a constant force fa is applied to an object of mass m, initially at rest. the object moves in the horizontal x-direction, and the force is applied in the same direction. after the force has been applied, the object has a speed of vf. which mathematical routines can be used to determine the time in which the force is applied to the object of mass m? select two answers.

You have travelled 3.375 km in the time it took for the laptop to start up.

Distance travelled is the total amount of distance that a person, vehicle, or object has traveled from one place to another. It is usually measured in miles, kilometers, or other units of measurement. Distance traveled is an important factor when calculating time, speed, or cost.

To calculate how far you have traveled in 27 seconds, we must first calculate the distance traveled in one second. To do that, we need to divide the speed (450.0 km/hr) by 3600, which is the number of seconds in an hour.
   450.0 km/hr / 3600 = 0.125 km/s
Now that we know the distance traveled in one second, we can multiply it by the number of seconds it took for the laptop to start up (27.00 seconds).
0.125 km/s x 27.00 seconds = 3.375 km
Therefore, you have traveled 3.375 km in the time it took for the laptop to start up.

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The specific heat of the substance is 0.99 J/g°C and it could be aluminum or copper.

The final temperature of the system after the unknown substance is placed in the water is 22.0°C. This can be determined by using the formula Q = mcΔT, where Q is the heat transferred, m is the mass of the substance, c is the specific heat, and ΔT is the change in temperature. In this case, the heat transferred from the unknown substance to the water results in a temperature increase of only 0.5°C, indicating a relatively low specific heat value for the unknown substance.

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The given statement about “direction cosines tell the angle between the force vector and each of the coordinate axes” is true.

Analytical geometry defines the directional cosines of a vector as the cosines of the angles formed by the vector with the three coordinate axes. To calculate the cosine of a vector's direction, divide the relevant coordinate by the vector's length. A direction's cosine is equivalent to a unit vector's x-coordinate. One such property of the direction cosine is that the sum of the squares of all the direction cosines equals one. The cosine of the angle subtended by a line having three coordinate axes, such as the x-axis, y-axis, and z-axis, is known to be the direction cosine. The direction cosines are cos α, cos β, and cos γ if the angles subtended by these three axes α, β, and γ.

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The upward throw of a ball. The gravity acceleration is 9.8 m/s2, and its combination 1 speed is 10.8 m/s. So, 1.10 seconds pass between the ball's release and the moment it reaches its highest point.

Gravity's acceleration is constantly downward and constant, however the speed and direction of the acceleration vary. The speed of the ball is zero at its top portion in its trajectory, then it picks up speed again as it descends toward.

Because the acceleration caused by the gravitational force is operating constantly downward at the greatest point when a body was thrown vertically upwards, only that point's velocity is zero. As a result, the velocity is zero due to the acceleration.

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As you were paddling upstream, your net or final velocity is 0.5 m/s.

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction. SI unit of velocity is meter/second.

The magnitude of velocity of river flowing: u = 1.5 m/min.

The magnitude of velocity of your canoe: v = 2 m/min.

As you were paddling upstream, that is, in opposite to the flow,  your net or final velocity is = v - u

= 2 m/min - 1.5 m/min

= 0.5 m/min.

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Explanation:

ρ = 997kg/m³

v = 375m³

ρ = m/v

m = ρv

m = 997×375

m = 373,875kg

The amount of the mass of the radioactive isotope remaining after 1 hour is 1.25 g.

The mass of the sample remaining after an hour is calculated from the half life of the isotope as shown below.

The half life of the radioactive isotope = 10 minutes

The amount of the mass of the radioactive isotope remaining after 1 hour is calculated as follows;

1 hour = 60 minutes

0 half life ---------------------------> 10 g

20 minutes ------------------------> 5 g

40 minutes -----------------------> 2.5 g

60 minutes -----------------------> 1.25 g

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The 1.55 g particle must have a positive charge that is equivalent to 635 N/C times (1.55 g / 9.8 m/s2) = 11.9 C. To maintain equilibrium against gravity.

for a)

a particle's charge must be opposite in sign and magnitude to the electric force acting on it.

mg = qe

1.55 X 10 ⁻³ X 9.81 = q X 635

q = - 0.023 X 10⁻³ C

it willl be negative

We get at q = F / E = 15.09 N / 635 N/C = 0.0237 C after solving for the charge.

