We have that for the Question " constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110." it can be said that
the final velocity vf is
[tex]vf=3.83m/s[/tex]
and the applied force Fnew is
[tex]F_{new}=3.43N[/tex]
From the question we are told
A constant applied force Fp of 11.0 N pushes a box with a mass=7 kg a distance x=15.0 m across a level floor. The coefficient of kinetic friction between the box and the floor is .110. Assuming the box starts from the rest, what is the final velocity vf of the box at 15.0 m point? If there were no friction between the box and the floor, what applied force F new would give the box the same final velocity?
Generally the equation for the Force is mathematically given as
F_p-\mu mg=ma
Therefore
11-0.110*7*9.8=7*a
a=0.49m/s^2
Using Newtons equation
v^2=u^2+2as
v^2=0+2*0.49*15
v=3.83m/s
Therefore
F=ma
F=0.49*7
F_{new}=3.43N
Therefore
the final velocity vf is
[tex]vf=3.83m/s[/tex]
and the applied force Fnew is
[tex]F_{new}=3.43N[/tex]
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Definition of continental polar
cold, dry, and stable air masses .
Calculate the volume occupied by a glass cup having a mass of 260 g knowing that the
density of glass is equal to 2.6 g/cm3
Answer:
100 milliliters
Explanation:
Which graph shows acceleration? A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a concave line running from 0 seconds 0 meters upward. A graph of position (meters) versus time (seconds) has a straight line running from 0 seconds positive number of meters downward to some later time 0 meters.
It's the one that has a concave line running upward.
Answer:
its the middle one
Explanation:
i did it on edge 2021
Which two criteria are least important for engineers to consider when developing a process to produce an important chemical?
A. The process should be located in a major city.
B. The process should use local, organic reactants.
C. The process should produce a significant amount of the product.
D. The process should be cost-effective.
Answer:
two least important criteria are A and B.
Explanation:
In an industrial production process there are criteria on the location of the production plants. Among the most important criteria we have that a good quantity is produced from the producer and that the process is cost-beneficial - cats to increase the profit of the company.
There are other desirable but minor criteria
A) The size of the city is of minor importance
b) Finding raw material locally is interesting, but its importance is less, the raw material can be sent from other locations.
Consequently the two least important criteria are A and B.
Answer:
A. The process should be located in a major city.
B. The process should use local, organic reactants.
Explanation:
ap.ex
A circular loop of radius 13 cm carries a current of 13 A. A flat coil of radius 0.94 cm, having 58 turns and a current of 1.9 A, is concentric with the loop. The plane of the loop is perpendicular to the plane of the coil. Assume the loop's magnetic field is uniform across the coil. What is the magnitude of (a) the magnetic field produced by the loop at its center and (b) the torque on the coil due to the loop
Answer:
[tex]6.28\times 10^{-5}\ \text{T}[/tex]
[tex]1.92\times 10^{-6}\ \text{Nm}[/tex]
Explanation:
[tex]\mu_0[/tex] = Vacuum permeability = [tex]4\pi 10^{-7}\ \text{H/m}[/tex]
[tex]I_l[/tex] = Current in circular loop = 13 A
[tex]r_l[/tex] = Radius of circular loop = 13 cm
[tex]N[/tex] = Number of turns = 58
[tex]r_c[/tex] = Radius of coil = 0.94 cm
[tex]I_c[/tex] = Current in coil = 1.9 A
[tex]\theta[/tex] = Angle between loop and coil = [tex]90^{\circ}[/tex]
Magnitude of magnetic field in circular loop
[tex]B_l=\dfrac{\mu_0I_l}{2r_l}\\\Rightarrow B_l=\dfrac{4\pi 10^{-7}\times 13}{2\times 13\times 10^{-2}}\\\Rightarrow B_l=6.28\times 10^{-5}\ \text{T}[/tex]
The magnetic field produced by the loop at its center is [tex]6.28\times 10^{-5}\ \text{T}[/tex].
Torque is given by
[tex]\tau=\pi NI_cr_c^2B_l\sin\theta\\\Rightarrow \tau=\pi 58\times 1.9\times (0.94\times 10^{-2})^2\times 6.28\times 10^{-5}\sin90^{\circ}\\\Rightarrow \tau=1.92\times 10^{-6}\ \text{Nm}[/tex]
The torque on the coil due to the loop [tex]1.92\times 10^{-6}\ \text{Nm}[/tex].
