Answer:
2.2 m/s
Explanation:
r = 0.1 m
ω₀ = 0 rad/s
α = 4.4 rad/s²
t = 5 s
ω = αt + ω₀
ω = (4.4 rad/s²) (5 s) + 0 rad/s
ω = 22 rad/s
v = ωr
v = (22 rad/s) (0.1 m)
v = 2.2 m/s
The linear velocity is 2.2 m/s
Given:
r = 0.1 m
ω₀ = 0 rad/s
α = 4.4 rad/s²
t = 5 s
So from the equation for angular acceleration we will get,
ω = αt + ω₀
ω = (4.4 rad/s²) (5 s) + 0 rad/s
ω = 22 rad/s
Angular velocity ω is analogous to linear velocity v
The relation between velocity and angular acceleration is given which is:
v = ωr
v = (22 rad/s) (0.1 m)
v = 2.2 m/s
Therefore, linear velocity of the point on its rim after 5s is 2.2 m/s.
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a student pushed a 100 N bicycle over a distance of 15 m in 5 s. calculate the power generated.
The catch in this one is: We don't know how much force the student used to push the bike.
It wasn't necessarily the 100N. That's just the weight of the bike. But you know that you can push a car, a wagon, or a bicycle hard, you can push it not so hard, you can give it a little push, you can give it a big push, you can push it strong, you can push it weak, you can push it medium. The harder you push, the more it'll accelerate, but it's completely up to you how hard you want to push. That's what's so great about wheels ! That's why they were such a great invention ! This is where I made my biggest mistake. This guy came into my store one day and said he's got this great invention, it's definitely going to take off, it'll be a winner for sure, he called it a "wheel". I looked at it, I turned it over and I looked on all sides. I thought it was too simple. I didn't know then it was elegant. I threw him out. I was so dumb. I could have invested money in that guy, today I would have probably more than a hundred dollars.
Anyway, can we figure out how much force the student used to push with ? Stay tuned:
-- The bike covered 15 meters in 5 seconds. Its average speed during the whole push was (15m/5s) = 3 meters/sec.
-- If the bike started out with no speed, and its average speed was 3 m/s, then it must have been moving at 6 m/s at the end of the push.
-- If its speed increased from zero to 6 m/s in 5 seconds, then its acceleration was (6m/s / 5 sec) = 1.2 m/s²
-- The bike's weight is 100N.
(mass) x (gravity) = 100N
Bikemass = (100N) / (9.8 m/s²)
Bikemass = 10.2 kilograms
-- F = m A
Force = (mass) x (acceleration)
Force = (10.2 kg) x (1.2 m/s²)
Force = 12.24 N
-- Work = (force) x (distance)
Work = (12.24 N) x (15 m)
Work = 183.67 Joules
-- Power = (work done) / (time to do the work)
Power = (183.67 joules) / (5 seconds)
Power = 36.73 watts
If the force on a spring is 4 N and it stretched 0.5 m, what is the spring constant?
Answer:
8N/m
Explanation:
spring constant = force/extension
4/0.5. = 8N/m
An electron moving with a velocity of 5 × 104 m s -1 enters into a uniform electric field and acquires a uniform acceleration of 104 m s -2 in the direction of its initial motion. (i) Calculate the time in which the electron would acquire a velocity double of its initial velocity. (ii) How much distance the electron would cover in this tim
Answer:
(i) t = 5s
(ii) x = 3.75*10^5 m
Explanation:
(i) To calculate the time that the electron takes to reach twice the value of its initial velocity, you use the following formula:
[tex]v=v_o+at[/tex] (1)
vo: initial velocity of the electron = 5*10^4 m/s
v: final velocity of the electron = 2vo = 1*10^5 m/s
a: acceleration of the electron = 1*10^4 m/s^2
You solve the equation (1) for t, and replace the values of the parameters:
[tex]t=\frac{v-v_o}{a}=\frac{1*10^5m/s-5*10^4m/s}{1*10^4m/s^2}=5s[/tex]
The electron takes 5s to reach twice its initial velocity.
(ii) The distance traveled by the electron in such a time is:
[tex]x=v_ot+\frac{1}{2}at^2[/tex] (2)
you replace the values of the parameters in the equation (2):
[tex]x=(5*10^4m/s)(5s)+\frac{1}{2}(1*10^4m/s^2)(5s)^2\\\\x=3.75*10^5m[/tex]
The distance traveled by the electron is 3.75*10^3m/s
Given the resistivities below, which matedal is best described as an insulator?
