A
B
C
D
isosceles triangle

A B C D Isosceles Triangle

Answers

Answer 1
A ? I think is the right answer

Related Questions

Find the area of triangle

Answers

Answer:

Step-by-step explanation:

A = 1/2 bh = 1/2 (12)(17) = 204 square inches

Please help I will give brainliest.

Answers

Answer:

Ten apples cost 9 dollars

Step-by-step explanation:

C(10) = 9

The input is 10 and the output is 9

You bought 10 apples for 9 dollars

Answer:

The last one

Step-by-step explanation:

10 is a function of C which says that the cost of 10 = 9.

determine the distance travelled by the car during this time D =(2m x t2)/2​

Answers

Answer:

D = 2mt

Step-by-step explanation:

D = (2m × 2t)/2

[tex] \sf \: d \: = \frac{2m \times t(2)}{2} [/tex]

[tex] \rightarrow \: \sf \: d = \frac{2m \times 2t}{2} [/tex]

[tex] \rightarrow \: \sf \: d = \frac{4mt}{2} [/tex]

[tex] \rightarrow \: \sf \: d = 2mt[/tex]

~Done~

------

Brandon rolls a six sided die twenty times, and records the result in the table below. how many times did brandon roll above the average? 6 1 3 4 4 4 6 5 5 3 6 4 4 5 2 3 5 4 4 2 a. 14 b. 7 c. 5 d. 4

Answers

The average is the arithmetic mean of all the observations of a set of numbers. The number of times Brandon rolls above the average is 7.

What is average?

The average is the arithmetic mean of all the observations of a set of numbers. it is found by dividing the sum of all the observations of the set by the number of observations in the set.

[tex]\rm{Average=\dfrac{Sum\ of\ observations}{Number\ of\ observations}[/tex]

In order to know the number of times Brandon rolls the dice above the average, we first need to calculate the average of the twenty rolls.

The average of the 20 times dice rolls,

[tex]\rm Average = \dfrac{6+1+3+4+4+4+6+5+5+3+6+4+4+5+2+3+5+4+4+2}{20}[/tex]

[tex]\rm Average = \dfrac{80}{20} = 4[/tex]

Thus, the average of the 20 rolls of the dice is 4.

Now, the number of times the result of the dice roll is above 4(x>4) is 7.

Hence, the number of times Brandon rolls above the average is 7.

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Which point is not on the graph of the function y = x + 2?



(3, 5)
(6, 8)
(7, 9)
(2, 0)

Answers

Answer:

(2,0) is not a point on the graph of the function y=x+2

Step-by-step explanation:

Go to the TI-84 plus calculator and go to the y= button and then type in x+2 and then press the 2nd button and then the graph button and then you should get your answer.

A small company has $8,250,000 in (annual) revenue, spends 49% of its revenues on purchases, and has a net profit margin of 8. 5%. They would like to increase their profits and they are looking at focusing in one of two directions. First, they think they can save 2. 05% on their purchase expenses. Or second, they can focus on increasing sales. By how many dollars would they have to increase sales in order to equal a 2. 05% savings to purchasing expenses? (Display your answer as a whole number. )

Answers

as far as I can read that, well, the company has a revenue income of 8250000 and their expenditure on purchases is 49% of that amount, how much is that?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{49\% of 8250000}}{\left( \cfrac{49}{100} \right)8250000}\implies 4042500[/tex]

so on saving 2.05% of purchasing expenses or namely 2.05% of 4042500

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{2.05\% of 4042500}}{\left( \cfrac{2.05}{100} \right)4042500}\implies 82871.25[/tex]

so sales must be increased by that much in order to match the 2.05% of 4042500.

help worth a lot of pounts

You want to buy a new computer that costs $2250. You check your savings-account balance and realize that to buy the computer, you will need $125 more than what you have in your savings account. How much money do you have in your savings account?

Equation:

Define the Variable:

How much money in your savings account?

Answers

Answer:

See below.

Step-by-step explanation:

Let x = amount of money you have in your account.

The money in your account plus the $125 extra that you need equals the total cost of the computer.

The equation is:

x + 125 = 2250

Now we solve the equation by subtracting 125 from both sides.

x = 2125

Answer: You have now $2125 in your account

Answer:

$2125

Step-by-step explanation:

PLEASE HELPPP

find the value of x

Answers

The answer is 62. So you add both numbers and subtract by 180 to get your answer

Answer:

x = 62°

Step-by-step explanation:

Concepts:

All angles in a triangle add up to 180°, and there are three angles in a triangle.  In this case, we're given the three angles as 50°, 68°, and x°. This means that x + 50 + 68 = 180.

