A certain brand of automobile tire has a mean life span of 35,000 miles, with a standard deviation of 2250 miles. Assume the life spans of the tires have a bell-shaped distribution.
(a) The life spans of three randomly selected tires are 34,000 miles, 37,000 miles, and 30,000 miles. Find the z-score that corresponds to each life span. Determine whether any of these life spans are unusual.
(b) The life spans of three randomly selected tires are 30,500 miles, 37,250 miles, and 35,000 miles. Using the Empirical Rule, find the percentile that corresponds to each life span.

Answer:

A  B  C

Step-by-step explanation:

Answer:

abc or 123

Step-by-step explanation:

Answer:

Quantity (lbs) of type 1 candy  x = 8

Quantity (lbs) of type 2 candy  y = 17,5

Step-by-step explanation:

Let´s call  "x" quantity (in pounds) of candy type 1 in the mixture, and "y" quantity (in pounds ) of candy type 2, then according to the problem statement.

x  +  y  =  25,5

2,20*x  +  7,30*y = 5,70 * 25,5   ⇒  2,20*x  +  7,30*y = 145,35

Then we have a two equation system

x  +  y  =  25,5                                   ⇒   y = 25,5 - x

2,20*x  +  7,30*y = 145,35               ⇒ 2,20*x + 7,30* (25,5 - x ) = 145,35

2,20*x + 186,15 - 7,30*x = 145,35

5,1*x  = 40,8

x = 40,8/5,1

x = 8 lbs

And   y  =  25,5 - 8

y = 17,5 lbs

Answer:

D. 6 pounds

Step-by-step explanation:

$9.50-$5.00=$4.50; $4.50/$0.75= 6 pounds

Answer:

A - 1.50 pounds

Step-by-step explanation:

Answer:

[tex]\huge\boxed{y=\sqrt{55}}[/tex]

Step-by-step explanation:

ΔADC and ΔDBC are similar (AAA)

Therefore the cooresponging sides are in proportion:

[tex]\dfrac{AC}{CD}=\dfrac{CD}{BC}[/tex]

Substitute:

[tex]AC=6+5=11\\BC=5\\CD=y[/tex]

[tex]\dfrac{11}{y}=\dfrac{y}{5}[/tex]              cross multiply

[tex](11)(5)=(y)(y)\\\\55=y^2\to y=\sqrt{55}[/tex]

Answer:

Real Estate Deals

The best "payoff deal:"

B. Office Building

Step-by-step explanation:

A) Payoff Table

                                  Good Economic         Bad Economic

                                     Conditions                 Conditions

Probability                          (.60)                          (.40)

Apartment Building         $50,000                    $30,000

Office Building               $100,000                   $-40,000

Warehouse                     $30,000                     $10,000

B) Calculation of Expected Values:

                             Good Economic      Bad Economic    Expected Values

                                  Conditions          Conditions

Probability                       (.60)                    (.40)

Apartment Building     $30,000             $12,000             $42,000

Office Building            $60,000            $-16,000             $44,000

Warehouse                  $18,000               $4,000            $22,000

b) The expected value for these real estate deals can be derived as the sum of the payoffs under the two economic conditions after they have been weighed with their odds of occurrence.  The office building, in this example, showed the best payoff deal as the expected payoff from it results to a payoff of $44,000, which is higher than the expected payoff from the Apartment and Warehouse.  However, it is also the riskiest, especially when bad economic conditions occur.  This also accords with the general economic risk-return pattern that higher risky investments attract higher returns.

If it has a single zero that means it has to be just touching the x-axis with its tip.

We know that if it has only one zero, the discriminant equals 0.

So,

[tex]D=b^2-4ac=0\implies (-k)^2-4(1)(9)=0[/tex]

Solving for k,

[tex]k=\pm\sqrt{36}=\boxed{\pm{6}}[/tex].

Hope this helps.

Answer:

21.7

Step-by-step explanation:

When anything is 5 or above in a decimal place you round up to the next number for example

2.35 this would round up to be 2.4

21.65

Place value of 1 = ones place

Face value of 1 = 1

Note : The face value of a number will not change at all

Hope it helps you..If it's wrong plz say and I'll try to recorrect it :)

Answer:

it's option b that is the right answer

Answer:

down b3low

Step-by-step explanation:

The point where the two lines intersect is the only solution. An inconsistent system has no solution. Notice that the two lines are parallel and will never intersect. A dependent system has infinitely many solutions.

