Answer:
The ratio of f at the higher temperature to f at the lower temperature is 5.356
Explanation:
Given;
activation energy, Ea = 185 kJ/mol = 185,000 J/mol
final temperature, T₂ = 525 K
initial temperature, T₁ = 505 k
Apply Arrhenius equation;
[tex]Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ][/tex]
Where;
[tex]\frac{f_2}{f_1}[/tex] is the ratio of f at the higher temperature to f at the lower temperature
R is gas constant = 8.314 J/mole.K
[tex]Log(\frac{f_2}{f_1} ) = \frac{E_a}{2.303 \times R} [\frac{1}{T_1} -\frac{1}{T_2} ]\\\\Log(\frac{f_2}{f_1} ) = \frac{185,000}{2.303 \times 8.314} [\frac{1}{505} -\frac{1}{525} ]\\\\Log(\frac{f_2}{f_1} ) = 0.7289\\\\\frac{f_2}{f_1} = 10^{0.7289}\\\\\frac{f_2}{f_1} = 5.356[/tex]
Therefore, the ratio of f at the higher temperature to f at the lower temperature is 5.356
Amy set up the following experiment to study how plant growth is influenced by weather conditions. mc052-1 One pot will model normal growing conditions, and the other will model drought conditions. Which of the following factors is it most important for Amy to change to model drought conditions?
Answer:
lack of sunlight, overcrowded region for shelter of the plants, no nutrients and water supply, etc.
Explanation:
The plants needs favorable climatic conditions and nutrient to grow. Plants need air, sunlight, water, proper temperature, nutrients, etc. grow and make their food. They make their food with the help of sunlight and carbon dioxide by a process called as photosynthesis.
Now in the context, Amy is setting up an experiment where she will study the growth of plants in two models. One in the normal growing conditions and the other in a drought condition.
Drought is considered the most important abiotic factor that limits the growth and adversely affects the growth and the crop. The factor that is important for Amy to change the model into a drought conditions is the lack of water and carbon dioxide in the atmosphere. Also scarcity of sunlight and nutrients. The drought stress is considered as one of the crop performance limiting factors.
Rotation about C-C single bonds allows a compound to adopt a variety of _____________. conformations configurations formations isomers projections are often used to draw the various conformations of a compound. conformations are lower in energy, while conformations are higher in energy. The difference in energy between staggered and eclipsed conformations of ethane is referred to as strain. strain occurs in cycloalkanes when bond angles deviate from the preferred °. The conformation of cyclohexane has no torsional strain and very little angle strain. The term "ring flip" is used to describe the conversion of one conformation into the other. When a ring has one substituent the equilibrium will favor the chair conformation with the substituent in the position.
Answer:
Conformation
Explanation:
Conformation refers to "any of the spatial arrangements which the atoms in a molecule may adopt and freely convert between, especially by rotation about individual single bonds"(Oxford dictionary).
Carbon-Carbon single bonds are known to undergo rotations about its axis. These rotations leads to various conformations. The energy difference between conformations may be low or high depending on the structure of the molecule. The difference in energy between conformations determines a molecules's preferred conformation.
How many significant figures
are in this number?
3 x 10^6
Look at the potential energy diagram below. What amount of energy does the products have ?
100
80
PE
50
AB
40
C D
20
Progress of the reaction
40 KJ
60 KJ
O 20 KJ
80 KJ
Answer:
20 kJ
Explanation:
The products are C + D which is on the right side of the diagram. And it says it has 20 kJ of energy.
Is Ag3 PO4 ionic or covalent?
A student burned her magnesium sample according to the procedure and obtained a light gray product. Since the crucible looked dirty anyway, she skipped the steps to convert the Mg3N2 contamination to MgO, weighed the gray sample, and calculated the mass of her product. Was her resulting mass likely to be higher or lower the expected
Answer:
The resulting mass will be higher than expected
Explanation:
We have to keep this in mind; When magnesium is being burnt in air, two reactions are taking place. The first one is;
2Mg(s) + O2(g) ------> MgO(s) -------1
And
3Mg(s) + N2(g) -------> Mg3N2(s) ---------2
Now, if the steps that should be taken to convert Mg3N2 to MgO are not taken, the reaction is much quicker but a higher mass of solid is obtained than what was expected.
