a control chart indicates that the current process fraction nonconforming is 0.02. if 50 items are inspected each day, what is the probability of detecting a shift in the fraction nonconforming to 0.04 on the first day after the shift?

Answer: This situation involves choosing a group of 5 players out of a total of 12 players, where the order in which the players are chosen does not matter. Therefore, this is an example of a combination problem.

The number of ways to choose a group of 5 players out of 12 is given by the formula for combinations:

n C r = n! / (r! * (n-r)!)

where n is the total number of players, r is the number of players being chosen, and "!" represents the factorial operation.

In this case, we have n = 12 and r = 5, so the number of different choices of starters is:

12 C 5 = 12! / (5! * (12-5)!)

= 792

Therefore, there are 792 different choices of starters that the coach can make from the team of 12 players.

Step-by-step explanation:

Rotate triangle △C'D'E' counterclockwise by approximately -0.785 radians about the origin:

[tex]x1' = 1 \times cos(-0.785) - (-4) \times sin(-0.785) \approx 0.436[/tex]

[tex]y1' = 1 \times sin(-0.785) + (-4) \times cos(-0.785) \approx -3.678[/tex]

[tex]x2' = -7 \times cos(-0.785) - 8[/tex]

The given point [tex]s C(2, -8), D(-6, 4),[/tex] and [tex]E(0, 4)[/tex] form the triangle △CDE, and the points U(1, -4), V(-3, 2), and W(0, 2) form the triangle △UVW, with △CDE being the preimage of △UVW.

To represent the transformation algebraically, we can use a combination of translations and rotations.

Translation:

To translate a point (x, y) by a vector (h, k), we add h to the x-coordinate and k to the y-coordinate of the point.

To transform triangle △CDE to triangle △UVW, we can first translate triangle △CDE by a vector (h, k) to obtain triangle △C'D'E', where C' = C + (h, k), D' = D + (h, k), and E' = E + (h, k).

Since the coordinates of C are (2, -8) and the coordinates of U are (1, -4), we can calculate the translation vector (h, k) as follows:

[tex]h = 1 - 2 = -1[/tex]

[tex]k = -4 - (-8) = 4[/tex]

So the translation vector is [tex](-1, 4).[/tex]

Rotation:

To rotate a point (x, y) by an angle θ counterclockwise about the origin, we use the following formulas:

[tex]x' = x \times \cos(\theta) - y times \sin(\theta)[/tex]

[tex]y' = x \times \sin(\theta) + y \times \cos(\theta)[/tex]

To transform triangle △C'D'E' to triangle △UVW, we can apply a rotation of angle θ counterclockwise about the origin to triangle △C'D'E', where C' = (x1', y1'), D' = (x2', y2'), and E' = (x3', y3'). Since the coordinates of C' are (2, -8) after translation, and the coordinates of U are (1, -4), we can calculate the rotation angle θ as follows:

[tex]\theta = atan2(y1' - y2', x1' - x2') - atan2(y1 - y2, x1 - x2)= atan2((-8 + 4) - (-4), (2 + 1) - (-6 + 3)) - atan2((-8) - (-4), 2 - (-6))[/tex]

Using a calculator, we can find θ to be approximately -0.785 radians.

So, the algebraic representation of the transformation that maps triangle [tex]\triangle CDE[/tex] to triangle [tex]\triangle UVW[/tex]  is:

Translate triangle △CDE by the vector (-1, 4) to obtain triangle △C'D'E':

[tex]C' = (2, -8) + (-1, 4) = (1, -4)[/tex]

[tex]D' = (-6, 4) + (-1, 4) = (-7, 8)[/tex]

[tex]E' = (0, 4) + (-1, 4) = (-1, 8)[/tex]

Therefore, Rotate triangle △C'D'E' counterclockwise by approximately -0.785 radians about the origin:

[tex]x1' = 1 \times cos(-0.785) - (-4) \times sin(-0.785) \approx 0.436[/tex]

[tex]y1' = 1 \times sin(-0.785) + (-4) \times cos(-0.785) \approx -3.678[/tex]

[tex]x2' = -7 \times cos(-0.785) - 8[/tex]

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The function f is onto.

