Answer: [tex]1.089\times 10^5\ A[/tex]
Explanation:
Given
Charge discharged [tex]Q=9.7\C[/tex]
time taken [tex]t=8.9\times 10^{-5}\ s[/tex]
Current is given as rate of change of discharge i.e.
[tex]\Rightarrow I=\dfrac{Q}{t}\\\\\Rightarrow I=\dfrac{9.7}{8.9\times 10^{-5}}\\\\\Rightarrow I=1.089\times 10^5\ A[/tex]
Therefore, the average current is [tex]1.089\times 10^5\ A[/tex]
A 10.0kg ball is falls from a window 7.00m above the ground. What will be the velocity of the ball as it strikes the ground?
Answer:
Explanation:
To find out something's speed (or velocity) after a certain amount of time, you just multiply the acceleration of gravity by the amount of time since it was let go of. So you get: velocity = -9.81 m/s^2 * time, or V = gt.22
A Boy can raise a load of 200N up to a
height of 2.5m in 15 seconds. calculate his
power
Explanation:
f=mg
=200×10
=200N
Now,
work done=df
25×200
=500J
What nuclear reaction is shown in the equation below?
Answer:
nuclear fission!!!
The nuclear fission is taken place in the given reaction.
What is nuclear fission and how it was related to the given equation?Nuclear fission reaction is the process how the larger energy particles hit by a neutron and separated into lighter elements with some energy. The lighter elements can exhibit energy in the form of electromagnetic radiation and in the form of kinetic energy.
For an example, the most known nucleus is Uranium - 235. This Uranium - 235 has the half life period of 740 million years. The Uranium - 235 when bombarded with neutrons, this causes the U-235 nucleus to split, producing, on average, Barium-141, Krypton-91, and three neutrons.
The given reaction is thus a nuclear fission reaction.
Thus, Option A is the correct answer.
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The gravity of Earth is attracting a person towards the center with 500N of gravitational force. The person is exerting a reactionary force on the Earth with how much force?
Answer:
The force is being pulled my the gravity or it could be a third party thing like a black hole you feel me
Explanation:
What is the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m?
a) 24 m/s
b) 10 m/s
c) 30 m/s
d) 46 m/s
Answer:
a ) 24 m/s
Explanation:
Given,
Frequency ( f ) = 6 Hz
Wavelength ( λ ) = 4 m
To find : Speed ( v ) = ?
Formula : -
v = f x λ
v
= 4 x 6
= 24 m/s
Therefore, the speed of a wave that has a frequency of 6 Hz and a wavelength of 4 m
is 24 m/s.
find a vector length of 5m in the xy plane that is perpendicular to A=3i+6j+2k hint use dot product
Answer:
Explanation:
vector A =(3i^+4J^-2k^),
let the required vector is B = x i^ + y j^
sqrt (x2 + y2) = 5,
x2 + y2 = 25 ..............(1)
Since vector A and B are perpendicular to each other then,
A.B = 0
3x + 4 y = 0
y = -3x/4 ..............(2)
Solving these two equations we get x = 4 and y = -3;
hence vector B = 4 i^ -3 j^
spotlight on a boat is 2.5 m above the water, and the light strikes the water at a point that is 8.0 m horizontally displaced from the spotlight (see the drawing). The depth of the water is 4.0 m. Determine the distance d, which locates the point where the light strikes the bottom. Assume water has a refraction index of 1.333
Answer:
Explanation:
Let i be the angle of incidence and r be the angle of refraction .
From the figure
Tan ( 90 - i ) = 2.5 / 8
cot i = 2.5 / 8
Tan i = 8 / 2.5 = 3.2
i = 72.65°
From snell's law
sini / sin r = refractive index
sin 72.65 / sinr = 1.333
sin r = .9545 / 1.333
= .72
r = 46⁰
From the figure
Tan r = d / 4
Tan 46 = d /4
d = 4 x Tan 46
= 4 x 1.0355
=4.14 m .
gayle cooks a roast in her microwave oven. the klystron tube in the oven emits photons whose energy is 1.20 x 10^-3 ev. what are the wavelengths of these photons
Answer:
[tex]\lambda=1.03\times 10^{-3}\ m[/tex]
Explanation:
Given that,
The energy of the microwave oven is [tex]1.2\times 10^{-3}\ eV[/tex].
We need to find the wavelength of these photons.
