A bear has just had a sandwich that contained the equivalent of 2.70 mol of glucose ΔHo 2810 kJ mol 1 The standard molar entropy ΔSo of reaction is 182 J K 1 mol 1 How much energy in kJ is available for sustaining the bear's muscular and nervous activity assuming a body temperature of 36.1oC Make sure that your answer has the correct number of significant figures

Answer:

Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.

Answer:

How is titration used in the industry?

Titration is an analytical technique that is widely used in the food industry. It allows food manufacturers to determine the quantity of a reactant in a sample. For example, it can be used to discover the amount of salt or sugar in a product or the concentration of vitamin C or E, which has an effect on product colour.

Answer:

carboxylic acid

Explanation:

Phenols will not be water-soluble unless a strong base is used (10% NaOH), and amines are only water-soluble if acid is used.

Answer:

D. 6.3 x 10-5 mol/L NaOH

Explanation:

Alizarin yellow is an indicator that is yellow when pH < 10.1. In the same way, thymol blue is blue when pH > 9

That means the pH of the solution is between 9 - 10.1

Any acid as HCl could have a pH of these.

The solution of 3.2x10⁻⁴M NaOH has a pH of:

pOH = -log[OH-] = 3.49

pH = 14-pOH = 10.51. The pH of the solution is not 10.5

Now, the solution of 6.3x10⁻⁵M NaOH has a pH:

pOH = -log[OH-] = 4.2

pH = 14-pOH = 9.8

The pH of the solution could be 9.8. Right option is:

Answer:

The first law of thermodynamics states that energy can neither be created nor destroyed, only altered in form. For any system, energy transfer is associated with mass crossing the control boundary, external work, or heat transfer across the boundary. These produce a change of stored energy within the control volume.

Explanation:

Answer:

[tex]CO_3^{2-}[/tex]

Explanation:

Trioxocarbonate (iv) salts result from the reaction of trioxocarbonate(iv) acid with metals and metal oxides.

All sodium, potassium, and ammonium of  trioxocarbonate(iv) salts appearas to be soluble, while all others are insoluble.

Apart from Na and K, all trioxocarbonate (iv) salts breakdown to release CO2 when heated.

The formula for Trioxocarbonate (iv) is: [tex]CO_3^{2-}[/tex]

So, we can have Sodium trioxocarbonate as [tex]Na_2CO_3[/tex] and sodium hydrogen trioxocarbonate (iv) [tex]NaHCO_3[/tex]

Answer: 10

Explanation:

Answer:

See explanation.

Explanation:

Hello there!

In this case, for this titration problem, we first need to set up the undergoing chemical equation between barium chloride and hydrochloric acid:

[tex]2HCl+Ba(OH)_2\rightarrow BaCl_2+2H_2O[/tex]

Which occurs in a 2:1 mole ratio of acid to base and thus, we can write the following:

[tex]2n_{base}=n_{acid}[/tex]

Which can be written in molarities and volumes:

[tex]2M_{base}V_{base}=M_{acid}V_{acid}[/tex]

And we solve for the molarity of the acid:

[tex]M_{acid}=\frac{2M_{base}V_{base}}{V_{acid}}[/tex]

Unfortunately, the molarity of the base was not given:

"The molarity of an aqueous solution of hydrochloric acid, , is determined by titration with a M barium hydroxide, , solution. If 31.2 mL of barium hydroxide are required to neutralize 15.4 mL of the acid, what is the molarity of the hydrochloric acid solution?"

Yet we can assume an arbitrary value, say 1.0 M in order to show you the solution so that you can modify it according to your given value:

[tex]M_{acid}=\frac{2(1.0M)(31.2mL)}{(15.4mL)}=4.05M[/tex]

So you just need to modify the (1.0 M) by the actually given molarity of the acid.

Regards!