O A. 4.5 Ω•m
O B. 2.8 x 10-8 Ω•m
O c. 3.2 x 108 Ω•m
O D. 1.7 x 10-8 Ω•m
Answer:
C. 3.2 x 10^8 Ω•m
Explanation:
An insulator is a material that resists the flow of electricity.
In the given data the material with the highest resistivity is the best insulator
3.2 x 10^8 Ω•m
Two forces of magnitudes 8N and 15N act at a point,if the resultant force is 17N,the angle between forces is equal to:
Answer:
The resultant of two vectors:
P
and
Q
is given by
R=
P
2
+Q
2
+2PQcosθ
where, P and Q are magnitudes of two vectors and θ is the angle between two vectors.
Here θ=? P=8N Q=15N R=17N
Therefore,
17=
8
2
+15
2
+2×8×15cosθ
289=64+225+240cosθ
289=289+240cosθ
289−289=240cosθ
cosθ=0
cosθ=cos90
θ=90
0
Explanation:
Two particles having charges of 0.50~\text{nC}0.50 nC (q_1q 1 ) and 10~\text{nC}10 nC (q_2q 2 ) are separated by a distance of 3~\text{m}3 m (r = 3~\text{m}r=3 m). At what distance away from charge q1 along the line connecting the two charges can a third positive charge be placed such that it experiences a net electric force equal to zero?
Answer:
The third charge must be placed 0.548 m from q₁.
Explanation:
Let r = 3m be the distance between charge q₁ and q₂.
Let x be the distance between charge q₁ and charge q₃ (the third positive charge)
Then r - x is the distance between charge q₂ and q₃
Let the electrostatic force between q₁ and q₃ be F = kq₁q₃/x²
Let the electrostatic force between q₂ and q₃ be F' = kq₂q₃/(r - x)²
Since F + (-F') = 0 (the signs on the forces are different since the forces are in opposite directions)which is required when the net force on q₃ is zero, then
F - F' = 0
F = F'
So, kq₁q₃/x² = kq₂q₃/(r - x)²
q₁/x² = q₂/(r - x)²
[(r - x)/x]² = q₂/q₁
taking square-root of both sides,
(r - x)/x = ±√q₂/q₁
r/x - 1 = ±√q₂/q₁
r/x = 1 ±√q₂/q₁
x = r/(1 ±√q₂/q₁)
substituting the values of the variables r = 3 m, q₁ = 0.50 nC and q₂ = 10 nC
x = 3 m/(1 ±√10 nC/0.5 nC)
x = 3 m/(1 ±√20)
x = 3 m/(1 ± 4.472)
x = 3 m/5.472 or 3 m/-3.472
x = 0.548 m or -0.864 m
So the third charge must be placed 0.548 m to the right of q₁ or 0.864 m to the left of q₁.
Since we are concerned about the line of charge that connects q₁ and q₂, the third charge must be placed 0.548 m from q₁.
Part II # 1 A mass on a string of unknown length oscillates as a pendulum with a period of 4 sec. What is the period if: (Parts (1-4 are independent questions, each referring to the initial situation.) 1) The mass is doubled? 2) The string length is doubled? 3) The string length is halved? 4) The amplitude is halved? A. 1) No Change (4 sec) 2) 2.8 sec 3) 5.7 sec 4) No Change (4 sec) B. 1) 5.7 sec 2) No Change (4 sec) 3) 2.8 sec 4) No Change (4 sec) C. 1) No Change (4 sec) 2) 5.7 sec 3) 2.8 sec 4) No Change (4 sec) D. 1) 5.7 sec 2) No Change (4 sec) 3) No Change (4 sec) 4) 2.8 sec
Answer:
C. 1) No Change (4 sec) 2) 5.7 sec 3) 2.8 sec 4) No Change (4 sec)
Explanation:
Given that:
Period (T) = 4 s
1) If the mass is doubled.
The period of a pendulum is given by the formula:
[tex]T=2\pi\sqrt{\frac{L}{g} }[/tex] where L is the length and g is the acceleration due to gravity.
From the formula, the period does not depend on the mass of the spring therefore if the mass is doubled the period does not change.
