At given mass 5.0kJ while the work being twice as much Speed=Distance/time = 2/5 = 0.4m/s
What is mass?A physical body's overall composition is measured by its mass. This term also measures inertia, or the body's resistance to acceleration when a net force is applied. The mass of a thing also affects how strongly it attracts other bodies through gravity.
The SI base unit for mass is the kilogram. In physics, mass is a way to quantify inertia, a fundamental property of all matter. In essence, it's the resistance of a mass of matter to changing its direction or speed in response to the application of a force. The more mass a body has, the smaller the change that is brought about by an applied force.
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When the effort is multiplied by the provided mass, 5.0 kJ, the speed is equal to 2/5 of that amount, or 0.4 m/s.
What is mass?The mass of a physical body is a measure of its entire makeup.
Inertia, or the body's resistance to acceleration when a net force is applied, is also measured by this term.
The strength of a body's gravitational pull on other bodies is also influenced by its mass.
The kilogram serves as the SI base unit for mass.
Mass is used in physics to express inertia, a fundamental characteristic of all matter.
A mass of matter's resistance to changing its direction or speed in response to the application of a force is what it essentially is.
The change produced by an applied force is smaller the more mass a body has.
Therefore, when the effort is multiplied by the provided mass, 5.0 kJ, the speed is equal to 2/5 of that amount, or 0.4 m/s.
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On a frictionless surface. An 80kg person was with a 50kg person at rest. After they pushed each other, B moved at 8.0 m/s to the right. Whar is the velocity of A ? If A = 80 kg and B = 50 kg
Given:
The mass of the person A is
[tex]m_A=\text{ 80 kg}[/tex]The mass of the person B is
[tex]m_B\text{ = 50 kg}[/tex]The initial velocity of A and B is zero as it is at rest.
The final velocity of person B is
[tex]v_B=\text{ 8 m/s }[/tex]towards right.
To find the velocity of A.
Explanation:
According to the conservation of momentum, the final velocity of person A will be
[tex]\begin{gathered} m_A\times0+m_B\times0=m_Av_A+m_Bv_B \\ v_B=-\frac{m_Bv_B}{m_A} \end{gathered}[/tex]On substituting the values, the final velocity of person A will be
[tex]\begin{gathered} v_B=-\frac{50\times8}{80} \\ =-5\text{ m/s} \end{gathered}[/tex]Here, the negative sign indicates that the final velocity i
Two blocks are stacked on top of each other on the floor of an elevator as shown. The mass of Block 2 (bottom) is 3.0 kg and the mass of Block 1 (upper) is 2.0 kg. The elevator is accelerating upwards at a constant rate of 1.6 m/s2.Find the magnitude of the force that Block 2 exerts on the floor of the elevator.
The magnitude of the force exerted by Block 2 takes into account the mass of Block 1 because it's above it, so the force must include both masses.
Use Newton's Second Law.
[tex]\Sigma F_y=ma[/tex][tex]\begin{gathered} N-W=(m_1+m_2)a \\ N-(m_1+m_2)g=(m_1+m_2)a_{} \\ N=(m_1+m_2)(g+a) \end{gathered}[/tex]Use the given magnitudes to find the force N.
[tex]\begin{gathered} N=(2\operatorname{kg}+3\operatorname{kg})(9.8\cdot\frac{m}{s^2}+1.6\cdot\frac{m}{s^2}) \\ N=5\operatorname{kg}\cdot11.4\cdot\frac{m}{s^2} \\ N=57N \end{gathered}[/tex]Therefore, the force exerted by Block 2 is 57 Newtons.
A tennis player serves a tennis ball such that it is moving horizontally when it leaves the racquet. When the ball travels a horizontal distance of 11 m, it has dropped 59 cm from its original height when it left the racquet. What was the initial speed, in m/s, of the tennis ball? (Neglect air resistance) m/s
Sound waves will travel faster on a dry day than on a humid day of the same temperature. Is this true or false?
The speed of a sound wave depends on the density of the medium on which it propagates. Then, it is affected by temperature and humidity.
The speed of sound in dry air is lower than in moist air.
Then, it is not true that sound waves will travel faster on a dry day.
Therefore, the answer is:
[tex]\text{False}[/tex]1. Describe your observations. Why do you think the ball moves (or does not move) as it is kicked on this soccer field?2. What should a pilot do to make sure an airplane stays in stable and consistent flight? Focus your response on the four forces of flight.
