a body weights 28N at a height of 3200km from the earth surface.What will be the gravitational force on that body if its lies on the earth surface.

Answers

Answer 1

Answer:

The object would weight 63 N on the Earth surface

Explanation:

We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:

[tex]F_G=G\,\frac{M_E\,m}{d^2} \\28\,\,N=G\,\frac{M_E\,m}{9600000^2}[/tex]

Now, if the body is on the surface of the Earth, its weight (w) would be:

[tex]F_G=G\,\frac{M_E\,m}{d^2} \\w=G\,\frac{M_E\,m}{6400000^2}[/tex]

Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:

[tex]\frac{w}{28} =\frac{9600000^2}{6400000^2} \\\frac{w}{28} =\frac{9}{4} \\\\ \\w=\frac{9\,*\,28}{4}\,\,\,N\\w=63\,\,N \\[/tex]


Related Questions

8. You have two iron rods which are identical in appearance, but one is a permanent magnet and the other is unmagnetized. What series of simple experiments can you perform, using only the two rods, which will allow you to determine which of the rods is the permanent magnet

Answers

Answer:

Explanation: Let assume that bars are labeled A and B

Method 1

Using just the identical appearing bar magnet and unmagnetized iron bar.

Place the end of bar A in the middle of bar B.

If bar A sticks to bar B, then bar A is the magnet and bar B the umagnetized iron bar.

If bar A jumps to one of the ends of bar B, then bar B is the magnet.

Reason been that the magnetic field on a bar magnet is greatest at the two poles where the field comes out of the magnet. The center, between the poles, will be the weakest part of the field.

Method 2

Another solution would be to separate the two by quite some distance, float them on a piece of cork/wood in a plastic bucket or suspend them from long strings, then see which one consistently (eventually) lines up tending towards the Earth’s magnetic field.

How is a less-intense wave different from a more-intense wave?
It has fewer decibels.
O It has a higher pitch.
O It has more volume.
It has more energy.

Answers

Answer: It has fewer decibels.

Explanation:

In a sound-wave, the intensity is defined as the power carried by the wave. The decibel is a measure of the ratio between two quantities. And in acoustics is used as the unit of the sound pressure level, which is related to the intensity of the wave, then:

As the intensity increases, we also should notice an increase in the decibels.

How is a less-intense wave different from a more-intense wave?

The less-intense wave has fewer decibels.

Answer:

It has fewer decibels.

Explanation:

Which of the following statements describes nucleons?
A. Nucleons are the particles that make up a nucleus.
B. Nucleons are the particles in an atom that are neutral.
C. Nucleons are the particles that make up an atom.
D. Nucleons are the particles in an atom that have a charge.

Answers

Answer: nucleons are the particles that make up in nucleus

Explanation:

Nucleons are the particles that make up a nucleus, and they include protons and neutrons.

What are nucleons?

Nucleons are particles that make up nucleus of an atom. They include either proton or neutron, or both found in atomic nucleus.

Generally, nucleons are subatomic particles found within nucleus of an atom.

Therefore, we can conclude that, nucleons are the particles that make up a nucleus.

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Janaki Temple and Pashupatinath Temple are increasing our pride how​

Answers

Answer:

Janaki temple and Pashupatinath Temple are found in Nepal. These structures are religious and they increase the pride of the country through tourism. These temples are important in the country and are mostly visited by tourists.

This also helps to bring in income for the country and also helps by attracting many visitors and a corresponding development of its tourism industry.

The density of water is 1000 kg m^3. What is the value expressed in gcm^-3 units? please help me..
(1) 1000 (2) 100 (3) 1 (4) 0.1 (5) 0.01​

Answers

The answer is 1 which is option 3

Here's the neat, cool way to convert units like this:

-- 1 kilogram  =  1,000 grams

-- 1 meter  =  100 centimeters

So . . . . .

(1000 kg/m³) x (1000 g/kg) x (1 m/100 cm)³ =

(1,000 kg/m³) x (1,000 g/kg) x (1 m³/1,000,000 cm³) =

(1,000 x 1,000 x 1 / 1,000,000) (kg-g-m³ / m³-kg-cm³)  =  1 g/cm³

Culture creates the context for behavior in society. true or false

Answers

Answer:

True every culture is diffrent and culture is the way to grow up, the people or things you live around, or the ways of life you follow or dress.

