The linear acceleration experienced by the bug depends on the time t. We cannot find a single value for it without knowing how much time has passed since the person started to pull the hose.
Since the bug is on the rim of the reel, it moves in a circular path along with the hose. Therefore, it experiences a centripetal acceleration that is given by the formula:
[tex]a = r * ω^2[/tex]
where r is the radius of the circular path, and ω is the angular velocity of the bug.
Initially, when the reel is at rest, the angular velocity of the bug is zero. When the person starts to pull the hose with a linear acceleration of [tex]0.75 m/s^2,[/tex] the reel also starts to rotate with an angular acceleration of:
α = a / r = [tex](0.75 m/s^2)[/tex] / (0.10 m) = [tex]7.5 rad/s^2[/tex]
Using the formula for angular acceleration, we can find the angular velocity of the reel after a certain time t:
ω = α * t
The angular velocity of the bug is the same as that of the reel, so we can use the same formula to find the angular velocity of the bug after time t.
Once we know the angular velocity of the bug, we can use the formula for centripetal acceleration to find the linear acceleration experienced by the bug:
[tex]a = r * ω^2[/tex]
Substituting the given values, we get:
a = [tex](0.33 m) * (α * t)^2[/tex]
a = [tex](0.33 m) * [(7.5 rad/s^2) * t]^2[/tex]
a = [tex]18.56 t^2 m/s^2[/tex]
Learn more about linear acceleration
https://brainly.com/question/13723307
#SPJ4
a 30.00 ml sample of 0.125 m hcooh is being titrated with 0.175 m naoh. what is the ph after 15.0 ml of naoh has been added? ka of hcooh = 1.8 × 10−4
The pH after 15.0 mL of 0.175 M NaOH has been added is 11.58.
The balanced equation for the reaction between formic acid (HCOOH) and sodium hydroxide (NaOH) is:
[tex]HCOOH + NaOH $\rightarrow$ NaCOOH + H$_2$O[/tex]
First, we need to determine how many moles of HCOOH are present in the initial 30.00 mL sample:
moles of HCOOH = (0.125 mol/L) x (0.03000 L) = 0.00375 mol
Next, we can use the stoichiometry of the reaction to determine how many moles of NaOH are required to neutralize all of the HCOOH:
1 mol HCOOH reacts with 1 mol NaOH
moles of NaOH = 0.00375 mol
Now, we can calculate the concentration of NaOH after 15.0 mL has been added:
final volume = 30.00 mL + 15.0 mL = 45.00 mL = 0.04500 L
moles of NaOH = (0.175 mol/L) x (0.01500 L) = 0.002625 mol
initial moles of HCOOH = 0.00375 mol
moles of HCOOH remaining after reaction = 0.00375 mol - 0.002625 mol = 0.001125 mol
The concentration of HCOOH at this point is:
[HCOOH] = 0.001125 mol / 0.04500 L = 0.025 M
The Ka expression for formic acid is:
Ka = [H+][HCOO-] / [HCOOH]
We can assume that the [H+] concentration is equal to the [OH-] concentration at this point, since the reaction is at the equivalence point. Therefore:
Ka = (x)(x) / 0.025
where x is the concentration of [OH-].
Solving for x, we get:
x = sqrt(Ka*[HCOOH]) = sqrt(([tex]1.8x10^-4[/tex])*(0.025)) = 0.003794
pOH = -log[OH-] = -log(0.003794) = 2.42
pH = 14.00 - pOH = 11.58
Therefore, the pH after 15.0 mL of 0.175 M NaOH has been added is 11.58.
Learn more about balanced equation
https://brainly.com/question/7181548
#SPJ4
A 500 N force is applied to a 25m/s2 object. The mass of the object is ____.
A. ) 20kg
B. ) 20 m/s
C. ) 12,500 m/s
D. ) 12,500 kg
A 500 N force is applied to a 25m/s2 object. The mass of the object is 20kg. The correct answer is option: A.
The force applied to an object is related to its mass and acceleration through the equation:
F = ma,
where F is the force, m is the mass, and a is the acceleration. Rearranging this equation, we get:
m = F/a.
In the given problem, a force of 500 N is applied to the object, and its acceleration is 25 m/s^2.
Substituting these values in the formula, we get :
m = 500 N / 25 m/s^2 = 20 kg.
Therefore, the mass of the object is 20 kg, which is option A.
To know more about acceleration, here
brainly.com/question/12550364
#SPJ4
The potential energy of an apple is 6.0 Joules. The apple is 1.22m high. What is the mass of the apple?