To make it fly, four forces are in play. The very same four forces also allow for the flight of an airplane. The four factors are thrust, drag, lift, and weight.
What does "field" actually mean?Fields are complex algebraic structures that resemble number systems. The mathematical areas of rational, real, & complex numbers—abbreviated Q, R, & C—are well-known examples. For reasons that will be covered later, the numbers with the prefix Z are a quasi of a field.
The meaning of a job fieldCareer sectors are a way to group distinct career types based on traits they have in common. These categories can be used by people to narrow down their employment alternatives and choose an appropriate course.
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Circle the 2 ranges of the spectrum that roughly correspond to both the frequency and wavelength of your musical note.So two circles: even though this is a light spectrum, there are frequencies and wavelengths of light that correspond to those particular frequencies and wavelengths of sound. They are not at the same place since the speeds of sound and light are different.
The rough frequency for the musical note audible to the human ear is 20 Hz - 20 kHz and the value for the wavelength is 17 m and 17 mm.
Radio waves are the wave that lies within the range of the frequencies and the wavelengths of the sound.
The image is given below
How many oxygen atoms are in the following formula? 2H2SO4 (the second two and four are down)A.2B.8C.4D.1
The given chemical formula is,
[tex]H_2SO_4[/tex]The number of oxygen atoms in the sulphuric acid formula is,
[tex]n=4[/tex]Hence,
If the current is 10A (Ampere) ,when connected to 1,000 volt line, find the resistance.
Apply Ohm's Law
V = I x R
Where:
V= voltage = 1,000 volt
I = current = 10 A
R= resistance = ?
Isolate R
R = V / I = 1,000 / 10 = 100 ohms
The magnitude of a vector represents its _____.Question 10 options:velocitydirectionsizecolor
Size
Explanations:A vector quantity is one that has both magnitude and direction
The magnitude of the physical quantity represents its size
Therefore, the most suitable choice is size
Suppose the torque produced by a wrench on a stubborn nut is 30 Nm. If the lever arm is doubled with no changein force, what is the resulting torque?
Given data
*The torque produced by a wrench on a stubborn is 30 N.m
The formula for the torque is given as
[tex]T\text{=F.r}[/tex]*Here F is the perpendicular force
*Here r is the distance
Now, if the lever arm is doubled with no change in force, then the resulting torque is also gets doubled
[tex]T=60\text{ N.m}[/tex]Choose the best answer from the choices below:The perpendicular bisector of a chord ____.A. bisects the chordB. is less than the radiusC. is perpendicular to any chordD. passes through the center of the circle
We have the next theorem.
The perpendicular bisector of any chord of a circle will pass through the center of the circle.
In our case
The perpendicular bisector of a chord passes through the center of the circle.
Therefore the correct choice
The circular pistons in a hydraulic press are 8 and 40 cm in diameter. What is the force in the bigger piston when a 50 N force is applied to the small piston?
ANSWER
1250 N
EXPLANATION
We have a hydraulic press, which is something like this:
The pressure of the fluid inside the press is the same on both pistons. The pressure is related to the force and the area of the piston by,
[tex]P=\frac{F}{A}[/tex]As stated before, P1 = P2,
[tex]\frac{F_1}{A_1}=\frac{F_2}{A_2}[/tex]We know the diameter of the pistons d1 = 8cm and d2 = 40cm, and the force applied to the small piston is F1 = 50N. We have to solve the equation above for F2,
[tex]F_2=F_1\cdot\frac{A_2}{A_1}[/tex]The pistons are circular, thus the area is.
[tex]A=\pi\cdot r^2=\pi\cdot(\frac{d}{2})^2=\pi\cdot\frac{d^2}{4}_{}[/tex]Replace into the equation of the force,
[tex]F_2=F_1\cdot\frac{\pi\cdot\frac{d^2_2}{4}}{\pi\cdot\frac{d^2_1}{4}}[/tex]π/4 cancels out,
[tex]F_2=F_1\cdot\frac{d^2_2}{d^2_1}[/tex]Usually, we have to put all the units so that they are consistent - in this case, that would mean to convert the diameters to meters, but since the diameters are dividing their units will cancel out, so we don't need to convert those measures from centimeters to meters.
Replace F1, d1, and d2 for their values,
[tex]F_2=50N\cdot\frac{40^2cm^2}{8^2cm^2}[/tex][tex]F_2=50N\cdot25=1250N[/tex]The force in the bigger piston is 1250 N.