2) The string length is doubled
Given that:
[tex]T=2\pi\sqrt{\frac{L}{g} }, but\ T =4s\\4=2\pi\sqrt{\frac{L}{g} }[/tex]
if the length is doubled, the new spring length is 2L. Therefore the new period (T1) is given as:
[tex]T_1=2\pi\sqrt{\frac{2L}{g} }=\sqrt{2} (2\pi\sqrt{\frac{L}{g} })=\sqrt{2}*4=5.7\ sec[/tex]
3) The string length is halved
Given that:
[tex]T=2\pi\sqrt{\frac{L}{g} }, but\ T =4s\\4=2\pi\sqrt{\frac{L}{g} }[/tex]
if the length is halved, the new spring length is L/2. Therefore the new period (T1) is given as:
[tex]T_1=2\pi\sqrt{\frac{L}{2g} }=\sqrt{1/2} (2\pi\sqrt{\frac{L}{g} })=\sqrt{1/2}*4=2.8\ sec[/tex]
4) The amplitude is halved
From the formula, the period does not depend on the amplitude therefore if the amplitude is halved the period does not change.
Jorge camina en línea recta por una plaza, cruzándola de forma diagonal, recorriendo 60 m en 3 min. A partir de esta situación, responde: a) ¿Cuál es la distancia que recorre? b) ¿Cuál es el módulo del desplazamiento? c) ¿Qué valor tendrá su rapidez y el módulo de su velocidad?
Answer:
a) d = 60m (distance)
b) D = 60m (displacement)
c) v = 20 m/min
d) |v| = 20 m/min
Explanation:
a) The distance traveled by Jorge is 60m
d = 60m
b) The module of the displacement D, is equal to the values of the distance d, because Jorge walked in a straight line.
D = d = 60m
c) The speed of Jorge is given by the following formula:
[tex]v=\frac{d}{t}[/tex]
d: distance = 60m
t: time of the walk = 3min
[tex]v=\frac{60m}{3min}=20\frac{m}{min}[/tex]
The speed is 20 m/min
The module of the Jorge's velocity is:
[tex]|v|=\frac{D}{t}[/tex]
D: displacement = d = 60m
t: time = 3 min
[tex]|v|=\frac{60m}{3min}=20\frac{m}{min}[/tex]
The module of Jorge's velocity is 20 m/min
Jorge recorre una distancia de 60 m en 3 min. Su desplazamiento de 60 m, lo hace con una rapidez, y módulo de su velocidad, de 20 m/min.
Jorge camina en linea recta por una plaza recorriendo 60 metros en 3 minutos (t).
La distancia recorrida (d) es 60 m.
Como se mueve en linea recta, el desplazamiento (D) coincide con la distancia recorrida, es decir, es de 60 m.
Podemos calcular la rapidez (s) de Jorge usando la siguiente fórmula.
[tex]s = \frac{d}{t} = \frac{60m}{3min} = 20m/min[/tex]
La rapidez es una magnitud escalar y coincide con el modulo de la velocidad, dado que la velocidad es vectorial.
Jorge recorre una distancia de 60 m en 3 min. Su desplazamiento de 60 m, lo hace con una rapidez, y módulo de su velocidad, de 20 m/min.
Aprende mas: https://brainly.com/question/24773606
A 0.850 kg mass is placed on a
spring, pulled and released. It
oscillates 40 times in 66.4 s.
What is the spring constant k?
(Unit = N/m)
Answer:
Picture
Explanation:
I am trying to solve this Q
but not sure if this a correct answer
or not.
Hope this helps.
Answer:
12.161 n/m
Explanation:
Trust me bro.
A train rolls past a stationary observer. To him, the train is moving at a speed of 23m/s west, and a woman on the train is moving at a speed of 22.4m/s west. How long does it take the women to move 13 m relative to the train?
A. 24.1s
B.21.7s
C. 23.2s
D. 25.6s
Answer:
21.7 seconds.
Explanation:
Woman's velocity relative to train (23 m/s - 22.4 m/s) = 0.6 m/s
Distance woman wants to travel = 13m
To find how long she will take to move 13m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.
(13m)/(0.6 m/s) = 21.6667 seconds or 21.7 seconds.
