A crowbar of 200 cm long is pivoted about to its other end to displace a load of 600 N. 0.5 m Calculate MA, VR and efficiency of the crowbar.

Answers

Answer 1

The mechanical advantage of the crow bar is 3 while the velocity ratio is 4. The efficiency of the machine is 75%.

What is the efficiency of the crow bar?

We know that a machine is any device that can be used to make work a lot much easier. Thus, the machine is the object that could make less effort to be applied in making a greater work to be done as we can see in this case we have here.

From the question, the pieces of information that we can get are;

Distance moved by Effort = 200 cm

Distance moved by load = 0.5 m or 50 cm

Velocity ratio = Distance moved by Effort/Distance moved by load

= 200 cm /50 cm

= 4

Mechanical advantage is found to be; Load/Effort

= 600 N/200 N

= 3

Efficiency = Mechanical advantage/ Velocity ratio * 100/1

= 6/4 * 100/1

=3/4 * 100/1

= 75%

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Related Questions

The diagram shows object N placed one on top of object M. M has a mass of 4 kg and N has a mass of 2 kg. Assume that all the contact surfaces are frictionless, what is the acceleration of N when M is
pulled by a force of 20 N?
A. 0 m/s²
B. 4 m/s²
C. 3.3 m/s²
D. 10 m/s²

Answers

If N placed one of these on top of item M, the acceleration when M is dragged by a force od 20 N is 10 m/s. N weighs 2 kg, but M is 4 kg in weight.

The correct answer is D

What happens during acceleration?

Acceleration is the rate at which the direction and speed of a moving object change over time. Anything is said to be accelerated when it goes straighter and faster or slower. Therefore, even though the speed is constant, travel on a circle increases due to the constant change in direction.

Is a gradual incline good?

Slow acceleration can be dangerous as well as unpleasant, especially when entering a busy state road when you must accelerate rapidly to avoid being rear-ended. When you are moving slowly up a slope while driving, acceleration can sometimes be a hassle.

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You hold a 0.125 kg glider A and a 0.500 kg glider B at rest on an air track with a compressed spring of negligible mass between them. When you release the gliders, the spring pushes them apart so that they move in opposite directions. When glider A has moved 0.960 m to the left from its starting position, how far to the right from its starting position has glider B moved?

Answers

Correct Answer:

Answer:
Magnitude |VB| = 0.32 m/s
and
Direction is to the left.

Explanation:
given data
glider A mass = 0.125 kg
glider B mass = 0.500 kg
glider A move = 0.960 m to the left
solution
we use here Conservation of momentum that is
M1 × U1 + M2 × U2 =M1 × V1 + M2 × V2 ........................1
put here value and we get
0.125 × 0 + 0.500 × 0 = 0.125 × 0.960 + 0.375 × VB
VB = −0.32 m/s
Magnitude |VB| = 0.32 m/s
and
Direction is to the left.

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A moving object is moving with a speed of 20m/s on the line y=√3x +1. How many meters does it move in the x direction in 3 seconds?
how can i solve it?​

Answers

2077 m distance  it move in the x direction in 3 seconds

speed=distance/time

distance=speed × time

distance= 20×3

√3x +1=60

x=119

put x's value in equation

distance= 2077 m

Distance, which is independent of direction, is the length between two points or things. Distance solely considers the overall magnitude and disregards the start and finish places because it is a scalar attribute. Distance can only have a positive or zero value because it is a scalar attribute; it cannot be negative.

The meter (m) is the most widely used unit of measurement for distance, however kilometers (km) can also be used to describe longer distances and centimeters (cm) or millimeters can be used to express shorter distances (mm). The distance traveled is frequently represented by the letter D when computing distance.

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You do 13 J of work as you lift a 35-N pail of water. Through what height did you lift the pail?​

Answers

Height to which the lift of the pail is taken is 0.37m.

Height is the vertical distance of an object from the surface of the Earth.

Work done = 13 J

Weight of the pail of the water = 35-N

Gravity is defined as the force that attracts a body to the Earth or any other physical body that has mass.

The acceleration due to gravity is denoted by 'g' which has the value of 9.81 [tex]m/s^{2}[/tex].Work done by gravity = mgh

W = mgh

mg = 13 J

W = 35 N

h = [tex]\frac{W}{mg}[/tex]

h = [tex]\frac{13}{35}[/tex]

h = 0.37 m

The height to which the lift of pail will be raised will be 0.37m.

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The mass of a planet is 10¹⁸ kg and its radius is 10³ m. Calculate the acceleration due to gravity on its surface. Use the known value of G. [6.673×10^-11 N m² kg^-2]​

Answers

[tex]g = \frac{GM}{r {}^{2} } \\ g = \frac{6.673 \times 10 {}^{ - 11} \times 10 {}^{18} }{(10 {}^{3}) {}^{2} } \\ g = \frac{6.673 \times 10 {}^{7} }{10 {}^{6} } \\ g = 6.673 \times 10 \\ g = 66.73 \: m.s {}^{ - 2} [/tex]

During a thunderstorm, why do you see the lightning before you hear the thunder?

Answers

Answer:

light travel faster than sound

Explanation:

because light, travels at about 300,000,000 meters per second, travels much faster than sound, which travels at 340 meters per second

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