A circle has a radius of 9 cm.
When written in terms of pi, how many times greater is the area than the circumference?

Step-by-step explanation:

Please refer to the attachment

Consider the missing part of the question is "Select the correct statement.

A. The number of employees is increasing by 50% every year.

B. The number of employees is decreasing by 10% every year.

C. The number of employees is decreasing by 90% every year.

D. The number of employees is increasing by 90% every year."

Given:

The function is:

[tex]f(t)=1.5(0.90)^t[/tex]

Where, f(t) is the number of employees working at a company, in thousands and t is the number of years since the company revised the benefits package.

To find:

The correct statement from the given options.

Solution:

The general exponential decay model is:

[tex]f(t)=a(1-r)^t[/tex]         ...(i)

Where, a is the initial value, r is the rate of decay and t is the number of years.

We have,

[tex]f(t)=1.5(0.90)^t[/tex]

It can be written as

[tex]f(t)=1.5(1-0.10)^t[/tex]        ...(ii)

From (i) and (ii), we get

[tex]a=1.5,r=0.10[/tex]

The initial value is 1.5 and the rate of decay is 0.10 or 10%. It means the number of employees is decreasing by 10% every year.

Therefore, the correct option is B.

Answer:

for 1 student it would equal 11.25

11.25 x 50 = 562.50

ur answer is 50 students hope this helps :)

Answer:

the teacher has 50 students

Step-by-step explanation:

1.75+9.50=11.25

562.50/11.25=50

Answer:

D.

Step-by-step explanation:

If you add them all up and subtract 30 you get 60

I MAYBE MESSED UP // haven't done this math in a while

Answer:

2

Step-by-step explanation:

The interquartile range of the given data set is 2.

We need to find the interquartile range of the data set given.

To find the interquartile range (IQR), ​first, find the median (middle value) of the lower and upper half of the data. These values are quartile 1 (Q1) and quartile 3 (Q3). The IQR is the difference between Q3 and Q1.

The given set of data is

0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

To find Q1:

The lower half of the numbers are

That is 0, 0, 0, 0, 0, 0, 1, 1, 1, 1, 1, 1, 1, 2,

So the median of the lower half (Q1)=1

To find Q3:

The upper half of the numbers are 2, 2, 2, 2, 3, 3, 3, 3, 4, 5, 5, 5, 6, 6

So the median of the upper half (Q3)=3

Then, IQR=Q3-Q1=3-1=2

Therefore, the interquartile range of the given data set is 2.

To learn more about the interquartile range visit:

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Answer:

The answer would be D

Step-by-step explanation:

Why? because as the temperature increases the amount of lemonade sold increases by 2

This is represented in 2(x) if that makes sense

For every 1-degree increase in high temp of the day, sales decrease by 2 glasses of lemonade. Then the correct option is D.

A connection between a number of variables results in a linear model when a graph is displayed. The variable will have a degree of one.

The linear equation is given as,

y = mx + c

Where m is the slope of the line and c is the y-intercept of the line.

The function is given below.

f(x) = 2(x – 65) + 12

f(x) = 2x – 130 + 12

f(x) = 2x – 118

For every 1-degree increase in high temp of the day, sales increase by 2 glasses of lemonade. Then the correct option is D.

More about the linear equation link is given below.

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The missing options are given below.

a) for every 65-degree decrease in high temp of the day, lemonade sales increase by 1 glass of lemonade

b) for every 1-degree increase in high temp of the day, sales increase by 2 glasses of lemonade

c) for every 65-degree decrease in high temp of the day, sales decrease by 1 glass

d) for every 1-degree increase in high temp of the day, sales decrease by 2 glasses of lemonade

Answer:

The system is of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

Where g is the amount of general tickets and r is the amount of reserve tickets.

35 general tickets and 25 reserve tickets were sold.

Step-by-step explanation:

Let general tickets be represented by g and reserved tickets be represented by r.