Answer:
The mass of the apple is 0.49kg
Explanation:
Potential energy=mgh
P=mgh
6=m×1.22×10
6=12.2m
divide both sides by 12.2
m=6/12.2
m=0.49kg
For a satellite to orbit Earth at a constant distance, its centrifugal acceleration must be equal and opposite Earth's gravitational acceleration. If a satellite is to orbit at a constant distance from Earth at a circular radius of 8,000,000 m, what is the required velocity of the satellite? (Assume the acceleration due to Earth's gravity is 6.2 m/s2 at this altitude.).
The required velocity of the satellite to orbit Earth at a constant distance of 8,000,000 m is 7,905 m/s.
What is Gravity?
Gravity is a force that attracts two bodies with mass towards each other. It is one of the four fundamental forces of nature and is responsible for holding planets in orbit around stars and stars in orbit around galaxies. Gravity is described by Einstein's theory of general relativity, which states that gravity is the result of the curvature of spacetime caused by the presence of mass or energy.
where G is the gravitational constant M is the mass of the Earth and r is the distance between the satellite and the center of the Earth (8,000,000 m).
First, we need to calculate the gravitational acceleration due to the Earth's gravity at this altitude using the formula:
g = GM/[tex]r^{2}[/tex]
g = (6.67 x 10^-11 N [tex]m^{2}[/tex]/[tex]kg^{2}[/tex]) x (5.97 x [tex]10^{24}[/tex] kg) / (8,000,000 m)^2
g = 6.19 m/[tex]s^{2}[/tex]
The required velocity can be found using:
v = √(GM/r)
v = √[(6.67 x 10^-11 N[tex]m^{2}[/tex]/[tex]kg^{2}[/tex]) x (5.97 x [tex]10^{24}[/tex] kg) / (8,000,000 m)]
v = 7,905 m/s
Learn more about Gravity from the given link
https://brainly.com/question/940770
#SPJ1
which force pairs must be equal because they are action/reaction pairs?multiple select question.the upward normal force on a car and the downward push of the car on the ground.the rightward force of a pull on a box traveling at constant velocity and the leftward friction force.the upward normal force on a book at rest on the table and its downward weight.the rightward force of you pushing on a wall and the leftward force of the wall pushing on you.
Force pairs that must be equal because they are action/reaction pairs. According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. This means that action and reaction forces are always equal in magnitude but opposite in direction.
Some examples of action/reaction force pairs include:
1. When you push a book across a table (action), the book pushes back with an equal force (reaction).
2. When a person jumps off a diving board (action), the diving board exerts an equal and opposite force on the person (reaction).
3. A person walking on the ground pushes against the ground (action), and the ground pushes back with an equal force (reaction).
In all these cases, the action/reaction force pairs are equal and opposite, illustrating Newton's Third Law of Motion.
To know more about Newton's Third Law of Motion:
https://brainly.com/question/29768600
#SPJ11
Students set up an experiment to test the effect of gravity on different objects. They fill balloons with different amounts of water and drop them from the third-floor window of their school. They time how long each balloon takes to reach the ground. They repeat the process three times. What is the experiment’s variable?
answers
number of times the drops were repeated
times that the balloons take to drop
mass of the balloons
height of the window
The number of times the drops were repeated and the mass of the balloons may be controlled variables that are kept constant during the experiment to isolate the effect of the height of the window on the time it takes for the balloons to reach the ground.
What is Isolated System?
An isolated system is a concept in thermodynamics and physics that refers to a system that does not exchange energy or matter with its surroundings. It is a closed system with respect to both energy and matter, meaning that no energy or matter is transferred across its boundaries. In an isolated system, the total energy, including both kinetic and potential energy, remains constant over time. This is known as the principle of conservation of energy.
The experiment's variable in this case is the height of the window from which the balloons are dropped. The students are specifically testing the effect of gravity, which is influenced by the height from which an object falls. By varying the height of the window, the students are manipulating the independent variable (height of the window) to observe the effect on the dependent variable (time it takes for the balloons to reach the ground).
Learn more about Isolated System from the given link
https://brainly.com/question/2846657
#SPJ1
a certain pendulum on earth has a period of 1.1 s. what would be the period of this pendulum if it were taken to another planet that had 2.5 times the mass of the earth and 2 times the earth's radius? express your answer in seconds to three significant digits.
The period of the pendulum on this planet would be 2.51 seconds to three significant digits.
The period of a pendulum is given by the formula:
T = 2π√(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Since the length of the pendulum is not changing, we can see that the period is directly proportional to the square root of the acceleration due to gravity.
