A blimp is flying directly above a football field. The angle of depression to the base of one goal post is 40°. The angle of depression to the base of the other goal post is 72°. If the goal posts are 360ft apart, how high is the blimp flying? Round to the nearest tenth of a foot.​

Answer:

. A blimp is flying directly above a football field. The angle of depression. 555.OF+ to the base of one goal post is 40. The angle of depression to the base of the other goal post is 72". If the goal posts are 360 feet apart. 7. how high is the blimp flying? Round to the nearest tenth of a foot. : a Sih C 8 360 5in (68) 333.8 36 0F 7. The bearing from a lighthouse to Ship A is S71 E. The bearing from the lighthouse to Ship B is S 39° E. If Ship A is 15 kilometers from the lighthouse and Ship B is 96 kilometers from the lighthouse, find the distance between the ships. Find the areg of each triangle. Round answers to the nearest tenth. B. 84.0 8. 2. 11m ((uSin 64) 15.q ft 64 10.

The blimp flying is "237 m" high.

According to the question,

In ΔABC,

∠XCA = ∠CAB = 72°

∠YCB = ∠CBA = 40°

Now,

→ ∠A + ∠B + ∠C = 180°

By putting the values,

  72° + 40° + ∠C = 180°

           112° + ∠C = 180°        

                     ∠C = 180° - 112°

                           = 68°

By applying Sin Rule,

→ [tex]\frac{AB}{Sin \ 68^{\circ}} = \frac{AC}{Sin \ 40^{\circ}}[/tex]

        AC = [tex]\frac{360\times Sin \ 40^{\circ}}{Sin \ 68^{\circ}}[/tex]

We know that,

Area of ΔABC = [tex]\frac{1}{2}[/tex] × AB × AC × Sin 72° ...(Equation 1)

Area of ΔABC = [tex]\frac{1}{2}[/tex] × AB × h ...(Equation 2)    

From "Equation 1 and 2",

→ [tex]\frac{1}{2}[/tex] × AB × AC × Sin 72° = [tex]\frac{1}{2}[/tex] × AB × h      

                                   h = AC × Sin 72°

By substituting value of "AC",

                                      = [tex]\frac{360\times Sin \ 40^{\circ}}{Sin \ 68^{\circ}}[/tex] × Sin 72°

                                      = 237.36 or, 273 m

Thus the answer above is correct.  

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