Each general ticket sells for $10 each and reserved tickets $15 each. Dave collected a total of $725. Thus:

[tex]10g+15r=725[/tex]

And a total of 60 tickets were sold. Hence:

[tex]g+r=60[/tex]

Our system of equations is:

[tex]\left\{ \begin{array}{ll} 10g+15r=725 & \quad \\ g+r=60 & \quad \end{array} \right.[/tex]

We can solve by substitution. First, divide both sides of the first equation by 5:

[tex]2g+3r=145[/tex]

Next, we can subtract a variable (r in this case) from the second equation:

[tex]g=60-r[/tex]

Substitute:

[tex]2(60-r)+3r=145[/tex]

Distribute:

[tex]120-2r+3r=145[/tex]

Simplify:

[tex]120+r=145[/tex]

Subtract:

[tex]r=25[/tex]

Using the previous equation:

[tex]g=60-r[/tex]

Substitute and evaluate:

[tex]g=60-(25)=35[/tex]

So, 35 general tickets and 25 reserve tickets were sold.

                   Step-by-step explanation:

so whats the equation

Answer:

She can invite 66 people so 66 x 5 = $330 + 120 = $450

Step-by-step explanation:

Answer:It’s the third choice y=3x+1

Step-by-step explanation:

Answer:

20 + 75 = 95

Step-by-step explanation:

10 - 5 = 5 x 4 = 20

5 x 15 = 75

Add them together,

75 + 20 = 95

Answer:

Step-by-step explanation:

A=19000( 1 + 0.03)^8

A=24068.6315464

A≈24100

Round to the nearest hundred dollars

Answer:

Slope is -7 and the y-intercept is 8

Step-by-step explanation:

Answer:

[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

Step-by-step explanation:

Given - A tank contains 350 liters of fluid in which 40 grams of salt is dissolved. Pure water is then pumped into the tank at a rate of 5 L/min; the well-mixed solution is pumped out at the same rate. Let the A(t) be the number of grams of salt in the tank at time t.

To find - Find the rate at which the number of grams of salt in the tank is changing at time t.

Find the number A(t) of grams of salt in the tank at time t.

Proof -

Given that,

Total fluid in the tank = 350 litres

Total salt = 40 grams

Rate in flow = 5 L/min

Rate out flow = 5 L/min

Concentration in = 0

Concentration out = (Amount of salt at time t )/ (Solution in tank at time t)

Now,

Total solution in the tank at time t = Total fluid in the tank + (Rate in flow - Rate out flow )t

                                                        = 350 + (5 - 5)t

                                                        = 350

⇒Solution in the tank at time t = 350

⇒Concentration out = [tex]\frac{A(t)}{350}[/tex]

Now,

Rate of change in the tank at time t = [tex]\frac{dA}{dt}[/tex]

                                                           =  (Rate in flow )( Concentration In) - (Rate out flow )( Concentration out)

                                                           = 5(0) - 5([tex]\frac{A(t)}{350}[/tex])

                                                           = 0 - [tex]\frac{A(t)}{70}[/tex]

                                                           = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{dt}[/tex] = [tex]-\frac{A(t)}{70}[/tex]

⇒[tex]\frac{dA}{A} = -\frac{1}{70} dt[/tex]

Integrate both sides , we get

ln(A) = [tex]-\frac{1}{70}t + C[/tex]

⇒A(t) = [tex]e^{-\frac{t}{70}+ C}[/tex]

         = [tex]e^{-\frac{t}{70}}*e^{C}[/tex]

         = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

⇒A(t) = [tex]C_{1} e^{-\frac{t}{70}}[/tex]

Now,

Given that,

Initially, the tank has 40 grams of salt

⇒A(0) = 40

⇒C₁ = 40

⇒A(t) = [tex]40 e^{-\frac{t}{70}}[/tex]

The relationship between the three pieces is such that, their

sum is the length of the given stick.

Correct response:

Three equations that show different ways in which he can

break the stick of length l based on a unit length x are;

Given parameters are;

The number of pieces into which Christopher has to break the stick = 3 pieces

Length of a piece ≠ The length of the other pieces

Required:

Three equations that shows the different ways Christopher can break the stick.

