Answer:
λ = 396.7 nm
Explanation:
For this exercise we use the diffraction ratio of a grating
d sin θ = m λ
in general the networks works in the first order m = 1
we can use trigonometry, remembering that in diffraction experiments the angles are small
tan θ = y / L
tan θ = [tex]\frac{sin \theta}{cos \theta}[/tex] = sin θ
sin θ = y / L
we substitute
[tex]d \ \frac{y}{L}[/tex] = m λ
with the initial data we look for the distance between the lines
d = [tex]\frac{m \lambda \ L}{y}[/tex]
d = 1 656 10⁻⁹ 1.00 / 0.600
d = 1.09 10⁻⁶ m
for the unknown lamp we look for the wavelength
λ = d y / L m
λ = 1.09 10⁻⁶ 0.364 / 1.00 1
λ = 3.9676 10⁻⁷ m
λ = 3.967 10⁻⁷ m
we reduce nm
λ = 396.7 nm
Prominences and sunspots are both:
A. Jets of burning gas
B. Patches on the Sun's surface
C. Influenced by the Sun's electromagnetic field
D. Visible during an eclipse
Answer:
C. Influenced by the Sun's electromagnetic field
Explanation:
"Sunspots occur in pairs because each is one side of a loop of the Sun's magnetic field that reaches the Sun's surface. Solar prominences are the plasma loops that connect two sunspots."
Question 1 of 10 Which characteristic of nuclear fission makes it hazardous?
O A. The process destroys every atomic nucleus that goes through it.
O B. The process changes existing atoms into atoms of different elements
C. The process requires very high pressures.
O D. The radioactive wastes it produces can spread to any part of the environment
Answer:
D.
The radioactive wastes it produces can spread to any part of the environment.
Explanation:
Fission is the name given to the splitting of a heavy nucleus into two medium-mass nuclei. Fission is said to be induced if it results from the absorption of a neutron to form an unstable nucleus that decays by fission. The induced fission usually produces further neutrons accompanying the fission fragments.
Answer: D. The radioactive wastes it produces can spread to any part of the environment
Explanation:
After the initial experiment, students wondered how a person's weight would influence the results. They conducted a second experiment to determine if the mass of an object affected friction, assuming the types of surfaces remained constant. A spring scale was attached to a wooden block (1 kg). The block was placed on a wooden board and the spring scale was used to pull the block. The magnitude of the force required to start the block moving was recorded in the data table. The experiment was repeated using two, three, and four blocks. The data can be seen in the data table at the top of the page. What is the relationship between static friction and weight?
Answer:
The greater the weight of the person, the more static friction.
Explanation:
USATestPrep
Give the relationship between the number of valence electrons in an atom's
valence electron shell and the position of the element on the Periodic Table
Answer:
they're reactions
Explanation:
The relationship between the valence electrons and position is: the number of valence electrons determines the position
What is valence electron?This is the number of electrons in the outermost shell of an atom.
NOTE: The outermost shell is called valence shell
Position in Periodic tableThis is where an element is located in the periodic table
Relationship between valence electrons and positionThe position of an element in the periodic table is determined by the number of valence electrons.
For example
Sodium, Na (atomic number of 11) has the following electronic configuration
1st shell = 2 electrons2nd shell = 8 electrons 3rd (valence) shell = 1 electronSince the valence electron is 1, thus, sodium is located in group 1 of the periodic table.
Thus, we can see that the position of an element in the periodic table is related to the valence electron(s) in the atomic shell of the element.
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A ball is rolling down a hill. Wich action would slow the ball down?
A disk of a radius 50 cm rotates at a constant rate of 100 rpm. What distance in meters will a point on the outside rim travel during 30 seconds of rotation?
Answer:
the distance in meters traveled by a point outside the rim is 157.1 m
Explanation:
Given;
radius of the disk, r = 50 cm = 0.5 m
angular speed of the disk, ω = 100 rpm
time of motion, t = 30 s
The distance in meters traveled by a point outside the rim is calculated as follows;
[tex]\theta = \omega t\\\\\theta = (100 \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1\min}{60 s} ) \times (30 s)\\\\\theta = 100 \pi \ rad\\\\d = \theta r\\\\d = 100\pi \ \times \ 0.5m\\\\d = 50 \pi \ m = 157.1 \ m[/tex]
Therefore, the distance in meters traveled by a point outside the rim is 157.1 m
Why is this true? Why is this true? Photons of lower-frequency light don't have enough energy to eject an electron. The electric field of low-frequency light does not vibrate the electrons rapidly enough to eject them. The number of photons in low-frequency light is too small to eject electrons. Low-frequency light does not penetrate far enough into the metal to eject electrons. Request Answer
Answer:
the only correct answer is: Photons of lower-frequency light don't have enough energy to eject an electron
Explanation:
This question is in the model of the photoelectric effect, where some electrons are expelled from the metal by the action of a ray of light.