Which wave type could move in the empty space between the Sun and the Earth
Answer:
Electromagnetic waves
1. A temperature of 162 °F is equivalent to what temperature in kelvins?
(a) 373 K
(b) 288 K
(C) 345 K
(d) 201 K (e) 308 K
345k
Because the formula for our Fahrenheit is Kevin = 5 * (°Fahrenheit + 459.67)
9.
A block of wood and a block of aluminum have been sitting out for a while. How do their temperatures compare?
Answer:
Block of aluminum
Explanation:
The block of aluminum because of the conductivity, and is a metal, so it gets hotter faster
The temperature of wood and the aluminium will depend upon thier thermal coductivity.
What is thermsal conductivity?The thermal conductivity of any material is defined as the amount of heat from a material can flow in a unit area per unit degree centigrade for a unit distance.
The thermal conductivity of wood is around 0.90 to 0.197 w/mk and that of aluminium is around 88 to 251 w/mk.
We can see that the aluminium block will absorb much amount of heat as compared to the wood block. Because the thermal conductivity of aluminium is much higher then the wood.
Hence temperature of wood and the aluminium will depend upon thier thermal coductivity.
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!Please help fast!!*18 pts*!
How is light amplified in a laser?
A. Photons "leak" through a partically reflecting mirror, causing them to travel in step.
B. Integrated circuits in a laser amplify the sound produced by photon emission.
C. Photons collide with gas particles, multiply, and reflect back and forth in a tube.
D. Electric current is amplified and directed into gas particles, which emit photons.
Answer:
A.
Explanation:
Some of these photons are absorbed by the atoms in the ground state and the photons are lost to the laser process. However, some photons cause stimulated emission in excited-state atoms, releasing another coherent photon. In effect, this results in optical amplification
A knife thrower throws a knife toward a 300 g target that is sliding in her direction at a speed of 2.30 m/s on a horizontal frictionless surface. She throws a 22.5 g knife at the target with a speed of 40.0 m/s. The target is stopped by the impact and the knife passes through the target. Determine the speed of the knife (in m/s) after passing through the target.
Answer:
The speed of the knife after passing through the target is 9.33 m/s.
Explanation:
We can find the speed of the knife after the impact by conservation of linear momentum:
[tex] p_{i} = p_{f} [/tex]
[tex] m_{k}v_{i_{k}} + m_{t}v_{i_{t}} = m_{k}v_{f_{k}} + m_{t}v_{f_{t}} [/tex]
Where:
[tex] m_{k}[/tex]: is the mass of the knife = 22.5 g = 0.0225 kg
[tex] m_{t}[/tex]: is the mass of the target = 300 g = 0.300 kg
[tex] v_{i_{k}}[/tex]: is the initial speed of the knife = 40.0 m/s
[tex] v_{i_{t}} [/tex]: is the initial speed of the target = 2.30 m/s
[tex]v_{f_{k}}[/tex]: is the final speed of the knife =?
[tex] v_{f_{t}} [/tex]: is the final speed of the target = 0 (it is stopped)
Taking as a positive direction the direction of the knife movement, we have:
[tex] m_{k}v_{i_{k}} - m_{t}v_{i_{t}} = m_{k}v_{f_{k}} [/tex]
[tex] v_{f_{k}} = \frac{m_{k}v_{i_{k}} - m_{t}v_{i_{t}}}{m_{k}} = \frac{0.0225 kg*40.0 m/s - 0.300 kg*2.30 m/s}{0.0225 kg} = 9.33 m/s [/tex]
Therefore, the speed of the knife after passing through the target is 9.33 m/s.
I hope it helps you!
Which device helps safely transmit electricity from the power plant to your
home?
Answer:
A. Transformer
Explanation:
it’s correct
Find the velocity of an object that has a mass of 500x10-6 kg and a charge of 1pc if it starts from
rest and passes through a potential difference of 120kV
Answer:
v = 4.8 10⁻⁴ m / s
Explanation:
To solve this exercise we can use the concepts of energy. In this case the potential energy is transformed into kinetic energy
U = K
q V = ½ m v²
v = [tex]\sqrt { \frac{2qV}{m} }[/tex]
in the exercise they indicate the value of the charge q₁ = 1 pC = 1 10⁻¹² C
let's calculate
v = [tex]\sqrt{ \frac{2 \ 1 \ 10^{-12} 120 \ 10^3}{500 ^{2} }[/tex]
v = 4.8 10⁻⁴ m / s
What do all clouds contain the some amount of
Answer:
A cloud is made up of liquid water droplets. A cloud forms when air is heated by the sun. As it rises, it slowly cools it reaches the saturation point and water condenses, forming a cloud.