To determine if the function f is one-to-one, we need to check if each element in the domain maps to a unique element in the range. Looking at the function, we can see that f(a) = 1, f(b) = 2, f(c) = 3, and f(d) = 3. Since two elements in the domain (c and d) map to the same element in the range (3), the function f is not one-to-one.

To determine if the function f is onto, we need to check if every element in the range is mapped to by at least one element in the domain. Looking at the function, we can see that all four elements in the range (1, 2, 3, and 4) are mapped to by at least one element in the domain. Therefore, the function f is onto.

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The slope of the rope is 0.25 with the respective situation as the rope is attached to 6-foot high wall and the horizontal distance is 24 feet.

We need to determine the ratio of the vertical change to the horizontal change to establish the slope of the rope's line. To begin, we may use the Pythagorean theorem to calculate the length of the rope:

a² + b² = c²

where an is the height of the wall, b is the horizontal distance from the wall to the point where the rope is tied to the ground, and c is the length of the rope.

When we solve for c, we get:

c = √(6² + 24²)

c = √(36 + 576)

c = √612

c = around 24.73 feet

Consider a right triangle created by the wall, the point where the rope is fastened to the ground, and a point on the rope directly above the wall's top.

The vertical change is the wall's height, which is 6 feet.

The horizontal change is the distance of 24 feet between the place where the rope is tied to the ground and the wall.

As a result, the slope of the rope-representing line is:

vertical change / horizontal change = slope

slope = 6 / 24

slope = 0.25

As a result, the slope of the rope's line is 0.25.

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To compute the covariance matrix of the variables in the data, the "matrix-operation" which should be used is ([tex]X^{t}[/tex] × X)/n.

The "Covariance" matrix is defined as a symmetric and positive semi-definite, with the entries representing the covariance between pairs of variables in the data.

The "diagonal-entries" represent the variances of individual variables, and the off-diagonal entries represent the covariances between pairs of variables.

Step(1) : Compute the transpose of the centered data matrix X, denoted as [tex]X^{t}[/tex]. The "transpose" of a matrix is found by inter-changing its rows and columns.

Step(2) : Compute the "dot-product" of [tex]X^{t}[/tex] with itself, denoted as [tex]X^{t}[/tex] × X.

The dot product of two matrices is computed by multiplying corresponding entries of the matrices and summing them up.

Step(3) : Divide the result obtained in step(2) by the number of samples in the data, denoted as "n", to get the covariance matrix.

This step scales the sum of the products by 1/n, which is equivalent to taking the average.

So, the covariance matrix "C" of variables in "centered-data" matrix X can be expressed as: C = ([tex]X^{t}[/tex] × X)/n.

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The given question is incomplete, the complete question is

Let X be a matrix of centered data with a column for each field in the data and a row for each sample. Then, not including a scalar multiple, how can we use matrix operations to compute the covariance matrix of the variables in the data?

The side length x of the triangle to the nearest tenth is 170.3

The figures in the image are right-triangle.

From the diagram:

Angle θ = 20°

Opposite to angle θ = 62

Adjacent to angle θ = x

To find the value of x, we use the trigonometric ratio.

Note that: tangent = opposite / adjacent

Plug in the values

tan( 20 ) = 62 / x

Solve for x

x = 62 / tan( 20 )

x = 170.3

Therefore, the measure of side length labelled x is 170.3 units.

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(a) The correct trigonometric ratio to use is the tangent ratio (tan).

(b) The trigonometric equation is tan(17°) = Opposite/Adjacent.

(c) tan(17°) = Opposite/Adjacent

tan(17°) = 150/Adjacent

Adjacent = 150/tan(17°)

Adjacent = 150/0.3045

The measure of the unknown side from the given triangle is 14.48.

