Answer:
f = 5.3 Hz
Explanation:
To solve this problem, let's find the equation that describes the process, using Newton's second law
∑ F = ma
where the acceleration is
a = [tex]\frac{d^2 y}{dt^2 }[/tex]
B- W = m \frac{d^2 y}{dt^2 }
To solve this problem we create a change in the reference system, we place the zero at the equilibrium point
B = W
In this frame of reference, the variable y' when it is oscillating is positive and negative, therefore Newton's equation remains
B’= m [tex]\frac{d^2 y'}{dt^2 }[/tex]
the thrust is given by the Archimedes relation
B = ρ_liquid g V_liquid
the volume is
V = π r² y'
we substitute
- ρ_liquid g π r² y’ = m \frac{d^2 y'}{dt^2 }
[tex]\frac{d^2 y'}{dt^2} + \rho_liquid \ g \ \pi r^2/m ) y' \ =0[/tex]
this differential equation has a solution of type
y = A cos (wt + Ф)
where
w² = ρ_liquid g π r² /m
angular velocity and frequency are related
w = 2π f
we substitute
4π² f² = ρ_liquid g π r² / m
f = [tex]\frac{1}{2\pi } \ \sqrt{ \frac{ \rho_{liquid} \ \pi r^2 \ g}{m } }[/tex]
calculate
f = [tex]\frac{1}{2 \pi } \sqrt{ \frac{ 1000 \ \pi \ 0.03^2 \ 9.8 }{0.025} }[/tex]
f = 5.3 Hz
can someone please take there time and answer this for me :)
Answer:
number 1
Explanation:
they have common ancestors
The coefficient of linear expansion of lead is 29 x 10 K What change in temperature will cause a 5-m long lead bar to change in length by 3.0 mm?
Answer:
These linear thermal expansion coefficients are room temperature values of metals. Linear thermal expansion coefficient is defined as material's fractional change in length divided by the change in temperature.
Explanation:
The change in temperature caused is 0.0000207 K.
To calculate the change in temperature we use the formula of linear expansivity below.
⇒ Formula:
∝ = ΔL/(LΔT).................. Equation 1⇒ Where:
∝ = Coefficient of linear expansionΔL = Change in lengthL = Original lengthΔT = Change in Temperature.⇒ Make ΔT the subject of the equation
ΔT = ΔL/(∝L)................ Equation 2From the question,
⇒ Given:
∝ = 2.9×10 K⁻¹ΔL = 3 mm = 3×10⁻³ mL = 5 m⇒ Substitute these values into equation 2
ΔT = (3×10⁻³)/(29×5)ΔT = 0.003/145ΔT = 0.0000207 KHence, the change in temperature caused is 0.0000207 K
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give 3 example of right quantities that have no unit
Answer:
velocity ratio
mechanical advantage
Relative density
When 16.35 moles of SI reacts with 11.26 moles of N2, how many moles of SI3N4 are formed
Answer:
5.45 moles
Explanation:
The chemical balanced equation of this reaction is;
3Si + 2N2 → Si3N4
From the balanced equation, we can see that that 3 moles of Si reacts with 2 moles of N2 to produce 1 mole of Si3N4.
Thus imies that the molar ration of Si to N2 is 3:2.
Now, we are told that 16.35 moles of Si reacts with 11.26 moles of N2.
16.35
Thus, using the ratio 3:2, we can say that moles of 16.35 miles of Si will react completely with (16.35 × ⅔) = 10.9 moles of N2.
Remaining N2 = 11.26 - 10.9 = 0.36 will be the excess.
From our balanced chemical equation, we saw that;
3 moles of Si produced 1 mole of Si3N4.
Thus; 16.35 moles of Si will produce;
no. of moles of Si3N4 produced = (1 × 16.35)/(3.0) = 5.45 moles
What is the animal behavior where organisms imitate another organism or environment in some way?
Mimicry. This is when oraganisms imitate another oraganism whether it be physical or behavoioral.
a student throws a 140 g snowball at 8.5 m/s at the side of a schoolhouse, where it hits and sticks. what is the magnitude of the average force on the wall if the duration of the collision is .16 s?