This indicates that the particle's charge must be positive and equal to 0.0237 Coulombs in order for it to balance against gravity in the 635 N/C-magnitude downward electric field.

qe = mg

1.6 X 10 ⁻¹⁹ E = 1.67 X 10 ⁻²⁷ X 9.81

E = 1.02 X 10⁻⁷N/C

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The magnitude of the electric field at a distance of 1 m is 7.33 x 10^7 N/C and direction of the electric field is from the positive charge to the negative charge.

The magnitude of the electric field at a distance of 1 m from the center of the dipole is given by:

E = k(2q)/r^2

where k is the Coulomb constant (8.99 x 10^9 Nm^2/C^2), q is the charge of each charge (2nc and -2nc), and r is the distance between the charges (1.5 cm).

E = (8.99 x 10^9 Nm^2/C^2)(2 x 2nc)/(0.015 m)^2

E = 7.33 x 10^7 N/C

The direction of the electric field is from the positive charge to the negative charge.

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Sound waves between layers of mass are dampened or diminished using MLV (Mass Loaded Vinyl).

By converting sound waves into heat through the use of a viscoelastic damping compound or MLV, the waves are weakened before they reach the next layer of mass.

Sound can only be stopped by mass. A mass can be made of plywood, drywall, or concrete.

The typical model for wave damping includes a velocity dependent term.

The damping increases when you try to distort the medium more quickly. The amount of damping is significantly influenced by the fluid's viscosity, through which the sound wave is propagating.

Only the bass portion of music is audible when heard from a distance because higher frequency sound dampens in air more quickly.

The wave's amplitude decreases with increasing displacement due to the decrease in energy per unit volume. However, when the wave's energy is dispersed over a huge region, causing it to decay rapidly, a different sort of damping (decrease in energy per unit volume) can be seen.

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The force acting on a negative charge is in opposition to the direction of the electric field [tex]-2.194 \times 10^{-5}[/tex].

In order for a charge to stay stationary, a weight must be balanced by an electric force that acts in the opposite direction as the weight, with the electric force acting upward.

In a directed electric field, the electric charge particles are subject to a force that is directed in that direction. It can be caused by a charge imbalance, which is when there are more positively charged particles than negatively charged particles in a certain region.

A particle of mass 1.50 g

A downward-directed electric field of magnitude 670 n/c

qE=mg

q=mg/E

Substitute the value in above equation we get,

[tex]& =\frac{1.50 \times 10^{-3} \times 9.8}{670} \\& =-2.194 \times 10^{-5} \mathrm{C}[/tex]

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Explanation:

"Outlier" data can shift a Normal Bell Curve ____.

A. to get a large peak

B. to flatten out

C. to the left or right

D. up at both ends

Answer: Therefore, the rock that has a mass of 10 kg and a gravitational energy of 2400 J must be at a height of 24 meters.

Explanation:

How high above the ground is a 10 kg boulder that has 2400 J of gravitational potential energy?

Data:

m = 10 kg

Epg = 1200 J

h = ?

g = 10 m/s²

The formula for gravitational potential energy is:

Where

We must calculate the height, for which we clear the formula, then

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{Ep_g}{m*g} } \end{gathered}$}}[/tex]

We substitute data in the formula and solve:

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ J}{10 \ kg*10\frac{m}{s^2} } } \end{gathered}$}}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ J}{100 \ kg*\frac{m}{s^2} } } \end{gathered}$}}[/tex]