On the other planet, the acceleration due to gravity will be:
[tex]g' = (GM')/r'^2[/tex]
where G is the gravitational constant, M' is the mass of the planet, and r' is the radius of the planet.
We are told that this planet has 2.5 times the mass of the Earth and 2 times the Earth's radius. Therefore,
[tex]M' = 2.5M[/tex]
[tex]r' = 2r[/tex]
Substituting these values into the formula for g', we get:
[tex]g' = (GM')/r'^2 = (G(2.5M))/(4r^2) = (5/8)g[/tex]
So the acceleration due to gravity on this planet is (5/8) times the acceleration due to gravity on Earth.
Using the formula for the period of a pendulum, we can see that the period of the pendulum on this planet would be:
[tex]T' = 2π√(L/g') = 2π√(L/(5/8)g) = 2.51s[/tex]
Therefore, the period of the pendulum on this planet would be 2.51 seconds to three significant digits.
Learn more about the pendulum
https://brainly.com/question/29702798
#SPJ4
A 20 Kg bike accelerates at 10 m/s^2. With what force was the person pedaling
NEED HELP PLEASE.
QUESTION: imagine that you carry a box of books, weighing 67.8 N, up a flight of stairs. if each step is 15.0 cm high, and there are 22 steps in the flight of stairs, how much work do you do on the box of books
Answer:
The answer for Work done is ≈224J or 224Nm
Explanation:
Work done=F×D
F=mg
F=W
d=15×22=330cm=3.3m
W=67.8×3.3
W=223.74J or 223.7Nm
W≈224J or 224 Nm
can someone just explain what this means. whats the squiggly red line for
Answer:
Intensity
Explanation:
The graph shows different types of radiation!
The red line imples how intense the radiation is. When the line is long and spread out, it implies less intensity. When it moves up and down quickly, as you can see in the end of the graph, it implies high intensity.
We can confirm this by seeing the labels. Indeed, Radio waves are the least powerful, and gamma rays the most.
~~~Harsha~~~
An asteroid is 4. 5 times as far from the sun as the earth. What is the period of that asteroid in terms of earth years?
The period of the asteroid in terms of Earth years is approximately 8.13 years. This means that it takes the asteroid 8.13 years to complete one orbit around the sun, while the Earth takes one year to complete its orbit.
To determine the period of an asteroid orbiting the sun, we can use Kepler's Third Law, which states that the square of the period of an object in orbit around the sun is proportional to the cube of its average distance from the sun. Mathematically, this can be expressed as:
[tex]\frac{(T_{\text{asteroid}})^2}{(T_{\text{earth}})^2} = \left(\frac{d_{\text{asteroid}}}{d_{\text{earth}}}\right)^3[/tex]
where T is the period of the asteroid and earth respectively, and d is the average distance from the sun.
Given that the asteroid is 4.5 times farther from the sun than the Earth, we can plug this ratio into the equation:
[tex]\frac{(T_{\text{asteroid}})^2}{(1 \text{ year})^2} = 4.5^3[/tex]
Solving for T asteroid, we get:
[tex](T_{\text{asteroid}})^2 = 4.5^3[/tex]
[tex]T_{\text{asteroid}} = \sqrt{4.5^3}[/tex] = 8.13 years
It is important to note that this calculation assumes a circular orbit, which is not always the case for asteroids.
To learn more about Kepler's Third Law
https://brainly.com/question/1086445
#SPJ4
a particle with a cahrge of 1 c is moving at 45 angle with respect to the positive x axis in teh horizontal xy-plane. the velocity of the charge is 1 m/s. a magnetic field of 1 t is directed in the negative x direction. what is the magnetic force acting on the charge?
The magnetic force acting on the charged particle is -0.707 N in the k direction and 0.707 N in the j direction.
In this problem, the charge of the particle is given as 1 C, and the velocity of the particle is 1 m/s at an angle of 45 degrees to the positive x-axis. We can break down the velocity vector into its x and y components as follows:
vx = vcos(45) = 0.707 m/s
vy = vsin(45) = 0.707 m/s
The magnetic field is given as 1 T in the negative x direction.
Substituting these values into the formula for the magnetic force, we get:
F = q * (vxi + vyj + 0k) x (-Bi)
where I, j, and k are the unit vectors in the x, y, and z directions, respectively.