Answer:
7.4375N
Explanation:
According to Newtons second law
F = ma
m is the mass = 140g = 0.14kg
Get the acceleration
v = u + at
8.5 = 0+0.1a
a = 8.5/0.16
a = 53.125m/s²
Get the required force
F = 0.14 * 53.125
F = 7.4375N
Hence the magnitude of the average force on the wall is 7.4375N
A ray diagram is shown. A tree acts as the object further than 2 F away from a biconvex lens. The distance between 2 F and the object is labeled W. The distance between F and 2 F is labeled X. There I a light ray parallel to the principal axis is bent through F on the image side of the lens. There is a ray straight through the center of the lens. The rays intersect a point below the principle axis between F and 2 F on the image side of the lens and is closer to the principal axis than the object is tall. The intersect point is labeled Z and the distance between F and 2 F on the image side of the lens is labeled Y. Which letter represents the location of the image produced by the lens? W X Y Z
Answer:
Z
Explanation:
correct on edge
Answer: Z
good luck!
The unit of work done is called derived unit why
Pause
He
When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be:
OA. 40 m/s
OB. 9.8 m/s2
OC 2.5 m/s2
OD. 0.40 m/s2
Answer:
C
Explanation:
a=f/m
10Kgm/s2/4kg
2.5m/s2
When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be 2.5 m/s².
What is acceleration?The rate at which an item changes its velocity is known as acceleration, a vector quantity. If an object's velocity is changing, it is acceleration. The net acceleration that objects get as a result of the combined action of gravity and centrifugal force is known as the Earth's gravity, or g. It is a vector quantity whose strength or magnitude is determined by the norm and whose direction correlates with a plumb bob.
Given in the question, force 10 N and mass 4.0 Kg the acceleration is,
a = 10/4 = 2.5 m/sec²
When an unbalanced force of 10 N is applied to an object whose mass is 4.0 kg, the acceleration of the object will be 2.5 m/s².
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Model the Earth's atmosphere as 79% N2, 19% O2, and 2% Argon, all of which are in thermal equilibrium at 280 K. At what height is the density of O half its value at sea level
Answer:
[tex]9.495 \times 10^3\ m[/tex]
Explanation:
From the given information:
Using the equation of Barometric formula as related to density, we have:
[tex]\rho (z) = \rho (0) e^{(-\dfrac{z}{H})} \ \ \ \ --- (1)[/tex]
Here;
[tex]p(z) =[/tex] the gas density at altitude z
[tex]\rho(0) =[/tex] the gas density at sea level
H = height of the scale
[tex]H = \dfrac{RT}{M_ag } \ \ \ --- (2)[/tex]
Also;
R represent the gas constant
temperature (T) a= 280 K
g = gravity
[tex]M_a =[/tex] molaar mass of gas; here, the gas is Oxygen:
∴
[tex]M_a =[/tex] 15.99 g/mol
= 15.99 × 10⁻³ kg/mol
[tex]H = \dfrac{8.3144 \times 280}{15.99 \times 10^{-3} \times 9.8 }[/tex]
[tex]H =14856.43 \ m[/tex]
Now we need to figure out how far above sea level the density of oxygen drops to half of what it is at sea level.
This implies that we have to calculate z;
i.e. [tex]\rho(z) =\dfrac{\rho(0) }{(2)}[/tex]
By using the value of H and [tex]\rho(z)[/tex] from (1), we have:
[tex]\dfrac{\rho(0) }{(2)} = \rho (0) e^{(-\dfrac{z}{14856.43})}[/tex]
∴
[tex]\dfrac{1}{2} = e^{(-\dfrac{z}{14856.43})} \\ \\ e^{(-\dfrac{z}{14856.43})} =\dfrac{1}{2}[/tex]
By rearrangement and taking the logarithm of the above equation; we have:
[tex]- z = 14856.43 \times \mathtt{In}\dfrac{1}{2} \\ \\ -z = 14856.43 \times (-0.6391) \\ \\ z = 9495 \ m \\ \\ z = 9.495 \times 10^3\ m[/tex]
As a result, the oxygen density at [tex]9.495 \times 10^3\ m[/tex] is half of what it is at sea level.
Can the tangent line to a velocity vs. time graph ever be vertical? Explain.
Answer:
No. Because it would correspond to zero Instantaneous acceleration.
