can someone help? NO LINKS OR IM REPORTING
Answer:
BjsjsjsiisudujdgjkkgywuuuyyyuwuA glass bottle of soda is sealed with a screw cap. The absolute pressure of the carbon dioxide inside the bottle is 1.50 x 105 Pa. Assuming that the top and bottom surfaces of the cap each have an area of 4.40 x 10-4 m2, obtain the magnitude of the force that the screw thread exerts on the cap in order to keep it on the bottle. The air pressure outside the bottle is one atmosphere
Answer:
[tex]F \approx 19.5 N[/tex]
Explanation:
From the question we are told that:
Pressure of [tex]P_{CO_2}=1.50 * 105 Pa.[/tex]
Bottle cap area [tex]A_b= 4.40 * 10-4 m^2[/tex]
Generally the equation for Resultant pressure [tex]P_r[/tex] is give as is mathematically given by
[tex]P_r=P_{CO_2}-P_a[/tex]
Where
[tex]P_a=atmospheric\ pressure = 1.013*10^5 pa[/tex]
[tex]P_r=1.50 * 105 Pa-1.013*10^5 pa[/tex]
[tex]P_r=0.487*10^5 pa[/tex]
Generally the equation for Force exerted by screw F is give as is mathematically given by
[tex]F = P*A\\F = 0.487*10^5*4.00*10^-4\\ F = 19.48 N[/tex]
[tex]F \approx 19.5 N[/tex]
A thin rod of length 0.75 m and mass 0.42 kg is suspended
freely from one end. It is pulled to one side and then allowed to swing
like a pendulum, passing through its lowest position with angular
speed 4.0 rad/s. Neglecting friction and air resistance, find (a) the
rod's kinetic energy at its lowest position and (b) how far above that
position the center of mass rises.
Answer:
a) K = 0.63 J, b) h = 0.153 m
Explanation:
a) In this exercise we have a physical pendulum since the rod is a material object, the angular velocity is
w² = [tex]\frac{m g d}{I}[/tex]
where d is the distance from the pivot point to the center of mass and I is the moment of inertia.
The rod is a homogeneous body so its center of mass is at the geometric center of the rod.
d = L / 2
the moment of inertia of the rod is the moment of a rod supported at one end
I = ⅓ m L²
we substitute
w = [tex]\sqrt{\frac{mgL}{2} \ \frac{1}{\frac{1}{3} mL^2} }[/tex]
w = [tex]\sqrt{\frac{3}{2} \ \frac{g}{L} }[/tex]
w = [tex]\sqrt{ \frac{3}{2} \ \frac{9.8}{0.75} }[/tex]
w = 4.427 rad / s
an oscillatory system is described by the expression
θ = θ₀ cos (wt + Φ)
the angular velocity is
w = dθ /dt
w = - θ₀ w sin (wt + Ф)
In this exercise, the kinetic energy is requested in the lowest position, in this position the energy is maximum. For this expression to be maximum, the sine function must be equal to ±1
In the exercise it is indicated that at the lowest point the angular velocity is
w = 4.0 rad / s
the kinetic energy is
K = ½ I w²
K = ½ (⅓ m L²) w²
K = 1/6 m L² w²
K = 1/6 0.42 0.75² 4.0²
K = 0.63 J
b) for this part let's use conservation of energy
starting point. Lowest point
Em₀ = K = ½ I w²
final point. Highest point
Em_f = U = m g h
energy is conserved
Em₀ = Em_f
½ I w² = m g h
½ (⅓ m L²) w² = m g h
h = 1/6 L² w² / g
h = 1/6 0.75² 4.0² / 9.8
h = 0.153 m
Should there be a salary cap for professional athletes?
answer:
From the fan side: Salary caps mean better competition and more parity between all teams in a given league (in theory, anyway). Salary caps in the NFL, NBA and NHL can foster this, but in MLB, luxury tax requirements may not be enough to prevent large-market teams from dominating.
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A 1 kg block of wood is attached to a spring, of force constant 200 N/m, which is attached to an immovable support. The block rests on a frictional surface with a coefficient of kinetic friction of 0.2. A 20 g bullet is fired into the block horizontally compressing the spring a maximum distance of 15 cm. Find the original velocity of the bullet before the collision.