Explanation:
0.5-lbm of a saturated vapor is converted to asaturated liquid by being cooled in a weighted piston-cylinder device maintained at 50 psia. During the phase conversion,thesystem volume decreases by 1.5 ft3; 250 Btu of heat areremoved; and the temperature remains fixed at 15F. Estimatethe boiling point temperature of this substance when itspressure is 60 psia.
Answer:
The boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
Explanation:
Given the data in the question;
Using the Clapeyron equation
[tex](\frac{dP}{dT} )_{sat } = \frac{h_{fg}}{Tv_{fg}}[/tex]
[tex](\frac{dP}{dT} )_{sat } = \frac{\frac{H_{fg}}{m} }{T\frac{V_{fg}}{m} }[/tex]
where [tex]h_{fg[/tex] is the change in enthalpy of saturated vapor to saturated liquid ( 250 Btu
T is the temperature ( 15 + 460 )R
m is the mass of water ( 0.5 Ibm )
[tex]V_{fg[/tex] is specific volume ( 1.5 ft³ )
we substitute
[tex](\frac{dP}{dT} )_{sat } =( \frac{250Btu\frac{778Ibf-ft}{Btu} }{0.5})[/tex] / [tex]( (15+460)\frac{1.5}{0.5})[/tex]
[tex](\frac{dP}{dT} )_{sat } =[/tex] 272.98 Ibf-ft²/R
Now,
[tex](\frac{dP}{dT} )_{sat } =[/tex] [tex](\frac{P_2 - P_1}{T_2 - T_1})_{sat[/tex]
where P₁ is the initial pressure ( 50 psia )
P₂ is the final pressure ( 60 psia )
T₁ is the initial temperature ( 15 + 460 )R
T₂ is the final temperature = ?
we substitute;
[tex]T_2[/tex] [tex]= ( 15 + 460 ) + \frac{(60-50)psia(\frac{144in^2}{ft^2}) }{272.98}[/tex]
[tex]T_2 = 475 + 5.2751\\[/tex]
[tex]T_2 =[/tex] 480.275 R
Therefore, boiling point temperature of this substance when its pressure is 60 psia is 480.275 R
What would be the mass of an atom with 2 protons and 3 neutrons?
Answer:
5
Explanation:
From the question given above, the following data were obtained:
Proton number = 2
Neutron number = 3
Mass number =.?
The mass number of a given atom is simply the sum of the protons and neutrons in the nucleus of the atom. Mathematically, it is expressed as:
Mass number = proton + neutron
With the above formula, we can obtain the mass number of the atom as follow:
Proton number = 2
Neutron number = 3
Mass number =.?
Mass number = proton + neutron
Mass number = 2 + 3
Mass number = 5
Thus, the mass number the atom is 5.
Suppose you design an apparatus in which a uniformly charged disk of radius R is to produce an electric field. The field magnitude is most important along the central perpendicular axis of the disk, at a point P at distance 2.00R from the disk. Cost analysis suggests that you switch to a ring of the same outer radius R but with inner radius R/2.00 . Assume that the ring will have the same surface charge density as the original disk. If you switch to the ring, by what percentage will you decrease the electric field magnitude at P?
Answer:
The electric field will be decreased by 29%
Explanation:
The distance between point P from the distance z = 2.0 R
Inner radius = R/2
Outer raidus = R
Thus;
The electrical field due to disk is:
[tex]\hat {K_a} = \dfrac{\sigma}{2 \varepsilon _o} \Big( 1 - \dfrac{z}{\sqrt{z^2+R_i^2}} \Big)[/tex])
[tex]\implies \dfrac{\sigma}{2 \vaepsilon _o} \Big ( 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0\ R)^2+(R)^2}} \Big)[/tex]
Similarly;
[tex]\hat {K_b} = \hat {k_a} - \dfrac{\sigma}{2 \varepsilon_o} \Big( 1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ r)^2 + (\dfrac{R}{2}^2)}}\Big)[/tex]
However; the relative difference is: [tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{E_a -E_a + \dfrac{\sigma}{2 \varepsilon_o \Big[1 - \dfrac{2.0 \ R}{\sqrt{(2.0 \ R)^2 + (\dfrac{R}{2})^2}} \Big] } } { \dfrac{\sigma}{2 \varepsilon_o \Big [ 1 - \dfrac{2.0 \ R}{\sqrt{ (2.0 \ R)^2 + (R)^2}} \Big] }}[/tex]
[tex]\dfrac{\hat {k_a} - \hat {k_b}}{\hat {k_a} }= \dfrac{1 - \dfrac{2.0}{\sqrt{(2.0)^2 + \dfrac{1}{4}}} }{1 - \dfrac{2.0 }{\sqrt{(2.0)^2 + 1}}}[/tex]
[tex]= 0.2828 \\ \\ \mathbf{\simeq 29\%}[/tex]
Low air pressure and warm temperatures over land are most likely to result in which of the following weather conditions or events?