Explanation:
hope this helps
While visiting Planet Physics, you toss a rock straight up at 15 m/s and catch it 2.7 s later. While you visit the surface, your cruise ship orbits at an altitude equal to the planet's radius every 250 min .
Part A What is the mass of Planet Physics?
Part B What is the radius of Planet Physics?
Answer:
R = 7.915 10⁶ m, M = 1.04 10³⁵ kg
Explanation:
Let's start by finding the acceleration of the planet's gravity, let's use the kinematic relations
v = v₀ - g t
the velocity of the body when it falls is the same for equal height, but it is positive when it rises and negative when it falls
v = -v₀
-v₀ = v₀ - g t
g = 2v₀ / t
g = 2 15 / 2.7
g = 11.11 m / s²
I now write the law of universal gravitation and Newton's second law
F = m a
G m M / R² = m a
a = g
g = G M / R²
Now let's work with the cruiser in orbit
F = ma
acceleration is centripetal
a = v² / r
G m M / r² = m v² / r (1)
the distance from the center of the planet is
r = R + h
r = R + R = 2R
we substitute in 1
G M / 4R² = v² / 2R
G M / 2R = v²
The modulus of the velocity in a circular orbit is
v = d / T
the distance is that of the circle
d = 2π r
v = 2π 2R / T
v = 4π R / T
G M / 2R = 16pi² R² / T²
T² = 32 pi² R³ / GM
let's write the equations
g = G M / R² (2)
T² = 32 pi² R³ / GM
we have two equations and two unknowns, so it can be solved
let's clear the most on the planet and equalize
g R² / G = 32 pi² R³ / GT²
g T² = 32 pi² R
R = g T² / 32 pi²
let's reduce the period to SI units
T = 250 min (60 s / 1 min) = 1.5 104 s
let's calculate
R = 11.11 (1.5 10⁴) ² / 32 π²
R = 7.915 10⁶ m
from equation 2 we can find the mass of the planet
M = g R² / G
M = 11.11 (7.915 10⁶) ² / 6.67 10⁻¹¹
M = 1.04 10³⁵ kg
10 POINTS!! SPACE QUESTION!
Answer:
The Gas Giants have more moons.
Explanation:
Mercury-0
Venus-0
Earth-1
Mars-2
Jupiter-66
Saturn-62
Uranus-27
Neptune-13
which statement can best describe the energy transformations that occur when a pendulum swings back and forth?
a. gravitational energy is converted to spring energy and back.
b. gravitational energy is converted to kinetic energy and back
c. kinetic energy is converted to spring energy and back
d. none of the above.
Answer:
I think it is C, I'm not for sure.
Electric Charge and Current Quiz CP ( fill in blank)
Answer:
1. Positive
2. Negative
3. induction
4. Insulator
5. Voltage
6. Static energy
7. Positive, Negative
8. Resistance
9. Increase
Would appreciate if you mark me as brainliest answer
1. Protons have positive electric charge and electrons have negative electric charge.
2. Opposite charges attract and like charges repel.
3. Charging by induction is the rearrangement of electrons on a neutral object caused by a nearby charged object.
4. Insulator are materials that do not allow electric current to pass through easily.
5. Voltage is the accumulation of electrical charges on on object.
6.Current is usually the flow of static electricity.
7. Charges flow from positive voltage to negative voltage.
8. The tendency of material to oppose the flow of electron is called resistance.
9. Making wires thinner, longer or hotter Increase the resistance.
What is current?The current is the stream of charges which flow from positive to negative terminal of voltage source.
Voltage is the collection or storage of charges. Resistance of the circuit is the opposition to the flow of current.
Charging a neutral object is done by induction. Like charges repel each other and unlike charges attract each other. The electron are positive charged and proton are positive charged.
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A car advertisement states that a certain car can accelerate from rest to
27m/s in 4.9 seconds at a temperature of 75F. What is the acceleration of
the car?
Answer:
Acceleration of the car = 5.51 m/s²
Explanation:
Given:
Initial speed of car = 0 m/s
Final speed of car = 27 m/s
Time taken by car = 4.9 seconds
Find:
Acceleration of the car
Computation:
Using first equation of motion
v = u + at
Where
v = Final velocity
u = Initial velocity
t = Time taken
a = Acceleration
So,
v = u + at
27 = 0 + a(4.9)
a(4.9) = 27
a = 5.51 m/s²
Acceleration of the car = 5.51 m/s²
Drag each statement to the correct location on the table.