Solving

Step 1: Combine like terms.

[tex](x)+(50+68)=180[/tex] [tex]x+118=180[/tex]

Step 2: Subtract 118 from both sides.

[tex]x+118-118=180-118[/tex][tex]x=62[/tex]

Step 3: Check if solution is correct.

[tex]62+50+68=180[/tex][tex]112+68=180[/tex] [tex]180=180[/tex]

Therefore, the answer is x = 62°.

Can u do these for me

Answers

Answer:

Step-by-step explanation:

Compare the decimals using >, <, or =

2.95 > 2.949 (2.95 can be written as 2.950, which is > 2.949)3.75 < 3.8 (3.8 can be written as 3.80, which is > 3.75)0.98 = 0.980 (0.98 can be written as 0.980, which is = 0.980)0.86 < 0.861 (0.86 can be written as 0.860, which is < 0.861)1.76 < 2 (2 can be written as 2.00, which is > 1.76)3.15 < 3.2 ( 3.2 can be written as 3.20, which is > 3.15)

Name two equivalent fractions for each fraction listed below.

2/4 = 1/2 = 4/81/3 = 2/6 = 3/91/10 = 2/20 = 3/30

If there are 16 cups in one gallon, how many cups are in 3 gallons?

16 cups = 1 gal.

? cups = 3 gals.

3 * 16 = 48 cups

How many cups are in 5 gallons?

5 * 16 = 80 cups

Compare and contrast squares are rectangles

Squares: have four sides and four equal sides

Rectangles: have four sides and have 2 parallel sides, meaning that they have 2 opposite sides that are equal.

Hope this helps!

Which equation can be used to solve for m∠1? m∠1 = one-half(a – b) m∠1 = one-half(a b) m∠1 = one-half(c – d) m∠1 = one-half(c d)

Answers

The equation will be:

[tex]m\angle 1=\dfrac{1}{2}(arc\ a-arc\ b)[/tex]

What is arc of circle?

The arc of the circle is the curved line on the circle formed by the angle and the radius of the circle.

In the attached picture of the question, we can see that

The measure of the interior angle is the semi-sum of the arches that comprise it and its opposite.

So the equation will be

[tex]m\angle 1=\dfrac{1}{2}(arc\ a-arc\ b)[/tex]

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Answer: a

Step-by-step explanation:

What is 7/15+13/19+5/12 expressed as a fraction in lower terms

Answers

The simplest form is 1787/1140

7/15+13/19+5/12 = 1787/1140, is in its lowest term.

A functionf(θ) is periodic if after some periodt, it repeats. In other wordsf(θ t) =f(θ) for allθ. Lettingθbe a real number, isf(θ) =eiθperiodic? (2 points) if so, what is its period? (2points)

Answers

The period of the given function is T = 2π

What is the period of the function?

The period T of a function f(x) is such that:

f(x + T) = f(x).

In this case, our function is:

f(θ) = e^{iθ}

Remember that this can be written as:

f(θ) = cos(θ) + i*sin(θ)

So yes, this is in did a periodic function.

Then the period of the function f(θ) is the same as the period of the cosine and sine functions, which we know is T = 2π.

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The period of the considered function f(θ) = e^{iθ} is found to be P = 2π (assuming 'i' refers to 'iota' and 'e' refers to the base of the natural logarithm)

What is euler's formula?

For any real value θ, we have:

[tex]e^{i\theta} = \cos(\theta) + i\sin(\theta)[/tex]

where 'e' is the base of the natural logarithm, and 'i' is iota, the imaginary unit.

What are periodic functions?

Functions which repeats their values after a fixed interval, are called periodic function.

For a function [tex]y = f(x)[/tex], it is called periodic with period 'T' if we have:

[tex]y = f(x) = f(x + T) \: \forall x \in D(f)[/tex]

where D(F) is the domain of the function f.

Suppose that, the period of the function [tex]f(\theta) = e^{i \theta}[/tex] be P, then we get:
[tex]f(\theta + P) = f(\theta)\\\\e^{i(\theta)} = e^{i(\theta + P)}\\\\\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex]

When two complex numbers are equal, then their real parts are equal and their imaginary parts are equal.