This higher mass of solid obtained owes to the fact that Mg3N2 from reaction 2 was not converted to MgO leading to contamination of the product.
what causes deep ocean currents to flow
Answer:Deep ocean currents (also known as Thermohaline Circulation) are caused by: ... The sinking and transport of large masses of cool water gives rise to the thermohaline circulation, which is driven by density gradients due to variations in temperature and salinity. The earth's rotation also influences deep ocean currents.
Explanation:
In a reaction involving the iodination of acetone, the following volumes were used to make up the reaction mixture: 5 mL 4.0M acetone 5 mL 1.0 M HCl 5 mL 0.0050 M I2 10 mL H2O While keeping the total volume at 25 mL and keeping the concentration of H ion and I2 as in the original mixture, how could you double the molarity of the acetone in the reaction mixture
Answer:
Explanation:
pls give me point so i can ask questions
Given that a 0.130 M HCl(aq) solution costs $39.95 for 500 mL, and that KCl costs $10/ton, which analysis procedure is more cost-effective
Answer:
KCl is cost effective
Explanation:
In order to know this, we need to see how much it cost 1 g of each reactant. Let's begin with HCl
HCl:
In this case, let's calculate the moles of HCl in a 0.130 M solution and then, the mass of HCl using the molecular weight of 36.5 g/mol, to get the cost the HCl at the end using the given price:
nHCl = 0.130 moles/L * 0.5 L = 0.065 moles
mHCl = 0.065 moles * 36.5 g/mol = 2.3725 g
Cost HCl = 39.95 $ / 2.3725 g = 16.84 $/g
Conclusion, 1 g of HCl costs 16.84 $
KCl:
In this case, it's pretty obvious that 1 ton of KCl cost 10$, so, there is no need to do further calculations because 1 ton (or more than 1000 kg of the salt) it's just 10$. This is less expensive than the 16.84$ for just 1 g of HCl, so, final conclusion, KCl is more cost-effective.
Hope this helps
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-1. If the initial pressure of N2O is 3.50 atm at 730°C, calculate the total gas pressure after one half-life. Assume that the volume remains constant. Insert your answer in decimal notation rounded to 3 significant figures.
Answer:
the total gas pressure after one half-life is 4.38 atm
Explanation:
The balanced equation for the decomposition of N2O to N2 and O2 is given as:
2N₂O(gas) ⇒ 2N₂(gas) + O₂(gas)
2 moles of N₂O produce 2 moles of N₂ and 1 mole of O₂
The change in pressure depends on the coefficient (number of moles) of the reactant and product.
N₂O N₂ O₂
number of moles 2 2 1
Initial pressure (atm) 3.50 0 0
change in pressure -2x +2x x
Final pressure (atm) 3.50 - 2x 2x x
The total final pressure is the sum of the individual total pressure. i.e.:
Total final pressure = final pressure of N₂O + final pressure of N₂ + final pressure of O₂
Total final pressure = (3.5 - 2x) + (2x) + x
Total final pressure = 3.5 + x
After one half life, the initial pressure of N₂O would be half its value.
Final pressure of N₂O = half of the initial pressure of N₂O
3.5 - 2x = 0.5(3.5)
3.5 - 2x = 1.75
2x = 1.75
x = 0.875 atm
Therefore, Total final pressure = 3.5 + x = 3.5 + 0.875
Total final pressure = 4.38 atm to 3 significant figures
Aqueous hydrochloric acid will react with solid sodium hydroxide to produce aqueous sodium chloride and liquid water . Suppose 14. g of hydrochloric acid is mixed with 6.55 g of sodium hydroxide. Calculate the minimum mass of hydrochloric acid that could be left over by the chemical reaction. Round your answer to significant digits.
