Answer:
v2f = +15.8 m/s
Explanation:
Conservation law of linear momentum:
m1v1i + m2vi2 = m1v1f + m2v2f
Given:
m1 = 1.1 × 10^3 kg
m2 = 2.3 × 10^3 kg
v1i = +22.0 m/s
v2i = 0
v1f = -11.0 m/s
v2f = ?
Re-arranging the conservation law, we get
m1v1i = m1v1f + m2v2f
Solving for v2f,
m2v2f =m1(v1i - v1f)
or
v2f = m1(v1i - v1f)/m2
= (1.1 × 10^3 kg)(22.0 m/s - (-11.0 m/s))/(2.3 m/s)
= (1.1 × 10^3 kg)(33.0 m/s)/(2.3 × 10^3 kg)
= +15.8 m/s
One thing you really notice is the complex, feathery, knotty structure of the gas and dust in our galaxy. If you look around, you can see a couple more objects that might be good candidates for being other galaxies with their own star-forming regions. What are these objects called
Answer:
Orion Nebula & cone nebula
Explanation:
From the huge, youthful stars that are forming the nebula to the pillars of thick gas that could be the homes of burgeoning stars, the Orion Nebula is a picture book of star formation. The four heaviest stars in the nebula reside in the bright central field. Since the stars are arranged in a trapezoid shape, they are known as the Trapezium.
These stars' ultraviolet radiation is cutting a hole in the nebula and stars that are already young enough to have disks of material encircling them can be seen near the Trapezium stars. Protoplanetary disks, also known as (proplyds) are too small to be seen distinctly and the disks are the foundation of solar systems.
The Cone Nebula is a monstrous creation, which resembles a nightmare beast flaring up from a crimson sea, is simply a benevolent pillar of gas and ashes. The Cone Nebula is so identified because it has a conical appearance in ground-based photographs. This massive pillar is located in a tumultuous star-forming area with gnarled mountainpeak of cold gas and dust is visible.
Convex lenses cause light rays to _____.
Answer:
to meet at a single point
(causing rays of light that are initially parallel to meet at a single point)
hope this helps:)
Explanation:
Answer:
focus
Explanation:
see more here
https://youtu.be/CJ6aB5ULqa0
Are surface currents warm or cold?
A:war m
B:cold
Answer:
Cold
Explanation:
Im pretty sure im sorry if I am wrong
the caste system is an example of
Answer:
It is example of Closed system
Water has a heat capacity of 4.184 J/g °C. If 50 g of water has a temperature of 30°C and a piece of hot copper is added to the water causing the temperature to increase to 70°C. What is the amount of heat absorbed by the water?
Answer:
Q = 8368 Joules.
Explanation:
Given the following data;
Mass = 50 g
Initial temperature = 30°C
Final temperature = 70°C
Specific heat capacity = 4.184 J/g °C
To find the amount of heat absorbed by the water;
Heat capacity is given by the formula;
[tex] Q = mcdt[/tex]
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
dt = T2 - T1
dt = 70 - 30
dt = 40°C
Substituting the values into the equation, we have;
[tex] Q = 50*4.184*40[/tex]
Q = 8368 Joules.
A man on the Moon observes two spaceships coming toward him from opposite directions at speeds of 0.600c and 0.600c. What is the relative speed of the two ships as measured by a passenger on either one of the spaceships
Answer:
If we use the equation for the transformation of velocities for moving frames:
v' = (v - u) / (1 - u * v / c^2) where we measure the speed of v' approaching from the left where v is in a frame moving at -u towards v'
v' = (.6 c - (-.6 c)) / (1 - (-.6 c) * .6 c / c^2) = 1.2 c / (1 + .6 * .6)
or v' = 1.2 c / (1 + .36) = .88 c
v is approaching from the left at .6 c in the reference frame and the other frame approaches from the right at -.6 c with speed u (-.6 c) and we measure the speed of v as seen in the frame moving to the left
Light of wavelength 580 nm is incident on a slit of width 0.30 mm. An observing screen is placed 2.0 m past the slit. Find the distance on the screen of the first order dark fringe from the center of the pattern.
Answer:
Y = 3.87 x 10⁻³ m = 3.87 mm
Explanation:
This problem can be solved by using Young's double-slit experiment formula:
[tex]Y = \frac{\lambda L}{d}[/tex]
where,
Y = fringe spacing = ?