Expanding the cross product, we get:
F = q*(-vxB)k + qvyB*j
Substituting the values for q, vx, vy, and B, we get:
F = (1 C) (-0.707 m/s) (1 T) k + (1 C) (0.707 m/s) *(1 T) *j
Simplifying, we get:
F = -0.707 k + 0.707 j
To know more about Charge:
https://brainly.com/question/3412043
#SPJ4
how fast would a 67 kg person have to run to have that amount of energy? express your answer with the appropriate units.
The 67 kg person has to run at the speed of [tex]\sqrt{((2 \times KE) / 67)}[/tex] m/s to have that amount of energy.
To calculate the kinetic energy (KE) of a person running, we can use the formula
KE = [tex]0.5 \times m \times v^2[/tex]
where m is the mass (67 kg) and v is the velocity in meters per second (m/s).
First, we need to determine the desired amount of energy, which is not provided in the question.
Obtain the desired energy value (in joules, J) you want the person to have while running.
Plug the mass (67 kg) and the desired energy value into the KE formula: [tex]KE = 0.5 \times 67 \times v^2[/tex].
Rearrange the formula to isolate v:
[tex]v^2 = (2 \times KE) / 67[/tex] m/s
Calculate v by taking the square root
[tex]v = \sqrt {(2 \times KE) / 67)}[/tex] m/s
The calculated value of v will be the velocity in meters per second (m/s) required for the person to have the desired amount of energy while running.
Remember to replace "KE" with the desired energy value in joules, and you will get the velocity (in m/s) needed for a 67 kg person to have that amount of energy.
For more such answers on Kinetic Energy
https://brainly.com/question/25959744
#SPJ11
describe the relationship between the angle of incoming light and the percentage of light that is transmitted through the water versus the percentage of light that is reflected
The angle of incoming light plays a significant role in determining the percentage of light that is transmitted through water versus the percentage of light that is reflected. As the angle of incidence of light increases, the amount of light that is transmitted through the water decreases, while the amount of light that is reflected off the surface of the water increases.
This is due to the fact that at higher angles of incidence, the light has to travel through more water, which causes it to be absorbed and scattered more, leading to a decrease in the amount of transmitted light. Additionally, the angle of incidence also affects the polarization of the reflected light, which can impact the amount of light that is reflected.Overall, the relationship between the angle of incoming light and the percentage of light that is transmitted versus reflected is complex and depends on a variety of factors, including the properties of the water, the characteristics of the light, and the angle of incidence.To learn more about angle of incidence please visit:
https://brainly.com/question/30048990
#SPJ11
What does it mean when we say our sense of motion depends on our frame of reference? Include the phrases “fixed frame” and “moving frame” in your answer.
frame of reference that is not inertial. A non-inertial frame is now defined as a frame that accelerates relative to the underlying inertial reference frame. Newton's law won't be valid.
How does the framework function?
Performance could change depending on the lighting. The Frame automatically modifies the Plasma tvs brightness and contrasting settings after analyzing the lighting conditions in the room and the light level of your content.
What distinguishes a system from a frame?
the hard architecture (bones and condyle) that serves as an animal's body's framework. skeletal system, skeleton, and systema skeletale. system: a collection of organs or bodily parts that function or are anatomically related; "the body contains a system for organs for digestion."
To know more about frame visit:
https://brainly.com/question/9708057
#SPJ1
Newton's first law of motion states that an object in motion will stay in motion unless acted upon by a force.
What are two forces on earth that could change the motion of the object?
Responses
friction and gravity
friction and gravity
speed and acceleration
heat and light
direction and time
The two forces on Earth that could change the motion of an object are friction and gravity.
Friction is a force that opposes the motion of an object when it is in contact with another surface. It can cause an object to slow down or come to a stop.
Gravity is a force of attraction between two objects, and it can cause an object to accelerate toward the center of the earth or towards another massive object. The gravitational force on an object depends on its mass and the distance between it and the other object.
Speed and acceleration are not forces, but rather measures of motion. Heat and light are also not forces that can change the motion of an object, but rather forms of energy that can be transferred to an object and affect its temperature or behavior. Direction and time are not forces, but concepts related to an object's motion.
Learn More about Newton's first law of motion:
https://brainly.com/question/1222214
if a plunge pool undercuts the support of the resistant rock layer above and causes it to collapse, then the
If a plunge pool undercuts the support of the resistant rock layer above and causes it to collapse, then this can result in a potentially dangerous situation, the collapse can cause erosion of the surrounding soil and vegetation, leading to further instability of the area.
The collapse of the resistant rock layer can lead to a landslide or rockfall, which can cause significant damage to the surrounding area and pose a threat to anyone in the vicinity. Additionally, the collapse can cause erosion of the surrounding soil and vegetation, leading to further instability of the area.