Answer:
8.02 g of HCl could be left over by the chemical reaction
Explanation:
We propose the reaction:
HCl(aq) + NaOH (s) → NaCl (aq) + H₂O (l)
Ratio is 1:1. First of all, we determine the moles of reactants:
14 g . 1mol / 36.45g = 0.384 mol of acid
6.55 g. 1mol / 40g = 0.164 mol of base
If a determined mass of HCl, could be left; this means that the acid is the excess reagent.
For 0.164 moles of NaOH, we need 0.164 moles of HCl.
As we have 0.384 moles, (0.384 - 0.164) = 0.220 moles of acid are left over in the reaction. We convert the moles to mass:
0.220 mol . 36.45 g /1mol = 8.02 g
In order to be in a position to manipulate any operation, one has to know all the fine details of the system and where and how one might apply subtle changes to affect the outcome. When looking at chemical reactions, it is from the study of its kinetics that one gleams the insight necessary to be able to do this. The main use of chemical kinetics is to measure the speed of a chemical reaction. But more importantly, in measuring the speed of a reaction, one gains insight as to what part of the reaction imparts this speed (or lack thereof) and thus allows one to propose a specific mechanism that details the critical pathway for the reaction. Measuring the speed of a chemical reaction is very similar to measuring speed in general, except that instead of talking in terms of distance traveled per unit time we are measuring either reactants consumed per unit time or products produced per unit time. There are many factors that affect the speed of a chemical reaction, some of the more common ones being:
Answer:
See explanation
Explanation:
Chemical kinetics, the branch of physical chemistry that is concerned with understanding how fast or how slow chemical reactions occur (Encyclopedia Britannica).
The study of the kinetics of a chemical reaction is helpful in many ways. Most important is the fact that it allows one to propose a specific mechanism that details the critical pathway for the reaction.
The factors that affect the rate of chemical reaction includes; concentration of reactants, temperature, nature of reactants , the solvent used, the presence of a catalyst, presence of light, surface area of reactants and pressure for gaseous reactants.
A chemical equation is balanced when the number of each
type of ____ is the same on both sides of the equation.
Answer:
element
Explanation:
Which would be another way to make the ice melt faster
Answer:
d because ur heating the ice and causing friction
assume that the density of all solutions are 1.000g/ml 1. Calculate the molarity of calcium in 1.9g of calcium chloride diluted in 100 ml of Di water. 2 Calculate the concentration of both calcium and chloride lons in problem 1 in units of mg/mL, ug/L, mg/L and ug/mL. 3. Calculate the concentration of both calcium and chloride ion in problem 1 in units of ppm and ppb. You may assume that the density of the solution is 1.0 g/ml 4. You have been provided 100 ml of a 1000 ug/ml barium standard. What volume of this standard must be diluted to a final volume of 50 ml using DI water to produce a 30 ug/mL standard
Answer:
1. 0.1712M
2. 6.86mg/mL Ca, 12.14mg/mL Cl, 6860000ug/L Ca, 12140000ug/L Cl, 6860mg/L Ca, 12140mg/L Cl, 6860ug/mL Ca, 12140ug/mL Cl.
3. 6860ppm Ca and 12140ppm of Cl.
4. 1.5mL of the 1000ug/mL barium standatd must be taken.
