A concave mirror has a centre of curvature of 24.0 cm. An object 2.5 cm tall is placed 40.0 cm in front of the mirror.
a) At what distance from the mirror will the image be formed?
b) What is the height of the image?

Answer:

"the spark plug gap"

The plug provides a gap between the input voltage and the ground supplied by the car chassis.

Answer:

60 N.C

Explanation:

The box will move in the direction of the push and pull with a force of 60 N. C.

If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes. , then the distance must she travel so the two of you can travel at the same speed would be 30 feet.

The total distance covered by any object per unit of time is known as speed. It depends only on the magnitude of the moving object.

As given in the problem If you and your friend are pushing a box at the same constant speed. You pushed 20 feet in 10 minutes, your friend was pushing for 5 minutes.

The distance traveled by box = 20 + 10

                                                 = 30 feets

Thus, the distance must she travel so the two of you can travel at the same speed would be 30 feet.

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Answer:

no work done

Explanation:

unless you moved the object

When we apply a force on an object, but the object remains at rest when the force is applied, then we have zero work done on the object because the object does not move.

Work done by a force is defined as the product of the displacement and the component of the force exerted by the object in the direction of displacement. Work done is expressed as:

Work done= Force* Displacement

When an object is at rest, there is no external force on it except gravity acting on it, in which case work will be zero because the force acting on it is perpendicular. Thus displacement is zero and if displacement is zero then work done will be zero.

Suppose that displacement is zero then,

W=f×0

Work done is zero

Thus, the work done is zero.

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Answer:

The formula for potential energy depends on the force acting on the two objects. For the gravitational force the formula is P.E. = mgh, where m is the mass in kilograms, g is the acceleration due to gravity (9.8 m / s2 at the surface of the earth) and h is the height in meters.

Answer:

I can give you a list of noncontact forces off of my head, if that is what you need.

Explanation:

First, gravity. It acts everywhere and pulls down every object that is in the air towards the ground, unless they have an equal and opposite force that counters it.

Second, wind. I don't think this will count because wind is a physical thing, but it can be used in the same way as we did with gravity. If the force counteracting it is larger, equal, and opposite of the force it is countering, then it will move forward, through the wind.

Answer:

1. wisest

2. more delicious

3. majestic (not sure about this one)

4. industrious

5. happiest

The best example of physics in the body is the movement of an arm throwing a ball. The correct option is D.

Physics is the branch of science that studies the structure of matter and how the universe's fundamental constituents interact.

It investigates objects ranging from the very small to the entire universe using quantum mechanics and general relativity.

Physics is the natural science that investigates matter, its fundamental constituents, its motion and behavior in space and time, as well as the related entities of energy and force.

Physics is one of the most fundamental scientific disciplines, with the primary goal of understanding how the universe functions.

The movement of an arm throwing a ball is the best example of physics in the body.

Thus, the correct option is D.

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Answer:

Mercury's natural state is where the atoms are close to each other but are still free to pass by each other. In which state(s) could mercury naturally exist?

Liquid is the answer

Explanation:

Answer:

C

Explanation:

fuses of same kind can be used for different things, and of different kinds could be used for different things as well.

Can i ask u a question

Brainliest me please

Answer:

Explanation:

It will be B.

The correct answer is the same mass and less weight.

The weight decreases. Your weight will be 1/6 of the weight on the moon that you had on Earth. This is because the mass of the moon is less hence the gravitational pull is very low compared to Earth.

Therefore, the mass of an object on the Moon remains the same as its mass on Earth. But its weight gets less because the gravity on the moon is less than on the Earth.

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Answer:

Below

Explanation:

On the moon, an objects weight will be different than it is on earth. This is because we cannot change the mass of an object, the mass of an object is the measure of matter an object has. However the weight is depended on the gravitational pull of whatever planet you are on. In this case, weight will be lighter on the moon than it is on earth because the moon's gravitational pull is 1.62 m/s^2 while earths is around 9.8 m/s^2.

Hope that helps!

Answer:

getting faster

Explanation:

the curve gets more steeper, and steeper line shows more distance for less time, meaning faster.

Answer

In the parallel circuit, you have to position the switch on only one of the loops.

The mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

Let us recall that the law of conservation of mass states that, mass can neither be created nor destroyed but is converted from one form to another. In accordance with this law of conservation of mass. The mass of the orange must remain the same after it has been cut in pieces.

Hence, If the mass of an orange is measured after it has been cut into pieces, the mass of the orange after it has been cut into pieces will still remain the same as the mass of the whole orange.

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Answer:

A force of 20N acts on each cm^2 of area

The coefficient of kinetic friction between the block and the horizontal surface is 0.051.