[tex]1.2\times 10^{-3}\ eV=1.2\times 10^{-3}\times 1.6\times 10^{-19}\\\\=1.92\times 10^{-22}\ J[/tex]
The energy of a wave is given by :
[tex]E=\dfrac{hc}{\lambda}\\\\\lambda=\dfrac{hc}{E}[/tex]
Put all the values,
[tex]\lambda=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{1.92\times 10^{-22}}\\\\\lambda=1.03\times 10^{-3}\ m[/tex]
So, the wavelength of these photon is [tex]1.03\times 10^{-3}\ m[/tex].
Which of these statements accurately describes the
relationship between the wavelength and frequency of
a wave?
A)
If wavelength increases, frequency increases.
B)
If frequency decreases, wavelength increases
Did ya
C)
If frequency remains constant,
wavelength increases.
Teach
D)
If wavelength remains constant,
frequency increases.
Answer:
(B) If frequency decreases wavelength increases
Yellow-green light has a wavelength of 560 nm. What is its frequency?
Answer:
The frequency is 5.4 × 10^14Hz
Explanation:
The frequency of yellow-green light with a wavelength of 560 nm is approximately 5.4 x 10¹⁴ Hz.
What is the frequency of light?The frequency of yellow-green light with a wavelength of 560 nm can be calculated using the formula:
frequency = speed of light/wavelength
Where the speed of light is approximately 3.0 x 10⁸ meters per second.
First, we need to convert the wavelength from nanometers to meters by dividing by 10⁹:
560 nm = 560 x 10⁻⁹ m
Then, we can plug in the values and calculate the frequency:
frequency = (3.0 x 10⁸ m/s) / (560 x 10⁻⁹ m)
frequency ≈ 5.4 x 10¹⁴ Hz
Therefore, yellow-green light with a wavelength of 560 nm has a frequency of approximately 5.4 x 1014 Hz.
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Particle A has less mass than particle B. Both are pushed forward across a frictionless surface by equals forces for 1 s. Both start from rest.
a. Compare the amount of work done on each particle. That is, is the work done on A greater thane, less than, or equal to the work done on B? Explain.
b. Compare the impulses delivered to particles A and B. Explain.
c. Compare the final speeds of particles A and B. Explain.
An Particle a has Weston practical.
What is Friction?
The resistance to motion of one object moving in relation to another is known as friction. It is not regarded as a fundamental force like gravity or electromagnetic, according to the International Journal of Parallel, Emergent and Distributed Systems(opens in new tab).
According to the book Soil Mechanics(opens in new tab), scientists started putting together the laws governing friction in the 1400s.
However, because the interactions are so complex, characterizing the force of friction in various circumstances typically requires experiments and can't be derived from equations or laws alone. There are numerous exceptions to every frictional general rule.
Therefore, An Particle a has Weston practical.
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A radio antenna broadcasts a 1.0 MHz radio wave with 20.0 kW of power. Assume that the radiation is emitted uniformly in all directions.
1) What is the wave's intensity 30 km from the antenna
2) What is the electric field amplitude at this distance?
Answer:
1) [tex]I=1.8*10^{-6}\: W/m^{2}[/tex]
2) [tex]E=0.037 \: V/m[/tex]
Explanation:
1)
The intensity equation is given by:
[tex]I=\frac{P}{4\pi r^{2}}[/tex]
Where:
P is the power of the radio waver is the distance from the source[tex]I=\frac{20000}{4\pi (30000)^{2}}[/tex]
[tex]I=1.8*10^{-6}\: W/m^{2}[/tex]
2)
Now, the intensity and the electric field are related as:
[tex] I=0.5c\epsilon_{0}E^{2}[/tex]
Here:
c is the speed of lightε₀ is the electric permittivityE is the electric fieldWe need to solve it for E.
[tex]E= \sqrt{\frac{2I}{c\epsilon_{0}}}[/tex]
[tex]E= \sqrt{\frac{2(1.8*10^{-6})}{(3*10^{8})(8.85*10^{-12})}}[/tex]
[tex]E=0.037 \: V/m[/tex]
I hope it helps you!
A 76 kg boater, initially at rest in a stationary 45 kg boat, steps out of the boat and onto the dock. If the
boater moves out of the boat with a velocity of 2.5 m/s to the right, what is the final velocity of the boat?
The final velocity of the boat is 4.22 m/s in opposite direction to the boater.