Explanation:
1. Molarity is defined as the amount of moles of solute (Calcium chloride) present in 1L of solution.
The moles of CaCl₂ are:
1.9g CaCl₂ * (1mol / 110.98g) = 0.01712 moles
In 100mL = 0.10L:
0.01712mol / 0.10L = 0.1712M
2. The masses of Calcium and Chloride ions are:
1.9g * (40.078g Ca / 110.98g) = 0.686g Ca
And:
1.9g - 0.686g Ca = 1.214g Cl
mg/mL:
686mg Ca / 100mL = 6.86mg/mL Ca
1214mg Cl / 100mL = 12.14mg/mL Cl
ug/L:
686000ug / 0.1L = 6860000ug/L Ca
1214000ug/ 0.1L = 12140000ug/L Cl
mg/L:
686mg Ca / 0.1L = 6860mg/L Ca
1214mg Cl / 0.1L = 12140mg/L Cl
ug/mL:
686000ug Ca / 100mL = 6860ug/mL Ca
1214000ug Cl / 100mL = 12140ug/mL Cl
3. ppm are defined as mg/L, the ppm of Ca are 6860ppm Ca and 12140ppm of Cl
4. The solution must be diluted from 1000ug/mL to 30ug/mL, that is a dilution of:
1000ug/mL / 30ug/mL:
33.33 times must be diluted the solution.
As final volume of the diluted solution must be 50mL, the volume of the standard needed is:
50mL / 33.33 times = 1.5mL of the 1000ug/mL barium standatd must be taken
4 points 15. The diagram below shows the relative positions of Earth, the moon, and the sun. The moon is shown at four possible positions around Earth. 3 Sunlight Sun Earth mo Which position of the moon could result in a lunar eclipse? В. 2 A B
Answer:
b c
Explanation:
Answer: b c
Explanation: i did test
Some hypothetical alloy is composed of 25 wt% of metal A and 75 wt% of metal B. If the densities of metals A and B are 6.17 and 8.00 g/cm3 , respectively, and their respective atomic weights are 171.3 and 162.0 g/mol, determine whether the crystal structure for this alloy is simple cubic, facecentered cubic, or body-centered cubic. Assume a unit cell edge length of 0.332 nm
Answer:
Simple cubic
Explanation:
The density of metal A (ρa) = 6.17 g/cm³, The density of metal B (ρb) = 8 g/cm³, The atomic weight of metal A (Aa) = 171.3 g/mol, The atomic weight of metal B (Ab) = 162 g/mol, the unit cell edge length (a) = 0.332 nm, concentration of metal A (Ca) = 25%, concentration of metal B (Cb) = 75%
The average density is given by:
[tex]\rho_{ave}=\frac{100}{\frac{C_a}{\rho_a} +\frac{C_b}{\rho_b} } \\\\\rho_{ave}=\frac{100}{\frac{25}{6.17} +\frac{75}{8} } =7.45\ g/cm^3\\\\The\ average\ atomic\ weight\ is:\\\\A_{ave}=\frac{100}{\frac{C_a}{A_a} +\frac{C_b}{A_b} } \\\\A_{ave}=\frac{100}{\frac{25}{171.3} +\frac{75}{162} } =164.23\ g/mol\\\\The\ number\ of\ atoms\ per\ unit(n)\ is:\\\\n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} \\\\N_A=Avogadro\ constant=6.02*10^{22} \ mol^{-1},a=0.332\ nm=3.32*10^{-8}cm\\\\Substituting:\\\\[/tex]
[tex]n=\frac{\rho_{ave}*a^3*N_A}{A_{ave}} =\frac{7.45*(3.32*10^{-8})^3*6.02*10^{23}}{164.23} \\\\n=0.999\\[/tex]
n≅1
Since n≅1, the crystal structure for this alloy is simple cubic
Strontium chlorate is mixed with ammonium phosphate
Explanation:
Please, if I may ask, what is the exact question?
Hard water often contains dissolved Ca^2+ and Mg^2+ ions. One way to soften water is to add phosphates. The phosphate ion forms insoluble precipitates with calcium and magnesium ions, removing them from solution. A solution is 0.055 MM in calcium chloride and 0.075 MM in magnesium nitrate. What mass of sodium phosphate would you add to 1.0 LL of this solution to completely eliminate the hard water ions? Assume complete reaction.