The question is incomplete, the complete question is:

The solubility of slaked lime, [tex]Ca(OH)_2[/tex], in water is 0.185 g/100 ml. You will need to calculate the volume of [tex]2.50\times 10^{-3}[/tex]M HCl needed to neutralize 14.5 mL of a saturated

Answer: The volume of HCl required is 290mL, the mass of [tex]Ca(OH)_2[/tex] is 0.0268g, the moles of

Explanation:

Given values:

Solubility of [tex]Ca(OH)_2[/tex] = 0.185 g/100 mL

Volume of [tex]Ca(OH)_2[/tex] = 14.5 mL

Using unitary method:

In 100 mL, the mass of [tex]Ca(OH)_2[/tex] present is 0.185 g

So, in 14.5mL. the mass of [tex]Ca(OH)_2[/tex] present will be =[tex]\frac{0.185}{100}\times 14.5=0.0268g[/tex]

The number of moles is defined as the ratio of the mass of a substance to its molar mass.

The equation used is:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex] ......(1)

Given mass of [tex]Ca(OH)_2[/tex] = 0.0268 g

Molar mass of [tex]Ca(OH)_2[/tex] = 74 g/mol

Plugging values in equation 1:

[tex]\text{Moles of }Ca(OH)_2=\frac{0.0268g}{74g/mol}=0.000362 mol[/tex]

Moles of [tex]OH^-[/tex] present = [tex](2\times 0.000362)=0.000724mol[/tex]

The chemical equation for the neutralization of calcium hydroxide and HCl follows:

[tex]Ca(OH)_2+2HCl\rightarrow CaCl_2+2H_2O[/tex]

By the stoichiometry of the reaction:

Moles of [tex]OH^-[/tex] = Moles of [tex]H^+[/tex] = 0.000724 mol

The formula used to calculate molarity:

[tex]\text{Molarity of solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (mL)}}[/tex] .....(2)

Moles of HCl = 0.000724 mol

Molarity of HCl = [tex]2.50\times 10^{-3}[/tex]

Putting values in equation 2, we get:

[tex]2.50\times 10^{-3}mol=\frac{0.000724\times 1000}{\text{Volume of solution}}\\\\\text{Volume of solution}=\frac{0.000725\times 1000}{2.50\times 10^{-3}}=290mL[/tex]

Hence, the volume of HCl required is 290mL, the mass of [tex]Ca(OH)_2[/tex] is 0.0268g, the moles of

Explanation:

Butanol (С4Н9OH)

Structural formula is :-

CH3-CH2-CH2-CH2-OH

Answer and Explanation:

Magnesium  = Mg (metal) ⇒ oxidation number = +2 (it loses 2 electrons)

Oxygen = O (non-metal) ⇒ oxidation number in oxides = -2 (it gains 2 electrons)

a) We first write the chemical elements with their oxidation numbers in superscripts:

Mg⁺² O⁻²

Then, the oxidation numbers are written crossed as subscripts:

Mg₂O₂

Finally, we divide by a common denominator (2):

MgO

b) Between a metal (Mg) and a non-metal (O), the formed bond is an ionic bond. The metallic element (Mg) loses 2 electrons that are accepted by the non-metallic element (O).

c) Mg : loses 2 electrons ⇒ +2

   O: gains 2 electrons ⇒ -2

The total electrical charge is: +2 + (-2) = 0

Answer:

B. Changing the daylight hours from 14 hrs to 10 hrs

Explanation:

Answer:

I wish i could help but I don't understand it .so maybe someone can come and help u

Answer:

b

Explanation:

Answer:

The volume of acetone is 9.24 mL

Explanation:

The 3D structure of R- CFClBrI is drawn using wedges and dotted line with I in the top and F right to I and Fischer projection is drawn using lines for bonds where C is placed at center and I in the top with F right to it.

An enantiomer is a spatial isomer of a compound having different spatial configuration but the same formula. Enantiomers are non-superimposable mirror images of each other.