The given triangle is a right triangle with the following sides;

Hypotenuse = 15

Adjacent = x

Acute angle = 52 degrees

We are to determine the measure of the unknown side using trigonometry identity

Cos 15 = Adjacent/Hypotenuse

Cos 15 = x/15

x = 15cos15

x = 15(0.9659)

x = 14.48

Hence the measure of the unknown side is 14.48

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Answer:

---------------------------

Use the identity for the square of a sum:

Comparing with the given we see that:

Then find b:

To complete the square we need to add b² = (-3)² = 9 to both sides:

Answer:

[tex]\large\boxed{\tt x \approx 95.6}[/tex]

Step-by-step explanation:

[tex]\textsf{We are asked to solve for x by using \underline{Trigonometric Identities}.}[/tex]

[tex]\large\underline{\textsf{What are Trigonometric Identities?}}[/tex]

[tex]\boxed{\begin{minipage}{20 em} \\ \underline{\textsf{\large Trigonometric Identities;}} \\ \\ \textsf{Trigonometric Identities are trigonometric ratios determined with what's given in order to find a missing value. For a Right Triangle, the Trigonometric Identities are Sine, Cosine, and Tangent. These are used to find missing sides.} \\ \\ \tt Sine = \tt $ \tt \frac{Opposite}{Hypotenuse} \\ \\ Cosine = \frac{Adjacent}{Hypotenuse} \\ \\ Tangent = \frac{Opposite}{Adjacent} \end{minipage}}[/tex]

[tex]\textsf{We should determine whether Sine, Cosine, or Tangent will actually help us}[/tex]

[tex]\textsf{determine x. We are given a Right Triangle that has 1 15}^{\circ} \ \textsf{angle, and a side with}[/tex]

[tex]\textsf{a length of 99. Because this side is opposite of the right angle, this side is called}[/tex]

[tex]\textsf{the \underline{Hypotenuse}.}[/tex]

[tex]\textsf{The side labeled x is \underline{Adjacent}, which means that it's touching the given angle.}[/tex]

[tex]\textsf{Using what was given to us, we should use Cosine since we are asked for the}[/tex]

[tex]\textsf{Adjacent Angle when given the Hypotenuse.}[/tex]

[tex]\large\underline{\textsf{Solving;}}[/tex]

[tex]\textsf{Remember that;}[/tex]

[tex]\tt \cos(15^{\circ}) =\frac{Adjacent}{Hypotenuse}[/tex]

[tex]\textsf{We're given;}[/tex]

[tex]\tt \cos(15^{\circ}) =\frac{x}{99}[/tex]

[tex]\textsf{To find the value of x, we first should remove the fraction using cancellation.}[/tex]

[tex]\textsf{We are able to use the \underline{Multiplication Property of Equality} to prove that the}[/tex]

[tex]\textsf{equation remains equal.}[/tex]

[tex]\underline{\textsf{Multiply both expressions by 99;}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) =\not{99} \frac{x}{\not{99}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) =x[/tex]

[tex]\underline{\textsf{Evaluate;}}[/tex]

[tex]\tt 99 \cos(15^{\circ}) \approx \boxed{\tt 95.6}[/tex]

[tex]\large\boxed{\tt x \approx 95.6}[/tex]

In the given triangle the 3 trigonometric ratios are:

(A) Sinθ = 3/5, (B) Cosθ = 4/5, and (Tanθ = 3/4)

The trigonometric functions in mathematics are real functions that connect the right-angled triangle's angle to the ratios of its two side lengths.

They are extensively employed in all fields of geometry-related study, including geodesy, solid mechanics, celestial mechanics, and many others.

In general, arcsine, arccosine, tangent, cotangent, secant, and cosecant functions are used to express the inverses of sine, cosine, tangent, cotangent, secant, and cosecant functions.

