Answer:
.0707 m / min
Explanation:
The computation is shown below:
= Flow of the volume ÷ crossectional area
A = π × r^2
= 9 π
= 28.27 m^2
so, the fast of the height of the water rise is
=(2 m^3 / min) ÷ 28.27 m^2
= .0707 m / min
I need help with 5 please and thank you
Answer: A
Explanation:
High-velocity charged particles can damage biological cells and are a component of radiation exposure in a variety of locations ranging from research facilities to natural background. Describe how you could use a magnetic field to shield yourself.
Answer:
The human body can be a source of magnetic fields. Charged particles when moving through a magnetic field experiences a force. This magnetic force on a moving charge is at right angles to the velocity which makes it possible to use the knowledge of the magnetic field on charged particles to shield yourself from radiation exposure by staying at a right angle to the velocity of the field since magnetic fields tend to shield moving charged particles that is at a right angle to the field. Though the charged particle’s kinetic energy and speed will remain constant.
Explanation:
A magnetic field is a vector field that is generated whenever an electrical charge is moving,
What is Gravity?
PLEASE ANSWER
Answer:
Gravity is the force by which a planet or other body draws objects toward its center. The force of gravity keeps all of the planets in orbit around the sun.
Please mark as brainliest
Have a great day, be safe and healthy
Thank u
XD
Answer:
GRAVITY:
In physics, gravity is the force that attracts a body towards the centre of the earth, or towards any other physical body having mass.
I need help with science:
Question 1: Chlorophyll makes some plants look yellow.
True
False
_________________________
Question 2:
Protozoa are a type of unicellular organisms.
True
False
__________________________________
Question 3:
Nerve cells carry oxygen to the body.
True
False
______________________________________
Question 4:
The__ is the basic unit of all living things.
Options:
nucleus
cell
___________________________
if you answer these all right:
( if u want brainlist's answer this question then ask another random question on your page so u can give me brainlist back, also i need to people to answer so i can chose one of you guys to give the brainlist's to, deal or no?)
no links and ill give good points so u better not steal them or ill report...
g A 4 lb weight stretches a spring 2 ft in equilibrium. It is attached to a damping mechanism with constant c. (a) Find the value of c for which the motion is critically damped. (b) If the motion is critically damped, find the displacement y(t) when the spring is initially displaced 6 inches above equilibrium and given a downward velocity of 3 ft/sec.
Solution :
Given :
Weight = 4 lb
Stretched of a spring in equilibrium,Δ = 2 ft
a). We know that
F = kΔ
4 = k x 2
k = 2 lb/ft
∴ Stiffness of the spring is, k = 2 lb/ft
Motion is critically damped.
[tex]$\epsilon = 1$[/tex]
[tex]$\epsilon=\frac{C}{C_c} = 1$[/tex]
[tex]$C=C_c[/tex]
[tex]$C=C_c=\sqrt{4k_m}[/tex]
[tex]$C=\sqrt{4 \times 2 \times \left(\frac{4}{32.174}\right)}[/tex]
C = 0.99729 lb.s/ft.
b). Displacement
[tex]$y(t)=y_0 \sin (\omega t)$[/tex]
[tex]$\dot{y}(t)= y_0 \omega \cos (\omega t)$[/tex]
[tex]$[\dot{y}(t)]_{mon}= y_0 \omega $[/tex]
Initial displacement = 6 inches
[tex]$y_0 = 0.5 \ ft , \ \ \ \dot y (t) = 3 \ ft/sec$[/tex]
[tex]$\Rightarrow 3=0.5 \times \omega$[/tex]
[tex]$\Rightarrow \omega = 6$[/tex]
Therefore, displacement :
[tex]$y(t)=y_0 \sin (\omega t)$[/tex]
[tex]$y(t)=0.5 \sin (6 t)$[/tex]
A baseball is thrown a distance of 20 m what is its speed if it takes 0.5 seconds to cover the distance
Answer:
40m/s
Explanation:
A resistor, an ideal capacitor, and an ideal inductor are connected in parallel to a source of an alternating voltage of 160 V at a frequency of 250 Hz. A current of 2 A flows through the resistor and a current of 0.8 A flows through the inductor. The total current through the circuit is 2.5 A. Assess the resistance of the resistor, the capacity of the ideal capacitor, and the inductance of the ideal inductor (presume that IC > IL).