Answer:
[tex]v=15.9499m/s[/tex]
Explanation:
From the question we are told that:
Mass of wood [tex]m=1kg[/tex]
force constants [tex]k= 200N-m[/tex]
Coefficient of kinetic friction [tex]\mu= 0.2[/tex]
Bullet mass [tex]m_b= 20 \approx 0.02kg[/tex]
Spring compresion [tex]y=15cm \approx 0.15 m[/tex]
Generally the equation for kinetic energy of bullet [tex]K>E_b[/tex] is mathematically given by
Complete Question
[tex]K.E_b=spring potential energy+work done against friction[/tex]
[tex]K.E_b=\frac{1}{2} mbv^2[/tex]
[tex]\frac{1}{2} m_b v^2=\frac{1}{2} ky^2+\mu my[/tex]
[tex]\frac{1}{2} (0.02)v^2=\frac{1}{2} (0.2)(0.15)^2+0.2(1)(0.15)[/tex]
[tex]v=15.9499m/s[/tex]
[tex]v\approx16m/s[/tex]
A ball weighing 100 g is attached to a string and swung around with a speed of 2 m/s. If the centripetal force exerted by the string is
0.5 N, what is the length of the string?
A) 0.08 m
B) 0.8 cm
C) 8 m
D) 80 cm
Assuming the ball is swung around in a circle parallel to the ground, it has a centripetal acceleration a of
a = v ² / R
where v is the tangential speed of the ball and R is the length of the string.
The tension in the string is 0.5 N, so by Newton's second law, the ball has acceleration
F = m a → a = F / m = (0.5 N) / (0.1 kg) = 5 m/s²
where m is the ball's mass.
Solve for R :
a = v ² / R → R = v ² / a = (2 m/s)² / (5 m/s²) = 0.8 m = 80 cm
The data points you have taken on your lab graphs roughly form a straight line. How do you interpret the slope of this line?
Steeper slopes mean higher speeds.
Steeper slopes mean lower speeds.
Steeper slopes mean higher error.
Steeper slopes mean lower error.
The slope has no relation to speed or error
Answer: Steeper slopes mean lower speeds.
Explanation:
People with schizophrenia are most likely to have delusions that reflect the theme of
Answer:
llogical or bizarre ideas or fantasies.
Explanation:
Quia
Active
16:05:5
A plant root is an example of
Answer:A plant root is an example of an organ
Explanation:The main function of the root is to collect nutrients and water from the soil.
Answer:
hi sorry i just want points YOSHIII :3
Explanation:
∁=f
E=hf
c=3x108m/s h=6.63x10-34 J*s
The spectrum of Hydrogen is in the picture below.
ShapeWrite their wavelength (m), frequency (Hz), speed (m/s), and energy (J).
ShapeShapeShape
wavelength
frequency
speed
energy
404x10-9m
4.04x10-7m
7.42x1014 Hz
3x108 m/s
4.92x10-19J
447 nm à ______________ m à f=_______________________ à E= __________________
471 nm à ______________ m à f=_______________________ à E= __________________
501 nm à ______________ m à f=_______________________ à E= __________________
587 mm à ______________ m à f=_______________________ à E= __________________
667 mm à ______________ m à f=_______________________ à E= __________________
2.56 m à ______________ m à f=_______________________ à E= __________________
Answer:
so you have a question
Explanation:
either way have a nice day
How far are two protons if they exert a force of 0.5 N on one another?
Answer:
5.08 metres
Explanation:
The both protons should be 5.08 meters apart so that force between them is equal to the weight of electron
The two protons will exert a repulsive force of 0.5 N when they are at a distance of [tex]2.146625 \times10^{-14} \,m[/tex] away from each other.
As protons have very little mass the gravitational force will be negligible. So here we will consider the electrostatic force between them.
According to Coulomb's law in electrostatics, the electrostatic force between two charges can be given by;[tex]F=k\frac{q_{1}q_{2} }{r^2}[/tex]Where [tex]k \approx 9 \times 10^9 \, Nm^2 /C^2[/tex]Here, since both the particles are protons;[tex]q_1 = q_2 = 1.6 \times 10^{-19}\,C[/tex]Given that F = 0.5 NSubstituting the known values in the Coulomb's law equation, we get;[tex]0.5\, N = 9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{r^2}[/tex]
ie; [tex]r= \sqrt{9\times 10^{9} Nm^2 /C^2 \times\frac{(1.6\times 10^{-19}\,C)\times(1.6\times 10^{-19}\,C)}{0.5\, N} } = 2.146625 \times 10^{-14}\,m[/tex]
Learn more about Coulomb's Law here:
https://brainly.com/question/1698562
What does weathering do?