Therefore, it will take the woman 21.7 seconds to move 13m.
the value of MA in the third class lever is alaways less than one,why
Answer:
It is always less than 1 because the load arm is always longer than effort arm.
Explanation:
In the formula, MA= effort divided by load which makes it less than 1.
This helps by reducing the applied force(effort). It is a speed multiplier.
Hope it helps.
A skateboarder rides swiftly up the edge of a bowl-shaped surface and leaps into the air. While in the air, the skateboarder flips upside and tosses the skateboard from hand to hand. The skateboarder then rides safely back down the bowl. During the time that the skateboarder and skateboard are not touching anything, one aspect of their motion that is constant is their total (or combined) [note: neglect any effects due to the air]
a. angular momentum.
b. angular velocity.
c. velocity.
d. momentum.
Answer:
Option(a) is the correct answer to the given question .
Explanation:
The main objective of the angular momentum is evaluating however much the rotational movement as well as the angular velocity in the entity does have.The angular momentum is measured in terms of [tex]kgm^{2 }\ / s[/tex].
In the given question the skateboarder rides quickly up the bottom of a bowl-shaped surface and climb into the air.it means it is rotational movement also it is not touching anything so it is angular momentum.All the other option is incorrect because it is not follows the given scenarioA garrafa térmica (também conhecida como "vaso de Dewar") é um dispositivo extremamente útil para conservar, no seu interior, corpos (essencialmente líquidos) em altas temperaturas, minimizando trocas de energia com o ambiente, geralmente mais frio. Uma garrafa térmica contém água a 60 o C. O conjunto garrafa térmica + água possui capacidade térmica C=80 cal/o C. O sistema é colocado sobre uma mesa e, após um intervalo considerável de tempo, a sua temperatura diminui para 55 o C. Nesse caso, conclui-se que o sistema formado pela garrafa térmica e pela água no seu interior: a) perdeu 400 cal. B) ganhou 404cal. C) perdeu 4 850 cal. D) ganhou 4 850 cal. E) não trocou calor com o meio externo.
Answer:
A opção A está correta.
O sistema formado pela garrafa térmica e a água perde 400 cal de calor para o meio ambiente.
Option A is correct.
The system formed by the thermos and the water loses 400 cal of heat to the environment.
Explanation:
Quando a temperatura de um sistema reduz, fica claro que o sistema perdeu calor ou energia térmica. Como a temperatura é um dos indicadores mais claros disso, esta conclusão é hermética e correta.
Mas, para saber a quantidade de calor perdida para o meio ambiente, agora fazemos alguns cálculos de energia térmica.
Transferência de calor de ou para o sistema de água e garrafa térmica = c × ΔT
c = capacidade térmica do sistema de água e garrafa térmica = 80 cal /°C
ΔT = Alteração da temperatura do sistema de água e garrafa térmica = (temperatura final) - (temperatura inicial) = 55 - 60 = -5°C
Calor transferido = 80 × -5 = -400 cal.
O sinal de menos mostra que o calor é transferido para fora do sistema, ou seja, o calor é perdido no sistema.
Espero que isto ajude!!!
English Translation
The thermos (also known as "Dewar vase") is an extremely useful device to conserve bodies (essentially liquid) at high temperatures, minimizing energy exchanges with the environment, which is generally colder. A thermos contains water at 60 o C. The thermos + water set has a thermal capacity of C = 80 cal / o C. The system is placed on a table and, after a considerable period of time, its temperature decreases to 55 o C. In this case, it is concluded that the system formed by the thermos and the water inside:
a) lost 400 cal. B) gained 404cal. C) lost 4 850 cal. D) gained 4 850 cal. E) did not exchange heat with the external environment.
Solution
When a system's temperature reduces, it is clear to conclude that the system has lost heat or thermal energy. Since temperature is one of clearest indicators of this, this conclusion is airtight and correct.
But, to know the amount of heat lost to the environment, we now do some thermal energy calculations.
Heat transferrred from or to the water and thermos system = c × ΔT
c = heat capacity of the water and thermos system = 80 cal/°C
ΔT = Change in temperature of the water and thermos system = (final temperature) - (initial temperature)
= 55 - 60 = -5°C
Heat transferred = 80 × -5 = -400 cal.
The minus sign shows that the heat is transferred out of the system, that is, the heat is lost from the system.
Hope this Helps!!!