In  R- enantiomer, the elements are arranges in a way that on numbering in clockwise direction, the priority of group decreases from 1 to 2 to 3 and follows. The highest priority group is numbered first.

If the count 1..2..3 goes in anti-clockwise direction, then the enantiomer is termed as S.  In 3D projection, wedges and dotted lines are used for representing bonds.

In Fischer projection, lines are used for bonds as shown in the uploaded image. Where the chiral carbon is shown in center and other groups are allotted as per the R or S configuration.

Therefore, the 3D image and Fischer projection of CFClBrI is drawn as in the image uploaded.

To learn more about, enantiomers, refer the link below:

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Answer:

1. 10 g / 100 g H₂O

2. 2 g / 100 g H₂O

Explanation:

Both questions ask about the solubility of cerium sulfate (Ce₂(SO₄)₃), meaning we need to focus on the dark blue line.

Hi there! Answer is below :)

Explanation:

For this question, we apply Boyle's Law and Charles' Law.

When you double the amount of pressure and temperature of a compound or mixture, the volume will decrease by a half. So, if the pressure and temperature are 2, and the volume is 1, and you double, your volume will be 0.5 and your pressure and temperature will be 4.

Best of Luck!

Answer:

C) 100:1

Explanation:

To solve this question we must use H-H equation:

pH = pKa + log [A-] / [HA]

Where pH = 7.0, pKa = 5.0, A- is proton aceptor and HA proton donor.

Replacing:

7 = 5 + log [A-] / [HA]

2 = log [A-] / [HA]

100 = [A-] / [HA]

That means the ratio of proton aceptor:proton donor is:

Answer:

glucose<NaCl<CaCl2

Explanation:

Hello there!

In this case, since the general equation for the calculation of the freezing point depression is:

[tex]\Delta T=-i*m*Kf[/tex]

Whereas m and Kf are the same for the given salts, then we conclude that the greatest freezing point is exhibited by the salt with the greatest Van't Hoff's factor and the smallest freezing point with the smallest Van't Hoff's factor. In such a way, since this factor is equal to the number of ionized species, we infer that CaCl2 has i=3, glucose i=1 (nonionizing) and NaCl i=2; therefore, the order from smallest to greatest is:

glucose<NaCl<CaCl2

Regards!

alimientos procesados:

cereales, queso ,verduras enlatadas, un pan bocadillos salados, como patatas fritas, panecillos de salchicha, tartas y empanadas productos cárnicos, como tocino, salchicha, jamón, salami y paté comidas para microondas o comidas preparadas pasteles y galletas bebidas, como leche o refrescos

alimientos naturales

1. Pescado · 2. Brócoli o cualquiera de las verduras crucíferas · 3. Remolacha · 4. Espinacas y otras verduras de hoja verde · 5. Col rizada · 6. Mantequilla de maní · 7. Almendras.pechugas de pollo, Cordero, Salmón, Camarón,Aceite de coco,Nueces y semillas

Answer:

what

Explanation:

Answer:

A) the mass in grams of one mole of a substance.

Explanation:

The molar mass of a substance is the mass in grams of 1 mole of the substance. As shown in this video, we can obtain a substance's molar mass by summing the molar masses of its component atoms. We can then use the calculated molar mass to convert between mass and number of moles of the substance.

Explanation:

hi sorry I wasn't able to find Nz on periodic Table may be just missed it so just find mr of Nz and times it by moles hope this helps

Answer:

C4H10

Explanation:

you already written it :)

Answer:

1.68 mol Ca(NO₃)₂

General Formulas and Concepts:

Atomic Structure

Stoichiometry

Explanation:

Step 1: Define

[Given] 275 g Ca(NO₃)₂

[Solve] mol Ca(NO₃)₂

Step 2: Identify Conversions

[PT] Molar Mass of Ca: 40.08 g/mol

[PT] Molar Mass of N: 14.01 g/mol

[PT] Molar Mass of O: 16.00 g/mol

Molar Mass of Ca(NO₃)₂: 40.08 + 2[14.01 + 3(16.00)] = 164.10 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

1.67581 mol Ca(NO₃)₂ ≈ 1.68 mol Ca(NO₃)₂

Answer:

1.68 mol Ca(NO₃)₂

Explanation:

Explanation:

A process where two or more number of miscible liquids present in different fractions are separated by boiling at different temperatures is called fractional distillation.