Explanation: The definition of culture is:  means a particular set of customs, morals, codes and traditions from a specific time and place. All of that develops how a person may behave in society.

Answer:

true

Explanation:

just took the quiz

What does addition of two vectors give you?

Answers

Answer:

Explanation:

To add or subtract two vectors, add or subtract the corresponding components. Let →u=⟨u1,u2⟩ and →v=⟨v1,v2⟩ be two vectors. The sum of two or more vectors is called the resultant. The resultant of two vectors can be found using either the parallelogram method or the triangle method .

A wire carrying a 35.0 A current passes between the poles of a strong magnet such that the wire is perpendicular to the magnet's field, and there is a 2.55 N force on the 3.00 cm of wire in the field. What is the average field strength (in T) between the poles of the magnet

Answers

Answer:

7.65 T

Explanation:

From the question,

Using,

F = BILsinФ......................... Equation 1

Where F = Force, B = magnetic field strength, I = current, L = Length, Ф = Angle.

Make B the subject of the equation

B = F/ILsinФ........................Equation 2

Given: F = 2.55 N, I = 32 A, L = 3.00 cm = 0.03 m, Ф = 90° (perpendicular)

Substitute into equation 2

B = 2.55/(32×0.03×sin90°)

B = 2.55/0.96

B = 7.65 T

What force is required to give an object with mass 300 kg an acceleration of 2
m/s2?
O A. 300 N
O B. 1200 N
O C. 600 N
O D. 150 N​

Answers

Answer:

C. 600 N

Explanation:

Given,

mass of object (m)= 300kg

acceleration(a) =2m/s^2

We know that,

Force(F)=ma

=300*2

=600N

So,600N force is required to give an object.

Answer:

600 N

Explanation:

aye pecks

Law of conservation
of momentum

Answers

Answer:

Explanation:

Law of conservation of momentum is applied in solving collision problem. When two body collides, their momentum after collision can be determined using the law.

The law States that the sum of momentum of two bodies before collision is equal to the sum of their momentum after collision. Before collision, both bodies moves with a different velocity while during some cases, the bodies moves with a common velocity after collision.

Whether they move with or without the same velocity depends on the type of collision that exists between them after the collision. After collision, some object sticks together and move with a common velocity while some doesn't.

If the bodies sticks together after collision, the type of collision that occur is inelastic (energy is not conserved) and if they splits after collision, the type of collision that occur is an elastic collision (energy is conserved).

Let m1 and m2 be the masses of the bodies

u1 and u2 be their velocities before collision

v1 and v2 be their velocities after collision.

According to the law;

m1u1 + m2u2 = m1v1 + m2v2

Note that momentum = mass × velocity of the body.

Please help me with this question ASAP.

In a a potentiometer circuit, a 1m long potentiometer wire PQ of resistance 10 ohms is connected in series with a cells of e.m.f. 9V with internal resistance 3 ohms Calculate:

i The p.d. across PQ
ii. The e.m.f. of a cell which has a balance point of 75cm.​

Answers

Answer:

i. 6.923 V

ii. The e.m.f. = 22.5 V

Explanation:

i. The given parameters are;

Length of potentiometer = 1 m

The resistance of the potentiometer = 10 Ω

The e. m. f. of the attached cell = 9 V

The current, I flowing in the circuit = e. m. f/(Total resistance)

The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A

The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire

The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V

ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;

[tex]\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}[/tex]

Where:

E = e.m.f. of the balance point cell

[tex]R_{balance}[/tex] = Resistance of 75 cm of potentiometer wire  = 0.75×10 = 7.5 Ω

[tex]R_{cell}[/tex] = Resistance of the cell in the circuit = 3 Ω

V = e.m.f. attached cell = 9 V

[tex]\dfrac{E}{7.5} = \dfrac{9}{3}[/tex]

E = 7.5*3 = 22.5 V

The e.m.f. = 22.5 V

A car engine burns gas at 495 K and exhausts to the air at 293 K. What is the highest possible efficiency it could have?
(NO UNIT)

Answers

Answer:

59.19%

Explanation:

Step 1:

Data obtained from the question. This include the following:

Input temperature = 495 K.