The velocity as a function of time of a moving object is presented by the graph to the right. Use the graph below for the following questions.What is the magnitude of acceleration of the object between 6 s and 10 s in m/s per second?
ANSWER:
1 m/s per second
STEP-BY-STEP EXPLANATION:
We can calculate the acceleration by the following formula and with the help of the graph.
Just like this:
[tex]\begin{gathered} a=\frac{\Delta v}{\Delta t}=\frac{v_f-v_i}{t_f-t_i} \\ \\ \text{ We replacing} \\ \\ a=\frac{0-4}{10-6}=\frac{-4}{4}=-1\text{ m/s}^2 \end{gathered}[/tex]The acceleration is negative, this tells us that from the second 6 the object began to slow down, but its magnitude is 1 m/s²
A stone is suspended from the free end of a wire that is wrapped around the outer rim of a pulley, similar to what is shown in (Figure 1). The pulley is a uniform disk with mass 11.0 kg and radius 27.0 cm and turns on frictionless bearings. You measure that the stone travels a distance 12.8 m during a time interval of 3.50 s starting from rest.
3.10 kg is the mass of the stone suspended from the free end of a wire that is wrap around the outer rim of a pulley
The acceleration along the y-direction is
a = 2 y / t^2
= 2 ×12.8/ 3.5^2
= 4.17 m/s^2
Torque on the pulley
torque = T ×R
= I × α
= T * R = 0.5 M R^2 × (a / R)
= T = 0.5, m a = 0.5 × 11 ×3.56 = 19.58 N
In the vertical direction, the equation for motion is
mg - T = ma
=m = T / g-a
= 19.58 / 9.8 - 3.566
=3.10 kg
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If 100 g of gold-198 decays to 12.5 g in 25.3 days, what is the half-life of gold-198
The coefficient of kinetic friction is NOT1) the slope of the line on the kinetic friction force vs. normal force graph.2) designated μk.3) more than the coefficient of static friction.4) equal to the quotient of the kinetic friction force and the normal force.
The magnitude of the kinetic friction is proportional to the normal force acting between the two bodies. Mathematically,
[tex]\begin{gathered} f_k\propto_{}N \\ f_k=\mu_kN \end{gathered}[/tex]Where N is the normal force. The proportionality constant μ_k is known as the coefficient of kinetic friction.
The coefficient of kinetic friction is given as,
[tex]\mu_k=\frac{f_k}{N}=\text{ slope}[/tex]The force of kinetic friction is always less than the force of static friction. Therefore, the coefficient of kinetic friction is always less than the coefficient of static friction.
Hence, option (3); The coefficient of kinetic friction is not more than the coefficient of static friction is the correct choice.
When building an electronic toy, a buzzer requires 30 mA (.03 amps) of current. If the voltage from the batteries for the toy add up to 12 volts, what sized resister must be used to ensure the buzzer receives the necessary 30 mA of current. Enter the numerical value rounded to the nearest whole number. For example if you calculate 327.45 ohms, enter 327.
Ohm's law states that the resistance, current and voltage are related from the equation:
[tex]R=\frac{V}{I}[/tex]In this case we know the voltage is 12 V and the current is 0.3 A, plugging these values we have:
[tex]\begin{gathered} R=\frac{12}{0.3} \\ R=400 \end{gathered}[/tex]Therefore, the resitsance need is 400 Ohms.
Gravitational force isa. the force of attraction between objects b. is dependent on mass and distance c. measured in newtonsd. all a, b and c
We will have the following:
Gravitational force is:
* The force of attraction between objects-
* Is dependent on mass and distance.
* Measured in Newtons.
So, the solution is d. All, a, b and c.
A geosynchronous satellite is to be placed in orbit about a planet that has a radiusof 6000 km, mass - 6.00 x 1024 kg, and whose period of rotation - 20 hours. Howfar from the center of the planet should be the orbit of the satellite? Mass ofsatellite = 500 kg.O 37,500 km© 400,000 km0 75.000 kmO 23,300 km
We will have the following:
We must solv using the orbital period eqiation, that is:
[tex]\frac{T^2}{R^3}=\frac{4\pi^2}{GM}[/tex]Where M is the mass of the planet, thus:
[tex]\begin{gathered} R^3=\frac{GMT^2}{4\pi^2}\Rightarrow R=\sqrt[3]{\frac{GMT^2}{4\pi^2}} \\ \\ \Rightarrow R=\sqrt[3]{\frac{(6.674\ast10^{-11})(6.00\ast10^{24}kg)(20h\ast3600s/1h)^2}{4\pi^2}}\Rightarrow R=37462136.66...m \\ \\ \Rightarrow R\approx37500km \end{gathered}[/tex]So, the radius is approximately 37500 km.