A.Clear sunny skies
B. tropical hurricane
C. chance of snow
D.Cloudy skies with rain
what is the main cause of the seasons
All of the following are characteristics of a laser diode except
Answer:
D
Explanation:
Given that all of the following are characteristics of a laser diode except
Solution.
A laser diode emit light of a single colour. That is, it emits a monochromatic light in which the light emitted monochromatically will definitely be coherent. That is, a light with a single wavelength emitted by a wide wavelength.
Also, all diode have positive and negative junction which is known as pn junction.
The incorrect among all the options is option D which is the answer.
A 4 kg particle moves at a constant speed of 2.5 m/s around acircle of radius 2 m. What is its angular momentum about the center of the circle? Answerin units of kg · m2/s. What is its moment of inertia about an axis through the center ofthe circle and perpendicular to the plane of the motion? Answer inunits of kg · m2. What is t
Explanation:
Given that,
Mass of the particle, m = 4 kg
Speed of the particle, v = 2.5 m/s
The radius of the circle, r = 2 m
We need to find the angular momentum about the center of the circle. The formula for the angular momentum is given by :
[tex]L=mvr[/tex]
Substitute all the values,
[tex]L=4\times 2.5\times 2\\\\L=20\ kg{\cdot}m^2s[/tex]
So, the angular momentum of the particle is 20 kg-m² s.
two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
Answer:
2 possible answers:
1# 2.5 Ω (when the resistors are in parallel)
2# 10 Ω (when the resistors are in series)
Explanation:
there are two possible answers for this:
1# if the resistors are in parallel in the circuit
then:
1/R-equivalent=1/5+1/5
1/R-equivalent=2/5
R-equivalent=5/2=2.5 Ω
2# if the resistors are in series in the circuit
then:
R-equivalent=5+5
R-equivalent=10 Ω
Two resistors, 5.0 ohm's each can be combined to give an equivalent resistance of
If connected in series :
R = R1 + R2
R = 5 + 5
R = 10 ohms
If connected in parallel :
R = 1/R1 + 1/R2
R = 1/ 5 + 1/5
= 2 / 5
= 2.5 ohms
What is equivalent resistance ?
"The equivalent resistance is where the aggregate resistance connected either in parallel or series is calculated." Essentially, the circuit is designed either in Series or Parallel. Electrical resistance shows how much energy one needs when you move the charges/current through your devices.
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a particle moves along of the x_axis according to the equation X=2t+3t^2, whare x is in m and t is in second. calcualt the instantaneous velocity and the instantaneous acceleration in t=3s
Answer:
Instantaneous velocity [tex]= 20[/tex] meter per second
Instantaneous acceleration [tex]= 6[/tex] meter per second square
Explanation:
Given equation of distance X = [tex]2t+3t^2[/tex]
Instantaneous velocity [tex]= \frac{dX}{dt}[/tex] [tex]= 2 + 6 t[/tex]
Substituting the value of t = 3 seconds, we get -
[tex]\frac{dX}{dt} = 2 + 6*3 = 20[/tex] meter per second
Instantaneous acceleration [tex]= \frac{d^2X}{dt^2}[/tex] [tex]= 6[/tex] meter per second square
A motorcyclist is moving 24.5 m/s
away from a stationary siren, and
hears an 894 Hz sound. What is
the frequency of the siren when the
cyclist is stationary?
(Hint: 894 Hz is the Doppler-shifted
frequency)
(Speed of sound = 343 m/s)
(Unit = Hz)
w
Answer:962 hz
Explanation: got it right on acellus
The frequency of the siren when the cyclist is stationary will be 963 Hz.
What is frequency ?The frequency of a wave is the number of cycles per second.
FRom the doppler effect,
f =f'[ (V+Vs/V-Vo) ]
Here, doppler shifted frequency f' = 894 Hz, Source is stationary, Vs =0. Velocity of observer Vo = 24.5m/s and velocity of sound wave V = 343m/s
Substitute the value into the expression , we get
f = 894 x [(343/343 - 24.5)}
f = 963 Hz
Thus, the frequency of the siren when the cyclist is stationary is 963 Hz.