Answer:

c = 11.3 mi/h

Step-by-step explanation:

Since Square has all of the same sides, hence bobs speed will be the same for all of the sides.

All of the sides are equal in a square

=> Let's consider the two sides along with the diagonal a right angled triangle

=> [tex]c^2 = a^2 + b^2[/tex]

Where c is the speed of Rob along the diagonal and b and c is the speed of Bob along the side

=> [tex]c^2 = 8^2+8^2[/tex]

=> [tex]c^2 = 64+64[/tex]

=> [tex]c^2 = 128\\[/tex]

Taking sq root on both sides

=> c = 11.3 mi/h

Answer:

$[58543.42; 73456.58]

Step-by-step explanation:

Hello!

For the variable

X: salary of a college graduate that took a statistics course

Out of n= 43 students, the calculated mean is [tex]\frac{}{X}[/tex]= $66000

The population standard deviation is δ= $18908

There is no information about the variable distribution, but since the sample size is big enough (n≥30), you can apply the CLT and approximate the distribution of the sample mean to normal [tex]\frac{}{X}[/tex]≈N(μ;σ²/n)

Then you can apply the approximation of the standard normal distribution to calculate the 99% CI

[tex]\frac{}{X}[/tex] ± [tex]Z_{1-\alpha /2}[/tex] * [tex]\frac{Singma}{\sqrt{n} }[/tex]

[tex]Z_{1-\alpha /2}= Z_{0.995}= 2.586[/tex]

[tex]\frac{Singma}{\sqrt{n} }= \frac{18908}{\sqrt{43} }= 2883.44[/tex]

[66000±2.586*2883.44]

$[58543.42; 73456.58]

With a 99% confidence level you'd expect that the interval $[58543.42; 73456.58] will include the average salary of college graduates that took a course of statistics.

I hope this helps!

Answer:  see below

Step-by-step explanation:

1) An inequality is an equation that uses >, ≥, <, or ≤ instead of an equal sign.

Example:  3x + 2 ≥ 10

2) A compound inequality is when 2 inequalities are combined using either "and" or "or".  

Example:     x > -2  and  x < 4       rewrite as: -2 < x < 4

Graph:        -2 o-----------------o 4        one line segment between the #'s

Example:          x < -2 or x > 4

Graph:        ←-----------o -2    4 o----------→      two lines in opposite directions

3) The GPA is dependent on the number of hours she studies.

Independent: hours Beth studies

Dependent: GPA

Answer:

0.75x+15=2+0.5x-1

0.25x=1-15

0.25x=-14

x=-56

Step-by-step explanation:

Answer: 45.5

Step-by-step explanation:

Im in 6th grade and all you had to do was add 18.3 and 27.2 and you’ll get 45.5

Answer:

The garbage dump is 58.3 miles west of the hotel, and the hotel is 57.1 miles west of the hardware store. The hardware store is 44.8 miles west of the library. The hardware store is 57.9 miles north of the office supply store, and the office supply store is 55.5 miles north of the science lab.

Step-by-step explanation:

Answer:  9c²

Step-by-step explanation:

To find the Greatest Common Factor of 207c³ and 108c², first factor them down to their primes and see what they have in common.

                207c³                     108c²

                 ∧   ∧                        ∧  ∧

             9·23  c·c·c              9·12   c·c

            ∧                            ∧  ∧

           3·3                         3·3 3·4

                                                  ∧

                                                 2·2

207c³: 3·3·23  c·c·c

108c²:  2·2·3·3·3·4 c·c

GCF = 3·3 c·c

        = 9c²

The GCF of 207c^3 and 108c² is 9c²

Given the expressions [tex]207c^3 \ and \ 108c^2[/tex]

We are to find the GCF of both terms

First, we need to get the factors as shown::

207c³ = 9 * 23 * c² * c

108c² =  9 * 12 * c²

From the factors, we can see that 9 and c² are common to both terms:

The GCF of 207c^3 and 108c² is 9c²

Learn more here: https://brainly.com/question/21612147

Answer:

Step-by-step explanation:

Given:      CS ≅ HR

           ∠CHS ≅ ∠HCR

           ∠CSH ≅ ∠HRC

Prove: CR ≅ HS

ΔCHS ≅ ΔHCR (Angle-Angle-Side, AAS, congruence property)

ΔICR ≅ ΔIHS (congruence property)

IS ≅ IR (similarity property)

CS ≅ HR (given)

Thus,

IC = IS + SC (addition property)

IH = IR + RH (addition property)

IC ≅ IH

Then,

CR ≅ HS (similarity property of triangles SCH and RHC)

Answer:

Refeect circle A over the the y line = x

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hello, because of the end behaviour it means that the leading coefficient is negative so we can construct such polynomial function as below.

[tex]\large \boxed{\sf \bf \ \ -(x+7)(x-6) \ \ }[/tex]

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

The polynomial function will be f ( x ) = - x² - x + 42

What is Quadratic Equation?

A quadratic equation is a second-order polynomial equation in a single variable x , ax²+ bx + c = 0. with a ≠ 0. Because it is a second-order polynomial equation, the fundamental theorem of algebra guarantees that it has at least one solution. The solution may be real or complex.

Given data ,

The polynomial function is of second degree with zeros of -7 and 6

So , x = -7 and x = 6

Let the function be f ( x ) where f ( x ) = ( x + 7 ) ( x - 6 )

Now , as x tends to infinity , the negative makes no such difference on the zeros of the function f ( x ) ,

And , f ( x ) = - ( x + 7 ) ( x - 6 )

Therefore , to find the polynomial function , f ( x ) = - ( x + 7 ) ( x - 6 )

f ( x ) = - [ x² - 6 x + 7 x - 42 ]

        = - [ x² + x - 42 ]

        = - x ² - x + 42

Hence , the polynomial function f ( x ) = - x ² - x + 42

To learn more about polynomial function click :

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Answer:

Option D is the correct option.

Step-by-step explanation:

Given: 3 boxes with volumes 1331 , 1331 , 729

To find : Height of stacked boxes

[tex]h {1}^{3} = 1331 = h1 = \sqrt[3]{1331} = 11[/tex]

[tex]h {2}^{3} = 1331 = h2 = \sqrt[3]{1331} = 11[/tex]

[tex]h {3}^{3} = 729 = h3 = \sqrt[3]{729} = 9[/tex]

Now,

[tex]h = h1 + h2 + h3[/tex]

[tex] = 11 + 11 + 9[/tex]

[tex] = 31[/tex]

Hope this helps...

Good luck on your assignment...

Answer:

The proportion of these light bulbs that will last less than the advertised time is 18.94% or 0.1894

Step-by-step explanation:

The first thing to do here is to calculate the z-score

Mathematically;

z-score = (x - mean)/SD

= (1500-1550)/57 = -50/57 = -0.88

So the proportion we will need to find is;

P( z < -0.88)

We shall use the standard score table for this and our answer from the table is 0.1894 which is same as 18.94%

Answer:

x = 49/15

Step-by-step explanation:

15x - 30 x 0 + 40 = 89           PEMDAS

15x + 40 = 89        Isolate the variable

15x = 49      

x = 49/15

━━━━━━━☆☆━━━━━━━

▹ Answer

x = 49/15 or 3 4/15 or 3.26

▹ Step-by-Step Explanation

15x - 30 * 0 + 40 = 89

15x - 0 + 40 = 89

15x + 40 = 89

15x = 89 - 40

15x = 49

x = 49/15 or 3 4/15 or 3.26

Hope this helps!

CloutAnswers ❁

Brainliest is greatly appreciated!

━━━━━━━☆☆━━━━━━━

Answer:

45 min

Step-by-step explanation:

Here,

the we take the work as W and Alan's speed as A and Zack's speed as Z.

A = 2Z

W = 30 ( A+Z)

if the time for Alan to done cleaning alone is t then t = W ÷ A

t = ( 30 (A+(A÷2)))÷ A

t = 45 min

I am done .

Answer:

The answer is 2 1/5 miles.

Step-by-step explanation:

You have to multiply 5/9 with 4 since you are going around 4 times. You could also use addition which is 5/9 + 5/9 + 5/9 + 5/9.