To prevent such occurrences, it is important to properly design and maintain plunge pools. The proper design includes ensuring that the pool is not located near a resistant rock layer or if it is, that measures are put in place to prevent the pool from undercutting the rock.
This may include reinforcing the rock layer, installing retaining walls or other support structures, or moving the pool to a different location.
Regular maintenance of the plunge pool is also crucial to prevent erosion and undercutting of the rock layer. This may involve monitoring the pool for signs of erosion or instability and taking corrective action if necessary, such as repairing or reinforcing the surrounding area.
Overall, it is important to ensure that plunge pools are designed and maintained properly to prevent the undercutting of resistant rock layers and potential collapses, which can have serious consequences.
To know more about erosion refer here:
https://brainly.com/question/1599677#
#SPJ11
-The diagram above represents two identical pulses approaching each other in a uniform medium.
As the pulses meet and are superposed, the maximum displacement of the medium is?
- 6 cm
0 cm
6 cm
3 cm
On the basis of constructive interference, when two identical pulses go together in a homogeneous medium and the pulses meet and overlap, the maximum displacement of the medium is equal to 6 cm. So, option (c) is right.
Wave interference is the phenomenon where two waves meet while propagating in the same medium. Constructive interference is a form of interference. It takes place when two pulses meet each other and form a larger pulse. The amplitude of the resulting larger pulse is the sum of the amplitudes of the first two pulses.
This could be done at meetings of two crests or troughs. It can appear anywhere between the two interfering waves are displaced upward. But the two negative effects are also seen when they move downwards.This is shown in the image above. Since we have two identical wave pluses, they are close together in a uniform medium.
Now, Amplitude of pluse A = 3 cm
Amplitude of pluse B = 3 cm
So, the pulses meet and are superposed, the amplitude or maximum displacement of the medium is sum of amplitudes of pluses, that is 3cm + 3 cm = 6 cm. Therefore, the displacement value should be 6 cm.
For more information about Constructive interference, visit :
https://brainly.com/question/11808546
#SPJ4
Complete question:
-The diagram above represents two identical pulses approaching each other in a uniform medium.
As the pulses meet and are superposed, the maximum displacement of the medium is?
a) - 6 cm
b) 0 cm
c)6 cm
d) 3 cm
According to constructive interference, the maximum displacement of the medium when two identical pulses collide and overlap in a homogeneous medium is equal to 6 cm. Option (c) is correct, therefore.
When two waves collide while moving across the same medium, the result is known as wave interference. Interference includes constructive interference. It happens when two pulses collide and create a bigger pulse. The initial two pulses' amplitudes are added to create the larger, resultant pulse.
This could be carried out when two crests or troughs meet. It could show up anywhere where the two competing waves are displaced upward. But when they descend, the two adverse impacts are also evident.In the picture up top, this is evident. In a homogeneous medium, they are close together since we have two identical wave pluses.
The current amplitude of pluse A is 3 cm.
The pluse B's amplitude is 3 cm.
The sum of the plus amplitudes of the pulses, or 3 cm + 3 cm = 6 cm, is the amplitude or maximum displacement of the medium as the pulses collide and superimpose. So, 6 cm should be the displacement value.
learn more about Constructive interference here:
https://brainly.com/question/16098226
#SPJ11
consider example 3.9 on page 87. suppose that the dog runs at a speed of 7.0 m/s. how far does the dog travel horizontally from the edge of the dock before splashing down?
The dog travels 2.1 meters horizontally from the edge of the dock before splashing down.
When dog runs at speed 7.0m/s,how far he reached the edge of the dock before splashing down?We know that the distance the dog travels horizontally before splashing down is equal to the product of the time in the air and the horizontal velocity of the dog.
Using the equation: distance = velocity x time
We can first solve for the time in the air.
The initial vertical velocity of the dog is zero, and we can use the equation:
distance = 1/2 x acceleration x time⁻²
to find the time it takes for the dog to fall from the edge of the dock to the water.
Assuming a gravitational acceleration of 9.8 m/s⁻², we get:
distance = 1/2 x 9.8 m/s⁻² x time⁻²
0.91 meters = 4.9 x time⁻²
time = sqrt(0.91 / 4.9) = 0.3 seconds
Now that we know the time in the air, we can find the horizontal distance traveled by the dog before splashing down.
Using the equation:
distance = velocity x time
where velocity is the horizontal velocity of the dog, which we know is 7.0 m/s, we get:
distance = 7.0 m/s x 0.3 s = 2.1 meters
The dog travels 2.1 meters horizontally from the edge of the dock before splashing down.