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9.
A 2.85-cm diameter coin is placed a distance of 31.4 cm from a diverging lens that has a focal length
of-11.6 cm. Determine the image distance and the diameter of the image.
Answer:
image distance = -8.47 cm
diameter of the image = 0.769 cm
There is only one temperature where the Celsius and Fahrenheit thermometers will read the same and no conversions need to be made. What is it?
A. -25 degrees
B. -40 degrees
C. 25 degrees
D. 0 degrees
Answer:
-40 degrees
Explanation:
I just took the Temperature Quiz and got it right. :)
what is the minimum effort required to raise the block?
Answer:
2000 N.
Explanation:
From the question given above, the following data were obtained:
Load (L) = 8000 N
Mechanical advantage (MA) = 4
Effort (E) =?
The mechanical advantage of a machine is simply defined as:
Mechanical advantage = Load / Effort
MA = L / E
With the above formula, we can obtain the effort used to raise the load of 8000 N as follow:
Load (L) = 8000 N
Mechanical advantage (MA) = 4
Effort (E) =?
MA = L / E
4 = 8000 / E
Cross multiply
4 × E = 8000
Divide both side by 4
E = 8000 / 4
E = 2000 N
Thus, the effort used to raised the load is 2000 N.
a violin is less than 0.5 m long. a bass fiddle is more than 1.5 m long. which instrument do you expect to be able to play notes with a lower pitch and why?
Explanation:
When there is a high frequency sound the speed of the vibrations is faster and makes a high pitch sound. When there is a low frequency sound the speed of the vibrations is slower and makes a lower pitch sound.
According to Newton’s second law of motion, weight depends on an object’s mass and the net force acting on the object. True or false
Answer:
true..
Explanation:
Newton's 2nd law of motion is greater the mass of an object the more force it will take to accelerate the object
According to Newton’s second law of motion, weight depends on an object’s mass and the net force acting on the object. The given statement is true.
What is force?Force is defined as the push or pull applied to the body. Sometimes it is used to change the shape, size, and direction of the body.
The following equation help to understand the statement;
Force is defined as the product of mass and acceleration. Its unit is Newton.
F=ma
F=mg
W=mg
The weight of an item is determined by its mass and the net force exerted on it, according to Newton's second rule of motion. The provided assertion is correct.
Hence,the given statement is true.
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The statement "if I raise the temperature of
a cup of water, then an increased amount of
sugar will be dissolved" is an example of
A. an observation
B. a hypothesis.
C. a theory
Two vehicles are approaching an intersection. One is a 2600 kgkg pickup traveling at 17.0 m/sm/s from east to west (the −x−x- direction), and the other is a 1300 kgkg sedan going from south to north (the +y−+y− direction at 24.0 m/sm/s ). Part A Find the xx -component of the net momentum of this system. pxpx = nothing kg⋅m/skg⋅m/s SubmitRequest Answer Part B Find the yy-component of the net momentum of this system. pypy = 0 kg⋅m/skg⋅m/s SubmitPrevious AnswersRequest Answer Incorrect; Try Again; 4 attempts remaining Part C What is the magnitude of the net momentum?
Answer:
a) the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) the magnitude of the net momentum is 54102.5 kgm/s
Explanation:
Given the data in the question;
a) x-component of the net momentum of this system.
the second vehicle ( sedan ) doesn't have momentum along x-axis, the momentum along x-axis is strictly contributed by the pick up
so;
Px = 2600 kg × 17.0 m/s [tex](-x)[/tex]
Px = 44200 kgm/s [tex](-x)[/tex]
Therefore, the x-component of the net momentum is 44200 kgm/s [tex](-x)[/tex]
b) y-component of the net momentum of this system
Also, momentum along y-axis is entirely provided by the sedan
Py = 1300 kg × 24.0 m/s [tex](y)[/tex]
Py = 31200 kgm/s [tex](y)[/tex]
Therefore, the y-component of the net momentum is 31200 kgm/s [tex](y)[/tex]
c) magnitude of the net momentum?
magnitude of the net momentum P = √( Px² + Py² )
so we substitute
P = √( (44200)² + (31200)² )
P = √( 2927080000 )
P = 54102.5 kgm/s
Therefore, the magnitude of the net momentum is 54102.5 kgm/s