The sudden decrease in temperature is because the compounds having lower boiling point have completed the distillation before vapor of the higher boiling point can actually fill the distillation head.

Answer:

Transition metals, alkali metals, alkaline earth metals Transition metals - Middle of the periodic chart, only average reactivity. alkali metals - As mentioned above, very reactive. Bad choice, going from lower reactivity to higher reactivity.

Hope this answer is right!

Answer:

0.877 M

Explanation:

Number of moles of ammonia = 0.879 g /17 g/mol = 0.05 moles

The reaction equation is ;

2NH3 + OBr-→ N2H4 + Br- + H2O

2 moles of NH3 reacts with 1 mole of hypobromite

0.05 moles of NH3 reacts with 0.05 moles ×1 mole/2 moles

= 0.025 moles

Number of moles = concentration × volume

Concentration = Number of moles / volume

Concentration = 0.025 moles × 1000/28.5

Concentration = 0.877 M

Answer: For the given reaction [tex]Pb(NO_{3})_{2} + AlBr_{3}[/tex] the products are [tex]PBr_{2} + Al(NO_{3})_{3}[/tex].

Explanation:

A reaction in which two substances chemically combine together and results in the formation of a new substance is called a chemical reaction.

For example, [tex]3Pb(NO_{3})_{2} + 2AlBr_{3} \rightarrow 2Al(NO_{3})_{3} + 3PbBr_{2}[/tex]

Products are the species that are written on the right side of an arrow in a chemical reaction equation.

Hence, we can conclude that for the given reaction [tex]Pb(NO_{3})_{2} + AlBr_{3}[/tex] the products are [tex]PBr_{2} + Al(NO_{3})_{3}[/tex].

Answer:

[tex]V'=1040ml[/tex]

Explanation:

From the question we are told that:

Initial Volume [tex]V_1=10.5mL[/tex]

Initial Aciditity of [tex]HN0_3 pH_1=2.0g[/tex]

Finial Aciditity of [tex]HN0_3 pH_2=4.0g[/tex]

Generally the equation for Acidity &Volume Relationship is mathematically given by

[tex]N_1V_1=N_2V_2[/tex]

Therefore

[tex]V_2=\frac{N_1V_2}{N_2}[/tex]

[tex]V_2=\frac{10^{-2}*10.5}{10^{-4}}V_2=1050ml[/tex]

Therefore

Change in Water volume is

[tex]V'=V_2-V_1[/tex]

[tex]V'=1050ml-10ml[/tex]

[tex]V'=1040ml[/tex]

Answer:

The AH+ for Br2() is 0 kJ/mol.

The AH+ for Hg() is 0 kJ/mol.

The AH; for N261) is 0 kJ/mol.

Explanation:

The statements 1,3,4 and 5 are true.

Enthalpy is defined as a thermodynamic quantity, which can be considered equal to the total heat of the system.

Here,

1) The enthalpy of formation of Br₂ (cr, l) is 0 kJ/mol.

So, the statement is true.

2) The enthalpy of formation of He(l) is not zero.

So, the statement is false.

3) The enthalpy of formation of Hg(l) is 0 kJ/mol.

So, the statement is true.

4) The enthalpy of formation of Cl₂(g) is 0 kJ/mol.

So, the statement is true.

5) The enthalpy of formation of N₂ is 0 kJ/mol.

So, the statement is true.

Hence,

The statements 1,3,4 and 5 are true.

To learn more about enthalpy, click:

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