This effect was explained by Einstein supposes that the light rays are formed by photons and the energy of these photons is given by the Planco relation
K = h f - Ф
where K is the kinetic energy of the ejected electrons and Ф is the work function, it keeps the electrons inside the material.
When analyzing this expression there is a minimum frequency (threshold) for which K = 0
hf = Ф
Below this frequency the photons in the light beam do not have the energy to expel the electrons from the material.
Let's examine the answers
a) True. You agree with the above
b) False. The analysis is in terms of individual shock
c) False. The expulsion does not have to do with the number of photons but with the energy of each one
therefore the only correct answer is: Photons of lower-frequency light don't have enough energy to eject an electron
What structure is represented by the letter
C?
PLEASE HELP!!!!!
Choose 1 answer:
А
Lysosome
B
Nucleus
C
Vacuole
D
Mitochondria
Calories are a unit of energy that are reserved for heat energy but can be
directly converted to and from mechanical units of energy (Joules). How
many calories of energy are there in 500 Joules of energy?
Two ice skaters, with masses of 40.0 kg and 65.0 kg , are at the center of a 50.0 m -diameter circular rink. The skaters push off against each other and glide to opposite edges of the rink. Part A If the heavier skater reaches the edge in 10.0 s , how long does the lighter skater take to reach the edge
Answer:
6.15 s
Explanation:
From the question,
Applying the law of conservation of momentum
Momentum of the Heavier skater = Momentum of the lighter skater.
Mv = mV................. Equation 1
Where M = mass of the heavier skater, m = mass of the lighter skater, v = Velocity of heavier skater, V = velocity of the lighter skater.
But,
v = r/t........................ Equation 2
V = r/t'................ Equation 3
Where r = radius of the circular rink, t = time taken for the heavier skater to reach the edge, t' = time taken for the lighter skater to reach the edge.
Substitute equation 2 and equation 3 into equation 1
M(r/t) = m(r/t')............. Equation 4
Given: M = 65 kg, m = 40 kg, r = 50/2 = 25 m, t = 10 s.
Substitute into equation 4 and solve for t'
65(25/10) = 40(25/t')
162.5 = 1000/t'
t' = 1000/162.5
t' = 6.15 seconds
Please Help!!!
For A&B
Answer:
A. 40N
B. 5m/s
Explanation:
A.
Impulse is equal to the area under the curve of a force vs. time graph. In this case, the area is in the shape of a triangle with base 8 (12-4=8) and perpendicular height 10:
Area of a triangle = (1/2)bh
A=(1/2)*8*10
=40
ANSWER: 40N
B.
Impulse = mass * velocity
40 = 8v
v = 5
ANSWER: 5m/s
In the nitrogen cycle, plants take in nitrates and convert them into
The more mass an object has,the less inertia the object has. True or False
Answer:
This is true. objects that have a greater mass has greater interia. which also means objects that have a less mass has also less interia.
Explanation:
i hope this helps!!!
g A projectile of mass 3 kg is launched horizontally from an initial height 3 m with an initial velocity 10 m/s. This velocity in the x direction is preserved when you ignore air resistance. The projectile still accelerates in the vertical y direction toward the ground, but this is exactly the energy lost from potential energy. Energy is conserved as long as you use the total mechanical energy equation. What is the final kinetic energy as the projectile just reaches the ground
Answer:
The kinetic energy at ground will be "238.2 J".
Explanation:
The given values are:
mass,
m = 3 kg
Initial height,
h = 3 m
Initial velocity,
v = 10 m/s
By using the conservation of energy at points A and B,
⇒ [tex]E_A=E_B[/tex]
⇒ [tex]mgh+\frac{1}{2}mv^2=k_B[/tex]
On substituting the values, we get
⇒ [tex]3\times 9.8\times 3+\frac{1}{2}\times 3\times (10)^2=k_B[/tex]
⇒ [tex]88.2+0.5\times 3\times 100=k_B[/tex]
⇒ [tex]88.2+150=k_B[/tex]
⇒ [tex]238.2 =k_B[/tex]
Which machine do you think will last longer, the traditional battery and motor, or the free energy machine?
Answer:
it will most likely be the free energy
what foxes need to eat to
stay alive
Answer:
They eat meat and vegetation.Answer:
Meat and vegetation...Which is the correct formula for calculating speed?