Match the characteristics with the states of matter.
does not have
a definite shape
or volume
has definite volume
but does not have a
definite shape
has a definite shape
and volume
changes to liquid
on heating
changes to liquid
on cooling
changes to solid
on cooling
Solid
Liquid
Gas
mentum. All rights reserved.
Answer:
Solid:
- has definite shape and volume.
- change to liquid on heating.
Liquid:
- has definite volume but does not have definite shape .
- changes to solid on cooling.
Gas :
- does not have definite shape or volume.
- change to liquid on cooling
Active listening includes all of the following EXCEPT: A. paraphrasing B. clarifying C. ignoring D. empathizing Please select the best answer from the choices provided. A B C D
Answer:
C: Ignoring
Explanation:
On edge 2021
Answer:
It's C.
Explanation:
A circuit is built based on this circuit diagram.
What is the equivalent resistance of the circuit?
0.61 Ω
Ο 1.6 Ω
7.5Ω
Ο 18 Ω
12V
3.0 Ω.
6.0 Ω
9.Ο Ω.
Will mark brainlyest. No “links” I don’t want them
[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the concept of resistors,
The equivalent circuit is given as,
1/Rp = 1/3 + 1/6 + 1/9
1/Rp = 6+3+2/18
1/Rp = 11/18
Rp = 18/11 ==> 1.63 ==> 1.6 ohms
hence the equivalent resistance of the circuit is 1.6 ohms
The equivalent resistance of the circuit is 1.6Ω. The correct option is B.
What is Ohm’s law?Ohm’s law state that ” At constant temperature, the current (I) flowing through a conductor is directly proportional to the potential difference(V) across the two endpoints of the given conductor.”
I.e V ∝ I
V=IR
Where V= potential difference across the conductor.
I = current flowing through the conductor.
R= constant pf proportionality i.e resistance which unit is ohm(Ω).
There are two ways we can connect the resistors.
(i) series connection
If a number of resistors are said to be connected in series When the same current (I) flows through them.
Let R1, R2, and R3 be the resistors connected in series.
Then the R equivalent is
Req=R1+R2+R3
(ii) parallel connection
A number of resistors are said to be connected in parallel when the same potential difference(V) exists across each of them.
Let R1, R2, and R3 be the resistors connected in parallel.
Then the R equivalent is
1/Req=1/R1+1/R2+1/R3
In this question,
The three resistance connected in parallel by applying the above formula we get,
1/Req=1/R1+1/R2+1/R3
1/Req = 1/3 + 1/6 + 1/9 ................. (∵R1=3Ω,R2=6Ω AND R3=9Ω)
1/Req =11/18
Req=18/11
Req=1.6363Ω
Req≈1.6Ω
Therefore, The equivalent resistance of the circuit is 1.6Ω.
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Determine the direction of the force on a charge.
a. along the line between the charge and the center of the square outward of the center
b. along the side of the square outward of the other charge that lies on the side
c. along the line between the charge and the center of the square toward the center
d. along the side of the square toward the other charge that lies on the side
Answer:
hi your question is incomplete below is the complete question
A charge of 2.15 mC is placed at each corner of a square 0.500 m on a side. Determine the direction of the force on a charge.