Final velocity of the boatThe final velocity of the boat is determined by applying the principle of conservation of linear momentum as follows;
Let the initial velocity of the boater and the boat = v
[tex]m_1 u_1 + m_2 u_2 = v(m_1 + m_2)\\\\76(2.5) + 45u_2 = 0(76 + 45)\\\\190 + 45u_2=0\\\\45u_2 = -190\\\\u_2 = \frac{-190}{45} \\\\u_2 = -4.22 \ m/s[/tex]
Thus, the final velocity of the boat is 4.22 m/s in opposite direction to the boater.
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2 ways in which a weather satellite can orbit the earth
Answer:
The two most common types of orbit are "geostationary" and "polar."
Answer:2 ways in which a weather satellite can orbit the earth
Explanation:
A magnetic field points up through a loop where the area can be increased by dragging the side of the loop along the rails that make up 2 of the other sides. If you are looking down on the loop (magnetic field out of the page from your perspective) what is the direction of the induced current as the loop increases in area
Answer:
Explanation:
The magnetic field is pointing upwards , so magnetic flux is upwards . Due to increase in area , magnetic flux in upward direction will increase . Hence according to Lenz's law , induced current will be such that it will try to counter this increase . It is possible if current is in clockwise direction . Due to it magnetic field will be induced in downward direction thus reducing the total magnetic flux.
Hence direction of induced current will be clockwise direction in the loop as shown in the image enclosed .
Two parallel plates are charged
with 3.08*10^-9 C of charge.
What must the area of the plates
be to create an electric field of
9220 N/C?
(Unit = m^2)
Answer:
0.0377
Explanation:
Trust brother
Answer:
0.0377
Explanation:
8. Aunt Barbara sets a full 2.0 kg milk carton on the kitchen table for breakfast. After the family has eaten, she pours herself a cup of coffee, sits down, and picks up the milk carton, only to find that the 20 N force she exerts accelerates the carton upward at a surprising 50 m/s². Calculate and describe why the milk carton accelerates up faster than Aunt Barbara expect
The proper time between two events is measured by clocks at rest in a reference frame in which the two events: The proper time between two events is measured by clocks at rest in a reference frame in which the two events:
a. are separated by the distance a light signal can travel during the time interval
b. occur at the same time
c. satisfy none of the above
d. occur in Nashville occur at the same coordinates
The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur in Nashville occur at the same coordinates. So, option d.
What is meant by frame of reference ?The perspective from which you perceive and measure things is known as a reference frame. It's applied to describe how an object is moving or where it is.
Here,
Depending on the frame of reference, the time elapsed between two occurrences may vary, according to the Theory of Special Relativity.
The duration between two events occurring in the rest frame, as measured from a reference frame in motion relative to the rest frame, will always be longer than the correct time. Time dilation is a phenomenon that develops in accordance with the relativity of space and time.
A single clock that is present for both occurrences can be used to determine the right time difference between them.
The appropriate time between two events is the amount of time that elapses within a frame in which the two events take place at the same location, to put it another way.
Hence,
The proper time between two events is measured by clocks at rest in a reference frame in which the two events occur in Nashville occur at the same coordinates. So, option d.
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Two parallel rods are each 0.69 m in length. They are attached at their centers to a spring that is initially neither stretched nor compressed. The spring has a spring constant of 130 N/m. When 1200 A of current is in each rod in the same direction, the spring is observed to be compressed by 3.0 cm. Treat the rods as long, straight wires and find the separation between them when the current is present.
Answer:
Explanation:
Let the separation required be d .
Force between rod = 10⁻⁷ x 2 I₁ I₂ L / d
where I₁ and I₂ are current in them , d is distance of separation and L is length of wire .
Force between rod = 10⁻⁷ x 2 x 1200 x 1200 x .69 / d
= .1987 /d
Restoring Force by spring = k x where k is force constant and x is compression .
= 130 x .03
= 3.9 N
For balancing
Restoring Force by spring = Force between rod
.1987 /d = 3.9
d = .1987 /3.9
= .0509 m
= 5.09 cm .