Answer:
14.2g of sodium phosphate are required
Explanation:
To solve this question we need to find the moles of Ca²⁺ and Mg²⁺ ions. And based on the reactions:
3Ca²⁺ + 2PO₄³⁻ → Ca₃(PO₄)₂ (s)
3Mg²⁺ + 2PO₄³⁻ → Mg₃(PO₄)₂ (s)
we can find the moles of phosphate required to precipitate all these ions and its mass:
Moles Ca²⁺:
1.0L * (0.055mol / L) = 0.055mol
Moles Mg²⁺:
1.0L * (0.075mol / L) = 0.075mol
Total moles = 0.13 moles of ions
Moles of phosphate ion required:
0.13 moles * (2 moles PO₄³⁻ / 3 moles ions) = 0.0867 moles PO₄³⁻
The moles of sodium phosphate (Na₃PO₄) are = 0.0867 moles
The mass is -Molar mass Na₃PO₄: 164g/mol-:
0.0867 moles Na₃PO₄ * (164g / mol) =
14.2g of sodium phosphate are requiredOne mole (mol) of nitrogen monoxide (NO) has a mass of 30.01 g. When
precisely 2 moles of NO(g) are produced in the following chemical reaction, 43
kcal of heat energy is "absorbed."
N2(g) + O2(g) → 2 NO(g), AH = +43 kcal
How much heat (in kJ) is exchanged when 152 g of NO(g) is produced?
Answer:
455.6 kJ.
Explanation:
Hello there!
In this case, according to the given reaction, we know that 2 moles of NO require 43 kcal of energy, thus, for the energy required by 150 g of NO we first need the moles, considering its molar mass (30.01 g/mol):
[tex]152g*\frac{1mol}{30.01g} =5.065mol[/tex]
Thus, we apply the following dimensional analysis to obtain the energy absorbed by 5.065 moles:
[tex]5.065mol*\frac{43kcal}{2mol} =108.9kcal[/tex]
Which kJ turns out:
[tex]108.9kcal*\frac{4.184kJ}{1kcal}\\\\455.6kJ[/tex]
Best regards!
Determine the energy change in the following reaction. This reaction is considered ...
C6H12 + O2
CO2 + H2O + heat
energy absorbed is equal to the energy released
endothermic
O isothermic
O exothermic
Answer:isothermic
Explanation:
Answer:
Energy abosorbed = Energy released.
Thus ISOTHERMIC
What is the specific heat of a 44 g piece of metal if 202 Joules of heat are required to
raise the temperature from 22ᵒC to 33.6ᵒC?
Answer:
≈ 395,8 J/(kg * °C)
Explanation:
m = 44 g = 0,044 kg
[tex]t_{1}[/tex] = 22 °C
[tex]t_{2}[/tex] = 33,6 °C
Q = 202 J
The formula is: Q = c * m * ([tex]t_{2} - t_{1}[/tex])
c = [tex]\frac{Q}{m * (t_{2} - t_{1} )}[/tex]
Calculating:
c = 202 J / 0,044 kg * (33,6 °C - 22 °C) ≈ 395,8 J/(kg * °C)
Which statement is true about the speed of light? (2 points)
Light travels relatively slowly.
Distance in space is measured using the speed of light.
Time in space is measured using the speed of light.
The speed of light is unknown
Answer:
2nd option is the correct answer of this question
Answer:
yes it is b
Explanation:
Based on your understanding of color's relationship to wavelength, identify the approximate wavelength of light (nm) emitted by strontium when it was burned in Part C. (No quantitative data was collected for this; you are giving an approximate value only, based on what you observed.) Explain your reasoning in full, making sure to cite specific data and observations to support your answer.
Answer:
The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.
Explanation:
Visible light is part of the electromagnetic spectrum. The electromagnetic waves are composed of electric and magnetic fields.
The visible spectrum is composed of seven different wavelengths that corresponds to different colours. When a metallic element is exposed flame, one of these colours is observed. This is commonly called the flame test.
The flame colour of strontium is red. Red has a wavelength of around 620 to 750 nm.