Learn more about Speed and splashing down
brainly.com/question/14575052
#SPJ11
A SHM has the equation y = 2.0cos 4t+ 45) What is the initial phase angle? b) What is the displacement at t=0 s? c) Calculate velocity at t=0 s. d) What is the maximum velocity?
a) The initial phase angle is 45 degrees, (b) displacement at t=0 s is 1.414 m, (c) the velocity at t=0 s is -5.656 m/s, (d) maximum velocity is 1.568 m/s.
What is simple harmonic motion (SHM)?Simple harmonic motion (SHM) is a type of periodic motion in which an object oscillates back and forth around a central point with a constant amplitude and a sinusoidal pattern.
The equation of a simple harmonic motion (SHM) is given by:
y = A cos(ωt + φ)
where A is the amplitude, ω is the angular frequency, t is the time, and φ is the phase angle.
Comparing with the given equation, we have:
A = 2.0
ω = 4
φ = 45 degrees
a) The initial phase angle is 45 degrees.
b) To find the displacement at t=0 s, we substitute t=0 in the given equation:
y = 2.0 cos(4t + 45)
y = 2.0 cos(45)
y = 1.414 m
Therefore, the displacement at t=0 s is 1.414 m.
c) To find the velocity at t=0 s, we differentiate the given equation with respect to time:
v = dy/dt = -2.0ω sin(ωt + φ)
Substituting t=0, we get:
v = -2.0 x 4 sin(45)
v = -8.0 x 0.707
v = -5.656 m/s (Note: the negative sign indicates that the direction of the velocity is opposite to the direction of the displacement)
Therefore, the velocity at t=0 s is -5.656 m/s.
d) To find the maximum velocity, we differentiate the given equation with respect to time and set it equal to zero (since the maximum velocity occurs when the displacement is zero):
v = -2.0ω sin(ωt + φ) = 0
Solving for t, we get:
ωt + φ = nπ (where n is an integer)
4t + 45 = nπ
t = (nπ - 45)/4
At t=0, n=1, so:
t = (1π - 45)/4 = -11.25 degrees
(Note: the negative sign indicates that the displacement is at its maximum position, whereas the velocity is zero)
Substituting this value of t in the expression for velocity, we get:
v = -2.0 x 4 sin(-11.25 + 45)
v = 8.0 x 0.196
v = 1.568 m/s
Therefore, the maximum velocity is 1.568 m/s.
Learn more about periodic motion here:
https://brainly.com/question/28249471
#SPJ1
calculate the ratio of the energy of a 15.0 nm -wavelength photon to the kinetic energy of a 15.0 nm -wavelength electron.
The ratio of the energy of a 15.0 nm-wavelength photon to the kinetic energy of a 15.0 nm-wavelength electron is approximately 1.255.
How to find the ratio of the energy of a photon?The energy of a photon is given by the equation:
[tex]E_p_h_o_t_o_n[/tex] = h*c/λ
where h is Planck's constant, c is the speed of light, and λ is the wavelength of the photon.
Substituting the given values, we get:
[tex]E_p_h_o_t_o_n[/tex] = (6.626 x [tex]10^-^3^4[/tex] J s)*(3.00 x [tex]10^8[/tex] m/s)/(15.0 x [tex]10^-^9[/tex] m)
[tex]E_p_h_o_t_o_n[/tex] = 1.325 x [tex]10^-^1^8[/tex] J
The kinetic energy of an electron is given by the equation:
K = (1/2)mv²
where m is the mass of the electron and v is its velocity.
To find the velocity of an electron with a wavelength of 15.0 nm, we can use the de Broglie equation:
λ = h/p = h/(m*v)
where p is the momentum of the electron.
Solving for v, we get:
v = h/(m*λ)
Substituting the given values, we get:
v = (6.626 x [tex]10^-^3^4[/tex] J s)/((9.109 x [tex]10^-^3^1[/tex] kg)*(15.0 x [tex]10^-^9[/tex] m))
v = 4.659 x [tex]10^6[/tex] m/s
Substituting this value into the equation for kinetic energy, we get:
K = (1/2)(9.109 x [tex]10^-^3^1[/tex] kg)(4.659 x [tex]10^6[/tex] m/s)²
K = 1.055 x [tex]10^-^1^8[/tex] J
Therefore, the ratio of the energy of a 15.0 nm-wavelength photon to the kinetic energy of a 15.0 nm-wavelength electron is:
[tex]E_p_h_o_t_o_n[/tex] /K = (1.325 x [tex]10^-^1^8[/tex] J)/(1.055 x [tex]10^-^1^8[/tex] J) = 1.255.
