Answer:3:1
Step-by-step explanation:
There are 2 sports cars out of a total of 8 total cars, so there are 2 favorable outcomes, and 8−2=6 unfavorable outcomes.
The odds against choosing a sports car are 6:2.
Both numbers are divisible by 2, so this ratio can be simplified to 3:1.
Find the slope of the line that passes through:
(6,7) and (4,2)
Answer:
5/2
Step-by-step explanation:
Slope = Change in y/Change in x
Slope = 2 - 7/4 - 6
Slope = -5/-2
Slope = 5/2
-Chetan K
At a sale this week, a desk is being sold for $285.60. This is 34% of the original price.
What is the original price?
well, let's say the original price is "x", which namely 100% of the price of the product, we also know that 285.60 is 34% of that.
[tex]\begin{array}{ccll} amount&\%\\ \cline{1-2} x&100\\ 285.60&34 \end{array}\implies \cfrac{x}{285.60}=\cfrac{100}{34}\implies \cfrac{x}{285.60}=\cfrac{50}{17} \\\\\\ 17x=14280\implies x = \cfrac{14280}{17}\implies x = 840[/tex]
The water level in a lake was monitored and was noted to have changed -2 1/3 inches in one year. The next year it was noted to have changed -1 5/6 inches. What was the total change in the water level over the two years?
Answer:
The total change in water level over the past 2 years is [tex]\displaystyle -4 \frac{1}{6}[/tex].
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightFractions
Proper and ImproperNumbers
Least Common Multiple (LCM)Step-by-step explanation:
Step 1: Define
Identify
Year 1 water change: [tex]\displaystyle -2 \frac{1}{3}[/tex]
Year 2 water change: [tex]\displaystyle -1 \frac{5}{6}[/tex]
Step 2: Find Total Water Change
[Set up] Add yearly water changes: [tex]\displaystyle -2 \frac{1}{3} + -1 \frac{5}{6}[/tex][Fractions] Convert to improper: [tex]\displaystyle \frac{-7}{3} - \frac{11}{6}[/tex][Fraction] Rewrite [LCM]: [tex]\displaystyle \frac{-14}{6} - \frac{11}{6}[/tex][Order of Operations] Subtract: [tex]\displaystyle \frac{-25}{6}[/tex][Fraction] Convert to proper: [tex]\displaystyle -4 \frac{1}{6}[/tex]Two numbers have a sum of 18. Their product is 72. Find the numbers
Answer:
Step-by-step explanation:
x + y = 18
y = 18 - x
xy = 72
x(18 - x) = 72
-x² + 18x = 72
0 = 72 - 18x + x²
x = (18 ± √(18² - 4(1)(72))) / (2(1))
x = (18 ± 6)/2
x = 12
x = 6
Can some please help me I will mark u brilliant
Question 2: -4/3
Question 3: -7/20
find measurement 1 and 4
Answer:
the info they gave us is to suppose that angle 6 is = 126°
step 1:
We know that angle 8 = angle 6 = 126°
Why? — when a circle (360°) is split by 2 lines that intersect, there will be 2 equal pairs of angles formed
step 2:
angle 2 = angle 8 = 126°
Why? — they’re alternate angles
step 3:
angle 4 = angle 2
Why? — when a circle (360°) is split by 2 lines that intersect, there will be 2 equal pairs of angles formed
step 4:
angle 1 = 180-126 (angle 4) = 54°
Why? — total angles in a straight line = 180°
Key Term:
Alternate angles:
Alternate angles are angles that occur on opposite sides of the transversal line and have the same size. Alternate angles are equal: We can often spot interior alternate angles by drawing a Z shape: There are two different types of alternate angles, alternate interior angles and alternate exterior angles.
Incredibly, Enzo wins 5 tickets from every game, and Beatriz wins 11 tickets from every game. When they stopped playing games, Enzo and Beatriz had won the same number of total tickets.
What is the minimum number of games that Enzo could have played?
Answer:
Enzo must have played 11 games.
Step-by-step explanation:
Since Enzo earns 5 tickets from every game and Beatriz wins 11 tickets from each game, we have to find the LCM (Least Common Multiple) since they earned the same amount of tickets when they stopped.
The LCM of 11 and 5 is 55.
To see how many games they both played we have to divide the amount of tickets they earn each time from the LCM (55).
Since Enzo earns 5 tickets from each game and both Enzo and Beatrice earned 55, Enzo must've played 11 games.