answer : Along the line between the charge and the center of the square outward of the center ( A )
Explanation:
The direction of the force on a charge is along the line between the charge and the center of the square outward of the center
Given that; Fnet = 3.17 * 10^-1 N ( calculated value )
The nature of the Force is repulsive in nature
attached below is a Pictorial representation of the direction of the force on a charge
Optical tweezers use light from a laser to move single atoms and molecules around. Suppose the intensity of light from the tweezers is 1000 W/m2, the same as the intensity of sunlight at the surface of the Earth. (a) What is the pressure on an atom if light from the tweezers is totally absorbed
Answer:
a= 4.4×10 m/s^2
Explanation:
pressure P = E/c
Where, E = 100 W/m^2 intensity of light
c= speed of light = 3×10^8 m/s
P = 1000/ 3×10^8
P = 3.33×10^(-6) Pa
Force F = P×A
P is the pressure and c= speed of lightF = 3.33×10^{-6}×6.65×10(-29)
= 2.22×10^{-6}
acceleration a = F/m = 2.22×10^{-6}/ 5.10×10^{-27}
a= 4.4×10 m/s^2
You want to find out how many atoms of the isotope 65Cu are in a small sample of material. You bombard the sample with neutrons to ensure that on the order of 1% of these copper nuclei absorb a neutron. After activation, you turn off the neutron flux and then use a highly efficient detector to monitor the gamma radiation that comes out of the sample. Assume half of the 66Cu nuclei emit a 1.04-MeV gamma ray in their decay. (The other half of the activated nuclei decay directly to the ground state of 66Ni.) (Enter your answer using one of the following formats: 1.2e-3 for 0.0012 and 1.20e 2 for 120.)
Required:
a. If after 10 min (two half-lives) you have detected 10000 MeV of photon energy at 1.04 MeV, approximately how many 65Cu atoms are in the sample?
b. Assume the sample contains natural copper. Refer to the isotopic abundances listed in your text (Chemical and Nuclear Information for Selected Isotopes) and estimate the total mass of copper in the sample.
Answer:
a) number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶ atoms
b) m_total Cu = 1.585 10⁹ u = 2.632 10⁻¹⁸ kg
Explanation:
a) For this exercise let's start by using the radioactive decay ratio
N = N₀ [tex]e^{- \lambda t}[/tex]o e - lambda t
The half-life time is defined as the time it takes for half of the radioactive (activated) atoms to decay, therefore after two half-lives there are
N = ½ (½ N₀) = ¼ N₀
N₀ = 4 N
in each decay a photon is emitted so we can use a direct rule of proportions. If an atom emits a photon it has Eo = 1,04 Mev, how many photons it has energy E = 10,000 MeV
# _atoms = 1 atom (photon) (E / Eo)
# _atoms = 1 10000 / 1.04
# _atoms = 9615,4 atoms
N₀ = 4 #_atoms
N₀ = 4 9615,4
N₀= 38461.6 atoms
in the exercise indicates that half of the atoms decay in this way and the other half decays directly to the base state of Zinc, so the total number of activated atoms
N_activated = 2 # _atoms
N_activated = 2 38461.6
N_activated = 76923.2
also indicates that 1% = 0.01 of the nuclei is activated by neutron bombardment
N_activated = 0.01 N_total
N_total = N_activated / 0.01
N_total = 76923.2 / 100
N_total = 7.692 10⁶ atoms
so the number of copper atoms 65 (⁶⁵Cu) is 7.692 10⁶
b) the natural abundance of copper is
⁶³Cu 69.17%
⁶⁵Cu 30.83%
Let's use a direct proportion rule. If there are 7.692 10⁶ ⁶⁵Cu that represents 30.83, how much ⁶³Cu is there that represents 69.17%
# _63Cu = 69.17% (7.692 10⁶ / 30.83%)
# _63Cu = 17.258 10⁶ atom ⁶³Cu
the total amount of comatose is
#_total Cu = #_ 65Cu + # _63Cu
#_total Cu = (7.692 + 17.258) 10⁶
#_total Cu = 24.95 10⁶
the atomic mass of copper is m_Cu = 63.546 u
m_total = #_totalCu m_Cu
m_total = 24.95 10⁶ 63,546 u
m_total = 1.585 10⁹ u
let's reduce to kg
m_total Cu = 1.585 10⁹ u (1,66054 10⁻²⁷ kg / 1 u)
m_total Cu = 2.632 10⁻¹⁸ kg
HURRY IM TIMED
How can you make people feel inspired?
By leading them on an emotional journey through various states to inspiration
By talking about something that interests you
By proving yourself to be a trustworthy speaker
By making them laugh and feel comfortable
Answer:
By talking about something that interesto you’
sorry if wrong
Explanation:
g A high-speed flywheel in a motor is spinning at 500 rpm when a power failure suddenly occurs. The flywheel has mass 39.0kg and diameter 78.0cm. The power is off for 34.0s, and during this time the flywheel slows due to friction in its axle bearings. During the time the power is off, the flywheel makes 170 complete revolutions.At what rate is the flywheel spinning when the power comes back on?