L = slit to screen distance = 2 m
λ = wavelength of light = 580 nm = 5.8 x 10⁻⁷ m
d = slit width = 0.3 mm = 3 x 10⁻⁴ m
Therefore,
[tex]Y = \frac{(5.8\ x\ 10^{-7}\ m)(2\ m)}{3\ x\ 10^{-4}\ m}[/tex]
Y = 3.87 x 10⁻³ m = 3.87 mm
I NEED HELP THIS QUESTION IS SO HARDDD!!
Answer:
c
Explanation:
search it up
Answer:
Option A.
Explanation:
Because this is a lunar eclipse it normally happens 2 times a year. This is a decently rare phenomenon due to the positions they have to be in to make a lunar eclipse. Therefore, it is option A.
g Monochromatic light with wavelength 633 nn passes through a narrow slit and a patternappears on a screen 6.0 m away. The distance on the screen between the centers of thefirst minima on either side of the screen is 32 mm. How wide (in mm) is the slit
Answer:
d = 1.19 x 10⁻⁴ m = 0.119 mm
Explanation:
This problem can be solved by using Young's double-slit experiment formula:
[tex]Y = \frac{\lambda L}{d}[/tex]
where,
Y = fringe spacing = 32 mm = 0.032 m
L = slit to screen distance = 6 m
λ = wavelength of light = 633 nm = 6.33 x 10⁻⁷ m
d = slit width = ?
Therefore,
[tex]0.032\ m = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{d}\\\\d = \frac{(6.33\ x\ 10^{-7}\ m)(6\ m)}{0.032\ m}[/tex]
d = 1.19 x 10⁻⁴ m = 0.119 mm
A 0.413 kg block requires 1.09 N
of force to overcome static
friction. What is the coefficient
of static friction?
(No unit)
PLEASE HELP!
Answer:
static friction=0.126
24. A anvil with a mass of 60 kg falls from a height of 9.5 m. How fast is it going right
before it hits the ground?
V= I*R
V = voltage (measured in volts) V
I = current (measured in amperes) A
R = resistance (measured in Ohms) Ω
So they give us this
V=IR
V= 1.8
I=0.4
R=?
So we insert the thing that we know.
1.8=0.4*R
We need to leave our unknown value alone. So if our value of 0.4 is multiplying the unknown value it passes to the other side dividing.
So we have this.
Lastly we solve.
R=4.5ohms
The formula to find R is V=IR
V/I=R
So the resistance will be the Voltage divided by the Current
Mass, volume and density are all properties of
Answer:
Properties of matter
Explanation:
All properties of matter are either extensive or intensive and either physical or chemical. Extensive properties, such as mass and volume, depend on the amount of matter that is being measured. Intensive properties, such as density and color, do not depend on the amount of matter.
Answer:
The pythagoream theorem
Explanation:
What can be the maximum value of the original kinetic energy of disk AA so as not to exceed the maximum allowed value of the thermal energy
The question is incomplete. The complete question is :
In your job as a mechanical engineer you are designing a flywheel and clutch-plate system. Disk A is made of a lighter material than disk B, and the moment of inertia of disk A about the shaft is one-third that of disk B. The moment of inertia of the shaft is negligible. With the clutch disconnected, A is brought up to an angular speed ?0; B is initially at rest. The accelerating torque is then removed from A, and A is coupled to B. (Ignore bearing friction.) The design specifications allow for a maximum of 2300 J of thermal energy to be developed when the connection is made. What can be the maximum value of the original kinetic energy of disk A so as not to exceed the maximum allowed value of the thermal energy?
Solution :
Let M.I. of disk A = [tex]$I_0$[/tex]
So, M.I. of disk B = [tex]$3I_0$[/tex]
Angular velocity of A = [tex]$\omega_0$[/tex]
So the kinetic energy of the disk A = [tex]$\frac{1}{2}I_0\omega^2$[/tex]
After coupling, the angular velocity of both the disks will be equal to ω.
Angular momentum will be conserved.