Answer:

Hey there!

The person jogged a total of 20/9 miles.

Hope this helps :)

so amnt of money is x

x - 5 is Mark's remaining amnt

x - 20 is Susan's remaining amount

x - 5 = 2( x - 20) as he has twice the amnt of Susan

x - 5 = 2x - 40

40 - 5 = 2x - x

35 = x

the original amnt is $35

Answer: y=3

Step-by-step explanation:

To solve the equation, we want to get the same terms onto the same side and solve.

y+3=-y+9                 [add y on both sides]

2y+3=9                    [subtract 3 on both sides]

2y=6                        [divide 2 on both sides]

y=3

Answer:

y=3

Step-by-step explanation:

Answer: 23 cans of soda/4 people.

or (23/4) cans of soda per person.

Step-by-step explanation:

So we have the rate:

46 cans of soda/ 8 people

First, 46 and 8 are multiples of 2, so we can divide both numerator and denominator by 2:

46/2 = 23

8/2 = 4

Then the rate can be:

23 cans of soda/4 people.

Now 23 is a prime number, so we can not simplify it furthermore

Answer:

You would basically expand all the equations!

1. 7(4z+8b) is equal to 28z+56b.

2. 8(2x+3^2) is equal to 16x+72

3. 4(r+r+r+r) is equal to 4r+4r+4r+4r

4. 9(3+8x) is equal to 27+72x

5. 4^2(3+6f) is equal to 48+96t

6. (t+t+t)/4 is equal to t/4+t/4+t/4

7. 2(4s^3+2) is equal to 8s^3+4

8. 30(3x+4) is equal to 90x+120

9. 6(5a+9b) is equal to 30a+54b

10. 9(3x+5^4) is equal to 27x+5625

11. 7(c+c+c) is equal to 7c+7c+7c

12. 9(2+7f) is equal to 18+63f

13. 7^5(4g-8d) is equal to 67228g-134456d

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. The Hamilton method has you compute the number represented by each board member (total population/# members). Using this factor, the number of board members for each district are computed. This raw value is rounded down.

Because this total does not allocate all board members, the remaining members of the board are allocated to the districts based on the size of the fraction that was truncated when rounding down. Allocations start with the largest fraction and work down until all board members have been allocated.

The attached spreadsheet implements this algorithm using a "threshold" that is adjusted to a value between 0 and 1, signifying the cutoff point between a fraction value that gets an additional member and one that doesn't. (Often, that threshold can be set at 0.5, equivalent to rounding the raw board member value to the nearest integer.)

The resulting allocations are ...

  Town A: 2

  Town B: 2

  Town C: 6

  Town D: 12

__

2. The second attachment shows the result after the population move. The allocations of board members are identical.

__

3. The "factor" (persons per board member) is about 4500, so we don't expect a move of 900 people to make any difference in the allocation. These results make complete sense.

__

4. Of course each town will consider its own interest at the expense of everyone else, so they may or may not consider the results fair. The towns have population ratio of about 9 : 9 : 25 : 56, so the ratios 2 : 2 : 6 : 12 are quite in line. Even in the second year, when the ratios are closer to 9 : 10 : 26 : 56, the changes are small enough that the allocation of board members still makes sense. The results are fair.

_____

Comment on "fair"

The reason there are different methods of allocation is that each seeks to rectify some perceived flaw in one or more of the others. The reason there is not a general agreement on the method to be used is that some benefit more from one method than from another. "Fair" is in the eye of the beholder. I believe in this case it would be very difficult to justify any other allocations than the ones computed here.

Answer:

If we have two functions g(x) and f(x)

I suppose that the functions here are:

f(x) = 2 - √(4*x)

g(x) = -3*x

First, let's analyze the functions:

g(x) as not any problem for any value of x, so the domain is the set of all the real numbers.

f(x) has a square root on it, and we know that the square root of a negative number is equal to a complex number, so here we can not have negative values of x.

The domain of f is D = x ∈ {0, ∞}

Then (gof)(x) = g(f(x)) = -3*(2 - √(4*x)) = -6 + 3*√(4*x)

We can see that g(x) does not have any problem, and the problems with f(x) remain there, so the domain of the composition is equal to the domain of f(x):

D =  x ∈ {0, ∞}