Answer:
R = 46,25 (Ω)
L = 0,07363 (H)
C = 2,7 *10⁻⁶ (F)
Explanation:
Statement problem does not specify if 160 (V) is peak voltage or RMS value. If 160 (V) is the peak value then for a sinusoidal wave, RMS value is V(rms) = 160 /√3
V(rms) = 92,49 (V)
In each branch: we have
V = I*Z V = voltage through the impedance in (V) , I current in (A)
and Z impedance in Ω
Resistor case Z = R then V = 92,49 = 2 * R
R = 92,49/2 R = 46,25 (Ω)
Inductor case |Z| = wL Then Z = 2*π*f*L V = 0,8 * |wl|
Inductor L in (H) |wL| * 0,8 = 92,49 |wL| = 92,5/0,8 w = 2*π*f 2*3,14*250= 1570
1570*L = 92,49/0,8
L = 0,07363 (H)
In the case of the capacitor
|Z| = 1/wc = 1/1570*c
The current is 2 + 0,8 = 2,8 2,8 - 2,5 = 0,3 (A)
Again V = I*Z 92,49 = 0,3 /1570*C
C = 0,3 / 1570*92,49
C = 2,7 *10⁻⁶ (F)
a girl runs and cover a distance of 200m in 20 secends.The speed of the girl is ................ m/s.
Speed = distance/time
Speed = (200m)/(20s)
Speed = 10 m/s
All of the following are true statements regarding line-voltage thermostats and control wiring except a. An electrician's license is often required to run line-voltage control wiring. b. Line-voltage thermostats must be matched to the voltage and current of the circuit. c. Line-voltage thermostats and controls are not as sensitive as low-voltage thermostats. d. Line-voltage thermostats and controls respond faster than low-voltage thermostats.
Answer:
c. Line - voltage thermostats and controls are not as sensitive as low - voltage thermostats.
Explanation:
Line voltage thermostat is a regulator which senses the temperature and maintains it to keep the desired level of the voltage. The license in required for the electricians to work on the voltage control wirings. There is technical aspects which an electrician must understand before working on the circuits and voltage lines.
A 34kg crate resting on a horizontal surface is pushed as shown. If the coefficient of static friction s between the surfaces is 0.25, what is the minimum force (Fs) required to start the motion?
1
a.
1332.80N
b.
83.30N
c.
8.50N
d.
136.00N
Heeelppp plzz
Answer:
D (not so sure, look in the explanation and judge yourself)
Explanation:
Assume that the acceleration due to gravity is 9.81 m/s^2 downwards
Minimum force required = 0.25 x 34 x 9.81
= 83.385 N
So technically the force need to be greater than 83.385 so the answer should be d, not really sure if it should be b though really depends on the acceleration due to gravity.
Two bicycle tires are set rolling with the same initial speed of 4.0 m/s along a long, straight road, and the distance each travels before its speed is reduced by half is measured. One tire is inflated to a pressure of 40 psi and goes a distance of 18.2 m; the other is at 105 psi and goes a distance of 92.6 m. Assume that the net horizontal force is due to rolling friction only and take the free-fall acceleration to be g = 9.80 m/s2. What is the coefficient of rolling friction μr for the tire under low pressure?
Answer:
The coefficient of rolling friction will be "0.011".
Explanation:
The given values are:
Initial speed,
[tex]v_i = 4.0 \ m/s[/tex]
then,
[tex]v_f=\frac{4.0}{2}[/tex]
[tex]=2.0 \ m/s[/tex]
Distance,
s = 18.2 m
The acceleration of a bicycle will be:
⇒ [tex]a=\frac{v_f^2-v_i^2}{2s}[/tex]
On substituting the given values, we get
⇒ [tex]=\frac{(2.0)^2-(4.0)^2}{2\times 18.2}[/tex]
⇒ [tex]=\frac{4-8}{37}[/tex]
⇒ [tex]=\frac{-4}{37}[/tex]
⇒ [tex]=0.108 \ m/s^2[/tex]
As we know,
⇒ [tex]f=ma[/tex]
and,
⇒ [tex]\mu_rmg=ma[/tex]
⇒ [tex]\mu_r=\frac{a}{g}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{0.108}{9.8}[/tex]
⇒ [tex]=0.011[/tex]
A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower
Complete question:
A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.
Calculate the gravitational potential energy of the pomegranate and melon.