A 7.00 g bullet, when fired from a gun into a 1.00 kg block of wood held in a vise, penetrates the block to a depth of 8.00 cm before stopping due to the frictional force between the wood and bullet. This block of wood is next placed on a friction-less horizontal surface, and a second 7.00-g bullet is fired from the gun into the block. To what depth will the bullet penetrate the block in this case
Answer:
Explanation:
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I NEEED HELP!!!!! Upon using Thomas Young’s double-slit experiment to obtain measurements, the following data were obtained. Use these data to determine the wavelength of light being used to create the interference pattern.
Do this using three different methods.
The angle to the eighth maximum is 1.12°.
The distance from the slits to the screen is 302.0 cm.
The distance from the central maximum to the fifth minimum is 3.33cm.
The distance between the slits is 0.000250 m
Answer:
The wavelength is approximately 611 nm
Explanation:
We can use the formula for the condition of maximum of interference given by:
[tex]d\,sin(\theta)=m\,\lambda\\(0.000250\,\,m)\,\,sin(1.12^o)=8\,\lambda\\\lambda=\frac{1}{8} \,(0.000250\,\,m)\,\,sin(1.12^o)\\\lambda \approx 610.8\,\,nm[/tex]
We can also use the formula for the distance from the central maximum to the 5th minimum by first finding the tangent of the angle to that fifth minimum:
[tex]tan(\theta)=\frac{y}{D}\\ tan(\theta)=\frac{0.0333}{3.02} =0.011026[/tex]
and now using it in the general formula for minimum:
[tex]d\,sin(\theta)\approx d\,tan(\theta)=(m-\frac{1}{2} )\,\lambda\\\lambda\approx 0.00025\,(0.011026)/(4.5)\,\,m\\\lambda\approx 612.55\,\,nm[/tex]
Answer:
The correct answer is [tex]6.1\times10^{-7}\:m[/tex]
Explanation:
The distance from the central maxima to 5th minimum is:
[tex]x_{5n}-x_{0} =3.33\:cm=0.033\:m[/tex]
The distance between the slits and the screen:
[tex]L = 302\:cm = 3.02\:m[/tex]
Distance between 2 slits: [tex]d = 0.00025\:m[/tex]
[tex](n-\frac{1}{2})\lambda=\frac{d(x_n)}{L}[/tex]
For fifth minima, n = 5... so we have:
[tex]x_{5n}=\frac{9\lambda L}{2d}[/tex]
For central maxima, n = 0... so we have:
[tex]x_{0}=\frac{n\lambda L}{d}=0[/tex]
So the distance from central maxima to 5th minimum is:
[tex]\frac{9\lambda \:L}{2d}-0=0.033[/tex] (Putting the values, we get):
[tex]\Rightarrow \lambda = 6.1\times 10^{-7}\:m[/tex]
Best Regards!
Madison applied a force of 150 N in a horizontal direction to a sleigh. Meanwhile the sleigh slid 30.0 m across a level surface of snow. The work done on the sleigh by Madison is _________ J.
Answer:
4500 joules
Explanation:
since work(joules) = force(newtons) x distance(meters),
150N x 30M = 4500 Joules
Answer:
4500 joules
Explanation:
150 N x 30 M = 4500 joules
Dan's plant will require two shifts of skilled workers, seven days a week. As he does his research, he
will pay particular attention to
A. the labor market.
B. regulatory restrictions.
C. performance measures.
D. his target market.
Answer:
the labor market.
Explanation:
Dan's plant will require two shifts of skilled workers, seven days a week. As he does his research, he will pay particular attention to the labor market.
A shower has a power of 10kw. A family uses the shower for 1 hour per day calculate how much energy, in kilowatt hours, they would have to pay for each week for using the shower. An electricity company charges 10p for each kwh calculate the cost in pounds
Answer:
70p per week
Explanation:
Power * time = energy
1 kw * 1 hour = 1 kwh per day
For 7 days,
Energy used = 1 kwH/day * 7 days = 7kwh
Total cost per week = 7 kwh * 10p
= 70p
According to Newton’s first law of motion, when will an object at rest begin to move? when its inertia decreases to zero when an unbalanced force acts upon it when the action and reaction forces are equal when two equal and opposite forces act upon it
Answer:
Option b
Explanation:
This is a nice and simple question!
