A box of Jell-O costs $0.50, and makes 2 cups. How much would it cost to fill a swimming pool 4 feet deep, 8 feet wide, and 12 feet long with Jell-O? (1 cubic foot is about 7.5 gallons)

Answers

Answer 1

Answer:

$11,520

Step-by-step explanation:

4 * 8 * 12 = 384 cu ft.

384 * 7.5 = 2880 gallons

There are 16 cups in a gallon

2880 * 16 = 46,080 cups

46,080/2 * .50 = $11,520


Related Questions

Which of the following best describes the dashed line shown in the regular
octagon below?

A. Altitude
B. Base
C. Apothem
D. Leg

Answers

Answer: Apothem

Step-by-step explanation: Half of an octagon is called an apothem

The dashed line shown in the regular octagon is called an apothem.

What is an octagon?

Octagon is an eight-sided two-dimensional geometrical figure. An octagon consists of 8 interior angles and 8 exterior angles. The sum of the interior angles of an octagon is 1080°, and the sum of its exterior angles is 360°.

Given is a regular octagon, we need to determine the asked part of the given octagon is called what,

So, the part asked is called the apothem.

A line from the center of a regular polygon at right angles to any of its sides is called an apothem.

Hence, the dashed line shown in the regular octagon is called an apothem.

Learn more about octagon, click;

https://brainly.com/question/30327829

#SPJ7

Apply the distributive property to factor out the greatest common factor of all three terms. {10a - 25 + 5b} =10a−25+5b =

Answers

Answer:

5(2a -5 + b)

Step-by-step explanation:

(10a - 25 + 5b) = 5( 2a - 5 + b)

5(b +  2a  - 5) = 5(2a - 5 + b)

Answer:

5(2a -5 + b)

Step-by-step explanation:

What is the measure of angle z in this figure?



Enter your answer in the box.

z =
°

Two intersection lines. All four angles formed by the intersecting lines are labeled. Clockwise, the angles are labeled 124 degrees, x degrees, y degrees, and z degrees.

Answers

Answer:

z= 56°

hope u understood it...

Answer:

Z=56

Step-by-step explanation:

Because i said so

Find the square root of 8-2√5​

Answers

Answer:

1.88

Step-by-step explanation:

8-2√5=3.527864045

square root of 3.527864045=1.87826090972

the question will probably want it to 2d.p (decimal places) which means the answer would be 1.88

Answer:

The square root of 8 - 2√5 is

[tex] \sqrt{4 + \sqrt{11} } \: - \sqrt{4 - \sqrt{11} } [/tex]

Step-by-step explanation:

To find the square root

8-2√5 must be in the form √a - √b where a > b

√ 8 - 2√5 = √a - √b

Square both sides

8 - 2√5 = (√a - √b)²

That's

8 - 2√5 = (a + b) - 2√ab

Since the two surd expressions are equal we can equate them

That's

8 = a + b ........ 1

a = 8 - b ........ 2

2√5 = 2√ab

Simplify

Divide both sides by 2

√5 = √ab

square both sides

We have

5 = ab ....... 3

Substitute a = 8 - b into equation 3

5 = ( 8 - b)b

5 = 8b - b²

b² - 8b + 5 = 0

After solving

b = 4 + √ 11 or 4 - √ 1

Since b is less than a

b = 4 - √11

a = 4 + √11

So the square root of 8 - 2√5 is

[tex] \sqrt{4 + \sqrt{11} } \: - \sqrt{4 - \sqrt{11} } [/tex]

Hope this helps you.

Can somebody help me with this math question?

Answers

Answer:

  GJ and HI

Step-by-step explanation:

No line through K is parallel to any other in the diagram. That eliminates the last three choices.

Opposite sides of the square base are parallel, so GJ║HI.

solve and find the value of (1.7)^2​

Answers

Answer:

2.89

Step-by-step explanation:

just do 1.7×1.7=2.89

help with this I don't know how to solve.

Answers

Answer:

sinR = 0.7184

Step-by-step explanation:

Pythagorean Theorem: a² + b² = c²

sin∅ = opposite/hypotenuse

Step 1: Find missing leg length

16² + b² = 23²

b² = 23² - 16²

b = √273

Step 2: Find sinR

sinR = √273/23

sinR = 0.718379

The following observations were made on fracture toughness of a base plate of 18% nickel maraging steel (in ksi √in, given in increasing order)].
68.6 71.9 72.6 73.1 73.3 73.5 75.5 75.7 75.8 76.1 76.2
76.2 77.0 77.9 78.1 79.6 79.8 79.9 80.1 82.2 83.7 93.4
Calculate a 90% CI for the standard deviation of the fracture toughness distribution. (Give answer accurate to 2 decimal places.)