Answer:
The gravitational potential energy of pomegranate is 282.24 J
The gravitational potential energy of melon is 250.88 J
Explanation:
Given;
mass of the pomegranate, m₁ = 0.3 kg
height of the pomegranate, h₁ = 96 m
mass of the melon, m₂ = 0.8 kg
height of the melon, h₂ = 32 m
The gravitational potential energy of pomegranate is calculated as;
P.E₁ = m₁gh₁
P.E₁ = 0.3 x 9.8 x 96
P.E₁ = 282.24 J
The gravitational potential energy of melon is calculated as;
P.E₂ = m₂gh₂
P.E₂ = 0.8 x 9.8 x 32
P.E₂ = 250.88 J
the one that answered this is correct so give him credit not me
Answer:
Complete question:
A person holds a 0.300 kg pomegranate at the top of a tower that is 96m high. Another person holds a 0.800 kg melon next to an open window 32m up the tower.
Calculate the gravitational potential energy of the pomegranate and melon.
The gravitational potential energy of pomegranate is 282.24 J
The gravitational potential energy of melon is 250.88 J
Given;
mass of the pomegranate, m₁ = 0.3 kg
height of the pomegranate, h₁ = 96 m
mass of the melon, m₂ = 0.8 kg
height of the melon, h₂ = 32 m
The gravitational potential energy of pomegranate is calculated as;
P.E₁ = m₁gh₁
P.E₁ = 0.3 x 9.8 x 96
P.E₁ = 282.24 J
The gravitational potential energy of melon is calculated as;
P.E₂ = m₂gh₂
P.E₂ = 0.8 x 9.8 x 32
P.E₂ = 250.88 J
the one that answered this is correct so give him credit not me
A police officer uses a radar gun that emits electromagnetic waves with a frequency of 10.525 GHz (1.0525 1010 Hz). Assume the police officer is at rest, and is aiming the radar gun at vehicles traveling either directly toward, or directly away from, the radar gun. Assume the speed limit is 110 km/h, as it is on many Canadian highways. The police officer observes reflected waves that have a frequency of 2460 Hz below the frequency of the emitted waves.
Required:
a. At what speed is the car moving?
b. Choose the two correct statements about this situation.
1. The car is moving toward the police officer.
2. The car is moving away from the police officer.
3. The police officer should not cite the driver for speeding.
4. The police officer should cite the driver for speeding.
Answer:
Explanation:
For Doppler effect in radar the formula is as follows
Δf = f₀ x 2v /c
Δf is change in frequency in reflected wave , f₀ is original frequency , v is velocity of source and c is velocity of right .
Δf = 2460 Hz , f₀ = 1.0525 x 10¹⁰ Hz , v = ? c is velocity of light .
2460 = 1.0525 x 10¹⁰ x 2 v / 3 x 10⁸
2460 = 105.25 x 2 v / 3
v = 2460 x 3 / (105.25 x 2 )
v = 35 .06 m /s .
(b)
Since the observed frequency is less , the source is moving away from the observer .
option (2) is correct .
The collision of objects which generates thermal energy is called _______________________________
A
Conduction
B
Force
C
Power
D
Newton
Answer:
a. Conduction
Explanation:
What instrument makes the slowest vibration? A drum? A whistle? A flute? Or a harmonica?
Answer:
A harmonica.
Explanation:
The structure of a harmonica is built in such a way that when the air is blown by the player in it, the air moves within the rectangular structure and making sound vibrations. Sound is heard when an object vibrates. The movement of this vibration creates sound waves, and these waves enter our ears in the form of music.
Therefore, the instrument that will make the slowest vibration among the given instrument will be the harmonica. Thus option D is correct.
3. Water near the poles receives much less solar energy than the tropical regions and often has water temperatures around 0 degrees Celsius. Why is the water in the polar
regions not completely frozen?
A color
C salinity B density
D phytoplankton
Answer:
Yes
Explanation:
sdfu8hdfhu8dfghgdfijndfgjknfdgjknfgdjkndfgjkndfgklndfgknldfgklmdfgklmdfgkondfgkjnodfgklndfgklndfglknfgdklndfgklndfgklndfgklndfgklndfgpkmfgdklnfdgyklndklndfgklndfglkngdfklndfgljkngdfklndfglkmdfgh
A frictionless piston-cylinder contains carbon dioxide gas (CO2) initially at 500oC and 2 MPa. The system is o3 cooled in an isobaric process until the final temperature becomes 350 C and the final volume is 1 m . For this process, determine: (a) The reduced pressure and the reduced temperature of the initial state. (b) The initial volume of the piston-cylinder (in m3). (c) The mass of CO2 in the piston-cylinder (in kg). (d) The total boundary work for the process (in kJ). (e) The amount of heat transfer during the cooling process (in kJ).