What is the range of the function f(x) = x4 – 2x2 + 1?
Answer:
all real numbers greater than or equal to zero
Explanation:
The range of a function is defined as all possible output values it can take.
Now in our case, we have the function
[tex]f(x)=x^4_{}-2x^2+1[/tex]Since,
[tex]x^4\ge2x^2[/tex]for all values of x, this tells us that the expression
[tex]x^4-2x^2+1[/tex]will always be greater than zero.
Therefore, we can say
[tex]f(x)=x^4_{}-2x^2+1\ge0[/tex]This tells us that the range of the function is all real numbers greater than or equal to zero.
Therefore, the correct answer choice is the following.
all real numbers greater than or equal to zero
Cleveland is performing an experiment, testing to see if increasing the acidity of the soil in which sunflower plants are growing makes them flower sooner. In this experiment, what are some values that Cleveland will want to hold constant.
Answer:
The temperature the plants are grown in
The amount of water the sunflowers get
The amount of light the sunflowers get
Explanation:
They want to know if increasing the acidity of the soil makes the plants flower sooner. So, they need to hold constant all the other variables in that area not the acidity of the soil or the day the plants begin to flower.
Therefore, the answers are
The temperature the plants are grown in
The amount of water the sunflowers get
The amount of light the sunflowers get
A cannon ball is launched at an 18 degree angle with a speed of 25 m/s. What is it’s horizontal velocity at the peak of its arc?
Given that the cannon ball is launched at an 18 degree angle
Initial speed = 25 m/s
So the initial velocity in the horizontal direction (say v_x) will be
[tex]v_x=25cos18\degree[/tex]The horizontal component of velocity will be constant throughout the motion since there is no acceleration in the x-direction, only acceleration due to gravity in y-direction.
So at the peak of its arc the velocity will be the same to its initial value, i.e.
[tex]v_{peak,x}=25cos18\degree=23.78\text{ m/s}[/tex]Result: Horizontal velocity at peak of its arc will be 23.78 m/s.A 7.8-meter long copper wire has a diameter of 3.3x10exp(- ) 2 m. Determine the resistance of the wire.
In order to calculate the wire resistance, we can use the formula below:
[tex]R=\frac{p\cdot L}{A}[/tex]Where p is the resistivity, L is the length and A is the cross-section area.
For copper, we have p = 1.72 * 10^-8.
Then, using L = 7.8 m and A = pi*r² (area of a circle), we have:
[tex]\begin{gathered} R=\frac{1.72\cdot10^{-8}\cdot7.8}{\pi\cdot(\frac{3.3}{2}\cdot10^{-2})^2} \\ R=\frac{13.416\cdot10^{-8}}{3.1416\cdot2.7225\cdot10^{-4}} \\ R=\frac{13.416\cdot10^{-8}}{8.553\cdot10^{-4}} \\ R=1.57\cdot10^{-4} \end{gathered}[/tex]Therefore the wire resistance is 1.57 * 10^-4 ohms.
A 1.3kg rocket is launched straight up with an initial speed of 11m/s. How high will it go up if we ignore air resistance
The initial speed of the rocket is u = 11 m/s
The mass of the rocket is m = 1.3 kg
The kinetic energy of the rocket will be
[tex]\begin{gathered} K\mathrm{}E\mathrm{}=\frac{1}{2}mu^2 \\ =78.65\text{ J} \end{gathered}[/tex]The kinetic energy will be converted to potential energy
[tex]KE=P\text{E}[/tex]Also, the potential energy will be
[tex]PE=\text{mgh}[/tex]Here, the acceleration due to gravity is g = 9.8 m/s^2
The height up to which the rocket will reach is h.
Substituting the values , the height will be
[tex]undefined[/tex]78.65
Hello I really need help with this question please!! Explain the energy conversations that occur as a basketball falls, hits the ground, and bounces up ignore frictional forces. ???