That means,

[tex]\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex] implies that:

[tex]\cos(\theta) = \cos(\theta + P)\\\sin(\theta) = \sin(\theta + P)[/tex]

Also, we know that the period of sine and cosine function is [tex]2\pi[/tex]

Thus, we get:

[tex]P = 2\pi[/tex]

Thus, the period of the function [tex]f(\theta) = e^{i \theta}[/tex]  is P = 2π

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An equilateral triangle has an area of 50 units 2. What is the length of each side?

Answers

Answer:

Length of each side of equilateral Traingle is 10.75 units

Step-by-step explanation:

Given that area of an equilateral traingle 50 square units.

Let the length of side of equilateral traingle be 'x' units. To calculate length of each side we will use the formula of area of equilateral traingle:

[tex] \: \: { \underline { \boxed{\pmb { \sf{ \purple {Area_{(equilateral \: traingle)} = \dfrac{\sqrt 3}{4} \times (Side)^2}} }}}} \\ [/tex]

By substituting the values in above formula:

[tex]~[/tex]

[tex] : \implies \sf \: \: 50 = \dfrac{ \sqrt{3} }{4} \times {(x)}^{2} \\ \\ \\ : \implies \sf \: \: {(x)}^{2} = \dfrac{50 \times 4}{ \sqrt{3} } \\ \\ \\ : \implies \sf \: \: {(x)}^{2} = \dfrac{200}{ \sqrt{3} } \\ \\ \\ : \implies \sf \: \: x = \sqrt{ \dfrac{200}{ \sqrt{3} } } \\ \\ \\ : \implies \: \: { \boxed{\pmb{ \frak{ x = 10.75 \: units }}}}\\ \\ \\ [/tex]

Hence, Length of each side of equilateral Traingle is 10.75 units

Find the 8th term of the sequence whose common ratio is 1/3 and whose first term is 3

Answers

Answer:

The 8th term is [tex]\frac{1}{729}[/tex].

Step-by-step explanation:

Let's begin with the formula for a geometric sequence. We know this is geometric because we are working with a common ratio, or the number we multiply to find each term.

[tex]a_n=a_0(r)^{n-1}[/tex]

In this formula, [tex]a_0[/tex] is the first term, [tex]r[/tex] is the common ratio, and [tex]n[/tex] is the desired term. We know the values of [tex]r[/tex], [tex]a_0[/tex], and [tex]n[/tex] from the given information:

[tex]a_0=3\\r=\frac{1}{3}\\n=8[/tex]

Substituting those values we get:

[tex]a_8=3(\frac{1}{3})^{8-1}[/tex]

[tex]a_8=3(\frac{1}{3})^7\\a_8=3(\frac{1}{2187})\\a_8=\frac{3}{2187}\\a_8=\frac{1}{729}[/tex]

each child has 9 crayons.if there are 38 children ,how many crayons are there in total?​

Answers

Answer:

342

Step-by-step explanation:

9x38=342, so the answer is 342 crayons

Answer:

342 crayons

Step-by-step explanation:

Each child has 9 crayons. This means each one of the children has 9 crayons for himself or herself. So if there are 38 children,it means each one of the 38 children has 9 crayons.

The total number of crayons is therefore gotten by multiplyiong the number of crayons of each child(9) by the total number of children(38).

∴38×9=342.

HELP ME PLEASE
PRETTY PLEASEEEEEEEEEEE

Answers

Answer:

93

Step-by-step explanation:

19x-2 =  18x+3

x=5

15(5) -2=93

18(5)+3=93

When Derek planted a tomato plant, he expected to be picking his first ripe tomato in 45 days. His estimate was 25% less than the actual time. How long did it take before Derek picked his first ripe tomato?

Answers

Answer:

60 days.

Step-by-step explanation:

Let the actual time be x, then:

x - 0.25x = 45

0.75x = 45

x = 45/0.75

= 60 days.

help!

Fill in the empty spaces with monomials that make each equality
into an
indentity.
(3x - ...)? = 9x2 - 6x +1

Answers

Answer:

  1

Step-by-step explanation:

The square of the value in the empty space is the constant in the expanded expression. That is ...

  [ ]² = 1

The value in the space is ...

  [ ] = √1 = 1

The filled-in equation is ...

  (3x -1)² = 9x² -6x +1

_____

The expansion of the square of a binomial is ...

  (ax -b)² = a²x² -2abx +b²

Above, we used the constant term to find 'b', but we could also have used the linear term:

  -6x = -2(3)bx . . . . . a=3 in this problem

  1 = b . . . . . . . divide by -6x

The area and the perimeter of a square are equal. Find the side
length of the square.

please help me

Answers

Answer:

side length = 4

Step-by-step explanation:

Let x = the side length

Area is x•x, which is x^2.