So, according to t the given triangle, the 3 trigonometric ratios would be:

Sinθ = B/H

Sinθ = 27/45

Sinθ = 3/5

Cosθ = P/H

Cosθ = 36/45

Cosθ = 4/5

Tanθ = B/P

Tanθ = 27/36

Tanθ = 3/4

Therefore, in the given triangle the 3 trigonometric ratios are:

(A) Sinθ = 3/5, (B) Cosθ = 4/5, and (Tanθ = 3/4)

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In the 8 Axioms, 4 and 6 axioms fails to holds and S is not a vector space. Rest of the axioms try to hold the vector space.

To demonstrate that S is not a vector space, we must demonstrate that at least one of the eight vector space axioms fails to hold. Let us examine each axiom in turn:

Therefore, axioms 4 and 6 fail to hold, and S is not a vector space.

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The correct question:

Let S be the set of all ordered pairs of real numbers. Define scalar multiplication and addition on S by α(x₁, x₂) = (αx₁, αx₂); (x₁, x₂) ⊕ (y₁, y₂) = (x₁ + y₁, 0). We use the symbol ⊕ to denote the addition operation for this system in order to avoid confusion with the usual addition x + y of row vectors. Show that S, together with the ordinary scalar multiplication and the addition operation ⊕, is not a vector space. Which of the eight axioms fail to hold?

By performing these statistical computations, you can analyze and interpret the central tendency of your dataset, which helps in understanding the overall pattern and distribution of the data.

It looks like you're seeking information on further statistical computation related to mean, mode, and median.

To calculate the mean, mode, and median of a dataset, follow these steps:

1. Mean: The mean is the average of all data points in a dataset.
  - Step 1: Add up all the data points.
  - Step 2: Divide the sum by the total number of data points.

2. Mode: The mode is the data point that occurs most frequently in a dataset.
  - Step 1: Count the frequency of each data point.
  - Step 2: Identify the data point(s) with the highest frequency.

3. Median: The median is the middle value in a dataset when the data points are arranged in ascending order.
  - Step 1: Arrange the data points in ascending order.
  - Step 2: If there is an odd number of data points, the median is the middle value. If there is an even number of data points, the median is the average of the two middle values.

By performing these statistical computations, you can analyze and interpret the central tendency of your dataset, which helps in understanding the overall pattern and distribution of the data.

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a. The most typical case is desired: Mode. The mode is a useful measure of central tendency when the most typical or common value is of relevance since it denotes the value or category that occurs most frequently in a data collection.

b. The distribution is open-ended: Median. The median is the middle value in a data set when arranged in ascending or descending order. It is a suitable measure of central tendency when the distribution is open-ended or skewed, as it is less affected by extreme values compared to the mean.

c. The data collection has an extreme value: the median. The median is less sensitive to extreme values compared to the mean, making it a better measure of central tendency in data sets with extreme values or outliers.

d. The data are categorical: Mode. The mode is appropriate for categorical data, as it represents the most frequently occurring category or value in the data set.

e. Further statistical computations will be needed: This statement does not indicate a specific measure of central tendency. Further statistical computations may be needed to determine the appropriate measure of central tendency depending on the characteristics of the data and the specific objectives of the analysis.

f. The numbers should be split into two roughly equal groups, one of which should contain the higher values and the other should contain the smaller values: Median.  The median is the value that separates a data set into two equal halves, making it suitable for dividing data into two approximately equal groups based on their values.

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COMPLETE QUESTION-

For these situations, state which measure of central tendency - mean, median, or mode-should be used.

a. The most typical case is desired.

b. The distribution is open-ended.

c. There is an extreme value in the data set.

d. The data are categorical.

e. Further statistical computations will be needed.

f. The values are to be divided into two approximately equal groups, one group containing the larger values and one containing the smaller values.

Both Andre and Elena are correct, but they have used different properties of exponents to simplify the expression.