(If that makes sense lol)
The annual number of burglaries in a town rose by 50% in 2012 and fell by 10% in 2013. hence the total number of burglaries increased by 40% over the two year period.
a. by what percent has the number of burglaries actually changed in the two-year period?
b. by what percent would the crime have to decrease in the second year in order for the change over the two-year period to actually be a 40% increase?
The percentage change in the number of burglaries over the two-year period is 35% .
The change in burglaries over the two-year period to have a 40% increase is 6.7%.
Let's assume that the annual number of burglaries in 2011 is 1000. After the 50% increase in 2012, the number of burglaries would be: 1000(1.50) = 1500.
The number of burglaries after the 10% reduction in 2013 would be: 1500(.90) = 1350
The change in burglaries over the two-year period = (1350 / 100) - 1 = 35%
In order to determine how much burglaries would have to reduce in order to have a 40% change in burglaries, this formula would be used
(x - 1000) / 1000 = 0.40
x - 1000 = 400
x = 1400
The change in burglaries over the two-year period to have a 40% increase = (1400 / 1500) - 1 = 6.7%
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Alexander Litvinenko was poisoned with 10 micrograms of the radioactive substance Polonium-210. Since radioactive decay follows a compounded continuously model, we can determine the amount of substance left in Alexander Litvinenko's body at any given time. If Polonium-210 has a decay rate of .502%, then determine the amount of Polonium-210 left in his body after 40 days. Provide 3 decimal places and units in your answer.
Compounded continuously model are evaluated using exponential functions
There are 8.177 bacteria left after 40 days
The given parameters are:
[tex]\mathbf{a = 10}[/tex] --- the initial number of bacteria
[tex]\mathbf{r = 0.502\%}[/tex] --- the decay rate
[tex]\mathbf{n = 40}[/tex] --- the number of days
The amount of bacteria left each day is calculated using:
[tex]\mathbf{T_n = a \times (1 - r)^n}[/tex]
So, we have:
[tex]\mathbf{T_{40} = 10 \times (1 - 0.502\%)^{40}}[/tex]
Express percentage as decimal
[tex]\mathbf{T_{40} = 10 \times (1 - 0.00502)^{40}}[/tex]
Simplify the expression in bracket
[tex]\mathbf{T_{40} = 10 \times 0.99498^{40}}[/tex]
Evaluate
[tex]\mathbf{T_{40} = 8.1766}[/tex]
Approximate
[tex]\mathbf{T_{40} = 8.177}[/tex]
Hence, there are 8.177 bacteria left after 40 days
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$200 is shared between Bill and Ann. Ann’s share is $50 more than Bill’s share. Calculate the size of each of their shares.
First subtract the difference between the two:
200 - 50 = 150
Now divide that by 2:
150/2 = 75
Bills share is $75
Now add the $50 to 75 to get Ann's share:
75 + 50 = $125
Ann's share is $125
Bill's share is $75
Tom is reviewing his cell phone bill. When he gets to the text message part he notices that he send 1 text message in October,7 text messages in November, 49 messages in December,and 343 text messages in January. what kind of sequence is this?
a. arithmetic b. geometric c. both d. neither
Answer:
it is c. both i guess anyways thanks
i hope you passed and sorry for taking your points
Step-by-step explanation:
I need help with this math problem
Answer: The drill will reach -915 feet after 18 days.
calculate lim F(X)
[tex] {x }^{2} + 1 - 3 \frac{ ln(x) }{x} [/tex]
[tex]Hiya![/tex]
Sokka is here to help!!
Here's the step:
[tex]x^2+1-3\frac{In(x)}{x}[/tex]
[tex]Mutiply[/tex] [tex]by:[/tex] [tex]3[/tex]
[tex]. \frac{In(x)}{x} :\frac{3In(x)}{x}[/tex]
[tex]= x^2+1-\frac{3In(x)}{x}[/tex]
ANSWER:
[tex]= x^2+1-\frac{3In(x)}{x} .[/tex]
Hopefully, this helps you!!