Output temperature = 293 K.

Efficiency =..?

Step 2:

Determination of the efficiency of the engine.

Efficiency is simply defined as the ratio of output to input times 100. Mathematically, it is expressed as:

Efficiency = output /input x 100

With the above formula, we can calculate the efficiency of the engine as follow:

Input temperature = 495 K.

Output temperature = 293 K.

Efficiency =..?

Efficiency = output /input x 100

Efficiency = 293/495 x 100

Efficiency = 59.19%

Therefore, the efficiency of the engine is 59.19%

Answer:

0.41

Explanation:

Trust me bro

Question 1 of 10
What is a neutron
A. A particle inside the nucleus that has no charge
B. A positive particle inside the nucleus
O C. A negative particle outside the nucleus
O D. A negative particle inside the nucleus​

Answers

Answer:

The neutron is a subatomic particle, symbol 

n

 or 

n0

, with no electric charge and a mass slightly greater than that of a proton. Protons and neutrons constitute the nuclei of atoms. Since protons and neutrons behave similarly within the nucleus, and each has a mass of approximately one atomic mass unit, they are both referred to as nucleons.[6] Their properties and interactions are described by nuclear physics.

Explanation:

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What rule should be used to transform a table of data to represent the
reflection of f(x) over the yaxis?

Answers

Answer:

Multiply the x values with -1.

Explanation:

By multiplying the numbers by one, you are changing them to be the opposite of their original state.

You multiply the numbers that are in the x-value column because you are reflecting the image over the y-axis.

Hope this helped and good luck!

Answer:

Multiply each x-value in the table by -1

Explanation:

when vector contains distance and direction it also known as

Answers

When vector contain distance and direction it is also known as displacement .

Find the net force on q3. Include the direction ( +or-).
q1= -53.0 uC; q2=105 uC; q3= -88.0 uC; q1 to q2= 0.50m; q2 to q3= 0.95m
I will give brainliest to whoever gets the correct answer!

Answers

Answer:

72.16 N

Explanation:

Given:

q₁ = -53.0 μC

q₂ = 105 μC

q₃ = -88.0 μC

q₁ to q₂ = 0.50 m

q₂ to q₃ = 0.95 m

To find:

Net force on q₃

Solution:

First compute net electric field on q₃

E = F/q = k.Q/d²

The formula of electric field at q₃:

E = k.Q / r²

Where    

r is distance

Q is magnitude of charge

k is a constant with a value of 8.99 x 10⁹ N m²/C²

When

q₂ to q₃ = 0.95m and

q₂ = 105 μC then

Find electric field due to charge q₂

E = ( (8.99 x 10⁹)x( 105 x 10⁻⁶) ) / 0.95²

  =  (8990000000  x 0.000105) / 0.9025

  = 943950  / 0.9025

  = 1045927.977839

  = 1.046 x 10⁶ N/C

This interprets that it will act or point away from q₂

q₁ to q₂= 0.50m

q₂ to q₃ = 0.95m and

q₁ = -53 μC then

Find electric field due to charge q₁

E = (8.99 x 10⁹) x (53 x 10⁻⁶) / (0 .50 + 0.95)²

  =  (8990000000  x  0.000053) / (1.45)²

  = 476470 /2.1025

  = 226620.689655

  = 0.227  x 10⁶ N/C

This interprets that it will act or point towards q₁

Since these fields are opposite in direction.

Compute Net Field

Net Field = 1.046 x 10⁶ - 0.227  x 10⁶ N/C

               =  1046000 - 227000

               = 819000

               = 0.819 x 10⁶

               ≈ 0.82 x 10⁶

This interprets that it will act or point away from q₂

Compute force on q3

q₃ E  = 88 x 10⁻⁶ x 0.82 x 10⁶

       = 88000000  x 820000

       = 72160000000000

       = 72.16 N

Force on -ive charge in a field is always in a direction opposite to direction of field

So this interprets that direction of this field will be towards q₂.