Consider Newton's first law of motion. It states that an object at rest will remain at rest until acted upon by an unbalanced force. That being said the reverse is applicable as well, an object in motion will remain in motion unless acted upon by an unbalanced force.
Thus, according to Newton's first law of motion, an object at rest begins to move when an unbalanced force acts upon it.
Answer:
b.
Explanation:
Briefly discuss:
(i) The principles of detecting thermal neutrons utilizing a Si detector.
(ii) The physics of fast neutron detection.
(iii) The principle of operation of strip detectors for charged particle detection and
their application.
Answer:
(i) Si device are coated with B or Li for neutron detection
(ii) Fast neutrons are normally first slowed down to thermal energies before measurement
(iii) The strip detectors consists of p⁺ and n implants in the region of a very thin (300 to 400 μm) depletion zone though which the neutrons traverse producing a readout based on the generated charges being directed to the cathode, p⁺, material which then transmits the charge to the device electronics
Explanation:
(i) Detection of neurons with only an Si device in not possible due to the large neutrons path in Si such that the silicon needs to be coated with B or Li which readily interact with neutrons. The neutron interaction with the reactive coating produces an alpha particle which can be detected by the semi conductor and a nucleus
(ii) Neutrons having a kinetic energy that is more than 1 MeV which as such has a velocity of more than 15,000 km/s is known as fast neutrons or fission neutrons. The fast neutrons are slowed in a nuclear reactor by neutron moderation to thermal energies
Due their high speed, fast neutrons are normally slowed down which however results in the loss of some vector properties of the neutron
Techniques for fast neutron detection includes,
1) Recoil detectors which are capable of fast neutron detection without moderation
2) Bonner spheres detector first converts the fast moving electron to slow down before detection
3) Scintillation counter are widely used but require the conversion of the neutron to a charged particles before detection
(iii) Strip detectors provide high precision measurement of a particle's crossing point which can be further improved by use of low noise electronics
Applications of silicon strip detectors include
1) Particle tracking in research in particle physics
2) Particle tracking in researches in x-spectroscopy nuclear research
3) Imaging in x-talography
4) Medical research imaging
5) Particle tracking and imaging in astrophysics.
determine the thrust produced if 1.5 x 10^3 kg of gas exits the combustion chamber each second, with a speed of 4.00 x 10^3 m/s.
Answer:
The thrust is [tex]6\times 10^6\ N[/tex]
Explanation:
Given that,
Mass of gas, [tex]m=1.5\times 10^3\ kg[/tex]
The rate at which the gas is expelling, [tex]\dfrac{dv}{dt}=4\times 10^{3}\ m/s[/tex]
We need to find the thrust produced by the gas.
We know that force is equal to the rate of change of momentum. So,
[tex]F=\dfrac{p}{t}[/tex]
Also, p = mv
[tex]F=\dfrac{mv}{t}[/tex]
So,
[tex]F=1.5\times 10^3\times 4\times 10^3\\\\F=6\times 10^6\ N[/tex]
So, the thrust is [tex]6\times 10^6\ N[/tex]
A spring is attached to the ceiling and pulled 9 cm down from equilibrium and released. The amplitude decreases by 7% each second. The spring oscillates 15 times each second. Find an equation for the distance, D the end of the spring is below equilibrium in terms of seconds, t.
Answer:
[tex]D(t) = 9(0.93)^t cos(30 \pi t)[/tex]
Explanation:
Amplitude begins at 9 cm, [tex]A_0 = 9 cm[/tex]
The amplitude decreases by 7% (0.07) each second
The amplitude function can then be modeled as:
[tex]A(t) = A_0(1 - 0.07)^t\\A(t) = 9(0.93)^t[/tex]
The spring oscillates 15 times each second, the period of oscillation (time to make 1 oscillation) will therefore be calculated as:
T = 1/15
[tex]\frac{2\pi }{B} = \frac{1}{15} \\\\B = 30\pi[/tex]
The graphical equation of the system described is:
[tex]D(t) = A cos ( Bt - C) + D[/tex]
Horizontal shift, C = 0
Vertical shift, D = 0
[tex]D(t) = 9(0.93)^t cos(30 \pi t)[/tex]
Help please !!!!
LIKE ASAP!
In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040. About how old will she appear to be?