Before continuing to answer, we must work with the units of Joules, so

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ N*m}{100 \ kg*\frac{m}{s^2} } } \end{gathered}$}}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \not{kg}*\not{\frac{m}{s^2}} *m}{100 \not{kg}*\not{\frac{m}{s^2}} } } \end{gathered}$}}[/tex]

[tex]\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h=\frac{2400 \ m}{100} } \end{gathered}$}}[/tex]

[tex]\boxed{\boxed{\large\displaystyle\text{$\begin{gathered}\sf \bf{h\cong24 \ m } \end{gathered}$}}}[/tex]

Therefore, the rock that has a mass of 10 kg and a gravitational energy of 2400 J must be at a height of 24 meters.

So the force you have to apply to break the ropes and accelerate the box with a=1 m/s^2 is 2 + √3 + 1 N

To determine the force FA that must be applied to break the ropes and accelerate the box with a=1 m/s^2, you can use the equation of motion:

F = ma

where F is the net force acting on the box, m is the mass of the box, and a is the acceleration of the box.

We know that the net force acting on the box is equal to the force applied to it minus the forces of tension in the top and side ropes.

So, F = FA - T1 - T2

and the acceleration of the box is 1 m/s^2

Given that,

FA = m×a + T1 + T2

Substitute the given values for m, a, T1 and T2,

FA = 2 kg × 1 m/s² + √3 N + 1 N

FA = 2 kg × 1 m/s² + √3 N + 1 N

                      = 2 + √3 + 1 N

An object's movement or shift in position in relation to its surroundings over time is referred to as the motion. A subfield of physics that deals with the behavior of physical systems and objects is mechanics, the study of motion.

There are various kinds of motion, such as:

This is straight-line motion. The linear velocity and acceleration of an object are calculated using the distance and time it takes to travel in a particular direction.

An axis is in motion here. When describing an object's rotational motion, the terms "angular displacement," "angular velocity," and "angular acceleration" are utilized.

Rhythmic oscillation: This is a motion that happens over and over again and revolves around a central point. It's called oscillation. A pendulum that swings or a guitar string that vibrates are two examples.

Motion of a projectile: This is the movement of an object that is projected into the air, like a ball that is thrown into the air or a gunshot.

Relational movement: This is how an object moves in relation to a reference point, like how a car moves on a road in relation to the earth.

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The height of the apartment is 127.5 m.

The height of the apartment is calculated by applying the following equation.

first equation for your throw; h = ¹/₂g(t +3.4)²

second equation for your friend's throw; h = vt  +  ¹/₂gt²

h = vt  +  ¹/₂gt²

h = 66.64t  +  ¹/₂gt²

now equate the two equations;

¹/₂g(t+3.4)² = 66.64t  +  ¹/₂gt²

¹/₂(9.8)(t² + 6.8t + 11.56) = 66.64t  +  ¹/₂(9.8)t²

4.9(t² + 6.8t + 11.56) = 66.64t  +  4.9t²

4.9t² + 33.32t + 56.64 = 66.64t  +  4.9t²

33.32t = 56.64

t = 1.7 seconds

The height of the apartment is calculated as;

h = ¹/₂g(t +3.4)²

h = ¹/₂(9.8)(1.7 +3.4)²

h = 127.5 m

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It takes total time of 74 seconds for a rock dropped from a height of 1.099 m to hit the surface.

That planet's gravitational acceleration is 3.699 meters per second squared. The height from which the object was dropped takes 0.8198 seconds to reach the surface. Because the initial velocity is zero,

H = Ut + 1/2 a[tex]t^{2}[/tex] Because u = 0, this is half multiplied by 3.699 multiplied by [tex]0.8198^{2}[/tex] divided the.81988198 right divide by 2. This gives us an estimate of 1.25 meters.

When the rock is launched upwards, it begins to decelerate immediately due to the opposing force of gravity. The rock will have reached its highest point and will then fall back down when the velocity on the ascent reaches zero.

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Answer:

electromagnetic waves transfer energy from one place to another.