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)

Answers

Answer:

[tex]\boxed{ V_{2}= 0.03189 m^3}[/tex]

Explanation:

According to Charles Law

=> [tex]\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}[/tex]

Where [tex]V_{1}[/tex] = 0.0279 m³, [tex]T_{1}[/tex] = 280 K and [tex]T_{2}[/tex] = 320 K

=> [tex]\frac{0.0279}{280} = \frac{V_{2}}{320}[/tex]

=> [tex]V_{2}[/tex] = 0.03189 m³

Let's say that we have a pilot that is dropping a package from a plane that is flying horizontally at a constant speed. If we neglect air resistance when the package hits the ground what would be the horizontal location of the package with respect to the plane?

Answers

Answer:

The package will be directly below the location of the plane.

Explanation:

Look up projectile motion for more information. The horizontal speed of the package is separate from the vertical speed of the package. The vertical speed of the falling package will be based on the rate of acceleration and the height of the package when dropped. The horizontal speed of the package will be the same as the plane so the package will remain directly below the plane the entire time until the package hits the ground.

The horizontal location of the package with respect to the plane will be parallel to the plane if no air resistance act on it. The pack will be straight to down because of the gravity.

What is gravitational force?

Gravitational force is the force by which an object attracts other objects into its center of mass. Earth attracts every objects in its surface towards its center that's why we are all standing on the ground.

The gravitational force acting on a body is dependent on its mass and height. From an  object falling from a height will experience a positive acceleration downwards to the ground.

If any air resistance is present there, the path of motion of the falling object from the height might be changed randomly. Here, the package is falling from plane without any air resistance and it will be straight down to the plane.

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Light travels 300 000 000 m/s and one year has approximately 32 000 000 second a light year is the distance light travels in one year

Answers

Explanation:

It is given that,

Speed of light, [tex]v=300 000 000\ m/s=3\times 10^8\ m/s[/tex]

Seconds in 1 year, [tex]t=32 000 000=32\times 10^6\ s[/tex]

We need to find the distance traveled by light in one year. Speed of an object is given by :

[tex]v=\dfrac{d}{t}[/tex]

So,

[tex]d=v\times t\\\\d=3\times 10^8\times 32\times 10^6\\\\d=9.6\times 10^{15}\ m[/tex]

Since,

[tex]1\ \text{light year}=9.46\times 10^{15}\ m\\\\1\ m=\dfrac{1}{9.46\times 10^{15}}\ \text{ly}\\\\9.6\times 10^{15}\ m=\dfrac{9.6\times 10^{15}}{9.46\times 10^{15}}\\\\d=1.01\ \text{ly}[/tex]

So, the distance covered by light is 1.01 light years.

Three books are at rest, in equilibrium, on a horizontal table as
shown. The weight of each book, which is equal to the force
gravity exerts in the downward direction, is given. What is the
net force on the middle book?​

Answers

Answer:

Net force = 0

Explanation:

Short answer: if the middle book is not acceleration in any direction, the net force is zero.

Long answer: refer to the attached free-body diagram (FBD) to see why the net force is zero.  Skills to draw FBD are  essential in solving problems in statics.

Top book exerts -mg (downwards) on the middle book.

Middle book exerts -mg (downwards) on the bottom book.

Total downward force is -mg-mg = -2mg

By Newton's third law, when an object is not in motion, reaction equals action of -2mg in the opposite direction, therefore the reaction (upwards) is +2mg.

This makes the net force of -2mg (downwards) + 2mg (upwards) =0

On a horizontal table, three books are resting and balanced. The net force on the middle book will be equal to zero.

What is equilibrium?

Equilibrium is the condition of an object when two or more opposing forces, whether internal, external or a combination of both, act on the body and cancel one another out to maintain the object in the same state as it was. The Latin term for weight or balance, libra, serves as the origin of the word equilibrium.

According to the question :

The net force is 0 if the middle book does not accelerate in any direction.

The Middle book is impacted negatively (downwards) by the top book.

The middle book pulls down on the lower book by -mg.

The total downward force is -2mg = (-mg-mg)

According to Newton's third rule, a reaction when an item is not moving equals an action of -2mg in the opposite direction, hence the reaction (upwards) is a response of +2mg.

Consequently, the net force of -2mg (downwards) + 2mg (upwards) = 0 is created.