2. What does erosion do?
3. What is physical weathering?
4. what are 3 examples of physical weathering?
5. What is chemical weathering?
6. What are 2 examples of chemical weathering?
7. What is biological weathering?
8. What are 3 examples of biological weathering?
Answer
Weathering describes the breaking down or dissolving of rocks and minerals on the surface of the Earth. Water, ice, acids, salts, plants, animals, and changes in temperature are all agents of weathering. Once a rock has been broken down, a process called erosion transports the bits of rock and mineral away.
Erosion is the geological process in which earthen materials are worn away and transported by natural forces such as wind or water. A similar process, weathering, breaks down or dissolves rock, but does not involve movement.
Physical weathering is caused by the effects of changing temperature on rocks, causing the rock to break apart. The process is sometimes assisted by water. ... Freeze-thaw occurs when water continually seeps into cracks, freezes and expands, eventually breaking the rock apart.
Swiftly moving water. Rapidly moving water can lift, for short periods of time, rocks from the stream bottom. ...
Ice wedging. Ice wedging causes many rocks to break. ...
Plant roots. Plant roots can grow in cracks.
the erosion or disintegration of rocks, building materials, etc., caused by chemical reactions (chiefly with water and substances dissolved in it) rather than by mechanical processes.
Carbonation. When you think of carbonation, think carbon! ...
Oxidation. Oxygen causes oxidation. ... or
Hydration. This isn't the hydration used in your body, but it's similar. ...
Biological weathering is weathering caused by plants and animals. Plants and animals release acid forming chemicals that cause weathering and also contribute to the breaking down of rocks and landforms. Chemical weathering is weathering caused by breaking down of rocks and landforms.
Burrowing animals like shrews, moles, earthworms, and even ants contribute to biological weathering. ...
When animals like birds forage for seeds and earthworms, they create holes and erode the upper surface of the soil, thus, contributes to weathering.
rabbits and other burrowing animals can burrow into a crack in a rock, making it bigger and splitting the rock. You may have seen weeds growing through cracks in the pavement.
Explanation:
Hope this helps you!!
Which choice is an example of an effect of agricultural techniques on the environment? increased oxygen levels in a pond due to fertilizer runoff sediment accumulation in a lake near a farm soil compaction caused by tillage increased plant growth caused by application of herbicides
Answer:
sediment accumulation in a lake near a farm.
Explanation:
In Agriculture, there are various techniques adopted by farmers for the growth and development of their crops. An effective and efficient agricultural technique would have a significant impact on the level of productivity attained by the farmers and as such meeting the unending requirements or needs of the consumers.
There are various agricultural techniques used in farming and these includes;
I. Mixed farming.
II. Arable farming.
III. Pastoral farming.
IV. Bush fallowing.
V. Shifting cultivation.
VI. Nomadic herding.
VII. Subsistence farming.
Generally, these agricultural techniques adopted by farmers has an effect or impact on the environment where it is practiced.
For example, one of such effect on the environment is the accumulation of sediments in a lake near the farm. Thus, this could lead to the formation of new materials such as silt, sand, clay, organic debris, etc., inside the lake.
Answer:
sediment accumulation in a lake near a farm.
Explanation:
What is the Underground water
Answer:
water found underground is called undergroundwater
. Name two ways to decrease the electric force between two charged object
Answer:
breaking the circuit
Explanation:
Use the simulation to determine the relationship between the distance from the magnet and the strength of the magnetic field at that point. Use a ruler to measure distance on the screen. Use a power fit to determine the B vs. r relationship for each location. To simplify your data collection, chose a data-collection axis where either Bx or By = 0. Measure the distance from the nearest edge of the magnet. You will need to obtain a ruler for collecting data.
Explanation:
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Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?
A) Θ decrease
B) Θ increase
C) Θ remains the same
D) distant between spheres increases
Answer:
Two small metallic spheres with equal mass are suspended as pendulums by strings of length L. The sphereshave the same electric charge and come to equilibrium with each string at an angle of Θ = 10.00° with the vertical. What happens if the electric charges are decreased?(D)
Explanation:
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Answer:
I don’t know what that is I’m sorry
Explanation:
Answer:
tbh i wish i can help
Explanation:
A particle A of mass 2kg originally moving with a velocity of 3ms collides directly with another particles B of mass 2kg moving with a velocity of 2ms in the opposite direction so that the velocity of A become 1ms after impact . Find the velocity of B after the impact.