Explanation:

With the help of slip rings, an AC generator connects the rotating armature to its external circuit.

A slip ring is an electronic device that permits the transfer of electrical currents and energy from a still structure to a spinning one. Any electrical device that needs to rotate while sending energy or currents can employ a slip ring.

A device that generates electrical energy from mechanical energy is an AC generator. Mechanical energy is provided by steam turbines, gas turbines, and combustion engines as the AC generator's input source. Alternating electrical power in the form of current and voltage is the output.

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Radiant energy is also called responses thermal energy (b)  light energy is correct option.

Radiant energy in physics refers to the energy of electromagnetic and gravitational radiation. Radiant energy is particularly studied via radiometry. Its SI unit for energy is the joule (J). Other than radiometry, electromagnetic energy is denoted by the letters E or W. The phrase is specifically used when electromagnetic radiation is released into the environment by a source. For the human eye, this radiation might be visible or invisible.

Energy included in electromagnetic waves is known as radiant energy. These consist of microwaves, infrared, radio waves, ultraviolet light, and visible light. The random molecular movements of substances store thermal energy, often known as heat energy.

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The curve of a parabolic path best captures the motion of the piece of cargo.

The parcel moves in a parabolic path, always remaining underneath the aircraft. As the package falls, it encounters a vertical acceleration that alters its vertical velocity. The downward force of gravity on the package is what is causing this vertical acceleration.

If the package's velocity could be roughly compared to projectile motion, then there would be no horizontal acceleration (that is, if the impact of air resistance could be assumed to be insignificant). In the absence of horizontal forces, there would be a constant horizontal velocity. This explains why the package was dropped beneath the plane, as it were.

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The pebble was traveling at 13.44 m/s when it impacted the water.

The speed at which something moves in a specific direction is known as its velocity. as the speed of a car driving north on a highway or the pace at which a rocket takes off.

A cliff is a group of rocks that rises nearly vertically, or straight up and down, from the ground. Cliffs are a frequent component in landscapes. Sea cliffs are one type that can occur around the coast, high in the mountains, or as the walls of canyons and valleys.

t = Time taken = 1.37 s

u = Initial velocity

v = Final velocity

s = Displacement

a = Gravitational acceleration is 9.81 m/s2 (downward direction is taken as positive)

Equation of motion

v = u + at

v = 0 + 9.81 × 1.37

v = 0 +  13.4397

v = 13.44 m/s

When the stone impacted the water, its speed was 13.44 m/s.

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In this case, a macro lens would've been ideal. In her backyard, Sue is taking pictures of some incredibly tiny and complex succulents. She aims to record as many specifics as she can.

A lens is a transparent piece of glass that, when light rays pass through it by refraction, either concentrates or disperses them. Lenses are employed in telescopes as well as other magnifying equipment because of their enlarging capabilities.

Refraction is the process by which a lens changes the path of sun beams as the pass thru it. It follows that objects viewed through a lens appear to be either larger or less then they actually are because the rays appear to originate from a location that is closer or further distant of where they actually do.

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Assume that the downhill velocity is multiplied by 0.25 inverse seconds to get the acceleration caused by air resistance. Describe the initial value issue and its resolution.

Because air resistance slows down the motion of the falling object, it impacts acceleration during a fall to a lesser extent than gravity (g). The object's surface area and speed both influence the amount it slows down.

A initial and boundary problem (IVP) in multivariable calculus consists of a normal differential equation and an initial condition that specify exact amount of the unknown variable at a specific location in the domain. In physics or even other sciences, modeling a system typically entails resolving an initial value dilemma.

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Answer:

870 m

Explanation:

d = Vit + 1/2at²

a = ΔV/Δt = (85 m/s - 60 m/s) / (12 s) = (25 m/s) / 12 s = 2.08 m/s²

d = (60 m/s)(12 s) + 1/2 (2.08 m/s²)(12 s)² = 870 m

Answer:

The automobile traveled 870 meters during the 12 second interval.

