A basketball is rolling rightward onto the court with a speed of 4.0 m/s and slows down with a consta leftward acceleration of magnitude 0.50 m/s^2 over 14 m.
What is the velocity of the basketball after rolling for 14 m?
a. 2.0 m/s
b. 5.5 m/s
c. 7.5 m/s
d. 1.4 m/s

Answers

Answer 1

Answer:

d. 1.4 m/s

Explanation:

Given;

initial velocity of the `basketball, u = 4.0 m/s

acceleration of the basketball, a = -0.5 m/s² (leftward)

distance the basketball traveled, d = 14 m

the final velocity of the basketball, v = ?

(this final velocity should be less than the initial velocity since the ball is slowing down at a constant rate)

Apply the following the kinematic equation;

v² = u² + 2ad

v² = 4² + 2(-0.5)14

v² = 16 - 14

v² = 2

v = √2

v = 1.41 m/s

Therefore, the final velocity of the basketball is 1.4 m/s.


Related Questions

What acceleration will you give a 22.4 kg box if you push it with a force of 83.1N

Answers

Answer:

mass =22.4kg

force=83.1N

a=?

f=ma

a=f/m

a=83.1/22.4

a=3.70m/s^2

A solid is 5 cm tall, 3 cm wide, and 2 cm thick. It has a mass of 129 g. What is its
density?

Answers

Answer:

4.3 g/cm³ or 4.3g/cc

Explanation:

Volume(V) = Height × Length × Width

= 5cm × 3cm × 2cm

= 30cm³

Mass(m) = 129gram

So,

Density = m/V

= 129g/30cm³

= 4.3g/cc or 4.3g/cm³

Bob, of mass m, drops from a tree limb at the same time that Esther, also of mass m, begins her descent down a frictionless slide. If they both start at the same height above the ground, which of the following is true about their kinetic energies as they reach the ground?
A) Bob's kinetic energy is greater than Esther's.B) Esther's kinetic energy is greater than Bob's.C) They have the same kinetic energy.D) The answer depends on the shape of the slide.

Answers

Answer:

Explanation:

They have the same kinetic energy

Mental processes refers to

overt actions and reactions.

only animal behavior.

internal, covert processes.

outward behavior.

Answers

Internal,covert processes


A circuit with a 12 V battery and lamp has a current of 3 A. What is the resistance of the lamp?

Answers

chicken is the resistance of the lamp

PLEASE HELP!!!!
Suppose a tractor was moving forward at 6.0 m/s. It runs into a pile of hay and is
brought to a stop in 1.1 s. If the tractor had a mass of 2550 kg, with what force did
the pile of hay stop the tractor?
A. -5.5N
B. -14000N
C. 15000N
D. -15000N
E. -0.0021N
F. -0.000072

Answers

Answer:

B )-14000N

Explanation:

F=mv-mu

t

F =2550(0)-2550(6)

1.1

F = -13909.09

approximately -14000N

Suppose a tractor was moving forward at 6.0 m/s. It runs into a pile of hay and is brought to a stop in 1.1 s. If the tractor had a mass of 2550 kg, the force did the pile of hay stop the tractor 14000N

What are the types of force ?

Force can be a unit of  pushing or pulling of any object which result   from the object’s interaction or movement, without applying force the objects can not be moved, can be stopped or change the direction.

Force is a  quantitative parameter between two physical bodies, means an object and its environment, there are various  types of forces in nature.

If an object present in its moving state will be either static or motion, the position of the object will be changed if it is pushed or pulled and The external push or pull upon the object is mainly called as Force.

The contact force  that occurs when we apply some effort on an object such as Spring Force, Applied Force, Air Resistance Force, Normal Force, Tension Force, Frictional Force

Non-Contact forces are the type of forces that occur from a distance  such as Electromagnetic Force, Gravitational Force, Nuclear Force

F=mv-mu

t

F =2550(0)-2550(6)

1.1

F = -13909.09

approximately -14000N

For more details Force, visit

brainly.com/question/13691251

#SPJ2

An object has an average acceleration of + 6.24 m/s ^ 2 for 0.300 s . At the end of this time the object's velocity is + 9.31 m/s . What was the object's initial velocity?

Answers

Answer:

initial velocity = 7.44 m/s   (3 s.f.)

Explanation:

a = 6.24 m/s²     t = 0.300 s     v = 9.31 m/s       u = ?

                               v = u + at

                       9.31 = u + (6.24 x 0.300)

                             9.31 = u + 1.872

                                    u = 7.438

                                    = 7.44 m/s       (3 s.f.)

Hope this helps!

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