Andre used the property that when multiplying powers with the same base, the exponents can be added. So, he added the exponents of 10^2, which is 2, to get 2+2+2 = 6. Therefore, his answer of 10^6 is correct.

Elena used the property that when a power is raised to another power, we can multiply the exponents. So, she rewrote 10^2 • 10^2 • 10^2 as (10^2)^3, and then multiplied the exponents of 10^2, which is 2, by 3 to get 2*3 = 6. Therefore, her answer of 10^5 is also correct.

Both methods are valid and result in the same answer, so it's a matter of personal preference which method to use.

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The linear function rule for an input of x + 1 is given as follows:

f(x + 1) = 2x + 5.

The slope-intercept representation of a linear function is given by the equation presented as follows:

y = mx + b

The coefficients of the function and their meaning are described as follows:

For this problem, the slope and the intercept of the function are given as follows:

Hence the function rule is:

y = 2x + 3.

The numeric value at x = x + 1 is given as follows:

f(x + 1) = 2(x + 1) + 3

f(x + 1) = 2x + 2 + 3

f(x + 1) = 2x + 5.

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The total number of holes Craigs need to have a score of 3 today is equal to 37.

On every every frisbee golf hole having a score 3 = one bonus.

Total scored while playing last week = 3 on 5 holes

Total extra bonus scored by Craig = 5

Getting extra bonus on total = 42 from score of 3

let us consider Craigs need 'x' holes on a score of 3 today

Required equation is,

x + 5 = 42

Subtract 5 from both the side of the equation we get,

⇒ x = 42 - 5

⇒ x = 37 holes

Therefore, Craigs need to have 37 holes to score a 3 today.

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The radius of the circle with the given chord length is: radius = 7.25

The Radius of a Circle based on the Chord and Arc Height helps us to computes the radius based on the chord length (L) and height (h).

The formula for the radius of a circle based on the length of a chord and the height is:

r = (L²/8h) + (h/2)

where:

r is the radius of a circle

L is the length of the chord.  This is the straight line length connecting any two points on a circle.

h is the height above the chord.  This is the greatest distance from a point on the circle and the chord line.

We are given:

L = 5 + 5 = 10

h = 2

Thus:

r = (10²/8(2)) + (2/2)

r = 6.25 + 1

r = 7.25

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This is a contradiction, which means that there is no solution for the given equation. Therefore, the correct answer is option C, "No solution".

There is only one solution for the given equation.

5 - 3x = 4 + x + 2 - 4x

Simplifying the equation, we get:

5 - 3x = 6 - 3x

Subtracting 6 from both sides, we get:

-1 - 3x = -3x

Adding 3x to both sides, we get:

-1 = 0

A linear equation is an equation that can be written in the form y = mx + b, where y and x are variables, m is the slope, and b is the y-intercept. It represents a straight line on a graph. Linear equations can be used to model a variety of real-world situations, such as the relationship between temperature and time, or the cost of producing a certain quantity of goods.

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We can see that both sides are equal, which means that the equation has infinitely many solutions.

Therefore, the answer is: D. Infinitely many solutions is correct.

To solve for the number of solutions of 5 - 3x = 4 + x + 2 -4x,

we first simplify the equation by combining like terms:

Combine like terms on both sides of the equation:

5 - 3x = 6 - 3x

Compare the coefficients of the x terms:

-3x = -3x

Since both sides of the equation have the same coefficients for the x terms, there are infinitely many solutions.

Therefore, the answer is: D. Infinitely many solutions is correct.

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Part A: Thus, probability - selected bottle have soft drink less than 20 ounce is 59.48%.

Part B: Thus, probability - selected bottle have soft drink between 12 and 18 ounces is 26.51%.

We shall compute the necessary probabilities in this situation using the characteristics of the normal distribution. A symmetric distribution is the normal distribution. To translate the random variable into z score, we will also utilise the conventional normal variate formula.