Answer:
[tex]10.54\ \text{rad/s}[/tex]
Explanation:
[tex]\omega_i[/tex] = Initial angular velocity = 500 rpm = [tex]500\times \dfrac{2\pi}{60}\ \text{rad/s}[/tex]
[tex]\omega_f[/tex] = Final angular velocity
t = Time = 34 s
[tex]\theta[/tex] = Angular displacement = 170 revs = [tex]170\times 2\pi\ \text{rad}[/tex]
[tex]\alpha[/tex] = Angulr acceleration
From the kinematic equations of angular motion we have
[tex]\theta=\omega_it+\dfrac{1}{2}\alpha t^2\\\Rightarrow \alpha=\dfrac{\theta-\omega_it}{\dfrac{1}{2}t^2}\\\Rightarrow \alpha=\dfrac{170\times 2\pi-500\times \dfrac{2\pi}{60}\times 34}{\dfrac{1}{2}\times 34^2}\\\Rightarrow \alpha=-1.23\ \text{rad/s}^2[/tex]
[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=500\times \dfrac{2\pi}{60}+(-1.23)\times 34\\\Rightarrow \omega_f=10.54\ \text{rad/s}[/tex]
The rate at which the wheel is spinning when the power comes back on is [tex]10.54\ \text{rad/s}[/tex].
The density of 1 kilogram of gold is
Answer:
0.02 kg/cm³
Explanation:
Which type of electromagnetic radiation is used to keep food warm?
O A. Infrared radiation
O B. Visible light
O C. Gamma rays
D. X-rays
Answer:
A. infrared
Explanation:
Heat lamps used to keep foods warm are infrared on the light spectrum
The half-life for a 400-gram sample of radioactive element X is 3 days. How much of element X remains after 15 days have passed?
A.
12.5 g
B.
25 g
C.
50 g
D.
100 g
Student Exploration: Energy Conversion in a SystemNCVPS Chemistry Fall 2014Vocabulary: energy, gravitational potential energy, heat energy, kinetic energy, law of conservation of energy, specific heat capacityPrior Knowledge Questions (Do these BEFORE using the Gizmo.)A battery contains stored energy in the form of chemical energy.1. What are some examples of devices that are powered by batteries? ____________________________________________________________________________________________2. What different forms of energy are dmonstrated by these devices? ___________________ _________________________________________________________________________Gizmo Warm-upEnergy constantly changes from one form to another, but in a closed system, the total amount of energy always remains the same. This concept is known formally as the law of conservation of energy.The Energy Conversion in a System Gizmo™ allows you to observe the law of conservation of energy in action. In the Gizmo, a suspended cylinder has gravitational potential energy. When the cylinder is released, the
Answer:
a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights
b) ed lights and flashlights transform into light energy and thermal energy
c) Em₀ = U = m gh, Em_f = K = ½ m v²
Explanation:
In this exercise ask to complete the sentences
a) Battery-operated devices have: small led lights, flashlights, wireless keyboards and mice, watches, electronic weights
b) These devices transform the chemical energy stored in the batteries into other forms of energy.
Led lights and flashlights transform into light energy and thermal energy
Keyboards transform into electromagnetic energy that is emitted
clocks transform to mechanical energy from the movement of the needles
Electronic weights transforms the chemical energy of the baria into gravitational potential energy that prevents the movement of the plate and this translates into the reading of the body weight
c) The total energy of the cylinder mechanical energy when sustained is
Em₀ = U = m gh
it is transformed as it descends into kinetic energy, at any point
Emₙ = K + U = 1/2 m v² + m g y
at the lowest point of the trajectory all energy is transformed
Em_f = K = ½ m v²
19. What is shape of BF3
Explanation:
The geometry of the BF 3 molecule is called trigonal planar (see Figure 5). The fluorine atoms are positioned at the vertices of an equilateral triangle. The F-B-F angle is 120° and all four atoms lie in the same plane.
What are the similarities between a resultant force equilibrant force?
Answer:
Explanation:
Resultant is a single force that can replace the effect of a number of forces. "Equilibrant" is a force that is exactly opposite to a resultant. Equilibrant and resultant have equal magnitudes but opposite directions.