A. speed - distance - time
B. speed = distange + time
C. speed = distance - time
D. speed = distance - acceleration
Answer:
speed=distance/time
Explanation:
its distance over time like division
Determine the activity of the sample of cerium when the sample was 80 seconds old
Answer is in a photo. I can only upload it to a file hosting service. link below!
bit.[tex]^{}[/tex]ly/3a8Nt8n
: A small block with mass 0.130 kg is attached to a string passing through a hole in a frictionless, horizontal surface. The block is originally revolving in a circle with a radius of 0.800 m about the hole with a tangential speed of 4.00 m/s. The string is then pulled slowly from below, shortening the radius of the circle in which the block revolves. The breaking strength of the string is 30.0 N. What is the radius of the circle when the string breaks
Answer:
r = 0.0173 m = 1.73 cm
Explanation:
Here, the centripetal force of the block will be providing the required breaking tension in the string:
[tex]Tension = Centripetal Force\\T = F_c\\\\T = \frac{mv^2}{r} \\\\r = \frac{mv^2}{T}\\[/tex]
where,
r = radius = ?
m = mass of block = 0.13 kg
v = tangential spee of block = 4 m/s
T = Breaking Strength = 30 N
Therefore,
[tex]r = \frac{(0.13\ kg)(4\ m/s)^2}{30\ N}[/tex]
r = 0.0173 m = 1.73 cm
When finding the radius of the string at the point it breaks, the tangential
velocity is assumed to be constant.
The radius when the string breaks is [tex]\underline{6.9 . \overline 3 \times 10^{-3}} \ m[/tex]Reasons:
The mass of the small block, m = 0.130 kg
Initial radius of the circle of rotation = 0.800 m
Tangential velocity, v = 4.00 m/s
The radius of the path of rotation is reduced as the string is pulled
Breaking strength of the string = 30.0 N
Required:
The radius of the circle when the string brakes
Solution:
[tex]Centripetal \ force = \dfrac{m \cdot v^2}{r}[/tex]
Where;
r = The radius of the circle of rotation
When the string brakes, w have;
Centripetal force = Breaking strength of the string = 30.0 N
Which gives;
[tex]\displaystyle r = \mathbf{\dfrac{m \cdot v^2}{Centrifugal \ force}} = \frac{0.130 \times 4^2}{30} =6.9\overline 3 \times 10^{-2}[/tex]
The radius of the circle when, the string breaks r = [tex]\underline{6.9\overline 3 \times 10^{-2}} \ m[/tex]
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How did our Sun form? *
A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to
fuse together.
Many smaller stars became fused together by gravity
It broke off from a larger star in the universe.
Two gas giants from another solar system became fused together by gravity.
Answer: A cloud of stellar dust from part of a Nebula collapsed causing hydrogen atoms to fuse together
Explanation:
gravitational potential is the energy due to an object's:
a. motion
b. spring stretch or compression
c. position in a gravity field
d. chemical bonds.
position in a gravitation field (c)
Answer:
The answer is C. position in a gravity field
The magnetic field due to a utility wire is 0.10 mT when you are at a distance of 10 meters from it. What current (in Amperes) flows through the wire?
Answer:
I = 5000 A
Explanation:
We will use Ampere's Law to calculate the current:
[tex]B = \frac{\mu I}{2\pi r}\\\\[/tex]
where,
B = Magnetic Field Strength = 0.1 mT = 1 x 10⁻⁴ T
μ = Permeability of Free Space = 4π x 10⁻⁷ N/A²
I = Current = ?
r = radius = 10 m
Therefore,
[tex]1\ x\ 10^{-4}\ T = \frac{(4\pi\ x\ 10^{-7}\ N/A^2)(I)}{2\pi(10\ m)}\\\\I = \frac{(1\ x\ 10^{-4}\ T)(2\pi (10\ m))}{4\pi\ x\ 10^{-7}\ N/A^2}[/tex]
I = 5000 A
Which has the least gravitational force?
Answer: Mount Nevado Huascarán
Explanation: Mount Nevado Huascarán in Peru has the lowest gravitational acceleration, at 9.7639 m/s2, while the highest is at the surface of the Arctic Ocean, at 9.8337 m/s2
A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?
Answer:
Explanation:
A 4.0 kg mass has a velocity of 10 m/s to the EAST. The 4.0 kg mass is subjected to a constant net force of 16 N to the WEST for 3.0 sec. What is the velocity of the 4.0 kg mass at the end of the 3.0 sec interval?
The final velocity of the 4.0 kg mass is equal to 22 m/s.
What is Newton's second law of motion?According to Newton’s second law of motion, the force acting on the object equals the mass of that object times its acceleration for a constant mass.
The acceleration of an object depends on two variables, one is the mass of the object and another is the net force acting. The acceleration of an object is directly proportional to the force acting on the body and inversely proportional to its mass.