Answer:
- 1 m/s ( here (-) means the opposite direction of A)
Explanation:
Let m1=2kg, m2=2kg,u1= 3m/s,u2= -2 m/s, v1= 1m/s
m1u1+m2u2= m1v1+m2v2
2×3+2×(-2) = 2×1 + 2x
2= 2(1+x)
x = -1
Hope it helps
If a car is traveling at a speed of 65 miles per hour, how can this be rewritten as a velocity?
Answer:
i.e 65 mph, and a direction, say "east'.
Explanation:
give 3 uses of mirrors in everyday life
Answer:
Putting on makeup lol
Driving
Magnification and Science
Photography
Explanation:
I did an extra one if the makeup one wasn't allowed hahah
A cylinder of gas has a frictionless but tightly sealed piston of mass M. A small flame heats the cylinder, causing the piston to slowly move upward. For the gas inside the cylinder, what kind of process is this?
Answer:
isobaric
Explanation:
According to the attached figure, the process would be isobaric as the gas would be expanded at the time when it maintains the constant pressure
The ideal gas law derives
PV = nRT
As the flame is there at the bottom side so atoms or molecules of gas would get heat up slowly also their temperature would be increased. Thus in the case when piston would not be permitted to move so the pressure would rise having maintaining the constant volume and after this the process could be isochronic but in the given case, the piston would be permitted to move slowly upward so that there is a rise in the volume. However, the gas particles would be adjust themselves in order to maintain constant pressure so the given process represent isobaric
A child is pushing a merry-go-round. The angle through which the merry-go-round has turned varies with time according to θ(t)=γt+βt3θ(t)=γt+βt3, where γ=γ= 0.450 rad/srad/s and β=β= 1.10×10−2 rad/s3rad/s3. Part A Calculate the angular velocity of the merry-go-round as a function of time. Express your answer in terms of the variables ββ, γγ, and tt. ωz(t)ωz(t) = nothing rad/srad/s SubmitRequest Answer Part B What is the initial value of the angular velocity? ωzωz = nothing rad/srad/s SubmitRequest Answer Part C Calculate the instantaneous value of the angular velocity ωzωz at t=t= 5.25 ss . ωzωz = nothing rad/srad/s SubmitRequest Answer Part D Calculate the average angular velocity ωav−zωav−z for the time interval t=0t=0 to t=t= 5.25 ss .
Answer:
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Explanation:
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HELP QUICK! Please can anyone do the other half for me
Answer:
9) c
10) c
11) d
12) d
Explanation:
I think it's helps you
When turning from your path onto a perpendicular path your speed
SHOULD BE at a STEADY
DRIVERS ED PLEASE HELP
Answer: 5-15MPH
Explanation: Trust me
What is responsible for the amount of current in a circuit?
Will mark as Brainliest!!!
Answer:
Voltage is required for there to be a current but resistance can effect the amount of current.
Answer:
the answer is voltage
Explanation:
we just finished this unit in class
35. What would a ship's position be if that ship started at
point B and traveled at an average velocity of 35 km/h
west to point D in a time period of 1.2 h?
Answer:
The final position of the ship after the given time period is 42 km West of B.
Explanation:
Given;
average velocity of the ship, v = 35 km/h
time taken for the ship to reach point D, t = 1.2 hours
The position of the ship after the given time period is calculated as follows;
x = v x t
x = (35 km/h) x 1.2 h = 42 km
x = 42 km West of B.
Therefore, the final position of the ship after the given time period is 42 km West of B.
What question were you trying to answer in this study?
A. Why are the lightbulbs exploding?
B. Why are the lightbulbs melting?
C. Why are the lightbulbs so dim?
D. Why are the lightbulbs burning out?
Three points A, B and C are located along a horizontal line. A positive test charge is released from rest at C and accelerates towards B. Upon reaching B, the test charge continues to accelerate toward A. Assuming that only motion along the line is possible,
a) Which point has the highest potential; A, B or C?
b) What will a negative test charge do when it is released from rest at B?
As the Moon revolves around the Earth, it also rotates on its axis. Why is it that the same side of the Moon is always visible from Earth?
Answer: The speed of the moon's rotation keeps the same side always facing Earth.
Explanation: Please mark me brainiest
Answer:
The speed of the Moon's rotation keeps the same side always facing Earth.
Explanation:
got it right on study island :)