The approximate wavelength of light (nm) emitted by strontium when it was burned is red, where red has a wavelength of round 620-750 nm.
Wavelength of light emitted by strontiumGenerally, Visible mild is phase of the electromagnetic spectrum. the electromagnetic waves are composed of electric powered and magnetic fields. When a metal factor is uncovered flame, one of they seven colors of visible spectrum is seen.
The flame shade of strontium is red, where red has a wavelength of round 620-750 nm.
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A careless student forgets to label one of their reagent containers. They know it contains one of the following solutions: 0.1 M NaCl, 0.1 M Ca(NO3)2, 0.1 M KCH3COO The student decides to add some 0.1 M Pb(NO3)2 to a sample of the reagent in question. Upon stirring, a white precipitate formed. Which of the possible solutions was present in the unlabeled container based on this observation
Answer:
He kinda lazy ngl
Explanation:
Rgheeghfgufugf
How much energy is required to remove a neutron from the nucleus of an atom of carbon-13?
Answer:
uh i think 12?
Explanation:
54.1miles/gallons how many liters of gas will be consumed traveling 132 km
Answer:
5.75 L.
Explanation:
From the question given above, the following data were obtained:
Rate = 54.1 miles/gallons
Distance = 132 km
Volume (in L) consumed =?
Next, we shall convert 132 km to mile. This can be obtained as follow:
1 km = 0.621 mile
Therefore,
132 km = 132 km × 0.621 mile / 1 km
132 km = 81.972 mile
Next, we shall determine the volume (in gallons) of the gas needed. This can be obtained as follow:
Rate = 54.1 miles/gallons
Distance = 81.972 mile
Volume (in gallon) =?
Rate = Distance / volume
54.1 = 81.972 / volume
Cross multiply
54.1 × volume = 81.972
Divide both side by 54.1
Volume = 81.972 / 54.1
Volume = 1.52 gallon.
Finally, we shall convert 1.52 gallon to litre (L). This can be obtained as follow:
1 gallon = 3.785 L
Therefore,
1.52 gallon = 1.52 gallon × 3.785 L / 1 gallon
1.52 gallon = 5.75 L
Therefore, 5.75 L of the gas will be consumed.
HELP! URGENT Which of the following best states the relationship between erosion and deposition?
A.
When the energy transporting sediments diminishes, the sediments settle in a low-lying area; therefore, deposition always follows erosion.
B.
When the energy transporting sediments diminishes, the sediments settle in a low-lying area; therefore, erosion always follows deposition.
C.
When rock is broken down into sediments, the sediments are eventually transported to another location; therefore, deposition is a form of erosion.
D.
When rock is broken down into sediments, the sediments are eventually transported to another location; therefore, erosion is a form of deposition.
How does the average reaction rate differ from an instantaneous reaction rate?
a) The average reaction rate is how quickly the reaction proceeds at a specific time. An instantaneous reaction rate is how quickly the reaction proceeds over time.
b) The average reaction rate is how quickly the reaction proceeds over time considering the reactants. An instantaneous reaction rate is how quickly the reaction proceeds at a specific time considering the products.
c) The average reaction rate is how quickly the reaction proceeds over time. An instantaneous reaction rate is how quickly the reaction proceeds at a specific time.
d) The average reaction rate is how quickly the reaction proceeds over time. An instantaneous reaction rate is how quickly the reaction proceeds compared to another reaction.
Answer:
The average reaction rate is how quickly the reaction proceeds at a specific time. An instantaneous reaction rate is how quickly the reaction proceeds over time.
Explanation:
What are metalloids?
A metalloid is a type of chemical element which has a preponderance of properties in between, or that are a mixture of, those of metals and nonmetals.
Answer:
Metalloid, in chemistry, an imprecise term used to describe a chemical element that forms a simple substance having properties intermediate between those of a typical metal and a typical nonmetal. There is no single property which can be used to unambiguously identify an element as a metalloid.