Answer:
(a) The reduced pressure is 0.2711 MPa
The reduced temperature is 2.54 K
(b) The initial volume of the piston is approximately 0.806 m³
(c) The mass of CO₂ is approximately 16.9884 kg
(d) The work done, W is approximately 388.023 kJ
(e) The heat transfer is approximately -2,650.1904 kJ
Explanation:
The initial temperature of the piston-cylinder, T₁ = 500°C = 773.15 K
The initial pressure of the gas, P₁ = 2 MPa
The final temperature of the gas, T₂ = 350°C
The final volume of the gas = 1 m³
(a) For an isobaric process, we have;
The reduced pressure,
[tex]P_r = \dfrac{P}{P_c}[/tex]
The critical pressure of carbon dioxide, [tex]P_c[/tex] = 7.3773 MPa
[tex]P_r = \dfrac{2 \, MPa}{7.3773 \, MPa} \approx 0.2711 \, MPa[/tex]
The reduced pressure, [tex]P_r[/tex] = 0.2711 MPa
The critical temperature, [tex]T_c[/tex] = 304.13 K
The reduced temperature, [tex]T_r[/tex], is given by the following formula;
[tex]T_r = \dfrac{T}{T_c}[/tex]
Therefore, [tex]T_r[/tex] = (773.15 K)/(304.13 K) = 2.54216947 K
The reduced temperature, [tex]T_r[/tex] ≈ 2.54 K
(b) The initial volume of the piston, V₁ = (V₂/T₂) × T₁
∴ V₁ = (1 m³/773.15) × 623.15 = 0.80598848865 m³ ≈ 0.806 m³
The initial volume of the piston, V₁ ≈ 0.806 m³
(c) The number of moles of CO₂ in the cylinder, 'n', is given according to the following formula;
n = P·V/(T·R)
The universal gas constant, n = (2 × 10⁶Pa × 1 m³)/(623.15 K × 8.3145 J/(mol·K)) ≈ 386.0124 moles
The mass of CO₂ ≈ 386.0124 moles × 44.01 g/mol = 16.9884 kg
(d) The work done, W = P·([tex]V_f - V_i[/tex])
W = 2 × 10⁶ × (1 - 0.80598848865) = 388023.0227
The work done, W ≈ 388.023 kJ
(e) The heat transfer dQ = m·[tex]c_p[/tex] ×(T₂ - T₁)
[tex]c_p[/tex] for CO₂ ≈ 1.04 kJ/(kg·K)
∴ dQ = 16.9884 × 1.04 × (350 - 500) = -2,650.1904 kJ
Therefore, the heat transfer = dQ = -2,650.1904 kJ
A cricketer lowers his hand while catching balls. Why?
Answer:
While catching a ball, a cricket player lowers his hands, because by doing so, he increases the time of catch. That is, the person increases the time to bring about a given change in momentum, and hence rate of change of momentum decreases. Thus, a small force is exerted by ball on the hands.
Explanation:
:)
Answer:
it is your answer....... if it is helpful plzz like and comment
Knowledge and skills learned through socialization are an example of
Multiple Choice
1. human resources.
2. social resources.
3. political resource.
4. cultural resources.
Answer:
I think no.2 the answer
Because socialization and social resources are both for me
The correct answer is 4. cultural resources. Knowledge and skills learned through socialization.
What are Knowledge and skills learned through socialization?Knowledge and skills learned through socialization refer to the cultural, social, and behavioral norms and values that individuals learn through interaction with others in their environment. This process of learning begins in childhood and continues throughout an individual's life, through various social institutions such as family, education, religion, media, and peer groups.
Here,
The correct answer is 4. cultural resources. Knowledge and skills learned through socialization are an example of cultural resources because they are shaped by the cultural norms, values, and beliefs of the society in which an individual grows up.
Learn more about knowledge and skill learned here:
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Direction of Wave Travel
С
Which letter
correctly
identifies the
wavelength of
this wave?
А
B
A. A
B. B
C. C
Answer:
I THINK it's A but I'm not completely sure
Will the 79 kg skier in the figure below slide down if f the coefficient of static friction is 0.25?