Light from a laser strikes a diffraction grating that has 5 308 grooves per centimeter. The central and first-order principal maxima are separated by 0.488 m on a wall 1.88 m from the grating. Determine the wavelength of the laser light. (In this problem, assume that the light is incident normally on the gratings.) nm
Solution :
Given :
The angle of the first maximum with the center is given by :
[tex]$a=\tan^{-1}\left(\frac{0.488}{1.88}\right)$[/tex]
= 14.5°
The grating distance can be calculated as :
[tex]$d=\frac{1 \ cm}{5308 \text{ slits}}$[/tex]
= [tex]$1.88 \times 10^{-4} \ m$[/tex]
When the principal maxima yields at y = 0.488 m and the length from the wall 1.88 m. Thus the equation of the wavelength is :
[tex]$\lambda = g \times \frac{\sin a}{n}$[/tex] , where n = 1
[tex]$=1.88 \times 10^{-4} \times \sin (14.5)$[/tex]
[tex]$=4.70 \times 10^{-5} \ m$[/tex]
At a soft drink bottling plant, a horizontal section of pipe carrying citric acid in liquid form goes from a cross-sectional area of 8.00 cm2, fluid flow speed of 320 cm/s, and pressure of 1.40 105 Pa to a section of pipe with a cross-sectional area of 3.70 cm2. The density of the citric acid is 1660 kg/m3. For the section of smaller pipe, determine the liquid flow speed and the liquid pressure.
(a) the liquid flow speed m/s
(b) the liquid pressure Pa
Answer:
a) [tex]V_2=8m/s[/tex]
b) [tex]P_2=9.54*10^4 Pa[/tex]
Explanation
From the question we are told that:
Initial Area of pipe [tex]A_1=8.00 cm^2[/tex]
Initial Fluid flow speed [tex]r_1 =320 cm/s,\approx 320*10^{-2}[/tex]
Initial Pressure of [tex]\rho_1 =1.40*10^5 Pa[/tex]
Final area of pipe [tex]A_2 =3.70 *10^{-2} cm^2[/tex]
Density of acid [tex]\rho=1660kg/m^3[/tex]
a)
Generally the equation for continuity is mathematically given by
[tex]A_1V_1=A_2V_2\\\\V_2=\frac{A_1*V_1}{A_2}[/tex]
Since volume is directly proportional to rate of flow
[tex]V_2=\frac{8*320}{3.20} *10^{-2}[/tex]
[tex]V_2=8m/s[/tex]
b)
Generally the Bernoulli's equation is mathematically given by
[tex]p_1+\frac{1}{2}\rho v_1^2+\rho gh_1=P_2+\frac{1}{2}\rho v_2^2+\rho gh_2\\\\with\ h_1=h_2\\\\p_1+\frac{1}{2}\rho v_1^2=P_2+\frac{1}{2}\rho v_2^2[/tex]
Therefore
[tex]P_2=P_1+\frac{1}{2}\rho(v_1^2-V_2^2)\\\\P_2=(1.40*10^5)+\frac{1}{2}(1660)(v_1^2-V_2^2)[/tex]
[tex]P_2=9.54*10^4 Pa[/tex]
Who discovered the laws of planter motion ?
Answer: Johannes Kepler
Explanation:
Kepler discovered that Mars' orbit was an ellipsoid using the exact data that Tycho had obtained.
Calculate the speed of a gamma ray with a frequency of 3.0 x 10^19 Hz and a wavelength of 1.0 x 10^-11 m.
A.) 3.00 x 10^19 m/s
B.) 9.00 x 10^27 m/s
C.) 3.00 x 10^8 m/s
D.) 3.00 x 10^11 m/s
Answer:
Speed of gamma rays = 3 x 10⁸ m/s
Explanation:
Given:
Frequency of gamma ray = 3 x 10¹⁹ Hz
Wavelength of gamma rays = 1 x 10⁻¹¹ meter
Find:
Speed of gamma rays
Computation:
Velocity = Frequency x wavelength
Speed of gamma rays = Frequency of gamma ray x Wavelength of gamma rays
Speed of gamma rays = [3 x 10¹⁹][1 x 10⁻¹¹]
Speed of gamma rays = 3 x [10¹⁹⁻¹¹]
Speed of gamma rays = 3 x [10⁸]
Speed of gamma rays = 3 x 10⁸ m/s
A 3 kg block is attached to a vertical spring. Initially, you exert a 50 N downwards force on the block, holding it in place, at rest. You let go. Find the instantaneous acceleration of the block immediately after you let go. What is the direction of the acceleration
As you were holding the block down and in place, the spring exerted an upward force that balanced the downward push by your hand and its own weight. So this restoring force has a magnitude of R such that
R - 50 N - (3 kg) g = 0 => R = 79.4 N
As soon as you remove your hand, the block has acceleration a such that, by Newton's second law,
R - (3 kg) g = (3 kg) a => a = (79.4 N - (3 kg) g) / (3 kg) ≈ 16.7 m/s^2
pointing upward.