[tex]Sokka[/tex]
Find the additive inverse and the multiplicative inverse, if it exists, of the given number. 5 in modulo 8 arithmetic
The additive inverse of 5 modulo 8 is the number a such that
5 + a ≡ 0 (mod 8)
Then
a ≡ -5 ≡ -5 + 8 ≡ 3 (mod 8)
The multiplicative inverse is m such that
5m ≡ 1 (mod 8)
Use the Euclidean algorithm:
8 = 1•5 + 3
5 = 1•3 + 2
3 = 1•2 + 1
Then
1 = 3 - 1•2
1 = 3 - 1•(5 - 1•3) = 2•3 - 1•5
1 = 2•(8 - 1•5) - 1•5 = 2•8 - 3•5
and so
1 ≡ 2•8 - 3•5 ≡ (-3)•5 (mod 8)
which means the inverse of 5 is
-3 ≡ 8 - 3 ≡ 5 (mod 8)
simplify
21m^2−122m+112/9m^2−196
Answer:
3m-8/7m+14
Step-by-step explanation:
The low temperature on a certain day is 56°F. The low temperature is 14°F lower than the high temperature, h. Which equation can be used to find the high temperature for that day? o 56 = h – 14 Oh + 56 = 14 O 56 = 14h 0 56 = h + 14 WHOEVER ANSWER GETS BRAINLESS NEED HELP
Answer: 1.09
Step-by-step explanation:
For any nonnegative real number a, (a)2 =
=
O A. a2
O B. va
Ос. а
O D. 1
SUBMIT
Answer:
C
Step-by-step explanation:
For example, if a is equal to 2.
[tex] \sqrt{2} {}^{2} = 2[/tex]
The answer is still the given number a.
The solution of the expression √a² is,
⇒ a
What is an expression?Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
The expression is,
⇒ √a²
Where, 'a' is nonnegative real number.
Now, We can simplify as;
⇒ √a²
⇒ √ a × a
⇒ a
Thus, The solution of the expression √a² is,
⇒ a
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#SPJ5
Which distance formula or formulas show(s) a joint variation?
Answer:
II and III only
Step-by-step explanation:
One variable quantity is said to vary jointly as a number of other variable quantities, when it varies directly as their product.
5) Placido pulls a rope attached to a wagon through a pulley at a rate of q m/s. With dimension as in Figure 5:
(a) Find a formula for the speed of the wagon in terms of q and the variable x in the figure.
(b) Find the speed of the wagon when x=0.6 if q=0.5 m/s.
The formula for the speed of the wagon can be found by using Pythagoras theorem, and chain rule of differentiation.
[tex](a) \ \mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = q -\dfrac{x}{\sqrt{x^2+ 5.76}}[/tex]
(b) When x = 0.6 and q = 0.5 m/s, the speed of the wagon is approximately 0.243 m/s.
Reasons:
(a) The distance from the cart to the pulley, r is given by Pythagoras's
theorem as follows;
r = √((3 - 0.6)² + x²) = √(2.4² + x²)
The speed of the wagon = [tex]\mathbf{\dfrac{dx}{dt}}[/tex]
The speed of the rope, q = [tex]\mathbf{\dfrac{dr}{dt}}[/tex]
By chain rule, we have;
[tex]\dfrac{dr}{dt} = \mathbf{\dfrac{dr}{dx} + \dfrac{dx}{dt}}[/tex]
[tex]\dfrac{dr}{dx} = \dfrac{x}{\sqrt{x^2+ 5.76}}[/tex]
Therefore;
[tex]\dfrac{dr}{dt} = q =\dfrac{x}{\sqrt{x^2+ 5.76}}+ \dfrac{dx}{dt}[/tex]
[tex]\mathrm{The \ speed \ of \ the \ wagon} , \ \dfrac{dx}{dt} = \underline{ q -\dfrac{x}{\sqrt{x^2+ 5.76}}}[/tex]
(b) The speed of the wagon when x = 0.6 if q = 0.5 m/s is given as follows;
[tex]\dfrac{dx}{dt} = 0.5 -\dfrac{0.6}{\sqrt{0.6^2+ 5.76}} =\sqrt{\dfrac{1}{17} } \approx 0.243[/tex]
The speed of the wagon when x = 0.6 and q = 0.5 m/s, [tex]\dfrac{dx}{dt}[/tex] ≈ 0.243 m/s
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For the two numbers listed, find two factors of the first number such that their product is the first number and their sum is the second number -12,-1
3. Your bedroom is 14 feet by 10 feet and your sister's room is 12 feet by 10 feet. If you
are going to paint both rooms the same color and the paint covers 250 square feet per
gallon, how much paint will you need if you are going to paint the walls and ceilings?
Assume the ceiling is 8 ft high.