Answer:
Man will not slide down
Explanation:
Given:
Coefficient of static friction = 0.25
Angle = 13°
Computation:
Man will slide down if
tan13° > Coefficient of static friction
Tan 13 = 0.23
So,
0.23 < 0.25
So,
Man will not slide down
which of the following characteristics is most useful for flower identification
Answer:
basically needing sunlight and water
Explanation:
hope it helps
ASSIGNMENT
1) A force of 2N stretches an elastic material by 30mm. what additional
force will stretch the material 35mm? Assume that the elastic limit is not
exceeded
Answer:
If 2N = 30mm
Then ? =35mm
2N×(35mm÷30mm)
2N×1.167
= 2.33N
To get the additional force required, subtract 2N from 2.33N
2.33N - 2N
= 0.33N
∴ The additional force needed is 0.33N
Explanation:
With this question, we establish the principles of proportion. That is, if more less divides and vice versa. If 2N is stretching the material to 30mm, then how more force will be needed to stretch the material to 35mm?
A student adds 5 grams of vinegar to 7 grams of baking soda in a sealed bag. Then she watches the bag inflate as a chemical
reaction occurs. Which of these amounts is a CORRECT prediction of the mass of the materials in the container after the reaction is
complete?
Answer:
The mass will stay the same if the bag stays sealed.
Explanation:
Which group is an international organization in which the United States is involved?
A. The Foreign Relations Committee
B. The Senate Armed Services Committee
C. The Department of Defense
D. The World Trade Organization
Ccorrect Answer Is D: The World Trade Organization
Answer:
the answer is d the world trade organization
Explanation:
What is double stroking
Answer: The double stroke roll works just like the single stroke roll - it's played in a sequence of alternating strokes (roll). But instead of having one stroke per hand you'll have two, as shown on the sheet music below. You can use full wrist turns to play each stroke of the double stroke at slower speeds.
Explanation: hope this helps!
Explanation:
it is played as a sequence of alternating strokes
Evidence supporting the humanistic perspective is easily measured. True or false?
Answer:
False
Explanation:
I believe it's false.
Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.
What is an Evidence?Evidence is defined as an object or information introduced to make the existence of a fact more or less probable that of testimony, document, photograph, video, voice recording, DNA test, or other tangible objects. can take form.
Evidence is used to prove an argument made by individuals or groups that believe something is true or a fact that can be used to refute or disprove a fact or argument that people disagree with, or considered false.
Thus, Evidence not supporting the humanistic perspective is easily measured. So, the given statement is False.
Learn more about Evidence, here:
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please help me with the working too.
Answer:
1 : b 2: d
Explanation:
what causes moon phases, rotation or revolution
Answer:
The Moon's monthly
cycle of phases
results from the
changing angle of
its illumination by the Sun.
Because its period of
revolution is the same as its
period of rotation, the Moon
always keeps the same face
toward Earth.
A capacitor is made from two hollow, coaxial, iron cylinders, one inside the other. The inner cylinder is negatively charged and the outer is positively charged; the magnitude of the charge on each is 11.5 pC. The inner cylinder has a radius of 0.550 mm, the outer one has a radius of 7.20 mm, and the length of each cylinder is 13.0 cm.
(a) What is the capacitance?
(b) What applied potential difference is necessary to produce these charges on the cylinders?
Answer:
A)2.811 × 10^-12 F
B)4.09V
Explanation:
(a) What is the capacitance?
Capacitance of coaxial cylinder can be determined using below expresion
C= (2π ε0 L)/ Ln[ rb/ra]
Where
ε0= permittivity of free space= 8.85×10^−12 Fm^-1
L= length of each cylinder =13.0 cm= 13×10^-2m
rb= radius of outer cylinder= 7.20 mm= 7.20×10^-3m
ra=radius of inner cylinder=0.550 mm= 0.550×10^-3 m
If we substitute the values we have,
C= (2π ε0 L)/ Ln[ rb/ra]
C= ( 2 × π × 8.85×10^−12 ×13×10^-2) / Ln[
7.20×10^-3/0.550×10^-3]
C=( 7.2288×10^-12 )/2.5729
C=2.811 × 10^-12 F
B) (b) What applied potential difference is necessary to produce these charges on the cylinders?
Vba= Q/C
Where Vba=potential difference
Q= charge on each = 11.5 pC. = 11.5×10^-12
C= capacitance= 2.811 × 10^-12 F
If we substitute the values we have
Vba=(11.5×10^-12)/2.811 × 10^-12
= 4.09V