Solution:

Let l represent the length of the stick, let x, represent a unit

length, and let, A, B, and C, represent the length of the pieces.

Three possible equations that can be written using multiples of x are;

Where;

The the relationship between the lengths of the pieces are;

A = x ≠ B = 2·x ≠ C = 3·x

[tex]x = \mathbf{ \dfrac{l}{6}}[/tex]

A = x ≠ B = 5·x ≠ C = 8·x

[tex]x = \mathbf{ \dfrac{l}{14}}[/tex]

Where;

A = 3·x ≠ B = 2·x ≠ C = 6·x

[tex]x = \mathbf{\dfrac{l}{11}}[/tex]

Learn more about writing equations here:

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Answer:

20

Step-by-step explanation:

add 3ft+3ft+11ft+3ft and that's your answer

Answer:

18

Step-by-step explanation:

[tex]\frac{6}{1}[/tex] ÷ [tex]\frac{1}{3}[/tex]

Keep Change Flip

[tex]\frac{6}{1}[/tex] × [tex]\frac{3}{1}[/tex] = [tex]\frac{18}{1}[/tex]

Answer:

y=3x^2 -15x-42

Step-by-step explanation:

Answer:

18/4 = 4.5

it would take you about 4 hours and 30 minutes  to walk 18 miles

Step-by-step explanation:

Answer:

4 1/2 hours

Step-by-step explanation:

RATIO:

Miles      Hours

4                  1

8                  2

12                 3

16                 4

18               4 1/2

You need to get from 16-18 so you have to get 4-2 and 1 hour to 1/2 hour.

Answer:

x=0 y=2 z=5

Step-by-step explanation:

so for z

2z=10

divid both side by 2

z=5

equation one

x+2y+5=9

x+2y=4 ------eqn1

equation two

x-y+ 3(5)=13

x-y+15=13

x-y=-2-----eqn2

now you solve it by elimination

eqn1-eqn2

3y=6

y=2

put y=2 into eqn2

x-2=-2

x=0

Answer:

3/26 students or 11% Pls give brainly :)  

Step-by-step explanation:

probability dependant formula:P(A∪B)=P(A)+P(B)−P(A∩B)

P(a)= basketball

P(b)=baseball

so

P(AUB)=P(A)+P(B)-P(A∩B)= 18/26+5/26-20/26=3/26

3/26 or 11%  

OR you could solve this by adding all the sport/non sport #'s 18+5+6=29 and subtract 26 from 29

29-26=3

hence 3/26 students would randomly play basketball or baseball

Hope this Helps!

Answer:

8.3

Step-by-step explanation:

Answer:

(26/4)*7=45.5 miles

Step-by-step explanation:

Answer:

x>36

Step-by-step explanation:

Hope this helps and good luck

Step-by-step explanation:

Per our conceptual understanding, when two parallel lines are cut by a transversal line then their corresponding angles are equal.

So, If PQ and RS are two parallel lines and line L1 as shown is the transversal line then the corresponding angles are equal.

Hence, ∠1 = ∠2Or, c0 = 1800 – c02c = 180c = 90°

Therefore, if we get c = 90° then PQ and RS are parallel else PQ and RS are not parallel,

With this understanding, let us now analyse the individual statements.

Step 3: Analyse Statement 1

“b = 2a”

Per conceptual understanding, the sum of all the angles of a triangle is 180.

Hence, a + b + c = 180a + 2a + c = 1803a + c = 180

However, from the above equation, we can get many values of a and c.

Hence, statement 1 is not sufficient to answer the question.

Step 4: Analyse Statement 2

“c = 3a”

a + b + c = 180a + b + 3a = 180b + 4a = 180

However, from the above equation, we can get many values of a and b.

Hence, statement 2 is not sufficient to answer the question.Step 5: Combine Both Statements Together (If Needed)

From statement 1:

3a + c = 180

From statement 2:

c = 3a

Combining both the statements:

3a + 3a = 180.

From the above equation, we can find the value of a. Then we can find c.

Since we could find the answer by combining both the statements, option C is the correct answer.

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