We know that, if we ignore frictional forces, the mechanical energy of the system is conserved, this means that all point of time we have that:
[tex]K_i+U_i=K_f+U_f[/tex]This means that as the ball is falling the potential energy is being converted to kinetic energy until all the potential energy becomes zero (when the ball hits the ground); at this point all the energy is kinetic. After this point all the kinetic energy of the ball is being converted to potential energy while the ball rises until it reaches the maximum height (which has to be the same from where the ball started); at this point all the energy is potential energy since the ball stops for a fraction of time. Then the process begins again and the potential energy is being converted into kinetic energy as we explained earlier and the process goes on.
When two waves interfere completely destructively, what is true of the resultant wave?A. has a shorter wavelengthB. has a larger amplitude.c. has a smaller amplitude.D. has a longer wavelength.
When two waves interefere destructively, the two waves cancel each other out. This results in a lower amplitude.
Therefore, when two waves interfere destructively, the resultant wave will have smaller amplitude.
What is Einstein‘s Theory of special relativity?
To find:
The special theory of relativity.
Explanation:
The special theory of relativity is based on two postulates:
1. The laws of physics are the same for the observers in the same inertial frames of reference.
2. The speed of light is constant regardless of the relative motion of the observer or the source of light.
Select all the wave properties that can change how we perceive light waves.amplitudeamplitudecrestscreststimetimefrequency
The properties that change how we perceive light waves are the following:
The amplitude of the light wave changes the brightness of light relative to other light waves of the same wavelenghth.
The frequency of the light wave changes the color and the type of the light wave.
What is the mass of 61.5 mL of ethanol? The density of ethanol at room temperature = 0.789 g/mL.
We are given that the density of ethanol is 0.789 g/mL. Density is defined as:
[tex]D=\frac{m}{V}[/tex]Where:
[tex]\begin{gathered} D=\text{ density} \\ m=\text{ mass} \\ V=\text{ volume} \end{gathered}[/tex]Since we are asked about the mass we will multiply the formula by "V" on both sides:
[tex]DV=m[/tex]Substituting the values we get:
[tex](\frac{0.789g}{mL})(61.5mL)=m[/tex]Solving the operations we get:
[tex]48.5g=m[/tex]Therefore, the mass of ethanol is 48.5 grams.
The mass of a hot-air balloon and its cargo (not including the air inside) is 200 kg. The airoutside is at a temperature of 10°C and a pressure of 1 atm = 10^5 N/m2. The volume of the balloon is 400 m^3. Which temperature below of the air in the balloon will allow the balloon to just lift off? (Air density at 10°C is 1.25 kg/m^3.)a. 37°Cb. 69°Cc. 99°Cd. 200°C
Use the ideal gas law for the initial and final conditions.
[tex]\begin{gathered} P_iV_i=n_iR_iT_i \\ P_fV_f=n_fR_fT_f \end{gathered}[/tex]Where P_i = 10^5 N/m^2, V_i = 400 m^3, T = 10 C = 283 K. So, we have the expression about the initial conditions
[tex]\frac{10^5N}{m^2}\cdot400m^3=n_iR_i\cdot283K[/tex]For the second expression, the final pressure and the final volume are the same because the hot-air balloon is open to the atmosphere.
[tex]\frac{10^5N}{m^2}\cdot400m^3=n_fR_fT_f[/tex]Then, use the density formula to find the initial mass and the final mass.
[tex]\begin{gathered} m_i=\rho_iV=\frac{1.25\operatorname{kg}}{m^3}\cdot400m^3=500\operatorname{kg} \\ m_f=m_i-200\operatorname{kg}=500\operatorname{kg}-200\operatorname{kg}=300\operatorname{kg} \end{gathered}[/tex]Now, we find the number of moles (n) by dividing the masses.
[tex]\frac{n_i}{n_f}=\frac{500\operatorname{kg}}{300\operatorname{kg}}\approx1.67[/tex]At last, we divide the initial equations (ideal gas law) to find the final temperature.
[tex]\frac{10^5\cdot400}{10^5\cdot400}=\frac{n_iR_i\cdot283K}{n_fR_fT_f}[/tex]The constant R is the same in both cases and use the ratio of moles.
[tex]\begin{gathered} 1=\frac{1.67\cdot283K}{T_f} \\ T_f=472.61K\approx473 \end{gathered}[/tex]But, in Celsius, the temperature is 200 Celcius.
Therefore, the answer is D.