Answers

Answer:

A 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Step-by-step explanation:

We are given the following observations that were made on fracture toughness of a base plate of 18% nickel maraging steel below;

68.6, 71.9, 72.6, 73.1, 73.3, 73.5, 75.5, 75.7, 75.8, 76.1, 76.2,  76.2, 77.0, 77.9, 78.1, 79.6, 79.8, 79.9, 80.1, 82.2, 83.7, 93.4.

Firstly, the pivotal quantity for finding the confidence interval for the standard deviation is given by;

                             P.Q.  =  [tex]\frac{(n-1) \times s^{2} }{\sigma^{2} }[/tex]  ~ [tex]\chi^{2} __n_-_1[/tex]

where, s = sample standard deviation = [tex]\sqrt{\frac{\sum (X - \bar X^{2}) }{n-1} }[/tex] = 5.063

            [tex]\sigma[/tex] = population standard deviation

            n = sample of observations = 22

Here for constructing a 90% confidence interval we have used One-sample chi-square test statistics.

So, 90% confidence interval for the population standard deviation, [tex]\sigma[/tex] is ;

P(11.59 < [tex]\chi^{2}__2_1[/tex] < 32.67) = 0.90  {As the critical value of chi at 21 degrees  

                                                  of freedom are 11.59 & 32.67}  

P(11.59 < [tex]\frac{(n-1) \times s^{2} }{\sigma^{2} }[/tex] < 32.67) = 0.90

P( [tex]\frac{ 11.59}{(n-1) \times s^{2}}[/tex] < [tex]\frac{1}{\sigma^{2} }[/tex] < [tex]\frac{ 32.67}{(n-1) \times s^{2}}[/tex] ) = 0.90

P( [tex]\frac{(n-1) \times s^{2} }{32.67 }[/tex] < [tex]\sigma^{2}[/tex] < [tex]\frac{(n-1) \times s^{2} }{11.59 }[/tex] ) = 0.90

90% confidence interval for [tex]\sigma^{2}[/tex] = [ [tex]\frac{(n-1) \times s^{2} }{32.67 }[/tex] , [tex]\frac{(n-1) \times s^{2} }{11.59 }[/tex] ]

                                     = [ [tex]\frac{21 \times 5.063^{2} }{32.67 }[/tex] , [tex]\frac{21 \times 5.063^{2} }{11.59 }[/tex] ]

                                     = [16.48 , 46.45]

90% confidence interval for [tex]\sigma[/tex] = [[tex]\sqrt{16.48}[/tex] , [tex]\sqrt{46.45}[/tex] ]

                                                 = [4.06 , 6.82]

Therefore, a 90% confidence interval for the standard deviation of the fracture toughness distribution is [4.06, 6.82].

Determine the product of (4.2 × 10–1) ⋅ (5.7 × 10–1). Write your answer in scientific notation. Question 7 options: A) 239.4 × 10–1 B) 2.394 × 10–1 C) 23.94 × 10–1 D) 239.4 × 10–2

Answers

Answer:

Its B

Step-by-step explanation:

B is the proper answer in scientific notation and scientific notation is only one decimal placed

The most common form of scientific notation inserts a decimal point after the first significant digit

What is the area of the sector shown in the diagram below?

Answers

Answer:

(B ) .  34.2cm^2

Step-by-step explanation:

[tex]A = \frac{\alpha }{360} \times \pi r^2\\\alpha=20 \\r = 14\\\\A =\frac{20}{360} \times 22/7\times 14^2\\A = 1/18 \times4312/7\\A =34.2 cm^2[/tex]

Find the missing side or angle in each problem. Show your work
(d)
7m
5.8cm
11:1m
62
10m
4.2cm

Answers

Answer:

d. t ≈ 5m

e. y ≈ 44°

f. x = 36°

Step-by-step explanation:

We'd apply the trigonometry function to solve for all missing sides and angles as follows:

d. Adjacent length = t

Hypothenuse = 11.1m

θ = 62°

Use Cos θ = adjacent/hypothenuse

Cos(62) = t/11.1

Multiply both sides by 11.1

11.1*cos(62) = t

11.1*0.4695 = t

t = 5.21 ≈ 5 m

e. Opposite = 7m

Hypotenuse = 10m

θ = y°

Use sine θ = opposite/hypotenuse

Thus,

sine θ = 7/10

sine θ = 0.7

θ = sin-¹(0.7) = 44.4

y ≈ 44° (nearest whole number)

f. Opposite = 4.2cm

Adjacent = 5.8cm

θ = x°

Use tan θ = opposite/adjacent

tan θ = 4.2/5.8

tan θ = 0.7241

θ = tan-¹(0.7241) = 35.91

θ = x ≈ 36°

I NEED HELP PLEASE, THANKS! :)
The senior class is having a fundraiser to help pay for the senior trip. Selling a box of chocolates yields a profit of $2.45, while selling a box of cookies yields a profit of $2.70. The demand for cookies is at least twice that of chocolates, but the amount of cookies produced must be no more than 550 boxes plus 3 times the number of chocolates produced. Assuming that the senior class can sell every box that they order, how many boxes of each should they order to maximize profit if they cannot order more than 1950 boxes combined? (Show work)

Answers

Answer:

  1600 boxes of cookies; 350 boxes of chocolates

Step-by-step explanation:

Let x and y represent the numbers of boxes of cookies and chocolates to order, respectively. The constraints seem to be ...

x ≥ 2yx ≤ 550 +3yx + y ≤ 1950

The objective function we want to maximize is ...

  p = 2.70x +2.45y

_____

Looking at the problem, we see that cookies yield the most profit, so we'd like to maximize the boxes of cookies sold within the allowed limits.

There are two limits on x:

  x ≤ 550 +3y

  x ≤ 1950 -y

x will be as large as it can be if it bumps up against these limits simultaneously:

  550 +3y = 1950 -y

  4y = 1400 . . . . . . . . . add y-550

  y = 350

  x = 1950 -350 = 1600

Profit will be maximized for an order of 1600 boxes of cookies and 350 boxes of chocolates.

_____

The "feasible region" of the solution is where the three constraint inequalities overlap. It is a quadrilateral with vertices at (0, 0), (550, 0), (1300, 650), and (1600, 350). We can reject the ones with x or y being 0. Per our analysis above, the solution of interest is (x, y) = (1600, 350), since it maximizes x.

The usual protocol for solving a linear programming model like this is to evaluate the objective function at each of the vertices. With a little thought about the problem, we have saved some evaluation effort.

Of the six members in the Spirit of Woodstock rock band, four can play guitar. There are three who can play keyboards. All of the singers play guitar, and two of the guitarists also play keyboards. Two members do all three. One guitarist doesn’t sing. How many members sing but do not play keyboards?

Answers

Answer:

1 can sing but cannot play keyboard.

Step-by-step explanation:

There are six members in the rock band. We need to identify how many person can sing, play guitar and play keyboard. To identify this we will find out number of member for each activity,

Total 6 members

4 can play guitar

3 can pay keyboard

All singers play guitar but one guitarist cannot sing.

There will be 1 singer who cannot play keyboard.

can someone help asAP!

Answers

Answer:

Option 3

Step-by-step explanation:

Interior angles of a triangle add up to 180 degrees. So to find a missing angle we just need to subtract the rest of the angles from 180.

So,

[tex]\theta = 180-(\alpha +\beta )[/tex]

what is tan 30*? picture below

Answers

Answer:

C

Step-by-step explanation:

Tan = opposite / adjacent

= 1 / √3

= √3 / 3

Answer:

C.

Step-by-step explanation:

Tangent= opposite over adjacent.

Tangent = 1/√3

Can you help me please solve

Answers

Answer:

(-0.5, 0)

Step-by-step explanation:

Coordinates of endpoints of segment are:

A= (-2, 1)

B= (1, - 1)

By mid-point formula:

The midpoint of [tex] \overline{AB} [/tex]

[tex] = \bigg(\frac{ - 2 + 1}{2}, \: \: \frac{1 + ( - 1)}{2} \bigg) \\ \\ = \bigg(\frac{ - 1}{2}, \: \: \frac{0}{2} \bigg)\\ \\ = \bigg(\frac{ - 1}{2}, \: \: 0 \bigg)\\ \\ = ( - 0.5, \: \: 0 )[/tex]

Part A: How many positive integers are there between 42 and 97 inclusive? I do not understand how the formula works! Part B: There is a line whose length is 200 feet. If points are placed every 2 feet starting from one end, how many points are on the line?