So,
[tex]$I_0\omega_0 = I_0 \omega + 3I_0 \omega$[/tex]
[tex]$I_0\omega_0 = 4I_0 \omega$[/tex]
[tex]$\omega = \frac{\omega_0}{4}$[/tex]
Now,
[tex]$K.E. = \frac{1}{2}I_0\omega^2+ \frac{1}{2}3I_0\omega^2$[/tex]
[tex]$K.E. = \frac{1}{2}I_0\frac{\omega_0^2}{16}+ \frac{1}{2}3I_0\frac{\omega_0^2}{16}$[/tex]
[tex]$K.E. = \frac{1}{2}I_0\omega_0^2 \left(\frac{1}{16}+\frac{3}{16}\right)$[/tex]
[tex]$K.E. = \frac{1}{2}I_0\omega_0^2\times \frac{1}{4}$[/tex]
[tex]$\Delta K = \frac{1}{2}I_0\omega_0^2 - \frac{1}{2}I_0\omega_0^2 \times \frac{1}{4} $[/tex]
[tex]$2300=\frac{3}{4}\left(\frac{1}{2}I_0\omega_0^2\right)$[/tex]
[tex]$\frac{1}{2}I_0\omega_0^2=2300 \times \frac{4}{3 } \ J $[/tex]
Therefore, the maximum initial K.E. = 3066.67 J
Henry has 8 pieces of pizza that he wants to give equally to 3 friends how much pizza will each friend get
Compare the number of electrons with the number of protons in a charged object.
Help I only have 7 minutes help now
If an electromagnetic wave has a frequency of 6×10^5 hz, what is its wavelength? what is its wavelength? A. 2 x 10^12m, B. 5 x 10^14m, C. 5 x 10^2m, 2 x 10^-3m
Answer:
5*10^2
Explanation:
A p e x
please teach me reflection of light
Problem 3:A starship voyages to a distant planet 10 ly away. The astronauts in the starship reach theplanet and then they immediately return to the Earth at the same speed. The round trip from the Earthto the planet and back to the Earth takes 25 years.(a) What is the speed of the starship
Answer:
speed = 0.8c
Explanation:
Given :
Distance from earth to the distant planet = 10 ly
Time taken by the astronauts for the entire journey = 25 years
The time taken to reach the planet is [tex]$t_1=\frac{25}{2}$[/tex]
= 12.5 years
Therefore, speed of the starship can be calculated by :
[tex]$\text{Speed} = \frac{\text{distance}}{\text{time}}$[/tex]
[tex]$v=\frac{10 \times c \times 3.15 \times 10^7}{12.5 \times 3.15 \times 10^7}$[/tex]
[tex]$=0.8c$[/tex]
Therefore the speed of the starship is 0.8c
A negative correlation coefficient, such as -.89, means
A. There is no relationship between two variables.
B. As one variable tends to increase or become larger, the other decreases or becomes smaller.
C. There is a direct relationship. As one variable increases, the other also increases or becomes larger.
D. Nothing, a mistake has been made.
Answer:
B - As one variable increases the other decreases. (-1 to +1) coefficient
If a coworker repeatedly asks you out for a date even though she knows you are not interested, what is she guilty of?
A. discrimination
OB. hate speech
OC. psychological harassment
O D. sexual harassment
With what tension must a rope with length 2.90 m and mass 0.125 kg be stretched for transverse waves of frequency 42.0 Hz to have a wavelength of 0.740 m
Answer:
41.64 N
Explanation:
Applying,
v = √(T/m')................ Equation 1
Where v = velocity of the wave, T = Tension of the rope, m' = mass per unit length of the rope.
make T the subject of the equation,
T = v²m'................. Equation 2
But,
v = λf............... Equation 3
Where λ = wavelength, f = frequency
And
m' = m/L........... Equation 4
Where m = mass of the rope, L = length of the rope
Substitute equation 3 and equation 4 into equation 2
T = (λf)²(m/L).............. Equation 5
From the question,
Given: λ = 0.740 m, f = 42 Hz, m = 0.125 kg, L = 2.9 m
Substitute these values into equation 5
T = (42×0.74)²(0.125/2.9)
T = 41.64 N
Particles in a medium through which a sound wave is traveling________. A move back and forth? B move randomly? C move in a circular motion? D move up and down?