Step-by-step explanation:
we paint the walls and ceilings.
and we ignore any doors or windows (no information about them).
so, each room has then 5 rectangles : 4 walls and 1 ceiling.
when we say a room is 14 ft × 10 ft, this also means there are 2 sides of 14 ft and 2 sides of 10 ft.
and the area is 14×10 ft².
the area of the ceiling is the same as the area of the floor : 14×10 = 140 ft²
for the walls we have 2 rectangles of 14×8 = 112 ft², and 2 rectangles of 10×8 = 80 ft² (remember, the height of the room is 8 ft).
for the sister's room it is similar.
just a 12×10 = 120 ft² ceiling.
and 2 rectangles of 12×8 = 96 ft² and again 2 rectangles of 10×8 = 80 ft² as walls.
altogether we have then
140 + 112 + 112 + 80 + 80 + 120 + 96 + 96 + 80 + 80 ft²
that is in total
996 ft²
how many gallons of paint do we need for this ?
well, 1 gallon per 250 ft².
so, how often does 250 fit into 996 ?
996 / 250 = 3.984 gallons.
since we get the paint most likely only in quantities of gallons, we need 4 gallons for the paint job.
HELP i need what is 4 divided by 120000 telll me plz in tried the calculator but my parents blocked the calculator on me so plz help me
A bag of sugar weighs 6²/⁵. What is the weight of 6¹/⁴ of such bag?
How many two thirds are there in 4¹/³?
Answer:
6 and a half 2 thirds are in 4 1/3
Step-by-step explanation:
2/3x=13/3
2x=13
x=6.5
what is 1/5 divided by 9?
Answer:
9/5
Step-by-step explanation:
Just divide the 9 by 1 so it'll be 9/5 hope it helps
Find the missing number.Write your answer on your answer sheet.
3/5÷2/6= 3/5÷6/2=
[tex] \huge \bf \color{gold} \frac{3}{5} \div \frac{2}{6} = [/tex]
[tex] \tt \frac{3}{5} \times \frac{6}{2} = [/tex]
[tex] \tt \frac{18 \div 2}{10 \div 2} = [/tex]
[tex] \tt \frac{9}{5} = [/tex]
[tex] \boxed {\color{blue}{ 1 \frac{4}{5}}}[/tex]
THE RESULT IS 1 4/5
Answer:
The solution is 9/5 and 1/5
Step-by-step explanation:
3/5÷2/6
= 3/5×6/2
= 3/5×3
= 9/5
3/5÷6/2
= 3/5×2/6
= 3/5×1/3
= 1/5
If $2,940.00 is invested for 4 months at 3.8% simple interest:
What is the amount of interest earned?
Answer:
I = $372.40
Step-by-step explanation:
Given the principal amount of $2,940, which is invested for 4 months at 3.8% interest rate:
Use the following simple interest formula to solve for the interest earned:
I = P × r × t
where:
I = interest earned
P = principal amount invested = $2,940
r = interest rate = 3.8% or 0.380
t = time = 4/12 months = ⅓ or 0.3333
Substitute to given values into the simple interest formula:
I = P × r × t
I = $2,940 × 0.380 × 0.3333
I = $372.40
Therefore, the simple interest earned in 4 months is $372.40.
2x+3-3=-6
x=3 ? Solve
[tex]2(x)+3-3=-6\\2(3)+3-3=-6\\6+3-3=-6\\6=-6\\[/tex]
[tex]x\neq 3[/tex]
As we can see, x cannot be equal to 3 as 6 cannot equal -6.
I hope I've helped! :)
A hummingbird lives in a nest that is 12 meters high in a tree. The hummingbird flies 15
meters to get from its nest to a flower on the ground. How far is the flower from the base of
the tree?
Answer:
The flower is 9 meters from the base of the tree.
Step-by-step explanation:
Use the Pythagorean theorem to solve. We are given the length of one leg and the length of the hypotenuse of a right triangle.
[tex]a^{2} +b^{2} =c^{2}[/tex]
where a and b are the legs, and c is the hypotenuse.
Plug in the given values and solve:
[tex]x^{2} +12^{2} =15^{2} \\x^{2} +144=255\\x^{2} =81\\x=9[/tex]
The flower is 9 meters from the base of the tree.
What is the perimeter of a rectangle with a length of 11.25 inches and a
width of 8 inches?
Answer:
38.5 in
Step-by-step explanation:
11.25 in + 11.25 in + 8 in + 8 in
= 38.5 in
The side of an equilateral triangle is 12. Its area is
Select one:
a. 72
b. 48
c. 144
d. 36 square root 3
A≈62.35
..................