Perimeter is x+x+x+x, which is 4x.

x^2 = 4x

x^2 - 4x = 0

Factor.

x(x-4) = 0

x = 0 or x = 4

Discard 0 as an answer as it is not useful.

x = 4.

Area = 4^2 = 16

Perimeter = 4(4)= 16

The side length is 4.

Helpp me with my sister's math​

Answers

Answer:

pq - 12r

step by step explanation:

20 = (-10) = (-20) +10

1) Is the equation up there true or false?

2) Support your decision below.

Help quick

Answers

Answer:

No, 20 ≠ -10

Step-by-step explanation:

20 = (-10) = (-20)+10

20≠-10=-20+10

20≠-10=-10

Given that cosθ= - 21/29 and the angle θ terminates in quadrant II, then what is the value of tan θ

Answers

Answer: -20/21

Step-by-step explanation:

Using the Pythagorean identity, we can get that the sine of angle theta is [tex]\pm 20/29[/tex].

But since theta terminates in Quadrant II, the sine of angle theta is positive, meaning that it has a value of 20/29.

Now, since tan = sin/cos, tan theta = (20/29)/(-21/29) = -20/21

which features of a figuer JKLM remain the same after any rigid transformation i-ready

Answers

The rigid transformation of figure JKLM would not change the side length and angle measure

The features of the figure JKLM that would remain the same are its side lengths and angles

How to determine the features?

A rigid transformation is any of the following

TranslationRotationReflection

All of the above transformation do not change the side length and the angle measure of the shape they transform

Hence, the features of the figure JKLM that would remain the same are its side lengths and angles

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In the adjoining figure triangle PQR is similar to triangle PMN , PM= 2MQ And PN = 2NR . Determine ratio of MN/QR

Answers

The triangles PQR and PMN are similar triangles

The ratio MN/ QR is 2/3

How to detemine the ratio MN/QR?

The question is incomplete, as the figure of the triangles are not given.

So, I will give a general explanation

The given parameters are:

PM= 2MQ

PN = 2NR

Rewrite PM= 2MQ  as:

PM/MQ = 2/1

The equation becomes

PM/(PM + MQ) = 2/(2 + 1)

PM/(PM + MQ) = 2/3

Add PM and MQ

PM/PQ = 2/3

The above means that:

PM/PQ = MN/ QR = 2/3

Hence, the ratio MN/ QR is 2/3

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Hello people ~
Factorise: x^2 + 7x + 12​

Answers

Step-by-step explanation:

x^2 + (4+3)X + 12

x^2 + 4x + 3X + 12

X (X + 4) + 3 ( X + 4)

( X + 3) (X +4)

Solving steps:

[tex]\sf \rightarrow x^2\:+\:7x\:+\:12[/tex]

breakdown the following

[tex]\sf \rightarrow x^2\:+\:3x + 4x\:+\:12[/tex]

break the expressions into groups

[tex]\sf \rightarrow \left(x^2+3x\right)+\left(4x+12\right)[/tex]

factor the following

[tex]\rightarrow \sf x\left(x+3\right)+4\left(x+3\right)[/tex]

factor the common term: (x+3)

[tex]\rightarrow \sf \left(x+3\right)\left(x+4\right)[/tex]

What percentage of Africa is savanna?

less than ten percent

approximately twenty-five percent

almost fifty percent

close to seventy percent

Answers

Answer:

C, Almost fifty percent

Step-by-step explanation: I just got it right.

Jake has 900 cm³ of material. He uses 14. 5 cm³ to make a right triangular prism. He wants to make a second prism that is a dilation of the first prism with a scale factor of 4. How much more material does Jake need in order to make the second prism? Select from the drop-down menu to correctly complete the statement. Jake needs an additional Choose. Cm³ of material to make the second prism.

Answers

A ratio shows the relation between two numbers. The amount of more material that is needed by Jake is 42.5 cm³.

What is a Ratio?

A ratio shows us the number of times a number contains another number.

Given that the volume of the first prism is 14.5cm³, while the scale factor is 4. Since the scale factor is applicable to dimension, and volume is always the cube of three-dimension.