im back and need help
Always here to help. Bring it!!!
if a box experiences three 400 n forces to the left and three different 410 n forces to the right which way does it go
Answer:
Explanation:
will accelerate to the right, because three different 410 N is greater than three different 400 N
A shaving or makeup mirror is designed to magnify your face by a factor of 1.40 when your face is placed 20.0cm in front of it
a) What type of mirror is it?
b) Describe the type of image that it makes of your face.
c) Calculate the required radius of curvature for the mirror.
Answer:
(a) convex mirror
(b) virtual and magnified
(c) 23.3 cm
Explanation:
The having mirror is convex mirror.
distance of object, u = - 20 cm
magnification, m = 1.4
(a) As the image is magnified and virtual , so the mirror is convex in nature.
(b) The image is virtual and magnified.
(c) Let the distance of image is v.
Use the formula of magnification.
[tex]m =-\frac{v}{u}\\1.4=-\frac{v}{-20}\\v =28 cm[/tex]
Use the mirror equation, let the focal length is f.
[tex]\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\\frac{1}{f}=\frac{1}{28}+\frac{1}{20}\\\frac{1}{f}=\frac{28+20}{560}\\f=11.67cm[/tex]
Radius of curvature, R = 2 f = 2 x 11.67 = 23.3 cm
A mass is hung from a vertical spring and allowed to come to rest or its equilibrium position. The mass is then pulled down an additional 0.5 m and released. As the mass oscillates, it completes one full cycle in 5.0 s . Using the given values, correctly identify the mass's amplitude, full range of vertical motion, frequency, and period. The full range of vertical motion is the distance between the maximum and minimum heights of the mass.
The amplitude of the spring is m.
The full range of vertical motion is m.
The frequency of the spring is Hz.
The period of the spring is s.
Explanation:
Given that,
The mass pulled down an additional 0.5 m and released.
The period of oscillation is 5 s
(a) The amplitude of the spring is equal to the maximum displacement i.e. 0.5 m.
(b) The full range of the vertical motion is (2×0.5) = 1 m.
(c) The frequency of the spring,
[tex]f=\dfrac{1}{T}\\\\=\dfrac{1}{5}\\\\=0.2\ Hz[/tex]
(d) The period of the spring is 5 seconds.
If two adjacent media have the same index of refraction, n, can you observe the phenomena of reflection or refraction?
If two adjacent media have the same index of refraction, n, then the phenomenon is refraction.
What is refraction?Assuming two materials have the very same refractive index, the light goes through with next to no (or negligible) dissipating or refraction. The light voyages straight since it can't recognize any distinction between the two materials, thus the speed of traveling with as little luggage as possible doesn't change (twist).
Examples are eyes and prism.
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Two car collide in an intersection. The speed limit in that zone is 30 mph. The car (mass of 1250 kg) was going 17.4 m/s (38.9). The truck (2020 kg) t-boned the car in the middle of the intersection. The car was slowed down to only 6.7 m/s. The truck after colliding with the car was going 10.3 m/s. How fast did the truck go into the intersection?
Answer:
u₂ = 3.7 m/s
Explanation:
Here, we use the law of conservation of momentum, as follows:
[tex]m_1u_1+m_2u_2=m_1v_1+m_2v_2\\[/tex]
where,
m₁ = mass of the car = 1250 kg
m₂ = mass of the truck = 2020 kg
u₁ = initial speed of the car before collision = 17.4 m/s
u₂ = initial speed of the tuck before collision = ?
v₁ = final speed of the car after collision = 6.7 m/s
v₂ = final speed of the truck after collision = 10.3 m/s
Therefore,
[tex](1250\ kg)(17.4\ m/s)+(2020\ kg)(u_2)=(1250\ kg)(6.7\ m/s)+(2020\ kg)(10.3\ m/s)\\\\(2020\ kg)(u_2) = 8375\ N.s + 20806\ N.s - 21750\ N.s\\\\u_2=\frac{7431\ N.s}{2020\ kg}[/tex]
u₂ = 3.7 m/s