Answers

Answer:

Step-by-step explanation:

To find the answer to Part A we can do (97 - 42) + 1 = 56. The reason we do + 1 is because 97 - 42 is just counting the numbers in between 42 and 97 but it leaves out 42 and since it's inclusive we need to include 42.

Part B: We can do (200 / 2) - 1 = 99. The reason we do - 1 is because 200 / 2 includes the endpoint of the line but since we don't want to include the endpoint of the line we do - 1.

Answer:

Part A = 56 Integers

Part B = 99 Points

Step-by-step explanation:

Part A ~ Since it's inclusive, at the end we must put n + 1 -->

97 - 42 = 55 => 55 = n => 56 Integers

Part B ~ n - 1  Since it is exclusive. so, =>

200/2 = 100, 100 = n (n-1) => 99 Points

Hope this helps!

Derive R = v0 2 sin2θ0 / g for the range of a projectile on level ground by finding the time t at which y becomes zero and substituting this value of t into the expression for x − x0, noting that R = x − x0.

Answers

Answer:

R = V₀² Sin 2θ₀/g

Step-by-step explanation:

Consider a projectile motion with following properties:

R = range of projectile

V₀ = Launch Velocity of Projectile

θ₀ = Launch Angle

V₀ₓ = V₀ Cos θ₀ =  x - component of launch velocity

V₀y = V₀ Sin θ₀ =  y - component of launch velocity

t = time to reach maximum height

T = 2t = total time of flight

First we use 1st equation of motion in vertical direction to find value of "t":

Vfy = V₀y + gt

where,

Vfy= final vertical velocity at highest point = 0 m/s

g = -g (for upward motion)

V₀y = V₀ Sin θ₀

Therefore,

0 = V₀ Sin θ₀ - gt

t = V₀ Sin θ₀/g

Now the total time of flight will be:

T = 2t = 2 V₀ Sin θ₀/g

Since, the horizontal velocity of the projectile remains uniform throughout the motion. Therefore:

x - x₀ = V₀ₓ T

where,

x - x₀ = R = Range of Projectile

V₀ₓ = V₀ Cos θ₀

Therefore,

R = (V₀ Cos θ₀)(2 V₀ Sin θ₀/g)

R = V₀² (2 Sin θ₀Cos θ₀)/g

since, 2 Sin θ Cos θ = Sin 2θ

Therefore,

R = V₀² Sin 2θ₀/g

Solve the system by the method of elimination.

Answers

Answer:

no solution

Step-by-step explanation:

4x+3y = 6

8x + 6y = 5

Multiply the first equation by -2

-2(4x+3y) = 6*-2

-8x -6y = -12

Add this to the second equation

-8x-6y = -12

8x + 6y = 5

---------------------

0x + 0y = -7

0 = -7

Since this is never true there is no solution

Answer:

X = 8/3, y= -14/9

Step-by-step explanation:

using elimination method:

subtract equation 1 from equation 2

8x-4x + 6y-3y = 5-6

4x+3y= -1

4x= -1-3y

divide both sides by 4

x = -1-3y÷4

substitute x = -1-3y/4 in equation 2

8(-1-3y)/4 +6y = 5

-8-24y/4+ 6y =5

-8-24y+6y/4 =5

-8-18y/4 = 5

Cross multy

-8-18y × 1 = 4×5

-8-18y = 20

collect like terms

-18y = 20+8

-18y = 28

divide both sides by-18

y = 28/-8

y = -14/9

put y = -14/9 in equation 1

4x+3(-14/9) = 6

4x-42/9 = 6

42/9 = 14/3

so, 4x=6+14/3

LCM =3

4x = 18+14/3

4x= 32/3

cross multiply

4x×3 = 32

12x = 32

divide both sides by 12

12x/12= 32/12

x = 8/3

so, x = 8/3, y = -14/9

check:

first equation:

4(8/3) + 3(-14/9)

32/3 - 14/3( 3 cancels 9 rem 3)

LCM= 3

32 - 14/3

= 18/3

= 6

a rectangular playing field measure 350 by 200m if kolade stroll 11 times around what is the answer in km​

Answers

Answer:

12.1 km

Step-by-step explanation:

350 * 2 = 700

200 * 2 = 400

700 + 400 = 1100

1100 * 11 = 12100

12100 / 1000 = 12.1

12.1 km

You are testing the claim that the proportion of men who own cats is significantly different than the proportion of women who own cats. You sample 80 men, and 55% own cats. You sample 100 women, and 30% own cats. Find the test statistic, rounded to two decimal places. 41.11Incorrect

Answers

Answer:

Step-by-step explanation:

This is a test of 2 population proportions. Let 1 and 2 be the subscript for the men and women who own cats respectively. The population proportion of men and women who own cats would be p1 and p2 respectively.

p1 - p2 = difference in the proportion of men and women who own cats.