Given that-

Part A:  probability - selected bottle have soft drink less than 20 ounce.

P(x < 20 ) = z (x - μ/  σ)

               = z (20 - 15 / 2)

               = z ( 5/ 2)

P(x < 20 ) = z (2.5)  (using  z score table online.

P(x < 20 ) = 0.5948

Thus, probability - selected bottle have soft drink less than 20 ounce is 59.48%.

Part B:  probability - selected bottle have soft drink between 12 and 18 ounces:

P(12 < x < 18 ) = z (x - μ/  σ < x < x - μ/  σ)

               = z (12 - 15 / 2 <  x < 18 - 15 / 2)

               = z ( -3/2 < x < 3/2)

P(12 < x < 18 ) = z (-1.5 < x < 1.5)  (using  z score table online.)

P(12 < x < 18 ) =  0.9332 - 0.6681

P(12 < x < 18 ) = 0.2651

Thus, probability - selected bottle have soft drink between 12 and 18 ounces is 26.51%.

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Slot machines are a real-world example of a variable ratio schedule.

A variable-ratio schedule in operant conditioning is a partial reinforcement schedule where a response is reinforced after an arbitrary number of responses. 1 A consistent, high rate of response is produced by this schedule. A reward based on a variable-ratio schedule is one that can be found in gambling and lottery games.

The individual will continue to engage in the target behavior in variable ratio schedules because he is unsure of how many responses he must give before receiving reinforcement. This leads to highly stable rates and increases the behavior's resistance to extinction.

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The number of terms in the expansion of the expression[tex][(3x^2y)^2(3x-2y)^2]^3[/tex] after it is simplified to lowest terms is the product of the number of terms in the base and the number of terms in the exponent,

which is:

[tex]1 \times 7 = \boxed{7}[/tex]

The expression [tex][(3x^2y)^2(3x-2y)^2]^3[/tex]by using the laws of exponents and expanding the products of powers.

First, we can simplify the term inside the square brackets:

[tex](3x^2y)^2(3x-2y)^2 = 9x^4y^2 (3x-2y)^2[/tex]

Expanding the square of [tex](3x-2y)^2[/tex] gives:

[tex](3x-2y)^2 = (3x)^2 - 2(3x)(2y) + (2y)^2 = 9x^2 - 12xy + 4y^2[/tex]

Substituting this back into the expression gives:

[tex]$[(3x^2y)^2(3x-2y)^2]^3 = (9x^4y^2)(9x^2 - 12xy + 4y^2)^2]^3[/tex]

Expanding the cube of the expression gives:

[tex]$[(9x^4y^2)(9x^2 - 12xy + 4y^2)^2]^3 = (9x^4y^2)^3(9x^2 - 12xy + 4y^2)^6$[/tex]

The expression has only one term, which is the product of two terms raised to a power.

To determine the number of terms in the expansion, we need to expand the binomial. [tex](9x^2 - 12xy + 4y^2)^6[/tex]

Using the binomial theorem,

The expansion will have 7 terms, since the exponents on [tex]9x^2, -12xy, and 4y^2[/tex]will range from 6 to 0, and the sum of the exponents will always be 6.

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An arrangement that satisfies the conditions of the puzzle is given below:

 4  9  2

 3  5  7

 8  1  6

Here is one possible arrangement of the digits 1, 2, 3, 4, and 5 in the square, with each row, column, and diagonal summing up to 15:

   4  9  2

   3  5  7

   8  1  6

We can check that this arrangement works:

Rows: 4+9+2=15, 3+5+7=15, 8+1+6=15

Columns: 4+3+8=15, 9+5+1=15, 2+7+6=15

Diagonals: 4+5+6=15, 2+5+8=15

Therefore, this arrangement satisfies the conditions of the b.

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The company should charge the person $240.

The expected value of a discrete distribution is calculated as the sum of each outcome multiplied by it's respective probability.