So, the ratio is approximately 1.255.
Learn more about Planck's constant
brainly.com/question/27389304
#SPJ11
particles of various masses, charges, and speeds are injected into a region in which a uniform field and a uniform field are perpendicular to each other. all the particles are initially moving in the same direction. which two conditions must be simultaneously fulfilled for the particles to continue moving in a straight line after entering the region?
a bicycle travels from a to b. half the time it travels with speed 20 km/h, and half the time with the speed 30 km/h. what is the average speed?
The bicycle travels from a to b. half the time it travels with speed 20 km/h, and half the time with the speed 30 km/h, therefore the average speed of the bicycle is 25 km/h.
To find the average speed of the bicycle, we need to use the formula:
Average Speed = Total Distance / Total Time
Since we don't know the distance between points A and B, we can assume it to be 'd' kilometers.
Let's say the time taken by the bicycle to travel from A to B is 't' hours.
According to the problem statement, the bicycle travels at 20 km/h for half the time and 30 km/h for the other half. This means that it covers the first half of the distance at 20 km/h and the second half at 30 km/h.
Hence, the time taken to cover the first half of the distance is (t/2) hours, and the time taken to cover the second half is also (t/2) hours.
Now, we can calculate the total time taken by the bicycle as follows:
Total Time = (t/2) + (t/2) = t hours
Next, we can calculate the total distance traveled by the bicycle as follows:
Total Distance = Distance Covered in First Half + Distance Covered in Second Half
= (20 km/h) x (t/2) + (30 km/h) x (t/2)
= 25t km
Substituting these values in the formula for average speed, we get:
Average Speed = Total Distance / Total Time
= 25t km / t hours
= 25 km/h
Therefore, the average speed of the bicycle is 25 km/h.
More on speed: https://brainly.com/question/15586792
#SPJ11
what is the average magnitude of the poynting vector 4.50 mi from a radio transmitter broadcasting isotropically (equally in all directions) with an average power of 200 kw?
The average magnitude of the Poynting vector at a distance of 4.50 miles from the transmitter is approximately 40.8 nanowatts per square meter.
This problem is about finding the average magnitude of the Poynting vector, which is a measure of the energy flow of electromagnetic waves, at a distance of 4.50 miles from an isotropic radio transmitter.
The transmitter broadcasts equally in all directions with an average power of 200 kW. We can use a formula that relates the power density of the transmitter to the Poynting vector. By substituting the given values and using the speed of light as the propagation velocity of electromagnetic waves, we can calculate the Poynting vector.
The average magnitude of the Poynting vector at a distance of 4.50 miles from the transmitter is approximately 40.8 nanowatts per square meter.
Learn more about magnitude:
https://brainly.com/question/30881682
#SPJ4
part a what is the highest order that contains the entire visible spectrum? (the wavelength range of the visible spectrum is approximately 400-700 nm .)
The highest order that contains the entire visible spectrum is the first order. The visible spectrum is the range of wavelengths of light that are visible to the human eye.
The first order is the smallest wavelength range that contains the entire visible spectrum, which ranges from approximately 400-700 nm.
This is because the visible spectrum is a relatively small range of the electromagnetic spectrum compared to other regions, such as radio waves or X-rays.
When light is diffracted through a diffraction grating, the first order is the most commonly used order as it contains the majority of the visible spectrum.
However, higher orders can also contain parts of the visible spectrum, but they are less commonly used as they contain smaller ranges of wavelengths.
For more such answers on the Visible spectrum
https://brainly.com/question/9839674
#SPJ11
a crane uses a block and tackle to lift a 2000 N flagstone to a height of 30 m. How much work is done on the flagstone
satellite motion: if earth had twice its present mass but it orbited at the same distance from the sun as it does now, its orbital period would be 1 year 1,5 year 2 year 2,5 year
The orbital period of the Earth around the Sun is determined by its distance from the Sun and its mass. If the Earth had twice its present mass but orbited at the same distance from the Sun, its gravitational attraction to the Sun would be stronger, resulting in a longer orbital period. Using Kepler's third law of planetary motion, we can calculate the new orbital period as follows:
T^2 = (4π^2/G) x (r^3/m)
where T is the orbital period, G is the gravitational constant, r is the distance from the Earth to the Sun, and m is the mass of the Earth.