The null hypothesis is

H0 : p1 = p2

p1 - p2 = 0

The alternative hypothesis is

Ha : p1 ≠ p2

p1 - p2 ≠ 0

it is a two tailed test

Sample proportion = x/n

Where

x represents number of success

n represents number of samples

For men

n1 = 80

p1 = 55/100 = 0.55

x1 = p1n1 = 0.55 × 80 = 44

For women,

n2 = 100

p2 = 30/100 = 0.3

x2 = p2n2 = 0.3 × 100 = 30

The pooled proportion, pc is

pc = (x1 + x2)/(n1 + n2)

pc = (44 + 30)/(80 + 100) = 0.41

1 - pc = 1 - 0.41 = 0.59

z = (p1 - p2)/√pc(1 - pc)(1/n1 + 1/n2)

z = (0.55 - 0.3)/√(0.41)(0.59)(1/80 + 1/100) = 3.39

Test statistic = 3.39

If possible, find AB, BA, and A2.

Answers

First product:

[tex]AB=\begin{bmatrix}3&-3\\-7&0\\2&4\end{bmatrix}\begin{bmatrix}1&0\\0&1\end{bmatrix}=\begin{bmatrix}\begin{bmatrix}3&-3\end{bmatrix}\begin{bmatrix}1\\0\end{bmatrix}&\begin{bmatrix}3&-3\end{bmatrix}\begin{bmatrix}0\\1\end{bmatrix}\\\begin{bmatrix}-7&0\end{bmatrix}\begin{bmatrix}1\\0\end{bmatrix}&\begin{bmatrix}-7&0\end{bmatrix}\begin{bmatrix}0\\1\end{bmatrix}\\\begin{bmatrix}2&4\end{bmatrix}\begin{bmatrix}1\\0\end{bmatrix}&\begin{bmatrix}2&4\end{bmatrix}\begin{bmatrix}0\\1\end{bmatrix}\end{bmatrix}=\begin{bmatrix}3&-3\\-7&0\\2&4\end{bmatrix}[/tex]

Notice how multiplying A by B produces A again, because B is an identity matrix.

The second product cannot be carried out because A has more columns that B has rows.

The third product also cannot be computed because A is not a square matrix.

confused on my math work.

Answers

Answer:

The right answer is the last option, 12,12.

Step-by-step explanation:

[tex]GI^2=FI*IH\\ GI^2 = 7*21\\ GI = \sqrt{147}[/tex]

[tex]\sqrt{147} = 12,124... = 12,12[/tex]

The diameter, D, of a sphere is 15.2m. Calculate the sphere's volume, V.

Answers

Using the formula:
V= 1/6 πd^3
V ≈ 1838.78

The average duration of labor from the first contraction to the birth of the baby in women over 35 who have not previously given birth and who did not use any pharmaceuticals is 16 hours. Suppose you have a sample of 29 women who exercise daily, and who have an average duration of labor of 17.8 hours and a sample variance of 77.4 hours. You want to test the hypothesis that women who exercise daily have a different duration of labor than all women. Calculate the t statistic. To do this, you first need to calculate the estimated standard error. The estimated standard error is s M

Answers

Answer:

There is not enough evidence to support the claim that women who exercise daily have a significantly different duration of labor than all women.

Standard error sm = 1.634

Test statistic t = 1.102

P-value = 0.28

Step-by-step explanation:

This is a hypothesis test for the population mean.

The claim is that women who exercise daily have a significantly different duration of labor than all women.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=16\\\\H_a:\mu\neq 16[/tex]

The significance level is 0.05.

The sample has a size n=29.

The sample mean is M=17.8.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=√77.4=8.8.