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Calculate the speed of a car that travels 355km in 15 hours , a good answer please

Answers

Answer:

23.67 km / hr

Explanation:

car travels 355 km (d)

duration = 15 hrs  (t)

average speed formula = v = d / t

v = 355 km / 15 hr

v = 23.67 km / hr

Explanation:

Hello, there!!!

Here, your question is asking about the speed and the given are:

distance (s)= 355km

time (t) = 15hrs.

speed (v)=?

now,

we have the formula:

v= s/t

or, v = 335km /15 hrs.

Therefore, the speed of car was 23.67km/hr.

Hope it helps..

What is the wavelength of the following waves?

Answers

Answer:

i. the wavelength is 7.2 m

ii. the wavelength is 2.4 m

Explanation:

the wavelength of a wave is from crest to crest or from trough to trough.

explain why the term Nano is used to describe nanotechnology​

Answers

Answer:

Nanotechnology means working with materials at the scale of one billionth of a metre.

Explanation:

The prefix “nano” refers to one billionth: it’s part of the scientific scale of measurement. Its science, engineering, and technology are conducted at the nanoscale, which is about 1 to 100 nanometers. Nanoscience and nanotechnology are the study and application of extremely small things. Thus, this describes why the term nano is used to describe nanotechnology.

I hope this helps :)

Answer:

Nanotechnology is technology that is about a nanometer in size, or between 1 nm and 100 nm.

Explanation:

its the sample response on edge 2021

A mass of 1.15 kg of air at 111 kPa and 27 C is contained in a gas-tight, frictionless piston cylinder device. The air is now compressed to a final pressure of 0.84 MPa. During this process, heat is transferred from the air such that the temperature inside the cylinder remains constant. Calculate the work input (in kJ) during this process.

Answers

Answer:

Work input W = -200.39 KJ

Explanation:

From the question, we are given;

m = 1.15 kg

Constant temperature T1 = T2 = 27 + 273 = 300k

Since the temperature is constant, we can say that the process is isothermal

P1 = 111 KPa

P2 = 0.84 MPa = 0.84 * 1000 KPa = 840 KPa

Now what we want to calculate is W1-2

Mathematically, for isothermal process;

W1-2 = mRTlnP1/P2

where R can be obtained from table and it is equal to 0.287 KJ/kg.k

Hence;

W1-2 = (1.15)(0.287)(300)(ln 111/840)

W1-2 = 99.015 * -2.023871690525 = -200.39 KJ

Kindly note that the value of the work is negative because work is done on the system and not by the system

Experimenting with free fall, Mariana observes that her baseball takes 1.5 s to travel the last 30m before hitting the ground. From what height above the ground did Mariana drop the ball?

Answers

Answer:

37.8 m

Explanation:

At point 0, the ball is at height y₀.

At point 1, the ball is at height 30 m.

At point 2, the ball is at height 0 m.

Given:

y₁ = 30 m

y₂ = 0 m

v₀ = 0 m/s

a = -10 m/s²

t₂ − t₁ = 1.5 s

Find: y₀

Use constant acceleration equation.

y = y₀ + v₀ t + ½ at²

Evaluate at point 1.

y₁ = y₀ + v₀ t₁ + ½ at₁²

30 m = y₀ + (0 m/s) t₁ + ½ (-10 m/s²) t₁²

30 = y₀ − 5t₁²

Evaluate at point 2.

y₂ = y₀ + v₀ t₂ + ½ at₂²

0 m = y₀ + (0 m/s) t₂ + ½ (-10 m/s²) t₂²

0 = y₀ − 5t₂²

y₀ = 5t₂²

Substitute:

y₀ = 5 (1.5 + t₁)²

y₀ = 5 (2.25 + 3t₁ + t₁²)

y₀ = 11.25 + 15t₁ + 5t₁²

30 = 11.25 + 15t₁ + 5t₁² − 5t₁²

30 = 11.25 + 15t₁

t₁ = 1.25

30 = y₀ − 5t₁²

30 = y₀ − 5(1.25)²

y₀ ≈ 37.8

Is The force of friction always opposite to the motion? ​

Answers

Answer:

Friction force always acts tangent to the surface at points of contact. Friction force acts opposite to the direction of motion.