The given parameters;

The acceleration of the block is calculated as follows;

[tex]v^2 = u^2 + 2(-a)s\\\\v^2 = u^2 - 2as\\\\a = \frac{u^2 - v^2}{2s} \\\\a = \frac{3^2 - 0^2}{2\times 9} \\\\a =0.5 \ m/s^2[/tex]

The coefficient of kinetic friction between the block and the horizontal surface is calculated as follows;

[tex]\mu_k mg = ma\\\\\mu_k = \frac{a}{g} \\\\\mu_k = \frac{0.5}{9.8} \\\\\mu_k = 0.051[/tex]

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Answer:

instantaneous velocity is a velocity covered at an instant while average velocity is the change in distance/ the change in time taken

Answer:

65km/h

Explanation:

Here,

Relative velocity of car moving in different directions with different velocities =Va + Vb

=25+40

=65 km/h

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

Please find attached photograph for your answer.

Hope it helps.

Do comment if you have any query.

The conservation of the momentum allows to find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1- \frac{m_2}{m_1} }[/tex]  

the momentum is defined by the product of the mass and the velocity of the body.

        p = mv

The bold letters indicate vectors, p is the moment, m the mass and v the velocity of the body.

If the system is isolated, the forces during the collision are internal and the it  is conserved. Let's find the momentum is two instants.

Initial instant. Before crash.

      p₀ = m₁ u₀ + 0

Final moment. After crash.

      [tex]p_f = m_1 u_f + m_2 v_f[/tex]  

The momentum is preserved.

      p₀ = [tex]p_f[/tex]  

      [tex]m_1 u_o = m_1 u_f + m_2 v_f[/tex]  

Since the collision is elastic, the kinetic energy is conserved.

      K₀ = [tex]K_f[/tex]

      ½ m₁ u₀² = ½ m₁ [tex]u_f^2[/tex]  + ½ m₂  [tex]v_f^2[/tex]  

Let's write our system of equations.

       [tex]m_1 u_o = m_1 u_f + m_2 v_f \\m_1 u_o^2 = m_1 u_f^2 + m_2 v_f^2[/tex]

Let's solve

       [tex]u_f = u_o - \frac{m_2}{m_2} \ v_f \\u_f^2 = u_o^2 - \frac{m_2}{m_1} \ v_f^2[/tex]

       [tex]( u_o - \frac{m_2}{m_1} v_f)^2 = u_o - \frac{m_2}{m_1} \ v_f^2 \\u_o^2 - 2 \frac{m_2}{m_1} \ u_o v_f + (\frac{m_2}{m_1} )^2 v_f^2 = u_o^2 - \frac{m_2 }{m_1} \ v_f^2[/tex]  

        [tex]2 \frac{m_2}{m_1} \ u_o = \frac{m_2}{m_1} v_f \ ( 1 - \frac{m_2}{m_1}) \\v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]

In conclusion, using the conservation of momentum, we can find the velocity of the second body after the elastic collision is:

           [tex]v_f = \frac{2u_o}{1-\frac{m_2}{m_1} }[/tex]  

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Answer:

So this is just a ratio/proportion problem

so lets say its in boys:minutes

so in the first scenario

20:8

and we want to find

x:10

So proportion really

20/8=x/10

cross multiply

25

25 boys can sweep it in 10 minutes

Answer:

They will go backwards?

Explanation:

If positive they go forward but is negative they go backwards.

Answer:

directly proportional

Explanation:

Explanation:

Uhhhh here is an example

a=vt. =27 m/s10 s. =2.7 m/s2.

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Acceleration of the car is ~

[tex] \boxed{1.5 \: \: m/s}[/tex]

[tex] \large \boxed{ \mathfrak{Step\:\: By\:\:Step\:\:Explanation}}[/tex]

We know that,

Acceleration = rate of change in velocity ~

that is ~

where,

now, let's solve ~

Answer:

c. lubricant..........

Answer:

A

Explanation:

There's no way to tell, without knowing the resistance of either X-1 or X-2, or the reading on A3.

Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.

They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.

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Which is not a general characteristic of starburst galaxies?

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Let the ball at the ground be A and that at the top be B.

Assume that you see the motion of A while sitting at B.

You(B) are obviously at rest w.r.t. yourselves. However you(B) and A have the same acceleration in the same direction. Thus acceleration of A w.r.t. you(B) is 0.

Thus, to you, it will appear as if A is travelling towards you with an uniform speed of 20m/s.

Dividing the distance 20m with that speed, we get that A reaches you(B) in 1s.

Now, you have considered these motions and time by assuming you were stationed at B. However, the time taken for A to meet B shouldn't be dependent on which reference frame you assume. Thus, time taken for A and B to collide is 1s.

Since B falls freely, he covers a distance of  1/2(g)(1²)=5  (assuming g = 10m/s²)

Thus, they meet at a height of (20–5)m = 15m from the ground.