The estimated standard error of the mean is computed using the formula:

[tex]s_M=\dfrac{s}{\sqrt{n}}=\dfrac{8.8}{\sqrt{29}}=1.634[/tex]

Then, we can calculate the t-statistic as:

[tex]t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{17.8-16}{1.634}=\dfrac{1.8}{1.634}=1.102[/tex]

The degrees of freedom for this sample size are:

[tex]df=n-1=29-1=28[/tex]

This test is a two-tailed test, with 28 degrees of freedom and t=1.102, so the P-value for this test is calculated as (using a t-table):

[tex]\text{P-value}=2\cdot P(t>1.102)=0.28[/tex]

As the P-value (0.28) is bigger than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that women who exercise daily have a significantly different duration of labor than all women.

A sample consists of every 30th worker from a group of 1000 workers. What sampling technique was used?

Answers

Answer:

Systematic sampling

Step-by-step explanation:

We have the following sampling technique:

-Random sampling is analogous to putting everyone's name in a hat and extracting several names. Each element of the population has the same probability of occurring.

-Systematic sampling, here the list of elements is "counted". That is, each element k is taken. This is similar to aligning everyone and listing "1,2,3,4; 1,2,3,4; etc."

-Convenience sampling, easily available data is used here. That is, the first people the surveyor meets.

-Cluster sampling is achieved by dividing the population into groups, generally geographically.

-Stratified sampling also divides the population into groups called strata. However, this time it is for some feature, not geographically

In the case of the statement it is systematic because every 30th multiple is picked up which is in a system order members

Use the table to identify values of p and g that can be used to factor X2 - x - 12
as (x + 2)(x + 9).
e
р
2
-2
ptq
-4
9
-6
6
-4
4
4
6
3
-3
-1
1
O A. -3 and 4
unctions
ving
O B-2 and 6
O C. 2 and -6
deling
O D. 3 and 4

Answers

Answer:

D. 3 and -4

Step-by-step explanation:

Given the expression, x² - x - 12, let's factorise to find the value of p and q using the table, for which we would have the expression simplified as (x + p)(x + q)

From the table, let's find the values of p and q that would give us -12 when multiplied together, and would also give us -1 when summed together.

Thus, from the table given, the row containing the values of p(3) and q(-4) gives us = -1 (p+q) . p = 3, q = -4 would be our values to use to factor x² - x - 12, as multiplying both will also give us "-12".

Thus, x² - x - 12 would be factorised or simplified as (x + 3)(x - 4)

Therefore, the answer is: D. 3 and -4

Answer:

D a p e x

Step-by-step explanation:

In professor Hoepker's class, there are X tests and a final. At the end of the semester, the lowest Y test scores are dropped and the remaining test scores and the final (which has twice the weight of a test) are averaged to compute the average score for the entire class. The final cannot be dropped. Going into the final, student Kaytee has an average of W on the X tests. The sum of her lowest Y test scores is L. Her final exam score is S. Find her average score G in the class in terms of X, Y, W, L, and S.

Answers

Step-by-step explanation:

Kaytee's total points are WX + 2S − L.  The total number of exams is W − Y + 2.  Therefore:

G = (WX + 2S − L) / (X − Y + 2)

The total number of exams is W − Y + 2.

We have given that,

In professor Hoepker's class, there are X tests and a final. At the end of the semester, the lowest Y test scores are dropped and the remaining test scores and the final (which has twice the weight of a test) are averaged to compute the average score for the entire class. The final cannot be dropped.

Going into the final, student Kaytee has an average of W on the X tests. The sum of her lowest Y test scores is L. Her final exam score is S.

What is the sum?

The sum brings two or more numbers together to make a new total.

We have to determine her average score of G in the class in terms of X, Y, W, L, and S.

Kaytee's total points are WX + 2S − L.  

The total number of exams is W − Y + 2.

Therefore:G = (WX + 2S − L) / (X − Y + 2)

To learn more about the scores visit:

https://brainly.com/question/5001250

#SPJ2

SOMEONE HELP! I AM GOING TO FAIL THIS WITHOUT U :(



A survey was taken of students in math classes to find
out how many hours per day students spend on social
media. The survey results for the first-, second-, and
third-period classes are as follows:
First period: 2, 4, 3, 1, 0, 2, 1, 3, 1, 4, 9, 2, 4, 3,0
Second period: 3, 2, 3, 1, 3, 4, 2, 4, 3, 1, 0, 2, 3, 1, 2
Third period: 4, 5, 3, 4, 2, 3, 4, 1, 8, 2, 3, 1, 0, 2, 1, 3
Which is the best measure of center for second period
and why?

Answers

Answer:

D) Standard deviation, because there are no outliers that affect the center

On a piece of paper Graph Y=-3x-2

Answers

Answer:

hope it helps uh......

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