Explanation:

A sports car moving at constant velocity travels 120m in 5.0s. If it then brakes and comes to a stop in 4.0s,what is the magnitude of it's acceleration? ​

Answers

AnswerQUESTION①):

✔ First calculating the speed :

V = d(in m)/t(in s)

V = 120/5 V = 24 m/s

✔ You now know the average car's speed, is time it takes to stop it completely, so you can calculate its acceleration :

a = V/t

a = -24/4 a = 6 m/s² The car has an acceleration of 6 m/s².

Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel and Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.

Answers

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

[tex]W = F\cdot \Delta s[/tex]

Where:

[tex]W[/tex] - Work, measured in joules.

[tex]F[/tex] - Force exerted on the object, measured in newtons.

[tex]\Delta s[/tex] - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

[tex]W_{net} = W_{Joel} - W_{Jerry}[/tex]

[tex]W_{net} = F\cdot \Delta s - F\cdot \Delta s[/tex]

[tex]W_{net} = (F-F)\cdot \Delta s[/tex]

[tex]W_{net} = 0\cdot \Delta s[/tex]

[tex]W_{net} = 0\,J[/tex]

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

[tex]W_{net} = W_{Joel}[/tex]

[tex]W_{net} = F\cdot \Delta s[/tex]

Hence, the work done by Joel is greater than the work done by Jerry.

Salt compounds are commonly used to melt ice that forms on sidewalks in the winter. A common chemical that is used to melt sidewalk ice is calcium chloride, CaCl2(s). When calcium chloride dissolves into solution is releases thermal energy which aides in melting
the ice.

The molar mass of water is 18.02 g/mol

The thermal energy, in kilojoules (kJ) that must be released from the calcium chloride,
CaCl2(s), to melt 10.0 kg of ice, expressed in scientific notation is a.bc x 104 k).
46
55
The values of a, b, c, and d.

Answers

Answer:

The values of a, b, c and d are

a = 3, b = 3, c = 4 and d = 3

Explanation:

The quantity of heat needed to melt the ice is given by Q = mL where m = mass of ice and L = latent heat of fusion of ice = 334 kJ/kg. This quanity of heat is also the thermal energy needed to be released by the calcium chloride, CaCl₂

Now, the mass of ice = 10 kg. So,

Q = mL

Q = 10 kg × 334 kJ/kg

Q = 3340 kJ

In scientific notation,

Q = 3.34 × 10³ kJ

So the thermal energy needed to be released by the calcium chloride is 3.34 × 10³ kJ

Comparing Q = 3.34 × 10³ kJ with a.bc × [tex]10^{d}[/tex] kJ

So, a = 3, b = 3, c = 4 and d = 3

The values of a, b, c and d are

a = 3, b = 3, c = 4 and d = 3

A vat of nitrogen at its boiling point (-196 degrees C) absorbs 384000 J of heat. How much mass of nitrogen burns off? (Unit = kg)

Answers

Answer:

1.92 kg of nitrogen.

Explanation:

The following data were obtained from the question:

Heat absorbed (Q) = 384000 J

Note: Heat of vaporisation (ΔHv) of nitrogen = 5600 J/mol

Next, we shall determine the number of mole of nitrogen that absorbed 384000 J.

This is illustrated below:

Q = mol·ΔHv

384000 = mole of N2 x 5600

Divide both side by 5600

Mole of N2 = 384000/5600

Mole of N2 = 68.57 moles

Next, we shall convert 68.57 moles of nitrogen, N2 to grams.

This can be obtained as follow:

Molar mass of N2 = 2 x 14 = 28 g/mol.

Mole of N2 = 68.57 moles.

Mass of N2 =..?

Mole = mass /molar mass

68.57 = mass of N2 /28

Cross multiply

Mass of N2 = 68.57 x 28

Mass of N2 = 1919.96 g

Finally, we shall convert 1919.96 g to kilograms.

This can be achieved as shown below:

1000g = 1 kg

Therefore,

1919.96 g = 1919.96/1000 = 1.92 kg.

Therefore, 1.92 kg of nitrogen were burned off.

Answer:

Explanation:

i cheat on Acellus cause I dont care about school. If i did I would be going to public school... Im never gonna use this info in my life so I dont bother learning it.

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