Answer:
42.11 years old
Explanation:
Given that:
In 2000, a 20-year-old astronaut left Earth to explore the galaxy; her spaceship travels at 2.5 x 10^8 m/s. She returns in 2040
To find her age we use:
[tex]\Delta t_m=\frac{\Delta t_s}{\sqrt{1-\frac{v^2}{c^2} } }\\[/tex]
Δtm is time interval for the observer stationary relative to the sequence of
events = 2040 - 2000 = 40 years
Δts is is the time interval for an observer moving with a speed v relative to the sequence of event
v = velocity = 2.5 x 10^8 m/s
c = speed of light = 3 x 10^8 m/s
[tex]\Delta t_s=\Delta t_m}{\sqrt{1-\frac{v^2}{c^2} } }\\\Delta t_s=40\sqrt{1-\frac{(2.5*10^8)^2}{(3*10^8)^2}}\\\Delta t_s=22.11\ yr[/tex]
Here age in 2000 is 20 year, therefore when she appear she would be 20 year + 22.11 year = 42.11 years old
As a motorcycle takes a sharp turn, the type of motion that occurs is called _______________ motion.
Answer:
circular motion
Explanation:
As a motorcycle takes a sharp turn, the type of motion that occurs is called circular motion.
Circular motion is a movement of an object along a circular path. As this motorcycle makes the sharp turn, it is acted upon by a centripetal force which directs the motorcycle towards the center.
Therefore, circular motion is the correct answer to the question.
Answer:
Circular Motion
What are the differences between concave lens and concave mirrors?
Explanation:
A concave mirror can form real, inverted images of various sizes and virtual, erect and enlarged images whereas a concave lens forms only virtual, errect and diminished images.
You want to paint the walls of a house so that they reflect as much light as possible. What paint would be preferable to use?
Answer:
white
Explanation:
white is less absorbent then black
Heat transfer between two substances is affected by specific heat and the
O chemical composition of the substances.
O state of matter of the substances at room temperature.
othermal equilibrium of the substances.
O amount of time and area of physical contact between the substances.
The correct answer is D. Amount of time and area of physical contact between the substances.
Explanation:
Heat transfer refers to the flow of thermal energy or heat between two or more objects. This process involves multiple factors and implies heat from the hottest object goes to the coldest one until there is an equilibrium. To begin, heat transfer depends on the amount of thermal energy in the objects because objects must have a different amount of thermal energy for heat to flow.
Besides this, the amount of energy that flows depends on the time and the contact between the substances of objects. Indeed, objects need to be in contact or close to each other for heat to transfer, and the time needs to be enough for the process to occur. For example, if you place a pot over the fire just for a few seconds it is likely the heat transferred is minimal, which does not occur if you leave the pot more time. At the same time if the pot is in close contact with fire more heat will be transferred.-
Answer:
the answer is D on edginuity.
Explanation:
Which actions most likely cause the domains in a ferromagnetic material to align? Check all that apply. heating the material rubbing the material against a magnet passing electricity around the material placing the material in a magnetic field of opposite polarity placing the material near a strong magnet hitting the material
Answer:
i. rubbing the material against a magnet
ii. placing the material in a magnetic field of opposite polarity
iii. placing the material near a strong magnet
Explanation:
Ferromagnetic materials are majorly metals which can be easily attracted by a magnet. ferromagnetic materials are made up of domains, behaves as minute pieces of magnet. They can be rearranged to align when under the influence of an external magnetic field.
The alignment of the domains in a ferromagnetic material can be caused by either of the following: rubbing the material against a magnet, placing the material in a magnetic field of opposite polarity, placing the material near a strong magnet.
Answer:
B, D, E
Explanation:
edg2020
Yeah Physics!!!! I will give Brainliest to whoever can solve this question!!!
If i workout 90 minutes on earth, if I am on a rocket traveling 0.80c, according to the timer on the rocket, how long should I exercise?
Answer:
The person should exercise 150 minutes
Explanation:
Recall that the Lorentz factor must be applied to the relationship between the elapsed time (T) of the clock at rest (time measured on Earth), and the elapsed time (T') measured by the clock in the frame moving at 0.8 c. The equation becomes:
[tex]T'=\frac{T}{\sqrt{1-(\frac{0.8\,c}{c})^2 } } \\T'=\frac{90\,min}{\sqrt{1-0.8^2} } \\T'=150\,\,min[/tex]