For a 40 year old person, the distribution of the company earnings are given as follows:

For an expected value of 70, the value of x is obtained as follows:

-200000(0.00085) + 0.99915x = 70

x = (70 + 200000(0.00085))/0.99915

x = $240.

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If the area of a kite is 35cm square, the area of the new kite with all diagonals multiplied by 2 is 70 cm².

If we multiply all the diagonals of a kite by 2, then the area of the new kite will be 4 times the area of the original kite.

The area of a kite is given by the formula:

Area = (diagonal 1 x diagonal 2)/2

Let the diagonals of the original kite be d1 and d2. Then, the area of the original kite can be expressed as:

Area = (d1 x d2)/2 = 35 cm²

If we multiply all the diagonals of the original kite by 2, then the new diagonals will be 2d1 and 2d2. The area of the new kite can be expressed as:

New area = (2d1 x 2d2)/2 = 2d1d2

Substituting the value of d1d2 from the original equation, we get:

New area = 2d1d2 = 2 x (d1 x d2) = 2 x Area = 2 x 35 cm² = 70 cm²

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The length of the segment [tex]\overline{ST}[/tex], obtained using Thales Theorem is 18 2/3

Thales Theorem, also known as the triangle proportionality theorem states that if a segment is drawn such that it is parallel to a side of a triangle, and it also intersects the other two sides of the triangle at distinct points, than the other two sides are divided by the segment in the same ratio

Thales Theorem, also known as the triangle proportionality theorem indicates;

12/14 = 16/[tex]\overline{ST}[/tex]

Therefore;

[tex]\overline{ST}[/tex]/16 = 14/12

[tex]\overline{ST}[/tex] = 16 × 14/12 = 56/3 = 18 2/3

Segment [tex]\overline{ST}[/tex] is 18 2/3 units long

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Answer:

No, they are not equivalent expressions.

Step-by-step explanation:

2(x + 6) + x = 2x + 12 + x = 3x + 12.

3x + 6 = 3x + 6.

The two expressions are not equal because they have different coefficients of x and different constant terms.

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There are 4,320 ways to select six of the letters of the word algorithm and write them in a row if the first letter must be "a".

There are 7 letters in the word "algorithm", and we need to select 6 of them and arrange them in a row such that the first letter is "a". We can first choose the remaining 5 letters from the remaining 6 letters (excluding "a") in 6 choose 5 ways

⁶C₅ = 6!/5! = 6

Once we have chosen the 5 letters, we can arrange the 6 selected letters (including "a") in a row in 6! ways. Therefore, the total number of ways to select 6 letters and arrange them in a row with the first letter being "a" is

⁶C₅ × 6! = 6 × 720 = 4,320

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The cost of 1 kg onion and cost of 3 kg sugar​ is Rs238

Let x be the cost of 1 kg onion in Rs, and let y be the cost of 1 kg sugar in Rs.

Then we have:

5x + 7y = 810 (since the total cost of 5 kg onion and 7 kg sugar is Rs 810)

2y = x (since the price of 1 kg onion is equal to 2 kg sugar)

So, we have

10y + 7y = 810

This guives

17y = 810

Divide

y = 47.6

For x, we have

x = 47.6 * 2

x = 95.2

To find the cost of 3 kg sugar, we can simply multiply the cost of 1 kg sugar by 3:

3(47.6) + 95.2 = 238

Therefore, the cost is Rs 238.

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The value of the angle x of the given pentagon is: x = 36°

The formula to find the interior angle of a regular polygon is:

θ = 180(n - 2)/n

where n is number of sides of polygon

In this case we have a pentagon which has 5 sides. Thus:

θ = 180(5 - 2)/5

θ = 540/5

θ = 108°

Now, the sides of the pentagon are equal and as such the triangle formed ΔBDC is an Isosceles triangle where:

∠BDC = ∠DBC

Thus:

x = (180 - 108)/2

x = 72/2

x = 36°

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