Answer:
s ಕಣಗಳು ಒಂದು ಮಧ್ಯಮ ಟ್ರೋಗ್ ಹಲೋ ನೀವು ಹೇಗಿದ್ದೀರಿ ಬಿಎನ್ ನಾನು ಹಾಡುಗಳಿಂದ ಸುಳ್ಳಲ್ಲ
source of sinusoidal electromagnetic waves radiates uniformly in all directions. At a distance of 10.0 m from this source, the amplitude of the electric field is measured to be 3.50 N>C. What is the electric-field amplitude 20.0 cm from the source
Answer:
[tex]175\ \text{N/C}[/tex]
Explanation:
[tex]E_1[/tex] = Initial electric field = 3.5 N/C
[tex]E_2[/tex] = Final electric field
[tex]r_1[/tex] = Initial distance = 10 m
[tex]r_2[/tex] = Final distance = 20 cm
Electric field is given by
[tex]E=\sqrt{\dfrac{2P}{\pi r^2c\varepsilon_0}}[/tex]
So,
[tex]E\propto \dfrac{1}{r}[/tex]
[tex]\dfrac{E_2}{E_1}=\dfrac{r_1}{r_2}\\\Rightarrow E_2=E_1\dfrac{r_1}{r_2}\\\Rightarrow E_2=3.5\dfrac{10}{0.2}\\\Rightarrow E_2=175\ \text{N/C}[/tex]
The electric field amplitude at the required point is [tex]175\ \text{N/C}[/tex].
Using a 2.5 meter long lever, we want to lift a body weighing 15 kilograms. If the lever support so that the pitch of the load is 55 cm, determine the force we must apply to be lift that burden? HURRYYYYY PLEASE ITS A TEST
Answer:
F = 668.9N
Explanation:
Using the formula;
m1d1 = m2d2
m1 and m2 are the masses
d1 and d2 are the distances
Substitute;
15 * 2.5 = x * (55/100) [55cm was converted to metres]
37.5 = 0.55x
Swap
0.55x = 37.5
x = 37.5/0.55
x = 68.18kg
Since F = mg
F = 68.18 * 9.81
F = 668.9N
This gives the required force
Which chemical reaction is most likely the slowest?
A. An egg is fried in a frying pan.
B. A ship with an iron hull rusts in seawater.
O
C. Wax reacts with oxygen when a candlewick is lit.
D. Cookies bake in an oven.
O
A 35.0 g bullet strikes a 5.3 kg stationary wooden block and embeds itself in the block. The block and bullet fly off together at 7.1 m/s. What was the original speed of the bullet? (WILL GIVE BRAINLIEST)
Answer:
= 1200m/s or 1.2 x [tex]10^{3}[/tex] m/s
Explanation:
Darth Vader has stolen a Bugatti Chiron (high speed sports car) and is now driving at aconstant velocity of 120 mph down the street for 45 seconds. Suddenly, he sees a family ofgeese crossing the street 200mahead and presses the brakes immediately (assume constant acceleration as he comes to a stop). He just barely avoids running over the geese. Putanswers in terms of SI units.
Required:
a. What is his acceleration as he comes to a stop?
b. How long does it take Vader to stop?
c. What is the total distance traveled?
The acceleration is 1.2 m/s^2. The distance travelled is 1197 m. The time taken is 44.7 seconds.
What is acceleration?The rate at which the velocity changes is called the acceleration of the body.
Given that;
v = u - at
v = 0 m/s because the car comes to stop
u = at
a = u/t
a = 53.6 m/s/ 45 seconds
a = 1.2 m/s^2
The distance travelled is;
v^2 = u^2 - 2as
v = 0 m/s
u^2 = 2as
s = u^2/2a
a = ( 53.6 )^2/2 * 1.2
s = 1197 m
Time taken to stop is obtained from;
v = u - at
when v = 0 m/s
u = at
t = u/a
t = 53.6/1.2
t = 44.7 seconds
Learn more about acceleration:https://brainly.com/question/12550364?
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A light ray in air strikes an oil
surface at a 61.0 deg angle, and
moves inside the oil at 38.3 deg.
What is the index of refraction of
the oil?
(Water n = 1.33, Air n = 1.00)
(No Unit)
Answer:
The index of refraction of the oil is 1.41.
Explanation:
We can find the index of refraction of the oil using Snell's law:
[tex] n_{1}sin(\theta) = n_{2}sin(\alpha) [/tex]
Where:
n₁: is the index of refraction of medium 1 (air) = 1.00
n₂: is the index of refraction of medium 2 (oil) =?
θ: is the angle between the light ray and the medium 1 = 61.0°
α: is the angle between the light ray and the medium 2 = 38.3°
Hence, the index of refraction of the oil is:
[tex] n_{2} = \frac{n_{1}sin(\theta)}{sin(\alpha)} = \frac{1.00*sin(61.0)}{sin(38.3)} = 1.41 [/tex]
Therefore, the index of refraction of the oil is 1.41.
I hope it helps you!
Answer:
1.41
Explanation:
e=mc² what is the name of the law?
Answer:
The name of law is mass engery law