. If the atom has more electrons than protons, it is a negative ion, or ANION. If it has more protons than electrons, it is a positive ion.
Explanation:
Can You please solve the question b in the photo. Will give branliest.
Answer:
Br₂ + 2e⁻ ⇄ 2Br⁻ Half reaction of reduction
2I⁻ ⇄ 2e⁻ + I₂ Half reaction of oxidation
Br₂ + 2I⁻ + 2K⁺ ⇄ I₂ + 2Br⁻ + 2K⁺
Explanation:
This is an easy redox reaction:
Br₂ + 2KI → I₂ + 2KBr
We determine the oxidation states.
0 for the elements at ground state.
K does not change the oxidation state during the reaction.
Bromine is reduced to bromide (oxidation state decreases)
and iodide is oxidized to Iodine (oxidation state increases)
Br₂ + 2e⁻ ⇄ 2Br⁻ Half reaction of reduction
2I⁻ ⇄ 2e⁻ + I₂ Half reaction of oxidation
In oxidation, electrons are released while in reduction, the electrons are gained. To make the ionic equation, we just add K⁺
So we sum both reactions
Br₂ + 2e⁻ + 2I⁻ + 2K⁺ ⇄ 2e⁻ + I₂ + 2Br⁻ + 2K⁺
We cancel the electrons on both sides of the equation:
Br₂ + 2I⁻ + 2K⁺ ⇄ I₂ + 2Br⁻ + 2K⁺
A piece of copper has a density of 8.96 g/cm3, what is the volume of a 4.2 g piece?
Answer:
0.47 cm³
Explanation:
[tex]Volume=Mass/Density\\[/tex]
Plug in the mass (4.2 grams) and the density (8.96 g/cm³)
[tex]Volume=4.2/8.96\\Volume=0.47[/tex]
Therefore, the volume of a 4.2 g piece of copper is approximately 0.47 cm³.
I hope this helps!
Solution A has a pH of 3, and solution B has a pH of 5. Which statement best
describes these solutions?
A. Solution A is acidic, and solution B is basic.
B. Solution A is basic, and solution B is acidic.
C. Solution B is less acidic than solution A.
O D. Solution B is more acidic than solution A.
Answer:
C. Solution B is less acidic than solution A.
URGENT PLEASE HELP! Given 3.4 grams of x element with a molar mass of 24 g/mol and 4.2 grams of y element with a molar mass of 35 g/mol. How much of compound xy2 can be generated?
x + 2y -> xy2
4.4 g XY
I'm not sure but that's the closest I can get or try
An acetate buffer solution is prepared by combining 50. mL of 0.20 M acetic acid,
HC2H3O2(aq), and 50. mL of 0.20 M sodium acetate, NaC2H3O2(aq). A 5.0 mL sample of 0.10 M NaOH(aq) is added to the buffer solution.
Which of the following is a correct pairing of the acetate species present in greater concentration and of the pH of the solution after the NaOH(aq) is added? (The pKa of acetic acid is 4.7.)
Acetate Species -- pH
(A) HC2H3O2 -- < 4.7
(B) HC2H3O2 -- > 4.7
(C) C2H3O2 -- < 4.7
(D) C2H3O2 -- > 4.7
Answer:
The answer is "Option B".
Explanation:
[tex]\to CH_3COOH + NaOH \longleftrightarrow CH_3COONa + H_2O\\\\\to CH_3COONa + NaOH\longleftrightarrow CH3COONa\\\\\therefore \ mol\ NaOH = (5 \ E-3\ L)\times(0.10 \ \frac{mol}{L}) = 5 \ E-4\ mol\\\\[/tex]
[tex]\to mol\ CH_3COOH = (0.05 \ L)\times(0.20 \frac{mol}{L}) = 0.01 \ mol\\\\\to C \ CH_3COOH = \frac{(0.01 \ mol - 5 \ E-4\ mol) }{(0.105 \ L)}\\\\\to C \ CH_3COOH = 0.0905 \ M\\\\\therefore \ mol \ CH_3COONa = (0.05\ L )\times (0.20 \ \frac{mol}{L}) = 0.01 \ mol\\\\[/tex]
[tex]\to C \ CH_3COONa = \frac{(0.01\ mol + 5 \ E-4\ mol)}{(0.105\ L )}\\\\\to C \ CH_3COONa = 0.1 \ M\\\\\therefore Ka = ([H_3O^{+}]\times \frac{(0.1 + [H_3O^+]))}{(0.0905 - [H_3O^+])} = 1.75\ E-5\\\\\to 0.1[H_3O^+] + [H_3O^+]^2 = (1.75 E-5)\times (0.0905 - [H_3O^+])\\\\[/tex]
[tex]\to [H_3O^+]^2 \ 0.1[H_3O^+] = 1.584\ E-6 - 1.75\ E-5[H_3O^+]\\\\\to [H_3O^+]^2 + 0.1000175[H_3O^+] - 1.584 \ E-6 = 0\\\\\to [H_3O^+] = 1.5835\ E-5 \ M\\\\\therefore pH = - \log [H_3O^+]\\\\\to pH = - \log (1.5835 \ E-5)\\\\ \to pH = 4.8004 > 4.7[/tex]
How many lone pairs are on the central atom of a molecule of RnCl4?
A. 0
B. 2
C. 3
D. 1
. Elements in the Periodic Table are arranged according to increasing numbers of _____________, which is called the ___________ ______________ on an element key.
Answer:. Elements in the Periodic Table are arranged according to increasing numbers of ______atoms_______, which is called the ______atomic _____ _______number_______ on an element key.
Explanation: I just learned about this at school!! ; )
what charge does copper have?
Answer: 1+charge
Explanation: hoped this helped:)
What is the pH of a solution that has a hydrogen ion concentration of 6.9*10^-4?
The pH would be 3.16 because the formula for finding the pH from a H± ion is pH = -log [H±]
So with that formula, you first have to substitute the H± with your numbers which in this case is 6.9 × 10^-4.
It should like this:
pH = -log (6.9 × 10^-4)
And lastly, just calculate.
pH = 3.16
Hope that helps, do let me know if you need more help in understanding this!