Therefore, the volume of the scaled prism will be the cube the of the volume of the first prism, which can be written as,

[tex]\rm \text{Volume of the Scaled prism}= (Scale\ factor)^3 \times \text{Volume of the first prism}[/tex]

Substitute the values,

[tex]\rm \text{Volume of the Scaled prism}= 4^3 \times 14.5 = 928\ cm^3[/tex]

Since, the volume of material with Jake is 900 cm³, while the material he has already used is 14.5 cm³, thus the volume of the material that is left with Jake is 885.5 cm³(900cm³-14.5cm³).

Now, since the material needed to make the scaled prism is 928 cm³, the amount of material that is with Jake is 885.5 cm³, therefore, the amount of the material that is needed by Jake to complete the scaled prism can be written as,

The Amount of more material Needed by Jake = Amount of material needed to make the scaled prism - Amount of material left with Jake

The Amount of more material Needed by Jake = 928 cm³ - 885.5 cm³

                                                                               = 42.5 cm³

Hence, the amount of more material that is needed by Jake is 42.5 cm³.

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What value of c makes x2 6x c a perfect square trinomial? c = If x2 6x c = (x d)2, then d =.

Answers

[tex]\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x^2 \pm \stackrel{\stackrel{2\sqrt{x^2}\sqrt{c^2}}{\downarrow }}{6x} +c^2~\hspace{10em}6x=2\sqrt{x^2}\sqrt{c^2}\implies 6x=2xc \\\\\\ \cfrac{6x}{2x}=c\implies 3=c\implies 9=c^2~\hfill \boxed{(x\pm 3)^2}[/tex]

c=9 makes the given expression a perfect square trinomial.

The given expression is:

[tex]x^{2} +6x+c[/tex]

We can rewrite it as:

[tex]x^{2} +2*x*3 + c[/tex].....(1)

What is the expansion of  [tex](a+b)^2[/tex]?

The expansion of [tex](a+b)^2[/tex] is [tex]a^{2} +2ab+b^{2}[/tex]

Comparing (1) with [tex]a^{2} +2ab+b^{2}[/tex]

We get

a=x

b=3

c=b²

So, c=3² =9.

So, c=9 makes the given expression a perfect square trinomial.

Hence,  c=9 makes the given expression a perfect square trinomial.

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find the slope of the line that passes through the pints (2,7) and (2,6)

Answers

Answer:

Undefined Slope

Step-by-step explanation:

The points (2,6) and (2,7) are on the same vertical line of 2, which results in an undefined slope.

Answer:

m=undefined

Step-by-step explanation:

The formula to find the slope isn't very complicated. The formula is:

    y₂-y₁

m= --------

      x₂-x₁

You have the points (2,7) and (2,-6). In (2,7) 2 is your x and 7 is your y. Since (2,7) is your first coordinate set, we put 2 as our x₁ . We put 7 as our y₁ .

In (2,-6) 2 is your x and -6 is your y. Since (2,-6) is your second coordinate set, we put 2 as our x₂ . We put -6 as our y₂ .

Let's substitute all of these numbers in:

    -6-7       -13

m= -------  = -------

     2-2         0

So we have -13/0 .You would think that any number divided by                0 is 0, right?

                No. Any number divided by 0 is undefined.

                   

Therefore, you slope, m, would be:

m=undefined .

"Your teacher brings two bags of colored goldfish crackers to class. Bag I has 25% red crackers and Bag II has 35% red crackers. Each bag contains more than 1000 crackers. Using a paper cup, your teacher takes an SRS of 50 crackers from Bag I and a separate SRS of 40 crackers from Bag II. Let p1-p2 be the difference in the sample proportions of red crackers. " The object is to find the standard deviation. I have 0. 971. Is this correct? I would like to verify

Answers

Using the Central Limit Theorem, it is found that the standard deviation is of 0.0971.

What does the Central Limit Theorem states?It states that for a proportion p in a sample of size n, the sampling distribution of sample proportion is approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1 - p)}{n}}[/tex], as long as [tex]np \geq 10[/tex] and [tex]n(1 - p) \geq 10[/tex].It also states that when two variables are subtracted, the standard deviation is the square root of the sum of the variances.

In this problem, for each sample, the standard error is given by:

[tex]s_I = \sqrt{\frac{0.25(0.75)}{50}} = 0.0612[/tex]

[tex]s_{II} = \sqrt{\frac{0.35(0.65)}{40}} = 0.0754[/tex]

Hence, for the distribution of differences, it is given by:

[tex]s = \sqrt{s_I^2 + s_{II}^2} = \sqrt{0.0612^2 + 0.0754^2} = 0.0971[/tex]

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