The equation of Newton’s second law can be represented as follows:
F = ma
or, a = F/m
Given, the initial velocity of the mass, u = 10m/s
The mass, m = 4.0 Kg
The force acting on the mass, F = 16 N
The acceleration of the mass will be: a = F/m
a = 16/4 = 4 m/s²
From the 1st equation of motion: v = u + at
The velocity after t = 3 sec can be calculated:
v = (10) + (4) × (3)
v = 10 + 12
v = 22 m/s
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what is the movement of energy by waves
Answer; thermal energy
Explanation:
'Wave' is a common term for a number of different ways in which energy is transferred: In electromagnetic waves, energy is transferred through vibrations of electric and magnetic fields. In sound waves, energy is transferred through vibration of air particles or particles of a solid through which the sound travels.
Constructive interference in wave patterns causes an increase in which measurement associated with waves and vibrations?
A. period
B. frequency
C. speed
D. amplitude
E. wavelength
Constructive interference in wave patterns causes an increase in amplitude measurement associated with waves and vibrations.
What is constructive interference?When two waves move in the same direction and are in phase with each other, their amplitudes are summed to produce the resultant wave.
The waves are considered to have suffered constructive interference in this case. Upward displacement occurs when waves experience constructive interference.
The medium's upward displacement is higher than the displacement of the two interfering pulses.
Hence option D is correct.
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What is the salt formed in the second sample reaction?
Answer:
This powder is sodium chloride. In the second reaction (sulfuric acid with copper(II) oxide) the resulting solution was blue in colour. When this solution was heated a small amount of white powder was noted.
Explanation:
i saw it on quizlet
1. You are given a bottle that contains 4.59 cm of a metallic solid. The total mass of the bottle
is 35.66 g. The empty bottle weighs 14.23 g. What is the density of the solid?
Particle track detectors are used to measure the speed of particles if the lifetime of the particle is known. Particle-X has a lifetime of 256.2 ps. These particles are created in an experiment inside the detector by a given reaction. The particles leave 10.7 cm long tracks on average before they decay into other particles not observable by the detector. What is the average speed of the particles in terms of the speed of light
Answer:
the average speed of the particles in terms of the speed of light is 0.81c
Explanation:
Given the data in the question;
[tex]t_p[/tex] = 256.2 ps = 256.2 × 10⁻¹² s
speed of light c = 2.99 × 10⁸ m/s
d = 10.7 cm = 0.107 m
we know that; Average speed v = d/t ------- let this be equation 1
Also, given that 256.2 ps is the lifetime of particle X frame, proper time will be;
t = Y[tex]t_p[/tex] = [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) --------- let this be equation 2
Next, we input equation 2 into equation 1'
v = d / [ [tex]t_p[/tex] / √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]
v = d/[tex]t_p[/tex][ √( 1 - [tex]\frac{v^2}{c^2}[/tex] ) ]
v[tex]t_p[/tex]/d = √( 1 - [tex]\frac{v^2}{c^2}[/tex] )
we square both sides
( v[tex]t_p[/tex]/d )² = (√( 1 - [tex]\frac{v^2}{c^2}[/tex] ) )²
v²[tex]t_p[/tex]²/d² = 1 - [tex]\frac{v^2}{c^2}[/tex]
v²[tex]t_p[/tex]²/d² + [tex]\frac{v^2}{c^2}[/tex] = 1
v²( [tex]t_p[/tex]²/d² + [tex]\frac{1}{c^2}[/tex] ) = 1
v²( ([tex]t_p[/tex]²c² + d²)/d²c² ) = 1
∴
v² = (d²c²) / ([tex]t_p[/tex]²c² + d²)
v = √[ (d²c²) / ([tex]t_p[/tex]²c² + d²) ]
v = (dc) / √([tex]t_p[/tex]²c² + d²)
so we substitute
v = (0.107 m × c) / √( (256.2 × 10⁻¹² s)²(2.99 × 10⁸ m/s)² + (0.107 m )²)
v = 0.107c / √( 0.00586814 + 0.011449 )
v = 0.107c / √( 0.01731714 )
v = 0.107c / 0.1315946
v = 0.81c
Therefore, the average speed of the particles in terms of the speed of light is 0.81c
Electromagnetic waves can carry more data at higher frequencies. Why would a scientist opt to transmit data at a lower frequency instead?
What are the limitations of sending information using electromagnetic waves?
What are the differences between analog and digital signals?
What are the advantages of using digital signals over analog signals?
Using reliable internet sources, identify three ways we use analog and digital signals in our everyday lives.
Describe how radio telescopes are used to explore space.
How are radio waves used on Earth?
Why do radio telescopes convert radio waves (analog signals) to electrical (digital) signals for analysis? (Hint: What did the article say about the advantages of digital signals?)