Explanation:

We can use this kinematics equation to evaluate how far the automobile traveled.

[tex]\overline v=\frac{\Delta x}{\Delta t}[/tex]

Note

[tex]\overline v[/tex] is the average velocity

[tex]\Delta x[/tex] is the change in position (displacement)

[tex]\Delta t[/tex] is the change in time (time interval)

The formula for average velocity is

[tex]\overline v=\frac{V_f-V_o}{2}[/tex]

We are given

[tex]V_f=85\\V_o=60\\\Delta t=12[/tex]

First lets evaluate the average velocity.

[tex]\overline v=\frac{85-60}{2}[/tex]

[tex]\overline v=72.5[/tex]

Rearranging our kinematics equation to isolate [tex]\Delta x[/tex] we get

[tex]\Delta x=\overline v \Delta t[/tex]

Now lets evaluate [tex]\Delta x[/tex].

[tex]\Delta x=72.5*12\\\Delta x=870[/tex]

There are many different ways you can solve this; I could have used a different equation.

The magnitude of the force F on the 1.0 nC charge in the figure is the positive charge and force F is 8 x 10^9 N (8 Giga Newtons).

The force F on the 1.0 nC charge in the figure can be calculated using Coulomb's law, which states that the force between two point charges is proportional to the inversely proportional to the square of the distance between the charges and a product of the charges. The magnitude of the force can be calculated using the following formula:

|F| = k x |q1| x |q2| / r^2

where k is the Coulomb constant (9 x 10^9 Nm^2/C^2), q1 and q2 are the charges (in Coulombs), and r is the distance between the charges (in meters).

In this case, q1 = 1.0 nC = 1.0 x 10^-9 C and q2 = -1.0 nC = -1.0 x 10^-9 C (since the charges are opposite and the force is attractive) and r = 0.1 m.

So, the magnitude of the force F can be calculated as:

|F| = k x |q1| x |q2| / r^2 = (9 x 10^9 Nm^2/C^2) x (1.0 x 10^-9 C) x (-1.0 x 10^-9 C) / (0.1 m)^2 = 8 x 10^9 N

The magnitude of the force F is 8 x 10^9 N (8 Giga Newtons)

It's important to note that the direction of the force is from the positive charge.

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(1) The force exerted by the hammer claws on the nail is 67.54 N.

(2) The the force exerted by the surface on the point of contact with the hammer head is 124 N.

The force exerted by the hammer claws on the nail is calculated by applying the following formula.

Fy = W sinθ

where;

Fy = 124 N x  sin ( 33 )

Fy = 67.54 N

The the force exerted by the surface on the point of contact with the hammer head is calculated as follows;

Fn = W sin (90)

Fn = 124 N

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The concept of net force  is important in understanding the relationship between the force experienced by an object  and its resultant magnitude.

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The potential energy of a 3 kg ball that is on the ground is zero.

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The region with the lowest pressures and highest temperatures at which the phase of x is known is the supercritical region.

This region is between the critical temperature and pressure, and is characterized by a single phase that is neither liquid nor gas, but rather a combination of the two.

This region exhibits properties that are intermediate between those of a liquid and a gas, and so the phase of X is known here.

A fluid is referred to as "supercritical" when it is subjected to pressure and temperature above the compound's critical point. The fluid exhibits specific characteristics and behaves in a manner that is in between that of a liquid and a gas in the supercritical region.

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My average velocity should be 7.5 m/sec.

Speed = [tex]\frac{distance covered }{time taken}[/tex]

Average speed = [tex]\frac{total distance}{total time}[/tex]

my friend has covered 60 m in 10s

Speed of friend =[tex]\frac{60}{10}[/tex]

                          = 6m/s

Friend will cover final  40 m in

                           [tex]\frac{40}{6}[/tex]=6.67 s

So, I need to cover final  50 m in 6.67 s

my average speed= [tex]\frac{50}{6.67}[/tex]

                        =7.5 m/s        

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