A car runs at a constant speed of 15ms-1 for 30secs, and then accelerates uniformly to a speed of 25ms-1 over a time of 20secs. this speed is maintain for the next 300secs before the car is brought to rest with uniform deceleration in 30secs.
a. draw the velocity time graph of the motion. and calculate
b. the total distance traveled by the car
c. average speed of the car
Answers
Answer:
a. Please find the attached velocity time graph of the car's motion created with Microsoft Excel
b. The total distance traveled by the car is 8,725 meters
c. The average speed of the car is 22.9605263 m/s
Explanation:
The given parameters of the motion are;
The initial speed of the car, v₁ = 15 m/s
The time during which the car runs at the initial speed, t₁ = 30 seconds
The new speed the car then accelerates at 'a₁' to, v₂ = 25 m/s
The duration it takes for the car to accelerate to the new speed = 20 seconds
The time during which the car runs at the initial speed = 300 seconds
The time it takes the car to be brought to rest with a deceleration, 'a₂' from the new speed (20 m/s) = 30 seconds
The final speed of the car at rest, v₃ = 0 m/s
The acceleration, a₁ = (v₂ - v₁)/t₁ = (25 - 15)/20 = 1/2 m/s²
The deceleration , a₂ = (v₃ - v₂)/t₁ = (0 - 25)/30 = -5/6 m/s²
a. Please find attached the drawing of the velocity time graph of the motion created with Microsoft Excel
b. The total distance traveled by the car, 'Δx', is given b the area under the velocity time graph as follows;
Area of trapezoid, A₁ = (320 + 300)/2 × 10 = 3,100
Area of rectangle, A₂ = 15 × 350 = 5,250
Area of triangle, A₃ = 1/2×30×25 = 375
The total area under the velocity time graph = A₁ + A₂ + A₃ = 3,100 + 5,250 + 375 = 8,725
The total area under the velocity time graph = The total distance traveled by the car, Δx = 8,725 meters
c. The average speed of the car is given as follows;
[tex]The \ average \ speed \ of \ the \ car, \overline v =\dfrac{\Delta x}{\Delta t} = \dfrac{The \ total \ distance \ traveled by \ the \ car}{The \ total \ time \ the \ car \ travels}[/tex]
Where;
Δt = The total time during which the car travels
∴ The average speed of the car = 8,725 m/(380 s) = 22.9605263 m/s
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