Plugging in the values, we get:
T^2 = (4π^2/6.6743 x 10^-11) x [(149.6 x 10^6)^3 / (2 x 5.9722 x 10^24)]
T^2 = 1.085 x 10^20
T = √(1.085 x 10^20)
T = 1.09 x 10^10 seconds
Converting this to years, we get:
T = 346 years
Therefore, if the Earth had twice its present mass but orbited at the same distance from the Sun as it does now, its orbital period would be approximately 346 years.
To know more about Kepler's third law :
https://brainly.com/question/30404084
#SPJ11
given the temperature readings in the topmost tube (in the system diagrammed), which would be reasonable temperatures for points 1 to 5 in the lower tube?
To help you determine the reasonable temperatures for points 1 to 5 in the lower tube, we'll need to consider the given temperature readings in the topmost tube and the temperature changes in the system.
Let's go through the steps to find the temperatures for each point.
Analyze the temperature readings in the topmost tube.
- Observe and record the temperatures at different points in the topmost tube.
Understand the heat transfer process in the system.
- Consider the direction of heat flow, such as from hot to cold regions.
Determine the temperature differences between the tubes.
- Based on the heat transfer process, estimate the temperature differences between the corresponding points in the topmost and lower tubes.
Calculate the temperatures for points 1 to 5 in the lower tube.
- Subtract the estimated temperature differences from the temperatures of the corresponding points in the topmost tube.
By following these steps, you will be able to find the reasonable temperatures for points 1 to 5 in the lower tube based on the given temperature readings in the topmost tube.
*complete question: Given the temperature readings in a topmost tube, which would be reasonable temperatures for points 1 to 5 in the lower tube?
More on temperature: https://brainly.com/question/26228909
#SPJ11
a piece of wood is has a density of 0.600 g/cm3. when dipped in water, what fraction of the wood is submerged inside water? (give answer to 3 significant figures)
To determine the fraction of the wood submerged in water, we need to compare the density of the wood to the density of water.
The density of water is 1.000 g/cm3 at standard temperature and pressure.
If the wood has a density of 0.600 g/cm3, it is less dense than water, which means it will float on water.
To determine the fraction of the wood submerged in water, we can use the following formula:
fraction submerged = (volume submerged) / (total volume)
Since the wood floats on water, the volume of water displaced by the wood is equal to the volume of the submerged portion of the wood.
The total volume of the wood is equal to its mass divided by its density:
total volume = mass / density
We don't have the mass of the wood, but we can use any arbitrary value to determine the fraction submerged.
Let's assume the wood has a mass of 100 g.
total volume = mass / density = 100 g / 0.600 g/cm3 = 166.67 cm3
Now, let's assume that when the wood is submerged in water, it displaces 80 cm3 of water.
fraction submerged = (volume submerged) / (total volume) = 80 cm3 / 166.67 cm3 = 0.48
Therefore, approximately 48% of the wood is submerged in water.
To know more about fraction visit link :
https://brainly.com/question/31215473
#SPJ11
starting from rest, a disk rotates about its central axis with constant angular acceleration. in 5.0 s, it rotates 50 rad. what is the instantaneous angular velocity of the disk at the end of the 20.0 s?
The instantaneous angular velocity is 20.0 s is 400 rad/s.
What is the final instantaneous angular velocity of a disk rotating about its central axis with constant angular acceleration?Since the angular acceleration is constant, we can use the formula:
[tex]θ = 1/2 * α * t^2 + ω0 * t[/tex]
where
[tex]θ = angle rotated = 50 rad[/tex]
[tex]α = angular acceleration[/tex]
[tex]t = time = 5.0 s[/tex]
[tex]ω0 = initial angular velocity = 0 (starting from rest)[/tex]
Solving for α, we get:
[tex]α = 2 * (θ - ω0 * t) / t^2 = 2 * 50 rad / 5.0 s^2 = 20 rad/s^2[/tex]
Now, using the formula:
[tex]ω = α * t + ω0[/tex]
where
ω = instantaneous angular velocity at the end of 20.0 s (what we need to find)
[tex]α = angular acceleration = 20 rad/s^2[/tex]
[tex]t = time = 20.0 s[/tex]
[tex]ω0 = initial angular velocity = 0 (starting from rest)[/tex]
we get:
[tex]ω = 20 rad/s^2 * 20.0 s + 0 = 400 rad/s[/tex]
Therefore, the instantaneous angular velocity of the disk at the end of 20.0 s is 400 rad/s.
Learn more about angular acceleration
brainly.com/question/29428475
#SPJ11